Plot (−134,412) on the coordinate plane.
Answers
We are given coordinate (-1 3/4, 4 1/2).
(-1 3/4, 4 1/2) represents x-coordinate -1 3/4.
And y-coordinate 4 1/2.
First we need to go -1 and three fourth between -1 and -2.
And then for 4 1/2, we need to got 4 above on y-axis and then a half between 4 and 5.
We would draw the coordinate of intersection of vertical line of point -1 3/4 and horizontal line at 4 1/2.
The shown green point on the graph is the coordinate (-1 3/4, 4 1/2).
Answer:
I hope this helps! <3
Step-by-step explanation:
Related Questions
What is the measure of angle B in the triangle?
m∠B= [???]
A triangle labeled ABC with angle A: 120, angle B: x [unknown] and angle C as ( x+16).
What is the value of X (aka angle B.)
Answers
180 = 120 + x + x + 16
Simplify: 180 = 136 + 2x
Subtract: 44 = 2x
Divide: x = 22
Answer: x (Angle B) = 22
Hope this helps!! :)
1. London Heathrow airport sees on average 191,200 passengers a day. How many passengers is this per minute?
Answers
60 minutes in 1 hour
7966.67 / 60 = 132.78 people per minute round to 133 people
PLEASE HELP ASAP!! BRAINLIEST TO RIGHT/BEST ANSWER
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Answer is B
HEY THERE
please help me in math>>>
Answers
Using the image, explain which angles are angles of elevation and which are angles of depression. Name all the angles that apply.
Answers
Angles 1 and 3 are angles of depression.
Angles of elevation are measured above the horizontal.
Angles 2 and 4 are angles of elevation.
Depression - 2, 4
Will mark brainliest and give 20 points! In what ways can vertical, horizontal, and oblique asymptotes be identified? Please use your own example to identify.
Answers
When you have a rational expression in which the denominator is zero, you have a vertical asymptote. So to find vertical asymptotes, just set the denominator of your rational expression equal to zero, and then, solve for [tex]x[/tex]:
[tex] \frac{x-1}{x-3} [/tex]
Set the denominator equal to zero:
[tex]x-3=0[/tex]
Solve for [tex]x[/tex]:
[tex]x=3[/tex] is the vertical asymptote of our rational expression.
Horizontal asymptote:
Here we have two scenarios.
1) Is the degree of the denominator is higher than the degree of the numerator, you will have a horizontal asymptote at [tex]y=0[/tex]:
[tex]y= \frac{x-1}{x^{2}+3} [/tex]
Since the degree of the denominator is higher of the degree of the numerator, our rational expression will have an asymptote at [tex]y=0[/tex]
2) If the degree of both denominator and numerator is the same, the rational expression will have an horizontal asymptote at the ratio of the leading coefficients:
[tex] \frac{3x^{2}+5}{2x^2-3x+1} [/tex]
Leading coefficients: 3 and 2
Ratio of leading coefficients:
[tex] \frac{3}{2} [/tex]. Our rational expression will have an horizontal asymptote at [tex]y= \frac{3}{2} [/tex]
Oblique asymptote:
If the degree of the numerator is higher than the degree of the numerator, you will have an oblique asymptote. To find it, we are going to perform long division; the quotient (without the remainder) will be the equation of the oblique asymptote line:
[tex] \frac{x^2+5x+2}{x+1} [/tex]
The quotient of the long division is [tex]x-1[/tex] with a remainder of 2; therefore, the equation of the oblique asymptote line will be:
[tex]y=x+4[/tex]
You are working at the register at a grocery store during the busiest time of the day. A customer buys a mud of cheese for 4.62 and a box of crackers for 1.29. She hands you $6.00, and the register says she still owes $0.54. Since you were in a hurry, you made a mistake by typing the numbers in the wrong order. What mistake did you make?
Answers
4.62+1.92=6.54
she gave you 6 and looks like she still own 0.54 cents
The difference of two numbers is 3 and their quotinet is 2 what are the 2 numbers
Answers
Medal
The table below shows the distance y, in miles, traveled by a toy car in x minutes:
Time (x)
(minutes)
10 20 30 40
Distance (y)
(miles)
4 8 12 15
Part A: What is the most likely value of the correlation coefficient of the data in the table? Based on the correlation coefficient, describe the relationship between time and distance traveled by the toy car.
[Choose the value of correlation coefficient from 1, 0.99, 0.5, 0.02]
Part B: What is the value of the slope of the graph of distance versus time between 10 minutes and 30 minutes, and what does the slope represent?
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Given: Quadrilateral ABCD is inscribed in circle O.
Prove: m∠A + m∠C = 180°
Drag an expression or phrase to each box to complete the proof.
Statements → Reasons
1. ___________ → Given
2. mBCD = 2(m∠A) → ________
3. mDAB = 2(m∠C) → Inscribed Angle Theorem
4. _________ → The sum of arcs that make a circle is 360°.
5. 2(m∠A) + 2(m∠C) = 360° → _________
6. m∠A + m∠C = 180° → Division Property of Equality
Answer Choices:
Substitution Property
Inscribed Angle Theorem
Central Angle Theorem
mBCD + mDAB = 360°
mBCD = mDAB
Quadrilateral ABCD is inscribed in circle O.
I'm guessing:
1. Quadrilateral ABCD is inscribed in circle O.
4. mBCD + mDAB = 360°
5. Inscribed Angle Theorem
I'm not sure about 5 or 2.
Thanks.
Answers
A quadrilateral is a four sided figure, in this case ABCD is a cyclic quadrilateral such that all its vertices touches the circumference of the circle.
A cyclic quadrilateral is a four sided figure with all its vertices touching the circumference of a circle.
2. mBCD = 2 (m∠A) = Inscribed Angle Theorem
An inscribed angle is an angle with its vertex on the circle, formed by two intersecting chords.
Such that Inscribed angle = 1/2 Intercepted Arc
In this case the inscribed angle is m∠A and the intercepted arc is MBCD
Therefore; m∠A = 1/2 mBCD
4. The sum of arcs that make up a circle is 360
Therefore; mBCD + mDAB = 360°
The circles is made up of arc BCD and arc DAB, therefore the sum angle of the arcs is equivalent to 360°
5. 2(m∠A + 2(m∠C) = 360; this is substitution property
From step 4 we stated that mBCD +mDAB = 360
but from the inscribed angle theorem;
mBCD= 2 (m∠A) and mDAB = 2(m∠C)
Therefore; substituting in the equation in step 4 we get;
2(m∠A) + 2(m∠C) = 360
Answer:
I took the test :) have a great day!
Step-by-step explanation:
Three dice are going to be rolled. What is the probability that the first die rolled is a 1, the second die rolled is a 2, and the third die rolled is a 3? (If necessary, round to the nearest tenth)
Answers
The chance of each given event happening is 1/6 because there are 6 different number on the dice and only 1 number is chose.
Therefore to find the combined probability, we have to multiply all the individual probabilities.
(1/6) x (1/6) x (1/6)
Or
(1/6)^3
The answer is about 0.46%,
Probability of getting first die rolled is a 1, second die rolled is a 2 and third die rolled is a 3 is equals to 0.46% (nearest tenth).
What is probability?
" Probability is a mathematical expression which represents the ratio of number of favourable outcomes to the total number of outcomes."
Formula used
Probability = [tex]\frac{Number of favourable outcomes}{Total number of outcomes}[/tex]
According to the question,
Possible outcomes on each die = { 1, 2, 3, 4, 5, 6}
Substitute the value in the formula as per the given condition we get,
Probability that the first die rolled is a 1 = ( 1 / 6)
Probability that the second die rolled is a 2 = ( 1 / 6)
Probability that the third die rolled is a 3 = ( 1 / 6)
Required Probability = (1 / 6) × (1 / 6) ×(1 / 6)
= ( 1 / 216)
= 0.0046
= 0.46% (nearest tenth)
Hence, required probability (nearest tenth) = 0.46%
Learn more about probability here
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How to solve: \frac{1}{y^{\frac{2}{5}}} ?
Answers
[tex]\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} \qquad \qquad \sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\ -------------------------------[/tex]
[tex]\bf \cfrac{1}{y^{\frac{2}{5}}}\implies \cfrac{1}{\sqrt[5]{y^2}} \quad \stackrel{rationalizing~it}{\implies }\quad \cfrac{1}{\sqrt[5]{y^2}}\cdot \cfrac{\sqrt[5]{y^3}}{\sqrt[5]{y^3}}\implies \cfrac{\sqrt[5]{y^3}}{\sqrt[5]{y^2}\cdot \sqrt[5]{y^3}} \\\\\\ \cfrac{\sqrt[5]{y^3}}{\sqrt[5]{y^2y^3}}\implies \cfrac{\sqrt[5]{y^3}}{\sqrt[5]{y^{2+3}}}\implies \cfrac{\sqrt[5]{y^3}}{\sqrt[5]{y^5}}\implies \cfrac{\sqrt[5]{y^3}}{y}[/tex]
Elliot has deposited $723 in a savings account that earns interest at a rate of 2.9% compounded twice a year. What will the account balance be in 23 years? (2 points)
Select one:
a. $826.02
b. $743.97
c. $1,401.95
d. $2,096.70
Answers
A=723(1+.029/2)^(2*23)
A=$1,401.95 So C
PLZ HELP!!!!!! The assessment for this lesson is to participate in a discussion about composite figures. You will be able to participate in the discussion throughout the unit. You are required to complete the following: 1) Respond to the discussion topic. 2) Respond to your two of your classmates’ ideas as well. Discussion Topic: What is an example of a composite figure in your home or community? How would you decompose it to find the area? Can you think of another reason that it would be helpful to decompose these figures in addition to making it easier to find the area of the figure? Before participating in the discussion, please review the discussion guidelines and grading rubric used to evaluate your participation.
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Imagine the sets of regular kitchen cabinets going around the walls, refrigerators and sinks in your kitchen. They are generally all connected together in one piece.
However, there are also all individual pieces. To find the total volume of the cabinets, you should break them all down into the individual single prisms.
You could also look at it as an area problem on the wall. How much total space are the cabinets taking up.
Based on the graph below, what is the solution of the equation f(x) = g(x)? graph of function f of x equals negative x plus 0.5 and graph of function g of x equals x squared plus 3 multiplied by x minus 4
Answers
f(x)=-x+0.5
g(x)=x²+3x-4
f(x)=g(x)------------> -x+0.5=x²+3x-4-------------> x²+3x-4+x-0.5=0
x²+3x-4+x-0.5=0---------------> x²+4x-4.5=0
using a graph tool
see the attached figure
the solution are the points (-4.915,0) and (0.915,0)
In a candy factory, the nutty chocolate bars contain 19.0 % pecans by mass. if 5.0 kg of pecans were used for candy last tuesday, how many pounds of nutty chocolate bars were made?
Answers
26.32 pounds of nutty chocolate were made.
Using the parameters given;
percentage of pecans per chocolate = 19%Mass of pecans used = 5kgThe amount of pounds of chocolate made ;
Mass of pecans used / Percentage of pecans 0er chocolateNow we have ;
5/0.19 = 26.315Hence, 26.32 pounds of nutty chocolate were made.
What’s the answer ???
(ONLY ANSWER IF YOU KNOW)
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______________________________________________________
When solving negative one over five(x − 25) = 7, what is the correct sequence of operations?
A. Multiply each side by negative one over five, add 25 to each side
B.Multiply each side by 5, subtract 25 from each side
C.Multiply each side by negative one over five, subtract 25 from each side
D.Multiply each side by −5, add 25 to each side
Answers
Option: D is the correct answer.
D.Multiply each side by −5, add 25 to each side
Step-by-step explanation:We are given an algebraic expression in terms of variable x as follows:
[tex]\dfrac{-1}{5}(x-25)=7[/tex]
Now, firstly we will multiply both side of the equation by -5 to get:
[tex]\dfrac{-1}{5}\times (-5)(x-25)=7\times -5\\\\i.e.\\\\x-25=-35[/tex]
Now we add both side of the equation by 25 to get:
[tex]x-25+25=-35+25\\\\i.e.\\\\x+0=-10\\\\i.e.\\\\x=-10[/tex]
Sam is walking to Joe’s house at a rate of 2 miles per hour. Joe left his house at the same time and is walking at a rate of 1.5 miles per hour. If Sam and Joe live 7 miles apart, how long will it take for Sam and Joe to meet?
Answers
The time it takes for Sam and Joe to meet in hours= t
Joe's speed = 1.5miles/hour
Sam's speed = 2 miles/hour
Distance between Joe and Sam = 7 miles
When they meet Joe covers a distance of J miles and Sam covers S miles
Now,
J+S=7
J=1.5 miles/hour *t
S= 2 miles/hour * t
1.5t + 2t =7
3.5 t = 7
t=2 hours
It will take 2 hours for Sam and Joe to meet
A four sided sandbox has exactly two right angles side lengths 5ft and two side lengths 6ft what shape best describes the shape of the sandbox
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A kite, however, has two pairs of equal-length sides that are adjacent to each other. It also has two sets of equal-measure angles, one of which can be 90° if it is a cyclic kite.
The sandbox has two right angles and two side lengths of 5ft and two side lengths of 6ft. This shape is consistent with a rectangle. Therefore, the shape of the sandbox is best described as a rectangle.
The sandbox described possesses two right angles and two pairs of opposite sides with equal lengths. Specifically, it has two sides of 5ft and two sides of 6ft. These characteristics are indicative of a rectangle.
Rectangles are quadrilaterals with four right angles, meaning each corner of the shape forms a 90-degree angle. Additionally, opposite sides of a rectangle are equal in length, which is evident in this sandbox with its 5ft and 6ft sides. The presence of two right angles further reinforces the shape's rectilinear nature.
Moreover, rectangles have parallel opposite sides, which allows for uniformity in the sandbox's shape. This geometric feature is crucial for ensuring a consistent and stable structure.
By definition, squares are also rectangles, but not all rectangles are squares. Given that the sides of the sandbox are not all of equal length (i.e., not a square), it is more appropriate to classify it as a rectangle.
Therefore, considering the sandbox's right angles, equal opposite sides, and parallel sides, it aligns most closely with the characteristics of a rectangle.
A) 90°
B) 180°
C). 6°
D). 86°
Answers
68°+26°+x°=180°
Solve it as an equation:
68+26+x=180
x=180-68-26
x=86°
Name the type of symmetry for the figure.
reflectional
rotational
rotational and reflectional
no symmetry
DOES ANYONE HAVE THE WHOLE QUIZ????
Answers
Answer:
Rotational
Step-by-step explanation:
Reflectional symmetry is when a figure can be folded in half through some given line and half each half congruent to the other. There is no line through which to fold this figure, so there is no reflectional symmetry.
Rotational symmetry is when a figure can be turned some degree and be congruent to itself; This figure can be rotated 180°, so this has rotational symmetry.
Without the figure, it's impossible to determine the type of symmetry it has. Symmetry in mathematics can be reflectional, rotational, both, or none at all depending on the characteristics of the given figure.
Explanation:To answer your question, we need the figure in order to determine the type of symmetry. In mathematics, symmetry can be classified as reflectional, rotational, both reflectional and rotational, or it can have no symmetry at all. Reflectional symmetry is when one half is the mirror image of the other half. Rotational symmetry is when the figure can be rotated to some degrees and still appears the same. The term doesn't have a specific figure attached, so without more information, a direct answer cannot be given.
Learn more about Symmetry here:https://brainly.com/question/34365664
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What is the sum or difference?
1. 2x^4 - 8x^4
(A). -6x^8
(B). -6x^4
(C). -16x^4
(D). -16x^8
What is the sum or difference?
2. 6y^5 - 9y^5
(A). -3y^10
(B). 15y^5
(C). -54y^5
(D). -3y^5
3. Write the Polynomial in standard form. Then name the Polynomial based on its degree and number of terms.
6 - 12x + 13x^2 - 4x^2
(A). 9x^2 - 12x; quadratic binomial
(B). 9x^2 - 12x + 6; quadratic trinomial
(C). -3x^2 + 6; quadratic binomial
(D). 9x^2 - 12x - 6; cubic trinomial
4. A biologist studied the populations of common guppies and Endler's guppies over a 6-year period. The biologist modeled the populations, in ten of thousands, with the following polynomials where x is time, in years.
Common guppies: 3.1x^2 + 6x + 0.3
Endler's guppies: 4.2x^2 - 5.2x + 1
What polynomial models the total number of common and Endler's guppies?
(A). 7.3x^2 + 0.8x + 0.7
(B). 7.3x^2 - 0.8x + 1.3
(C). 7.3x^2 + 0.8x + 1.3
(D). 7.3x^2 + 0.8x - 1.3
5. A family is building a circular fountain in the backyard. The yard is rectangular and measures 14x by 19x and the fountain is going to be circular with a radius of 6x. Once the fountain is built, what will be the area of the remaining yard?
(A). 230πx^2
(B). 230x^2
(C). 266x^2 - 6πx^2
(D). 2x^2(133 - 18π)
6. A sports team is building a new stadium on a rectangular lot of land. If the lot measures 6x by 10x and the sports field will be 1x by 4x, how much of the lot will be left over to build bleachers on?
(A). 56x^2
(B). 64x^2
(C). 30x^2
(D). 60x^2
Can someone please help!! This is lesson 9, Unit 3, Polynomials and Factoring!!
Answers
Explanation:
Given: [tex]2x^4 - 8x^4[/tex]
Take the common out:
=> [tex]x^4(2 - 8)[/tex]
Hence: => [tex][tex]-6x^4[/tex][/tex] (Option B)
2. Ans: Option (D) [tex]-3y^5[/tex]
Explanation:
Given: [tex]6y^5 - 9y^5[/tex]
Take the common term(s) out:
=> [tex]y^5(6-9)[/tex]
Hence: => [tex]-3y^5[/tex] (Option D)
3. Ans: Option (B) [tex]9x^2 - 12x + 6[/tex] quadratic trinomial
Explanation:
Given: [tex]6 - 12x + 13x^2 - 4x^2[/tex]
The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.
=> [tex]13x^2 - 4x^2 - 12x + 6[/tex]
=> [tex]9x^2 - 12x + 6[/tex] (Option B)
4. Ans: Option (C) [tex]7.3x^2 + 0.8x + 1.3[/tex]
Explanation:
In order to find the total number of Common and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:
Common guppies: [tex]3.1x^2 +6.0x + 0.3[/tex]
Endler's guppies: [tex]4.2x^2 - 5.2x + 1.0 [/tex]
(add both)
-----------------------------------------------------------------
Total number: [tex]7.3x^2 +0.8x + 1.3[/tex]
-----------------------------------------------------------------
Hence the ans is Option(C) [tex]7.3x^2 + 0.8x + 1.3[/tex]
5. Ans: Option (D) [tex]2x^2(133 - 18 \pi )[/tex]
Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = [tex]266x^2[/tex]
Now the area of the circular fountain:
Area of the Circular Fountain = [tex] \pi r^2[/tex]
Since, r=6x
Therefore,
Area of the Circular Fountain = [tex] \pi (6x)^2 = 36 \pi x^2[/tex]
Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = [tex]266x^2[/tex] - [tex]36 \pi x^2[/tex]
=> Final area of the Yard = [tex]2x^2(133 - 18 \pi)[/tex] (Option D)
6. Ans: Option (A) [tex]56x^2[/tex]
Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = [tex]60x^2[/tex]
Now the area of the stadium:
Area of the stadium = 1x * 4x = [tex]4x^2[/tex]
Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= [tex]60x^2[/tex] - [tex]4x^2[/tex]
=> Final area of the lot = [tex]56x^2[/tex] (Option A)
-i
Answer:1. B
Step-by-step explanation:
Convert the equation to the standard form for a hyperbola 4x^2-25y^2-8x+50y-121=0
Answers
4x²-25y²-8x+50y-121=0
Group terms that contain the same variable, and move the constant to the opposite side of the equation
(4x²-8x)+(-25y²+50y)=121
Factor the leading coefficient of each expression
4(x²-2x)-25(y²-2y)=121
Complete the square twice. Remember to balance the equation by adding the same constants to each side.
4(x²-2x+1)²-25(y²-2y+1)²=121+4-25
Rewrite as perfect squares
4(x-1)²-25(y-1)²=100
Divide both sides by the constant term to place the equation in standard form
(4/100)(x-1)²-(25/100)(y-1)²=100/100
(1/25)(x-1)²-(1/4)(y-1)²=1
[(x-1)²]/25-[(y-1)²]/4=1
the answer is
[(x-1)²]/25-[(y-1)²]/4=1
a. The figure at the right shows a long rectangular strip of paper, one corner of which has been folded over to meet the opposite edge, thereby creating a 30-degree angle. Given the width of the strip is 12 inches, find the length of the crease.
b. Instead of a 30-degree angle, suppose that the angle has an unspecified size t. Use trigonometry to find the length of the crease, expressed in terms of t.
c. Find the approximate value of t that makes the crease as short as it can be. Restrict your attention to values of t that are less than 45 degrees. Explain your method.
Answers
m∠CDF = m∠CAE = 2t
Putting these relationships together, we have
.. DF/CD = cos(2t) = (12-x*sin(t))/(x*sin(t))
Solving for x, we get
.. x*sin(t)*cos(2t) = 12 -x*sin(t)
.. x*sin(t)*(1 +cos(2t)) = 12
.. x = 12/(sin(t)*(1 +cos(2t))
.. x = 6/(sin(t)*cos(t)^2)
For t = 30°, x = 6/(3/8) = 16
For a 30° angle, the length of the crease in 16 inches.
B. From above,
.. crease length = (6 inches)/(sin(t)*cos(t)^2)
C. Using a graphing calculator, we can find the angle that makes the crease length a minimum. See the second figure. It is about 35.264°.
___
An exact solution using derivatives gives arcsin(1/√3) ≈ 35.264390°.
Describe how to transform -------- into an expression with a rational exponent.
(a index of 3, square root of x^4) raised to the 5th power
Answers
Solution:
Simplify. ( cube root of x to the power of 4 )from the given :(a index of 3, square root of x^4) raised to the 5th power.
=x to the power of 4/3
multiply it by five will give you the answer of x to the power of 20/3
A convex, 11 sided polygon can have at most how many obtuse interior angles?
Answers
Answer:
11
Step-by-step explanation:
How many positive integers less than 1000 are divisible by exactly one of 7 and 11?
Answers
= 220
hope i helped :)
How do you solve this?
Answers
You know a > 0, so the parabola will open up.
If the parabola opens up, the vertex is a minimum.
Use the formula for the axis of symmetry.
.. x = -b/(2a) = -5/(2*2) = -5/4
.. f(-5/4) = 2(-5/4)^2 +5(-5/4) +3 = -1/8
The vertex is (-5/4, -1/8).
Use the formula for the discriminant.
.. b^2 -4ac = 5^2 -4*2*3 = 25 -24 = 1
This is positive and a perfect square, so there are 2 real roots. They are (1) rational and unequal.
Use the quadratic formula to tell you the roots.
.. x = -b/(2a) ±(√discriminant)/(2a)
.. = -5/4 ±√1/(2*2)
.. = -5/4 ±1/4
.. = {-3/2, -1}
Simplify the expression square root -1/(3+8i)-(2+5i)
a. 3+i/10.
b.-3+i.
c.3-I/10.
d.-3-i/10
Answers
.. -1/((3 +8i) -(2 +5i)) = (-1 +3i)/10