PLS HELP! 20 PTS
Use rounding to determine if the answer is reasonable. Round each of the factors to the nearest ten, then multiply. 587 × 92 = 54,004

Answer:

This proof involves the definitions of congruence and supplementary angles, as well as some of the properties of equality.

∠1 and ∠2 are supplementary    // given

∠3 and ∠4 are supplementary    // given

∠1 ≅ ∠3    // given

m∠1 + m∠2 = 180°    // definition of supplementary angles

m∠3 + m∠4 = 180°    // definition of supplementary angles

m∠1 + m∠2 = m∠3 + m∠4    // transitive property of equality

m∠1 = m∠3    // definition of congruent angles

m∠1 + m∠2 = m∠1 + m∠4    // substitution property of equality (replaced m∠3 with m∠1)

m∠2 = m∠4    // subtraction property of equality (subtracted m∠1 from both sides)

∠2 ≅ ∠4    // definition of congruent angles

hope this helps

Step-by-step explanation:

Answer:

For the future students who need answer to this problem ....

Step-by-step explanation:

5. given

7.  Transitive property of equality

8.  Substitution Property

9.  Subtraction Property of Equality

10.  Converse of Angles Congruent Postulate

I am writing this test now and these are the answers I put in. It hasn't been graded yet but I'm pretty sure that they are correct. But pls lmk if anything is wrong. HOPE THIS HELPS

PLEASE RATE AND CLICK ON THANKS IF THIS WAS HELPFUL :))))

For this case, we have the following generic expression:

[tex]a + b = c\\[/tex]

The commutative property of the addition states that the order of the addends does not alter the sum, therefore the previous expression above can be written as:

[tex]b + a = c\\[/tex]

Thus the expression[tex]8 + 7 = 15[/tex], applying the commutative property, can be written as:

[tex]7 + 8 = 15\\[/tex]

Answer:

Option c

f(x):  y = 9x² - 12

f⁻¹(x):  x = 9y² - 12

    x + 12 = 9y²

     [tex]\frac{x+12}{9} = y^{2}[/tex]  

     [tex]\sqrt{\frac{x+12}{9}} = |y|[/tex]     ; x ≥ -12

     [tex]+/-\sqrt{\frac{x+12}{9}} = y[/tex]

Answer: C

3x + 32 + x + 48 = 180

4x + 80 = 180

4x = 100

x = 25

Angles

x + 48 = 25 + 48 = 73

3x + 32 = 3(25) + 32 = 75 + 32 = 107

Larger angle = 107

Answer

C) x = 25, 107 degrees

answer is (2,1)

y = 6x – 11

-2x – 3y = -7

Substitute 6x - 11 for y in the second equation

-2x – 3(6x-11) = -7

-2x – 18x +33 = -7

-20x + 33 = -7

Now subtract 33 on both sides

-20x   = -7 - 33

-20x = -40 ( divide by -20 on both sides)

x= 2

We know y = 6x -11

Plug in 2 for x  and find out y

y = 6(2) -11= 12 -11 = 1

So answer is (2,1)

OK

I'll take a hypothetical case. Suppose one of the ordered pairs = (1, 6)  which means 'x = 1 when y = 6)'

we substitute  x = 1 and y = 6 into the equation and see if the left side = right side

left: y = 6

right: -9x + 4 = -9(1) + 4 = -9 + 4 = -5

Therefore this ordered pair is NOT a solution to the equation.

Answer: Hello mate!

we have the equation y = –9x + 4 and we want to find ordered a pair that is a solution of the equation.  Where a pair has the form (x, y)

First, you need to know that there are infinite ordered pairs that are a solution of this equation, if you want to find them, you need to replace the value of x (or the value of y) with a number, and solve the equation:

suppose x = 1

then y = -9*1 + 4 = -9 + 4 = 5

then the pair (1,5) is a solution of the equation.

The general form of the pairs is (x,y), then the pairs that are a solution for this equation are the pairs of the form (x, y(x)) = (x, -9x + 4)

Answer:

2x60, 4x30

Step-by-step explanation:

Given that the glee club has 120 cupcakes to sell.

These 120 cupcakes are to be arranged in a rectangle shape such that

there are even number of cakes lengthwise and even number of cakes breadthwise.

If l is the number of cakes along row, and m is the number of cakes along column, then we have both l and m as even.

Also lm=120

In other words, we must find 2 even  factors of 120 l and m such that lm = 120

2x60 is one such pair

Next is 4x30.

There cannot be any other pair satisfying this condition.

Hence answer is 2x60 or 4x30

Your answer should be D. 3

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

[tex]Speed=\frac{distance}{time}[/tex]

in this problem we have

[tex]distance=400\ m \\time=120\ sec[/tex]

substitute in the formula

[tex]Speed=\frac{400}{120}[/tex]

[tex]Speed=3.5\frac{m}{sec}[/tex]

therefore

the answer Part a) is

the speed is equal to [tex]3.5\frac{m}{sec}[/tex]

Part b) Find the velocity

we know that

Velocity is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

[tex]magnitude=3.5\frac{m}{sec}[/tex]

[tex]direction=North\ East\ (NE)[/tex]

therefore

the answer Part b) is

the velocity is [tex]3.5\frac{m}{sec}\ North\ East\ (NE)[/tex]

Part c)

we know that

the acceleration is equal to the formula

[tex]a=\frac{V2-V1}{t2-t1}[/tex]

in this problem we have

[tex]V2=0 \\V1=3.5\frac{m}{sec}[/tex]

[tex]t2=15\ sec\\t1=0[/tex]

substitute in the formula

[tex]a=\frac{0-3.5}{15-0}[/tex]

[tex]a=-\frac{3.5}{15}\frac{m}{sec^{2}}[/tex]

[tex]a=-\frac{7}{30}\frac{m}{sec^{2}}[/tex]

therefore

the answer Part c) is

the acceleration is [tex]-\frac{7}{30}\frac{m}{sec^{2}}[/tex]

This is an example of negative acceleration

Step-by-step explanation:

1. It is given that,

Distance covered by the cyclist, d = 400 m

Time taken, t = 120 s

Speed = distance / time taken

[tex]v=\dfrac{400\ m}{120\ s}[/tex]

v = 3.33 m/s

So, the speed of the cyclist is 3.33 m/s.

2. The cyclist comes to a stop position within 15 seconds. Its acceleration is given by :

[tex]a=\dfrac{v-u}{t}[/tex]

[tex]a=\dfrac{0-3.33\ m/s}{15\ s}[/tex]  

[tex]a=-0.22\ m/s^2[/tex]

So, the acceleration of the cyclist is [tex]-0.22\ m/s^2[/tex]. It is an example of negative acceleration as the cyclist is decelerating. Hence, this is the required solution.              

ANSWER

When [tex]f(x)=x^2-10x+9[/tex] is written in the form [tex]f(x)=a(x-h)^2+k[/tex], it looks like [tex]f(x)=(x-5)^2-16[/tex]

EXPLANATION

To write  [tex]f(x)=x^2-10x+9[/tex] in the form [tex]f(x)=a(x-h)^2+k[/tex], we have to complete the squares.

We add and subtract half the coefficient of [tex]x[/tex] square.

[tex]f(x)=x^2-10x+(-5)^2-(-5)^2+9[/tex]

The first three terms of the function is now a perfect square.

[tex]f(x)=(x-5)^2-25+9[/tex]

We now simplify rto obtain,

[tex]\Rightarrow f(x)=(x-5)^2-16[/tex]

Answer: Option C. Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)

Solution:

Conditional relative frequency single employees in grade 2:

[(Single employees in job grade 2)/(Total employees in job grade 2)]*100%=

(222/4,239)*100%=0.052370842*100%=5.2370842% approximately 5.2%

Conditional relative frequency married employees in grade 2:

[(Married employees in job grade 2)/(Total employees in job grade 2)]*100%=

(3,927/4,239)*100%=0.926397735*100%=92.6397735% approximately 92.6%

92.6%>5.2%:

Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)

Answer:

c

Step-by-step explanation:

The Answer Is A. above me is the example.

If relationship is an inverse variation then the product of x and y is constant.

A)

2 · 6 = 12

3 · 9 = 27

NOT

B)

1 · 6 = 6

2 · 3 = 6

3 · 2 = 6

6 · 1 = 6

YES

C)

0 · 0 = 0

2 · 8 = 16

NOT

D)

-3 · 4 = -12

-4 · (-3) = 12

NOT

The inequality:

[tex]0.19x+75\geq100\qquad|-75\\\\0.19x\geq25\qquad|:0.19\\\\x\geq\dfrac{25}{0.19}\approx132[/tex]

C. The answer is C because the total amount of students is 14, and there are 4 boys, which makes the ratio 4 boys to 14 students in total. 4 and 14 are both divisable by 2, so divide 4 to get 2 and divide 14 to get 7. This leaves you with 2 and 7. The ratio would be 2 boys to 7 total students. Hope this helped

Answer:2:5

[tex]4 divided by two = 2 10/2=5[/tex]

To find the y-intercept you first need to set everything equal to y and that will put everything in the y=mx+b line equation. Where m is the slope and b is the y intercept

x+3y = 14           subtract x over

3y = -x+14         divide by 3

y = -1/3x +14

So 14 is the y-intercept of the equation

he could save $645 a year so he could save up

The workers make 751 toys per day

They work for 5 days per week

Number of toys made in one week is;

751 × 5 = 3755 toys

Number of toys made in 3 weeks is;

3755 × 3 = 11,265 toys

Remark

You need a split statement like C or D. A and B would have to be considered if the ages were between 12 and 60.  However the discounts apply the other way. Up to 12 and over 60. You need two inequalities to describe this.

Under 12

x ≤ 12

The pointy end of the arrow points toward the x. x must be less than or at most equal to 12. The pointy end of the inequality must be directed towards the smaller number.

Over 60

x ≥  60

This time the pointy end is directed towards the 60. x must be at least 60 and then upwards.

So C is the correct answer.

Answer:

answer in c pls give brainlist

Step-by-step explanation:

The equation of a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

(h, k) - center

r - radius

We have:

[tex](x-2)^2+(y+3)^2=16\\\\(x-2)^2+(y-(-3))^2=4^2[tex]

Therefore:

[tex]h=2,\ k=-3\to\text{center:}\ (2,\ -3)\ \text{and}\ r=4[/tex]

The graph matches the circle defined by this equation (x-2)^2 + (y+ 3)^2 = 16 is option D.

If a circle O has radius of r units length and that it has got its center positioned at (h, k) point of the coordinate plane,

then its equation is given as:

[tex](x-h)^2 + (y-k)^2 = r^2[/tex]

The given equation of the circle is;

[tex](x-2)^2 + (y+ 3)^2 = 16[/tex]

Where, (h, k) - center

r - radius

here the radius of the circle is 4.

So, the graph matches the circle defined by this equation (x-2)^2 + (y+ 3)^2 = 16 is option D.

Learn more about equation of a circle here:

https://brainly.com/question/10165274

#SPJ2

Answer:

400,000

Step-by-step explanation:

29, 30, 31

consecutive integers have a difference of 1 between them

let the 3 integers be n, n + 1, n + 2

then n + n + 2 = 60

2n  + 2 = 60 ( subtract 2 from both sides )

2n = 58 ( divide both sides by 2 )

n = 29 ← least integer

thus the 3 integers are 29, 30, 31

I believe the answer is $8.76!

The linear equation that represents the arithmetic sequence is[tex]a_n=10-2(n-1)[/tex]

Writing arithmetic sequence as a function of linear equations.

Arithmetic sequence is a progressive set of numbers with a common difference between each term. On the other hand a linear equation y =mx + b where m= slope and b = y-intercept.

In the given question, we have the arithmetic sequence;

10, 8, 6, 4 ...

Here the arithmetic sequence, the common difference is -2. So the common difference relates to the slope of the linear equation.

The first term is 10, the common difference is - 2. Using the general formula for arithmetic sequence, we have:

[tex]a_n=10-2(n-1)[/tex]

The problem requires mathematical analysis to find the time intervals during which the outside temperature, represented by a function of time, exceeds the AC's set point, thus determining when the AC was actively cooling the castle.

The question presented to Princess Poly and Prince Digit by Wizard N. Gineer involves a mathematical analysis of an air conditioning (AC) system's performance based on outside temperature fluctuations over time. The outside temperature function provided by Mr. N. Gineer is f(t) = 24 - 5cos(rac{
pi}{12}t), where t is the number of hours past midnight. To determine when the AC was actively cooling the castle, one would need to identify the time intervals during which the temperature exceeded the set point at which the AC is triggered to cool. These intervals will be when the function values are above the temperature set point for the AC to start.

For example, if the AC is set to cool the castle at any temperature above 24 degrees Celsius, the solution would involve finding the values of t for which the function exceeds this limit. This involves solving inequalities and possibly using trigonometric identities and properties to find the appropriate time intervals. However, without the exact temperature set point at which the AC starts, we cannot solve for the specific hours during which the AC would be actively cooling.

[tex]f(x)=\left\{\begin{array}{ccc}2-x&if&x\leq-5\\x+11&if&x > -5\end{array}\right\\\\-5\leq-5\ \text{therefore for}\ x=-5,\ f(x)=2-x\\\\f(-5)=2-(-5)=2+5=7[/tex]

[tex]\frac{375}{14}=\frac{x}{16}:x=\frac{3000}{7}(Decimal: x=428.57143...)[/tex]