Plzzz helppp me!!!!!!!!!!!!!

It's A. if a = b, then a^2 = b^2

Answer:

C) (x – 2)(x + 2)(x² + 4)(x⁴ + 16)

Step-by-step explanation:

The difference of squares is factored like this:

... a² - b² = (a - b)(a + b)

The given expression is the difference of squares:

... (x⁴)² - (2⁴)²

so can be factored as ...

... (x⁴ - 2⁴)(x⁴ + 2⁴) . . . . . . . 2⁴=16

Once again, the difference term is the difference of squares, so it can be factored as ...

...  x⁴ - 2⁴ = (x² -2²)(x² + 2²) . . . . . . 2²=4

And the difference in the first factor is also the difference of squares and can be factored.

... x² -2² = (x - 2)(x + 2)

Putting each factorization in its place in the whole expression, we get

... x⁸ - 256 = (x - 2)(x + 2)(x² +4)(x⁴ +16)

i think that it is 1/6

Answer:

But why is it 1/6? Why don't you divide?

Step-by-step explanation:

Answer:

Corresponding angle theorem, vertical angle theorem, and the transitive property of congruence.

Step-by-step explanation:

Considering a set of parallel lines cut by a transversal. (Refer the attached image).

Now that lines J and K are parallel, then by "corresponding angle theorem"

[tex]\angle 1=\angle 5[/tex]

By "vertical angle theorem"

[tex]\angle 5 = \angle 7[/tex]

Using, "transitive property of congruence"

[tex]\angle 1 = \angle 7[/tex]

And that is our required proof. In this whole proof we have used "corresponding angle theorem", "vertical angle theorem", and the "transitive property of congruence".

Angles between a transversal line and parallel lines are congruent based on vertical angle theorem, corresponding angles and transitive property.

I will use the attached figure to explain the congruence of the angles.

Corresponding Angles Theorem

From the attached figure, the following angles are congruent based on corresponding angle theorem

[tex]\angle 2 = \angle 6[/tex]            

[tex]\angle 1 = \angle 5[/tex]

[tex]\angle 4 = \angle 8[/tex]

[tex]\angle 3 = \angle 7[/tex]

Vertical Angle Theorem

From the attached figure, the following angles are congruent based on vertical angle theorems

[tex]\angle 2 = \angle 3[/tex]            

[tex]\angle 1 = \angle 4[/tex]

[tex]\angle 5 = \angle 8[/tex]

[tex]\angle 6 = \angle 7[/tex]

Transitive Property

From the attached figure, the following angles are congruent based on transitive property

[tex]\angle 1 = \angle 7[/tex]

[tex]\angle 4 = \angle 6[/tex]

[tex]\angle 5 = \angle 3[/tex]            

[tex]\angle 2 = \angle 8[/tex]

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I believe 0.75/ 8=0.09375 so 0.09375 is the answer i hope i helped

The percent increase to earned money will be 9.375%.

What is Percentage?

A relative value indicating hundredth part of any quantity is called percentage.

Given that;

An employee was hired at a wage of $8 per hour.

After a raise, the employee earned $8.75 per hour.

Now, The increase percent will be calculate as;

Increase percent in money = Increase money/Actual money x 100

                                          = (8.75 - 8.00) / 8 x 100

                                          = (0.75/8) x 100

                                          = 75/8

                                          = 9.375

Thus, The percent increase to earned money will be 9.375%.

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Answer:

6

Step-by-step explanation:

The area of a polygon created with a scale factor of xxx is x^2x  

2

x, start superscript, 2, end superscript times larger than the original polygon:

\text{scale factor}^2=\text{how many times larger area of scale copy is}scale factor  

2

=how many times larger area of scale copy iss, c, a, l, e, space, f, a, c, t, o, r, start superscript, 2, end superscript, equals, h, o, w, space, m, a, n, y, space, t, i, m, e, s, space, l, a, r, g, e, r, space, a, r, e, a, space, o, f, space, s, c, a, l, e, space, c, o, p, y, space, i, s

The area of Rectangle RRR is 363636 times greater than the area of Rectangle QQQ. Let's substitute 363636 into the equation to find the scale factor.

?^2=36?  

2

=36question mark, start superscript, 2, end superscript, equals, 36

The scale factor is 666.

Hint #33 / 3

Thea used a scale factor of 666 to go from Rectangle QQQ to Rectangle RRR.

Answer:

6

Step-by-step explanation:

The area of a polygon created with a scale factor of xxx is x^2x  

2

x, start superscript, 2, end superscript times larger than the original polygon:

\text{scale factor}^2=\text{how many times larger area of scale copy is}scale factor  

2

The area of Rectangle RRR is 363636 times greater than the area of Rectangle QQQ. Let's substitute 363636 into the equation to find the scale factor.

?^2=36?  

2

=36question mark, start superscript, 2, end superscript, equals, 36

The scale factor is 666.

Hint #33 / 3

Thea used a scale factor of 6 to go from Rectangle Q to Rectangle R.

A slope is also known as the gradient of a line. The slope of the line is positive and is equal to 0.2.

A slope also known as the gradient of a line is a number that helps to know both the direction and the steepness of the line.

Since the line is passing through the origin and (5,1). The slope of the line is,

m = (1-0)/(5-0) = 1/5 = 0.2

Hence, the slope of the line is positive and is equal to 0.2.

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Answer:

D.) Neither A or B

Step-by-step explanation:

A.) Substituting X=2 and y=4 results to 9=10 which is a false statement

B.) Substituting X=3 and y=6 results to 16=18 Which is a false statement

C.) Look at A and B they lead to a false statement so It can't be both

The answer of the ordered pair is a solution of the equation 7x−5=4y−6 would be option D. neither A or B.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given equation;

7x - 5 = 4y -6 ...…...... (1)

Substitute x = 2 and y = 4 in equation (1)

7(2) -5 = 4(4) -6

9 ≠ 10

a) (2,4) is not satisfied

Now, Substitute x = 3 and y= 6 in equation (1)

7(3) -5 = 4(6) -6

 16 ≠ 18

b) Thus, (3,6) is not satisfied

c)  both A and B is also not satisfied

Hence, the answer would be option D. neither A or B.

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be smart be funny be kind smell good watch tv do homework

r = [tex]\sqrt[3]{\frac{3V}{4\pi } }[/tex

given [\frac{4}{3}[/tex]πr³ = V ( multiply both sides by 3 to eliminate fraction )

4πr³ = 3V ( divide both sides by 4π )

r³ = [tex]\frac{3V}{4\pi }[/tex] ( take the cube root of both sides )

r = [tex]\sqrt[3]{\frac{3V}{4\pi } }[/tex]

The domain is how far the graph stretches horizontally (on the x-axis).

Domain:  ( -∞ , ∞ )  or  -∞ < x < ∞

The range is how long the graph stretched vertically (on the y-axis).

Range:  ( -∞ , 2 ]  or  -∞ < y ≤ 2

The zeros are where the graph intersects with the x-axis. In other words, the x-values when y=0.

Zeros:  x = -1  and  x = 3

can you give more detail

By combining the like terms; the simplified answer in the correct way is 16x^2+6xy+6y^2

How to get answer:

- Find how many terms are in the algebraic equation. Counting I got 6 terms.

There are 2 xy's and 2 x's and 2y's

- Next combine all like terms

[tex]8x^{2} + 8x^{2} = 16x^{2}[/tex]

7xy+-xy=6xy

[tex]5y^{2} + y^{2}[/tex]=[tex]6y^{2}[/tex]

- Next Simplify

[tex]16x^{2}+6xy+6y^{2}[/tex]

I would say the answer would be B. or C.

not sure which but i hope i helped narrow it down..

Answer:

Its B

Step-by-step explanation:

Here we have a problem with tax rates and percentages, we will find that the total price will be $48.66.

So we know that the price of the skirt is $45.99, this is our 100%.

So, when we know that a tax of 5.8% is applied, is over that 100%, meaning that the total price will be 105.8% of the original price.

Then we can write the equations.

105.8% = x

100% = $45.99

Taking the quotient of these two equations and solving for x we get:

(105.8%/100%)*$45.99 = x = $48.66

So the total price of the skirt is $48.66.

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A total of 812 tickets were sold for the school play. 375 adult tickets were sold.

Let's assume the number of adult tickets sold is "A" and the number of student tickets sold is "S."

We are given two pieces of information:

The total number of tickets sold is 812:

A + S = 812

There were 62 more student tickets sold than adult tickets:

S = A + 62

Now, we can set up a system of equations to represent the given information:

A + S = 812

S = A + 62

Now, we can solve the system of equations to find the values of A and S.

Substitute equation (2) into equation (1):

A + (A + 62) = 812

Combine like terms:

2A + 62 = 812

Subtract 62 from both sides:

2A = 812 - 62

2A = 750

Now, divide by 2 to solve for A:

A = 750 / 2

A = 375

So, 375 adult tickets were sold.

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Final answer:

375 adult tickets were sold.

Explanation:

Let's denote the number of adult tickets sold as x. According to the information provided, there were 62 more student tickets sold than adult tickets. So, the number of student tickets sold can be represented as x + 62.

Since a total of 812 tickets were sold, we can write the equation x + (x + 62) = 812. This equation represents the sum of adult tickets and student tickets being equal to the total tickets sold.

Solving this equation, we have 2x + 62 = 812. Subtracting 62 from both sides, we get 2x = 750. Then, dividing both sides by 2, we find that x = 375. Therefore, 375 adult tickets were sold.

I do not know what diagram that you are talking about, but it might be the one that I am thinking, so if this is the questions on your page, then let me know.

A - Vertex angles

B - 5 is congruent to 4

C - 5 and 4 are alternate interior angles, or Z angles

P and R are parrallel.

Hope I helped.

As per given information: m∠5 = 40° and m∠2 = 140°. It then uses the theorems that supplementary angles are congruent and that if two same-side interior angles are congruent, then the lines are parallel, to conclude that a || b.

The proof begins with the givens: m∠5 = 40° and m∠2 = 140°. From this, we can conclude that ∠5 and ∠2 are supplementary angles (since their measures add up to 180°).

We also know that ∠5 and ∠2 are same-side interior angles (since they are both on the same side of the transversal and inside the two lines).

Now, we can use the following theorems to complete the proof:

Theorem 1: Supplementary angles are congruent.

Theorem 2: If two same-side interior angles are congruent, then the lines are parallel.

Proof:

Given: m∠5 = 40° and m∠2 = 140°

∠5 and ∠2 are supplementary angles. (Theorem 1)

∠5 and ∠2 are same-side interior angles.

If two same-side interior angles are congruent, then the lines are parallel. (Theorem 2)

Therefore, a || b.

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For this case we have:

Part A:

Point 1: [tex](x1, y1) = (6,10)\\[/tex]

Point 2:[tex](x2, y2) = (4, -2)\\[/tex]

We know that the slope m is given by:

[tex]m = \frac{(y2-y1)}{(x2-x1)}\\\\m = \frac{(- 2-10)}{(4-6)}\\\\m = \frac{(- 12)}{(- 2)}\\[/tex]

[tex]m = 6\\[/tex]

The slope is [tex]m = 6\\[/tex]

Part b:

The equation of the line in point-slope form is given by:

[tex](y-y1) = m (x-x1)\\[/tex]

Substituting the point 1 [tex](x1, y1) = (6,10)[/tex]we have:

[tex](y-10) = 6 (x-6)\\[/tex]

Thus, the point-slope equation is: [tex](y-10) = 6 (x-6)\\[/tex]

Part c:

The equation of the line in slope-intersection form is given by:

[tex]y = mx + b\\[/tex]

Rewriting the equation of part b we have:

[tex]y = 6 (x-6) +10\\\\y = 6x-36 + 10\\\\y = 6x-26\\[/tex]

Thus, the equation of the line in slope-intersection form is

[tex]y = 6x-26\\[/tex]

Answer:

[tex]m = 6\\\\(y-10) = 6 (x-6)\\\\y = 6x-26[/tex]

The answer is 293 meters because you multiply the 14650 books by how thick they are which is 0.02, and that should reveal your answer. Hope this helps!

Solution :

Given a soda can has a diameter of 6 cm.

As we know,  the circumference of circle with radius r is , [tex]C=2\pi r[/tex].

And diameter of  the circle [tex]D = 2r[/tex]

So, the circumference of the circle with diameter D is ,  [tex]C=\pi D[/tex]

Put D= 6

[tex]\Rightarrow C=6 \pi\\\\Using\: \pi=3.14\\\Rightarrow C=6\times3.14\\\\\Rightarrow C=18.84[/tex]

Hence, the circumference of the can is 18.84 cm. (option C)

$504 + $580= $1084 is how much the bus company got in all.

Answer:

$1,084

Step-by-step explanation:

Multiply 36 by $14 and you get 504.

Then multiply 20 by $29 an you will get 580.

In order to figure out how much money they collected in total, you should add your two answers together, which will then be 1,084. The bus company collected $1,084

Answer:

3 inches/hour

Step-by-step explanation:

During one winter snow storm in Denver Colorado Jesse noted that 16 inches of snow fell in [tex]5\frac{1}{3}[/tex] hours = [tex]\frac{16}{3}[/tex] hours

the snow fell in [tex]\frac{16}{3}[/tex] hours = 16 inches

snow fell in 1 hour = [tex]\frac{16}{\frac{16}{3}}[/tex]

                              = [tex]\frac{16\times 3}{16}[/tex]

                              = [tex]\frac{48}{16}[/tex]

                              = 3 inches

The rate of snowfall would be 3 inches/hour.

104 and 105 are consecutive numbers that add up to 209. Maybe this answers your question? Let me know otherwise.

Given : Invested amount = $5000.

Rate of interet = r% compunded monthly.

Number of years = 4 years.

Total interest received = $1866.

Therefore, total amount after 4 years = 5000+1866 = $6866.

We know, formula for compound interest :

[tex]A=P(1+\frac{r}{n})^{t\times n}[/tex], where P is the invested amount, n is the number of monthly installments in an year.

Number of months in an year are 12.

Plugging n=12, P=5000, t=4 in the formula now, we get

[tex]6866=5000{(1+\frac{r}{12})^{12\times 4}[/tex]

[tex]6866=5000{(1+\frac{r}{12})^{48}[/tex]

Dividing both sides by 5000, we get

[tex]\frac{6866}{5000} =\frac{5000}{5000} {(1+\frac{r}{12})^{48}[/tex]

[tex]\frac{6866}{5000} = {(1+\frac{r}{12})^{48}[/tex]

[tex]1.3732= {(1+\frac{r}{12})^{48}[/tex]

Taking 48th root on both sides, we get

[tex]\sqrt[48]{1.3732} = \sqrt[48]{(1+\frac{r}{12})^{48}}[/tex]

[tex]\sqrt[48]{1.3732}=\left(1+\frac{r}{12}\right)[/tex]

[tex]1.00662903758=1+\frac{r}{12}[/tex]

Subtracting 1 from both sides, we get

0.00662903758 = [tex]\frac{r}{12}[/tex]

Multiplying by 12 on both sides, we get

r=0.07954845101

r≈0.0795

Or 7.95%.

Now, we need to find the interest after four years if the rate of interest is 3.6% compounded quarterly.

There are 4 quarters in an year.

So, n=4 and r=3.6%= 0.036.

Plugging values in compound interest formula now, we get

[tex]A=5000{(1+\frac{0.036}{4})^{4\times 4}[/tex]

[tex]\mathrm{Divide\:the\:numbers:}\:\frac{0.036}{4}=0.009[/tex]

[tex]A=5000\times \:1.009^{16}[/tex]

[tex]A=5000\times \:1.15414\dots[/tex]

[tex]=5770.70222\dots[/tex]

A≈5770.70

Subtracting 5770.70 -5000.00 = 770.70.

(A)

We are given

Mr tan invested 5000 Swiss francs(CHf) bank

so,

[tex]P=5000[/tex]

nominal annual interest rate of r% compounded monthly

so, n=12

t=4

total interest he received was 1866 CHF

I=1866

we can use formula

[tex]I=P(1+\frac{r}{n} )^{nt}-P[/tex]

now, we can plug values

[tex]1866=5000(1+\frac{r}{12} )^{12*4}-5000[/tex]

now, we can solve for r

[tex]r=0.0795[/tex]

so, interest rate is 7.95%..........Answer

(B)

we are given

P=5000

r=0.036

n=4

t=4

so, we can use interest formula

[tex]I=P(1+\frac{r}{n} )^{nt}-P[/tex]

now, we can plug values

[tex]I=5000(1+\frac{0.036}{4} )^{4*4}-5000[/tex]

now, we can simplify it

and we get

[tex]I=770.702[/tex]

The total interest is 771 CHF...........Answer