probability of drawing two number cards from a standard deck (without replacement)

Answer:  The list price was $1815.00.  

Step-by-step explanation:  Given that the discount on a LCD TV is $240 and the sale price is $1575.00.

We are to find the list price.

The discount is given on the price that is listen on the LCD TV.

So, the list price will be equal to the sum of the sale price and the discount price.

Therefore, the required list price of the LCD TV is given by

[tex]L.P.\\\\=\textup{sale price}+\textup{discount}\\\\=\$(1575.00+240.00)\\\\=\$1815.00.[/tex]

Thus, the list price was $1815.00.  

Answer:

0.0358

Step-by-step explanation:

In a 52 deck, 13 cards are Clubs, and 26 cards are red.

There are ₁₃C₃ ways to choose 3 Clubs from 13.

There are ₂₆C₂ ways to choose 2 red cards from 26.

There are ₅₂C₅ ways to choose 5 cards from 52.

P = (₁₃C₃ ₂₆C₂) / ₅₂C₅

P = (286 × 325) / 2598960

P = 0.0358

Answer:

radius 5

center (0,-2)

Step-by-step explanation:

The goal is to get to [tex](x-h)^2+(y-k)^2=r^2 \text{ where } (h,k) \text{ is the center and } r \text{ is the radius }[/tex].

We will need to complete the square for both parts.

That is we need to use:

[tex]u^2+bu+(\frac{b}{2})^2=(u+\frac{b}{2})^2[/tex].

First step is group the x's and y's together and put the constant on the opposing side.  The x's and y's are already together.  So we need to add 21 on both sides:

[tex]x^2+y^2+4y=21[/tex]

Now the x part is already done.

If you compare y^2+4y to [tex]u^2+bu+(\frac{b}{2})^2=(u+\frac{b}{2})^2[/tex]

on the left side we have b is 4 so we need to add (4/2)^2 on both sides of [tex]x^2+y^2+4y=21[/tex].

[tex]x^2+y^2+4y+(\frac{4}{2})^2=21+(\frac{4}{2})^2[/tex]

Now we can write the y part as something squared still using my completing the square formula:

[tex]x^2+(y+\frac{4}{2})^2=21+2^2[/tex]

[tex]x^2+(y+2)^2=21+4[/tex]

[tex](x-0)^2+(y+2)^2=25[/tex]

The center is (0,-2) and radius is [tex]\sqrt{25}=5[/tex]

The answer is:

Center: (0,-2)

Radius: 2.5 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

[tex]x^2+y^2+4y-21=0[/tex]

So, solving we have:

[tex]x^2+y^2+4y=21[/tex]

[tex]x^2+(y^2+4y+(\frac{4}{2})^{2})=21+(\frac{4}{2})^{2}\\\\x^2+(y^2+4y+4)=21+4\\\\x^2+(y^2+2)=25[/tex]

[tex]x^2+(y^2-(-2))=25[/tex]

Now, we have that:

[tex]h=0\\k=-2\\r=\sqrt{25}=5[/tex]

So,

Center: (0,-2)

Radius: 5 units.

Have a nice day!

Note: I have attached a picture for better understanding.

Answer: [tex]-3\dfrac{1}{2}[/tex].

Step-by-step explanation:

We know that the slope of a line passing through points (a,b) and (c,d) is given by :_

[tex]m=\dfrac{d-b}{c-a}[/tex]

The given points : (-4,3) and (-2, -4)

Now, the slope of the line passing through points (-4,3) and (-2, -4) is given by :-

[tex]m=\dfrac{-4-3}{-2-(-4)}\\\\\Rightarrow\ m=\dfrac{-7}{-2+4}\\\\\Rightarrow\ m=\dfrac{-7}{2}=-3\dfrac{1}{2}[/tex]

The slope of a line passing through points (-4,3) and (-2, -4) is [tex]-3\dfrac{1}{2}[/tex].

Answer:

The coefficient is 15120.  

Step-by-step explanation:

Since, by the binomial expansion formula,

[tex](x+y)^n=\sum_{r=0}^n^nC_r x^{n-r} y^r[/tex]

Where, [tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex]

Thus, we can write,

[tex](3x+2y)^7 = \sum_{r=0}^n ^7C_r (3x)^{7-r} (2y)^r[/tex]

For finding the coefficient of [tex]x^3y^4[/tex],

r = 4,

So, the term that contains [tex]x^3y^4[/tex] = [tex]^7C_4 (3x)^3 (2y)^4[/tex]

[tex]=35 (27x^3) (16y^4)[/tex]

[tex]=15120 x^3 y^4[/tex]

Hence, the coefficient of [tex]x^3y^4[/tex] is 15120.

Answer:[tex][/tex]

Coefficient of  [tex]x^3y^4[/tex] in [tex](3x+2y)^7[/tex] is 15120

Step-by-step explanation:

We know that [tex](x+y)^{n}[/tex]) can be expanded in (n+1) terms by using binomial theorem and each term is given as

[tex]n_C_{r}x^{n-r}y^{r}[/tex]

Here value of r is taken from n to 0

we have to determine the coefficient of [tex]x^3y^4[/tex] in [tex](3x+2y)^7[/tex]

in this problem we have given n=7

We have to determine the coefficient of [tex]x^3y^4[/tex]

it means in the expansion we have to find the the 3rd power of x and therefore

r=n-3

here n=7

therefore, r=7-3=4

Hence the coefficient of [tex]x^3y^4[/tex]  can be determine by using formula

[tex]n_C_{r}x^{n-r}y^{r}[/tex]

here n=7, r=4

[tex]7_C_{4}x^{7-4}y^{4}[/tex]

=[tex]\frac{7\times 6\times 5\times 4}{1\times 2\times 3\times 4} (3x)^3(2y)^4[/tex]

=[tex]15120x^3y^4[/tex]

Therefore the coefficient of  [tex]x^3y^4[/tex] in [tex](3x+2y)^7[/tex] is 15120

The price of the house = $ 100000

The down payment is 20 % of 100000 means [tex]0.20\times100000=20000[/tex] dollars

So, loan amount will be = [tex]100000-20000=80000[/tex] dollars

Case A:

30-year mortgage at a rate of 7 %

p = 80000

r = [tex]7/12/100=0.005833[/tex]

n = [tex]30\times12=360[/tex]

EMI formula is :

[tex]\frac{p\times r\times(1+r)^n}{(1+r)^n-1}[/tex]

Putting the values in formula we get;

[tex]\frac{80000\times0.005833\times(1+0.005833)^360}{(1+0.005833)^360-1}[/tex]

= [tex]\frac{80000\times0.005833\times(1.005833)^360}{(1.005833)^360-1}[/tex]

Monthly payment = $532.22

So, total amount paid in 30 years will be = [tex]532.22\times360=191599.20[/tex]

Interest paid will be = [tex]191599.20-100000=91599.20[/tex] dollars

Case B:

15-year mortgage at a rate of 7 %.

Here everything will be same as above. Only n will change.

n = [tex]15\times12=180[/tex]

Putting the values in formula we get;

[tex]\frac{80000\times0.005833\times(1+0.005833)^180}{(1+0.005833)^180-1}[/tex]

= [tex]\frac{80000\times0.005833\times(1.005833)^180}{(1.005833)^180-1}[/tex]

Monthly payment = $719.04

Total amount paid in 15 years will be = [tex]719.04\times180=129427.20[/tex]

Interest paid will be = [tex]129427.20-100000=29427.20[/tex] dollars

To find the monthly payment and total amount of interest paid for each mortgage, use the formula A = P(1+r/12)^(12n) / (12n), where A is the monthly payment, P is the principal, r is the interest rate, and n is the number of months.

To find the monthly payment and total amount of interest paid for each mortgage option, we can use the formula for calculating the monthly mortgage payment:

A = P(1+r/12)^(12n) / (12n)

where A is the monthly payment, P is the principal (price of the house minus the down payment), r is the interest rate (expressed as a decimal), and n is the number of months in the mortgage term.

For option a) the 30-year mortgage, we have:

P = 100000 - (0.2 * 100000) = $80000

r = 0.07

n = 30 * 12 = 360

Plugging these values into the formula, we get:

A = (80000(1+(0.07/12))^(12 * 30)) / (12 * 30) = $532.09

To calculate the total amount of interest paid, we subtract the principal from the total payment over the life of the mortgage:

Total Interest Paid = (360 * 532.09) - 80000 = $93891.24

For option b) the 15-year mortgage, we have:

P = 100000 - (0.2 * 100000) = $80000

r = 0.07

n = 15 * 12 = 180

Plugging these values into the formula, we get:

A = (80000(1+(0.07/12))^(12 * 15)) / (12 * 15) = $754.56

To calculate the total amount of interest paid, we subtract the principal from the total payment over the life of the mortgage:

Total Interest Paid = (180 * 754.56) - 80000 = $75822.80

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Answer:

The results do not contradict expectations.

Step-by-step explanation:

Given that a genetic experiment with peas resulted in one sample of offspring that consisted of 447 green peas and 172 yellow peas.

Proportion of yellow peas = [tex]\frac{172}{172+447} =27.79%[/tex]

Std error = 0.25(0.75)/sq rt 619

=0.0174

Proportion difference = 0.2779-0.25=0.0279

Test statistic = 0.0279/0.0174 =1.603

p value = 0.1089

For two tailed we have p value >0.10

Hence accept null hypothesis.

The results do not contradict expectations.

Answer:

At 95% confidence level, she used 11 people to estimate the confidence interval

Step-by-step explanation:

The bounds of the confidence interval are: 740 to 920

Mean is calculated as the average of the lower and upper bounds of the confidence interval. So, for the given interval mean would be:

[tex]u=\frac{740+920}{2}=830[/tex]

Margin of error is calculated as half of the difference between the upper and lower bounds of the confidence interval. So, for given interval, Margin of Error would be:

[tex]E=\frac{920-740}{2}=90[/tex]

Another formula to calculate margin of error is:

[tex]E=z\frac{\sigma}{\sqrt{n}}[/tex]

Standard deviation is given to be 150. Value of z depends on the confidence level. Confidence Level is not mentioned in the question, but for the given scenario 95% level would be sufficient enough.

z value for this confidence level = 1.96

Using the values in above formula, we get:

[tex]90=1.96 \times \frac{150}{\sqrt{n} }\\\\ n = (\frac{1.96 \times 150}{90})^{2}\\\\ n=11[/tex]

So, at 95% confidence level her assistant used a sample of 11 people to determine the interval estimate

Final answer:

The sample size used by the assistant to determine the interval estimate is 7.

Explanation:

To determine how large a sample the assistant used to determine the interval estimate, we need to use the formula for the margin of error:

Margin of Error = Critical Value × Standard Deviation / sqrt(Sample Size)

In this case, the margin of error is half the width of the interval estimate, which is (920 - 740) / 2 = 90.

Using a z-table, the critical value for a 95% confidence level is approximately 1.96.

By substituting the given values into the formula, we can solve for the sample size:

90 = 1.96 × 150 / sqrt(Sample Size)

Simplifying the equation, we get:

sqrt(Sample Size) = 1.96 × 150 / 90

Sample Size = (1.96 × 150 / 90)^2 = 6.83

Since we cannot have a fraction of a sample, we round up to the nearest whole number.

Therefore, the assistant used a sample size of 7 to determine the interval estimate.

the answer is 17. the answer is 17

Answer:14

Step-by-step explanation:

A nickel is 5 cents (20% of dollar)

and a quarter is 25 cents (25% of dollar)

We have given a pile of 42 coins worth of $4.90

Let x be the no nickels and

y be the no of quarter

therefore

x+y=42    -----1

[tex]\frac{x}{4}[/tex]+[tex]\frac{y}{20}[/tex]=4.90 ---2

Solving [tex]\left ( 1\right )&\left ( 2\right )[/tex] we get

x=14 & y=28

Therefore no of nickels is 14 & no of quarters is 28

I'm partial to solving with generating functions. Let

[tex]T(x)=\displaystyle\sum_{n\ge0}t_nx^n[/tex]

Multiply both sides of the recurrence by [tex]x^{n+2}[/tex] and sum over all [tex]n\ge0[/tex].

[tex]\displaystyle\sum_{n\ge0}2t_{n+2}x^{n+2}=\sum_{n\ge0}3t_{n+1}x^{n+2}+\sum_{n\ge0}2t_nx^{n+2}[/tex]

Shift the indices and factor out powers of [tex]x[/tex] as needed so that each series starts at the same index and power of [tex]x[/tex].

[tex]\displaystyle2\sum_{n\ge2}2t_nx^n=3x\sum_{n\ge1}t_nx^n+2x^2\sum_{n\ge0}t_nx^n[/tex]

Now we can write each series in terms of the generating function [tex]T(x)[/tex]. Pull out the first few terms so that each series starts at the same index [tex]n=0[/tex].

[tex]2(T(x)-t_0-t_1x)=3x(T(x)-t_0)+2x^2T(x)[/tex]

Solve for [tex]T(x)[/tex]:

[tex]T(x)=\dfrac{2-3x}{2-3x-2x^2}=\dfrac{2-3x}{(2+x)(1-2x)}[/tex]

Splitting into partial fractions gives

[tex]T(x)=\dfrac85\dfrac1{2+x}+\dfrac15\dfrac1{1-2x}[/tex]

which we can write as geometric series,

[tex]T(x)=\displaystyle\frac8{10}\sum_{n\ge0}\left(-\frac x2\right)^n+\frac15\sum_{n\ge0}(2x)^n[/tex]

[tex]T(x)=\displaystyle\sum_{n\ge0}\left(\frac45\left(-\frac12\right)^n+\frac{2^n}5\right)x^n[/tex]

which tells us

[tex]\boxed{t_n=\dfrac45\left(-\dfrac12\right)^n+\dfrac{2^n}5}[/tex]

# # #

Just to illustrate another method you could consider, you can write the second recurrence in matrix form as

[tex]49y_{n+2}=-16y_n\implies y_{n+2}=-\dfrac{16}{49}y_n\implies\begin{bmatrix}y_{n+2}\\y_{n+1}\end{bmatrix}=\begin{bmatrix}0&-\frac{16}{49}\\1&0\end{bmatrix}\begin{bmatrix}y_{n+1}\\y_n\end{bmatrix}[/tex]

By substitution, you can show that

[tex]\begin{bmatrix}y_{n+2}\\y_{n+1}\end{bmatrix}=\begin{bmatrix}0&-\frac{16}{49}\\1&0\end{bmatrix}^{n+1}\begin{bmatrix}y_1\\y_0\end{bmatrix}[/tex]

or

[tex]\begin{bmatrix}y_n\\y_{n-1}\end{bmatrix}=\begin{bmatrix}0&-\frac{16}{49}\\1&0\end{bmatrix}^{n-1}\begin{bmatrix}y_1\\y_0\end{bmatrix}[/tex]

Then solving the recurrence is a matter of diagonalizing the coefficient matrix, raising to the power of [tex]n-1[/tex], then multiplying by the column vector containing the initial values. The solution itself would be the entry in the first row of the resulting matrix.

Answer:

30

Step-by-step explanation:

Follow the correct order of operations.

There are only multiplications and divisions, so do them in the order they appear from left to right.

625 ÷ 62.5 × 30 ÷ 10 =

= 10 × 30 ÷ 10

= 300 ÷ 10

= 30

Final answer:

To solve for the width of the rectangle, define the width as w, set up the equation 144 = w(w + 10), and factor the resulting quadratic equation to find w = 8 inches. Hence, the rectangle's dimensions are 8 inches in width and 18 inches in length.

Explanation:

To find the dimensions of a rectangle with an area of 144 square inches where the length is 10 inches longer than its width, we first recall the formula for the area of a rectangle:

Area = Length × Width

Let's define the width as w, and since the length is 10 inches longer, we can say the length is w + 10. Plugging these into the area formula we get:

144 = w × (w + 10)

Now, we have a quadratic equation to solve for w:

Expand the equation: 144 = w2 + 10w

Subtract 144 from both sides to set the equation to zero: w2 + 10w - 144 = 0

Factor the quadratic equation: (w + 18)(w - 8) = 0

Solve for w: w = -18 or w = 8 (since width cannot be negative, w = 8 is the solution.)

Therefore, the dimensions of the rectangle are a width of 8 inches and a length of 18 inches (8 + 10).

Answer:

  80°

Step-by-step explanation:

The sum of the two angles (red and blue) is 145°, so you have ...

  (4x +5)° +(6x -10)° = 145°

  10x = 150 . . . . . . . . divide by °, add 5, simplify

  x = 15 . . . . . . . . . . . divide by 10

Then the measure of the angle of interest is ...

  m∠XMN = (6x -10)° = (6·15 -10)° = 80°

Answer:

25%

Step-by-step explanation:

Great question, since a regular coin has two sides one heads and one tails. That gives us a 50% probability of it landing on either side of the coin. Since we would like to know the probability of getting 2 heads in a row, we would need to multiply the probability of the first toss landing on heads with the second toss landing on heads, like so...

[tex]\frac{1}{2} *\frac{1}{2} =\frac{1}{4}[/tex]

So we can see that the probability of us getting two heads in a row is that of \frac{1}{4}[/tex] or 25%.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Answer:

[tex]y=2e^{sin(x)}[/tex]

Step-by-step explanation:

Given equation can be  re written as

[tex]\frac{\mathrm{d} y}{\mathrm{d} x}-ycos(x)=0\\\frac{\mathrm{d} y}{\mathrm{d} x}=ycos(x)\\\\=> \frac{dy}{y}=cox(x)dx\\\\Integrating  \\ \int \frac{dy}{y}=\int cos(x)dx \\\\ln(y)=sin(x)+c[/tex]............(i)

Now it is given that y(π/2) = 2e

Applying value in (i) we get

ln(2e) = sin(π/2) + c

=> ln(2) + ln(e) = 1+c

=> ln(2) + 1 = 1 + c

=> c = ln(2)

Thus equation (i) becomes

ln(y) = sin(x) + ln(2)

ln(y) - ln(2) = sin(x)

ln(y/2) = sin(x)

[tex]y= 2e^{sinx}[/tex]

Answer:

about 29,748.3

Step-by-step explanation:

4000040000 - 4018040180 = 18000180

(11 gallons were used there^)

4018040180 - 4048440484 = 30400304

1616+11 = 1627 total gallons

18000180 + 30400304 = 48400484

48400484/ 1627 = 29,748.3

Answer:

The Annual percentage yield is 3.25%.

Step-by-step explanation:

Given : Money invested at the rate of 3.2% compounded continuously.

To find : What's the annual percentage yield?

Solution :

Money invested at the rate of 3.2% compounded continuously.

The compounded continuously formula is

[tex]A=Pe^{rt}[/tex]

Where, P is the principal P=1

t is the time t=1

r is the interest rate r=3.2%=0.032

Substitute the value in the formula,

[tex]A=Pe^{rt}[/tex]

[tex]A=1\times e^{0.032}[/tex]

[tex]A=1.0325[/tex]

The Annual percentage yield is

[tex]APY=(A-1)\times 100[/tex]

[tex]APY=(1.0325-1)\times 100[/tex]

[tex]APY=0.0325\times 100[/tex]

[tex]APY=3.25\%[/tex]

Therefore, The Annual percentage yield is 3.25%.

Answer:

The correct option is D.

Step-by-step explanation:

The slope of a line is the change in y with respect to x.

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

If the slope of a line is undefined it means it is a vertical line and a vertical line  can not passes through three quadrants. So, option A is incorrect.

If the slope of a line is 0 it means it is a horizontal line and a horizontal line  can not passes through three quadrants. So, option B is incorrect.

If the slope of a line is positive it means the value of y increases as x increases.

Since it is an increasing line, therefore after a certain period both x and y will positive. It means the line will passes through first quadrant. So, option C is incorrect.

If the slope of a line is negative it means the value of y decreases as x increases. It can passes through each of Quadrants II, III, and IV.

Therefore the correct option is D.

Answer:

  a) uniform

  b) 1/2

  c) 1/1000

Step-by-step explanation:

a) "numbers with equal​ probability" have a uniform distribution.

__

b) Even numbers make up 1/2 of all numbers.

__

c) There are ten such numbers in the range, so the probability is ...

  10/10000 = 1/1000

The selection of telephone numbers can be modeled using a Uniform distribution. The probability of selecting an even number is 1/2, while the chance of selecting a number ending in 666 is 0.001.

The questions asked can be explained using probability theory, a branch of mathematics.

a) To model the selection of the telephone numbers, one would use a Uniform distribution. This is because every number in the range has an equal chance of being selected.

b) The probability that the selected number is even relies on the last digit of the telephone number. As the last digit could be 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9, each with equal probability, the chance that it is even (0, 2, 4, 6, or 8) is 1/2 or 50%.

c) The probability that the selected number ends in 666 is much lower. Since there are 10,000 possible numbers, and only 10 of them end in 666 (443-0666, 443-1666, etc. through 443-9666), the probability is 10 in 10,000 or 0.001 (0.1%).

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You can use

[tex]x=u\cos v[/tex]

[tex]y=u\sin v[/tex]

[tex]z=u\cos v+3[/tex]

with [tex]0\le u\le3[/tex] and [tex]0\le v\le2\pi[/tex].

The parametric equations for the part of the plane z = x + 3 that lies inside the cylinder x² + y² = 9 can be written as x = 3cos(θ), y = 3sin(θ), and z = 3cos(θ) + 3.

The parametric representation of a surface can be found by expressing the variables x, y, and z in terms of parameters. Given the cylinder equation x² + y² = 9, we can express x and y in terms of a single parameter θ as follows:

Here we've used the parametric equations for a circle of radius 3. Moving further with the given plane equation z = x+3, we substitute x from our parametric equations above:

So, the parametric representation for the given surface is:

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The rate at which the water level is rising when the water level is 6 cm is 8.33 cm/s.

We can find the rate at which the water level is rising by using similar triangles. Let the height of the water level be h (in cm). Since the pyramid is inverted, the volume of water inside the pyramid is given by V = (6-h)^2 * h. Taking the derivative of both sides with respect to time, we get dV/dt = 50. Solving for dh/dt, we find that the rate at which the water level is rising is dh/dt = 50 / (12 - h).

When the water level is 6 cm, we substitute h = 6 into the equation to find the rate at which the water level is rising. dh/dt = 50 / (12 - 6) = 50 / 6 = 8.33 cm/s. Therefore, when the water level is 6 cm, the rate at which the water level is rising is 8.33 cm/s.

Answer:

5 pounds of nuts and 20 pounds of pretzels

Step-by-step explanation:

Let

x ----> the number of pounds of nuts

y ----> the number of pounds of pretzels

we know that

x+y=25

x=25-y ------> equation A

4x+2y=60 ---> equation B

Solve the system by substitution

Substitute equation A in equation B and solve for y

4(25-y)+2y=60

100-4y+2y=60

4y-2y=100-60

2y=40

y=20 pounds of pretzels

Find the value of x

x=25-y

x=25-20=5 pounds of nuts

Final answer:

Dave should use 5 pounds of nuts and 20 pounds of pretzels to make the party mix.

Explanation:

Let's assume that Dave buys x pounds of nuts and y pounds of pretzels. Since he wants to buy a total of 25 pounds of party mix, we can write the equation x + y = 25.

The cost of nuts per pound is $4 and the cost of pretzels per pound is $2. Therefore, the cost of x pounds of nuts is 4x dollars and the cost of y pounds of pretzels is 2y dollars.

We can write the equation 4x + 2y = 60 to represent the total cost of the party mix.

To solve this system of equations, we can use substitution. Solve the first equation for x in terms of y: x = 25 - y.

Substitute this expression for x into the second equation to get 4(25 - y) + 2y = 60.

Simplify this equation to get 100 - 4y + 2y = 60. Combine like terms to get -2y = -40. Divide both sides by -2 to solve for y: y = 20.

Substitute this value back into the first equation to find x: x = 25 - 20 = 5.

Therefore, Dave should use 5 pounds of nuts and 20 pounds of pretzels to make the party mix.

Answer:

The vertex (h,k) is (-4,-7).

Step-by-step explanation:

I assume you are looking for the vertex [tex]y=-4(x+4)^2-7[/tex].

The vertex form of a quadratic is [tex]y=a(x-h)^2+k[/tex] where the vertex is (h,k) and a tells us if the parabola is open down (if a<0) or up (if a>0). a also tells us if it is stretched or compressed.

Anyways if you compare [tex]y=-4(x+4)^2-7[/tex] to [tex]y=a(x-h)^2+k[/tex] , you should see that [tex]a=-4,h=-4,k=-7[/tex].

So the vertex (h,k) is (-4,-7).

Answer:

The vertex is [tex](-4,-7)[/tex]

Step-by-step explanation:

The vertex form of a parabola is given by:

[tex]y=a(x-h)^2+k[/tex], where (h,k) is the vertex and [tex]a[/tex] is the leading coefficient.

The given parabola has equation:

[tex]y=-1(x+4)^2-7[/tex]

When we compare to the vertex form, we have

[tex]-h=4\implies h=-4[/tex] and [tex]k=-7[/tex].

Therefore the vertex is (-4,-7)

Answer:

The required sales in units to achieve its target net income is 1,237,500 units.

Step-by-step explanation:

From the given information it is clear that

Fixed cost = $480,000

Selling Price = $6 per unit

Variable Cost = $4.4 per unit

Target net income = $1,500,000

We need to find the required sales in units to achieve its target net income.

[tex]Units=\frac{\text{Fixed cost + Target net income}}{\text{Selling Price - Variable Cost}}[/tex]

[tex]Units=\frac{480000+1500000}{6-4.4}[/tex]

[tex]Units=\frac{1980000}{1.6}[/tex]

[tex]Units=1237500[/tex]

Therefore the required sales in units to achieve its target net income is 1,237,500 units.

Answer:

Using the critical value rule, if a two-sided null hypothesis is rejected for a single mean at a given significance level, the corresponding one-sided null hypothesis will "always" be rejected at the same significance level.

Step-by-step explanation:

Consider the provided statement.

As the value of p is less than the significance level, therefore always reject the null hypothesis. Where p is exact level of significance.

Therefore, the answer to the statement is "Using the critical value rule, if a two-sided null hypothesis is rejected for a single mean at a given significance level, the corresponding one-sided null hypothesis (i.e., the same sample size, the same standard deviation, and the same mean) will always be rejected at the same significance level."

If a two-sided null hypothesis is rejected at a given significance level, the corresponding one-sided null hypothesis will also be rejected at the same significance level, because the two-sided test is more stringent.

Using the critical value rule, if a two-sided null hypothesis is rejected for a single mean at a given significance level, the corresponding one-sided null hypothesis will also be rejected at the same significance level.

This is because when performing a two-sided test, we are testing both ends of the distribution, thus it requires a stricter criteria to reject the null hypothesis than a one-sided test. Since we have already rejected it under a stricter evaluation, we will definitely reject it under a less strict one.

Consider an example where you are using a significance level of 5 percent (α = 0.05). Suppose that your computed t-statistic is 2.2. This value is greater than the critical value for a two-tailed test from the t29 distribution, which is 2.045. Therefore, you reject the two-sided null hypothesis.

Consequently, when comparing your t-statistic (2.2) with the critical value for a one-sided test (which will be less stringent than that for a two-tailed test), you also reject the one-sided null hypothesis.

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Answer:

p(0) = 800

p(8) = 997

Step-by-step explanation:

p(t) = 800 * (1.028)^t

The current price is when t=0

p(0) = 800 * (1.028)^0

       = 800(1)

       = 800

The price in 8 years

p(8) = 800 * (1.028)^8

       =997.7802522414861936754688

To the nearest dollar

        = 998

Answer:

[tex]p(0)=\$\ 800[/tex]

[tex]p(8)=\$\ 998[/tex]

Step-by-step explanation:

The function that the mode in the price is a function of exponential growth

[tex]p(t)=800(1.028)^t[/tex]

If t represents time in years, then to find the current price we do [tex]t = 0[/tex]

Then:

[tex]p(t=0)=800(1.028)^0[/tex]

[tex]p(0)=800(1)[/tex]

[tex]p(0)=\$\ 800[/tex]

To find the price after 8 years substitute t = 8 in the equation

[tex]p(t=8)=800(1.028)^8[/tex]

[tex]p(8)=\$\ 998[/tex]

Answer:

$2000 a year.

Step-by-step explanation:

Let's find the answer by using the following formula:

taxes=(house assessment)*(tax rate) for the initial conditions we have:

(1600/year)=(64000)*(tax rate)

(1600/year)/(64000)=(tax rate)

tax rate=0.025/year

For the current conditions we have:

taxes=(house assessment)*(tax rate)

taxes=(80000)*(0.025/year)

taxes=2000/year

So, the taxes will be $2000 a year.

Answer with Step-by-step explanation:

Since we have given that

AB = 0 and A is invertible so, AA⁻¹ = I

So, Consider,

[tex]AB=0[/tex]

Multiplying A⁻¹ on both the sides, we get that

[tex]A^{-1}AB=A^{-1}0\\\\(AA^{-1})B=0\\\\IB=0\\\\B=0[/tex]

Hence proved.

The standard form of the hyperbola is derived using trigonometric identities and substituted values. The given hyperbola has vertices (0,±2) and foci (0,±5), which yields a = 2, and c = 5. Using these, the standard form of the hyperbola would be y²/4 - x²/21 = 1, and the parametric equations are x = sqrt(21) tan(θ), y = 2 sec(θ).

To eliminate the parameter and obtain the standard form of the rectangular equation for a hyperbola, use the properties of trigonometric identities and apply the Pythagorean identity tan²(θ) + 1 = sec²(θ). Now, express tan(θ) and sec(θ) in terms of x and y, and substitute these into the Pythagorean identity to obtain the equation of the hyperbola.

In this case, tan(θ) = (x - h) / b and sec(θ) = (y - k) / a. Substitute these into the Pythagorean identity to get ((x - h) / b)² + 1 = ((y - k) / a)². Rearrange to obtain ({(x - h)²}/{b²}) - ({(y - k)²}/{a²}) = 1. This is the standard form of the hyperbola equation centered at (h, k).

For the specific hyperbola given with vertices (0,±2) and foci (0,±5), you can determine that a = 2, and c = 5. Using the relationship c² = a² + b² (for hyperbolas), you can find b = sqrt(c² - a²) = sqrt((5)² - (2)²) = sqrt(21).

So, the standard form of the equation would be y²/4 - x²/21 = 1. The parametric equations revert back to the original equation with specific values, i.e., x = sqrt(21) tan(θ) and y = 2 sec(θ).

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