Answer:
For linear equations we use:
p=mx+b ------ (1)
Now we have the following coordinates:
(x1,p1)= (1000,280) and (x2, p2)=(5000,400)
First we need slope (m)
m= [tex](400-280)/(5000-1000)[/tex]
= [tex]120/4000=0.03[/tex]
Now we will plug the value of m in the first equation
[tex]280=0.03(1000)+b[/tex]
=> [tex]280=30+b[/tex]
=> b = 250
Now plug into p=mx+b using only m=0.03 and b=250
[tex]p=0.03x+250[/tex]
When the unit price is $440, we can plug in 440 in for p;
[tex]440=0.03x+250[/tex]
=> [tex]0.03x=440-250[/tex]
=> [tex]0.03x=190[/tex]
=> x = 6333 refrigerators
The lowest price at which a refrigerator will be marketed, we can find this by plugging x = 0 in p=mx+b.
[tex]p=0.03(0)+250[/tex]
=> p = $250
The linear equation relating the unit price p to the quantity supplied x is p = 0.03x + 250. When the unit price is $440, approximately 6333 refrigerators will be marketed. The lowest price at which a refrigerator will be marketed is $250.
To find the equation relating the unit price p of a refrigerator to the quantity supplied x when the relationship is known to be linear, we can use the two given points: (1000, 280) and (5000, 400).
First, we determine the slope (m) of the line:
m = (400 - 280) / (5000 - 1000) = 120 / 4000 = 0.03
Next, we use the point-slope form of the equation y - y₁ = m(x - x₁) where (x₁, y₁) is one of our points. We can use (1000, 280):
p - 280 = 0.03(x - 1000)
p = 0.03x + 250
Now, let's determine how many refrigerators will be marketed when the unit price is $440:
440 = 0.03x + 250
190 = 0.03x
x = 6333.33
So, approximately 6333 refrigerators will be marketed when the unit price is $440.
Lastly, we find the lowest price at which a refrigerator will be marketed by setting x to 0:
p = 0.03(0) + 250 = 250
The lowest price at which a refrigerator will be marketed is $250.
The deep body temperature of a healthy person is 37°C. What is it in kelvins?
Answer:
The deep body temperature of a healthy person is 310.15 K
Step-by-step explanation:
The formula we are going to use is [tex]T_{K}=T_{C}+273.15[/tex]
We know that the deep body temperature is 37°C, putting this value into the formula we have that [tex]T_{K}=37+273.15 = 310.15 K[/tex]
find the focus of teh parabola that has vertex (-3,2), opens horizontally, and passes through the point (-10,1).
Answer:
[tex](-\frac{85}{28},2)[/tex]
Step-by-step explanation:
We are asked to find the focus of the parabola that has a vertex [tex](-3,2)[/tex] opens horizontally and passes through the point [tex](-10,1)[/tex].
We know that equation of a horizontal parabola is [tex](y-k)^2=4p(x-h)[/tex], where p is not equal to zero.
[tex](h,k)[/tex] = Vertex of parabola.
Focus: [tex](h+p,k)[/tex]
Upon substituting the coordinates of vertex and given point in equation of parabola, we will get:
[tex](1-2)^2=4p(-10-(-3))[/tex]
[tex](-1)^2=4p(-10+3)[/tex]
[tex]1=4p(-7)[/tex]
[tex]1=-28p[/tex]
[tex]\frac{1}{-28}=\frac{-28p}{-28}[/tex]
[tex]-\frac{1}{28}=p[/tex]
Focus: [tex](h+p,k)[/tex]
[tex](-3+(-\frac{1}{28}),2)[/tex]
[tex](-3-\frac{1}{28},2)[/tex]
[tex](\frac{-3*28}{28}-\frac{1}{28},2)[/tex]
[tex](\frac{-84}{28}-\frac{1}{28},2)[/tex]
[tex](\frac{-84-1}{28},2)[/tex]
[tex](\frac{-85}{28},2)[/tex]
[tex](-\frac{85}{28},2)[/tex]
Therefore, the focus of the parabola is at point [tex](-\frac{85}{28},2)[/tex].
For a normal distribution with mean equal to - 30 and standard deviation equal to 9 What is the area under the curve that is between - 34.5 and - 39.
Answer: 0.1498 square units.
Step-by-step explanation:
Let x be any random variable that follows normal distribution.
Given : For a normal distribution with mean equal to - 30 and standard deviation equal to 9.
i.e. [tex]\mu=-30[/tex] and [tex]\sigma=9[/tex]
Use formula [tex]z=\dfrac{x-\mu}{\sigma}[/tex] to find the z-value corresponds to -34.5 will be
[tex]z=\dfrac{-34.5-(-30)}{9}=\dfrac{-34.5+30}{9}=\dfrac{-4.5}{9}=-0.5[/tex]
Similarly, the z-value corresponds to -38 will be
[tex]z=\dfrac{-39-(-30)}{9}=\dfrac{-39+30}{9}=\dfrac{-9}{9}=-1[/tex]
By using the standard normal table for z-values , we have
The area under the curve that is between - 34.5 and - 39. will be :-
[tex]P(-1<z<-0.5)=P(z<-0.5)-P(z<-1)\\\\=(1-P(z<0.5))-(1-P(z<1))\\\\=1-P(z<0.5)-1+P(z<1)\\\\=P(z<1)-P(z<0.5)\\\\=0.8413-0.6915=0.1498[/tex]
Hence, the area under the curve that is between - 34.5 and - 39 = 0.1498 square units.
Team A and team B play against each other repeatedly until one team wins two games in a row or a total of three games. 1) how many ways can the tourney be played? 2) what is the probability of 5 games being played? 3) what is the probability of a team winning two games in a row. Show work.
Answer:
1) The tournament can be played in 10 different ways
2) The probability of 5 games being played is 0.40
3) The probability of a team winning two games in a row is 0.80
Step-by-step explanation:
a) From the tree diagram below we can observe that the tournament can be played in 10 different ways.
b)The probability of 5 games being played is
P= (number of possibilities where 5 games are being played) / (Total games)
P = 4 / 10
P= 0.40
c) The probability of a team winning two games in a row is
P = (number of possibilities where a team wins two games in a row) / Total games
P = 8 / 10
P = 0.80
Let A-10, 1, 2, 3, 4, 5,6), let B = 10, 1, 2, 3, 4, 5,6, 7,8), and let R be the relation from A to B given by "the greatest common divisor of a and b is 2." [Note: "greatest common divisor" is sometimes called "highest common factor"] List the elements of R.
Answer:
R = {(10,2), (10,4), (10,6), (10,8), (2,10), (2,2), (2,4), (2,6), (2,4), (4,10), (4,2), (4,6), (6,10), (6,2), (6,4), (6,8)}
Step-by-step explanation:
A = (10, 1, 2, 3, 4, 5, 6)
B = (10, 1, 2, 3, 4, 5, 6, 7, 8)
R is a relation and defined as
R: A→B
R: The greatest common divisor of a and b is 2
To find the elements of R we need to find pair from A and B respectively.
R = {(10,2), (10,4), (10,6), (10,8), (2,10), (2,2), (2,4), (2,6), (2,4), (4,10), (4,2), (4,6), (6,10), (6,2), (6,4), (6,8)}
Now, these pairs were found by picking one element from A and checking with elements of B if they have a gcd of 2. If yes, they fall under the defined relation.
One of the events at a swim meet is the 500 meter freestyle. Use conversion factors and dimensional analysis to determine the length of this race in: 2) a) feet. b) miles.
Answer:
1) Distance in feet equals 1640.4 feet
2) Distance in miles equals 0.3107 miles.
Step-by-step explanation:
From the basic conversion factors we know that
1 meter = 3.2808 feet
Thus by proportion we conclude that
[tex]500meters=500\times 3.2808feet\\\\\therefore 500meters=1640.4feet[/tex]
Similarly using the basic conversion factors we know that
1 mile = 1609.34 meters
thus we conclude that 1 meter =[tex]\frac{1}{1609.34}[/tex] miles
Hence by proportion 500 meters = [tex]500\times \frac{1}{1609.34}=0.3107[/tex] miles
Mrs. Brown needs $5,000 in three years. If the interest rate on her investment account is 8.4% compounded monthly, how much should she put into her account at the end of each month to have $5,000 in three years?
Give answer in US dollars and cents rounded to the nearest cent. Do NOT enter "$" sign
Answer:
ohhh you have the right time and I am so glad to see it in a better time and if it was not to do you have no doubt
Step-by-step explanation:
your body has to have your body to have the best results you need for kids in a group that can help with a lot to learn about it as you do so much of the time it works out to you to get the job you need for the next few years or 8īijjhguu is not just the best person but the meaning and skills of a person is the meaning of life and the meaning is the only 3AM in a school that you need a lot of a job 3to to do with you need to get your mind off to get your job done with your mind and then you have to do it right now and.
Find the surface area of the part of the paraboloid z=5-3x^2-2y^2 located above the xy plane. (10 points) z
Answer:
Use the formula [tex]Area(S)=\iint_{S} 1 dS= \iint_{D} \lVert r_{u}\times r_{v} \rVert dudv[/tex]
Step-by-step explanation:
Let [tex]r(x,y)=(x,y,5-3x^2-2y^2)[/tex] be the explicit parametrization of the paraboid. The intersection of this paraboid with the xy plane is the ellipse given by
[tex]\dfrac{x^2}{\frac{5}{3}}+\dfrac{y^{2}}{\frac{5}{2}}=1[/tex]
The partial derivatives of the parametrization are:
[tex]\begin{array}{c}r_{x}=(1,0,-6x)\\r_{y}=(0,1,-4y)\end{array}[/tex]
and computing the cross product we have
[tex]r_{x}\times r_{y}=(6x,4y,1)[/tex]. Then
[tex]\lVert r_{x}\times r_{y}\rVert =\sqrt{1+36x^{2}+16y^{2}}[/tex]
Then, if [tex]R[/tex] is the interior region of the ellipse the superficial area located above of the xy is given by the double integral
[tex]\iint_{R}\sqrt{1+36x^2+16y^2}dxdy=\int_{-\sqrt{5/3}}^{\sqrt{5/3}}\int_{-\sqrt{5/2}\sqrt{1-\frac{x^2}{5/3}}}^{\sqrt{5/2}\sqrt{1-\frac{x^2}{5/3}}}\sqrt{1+36x^2+16y^2}dy dx=30.985[/tex]
The last integral is not easy to calculate because it is an elliptic integral, but with any software of mathematics you can obtain this value.
x=25.36+0.45(25.36)
LaTeX: x=
Answer:
[tex]x=36.772[/tex]
Step-by-step explanation:
Given : Expression [tex]x=25.36+0.45(25.36)[/tex]
To find : Solve the expression ?
Solution :
Step 1 - Write the expression,
[tex]x=1(25.36)+0.45(25.36)[/tex]
Step 2 - Apply distributive, [tex]ab+ac=a(b+c)[/tex]
Here, a=25.36, b=1, c=0.45
[tex]x=25.36(1+0.45)[/tex]
Step 3 - Solve the expression,
[tex]x=25.36\times 1.45[/tex]
[tex]x=36.772[/tex]
Therefore, [tex]x=36.772[/tex]
Use De Morgan's Law to negate the following statements. a. Vx(x >5) b. 3.(x2+2x + 1 = 0)
Answer:
a) [tex]\neg \forall x :x>5 \equiv \forall x:x\leq 5[/tex]
b) [tex]\neg [x^2+2x+1=0]\equiv x^2+2x+1\neq0[/tex] or the set [tex]\{x:x\neq-1\}[/tex]
Step-by-step explanation:
First, notice that in both cases we have to sets:
a) is the set of all real numbers which are higher than 5 and in
b) the set is the solution of the equation [tex]x^2+2x+1=0[/tex] which is the set [tex]x=-1[/tex]
De Morgan's Law for set states:
[tex]\overline{\rm{A\cup B}} = \overline{\rm{A}} \cap \overline{\rm{B}}\\[/tex], being [tex]\overline{\rm{A}}[/tex] and [tex]\overline{\rm{B}}[/tex] are the complements of the sets [tex]A[/tex] and [tex]B[/tex]. [tex]\cup[/tex] is the union operation and [tex]\cap[/tex] the intersection.
Thus for:
a) [tex]\neg \forall x :x>5 \equiv \forall x:x\leq 5[/tex]. Notice that [tex]\forall x:x\leq 5[/tex] is the complement of the given set.
b) [tex]\neg [x^2+2x+1=0]\equiv x^2+2x+1\neq0[/tex] which is the set [tex]B = \{x:x\neq-1\}[/tex]
A commercial package contains thirty-six 200-mg tablets of ibuprofen. How many kilograms of ibuprofen were
Final answer:
To find the total kilograms of ibuprofen, multiply 36 tablets by 200 mg each to get 7200 mg, and then divide by 1,000,000 to convert to kilograms, resulting in 0.0072 kg.
Explanation:
To calculate the total amount of ibuprofen in kilograms, you start by finding the total amount in milligrams. Multiply the number of tablets (36) by the amount of ibuprofen per tablet (200 mg).
36 tablets × 200 mg/tablet = 7200 mg
Now, since there are 1,000,000 milligrams in a kilogram, you'll need to divide the total milligrams by 1,000,000 to convert it to kilograms.
7200 mg ÷ 1,000,000 mg/kg = 0.0072 kg
Therefore, the package contains 0.0072 kilograms of ibuprofen.
If 30 participants each completed a memory task three times – once each after having no, moderate, or high levels of caffeine, calculate the total degrees of freedom.
Answer: 29
Step-by-step explanation:
In statistics, the degrees of freedom gives the number of values that have the freedom to vary.
If the sample size is 'n' then the degree of freedom is given by:-
df= n-1
Given: The number of participants for the sample =30
Then the degree of freedom for this sample=30-1=29
Hence, The total degree of freedom= 29
In the context of the experimental design, the total degrees of freedom would be calculated based on the between-group and within-group variations. With three groups and three repeats, the total degrees of freedom would be 62.
Explanation:When calculating the total degrees of freedom in an experiment where 30 participants each completed a memory task three times under different levels of caffeine, we can determine the degrees of freedom by considering the number of groups and the number of repeats within each group. Since there are three groups (no, moderate, and high levels of caffeine), and each participant completes the task three times, this setup hints at an Analysis of Variance (ANOVA) scenario with repeated measures. However, without the detailed design for the within-subject factors, we can only calculate the between-group degrees of freedom. For three groups, the between-group degrees of freedom would be the number of groups minus one, which would give us 2 degrees of freedom (dfbetween = number of groups - 1).
For within-group or repeated measures, you typically have dfwithin = (number of repeats - 1) × number of subjects. Since each participant repeats the task three times, and there are 30 participants, the calculation would be dfwithin = (3 - 1) × 30 = 2 × 30 = 60 degrees of freedom. Hence, the total degrees of freedom would be the sum of between-group and within-group degrees of freedom, which is 2 + 60 = 62.
The cost, in dollars, of making x items is given by the function C(C) = 250 + 300. Find C(1500), the cost of making 1500 items. a) $4050 Ob) $25,300 Oc) $30,300 Od) $37,800 O e) none
Answer:
$37,800.
Step-by-step explanation:
We have been given that the cost, in dollars, of making x items is given by the function [tex]C(x)=25x+300[/tex]. We are asked to find [tex]C(1500)[/tex].
To find [tex]C(1500)[/tex], we will substitute [tex]x=1500[/tex] in our given function as:
[tex]C(1500)=25(1500)+300[/tex]
[tex]C(1500)=37,500+300[/tex]
[tex]C(1500)=37,800[/tex]
Therefore, the cost of making 1500 items would be $37,800 and option D is the correct choice.
The "Double-R-7" Ranch has a new owner. The 20 animals, all hummingbirds and mice, are dismayed, as they have heard that he is both foolish and inexperienced. Not being quite sure what he was looking for, however, he checked on the health of his animals by inspecting all their feet. There were 64 feet in all. How many hummingbirds and how many mice are on this ranch?
Please help immediately I'm so confused!!! :(
A survey of 1,107 tourists visiting Orlando was taken. Of those surveyed:
268 tourists had visited the Magic Kingdom
258 tourists had visited Universal Studios
68 tourists had visited both the Magic Kingdom and LEGOLAND
79 tourists had visited both the Magic Kingdom and Universal Studios
72 tourists had visited both LEGOLAND and Universal Studios
36 tourists had visited all three theme parks
58 tourists did not visit any of these theme parks
How many tourists only visited the LEGOLAND (of these three)?
Answer:
602 tourists visited only the LEGOLAND.
Step-by-step explanation:
To solve this problem, we must build the Venn's Diagram of this set.
I am going to say that:
-The set A represents the tourists that visited LEGOLAND
-The set B represents the tourists that visited Universal Studios
-The set C represents the tourists that visited Magic Kingdown.
-The value d is the number of tourists that did not visit any of these parks, so: [tex]d = 58[/tex]
We have that:
[tex]A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)[/tex]
In which a is the number of tourists that only visited LEGOLAND, [tex]A \cap B[/tex] is the number of tourists that visited both LEGOLAND and Universal Studies, [tex]A \cap C[/tex] is the number of tourists that visited both LEGOLAND and the Magic Kingdom. and [tex]A \cap B \cap C[/tex] is the number of students that visited all these parks.
By the same logic, we have:
[tex]B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)[/tex]
[tex]C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)[/tex]
This diagram has the following subsets:
[tex]a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)[/tex]
There were 1,107 tourists suveyed. This means that:
[tex]a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,107[/tex]
We start finding the values from the intersection of three sets.
The problem states that:
36 tourists had visited all three theme parks. So:
[tex](A \cap B \cap C) = 36[/tex]
72 tourists had visited both LEGOLAND and Universal Studios. So:
[tex](A \cap B) + (A \cap B \cap C) = 72[/tex]
[tex](A \cap B) = 72 - 36[/tex]
[tex](A \cap B) = 36[/tex]
79 tourists had visited both the Magic Kingdom and Universal Studios
[tex](B \cap C) + (A \cap B \cap C) = 79[/tex]
[tex](B \cap C) = 79 - 36[/tex]
[tex](B \cap C) = 43[/tex]
68 tourists had visited both the Magic Kingdom and LEGOLAND
[tex](A \cap C) + (A \cap B \cap C) = 68[/tex]
[tex](A \cap C) = 68 - 36[/tex]
[tex](A \cap C) = 32[/tex]
258 tourists had visited Universal Studios:
[tex]B = 258[/tex]
[tex]B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)[/tex]
[tex]258 = b + 43 + 36 + 36[/tex]
[tex]b = 143[/tex]
268 tourists had visited the Magic Kingdom:
[tex]C = 268[/tex]
[tex]C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)[/tex]
[tex]268 = c + 32 + 43 + 36[/tex]
[tex]c = 157[/tex]
How many tourists only visited the LEGOLAND (of these three)?
We have to find the value of a, and we can do this by the following equation:
[tex]a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,107[/tex]
[tex]a + 143 + 157 + 58 + 36 + 32 + 43 + 36 = 1,107[/tex]
[tex]a = 602[/tex]
602 tourists visited only the LEGOLAND.
18. Naruto practices his harmonica 1 hour, spends hour working on
homework, and takes another hour to do chores every day. How much
longer does Naruto spend practicing his harmonica and doing his chores
than working on homework?
Answer:
If he uses 1 hour to practice harmonica, one our on homework, and another hour doing chores. He will be spending twice as much time practicing harmonica and doing homework than he would spend on chores.
Answer:
2
Step-by-step explanation:
UP
The cost of stainless steel tubing varies jointly as the length and the diameter of the tubing. If a 5ft length with diameter 2 inches costs $48.00, how much will a 17tf length with diameter 5in. cost?
Answer:
The cost for 17 ft length with diameter 5 in is $408.
Step-by-step explanation:
Consider the provided information.
It is given that the cost of stainless steel tubing varies jointly as the length and the diameter of the tubing. If a 5 foot length with a diameter 2 inches costs $48.00.
let [tex]C\propto L\cdot D[/tex]
[tex]C=k\cdot L\cdot D[/tex]
[tex]48=k\cdot 5\cdot 2[/tex]
[tex]\frac{48}{10}=k[/tex]
[tex]k=4.8[/tex]
For 17 ft length with diameter 5in the cost will be:
[tex]C=k\cdot L\cdot D[/tex]
Substitute the respective values in the above formula.
[tex]C=4.8\cdot 17\cdot 5[/tex]
[tex]C=408[/tex]
Cost = $408
Hence, the cost for 17 ft length with diameter 5in is $408.
Your 401(k) retirement account is currently worth $55,000. Assuming no more contributions, what will your account be worth in 20 years at an annual rate of 10.5%?
N= I/Y= PV= PMT= FV= P/Y=
Answer:
Your account is going to be worst $405,142.92
Step-by-step explanation:
This is a compound interest problem.
The compound interest formula is given by:
[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]
Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.
So, for this problem:
We want to find A
[tex]P = 55,000[/tex]
[tex]n = 1[/tex]
[tex]r = 0.105[/tex]
[tex]t = 20[/tex]
[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]
[tex]A = 55000(1 + \frac{0.105}{1})^{20}[/tex]
[tex]A = 405,142.92[/tex]
Your account is going to be worst $405,142.92
How can this be proved to be a tautology using laws of logical equivalence?
((x ∨ y) ∧ (x → z) ∧ (¬z)) → y
Answer:
Step-by-step explanation:
If we assume that [tex][(x \vee y) \wedge (x \rightarrow z) \wedge (\neg z)][/tex] is true, then:
[tex](x \vee y)[/tex] is true
[tex](x \rightarrow z)[/tex] is true
[tex](\neg z)[/tex] is true
If [tex](\neg z)[/tex] is true, then [tex]z[/tex] is false.
[tex](x \rightarrow z) \equiv (\neg x \vee z)[/tex], since [tex](x \rightarrow z)[/tex] is true, then [tex](\neg x \vee z)[/tex] is true
If [tex]z[/tex] is false and [tex](\neg x \vee z)[/tex] is true, then [tex]\neg x[/tex] is true.
If [tex]\neg x[/tex] is true, then [tex]x[/tex] is false, as [tex](x \vee y)[/tex] is true and [tex]x[/tex] is false, then [tex]y[/tex] is true.
Conclusion [tex]y[/tex] it's true.
During the 2010 baseball season, the number of wins for three teams was three consecutive integers. Of these three teams, the first team had the most wins. The last team had the least wins. The total number of wins by these three teams was 228228. How many wins did each team have in the 2010 season?
Answer:
76075, 76076, 76077
Step-by-step explanation:
There are 3 teams; Team A, Team B and Team C
Team A has most wins
Team C has least wins
Team B is in between
All these will be consecutive numbers.
Team B: x
Team A: x + 1 (most wins)
Team C: x - 1 (least wins)
Team A + Team B + Team C = Total number of wins
x + x + 1 + x - 1 = 228228
3x = 228228
x = 76076
Wins of Team B : x = 76076
Wins of Team A : x + 1 = 76076 + 1 = 76077
Wins of Team C : x - 1 = 76076 - 1 = 76075
Therefore, in the 2010 season, Team A had 76077 wins, Team B had 76076 wins and Team C had 76075 wins.
!!
Calculate the Laplace transforms of the following from the definition. 1. y = t^2. y = t^3
Answer:
1) [tex]L(y)=\frac{2}{s^{3}}[/tex]
2) [tex]L(y)=\frac{6}{s^{4}}[/tex]
Step-by-step explanation:
To find : Calculate the Laplace transforms of the following from the definition ?
Solution :
We know that,
Laplace transforms of [tex]t^n[/tex] is given by,
[tex]L(t^n)=\frac{n!}{s^{n+1}}[/tex]
1) [tex]y=t^2[/tex]
Laplace of y,
[tex]L(y)=L(t^2)[/tex] here n=2
[tex]L(y)=\frac{2!}{s^{2+1}}[/tex]
[tex]L(y)=\frac{2}{s^{3}}[/tex]
2) [tex]y=t^3[/tex]
Laplace of y,
[tex]L(y)=L(t^3)[/tex] here n=3
[tex]L(y)=\frac{3!}{s^{3+1}}[/tex]
[tex]L(y)=\frac{3\times 2}{s^{4}}[/tex]
[tex]L(y)=\frac{6}{s^{4}}[/tex]
Calculate how many Fluid ounces (fl oz) of water is needed if a recipe requires 2 cups of water.
Answer:
Is needed 16 fluid oz of water to fill in 2 cups of water
Step-by-step explanation:
1 cup have 8 fluid oz
2 cups = 2 * 8 fluid oz = 16 fluid oz
Final answer:
The recipe requires 2 cups of water, which is equivalent to 16 fluid ounces since there are 8 fluid ounces in one cup.
Explanation:
To calculate how many fluid ounces of water is needed if a recipe requires 2 cups of water, you need to understand the unit equivalence between cups and fluid ounces. One cup is equivalent to 8 fluid ounces. Since the recipe requires 2 cups, you will multiply the number of cups by the unit equivalence to find the total number of fluid ounces.
Here is the calculation:
2 cups × 8 fluid ounces/cup = 16 fluid ounces
Therefore, the recipe requires 16 fluid ounces of water.
use Gaussian elimination to write each system in triangular form
x+ y+z+ w= 1
x+y −w=−1
−x+ y+z+2w= 2
x+2y−z+ w= 0
Answer:
To see the steps to the diagonal form see the step-by-step explanation. The solution to the system is [tex]x = -\frac{1}{9}[/tex], [tex]y= -\frac{1}{9}[/tex], [tex]z= \frac{4}{9}[/tex] and [tex]w = \frac{7}{9}[/tex]
Step-by-step explanation:
Gauss elimination method consists in reducing the matrix to a upper triangular one by using three different types of row operations (this is why the method is also called row reduction method). The three elementary row operations are:
Swapping two rowsMultiplying a row by a nonzero numberAdding a multiple of one row to another rowTo solve the system using the Gauss elimination method we need to write the augmented matrix of the system. For the given system, this matrix is:
[tex]\left[\begin{array}{cccc|c}1 & 1 & 1 & 1 & 1 \\1 & 1 & 0 & -1 & -1 \\-1 & 1 & 1 & 2 & 2 \\1 & 2 & -1 & 1 & 0\end{array}\right][/tex]
For this matrix we need to perform the following row operations:
[tex]R_2 - 1 R_1 \rightarrow R_2[/tex] (multiply 1 row by 1 and subtract it from 2 row)[tex]R_3 + 1 R_1 \rightarrow R_3[/tex] (multiply 1 row by 1 and add it to 3 row)[tex]R_4 - 1 R_1 \rightarrow R_4[/tex] (multiply 1 row by 1 and subtract it from 4 row)[tex]R_2 \leftrightarrow R_3[/tex] (interchange the 2 and 3 rows)[tex]R_2 / 2 \rightarrow R_2[/tex] (divide the 2 row by 2)[tex]R_1 - 1 R_2 \rightarrow R_1[/tex] (multiply 2 row by 1 and subtract it from 1 row)[tex]R_4 - 1 R_2 \rightarrow R_4[/tex] (multiply 2 row by 1 and subtract it from 4 row)[tex]R_3 \cdot ( -1) \rightarrow R_3[/tex] (multiply the 3 row by -1)[tex]R_2 - 1 R_3 \rightarrow R_2[/tex] (multiply 3 row by 1 and subtract it from 2 row)[tex]R_4 + 3 R_3 \rightarrow R_4[/tex] (multiply 3 row by 3 and add it to 4 row)[tex]R_4 / 4.5 \rightarrow R_4[/tex] (divide the 4 row by 4.5)After this step, the system has an upper triangular form
The triangular matrix looks like:
[tex]\left[\begin{array}{cccc|c}1 & 0 & 0 & -0.5 & -0.5 \\0 & 1 & 0 & -0.5 & -0.5\\0 & 0 & 1 & 2 & 2 \\0 & 0 & 0 & 1 & \frac{7}{9}\end{array}\right][/tex]
If you later perform the following operations you can find the solution to the system.
[tex]R_1 + 0.5 R_4 \rightarrow R_1[/tex] (multiply 4 row by 0.5 and add it to 1 row)[tex]R_2 + 0.5 R_4 \rightarrow R_2[/tex] (multiply 4 row by 0.5 and add it to 2 row)[tex]R_3 - 2 R_4 \rightarrow R_3[/tex](multiply 4 row by 2 and subtract it from 3 row)After this operations, the matrix should look like:
[tex]\left[\begin{array}{cccc|c}1 & 0 & 0 & 0 & -\frac{1}{9} \\0 & 1 & 0 & 0 & -\frac{1}{9}\\0 & 0 & 1 & 0 & \frac{4}{9} \\0 & 0 & 0 & 1 & \frac{7}{9}\end{array}\right][/tex]
Thus, the solution is:
[tex]x = -\frac{1}{9}[/tex], [tex]y= -\frac{1}{9}[/tex], [tex]z= \frac{4}{9}[/tex] and [tex]w = \frac{7}{9}[/tex]
A simple random sample of men over age 18 is taken to estimate the mean weight of all adult males.
Is this study
A. REPRESENTATIVE?
B. NON-REPRESENTATIVE?
Answer:
A. Representative
Step-by-step explanation:
The sample is a subset of the population. We take samples because it is easy to analyze samples as compared to population and it is less time taken. Further, Sample is said to be good if the sample is the representative of the population.
Simple Random Sampling is the sampling where samples are chosen randomly, where each unit has an equal chance of being selected in a sample.
Since, observer is taken the weight of men over age 18. Thus, it is good sample which represent whole population.
I need this input into MATLAB. I'm so lost on how to code it.
Evaluate the integral sintcos tdt .
I have already solved and found the answer to be -cost 2cost cos t + C 5 9 7
I just need to prove my work with MATLAB
Answer:
>>syms t
>>f=sin(t)*cos(t);
>>int(f)
Step-by-step explanation:
It's actually pretty easy, just use symbolic variables.
First, create the symbolic variable t using this command:
syms t
Now define the function
f=sin(t)*cos(t)
Finally use the next command in order to calculate the indefinite integral:
int(f)
I attached a picture in which you can see the procedure and the result.
To evaluate the integral of sintcost tdt in MATLAB, use the symbolic math toolbox and the 'int' function.
Explanation:To evaluate the integral sintcost tdt in MATLAB, you can use the symbolic math toolbox. First, define the extended variable t using 'syms t'. Then, determine the integrand using the symbolic expression 'f = sin(t) * cos(t)'. Finally, use the 'int' function to find the integral, 'int(f, t)'.
Here's the MATLAB code:
syms tThe resulting 'integral_value' will be the evaluated integral.
Learn more about Evaluating integrals in MATLAB here:https://brainly.com/question/34616100
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Suppose that A and B are square matrices and that ABC is invertible. Show that each of A, B, and C is invertible.
Answer:
Step-by-step explanation:
Let A, B and C be square matrices, let [tex]D = ABC[/tex]. Suppose also that D is an invertible square matrix. Since D is an invertible matrix, then [tex]det (D) \neq 0[/tex]. Now, [tex]det (D) = det (ABC) = det (A) det (B) det (C) \neq 0[/tex]. Therefore,
[tex]det (A) \neq 0[/tex]
[tex]det (B) \neq 0 [/tex]
[tex]det (C) \neq 0[/tex]
which proves that A, B and C are invertible square matrices.
The length of the hypotenuse of an isosceles right triangle
is30 meters. Find the area of the triangle. Round to thenearest
tenth, if necessary.
Answer: [tex]224.9\ m^2[/tex]
Step-by-step explanation:
An isosceles right triangle is a right triangle having two legs (other than hypotenuse ) of same length .
Given : The length of the hypotenuse of an isosceles right triangle is 30 meters.
Let x be the side length of the other two legs, then by using the Pythagoras theorem for right triangle , we have
[tex](30)^2=x^2+x^2\\\\\Rightarrow\ 900=2x^2\\\\\Rightarrow\ x^2=\dfrac{900}{2}\\\\\Rightarrow\ x^2=450\\\\\Rightarrow\ x=\sqrt{450}=\sqrt{9\times25\times2}=\sqrt{3^2\times5^2\times2}\\\Rightarrow\ x=3\times5\sqrt{2}=15(1.414)=21.21[/tex]
Thus, the other two legs have side length of 21.21 m each.
Now, the area of a right triangle is given by :-
[tex]A=\dfrac{1}{2}\times base\times height\\\\\Rightarrow\ A=\dfrac{1}{2}(21.21)\times(21.21)=224.93205\approx224.9\ m^2[/tex]
Hence, the area of the given isosceles right triangle= [tex]224.9\ m^2[/tex]
What weight of magnesium chloride (MgCl2, formula weight 95.3; Mg2, atomic weight = 243; Cl, atomic weight-35.5) is required to prepare 1,000 mL of a solution that contains 5.0 mEq of magnesium?
Answer:
238.25 mg
Step-by-step explanation:
Given:
Molar mass of MgCl₂ = 95.3
atomic weight of Mg₂ = 243
Atomic weight of Cl = 35.5
Volume of solution required = 5.0 mEq of magnesium
Now,
mEq = [tex]\frac{\textup{Weight in mg\timesValency}}{\textup{Atomic mass}}[/tex]
on substituting the values, we get
5 = [tex]\frac{\textup{Weight in mg\times2}}{\textup{95.3}}[/tex]
or
weight of magnesium chloride = 238.25 mg
Therefore,
the required mass of MgCl₂ is 238.25 mg
A liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle. Calculate the concentration of morphine sulfate on a mg/mL basis.
Answer:
20 mg/ml.
Step-by-step explanation:
We have been given that a liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle.
[tex]\text{Concentration of morphine sulfate on g/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}[/tex]
To convert the concentration of morphine sulfate on a mg/mL basis, we need to convert 2.4 grams to milligrams.
1 gram equals 1000 milligrams.
[tex]\text{Concentration of morphine sulfate on mg/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}\times\frac{\text{1,000 mg}}{\text{1 g}}[/tex]
[tex]\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2.4\times\text{1,000 mg}}{\text{120 ml}}[/tex]
[tex]\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2400\text{ mg}}{\text{120 ml}}[/tex]
[tex]\text{Concentration of morphine sulfate on mg/mL basis}=\frac{20\text{ mg}}{\text{ml}}[/tex]
Therefore, the concentration of morphine sulfate would be 20 mg per ml.
Answer:
Step-by-step explanation:
A = {a, b, c, d}
B = {c, d, e, f, g, h}
LaTeX: A\cup BA∪B is the set of all elements that belong to A or B.
When given this information Johnny stated that union of A and B is {a, b, e, f, g, h}.
POST (by Thursday): Is Johnny correct? If not, correct his answer. Either way give a every day example to justify your answer. After posting your response, please REPLY to the responses of your group members explaining whyyou agree or disagree with their response, or asking clarifying questions.
Answer:
Johnny is wrong.
[tex]A \cup B = \left\{a,b,c,d,e,f,g,h\right\}[/tex]
Step-by-step explanation:
Johnny is wrong.
A better definition would be: [tex]A \cup B[/tex] is the set of all elements that belong to at least one A or B.
So, the elements that belong to both A and B, like c and d in this exercise, also belong to [tex]A \cup B[/tex].
So:
[tex]A \cup B=\left\{a,b,c,d,e,f,g,h\right\}[/tex]