Answer: Ok, we have two numbers, and one of them is an odd integer, and the other is even.
Lets call M to the odd integer and N the even.
We know that a even integer can be written as 2k, where k is a random integer, and a odd integer can be written as 2j + 1, where j is also a random integer.
then M = 2k, N= 2j+1
then the product of M and N is: M*N = 2*k*(2*j + 1) = 2*(k*2*j + k)
is obvious to see that (k*2*J + k) is a integer, because k and j are integers.
then if we call g = ( k*2*J + k), we can write M*N=2g, and we already know that this is an even number. So M*N is a even integer.
If $5000 is deposited into an account which pays 6% compounded
monthly, approximately how much money will be in the account at the
end of 8 years?
Answer:
The amount in the account at the end of 8 years is about $8070.71.
Step-by-step explanation:
Given information:
Principal = $5000
Interest rate = 6% = 0.06 compounded monthly
Time = 8 years
The formula for amount after compound interest is
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where,
P is principal.
r is rate of interest.
n is number of times interest compounded in a year.
t is time in years.
Substitute P=5000, r=0.06, n=12 and t=8 in the above formula.
[tex]A=5000(1+\frac{0.06}{12})^{(12)(8)}[/tex]
[tex]A=5000(1.005)^{96}[/tex]
[tex]A=5000(1.61414270846)[/tex]
[tex]A=8070.7135423[/tex]
[tex]A\approx 8070.71[/tex]
Therefore the amount in the account at the end of 8 years is about $8070.71.
eight increased by the product of a number and 4 is at most 20
Answer:
I am not entirely sure what you are asking, but I believe the answer is 4*2=8
Step-by-step explanation:
This is because:
8 increased by the product of a number and 4 is at most 20.
8 + p + 4 = 20
We are trying to find p.
8 +4= 12
20 - 12= 8
So I believe the answer is 8.
(If the answer is wrong, plz tell me in the comments)
Answer:
3
Step-by-step explanation:
eight increased by the product of a number and 4 is at most 20
these implies
8 + a x4 = 20
a is the number whose product with 4 is increased by eight to give at most 20
8 + a x4 = 20
8 + 4a = 20
subtract 8 from both sides
4a = 20 -8
4a= 12
divide both sides by 4
a = 12/4 = 3
the number is 3
Your third-grade classroom has 32 boys and girls. Two-thirds of the boys and three-fourths of the girls are going on a field trip. There are 9 children left. What is the ratio of boys to girls in your class?
Draw diagrams to support your answer.
Answer: The ratio of boys to girls would be 3 : 5 .
Step-by-step explanation:
Since we have given that
Number of boys and girls = 32
Fraction of boys are going on a field trip = [tex]\dfrac{2}{3}[/tex]
Fraction of girls are going on a field trip = [tex]\dfrac{3}{4}[/tex]
Number of children left = 9
Let the number of boys be 'b'.
Let the number of girls be 'g'.
According to question, it becomes ,
[tex]b+g=32------------(1)\\\\32-9=\dfrac{2}{3}b+\dfrac{3}{4}g\\\\23=\dfrac{2b}{3}+\dfrac{3g}{4}-------------(2)[/tex]
From eq(1), we get that g = 32-b
So, it becomes,
[tex]\dfrac{2}{3}b+\dfrac{3}{4}(32-b)=23\\\\\dfrac{2}{3}b+24-\dfrac{3}{4}b=23\\\\\dfrac{2}{3}b-\dfrac{3}{4}b=23-24=-1\\\\\dfrac{8b-9b}{12}=-1\\\\\dfrac{-b}{12}=-1\\\\b=-1\times -12\\\\b=12[/tex]
so, number of girls would be 32 - b = 32 - 12 = 20
So, Ratio of boys to girls in class would be 12 : 20 = 3 : 5.
Therefore, the ratio of boys to girls would be 3 : 5 .
If we are performing a two-tailed test of whether mu = 100, the probability of detecting a shift of the mean to 105 will be ________ the probability of detecting a shift of the mean to 110.
Answer:
less than
Step-by-step explanation:
When we are performing a two-tailed test of whether μ = 100, the probability of detecting a shift of the mean to 105 will be ___Less__than___ the probability of detecting a shift of the mean to 110.
this means that
mean of 105 < mean of 110.
1.How much will $5,000 accumulate in 5 years if it earns 6% per annum for the first 3 years and then 8% per annum for the next 2 years?
Answer: Amount after 5 years become $5937.60.
Step-by-step explanation:
Since we have given that
Principal amount = $5000
Time period = 5 years
Rate of interest for 3 years = 6%
Rate of interest for 2 years = 8%
so, Amount becomes
[tex]Amount=5000(1+\dfrac{6}{1000})^3(1+\dfrac{8}{100})^2\\\\Amount=5000(1+0.006)^3(1+0.08)^2\\\\Amount=5000(1.006)^3(1.08)^2\\\\Amount=\$5937.60[/tex]
Hence, Amount after 5 years become $5937.60.
Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each unit of fuel energy used, the plant produces 0.34 units of electrical energy. Assuming continuous operation, determine the amount of nuclear fuel consumed by the plant per year.
Answer:
The amount of nuclear fuel required is 1.24 kg.
Step-by-step explanation:
From the principle of mass energy equivalence we know that energy generated by mass 'm' in an nuclear plant is
[tex]E=m\cdot c^2[/tex]
where
'c' is the speed of light in free space
Since the power plant operates at 1200 MW thus the total energy produced in 1 year equals
[tex]E=1200\times 10^6\times 3600\times 24\times 365=3.8\times 10^{16}Joules[/tex]
Thus using the energy produced in the energy equivalence we get
[tex]3.8\times 10^{16}=mass\times (3\times 10^{8})^2\\\\\therefore mass=\frac{3.8\times 10^{16}}{9\times 10^{16}}=0.422kg[/tex]
Now since the efficiency of conversion is 34% thus the fuel required equals
[tex]mass_{required}=\frac{0.422}{0.34}=1.24kg[/tex]
Which function r or s is the inverse function for function q
And could you also help on my second picture
Answer:
In the first picture, correct answer is b: the inverse of function q is function r, because they are symmetrical about the line y = x.
In the second picture, correct answer is b: {y| 0<= y < 8}.
Step-by-step explanation:
The inverse function of f ( f⁻¹(x) ) must satisfy that: f(f⁻¹(x)) = f⁻¹(f(x)) = x; it returns every point x, transformed under function f, to its original place. In the graph, this property translates in the following statement: the inverse function of a function f is the reflection over the identity function (y = x).
In the graph shown in the question, the blue graph (r), is the one that corresponds to the reflection under the identity function. Therefore, the correct answer is b.
Regarding the second picture, first we need to understand what the range means. The range of a function corresponds to the set of all resulting values of the dependent variable. Since the values taken by the dependent variable span from 0 to 8 (including the 0 but not including the 8), then the answer is b: {y| 0<= y < 8}.
Show that the area of a right triangle of sides 5, 12 and 13 cannot be a square
Answer and Explanation:
Given : Sides of right triangle 5,12 and 13.
To find : Show that the area of a right triangle of sides 5, 12 and 13 cannot be a square ?
Solution :
If 5,12 and 13 are sides of a right angle triangle then
13 is the hypotenuse as it is largest side.
then we take perpendicular as 12 and base as 5.
The area of the right angle triangle is
[tex]A=\frac{1}{2}\times b\times h[/tex]
Here, h=12 and b=5
[tex]A=\frac{1}{2}\times 5\times 12[/tex]
[tex]A=5\times 6[/tex]
[tex]A=30[/tex]
The area of the right angle triangle is 30 units.
30 is not a perfect square as [tex]30=2\times 3\times 5[/tex]
There is no square pair formed.
Find the marginal and average revenue functions associated with the demand function P= -0.3Q + 221
Answer:
Marginal revenue = R'(Q) = -0.6 Q + 221
Average revenue = -0.3 Q + 221
Step-by-step explanation:
As per the question,
Functions associated with the demand function P= -0.3 Q + 221, where Q is the demand.
Now,
As we know that the,
Marginal revenue is the derivative of the revenue function, R(x), which is equals the number of items sold,
Therefore,
R(Q) = Q × ( -0.3Q + 221) = -0.3 Q² + 221 Q
∴ Marginal revenue = R'(Q) = -0.6 Q + 221
Now,
Average revenue (AR) is defined as the ratio of the total revenue by the number of units sold that is revenue per unit of output sold.
[tex]Average\ revenue\ = \frac{Total\ revenue}{number\ of\ units\ sold}[/tex]
Where Total Revenue (TR) equals quantity of output multiplied by price per unit.
TR = Price (P) × Total output (Q) = (-0.3Q + 221) × Q = -0.3 Q² + 221 Q
[tex]Average\ revenue\ = \frac{TR}{Q}[/tex]
[tex]Average\ revenue\ = \frac{-0.3Q^{2}+221Q}{Q}[/tex]
∴ Average revenue = -0.3Q + 221
You are the owner of a small bakery. This week the bakery has orders for 48 birthday cakes. Each cake sells for $52. Suppose you spend 1/4
of each cake's selling price for ingredients. How much will the ingredients cost for all of the birthday cake orders?
Answer:$624
Total sales: $52 x 48 = $2,496
Cost of ingredients:
$2,496
4
= $624
Step-by-step explanation:
$624
Total sales: $52 x 48 = $2,496
Cost of ingredients:
$2,496
4
= $624
Answer:
The ingredients will cost $624 for all of the birthday cakes.
Step-by-step explanation:
This week the bakery has orders for 48 birthday cakes. Each cake sells for $52.
1/4 of each cake's selling price is spent on ingredients.
This becomes [tex]\frac{1}{4}\times52= 13[/tex] dollars
Hence, the total cost of ingredients for 48 cakes will be "
[tex]13\times48=624[/tex] dollars
Therefore, the ingredients will cost $624 for all of the birthday cakes.
An experimenter is studying the effects of temperture, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.
(a) If any particular experiental run involves the use of single temperature, pressure, and catalyst, how many experimental runs are possible?
(b) How many experimental runs are there that involve use of the lowest temperature and two lowest pressure?
Answer:
Step-by-step explanation:
Given that an experimenter is studying the effects of temperture, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.
a) Experimental runs possible if use of single temperature, pressure and catalyst is there = no of temperatures x no of pressures x no of catalysts
= [tex]3*4*5 = 60[/tex]
b) Here pressure and temperature have no choice as lowest is selected.
no of methods = no of catalysts x 1 x1
= 5
If we assume the population of Grand Rapids is growing at a rate of approximately 4% per decade, we can model the population function with the formula
P( t ) = 181843 ( 1.04 )^(t / 10).
Use this formula to compute the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] .
Answer:
The average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.
Step-by-step explanation:
The given function is
[tex]P(t)=181843(1.04)^{(\frac{t}{10})}[/tex]
where, P(t) is population after t years.
At t=5,
[tex]P(5)=181843(1.04)^{(\frac{5}{10})}=185444.20[/tex]
At t=6,
[tex]P(6)=181843(1.04)^{(\frac{6}{10})}=186172.95[/tex]
At t=7,
[tex]P(7)=181843(1.04)^{(\frac{7}{10})}=186904.57[/tex]
At t=8,
[tex]P(8)=181843(1.04)^{(\frac{8}{10})}=187639.06[/tex]
At t=9,
[tex]P(9)=181843(1.04)^{(\frac{9}{10})}=188376.44[/tex]
At t=10,
[tex]P(10)=181843(1.04)^{(\frac{10}{10})}=189116.72[/tex]
The rate of change of P(t) on the interval [tex][x_1,x_2][/tex] is
[tex]m=\frac{P(x_2)-P(x_1)}{x_2-x_1}[/tex]
Using the above formula, the average rate of change of the population on the intervals [ 5 , 10 ] is
[tex]m=\frac{P(10)-P(5)}{10-5}=\frac{189116.72-185444.20}{5}=734.504[/tex]
The average rate of change of the population on the intervals [ 5 , 9 ] is
[tex]m=\frac{P(9)-P(5)}{9-5}=\frac{188376.44-185444.20}{4}=733.06[/tex]
The average rate of change of the population on the intervals [ 5 , 8 ] is
[tex]m=\frac{P(8)-P(5)}{8-5}=\frac{187639.06-185444.20}{3}=731.62[/tex]
The average rate of change of the population on the intervals [ 5 , 7 ] is
[tex]m=\frac{P(7)-P(5)}{7-5}=\frac{186904.57-185444.20}{2}=730.185[/tex]
The average rate of change of the population on the intervals [ 5 , 6 ] is
[tex]m=\frac{P(6)-P(5)}{6-5}=\frac{186172.95-185444.20}{1}=728.75[/tex]
Therefore the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.
It takes Kay 20 minutes to drive to work traveiling 45 mph. Two minutes after she left home this morning, her husband, Dan, started out with her briefcase, which she had forgotten. If Dan arrived at Kay's office just as she did, how fast did he drive?
Answer:
Kay's husband drove at a speed of 50 mph
Step-by-step explanation:
This is a problem of simple motion.
First of all we must calculate how far Kay traveled to her job, and then estimate the speed with which her husband traveled later.
d=vt
v=45 mph
t= 20 minutes/60 min/hour = 0.333 h (to be consistent with the units)
d= 45mph*0.333h= 15 miles
If Kay took 20 minutes to get to work and her husband left home two minutes after her and they both arrived at the same time, it means he took 18 minutes to travel the same distance.
To calculate the speed with which Kate's husband made the tour, we will use the same initial formula and isolate the value of "V"
d=vt; so
v=[tex]\frac{d}{t}[/tex]
d= 15 miles
t= 18 minutes/60 min/hour = 0.30 h (to be consistent with the units)
v=[tex]\frac{d}{t}=\frac{15 miles}{0.3 h}=50mph[/tex]
Kay's husband drove at a speed of 50 mph
An automobile insurance company divides customers into three categories, good risks, medium risks, and poor risks. Assume that 78% of the customers are good risks, 20% are medium risks, and 2% are poor risks. Assume that during the course of a year, a good risk customer has probability 0.005 of filing an accident claim, a medium risk customer has probability 0.01, and a poor risk customer has probability 0.025. A customer is chosen at random. What is the probability that the customer has filed a claim? Round the answer to four decimal places.
Answer:
There is a 0.64% probability that the costumer has filed a claim.
Step-by-step explanation:
Probability:
What you want to happen is the desired outcome.
Everything that can happen iis the total outcomes.
The probability is the division of the number of possible outcomes by the number of total outcomes.
Our problem has these following probabilities:
-78% that a costumer is a good risk.
-20% that a costumer is a medium risk.
-2% that a costumer is a poor risk.
Also:
- 0.5% of a good risk costumer filling an accident claim
- 1% of a medium risk costumer filling an accident claim.
-2.5% of a poor risk costumer filling an accident claim.
The question is:
What is the probability that the customer has filed a claim?
[tex]P = P_[1} + P_{2} + P_{3}[/tex], in which:
-[tex]P_{1}[/tex] is the probability that a good risk costumer is chosen and files a claim. This probability is: the probability of a good risk costumer being chosen multiplied by the probability that a good risk costumer files a claim. So:
[tex]P_[1} = 0.78*0.005 = 0.0039[/tex]
-[tex]P_{2}[/tex] is the probability that a medium risk costumer is chosen and files a claim. This probability is: the probability of a medium risk costumer being chosen multiplied by the probability that a medium risk costumer files a claim. So:
[tex]P_[2} = 0.20*0.01 = 0.002[/tex]
-[tex]P_{3}[/tex] is the probability that a poor risk costumer is chosen and files a claim. This probability is: the probability of a poor risk costumer being chosen multiplied by the probability that a poor risk costumer files a claim. So:
[tex]P_[3} = 0.02*0.025 = 0.0005[/tex]
[tex]P = P_[1} + P_{2} + P_{3} = 0.0039 + 0.002 + 0.0005 = 0.0064[/tex]
There is a 0.64% probability that the costumer has filed a claim.
The probability that a randomly selected customer has filed a claim is calculated using the total law of probability, which yields a result of 0.0064 or 0.64%, after considering the probabilities of each risk group filing a claim.
Explanation:To calculate the probability that a randomly chosen customer has filed a claim, we need to use the total law of probability. This involves multiplying the probability of a customer being in each risk group by the probability that a customer in that risk group files a claim, and then summing these products.
For good risks, this probability is 0.78 (the percentage of good risk customers) multiplied by 0.005 (the probability a good risk customer files a claim): 0.78 * 0.005 = 0.0039.
For medium risks, the calculation is 0.20 * 0.01 = 0.0020.
For poor risks, the calculation is 0.02 * 0.025 = 0.0005.
Adding these probabilities together gives us the total probability that a customer has filed a claim: 0.0039 + 0.0020 + 0.0005 = 0.0064, or 0.64% if expressed as a percentage.
Therefore, the probability that a randomly selected customer from the insurance company has filed a claim is 0.0064 or 0.64%, rounded to four decimal places.
7:( 4 11 m)=56:3.2
I'm too lazy to do this....Please can someone do this for meh.
Who ever does it with steps gets a virtual hug. -w-
Answer:
0.000973236=m
Step-by-step explanation:
Given the question as;
7:(411m) = 56 : 3.2
7/411m =56/3.2
7×3.2=56×411m
(7×32)/(560×411)=m
224/230160=m
0.000973236=m
checking the answer
7: (411 *0.000973236) = 56: 3.2
7: (0.4)= 56 : 3.2
7/0.4 =56/3.2
70/4=560/32
17.5 =17.5
Prove that the each element of a group G has a unique inverse. That is, if a, b, W E G satisfy then b
Step-by-step explanation:
Say [tex]a[/tex] is an element of [tex]G[/tex] which might have more than 1 inverse. Let's call them [tex]b[/tex], and [tex]c[/tex]. So that [tex]a[/tex] has apparently two inverses, [tex]b[/tex] and [tex]c[/tex].
This means that [tex]a*b = e[/tex] and that [tex]a*c=e[/tex](where [tex]e[/tex] is the identity element of the group, and * is the operation of the group)
But so we could merge those two equations into a single one, getting
[tex]a*b=a*c[/tex]
And operating both sides by b by the left, we'd get:
[tex]b*(a*b)=b*(a*c)[/tex]
Now, remember the operation on any group is associative, meaning we can rearrange the parenthesis to our liking, gettting then:
[tex](b*a)*b=(b*a)*c[/tex]
And since b is the inverse of a, [tex]b*a=e[/tex], and so:
[tex](e)*b=(e)*c[/tex]
[tex]b=c[/tex] (since e is the identity of the group)
So turns out that b and c, which we thought might be two different inverses of a, HAVE to be the same element. Therefore every element of a group has a unique inverse.
If f(x) = c is constant for all x in R, why lim x-> infinite (gap P) no equal to 0
Answer:
[tex]\lim_{x\rightarrow \infty}C=C[/tex]
Step-by-step explanation:
We are given that f(x)=c=Constant for all x in R
We have to find that why f(x) not equal to zero when x approaches to zero.
[tex]\lim_{x\rightarrow \infty}f(x)[/tex]
[tex]\lim_{x\rightarrow \infty}C=C[/tex] not equal to zero
We are given that function which is constant for all x in R.
When x approaches then the value of function does not change. it remain same for all x in R because function is constant.
Hence, when x tends to infinity then f(x) is not equal to zero.
Determine whether the description below corresponds to an observational study or an experiment.
In a study sponsored by a company, 12,543 people were asked what contributes most to their happiness commahappiness, and 87% of the respondents said that it was their job.
is the study described above an observational study or an experiment?
(A) The study is an observational study because the responses of the survey subjects were observerd.
(B) The study is an observational study because the survey subjects were not given any treatment
(C) The study is an experiment because it was done with statistical methods.
(D) The study is an experiment because the survey subjects were given a treatment.
Answer:
The correct option is B) The study is an observational study because the survey subjects were not given any treatment.
Step-by-step explanation:
Consider the provided information.
In a study sponsored by a company, 12,543 people were asked what contributes most to their happiness, and 87% of the respondents said that it was their job.
Observational study is the study in which observer only observe the subjects, and measure variables of interest without allocating treatments to subjects.
Experiment study is the study in which the researchers are applying treatments to experimental units in the research, then the effect of the treatments on the experimental units is observed.
Now consider the provided statement.
The research is based on information that nobody manipulates any experimental variables.
Hence, the study is an observational study where no treatment is given.
Thus, the correct option is B) The study is an observational study because the survey subjects were not given any treatment.
Consider the following. x'' + 2x' + x = 0, x(0) = 8, x'(0) = −8; family of solutions x = C1e−t + C2te−t Show that the family of solutions satisfies the equation for all values of the constants. (Enter your answers in terms of t.)
Answer:
Everything is verified in the step-by-step explanation.
Step-by-step explanation:
We have the following differential equation:
[tex]x'' + 2x' + x = 0[/tex]
This differential equation has the following characteristic polynomial:
[tex]r^{2} + 2r + 1 = 0[/tex]
This polynomial has two repeated roots of [tex]r = -1[/tex].
Since the roots are repeated, our solution has the following format:
[tex]x(t) = c_{1}e^{-t} + c_{2}te^{-t}[/tex]
This shows that the family of solutions satisfies the equation for all values of the constants. The values of the constants depends on the initial conditions.
Lets solve the system with the initial conditions given in the exercise.
[tex]x(0) = 8[/tex]
[tex]c_{1}e^{0} + c_{2}(0)e^{0} = 8[/tex]
[tex]c_{1} = 8[/tex]
--------------------
[tex]x'(0) = 8[/tex]
[tex]x(t) = c_{1}e^{-t} + c_{2}te^{-t}[/tex]
[tex]x'(t) = -c_{1}e^{-t} + c_{2}e^{-t} - c_{2}te^{-t}[/tex]
[tex]-c_{1}e^{0} + c_{2}e^{0} - c_{2}(0)e^{0} = 8[/tex]
[tex]-c_{1} + c_{2} = 8[/tex]
[tex]c_{2} = 8 + c_{1}[/tex]
[tex]c_{2} = 8 + 8[/tex]
[tex]c_{2} = 16[/tex]
With these initial conditions, we have the following solution
[tex]x(t) = 8e^{-t} + 16te^{-t}[/tex]
how many numbers are there that have distinct digits and are greater than 4500? how many 5 digit odd numbers are there that have distinct digits?how many 5 digit even number are there that have distinct digits?
Answer:
4-digit numbers with distinct digits and greater than 4500: 2800 numbers
5-digit numbers with distinct digits: 27216 numbers.
Step-by-step explanation:
If we represent a 4 number digit by ABCD, we have 9 posibilities for A (1,2,3,4,5,6,7,8 and 9, all but 0).
If every digit has to be different, we have 9 posibilities for B: ten digits (0,1,2,3,4,5,6,7,8 and 9 minus the one already used in A).
Int he same way, we have 8 posibilities for C and 7 for D.
Considering all 4-digits numbers, we have 9*9*8*7 = 4536 numers with distinct digits.
To know how many of these numbers are greater than 4500, we can substracte first the numbers that are smaller than 4000: A can take 3 digits (1,2 and 3) and B, C and D the same as before.
3*9*8*7 = 1512 numbers smaller than 4000
Then we can substrat the ones that are between 4000 and 4500
1*4*8*7 = 224 numbers between 4000 and 4500
So, if we substract from the total the numbers that are smaller than 4500 we have the results:
4-digit numbers with distinct digits greater than 4500 = 4536-(1512+224) = 2800
For 5-digit numbers, we can call the number ABCDE.
For A we have 9 digits possible (all but 0).
For B, we also have 9 posibilities (all digits but the one used in A).
For C, we have 8 digits (all 10 but the ones used in A and B).
For D, we have 7 digits.
For E, we have 6 digits.
Multiplying the possible combinations, we have:
9*9*8*7*6 = 27,216 5-digit numbers with distinct digits.
Two thousand five hundred twenty numbers have distinct digits and are more significant than 4500. There are 15120 5-digit odd numbers and 15120 5-digit even numbers with different numerals.
Explanation:In Mathematics, to calculate how many numbers have distinct digits and are more significant than 4500, consider that any number greater than 4500 and less than 10000 is a 4-digit number. The thousands place can be filled by any number from 5 to 9, giving five options. Any ten digits can fill the hundreds place minus the one used in the thousands, giving nine options. The tens place, similarly, has eight votes. Similarly, the one's site has seven options, as the digit in that place cannot duplicate any of the prior digits. So, the answer is 5*9*8*7 = 2520 distinct numbers.
For the second part of your query, the 5-digit odd numbers with non-repeating digits, the tens place must be filled by five possible odd digits (1, 3, 5, 7, 9), and the first place can be filled by any number from 1 to 9, giving nine options. The other three areas have 8, 7, and 6 votes, respectively, leading to 9*8*7*6*5 = 15120 distinct numbers.
As for the 5-digit even numbers with non-repeating digits, the tens place can be filled by five possible even digits (0, 2, 4, 6, 8), and the first place can be filled by any number from 1 to 9, giving nine options. The other three areas have 8, 7, and 6 votes, respectively. So there are 9*8*7*6*5 = 15120 five-digit, distinct digit, even numbers.
Learn more about the Counting Principle here:https://brainly.com/question/29594564
#SPJ12
2m + 7 = 9
Answer when solved??
For a certain event, 817 tickets were sold, for a total of $1919. If students paid $2 per ticket and nonstudents paid $3 per ticket, how many student tickets were sold?
Answer: 532
Step-by-step explanation:
Let x be the number of students and y be the number of non-students.
Then, by considering the given information, we have
[tex]x+y=817-----(1)\\\\2x+3y=1919-----------(2)[/tex]
Multiply 2 on the both sides of equation (1), we get
[tex]2x+2y=1634--------(3)[/tex]
Subtract (3) from (2), we get
[tex]y=285[/tex]
Put the value of y in (1), we get
[tex]x+285=817\\\\\Rightarrow\ x=817-285=532[/tex]
Hence, 532 student tickets were sold .
8 + 12 = 2x
HELPPPP GOOD ANSWERS
Answer:
x = 10
Step-by-step explanation:
8 + 12 = 2x
8 + 12 = 20
20 = 2x
---- -----
2 2
10 = x
x = 10
Hey!
----------------------------------------------------
Solution:
8 + 12 = 2x
~Divide 2 to both sides
20/2 = 2x/2
~Simplify
10 = x
----------------------------------------------------
Answer:
x = 10
----------------------------------------------------
Hope This Helped! Good Luck!
A boat is heading due east at 22 km/hr (relative to the water). The current is moving toward the southwest at 10 km/hr.(a) Give the vector representing the actual movement of the boat. (Round each component to two decimal places.)
The actual movement of the boat is calculated by adding the vectors representing the velocity of the boat and the water current. The net vector shows both the speed and direction of the actual movement.
Explanation:The actual movement of the boat is determined by adding vectorially, the velocity of the boat and the velocity of the current. This is because we need to consider both the speed and direction of the boat (traveling due east) and the current (flowing southwest).
Let's assume East as +i direction, and North as +j direction. So, the velocity of the boat is 22i km/hr and the velocity of the current is -10i/√2 -10j/√2 km/hr (as it is moving southwest).
To find the net velocity or actual movement, we add these two vectors.
Resultant velocity = 22i -10i/√2 -10j/√2 // Adding the i-components and the j-components
= (22 -10/√2)i -10/√2 j km/hr
Therefore, the actual movement of the boat is (22 -10/√2)i -10/√2 j km/hr.
Learn more about Vector addition here:https://brainly.com/question/31940047
Ms. Jones deposited $100 at the end of each month for 10 years into a savings account earning 6% interest compounded monthly. However, she deposited an additional $1000 at the end of the first year. How much money was in the account at the end of the tenth year?
Answer:
$1895.64
Step-by-step explanation:
Given:
Principle for the first year = $100
rate of interest = 6% compounded monthly
thus,
rate per month, r = \frac{\etxtup{6}}{\textup{12}}= 0.5% = 0.005
Total time = 10 year\
Now,
for the first year
number of months, n = 12
Amount at the end of first year = Principle × ( 1 + r )ⁿ
on substituting the values, we get
Amount at the end of first year = 100 × ( 1 + 0.005 )¹²
or
Amount at the end of first year = $106.17
Therefore,
The principle amount for the consecutive years will be
= $1000 + Amount at the end of first year
= $1000 + $106.17 = $1106.17
Thus, for the rest 9 years
n = 9 × 12 = 108
Principle = $1106.17
Final amount after the end of 10th year = Principle × ( 1 + r )ⁿ
or
Final amount after the end of 10th year = $1106.17 × ( 1 + 0.005 )¹⁰⁸
or
Final amount after the end of 10th year = $1895.64
A company asks an investor for an investment of $950,000 in exchange for 25% equity in the business. What is the implied valuation of the business?
Answer:
$2,850,000
Step-by-step explanation:
Data provided in the question:
Investment amount asked for by the company = $950,000
Exchange of equity = 25%
Now,
Equity exchanged = [tex]\frac{\textup{Amount invested}}{\textup{Post money evaluation}}\times100[/tex]
or
Post money evaluation = [tex]\frac{\textup{950,000}}{\textup{25}}\times100[/tex]
or
Post money evaluation = $3,800,000
Therefore,
Implied valuation = Post money evaluation - Amount invested
or
Implied valuation = $3,800,000 - $950,000 = $2,850,000
In American football, the playing field is 53.33 yards (yd) wide by 120 yards (yd) long. For a special game, the field staff want to paint the playing field orange. Of course, they will use biodegradable paint available for purchase in 25-gallon (gal) containers. If the paint is applied in a thickness of 1.2 millimeters (mm) in a uniform layer, how many containers of paint will they need to purchase?
Answer:
214
Step-by-step explanation:
The playing field is 53.33 yards wide and 120 yards long you would need to find the area so multiply 53.33 by 120 yards. That equals 6399.6 , the thickness they are applying is 1.2 millimeters. You would divide the area, 6399.6 by 1.2 which would equal 5333. Divide that by 25 gallons and it equals 213.32, you would need to purchase 214, rounded.
Answer:
The number of containers to purchase is [tex]N_V= 67.85[/tex]
Step-by-step explanation:
From the question we are told that
The playing field width is [tex]w_f = 53.33 \ yard = 53.33*0.9144 = 48.76m[/tex]
The playing field length is [tex]l_f = 120 \ yards = 120 * 0.9144 = 109.728m[/tex]
The volume of one container is [tex]V= 25 \ gallon = 25 * 0.00378541 = 0.094625m^3[/tex]
The thickness of the painting is [tex]t = 1.2 \ mm = 1.2 * 0.001 = 0.0012m[/tex]
The area of the playing field is [tex]A = 48.76 * 109.728[/tex]
[tex]=5350.337m^2[/tex]
The number of container of paint needed [tex]N_V[/tex] [tex]= \frac{area \ of \ playing \ field(A) * thickness \ of \ paint \ application(t) }{volume\ single \ container(V)}[/tex]
=> [tex]N_V = \frac{5350.337 * 0.0012}{0.094625}[/tex]
[tex]N_V= 67.85[/tex]
translate phrases into algebraic expressions, the difference between the cube of a number and the square of the number
Answer:
[tex]x^3-x^2.[/tex]
Step-by-step explanation:
The word "difference" represents a subtraction. Then the algebraic expression will be of the form a-b.
Now, the difference is between the cube of a number and the square of the number, then let's call the number x. The square of the number is raise to two. Then the square of the number is [tex]x^2[/tex].
The cube of the number is raise to three. Then the cube of the number is [tex]x^3[/tex].
So, the difference between the cube of a number and the square of the number (we are talking about the same number in the square and the cube) is [tex]x^3-x^2[/tex].
dy/dx = (sin x)/y , y(0) = 2
Answer:
The solution for this differential equation is [tex]y=\sqrt{-2cos(x)+6}[/tex]
Step-by-step explanation:
This differential equation [tex]\frac{dy}{dx}=\frac{sin(x)}{y}[/tex] is a separable First-Order ordinary differential equation.
We know this because a first-order differential equation is separable if and only if it can be written as
[tex]\frac{dy}{dx}=f(x)g(y)[/tex] where f and g are known functions.
And we have
[tex]\frac{dy}{dx}=\frac{sin(x)}{y}\\ \frac{dy}{dx}=sin(x)\frac{1}{y}[/tex]
To solve this differential equation we need to integrate both sides
[tex]y\cdot dy=sin(x)\cdot dx\\ \int\limits {y\cdot dy}= \int\limits {sin(x)\cdot dx}[/tex]
[tex]\int\limits {y\cdot dy}=\frac{y^{2} }{2} + C[/tex]
[tex]\int\limits {sin(x) \cdot dx}=-cos(x) + C[/tex]
[tex]\frac{y^{2} }{2} + C=-cos(x) + C[/tex]
We can make a new constant of integration [tex]C_{1}[/tex]
[tex]\frac{y^{2} }{2}=-cos(x) + C_{1}[/tex]
We need to isolate y
[tex]\frac{y^{2} }{2}=-cos(x) + C_{1}\\y^2=-2cos(x)+2*C_{1}\\\mathrm{For\:}y^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}y=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\y=\sqrt{-2cos(x)+c_{1} } \\y=-\sqrt{-2cos(x)+c_{1} }[/tex]
We have the initial conditions y(0)=2 so we can find the value of the constant of integration for [tex]y=\sqrt{-2cos(x)+c_{1} } [/tex]
[tex]2=\sqrt{-2\cos \left(0\right)+c_1}\\2= \sqrt{-2+c_1} \\c_1=6[/tex]
For [tex]y=-\sqrt{-2cos(x)+c_{1} } [/tex] there is not solution for [tex]c_{1}[/tex] in the domain of real numbers.
The solution for this differential equation is [tex]y=\sqrt{-2cos(x)+6}[/tex]
use matrices and elementary row to solve the following system:
5x - 3x + 2x =13
2x - y - 3z =1
4x - 2y + 4z =12
I assume the first equation is supposed to be
[tex]5x-3y+2z=13[/tex]
and not
[tex]5x-3x+2x=4x=13[/tex]
As an augmented matrix, this system is given by
[tex]\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right][/tex]
Multiply through row 3 by 1/2:
[tex]\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right][/tex]
Add -1(row 2) to row 3:
[tex]\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right][/tex]
Multiply through row 3 by 1/5:
[tex]\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right][/tex]
Add -2(row 3) to row 1, and add 3(row 3) to row 2:
[tex]\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right][/tex]
Add -3(row 2) to row 1:
[tex]\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right][/tex]
Multiply through row 1 by -1:
[tex]\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right][/tex]
Add -2(row 1) to row 2:
[tex]\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right][/tex]
Multipy through row 2 by -1:
[tex]\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right][/tex]
The solution to the system is then
[tex]\boxed{x=1,y=-2,z=1}[/tex]