Using the t-distribution, we have that:
a)
The null hypothesis is [tex]H_0: x_1 - x_2 \leq 0[/tex].The alternative hypothesis is [tex]H_1: x_1 - x_2 > 0[/tex]i) The test statistic is t = 0.746.
ii) The p-value is of 0.2299.
b) The 90% confidence interval is from -1.25 to 3.25.
Item a:
For a right-tailed test, we test if [tex]x_1[/tex] is greater than [tex]x_2[/tex], hence:
The null hypothesis is [tex]H_0: x_1 - x_2 \leq 0[/tex].The alternative hypothesis is [tex]H_1: x_1 - x_2 > 0[/tex]The standard errors are:
[tex]S_{e1} = \frac{5}{\sqrt{25}} = 1[/tex]
[tex]S_{e2} = \frac{4}{\sqrt{20}} = 0.8944[/tex]
The distribution of the difference has mean and standard error given by:
[tex]\overline{x} = x_1 - x_2 = 11 - 10 = 1[/tex]
[tex]s = \sqrt{S_{e1}^2 + S_{e2}^2} = \sqrt{1^2 + 0.8944^2} = 1.34[/tex]
We have the standard deviation for the samples, hence, the t-distribution is used.
The test statistic is given by:
[tex]t = \frac{\overline{x} - \mu}{s}[/tex]
In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis.
Hence:
[tex]t = \frac{\overline{x} - \mu}{s}[/tex]
[tex]t = \frac{1 - 0}{1.34}[/tex]
[tex]t = 0.746[/tex]
The test statistic is t = 0.746.
The p-value is found using a t-distribution calculator, with t = 0.746, 25 + 20 - 2 = 43 df and 0.05 significance level.
Using the calculator, it is of 0.2299.Item b:
The critical value for a 90% confidence interval with 43 df is [tex]t = 1.6811[/tex].
The interval is:
[tex]\overline{x} \pm ts[/tex]
Hence:
[tex]\overline{x} - ts = 1 - 1.6811(1.34) = -1.25[/tex]
[tex]\overline{x} + ts = 1 + 1.6811(1.34) = 3.25[/tex]
The 90% confidence interval is from -1.25 to 3.25.
A similar problem is given at https://brainly.com/question/25840856
Two components in a rocket operate independently, and the probability that for every component to fail on a launch is p. Let X denote the number of launches required to have a failure of the first component, and let Y denote the number of launches required to have a failure of the second component, X, Y
Answer: p = X/(1-X)X + Y/(1-Y)Y
Step-by-step explanation:
Cards from an ordinary deck of 52 playing cards are turned face up one at a time. If the first card is an ace, or the second a deuce, or the third a three, or, . . . , or the thirteenth a king, or the fourteenth an ace, and so on, we say that a match occurs. Note that we do not require that (13n + 1)th card be any particular ace for a match to occur but only that it be an ace. Compute the expected number of matches that occur.
Answer:
The expected number of matches that occur is 4.
Refer below for the explanation.
Step-by-step explanation:
Refer to the picture for complete steps.
The University of Montana ski team has nine entrants in a men's downhill ski event. The coach would like the first, second, and third places to go to the team members. In how many ways can the nine team entrants achieve first, second, and third places
Answer:
504 ways
Step-by-step explanation:
The first position can go in 9 ways
The second position can go to the team in 8 ways
The third position can go to the team in 7 ways
Therefore, the first,second and third position can go to the team in:
9 X 8 X 7=504 ways
or Simply, we can use Permutation.
[tex]^9P_3=504[/tex] ways
Tommy Wait, a minor league baseball pitcher, is notorious for taking an excessive amount of time between pitches. In fact, his time between pitches are normally distributed with a mean of seconds and a standard deviation of seconds. What percentage of his times between pitches are longer than seconds
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
Tommy Wait, a minor league baseball pitcher, is notorious for taking an excessive amount of time between pitches. In fact, his time between pitches are normally distributed with a mean of 29 seconds and a standard deviation of 2.1 seconds. What percentage of his times between pitches are longer than 31 seconds ?
Given Information:
Mean pitching time = μ = 29 seconds
Standard deviation of pitching time = σ = 2.1 seconds
Required Information:
P(X > 31) = ?
Answer:
[tex]P(X > 31) = 17.11 \%[/tex]
Step-by-step explanation:
What is Normal Distribution?
We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.
We want to find out the probability that what percentage of his times between pitches are longer than 31 seconds.
[tex]P(X > 31) = 1 - P(X < 31)\\P(X > 31) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\P(X > 31) = 1 - P(Z < \frac{31 - 29}{2.1} )\\P(X > 31) = 1 - P(Z < \frac{2}{2.1} )\\P(X > 31) = 1 - P(Z < 0.95)\\[/tex]
The z-score corresponding to 0.95 is 0.8289
[tex]P(X > 31) = 1 - 0.8289\\P(X > 31) = 0.1711\\P(X > 31) = 17.11 \%[/tex]
Therefore, 17.11% of his times between pitches are longer than 31 seconds.
How to use z-table?
Step 1:
In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 0.9 1.4, 2.2, 0.5 etc.)
Step 2:
Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.95 then go for 0.05 column)
Step 3:
Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.
A charge q1 = 5 μC, is at the origin. A second charge q2 = -3 μC is on the x-axis 0.8 m from the origin. The electric field at a point on the y-axis 0.5 m from the origin is:
Answer:
[tex]\vec{E}=\vec{E_1}+\vec{E_2}=[25856\hat{i}+163443.2\hat{j}]N/C[/tex]
Step-by-step explanation:
The electric field is given by:
[tex]E=k\frac{q_1q_2}{r^2}[/tex]
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
at the point P(0,0.5m) you have both x ad y component of the electric field. For the particle q1 you have:
[tex]\vec{E_1}=Ex\hat{i}+Ey\hat{j}\\\\\vec{E_1}=0\hat{i}+(8.89*10^9Nm^2/C^2)\frac{(5*10^{-6}C)}{(0.5m)^2}\hat{j}=179600N/C\hat{j}[/tex]
for the particle q2, it is necessary to compute the angle between the E vector and the axis, by using the distance y and x. Furthermore it is necessary to know the distance from q2 to the point P.
[tex]\vec{E_2}=Excos\theta \hat{i}-Eysin\theta \hat{j}\\\\\theta=tan^{-1}(\frac{0.5}{0.8})=32\°\\\\r=\sqrt{0.5^2+0.8^2}=0.94m\\\\\vec{E_2}=(8.89*10^9Nm^2/C^2)\frac{(-3*10^{-6C})}{(0.94m)^2}[cos(32)\hat{i}-sin(32)\hat{j}]\\\\=[25856.06\hat{i}-16156.71\hat{j}]N/C[/tex]
Finally, by adding E1 and E2 you obtain:
[tex]\vec{E}=\vec{E_1}+\vec{E_2}=[25856\hat{i}+163443.2\hat{j}]N/C[/tex]
A mixture of pulverized fuel ash and Portland cement to be used for grouting should have an average compressive strength of more than 1300KN=m2. The mixture will not be used unless experimental evidence indicates conclusively that the strength specification has been met. Suppose compressive strength for specimens of this mixture has standard deviation ? = 60. Let ? denote the true average compressive strength.
Answer:
Check the explanation
Step-by-step explanation:
Hypotheses are:
[tex]H_o[/tex] : μ 1300, [tex]H_a[/tex] : μ > 1300
The distribution of test statistics will be normal with mean
mean 1300
and standard deviation
[tex]sd=\frac{\sigma}{\sqrt{n}}=\frac{68}{\sqrt{11}}[/tex]=20.50277
Now z-score for T-1331.26 and μ 1300 is
-1300-1.52 1331.26 1300 68/V11
[tex]z=\frac{1331.26-1300}{68/\sqrt{11}}= 1.52[/tex]
So the probability distribution of the test statistic when H0 is true is
a = P(z > 1.5247) = 0.0643
Lena is a college basketball player who has made 75%, percent of the free-throws she has attempted in her career. she decided to practice a new technique for shooting her free-throws. lena was curious if this new technique produced significantly better or worse results. she tried the new technique and made 70%, percent of 50 attempts. here's lena's alternative hypothesis: ha : the proportion of attempts made using this new technique is. what is an appropriate way for lena to finish her alternative hypothesis a.equal to 75% b.not equal to 75% c.not equal to 70% d.equal to 70%
Answer:
b
Step-by-step explanation:
Select the correct answer.
What is the solution for p in the equation?
1/3p + 1/2p = 7/6p +5 + 4
A.
p = -6
B.
p = -1
C.
p = 1
D.
p = 6
To solve for p in the equation 1/3p + 1/2p = 7/6p + 5 + 4, you need to combine like terms and isolate p. The solution is p = 27.
Explanation:To solve for p in the equation 1/3p + 1/2p = 7/6p + 5 + 4, you need to combine like terms and isolate p on one side of the equation.
Multiply the fractions by their respective denominators to eliminate the fractions. This gives us 2/6p + 3/6p = 7/6p + 9.
Combine like terms. On the left side, 2/6p + 3/6p = 5/6p. On the right side, 7/6p + 9 remains unchanged.
Subtract 5/6p from both sides to isolate p. This gives us 7/6p - 5/6p = 9.
Combine like terms on the left side. 7/6p - 5/6p = 2/6p.
Simplify the equation further. 2/6p = 9 can be reduced to 1/3p = 9.
Multiply both sides of the equation by the reciprocal of 1/3, which is 3/1. This gives us p = 9 * (3/1) = 27.
Therefore, the solution for p in the equation is p = 27.
At crescent high school, 108 students plan on going to an in-state college and 63 students plan on going out of state college what is the ratio of students planning on going to an in state college to students planning on going to an out state college
Answer:
12/7
Step-by-step explanation:
To set up a ratio of "thing 1" to "thing 2", build a fraction with "thing 1" on top (numerator) and "thing 2" on the bottom (denominator).
The ratio of in-state students to out-of-state students is [tex]\frac{108}{63}[/tex] and this can be simplified ("reduced") by dividing both numbers by 9 to get the fraction 12/7.
Final answer:
Explanation on finding the ratio of students planning in-state college to out-of-state college.
Explanation:
The ratio of students planning on going to an in-state college to students planning on going to an out-of-state college:
To find the ratio, you need to divide the number of students planning in-state college by the number planning out-of-state college.
Number of students planning in-state college: 108
Number of students planning out-of-state college: 63
Ratio: 108:63 which simplifies to 36:21 or 12:7
A polynomial of degree at least 3 where all the zeros are positive whole numbers
We can build a polynomial given it's degree and zeros. Below I am going to show how we do that, and then I will solve the question, finding that one example of a desired polynomial is:
[tex]f(x) = x^3 - 15x^2 + 54x - 40[/tex]
Zeros of a function:
Given a polynomial f(x), this polynomial has roots [tex]x_{1}, x_{2}, x_{n}[/tex] such that it can be written as: [tex]a(x - x_{1})*(x - x_{2})*...*(x-x_n)[/tex], in which a is the leading coefficient.
In this question:
Polynomial of degree 3, so 3 roots.
All positive, I will choose:
[tex]x_1 = 1, x_2 = 4, x_3 = 10[/tex]
I will choose the leading coefficient as a = 1.
Thus
[tex]f(x) = a(x - x_1)(x - x_2)(x - x_3)[/tex]
[tex]f(x) = (x-1)(x-4)(x-10)[/tex]
[tex]f(x) = (x^2-5x+4)(x-10)[/tex]
[tex]f(x) = x^3 - 15x^2 + 54x - 40[/tex]
The image shown in the end of this question shows that this polynomial has three positive roots, also all whole numbers.
Another similar example is given at https://brainly.com/question/21328461
What is the area of the following shape?
Answer:
104 m^2
Step-by-step explanation:
We first find the area of the rectangle
A = l*w
A = 10*8
A = 80
Then we find the area of the triangle
A = 1/2 bh
A = 1/2 (8)(6)
= 24
Then we add the areas together to find the total area
80+24 = 104
n a study of the accuracy of fast food drive-through orders, Restaurant A had 314 accurate orders and 61 that were not accurate. a. Construct a 90% confidence interval estimate of the percentage of orders that are not accurate. b. Compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at Restaurant B: 0.147less thanpless than0.206. What do you conclude?
Answer:
a. 0.1576<p<0.2310
b. The two restaurants likely have similar order rates which are inaccurate.
Step-by-step explanation:
a. We first calculate the proportion, [tex]\hat p[/tex]:
[tex]\hat p=\frac{61}{314}\\\\=0.1943[/tex]
-We use the z-value alongside the proportion to calculate the margin of error:
[tex]MOE=z\sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\=1.645\times \sqrt{\frac{0.1943(1-0.1943)}{314}}\\\\=0.0367[/tex]
The confidence interval at 90% is then calculated as:
[tex]CI=\hat p\pm MOE\\\\=0.1943\pm 0.0367\\\\=[0.1576,0.2310][/tex]
Hence, the confidence interval at 90% is [0.1576,0.2310]
b. From a above, the calculated confidence interval is 0.1576<p<0.2310
-We compare the calculated CI to the stated CI of 0.147<p<0.206
-The two confidence intervals overlap each other and have the same value for 0.1576<p<0.206
-Hence, we conclude that the two restaurants likely have similar order rates which are inaccurate.
On a very hot summer day, 5 percent of the production employees at Highlander Steel are dehydrated. The production employees are randomly selected for a special in-depth study on dehydration. What is the probability of randomly selecting 8 production employees on a hot summer day and finding that none of them are dehydrated
Answer:
P(X=0) = 0.0332
Step-by-step explanation:
5% of the employees are dehydrated. I.e. p = 5/100
p = 0.05
The percentage of employees that are not dehydrated = 100-5 = 95%
q = 1 - p = 1 - 0.05
q = 0.95
A total of 8 employees were randomly selected. n = 8
This is a binomial distribution question
P(X =r) = nCr (p^r)q^(n-r)
n = 8, r = 0
n -r = 8-0 = 8
P(X = 0) = 8C0 (0.05^0)(0.95^8)
8C0 = 1
P(X=0) = 1 * 1* 0.6634
P(X=0) = 0.6634
Answer:
The probability of picking 8 employee and none of them is dehydrated is 0.66
Step-by-step explanation:
P(employee is dehydrated) = 5%=5/100=1/20= 0.05
P(employee not dehydrated) = 1 - 0.05= 0.95
The probability of picking 8 employee and they are not dehydrated is:
= (0.95)^8
= 0.6634204312890625
= 0.66
Short=7 Long=
30 60 90 triangle
Final answer:
To find the "long" side opposite the 60° angle in a 30-60-90 triangle with a "short" side length of 7, we multiply 7 by √3 to get 7√3.
Explanation:
The student appears to be asking about the relationships between the sides of a 30-60-90 triangle, which is a special type of right triangle. In such a triangle, the sides are in the ratio 1:√3:2. So, if the "short" side opposite the 30° angle is given as 7, then the "long" side opposite the 60° angle can be found by multiplying the short side by √3. To find the hypotenuse (opposite the 90° angle), we would multiply the short side by 2.
Step-by-step to find the long side:
Identify the given "short" side, which is opposite the 30° angle, as 7.Use the special triangle ratio for a 30-60-90 triangle to find the "long" side by calculating 7 × √3.Therefore, the length of the "long" side opposite the 60° angle is 7√3.
What can we conclude for the following linear homogeneous equation? t2y''+3ty'+y=0, t>0. y1=t is a solution. By the method of reduction of order, we can ALWAYS find another independent solution y2 satisfying W(y1,y2)≠ 0 y1=t−1 is a solution. By the method of reduction of order, we can ALWAYS find another independent solution y2 satisfying W(y1,y2)≠ 0 None of these y1=t is a solution. By the method of reduction of order, we can SOMETIMES find another independent solution y2 satisfying W(y1,y2)≠ 0 y1=t−1 is a solution. By the method of reduction of order, we can SOMETIMES find another independent solution y2 satisfying W(y1,y2)≠ 0
Answer:
Required conclusion is that if [tex]y_1, y_2[/tex] satisfies given differential equation and wronskean is zero then they are considered as solution of that differential equation.
Step-by-step explanation:
Given differential equation,
[tex]t^2y''+3ty'+y=0[/tex] [tex] t>0\hfill (1)[/tex]
(i) To verify [tex]y_1(t)=t[/tex] is a solution or not we have to show,
[tex]t^2y_{1}^{''}+3ty_{1}^{'}+y_1=0[/tex]
But,
[tex]t^2y_{1}^{''}+3ty_{1}^{'}+y_1=(t^2\times 0)=(3t\times 1)+t=4t\neq 0[/tex]
hence [tex]y_1[/tex] is not a solution of (1).
Now if [tex]y_2=t-1[/tex] is another solution where [tex]y_2(t)=t-1[/tex] then,
[tex]t^2y_{2}^{''}+3ty_{2}^{'}+y_2=0[/tex]
But,
[tex]t^2y_{2}^{''}+3ty_{2}^{'}+y_2=(t^2\times 0)+(3t\times 1)+t-1=4t-1\neq 0[/tex]
so [tex]y_2[/tex] is not a solution of (1).
(ii) Rather the wronskean,
[tex]W(y_1,y_2)=y_{1}y_{2}^{'}-y_{2}y_{1}^{'}=(t\times 1)-((t-1)\times 1)=t-t+1=1\neq 0[/tex]
Hence it is conclude that if [tex]y_1, y_2[/tex] satisfies (i) along with condition (ii) that is wronskean zero, only then [tex]y_1, y_2[/tex] will consider as solution of (1).
Solve for 3x minus one equals 27
Answer:
the answer is 9.3
Step-by-step explanation:
Answer:
9.
Step-by-step explanation:
You would subtract the one to isolate the variable so 3x = 27 then divide by 3 so the answer is 9.
A group of statistics students conducted a survey about smoking habits on campus to determine the proportion of students who believe that smoking hookah (a water pipe) is less harmful than smoking cigarettes. Of the 50 students surveyed, 45 think that smoking hookah is less harmful than smoking cigarettes.
Which of the following is a reason that this group of students should not calculate a confidence interval for the proportion of all students who believe that smoking hookah is less harmful than smoking cigarettes? Check all that apply.
a) The sample needs to be random but we don’t know if it is.
b) The actual count of students who believe that smoking hookah is less harmful than smoking cigarettes is too small.
c) The actual count of students who do not believe that smoking hookah is less harmful than smoking cigarettes is too small.
d) n(p^) is not greater than 10.
e) n(1 - p^) is not greater than 10.
Answer:
The answer is A, C and D
Step-by-step explanation:
a
c
d
The correct answer is a) The sample needs to be random but we don’t know if it is.
Calculate success by multiplying the sample % by the sample size to make sure the sample size is adequate.
Why is it necessary to satisfy the random condition?The situation at random we receive impartial population data from random sampling. It might be dangerous to draw conclusions about a community from data that was not randomly chosen samples since such data typically contains some type of bias.
Calculate success by multiplying the sample % by the sample size to make sure the sample size is adequate, and calculate failure by multiplying one less than the sample percentage by the sample size. The condition is satisfied if both of these items are larger than ten.
To learn more about random condition refer to:
https://brainly.com/question/251701
#SPJ2
What are the functions of money?
Answer:
The functions of money are:
Function # 1. A Medium of Exchange: ...
Function # 2. A Measure of Value: ...
Function # 3. A Store of Value (Purchasing Power): ...
Function # 4. The Basis of Credit: ...
Function # 5. A Unit of Account: ...
Function # 6. A Standard of Postponed Payment:
Explanation:
My parents are bankers.
Expression is equivalent 1/3+(3/4+2/3)?
The expression 1/3 + (3/4 + 2/3) is equivalent to 7/4.
Explanation:The expression is equivalent to 1/3 + (3/4 + 2/3). To solve this expression, we need to simplify the inner parentheses first. Adding 3/4 and 2/3, we get a common denominator of 12:
3/4 + 2/3 = 9/12 + 8/12 = 17/12Now, we can substitute the simplified fraction back into the original expression:
1/3 + (3/4 + 2/3) = 1/3 + 17/12To add the fractions with different denominators, we need to find a common denominator. In this case, the common denominator is 12:1/3 + 17/12 = 4/12 + 17/12 = 21/12Finally, we can simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 3:21/12 = (3 * 7) / (3 * 4) = 7/4Therefore, the expression 1/3 + (3/4 + 2/3) is equivalent to 7/4.
A buyer owes a supplier $820. The terms were 3/10, n/60. Within 10 days, the buyer sent in a payment of $140. How much is the new balance? (Round your answers to the nearest hundredth)
Answer:
The new balance is $675.8
Step-by-step explanation:
Solution
Given that
The total amount of loan = $820.
The terms were = 3/10, n/60
Within 10 days, the buyer sent in a payment of =$140
What is the new balance =?
Now,
3/10 = if the amount is paid in 10 days, a discount of is included
n/60 = This means that all amount should be paid within 60 days
Thus,
$140 for 3/10 as this is paid within 10 days
140 *3% = 140 * 3/100
we get
=$4.2 of discount
Then,
The balance amount becomes $ 820 - 140 -4.2
=$675.8
The scores of individual students on the American College Testing (ACT) Program composite college entrance examination have a Normal distribution with mean that varies slightly from year to year and standard deviation 6.0. You plan to take an SRS of size n of the students who took the ACT exam this year and compute the mean score of the students in your sample. You will use this to estimate the mean score of all students this year. In order for the standard deviation of to be no more than 0.1, how large should n be
Answer:
The sample size must be atleast 3600
Step-by-step explanation:
We are given the following in the question:
The scores of individual students on the American College Testing (ACT) Program is a bell shaped distribution that is a normal distribution.
Population standard deviation = 6.0
We want that the sample standard deviation should not be more than 0.1.
Thus, the standard error should not be more than 0.1.
Standard error =
[tex]=\dfrac{\sigma}{\sqrt{n}}[/tex]
Putting values, we get,
[tex]\dfrac{\sigma}{\sqrt{n}}\leq 0.1\\\\ \dfrac{6}{\sqrt{n}} \leq 0.1\\\\ \sqrt{n}\geq 60\\n\geq 3600[/tex]
Thus, the sample size must be atleast 3600
If you double a number and then add 32, you get two ninths
of the original number. What is the original number?
Answer:
The number is -18
Step-by-step explanation:
Let x be the original number
2x +32 = 2/9x
Multiply each side by 9 to get rid of the fractions
9(2x +32) =9* 2/9x
18x +288 = 2x
Subtract 18x from each side
18x-18x+288 = 2x-18x
288 = -16x
Divide each side by -16
288/-16 = -16x/-16
-18 =x
Answer:
–18
Step-by-step explanation:
let the number is [tex]x[/tex], from the problem we know that
[tex]2x+32=\frac{2}{9}x
\\9x+144=x
\\x=-\frac{144}{8}=-18[/tex]
A waste management service attempts to design routes so that each of their trucks pick-up on average
four tons of garbage or less. A garbage collector believes, however, that he averages picking up more
than four tons of garbage per day and decides to perform a hypothesis test.
Identify a Type II error in the context of this hypothesis test.
a) Concluding that the garbage collector picks up on average more than 4 tons of garbage per day when,
in fact, he doesn’t.
b) Not concluding that the garbage collector picks up on average more than 4 tons of garbage per day
when, in fact, he does.
c) Concluding that the garbage collector picks up on average 4 tons of garbage per day when, in fact, he
picks up more.
d) Not concluding that the garbage collector picks up on average 4 tons of garbage per day when, in fact,
he does.
I'm confused with the wording but my guess is between B and C
Answer:
The correct option is (c).
Step-by-step explanation:
A type II error is a statistical word used within the circumstance of hypothesis testing that defines the error that take place when one is unsuccessful to discard a null hypothesis that is truly false. It is symbolized by β i.e.
β = Probability of accepting H₀ when H₀ is false.
In this case we need to test the hypothesis whether the garbage collector's belief is true or not.
The hypothesis can be defined as:
H₀: The garbage collector averages picking up four tons of garbage per day, i.e. μ = 4.
Hₐ: The garbage collector averages picking up more than four tons of garbage per day, i.e. μ > 4.
Consider that the garbage collector made a type II error while drawing the conclusions of the test.
This implies that the garbage collector failed to reject the null hypothesis incorrectly.
That is, he concluded that the he picks up on average four tons of garbage per day, when in fact he picks up more than four tons of garbage every day.
Thus, the correct option is (c).
Answer:4 tons
Step-by-step explanation:
just because ik;;;:)
What is another name used for permanent cement?
Answer:
Zinc Phosphate cement
Answer:
luting agent
Step-by-step explanation:
For which of the following procedures would you include a temporary
luting agent is basicslly the same thing
What is the volume of the square pyramid with base edges 32 mm and slant height 34 mm?
9,920 mm3
10,010 mm3
7,680 mm3
10,240 mm3
Answer:
V = 10,240mm^3
Step-by-step explanation:
The volume of pyramid is given by the following formula:
[tex]V=\frac{1}{3}bh[/tex] (1)
b: base of the pyramid = (32mm)^2
h: height
Thus, it is necessary to find the value of h, by using the Pitagoras's theorem, one half of the base and the slant height (which forms a rectangle triangle with h):
[tex]h=\sqrt{(34)^2-(16)^2}=30mm[/tex]
by replacing in (1) you obtain:
[tex]V=\frac{1}{3}(32mm)^2(30mm)=10,240\ mm^3[/tex]
hence, the volume is 10240mm^3
What is the surface area of this cylinder? Use 3.14 and round your answer to the nearest hundredth.
What type of triangle, if any can be formed with angle measures of 32 degrees, 126 degrees, and 32 degrees?
Answer 1 only an obtuse triangle
Answer 2 either an acute isosceles triangle or an obtuse isosceles triangle
Answer 3 only an acute isosceles triangle
Answer 4 no triangle
No triangle can be formed.(answer 4)
What is triangle?In Geometry, a triangle is a three-sided polygon that consists of three edges and three vertices. The most important property of a triangle is that the sum of the internal angles of a triangle is equal to 180 degrees
We have,
Angles of triangle= 32 degrees, 126 degrees , 32 degrees
We know,
All triangles must have angles that measure up to 180 degrees.
[tex]32^{o} +126^{o} + 32^{o}[/tex]
=[tex]190^{o}[/tex] > [tex]180^{0}[/tex]
Hence ,That means that is no triangle can be formed.
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The sum of the given angles exceeds 180 degrees, which violates the basic rule of triangles, so no triangle can be formed with these measures.
Explanation:To determine what type of triangle can be formed with angle measures of 32 degrees, 126 degrees, and 32 degrees, we need to consider two rules: First, the sum of the angles in any triangle must be 180 degrees. Second, the classification of whether a triangle is acute, obtuse, or right is based on the measures of its angels.
Adding the given angles together (32 degrees + 126 degrees + 32 degrees), we get 190 degrees. Since this sum is greater than 180 degrees, it violates the first rule of triangles. Therefore, no triangle can be formed with these given angle measures.
Given that’s the measure of the angle is 109, what is the measure of angle k?
Answer:
k is also 109 degrees bcoz they are corresponding angles
Solve for x.
2(4x− 9) = 5(x − 4)
Answer:
2(4x− 9) = 5(x − 4)
=>8x- 18= 5x-20
=>8x-5x= -20+18
=>3x = -2
=>x= -2/3
At a large university a simple random sample of five female professors is selected and a simple random sample of 10 male professors is selected. The two samples are combined to give an overall sample of 15 professors. The overall sample is a A. simple random sample. B. biased due to imbalance. C. a stratified sample. D. All of the above
Answer:
D. All of the above
Step-by-step explanation:
Samples may be classified as:
Random: Basically, put all the options into a hat and drawn some of them.
Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.
Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.
In this problem:
Two random samples are selected and combined. The combination is a random sample. So A. is correct.
They are not balanced. More male professors than female are chosen. So B. is correct.
The teachers are divided into groups(male and female). And some members of each group are selected. So C. is correct.
So the correct answer is:
D. All of the above