Answer:
A. They are equal.
B. The ratio of ions to molecules is 1 to 2.78× 10⁸.
Explanation:
A. Concentration of ions
In pure water, [H₃O⁺] = [OH⁻] = 1.00 × 10⁻⁷ mol·L⁻¹.
The concentration of hydroxide ions equals that of hydronium ions.
B. Ratio of ions to molecules
Assume you have 1 L of pure water.
[tex]\text{Moles of water} = \text{1000 g} \times \dfrac{\text{1 mol}}{\text{18.02 g}} = \text{55.49 mol}[/tex]
You have 1.00× 10⁻⁷ mol·L⁻¹ [H₃O⁺] and 1.00× 10⁻⁷ mol·L⁻¹ [OH⁻], so you have 2,00 mol·L⁻¹ of ions.
The ratio of concentrations is
[tex]\dfrac{\text{[Ions]}}{\text{[Molecules]}} = \dfrac{2.00 \times 10^{-7}}{55.49} = \dfrac{ 3.60 \times 10^{-5}}{1} = \mathbf{\dfrac{1}{2.78 \times 10^{8}}}[/tex]
what statement defines enzymatic activity
A chemical change :a.occurs when powdered lemonade is stirred into water. b.occurs when water is vaporized. c.occurs when paper is shredded. d.occurs when salt is dissolved in water. e.occurs when methane gas is burned.
Answer: E. Occurs when methane gas is burned.
Explanation:
A chemical change occurs when matter undergoes a change to form a new substance with different chemical properties, and the reaction is usually not reversible.
In the case of burning methane gas (CH4) ,oxygen and methane are the reactants, while the new substance formed from the reaction are carbondioxide (CO2) and water (H2O) .
A chemical change, involving a chemical reaction and the formation of new substances, occurs when methane gas is burned. Therefore, option e is the correct answer.
Explanation:In the provided options, the chemical change occurs when methane gas is burned (option e). A chemical change involves a chemical reaction, with the formation of new substances that have different properties from those of the original substances. In the case of burning methane, the chemical reaction can be represented as CH4 + 2O2→ CO2 + 2H2O. As a result of this reaction, methane (CH4) and oxygen (O2) are transformed into carbon dioxide (CO2) and water (H2O), which are completely distinct entities with different properties.
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PLEASE NEED HELP QUICK DEADLINE SOON
The atomic mass of an element can be approximated by adding the number of _______ plus the average number of _______.
A.
protons; electrons
B.
protons; isotopes
C.
neutrons; electrons
D.
protons; neutrons
Answer:
D. Protons ; neutrons.
Explanation:
For a given element the number of protons is fixed, but the number of neutrons differ because the element usually consist of a number of isotopes.
For example Carbon has isotopes which contain 12, 13 and 14 neutrons.
So that is why you average the number of neutrons to find the approximate atomic mass..
Use your understanding of the ideal gas law to identify the correct relationships among the variables Pressure is tempature is volume is moles are
Pressure is inversely related to volume. Temperature is inversely related to moles. Volume is inversely related to pressure. Moles are inversely related to temperature.
Explanation:
The ideal gas law is represented mathematically as: PV=nRT. P- pressure, V- volume, n-number of moles of gas, R- ideal gas constant, T- temperature.
The ideal gas law is used as a prediction of the behavior of many gases, when subjected to different conditions.
An increase in the pressure or volume, decreases the number of moles and temperature of the gas.
Empirical laws that led to generation of the ideal gas laws, considered two variables and keeping the others constant. This empirical laws include, Boyle's law, Charles's law, Gay Lusaac's law and Avogadro's law.
Answer:
Pressure is
✔ inversely related to volume
.
Temperature is
✔ inversely related to moles
.
Volume is
✔ inversely related to pressure
.
Moles are
✔ inversely related to temperature
.
Identify the ideal gas law equation.
✔ PV=nRT
Explanation:
What is the electron structure of sodium?
1s 22s 23s 23p 5
1s 22s 22p 63s 1
1s 22s 23s 22p 5
1s 22s 22p 23s 23p 3
Answer:
B. is the answer
Explanation:
Look at an electron configuration chart. You need to know the number of protons in an element to figure this out.
- Hope that helped! Please let me know if you need a further explanation.
Answer:
1s^2 , 2s^2 , 2p^6 , 3s^1
Explanation:
The above electron configuration is the structure for Sodium.
(-5)+(+7)-(-4) + (+12)
A 8
B 10
C 18
d 20
Answer:
C-18
Explanation:
Step one follow order of operations
Add and subtract from left to right(-5)+(7)=2-(-4)+(12)
STEP 2
Apply negative Rule -(-4)=+4=2+4+(12)
then add 2+4+12=18
At high concentrations, inorganic fluoride inhibits enolase. In an anaerobic system that is metabolizing glucose as a substrate, which of the following compounds would you expect to immediately increase in concentration following the addition of fluoride?
A. 2-phosphoglycerate.
B. Glucose.
C. 3-phosphoglycerate
D. Phosphoenolpyruvate
E. Pyruvate
Answer:
A. 2-phosphoglycerate
Explanation:
Glycolysis is the process of breakdown of glucose into two 3-carbon molecules called pyruvate. The energy released during glycolysis is used to make ATP.
Enolase is the enzyme which plays very important role in glycolysis. In the 9th step of glycolysis, Enolase converts 2-phosphoglycerate into phosphoenolpyruvate.
This reaction of conversion of 2-phosphoglycerate to phosphoenolpyruvate is a reversible dehydration reaction.
Fluoride inhibits enolase, so when enolase is become non-functional then there is no convertion of 2-phosphoglycerate to phosphoenolpyruvate, so the concentraion of 2-phosphoglycerate is increases by the addition of fluoride.
i need help asap!! and a explanation would be really appreciated
Answer:
The answer to your question is Ionic
Explanation:
Data
Phosphorous and Lithium
type of bond = ?
Process
In chemistry there are 2 main bonds:
Ionic is a bond between a metal and a nonmetal but also we can identify these bonds if the difference of electronegativity is higher than 1.7.
Covalent is a bond between two nonmetals or when the difference of electronegativity is lower than 1.7.
For this molecule:
Lithium is metal and Phosphorous is a nonmetal so the bond is Ionic.
or
Electronegativity for Lithium = 0.98
Electronegativity for Phosphorous = 2.19
Difference of electronegativity = 1.21
As 1.21 > 1.7 the bond is Ionic.
At what temperature will a balloon have a volume of 6.08 L if the temperature is 41.0 ℃ when its volume is 4.87 L? Answer in Kelvin.
P.S please show the equation steps.
Answer:
392.20K
Explanation:
-We apply Charles' Law which states that for an ideal gas at constant pressure, its volume is directly proportional to it's temperature:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
-Given that:
[tex]V_1=4.87L, V_2=6.08\\\\T_1=41.0\textdegree C=314.15\ K\\T_2[/tex]
#We substitute in the ratio formula above and calculate for [tex]T_2[/tex]:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\T_2=\frac{V_2T_1}{V_1}\\\\=\frac{6.08\ l\times 314.15\ K}{4.87\ L}\\\\\\=392.20\ K[/tex]
Hence, the temperature of the balloon at a volume of 6.08L is 392.20K
3) Tarnished silver contains Ag2S. The tarnish can be removed by placing silverware in an aluminum pan containing an inert electrolyte Such as NaCl. Explain the electrochemical principle for this procedure. The standard reduction potential for the half-cell reaction: Ag2S (s) + 2e- 2Ag (s) + S-2 (aq) is -0.71 V
Tarnished silver ware is cleaned by placing it in an aluminium pan as E°cell is positive.
Explanation:
The tarnish silver due to silver sulphate is removed by placing the tarnished ware in an aluminium pan. Certainly, aluminium is a stronger reducing agent than silver. Hence, it reduces the silver ions(Ag+) to metallic silver. The silvery white white colour will slowly get deposited on the walls of silwer ware and then the tarnish will be removed.
Al(s)+ 3Ag+ (aq)→ Al3+ (aq)+ 3Ag(s)
E° cell = E ° cathode - E° anode
= (-0.71)- (-1.66) = 0.95 V is positive.
Hence, the reaction is feasible and the tarnish will be removed.
The electrochemical principle behind the procedure is aluminum is a strong reducing agent.
What is an electrochemical reaction?
Electrochemical reaction is the reaction in which the electrons flow between a solid electrode.
The reaction is [tex]Ag^2S (s) + 2e- 2Ag (s) + S-2 (aq) is -0.71 V[/tex]
E° cell = E ° cathode - E° anode
(-0.71)- (-1.66) = 0.95 V is positive.
Thus, the electrochemical principle behind the procedure is aluminum is a strong reducing agent.
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Find the molarity of a solution made from 275 g of CuSO4 dissolved in enough water to make 4.25 L.
0.405M is the molarity of a solution made from 275 g of CuSO[tex]_4[/tex] dissolved in enough water to make 4.25 L.
What is molarity?The amount of moles of solute multiplied by the amount of liters of solutions is the definition of molarity, a concentration unit in chemistry. It is crucial to comprehend how it is calculated as well as when to employ it in comparison to other units because it ranks among the most widely used concentration units.
A chemical solution's concentration is measured in molarity (M). It refers to the moles of solvent /100 liters of solution. To be clear, this is not the same as the liters of solvents (a common mistake).
molarity = moles of solute/ volume of solution
=(275 /159.6)1/4.25
= 0.405M
Therefore, 0.405M is the molarity of a solution made from 275 g of CuSO[tex]_4[/tex] dissolved in enough water to make 4.25 L.
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Final answer:
To calculate the molarity of a CuSO₄solution, first find the moles ofCuSO₄ by dividing its mass by the molar mass, then divide by the volume of the solution thats molarity is 0.0073225M.
Explanation:
To find the molarity of a solution made from 275 g oF CuSO₄ dissolved in enough water to make 4.25 L, follow these steps:
Calculate the number of moles of CuSO₄. Using the molar mass of CuSO₄ (159.61 g/mol), divide the mass of the solute by its molar mass:
moles ofCuSO₄= 275 g / 159.61 g/mol.
Divide the number of moles of CuSO₄ by the volume of the solution (in liters) to find the molarity:
Molarity (M) = moles of CuSO₄ / 4.25 L.
According to the following reaction, how many grams of hydrogen peroxide (H2O2) are needed to form 32.0 grams of oxygen gas?
Answer:
The answer to your question is 34 g of H₂O₂
Explanation:
Data
mass of H₂O₂ = ?
mass of O₂ = 32 g
Process
1.- Write the balanced chemical reaction
H₂O₂ ⇒ H₂ + O₂
2.- Calculate the molar mass of H₂O₂ and O₂
Molar mass H₂O₂ = (1 x 2) + (16 x 2) = 34 g
Molar mass of O₂ = 2 x 16 = 32 g
3.- Use proportions to calculate the mass of O₂
34g of H₂O₂ -------------- 32g of O₂
x -------------- 32g of O₂
x = (32 x 34) / 32
x = 34 g of H₂O₂
Which of the units is NOT a measure of pressure ?
Answer:
Dynes
Explanation:
Dynes is not a unit of pressure. Dynes is CGS unit of force.
Use the problem below to answer the question:
34 grams of carbon react with an unlimited amount of H2O. The reaction is:
C + H20 - CO + H2
Is this equation balanced?
Yes or No
Answer:
yes
Explanation:
yes
A sample of hydrogen gas is placed in a 0.500 L container at 295K. The gas pressure is 1.442 bar. How many moles of H2 gas are in the container.
Answer:
0.0294
Explanation:
To whomever gets this right i will give 68 points on the next question for them and the brainliest answer. NEED HELP!
Lithium's atomic number is 3. Fluorine's is 9. Explain how an atom of lithium and an atom of fluorine combine by ionic bonding.
Answer:
The answer to your question is below
Explanation:
The information given is not important to determine if the bond is ionic.
An ionic bond is when a metal and a nonmetal combine or when the electronegativity of the elements is higher than 1.7.
In this example, lithium is a metal and fluorine is a nonmetal so they will form an ionic compound.
Lithium is in group lA so it has 1 electron in its outermost shell.
Fluorine is in group VIIA so it has 7 electrons in its outermost shell.
Lithium donates one electron to fluorine so they become stable.
How did medical advances help Europeans imperialize?
Answer:
Doctors began to use sterilized medical
instruments; European and American
hospitals developed a standard of
cleanliness.
Explanation:
Medical advancements were pivotal in allowing Europeans to sustain imperial control in tropical regions by preventing diseases that previously hindered colonization. Additionally, medical superiority was used to justify imperialism and perpetuate colonial domination, although it often led to health disparities favoring the colonial elite.
Medical advances played a critical role in facilitating European imperial expansion into regions such as Africa, the Middle East, and Asia. The improvements in healthcare and the ability to manage and prevent tropical diseases allowed European soldiers and administrators to survive in environments that were previously inhospitable due to diseases like malaria. The global homogenization of disease also meant that European powers brought infectious diseases to colonized areas, which often had devastating effects on the local populations.
Technology afforded Europeans with advanced weapons and transportation, but medical technology specifically enabled them to maintain their imperial presence overseas. This, along with ideologies like Social Darwinism, justified their actions and supported the spread of imperialism. It also resulted in the unequal improvement of healthcare systems in colonized regions, favoring the urban elite over the rural poor.
Moreover, European dominance in medicine was used to demonstrate their supposed superior science. While European medical practices sometimes improved health outcomes for colonized populations, they also exploited these populations for research and reinforced colonial domination. Infrastructure, such as railroads and irrigation canals, while beneficial for the imperial powers' economic interests, also contributed to the spread of disease. In some cases, the introduction of diseases by Europeans led to high mortality rates among indigenous peoples, weakening resistance to imperial control.
2. How do chemical reactions involve energy?
Answer:Chemical reactions often involve changes in energy due to the breaking and formation of bonds. Reactions in which energy is released are exothermic reactions, while those that take in heat energy are endothermic. exothermicA description of a chemical reaction that releases heat energy to its surroundings.
How many moles of oxygen gas would be needed to completely burn 8 moles of
hydrogen sulfide?
Answer:
12 mol O2
Explanation:
This is assuming you're using a combustion equation of
2 H2S + 3O2 -> 2H2O + 2SO2
Next time include the equation because that is where you will find your mol to mol ratio
8 mol H2S x (3 mol O2 / 2 mol H2S) = 12 mol O2
Final answer:
To completely burn 8 moles of hydrogen sulfide, 12 moles of oxygen gas are required according to the stoichiometry of the balanced chemical equation.
Explanation:
The question is asking how many moles of oxygen gas (O₂) are required to completely burn 8 moles of hydrogen sulfide (H₂S). The balanced chemical equation for the reaction of hydrogen sulfide with oxygen is:
2 H₂S(g) + 3 O₂(g) → 2 SO₂(g) + 2 H₂O(g)
From the balanced equation, we see that 2 moles of H₂S react with 3 moles of O₂. To find out how many moles of O₂ are needed for 8 moles of H₂S, we can set up a proportion:
(3 moles O₂ / 2 moles H₂S) = (x moles O₂ / 8 moles H₂S)
Solving for x gives us:
x = (3 moles O₂ / 2 moles H₂S) × 8 moles H₂S
x = 12 moles O₂
Therefore, 12 moles of oxygen gas are required to completely burn 8 moles of hydrogen sulfide.
A sample of ammonia gas occupies 23.6 mL at 527 mm Hg and 24.6oC. If the volume of the gas is changed to 53.9 mL at 56.7oC, what is the new pressure?
Answer:
The new pressure is 255.6 mmHg
Explanation:
Step 1:Data given
Volume of the ammonia gas = 23.6 mL = 0.0236 L
Pressure of the ammonia gas = 527 mmHg
The temperature is 24.6 °C = 297.75 K
The volume increases to 53.9 mL
The increases to 56.7 °C = 329.85 K
Step 2: Calculate the new pressure
(P1*V1)/T1 = (P2*V2)/T2
⇒with P1 = the initial pressure ofammonia gas = 527 mmHg
⇒with V1 = the initial Volume of ammonia gas = 23.6 mL = 0.0236 L
⇒with T1 = the initial temperature = 297.75 K
⇒with P2 = the new pressure = TO BE DETERMINED
⇒with V2 = the increased volume = 0.0539 L
⇒with T2 = the increased temperature = 329.85 K
527 mmHg * 0.0236 L / 297.75 K = P2* 0.0539 L / 329.85 K
0.04177 = P2* 0.0539 L / 329.85 K
P2 * 0.0539 = 13.778
P2 = 255.6 mmHg
The new pressure is 255.6 mmHg
If 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius, what is the final temperature of the water?
Answer:49.3
Explanation:4.1j/g c * 25g * (t2-45c)=455j
T2-45c = 455j/4.1j/g c * 25g
455/104.6
45+4.3= 49.3 celsius
The final temperature of water if 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius is 63.2°C.
How to calculate final temperature?The final temperature of water can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperatureAccording to this question, 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius.
455 = 25 × (T - 45)
455 = 25T - 1125
25T = 1580
T = 63.2°C
Therefore, the final temperature of water if 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius is 63.2°C.
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Which of the following is the answer that illustrates a single replacement reaction?
Answer:
The answer to your question is the letter B.
Explanation:
Data
Single replacement reaction
Definition
A single replacement reaction consists most of the times of a metal that reacts with a compound and this metal replaces the cation of the compound.
The options show
A. A synthesis reaction
B. A single replacement reaction
C. A double replacement reaction
D. A double replacement reaction
Fe + CuSO4 → Cu + FeSO4, is an example of a Single-Replacement Reactions. In this reaction, the iron (Fe) displaces copper (Cu) from the copper sulfate (CuSO4), forming copper (Cu) and iron sulfate (FeSO4).
The question posed asks for an example of a single-replacement reaction.
These types of reactions, also known as substitution or single-displacement reactions, are characterized by an element being displaced from a compound by another element.
In this case, the answer option that fits this category is Fe + CuSO4 → Cu + FeSO4.
Here, the iron (Fe) displaces the copper (Cu) in the solute copper sulfate (CuSO4), thereby forming copper (Cu) and iron sulfate (FeSO4).
This example clearly represents the concept and characteristics of a single-replacement reaction.
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When 0.610 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °C to 50.50 °C. In a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kJ/K. What is the enthalpy change for the reaction in kJ per mole of Ti?
Answer:
(ΔHrxn)= 0.15kJ/mol
Explanation:
(ΔHrxn) = mc∆t
=0.00061×9.84×(50.5-25)
= 0.153kJ/mol
To calculate the enthalpy change for the combustion of titanium in a bomb calorimeter, first calculate the total heat absorbed by the calorimeter, then divide this by the moles of titanium combusted. The result is an approximate value of 19688.85 kJ per mole of Titanium combusted, indicating an exothermic reaction.
Explanation:The subject here relates to thermochemistry, specifically calorimetry and the calculation of enthalpy change. First, we calculate the heat absorbed by a bomb calorimeter when the temperature increases, using the formula heat = heat capacity * delta_Temperature. Given in the question, heat capacity = 9.84 kJ/K and delta_Temperature = 50.50°C - 25.00°C = 25.5K. The heat absorbed by the calorimeter is therefore 9.84 kJ/K * 25.5K = 250.92 kJ.
This heat is equivalent to the heat released by the combustion of 0.610g of Titanium. To find the enthalpy change per mole of Titanium, we should first convert the mass of Titanium to moles using the atomic weight of Titanium (47.867 g/mol). 0.610g is about 0.01274 mol of Titanium. Finally, we find the enthalpy change per mole by dividing total heat by the number of moles, giving us 250.92 kJ / 0.01274 mol = 19688.85 kJ/mol.
This suggests that the process is highly exothermic, as when 1 mole of Titanium is combusted, it releases around 19688.85 kJ of energy.
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How many grams of MgBr2 are in 4.3x10^23 atoms of MgBr2??
Answer:
The answer to your question is 131.43 grams of MgBr₂
Explanation:
Data
number of grams = ?
number of atoms = 4.3 x 10²³
Molecule = MgBr₂
Process
1.- Calculate the molar mass of MgBr₂
MgBr₂ = 24.3 + (79.9 x 2) = 24.3 + 159.8 = 184.1 g
2.- Use proportions to calculate the number of atoms
184.1 g of MgBr₂ -------------- 6.023 x 10²³ atoms
x -------------- 4.3 x 10²³ atoms
x = (4.3 x 10²³ x 184.1) / 6.023 x 10²³
x = 7.92 x 10²⁵ / 6.023 x 10²³
x = 131.43 grams
Given AgNO 3 (aq) + NaCl(aq)→ AgCl(s) + NaNO 3 (aq), if titration of 30.00 mL of the solution with 0.2503 M AgNO3 requires 20.22 mL, of NaCl to reach the end point, what is the concentration of NaCl in the solution?
Answer:
0.3714 M
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
AgNO3 (aq) + NaCl (aq) -> AgCl(s) +
NaNO3 (aq)
Step 2:
Determination of the number of moles of AgNO3 in 30.00 mL of 0.2503 M AgNO3. This is illustrated below:
Molarity of AgNO3 = 0.2503 M
Volume of solution = 30mL = 30/1000 = 0.03L
Number of mole of AgNO3 =?
Molarity = mole /Volume
0.2503 = mole / 0.03
Cross multiply to express in linear form
Mole = 0.2503 x 0.03
Mole of AgNO3 = 7.509x10^-3 mole
Step 3:
Determination of the number of mole of NaCl required to react with AgNO3. This is illustrated below:
AgNO3 (aq) + NaCl (aq) -> AgCl(s) +
NaNO3 (aq)
From the balanced equation above,
1 mole of AgNO3 required 1 mole of NaCl for complete neutralization.
Therefore, 7.509x10^-3 mole of AgNO3 will also require 7.509x10^-3 mole of NaCl for complete neutralization.
Step 4:
Determination of the molarity of NaCl. This is illustrated below:
Mole of NaCl = 7.509x10^-3 mole
Volume of solution = 20.22 mL = 20.22/1000 = 0.02022L
Molarity =?
Molarity = mole /Volume
Molarity of NaCl = 7.509x10^-3/0.02022
Molarity of NaCl = 0.3714 M
Answer:
The concentration of NaCl in the solution is 0.371 M
Explanation:
Step 1: Data given
Volume of 0.2503 M AgNO3 solution = 30.00 mL = 0.030 L
Volume of NaCl = 20.22 mL = 0.02022 L
Step 2: The balanced equation
AgNO3(aq) + NaCl(aq) ===> AgCl(s) + NaNO3(aq)
Step 3: Calculate concentration of NaCl
C1*V1 = C2*V2
⇒with C1 = the concentration of AgNO3 = 0.2503 M
⇒with V1= the volume of AgNO3 = 0.030 L
⇒with C2 = the concentration of NaCl = TO BE DETERMINED
⇒with V2 = the volume of NaCl = 0.02022 L
0.2503 M * 0.030 L = C2 * 0.02022L
C2 = (0.2503 * 0.030) / 0.02022
C2 = 0.371 M
The concentration of NaCl in the solution is 0.371 M
Drag the appropriate labels to their respective targets. use only pink labels for pink targets and gray labels for gray targets. resethelp more nucleophilic than less nucleophilic than about as nucleophilic as s is smaller than o s is larger than o s and o are about the same size s is better solvated than o s is less well solvated than o s is about as well solvated as o submitrequest answer
Answer:
The correct option is;
S is more nucleophiclic than O because S is larger than O therefore S is less well solvated than O
Explanation:
Here we have
As the size of atoms increases, the basicity increases and the nucleophilicity increases. Therefore since S is larger than O it is more nucleophilic than O.
Also we have smaller nucleophiles are more solvated than larger nucleophiles therefore S is less well solvated than O.
Which gives the correct answer as;
S is more nucleophiclic than O because S is larger than O therefore S is less well solvated than O.
A nucleophile is a molecule or ion that donates an electron pair to form a new covalent bond, while an electrophile accepts an electron pair to form a new covalent bond.
Explanation:A nucleophile is a molecule or ion that donates an electron pair to form a new covalent bond. An electrophile is a molecule or ion that accepts an electron pair to form a new covalent bond. Nucleophiles are typically more nucleophilic than electrophiles due to the presence of a lone pair of electrons. The nucleophilicity of a nucleophile can be influenced by factors such as electronegativity and steric hindrance.
For example, in a reaction between a nucleophile and an electrophile, the nucleophile attacks the electrophilic center, forming a new bond and displacing a leaving group. The nucleophile is usually a lone pair donor, such as an anion or a molecule with a lone pair of electrons, while the electrophile is typically an atom or molecule with a partially positive charge.
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Please help me right now
If the surface area of a substance increases,the rate of dissolving will _____ ????
Answer:
decrease
Explanation:
If the surface area of a substance increases, the rate of dissolving will increase due to more frequent and effective collisions between the solvent molecules and solute particles.
This effect happens because dissolution is a surface phenomenon, where solvent molecules must collide with the outer surface of the solute. More surface area means more opportunities for these collisions. For instance, powdered CaCO₃ will react faster with HCI than a lump of CaCO₃ because the increased surface area allows more particles to be in contact with the acid, leading to more frequent collisions. Furthermore, an effervescent tablet will dissolve more rapidly when broken into smaller pieces since the available surface area for reaction is increased.
Additionally, the rate of dissolution is influenced by factors such as agitation and temperature. Stirring or shaking a solution can facilitate solute particles contact with solvent, thus increasing dissolution rate. Similarly, dissolving a substance in a warmer solvent can lead to faster dissolution due to increased molecule's kinetic energy.
a force of 20 N acts upon 5 kg block caculate the accerleration of the object
Answer:
[tex]\boxed{\text{4 m $\cdot$ s$^{-2}$}}[/tex]
Explanation:
F = ma
[tex]a = \dfrac{F}{m} = \dfrac{\text{20 N}}{\text{5 kg}} \times \dfrac{\text{1 kg$\cdot$ m $\cdot$ s$^{-2}$}}{\text{1 N}} = \text{4 m $\cdot$ s$^{-2}$}\\\\\text{The acceleration of the object is } \boxed{\textbf{4 m $\cdot$ s$^{\mathbf{-2}}$}}[/tex]
Michael drove 36 000 s at 65 km/hr. How far did Michael drive in meters? Show each step of the process and use correct significant digits and units in your final answer. You must write this out as one long calculation in order to get full marks. *
The Michael drove 648,000 m.
Explanation:
It is given that the time taken by Michael, that is t = 36000 s
Speed is nothing but distance traveled by the time taken in seconds. Its unit is m/s.
Here we have the speed in km/hr, we have to convert it to m/s as,
1 km = 1000 m
1 hr = 3600 s
So it is converted as,
[tex]$\frac{65 \times 1000}{3600}[/tex]
= 18 m/s
Now we have the speed in m/s.
18 m/s = [tex]$\frac{x m}{36000s}[/tex]
We can find the distance x as = 18 m/s ×36000 s = 648,000 m
So the Michael drive 648,000 m.
is 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O a double replacement?
The reaction in question is a combustion reaction involving butane and oxygen, producing carbon dioxide and water; it is not a double replacement reaction.
Explanation:The equation 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O represents a combustion reaction, not a double replacement reaction. In a double replacement reaction, two compounds exchange parts to form two new compounds. However, in the given reaction, butane (C4H10) reacts with oxygen (O2) in a combustion process to produce carbon dioxide (CO2) and water (H2O), which is typical for hydrocarbons burning in an oxygen-rich environment.
For example, a double replacement reaction is demonstrated by the equation Ca(NO3)2 + KBr → CaBr2 + 2 KNO3, where the cations Ca^2+ and K+ switch places between the anions NO3^- and Br^-, forming two new compounds: calcium bromide and potassium nitrate.