-px+r=-8x-2 solve for x.

Answer:

z-score

Step-by-step explanation:

Z-score gives the relative value of any data population in relation to its mean. It depicts at what distance any data is from the mean. In technical terms it can be termed as the number of times a data is data away from the mean. Positive value of z score means value is more than mean while a negative value signifies data is less than that of mean.

Z – score is primarily used in qualitative analysis of numerical data by the statistician after data is arranged in normal distribution form. Z score of 0 means the value is same as mean while z-score of value 1 means data is one standard deviation away from the mean.

The z-score is the measure that determines the distance of a value from the mean in terms of standard deviations which is option c.

A z-score determines how far a particular value is from the mean relative to the data set's standard deviation. Given an experimental value, X, the mean, μ (mu), and the standard deviation, σ (sigma), the z-score is calculated using the formula Z = (X - μ) / σ. A z-score represents the number of standard deviations an experimental value is above or below the mean. For example, if a data value has a z-score of 2, it is two standard deviations above the mean. Contrarily, a z-score of -1.5 indicates that the value is one and a half standard deviations below the mean. Z-scores are used across various fields to compare different values within a data set or among different data sets with different means and standard deviations.

Answer:

a) 1/6

b) 3/8

Step-by-step explanation:

Even i struggle with fractions but im sure you will get it one day (✿◡‿◡)

Answer:

T(n) = cn +(a-c)

Step-by-step explanation:

Note that T(1) = a, then T(2) = a+c, T(3) = (a+c)+c = a+2c, T(4) = (a+2c)+c = a+3c. Thus, our hypotheis is that T(n) = a+(n-1)c. We will prove this by strong induction.

Note that T(1) = a = a+(1-1)c. So the base case is proved. Assume that the result is true for all k<n. Then

T(n) = T(n-1)+c = (a+(n-2)c)+c = a+(n-1)c= cn+ (a-c).

So, by induction, the result holds.

Note that if a=1 and c = 3 then T(n) = 1+(n-1)3 = 3n-3+1 = 3n-2, which invalidates option b)

If a=3 and c=5 then we have that T(n) = 5n+(3-5) = 5n-2, which invalidates c) and d).

Then the formula is correct.

Answer:

(a) is correct

[tex]T(n) = a+(n-1)c[/tex]

Step-by-step explanation:

Notice that according to the information that you are given

[tex]T(1)=a \\T(2)=T(1)+c = a+c\\T(3)=T(2)+c = a+c+c = a+2c[/tex]

If you think about it there is a clear pattern, it would be

[tex]T(n) = a+(n-1)c[/tex]

Now notice that (a) is correct  if we set a=1 and c=3 we get

[tex]T(n) = 1+3(n-1) = 3n-2[/tex]

Answer:

Probability that a randomly selected bill will be at least $39.10 is 0.03216.

Step-by-step explanation:

We are given that the daily dinner bills in a local restaurant are normally distributed with a mean of $28 and a standard deviation of $6.

Let X = daily dinner bills in a local restaurant

So, X ~ N([tex]\mu=28,\sigma^{2} =6^{2}[/tex])

The z-score probability distribution for normal distribution is given by;

               Z = [tex]\frac{ X -\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = mean amount = $28

            [tex]\sigma[/tex] = standard deviation = $6

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, the probability that a randomly selected bill will be at least $39.10 is given by = P(X [tex]\geq[/tex] $39.10)

  P(X [tex]\geq[/tex] $39.10) = P( [tex]\frac{ X -\mu}{\sigma}[/tex] [tex]\geq[/tex] [tex]\frac{ 39.10-28}{6}[/tex] ) = P(Z [tex]\geq[/tex] 1.85) = 1 - P(Z < 1.85)

                                                           = 1 - 0.96784 = 0.03216

Now, in the z table the P(Z [tex]\leq[/tex] x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.85 in the z table which has an area of 0.96784.

Hence, the probability that a randomly selected bill will be at least $39.10 is 0.03216.

The probability that a randomly selected bill will be at least $39.10 is approximately 0.0323.

First, we calculate the z-score for a bill of $39.10 using the formula:

[tex]\[ z = \frac{X - \mu}{\sigma} \][/tex]

where X is the value for which we want to find the probability, [tex]\( \mu \)[/tex] is the mean, and [tex]\( \sigma \)[/tex] is the standard deviation.

Given:

[tex]\[ \mu = 28 \] \[ \sigma = 6 \] \[ X = 39.10 \][/tex]

Plugging in the values:

[tex]\[ z = \frac{39.10 - 28}{6} \] \[ z = \frac{11.10}{6} \] \[ z \approx 1.85 \][/tex]

Now, we look up the z-score of 1.85 in the standard normal distribution table or use a calculator to find the probability of a z-score being at least 1.85. This gives us the area to the right of the z-score on the standard normal curve.

Using a standard normal distribution table or calculator, we find:

[tex]\[ P(Z \geq 1.85) \approx 0.0323 \][/tex]

Answer:

The answer is 30% off

Step-by-step explanation:

if you do 21.50 - 30% = 15.05

Answer:

393/1000

Step-by-step explanation:

Answer:

Step-by-step explanation:

393/1000

Answer:

315

Step-by-step explanation:

The missing percentages of the given scenario are;

Adventure Games: 22%

Puzzles: 28%

Card Games: 30%

Arcade Games: 9%

Board Games: 11%

So in order to solve the problem, we simply use the pie chart distributions to get the result

Now if look at the percentages, we that card games percentage is 30 while arcade games is 9 so, 21 % of people play more card games.

In terms of number of people = 21/100 x 1500 = 315

Hence out of 1500, 315 people play card games more than arcade

Answer:

The number of more people that played card games than arcade games is 150 people

Step-by-step explanation:

Here  we have a pie chart showing games people play in the following proportions

Assumption; Card games = 49%

Arcade games = 32%

Classic = 15%

Kids = 4%

Therefore. if 49%  played card games, we have 49% of 1500 which is 735 people, while 32% that played arcade games, we have 39% of 1500 = 0.39×1500 = 585

Therefore, the number of more people that played card games than arcade games = 735 - 585 = 150 people.

Answer:

-2 and 4

Step-by-step explanation:

When you look for values that make an expression “illegal” the first step is to look for 3 things.

1) a variable in a denominator

- we have b, a variable, in the denominator of this expression

- values in the denominator cannot be 0

2) variables under even roots

- variables under even roots are a restriction because even roots are undefined when there are negative values under them

- there are no roots in this case so we dont have to worry about that

3) the literal letters: “log” in the expression

- there’s no “log” in the expression so we dont have to worry about that

—moving on—

We have a variable in the denominator, b.

The expression is a quadratic:

b^2 - 2b - 8

You have to find values that make this quadratic 0.

So you can make an equation setting the quadratics equal to 0.

b^2 - 2b - 8 = 0

Solve for b

Factor:

(b - 4)(b + 2) = 0

Because of zero product property we can say:

b = -2, b = 4.

If these values are plugged into your expression, it will be “illegal,” or “undefined,”

Answer:

a) The volume of S is 34.13

b) The volume of S is 14.8

c) The volume of S is 5.17

d) The volume of S is 11.33

Step-by-step explanation:

a) The cross section area is equal to:

[tex]A=a^{2} =((5x-x^{2})-x)^{2} =(4x-x^{2} )^{2}[/tex]

The volume of S is equal to:

[tex]Vol_{S} =\int\limits^4_0 {A(x)} \, dx =\int\limits^4_0 {(4x-x^{2})^{2} } \, dx =34.13[/tex]

b) The cross section area is equal to:

[tex]A=\frac{a^{2}\sqrt{3} }{4} =\frac{\sqrt{3} }{4} ((5x-x^{2} )-x)^{2} =\frac{\sqrt{3} }{4} (4x-x^{2} )^{2}[/tex]

The volume of S is equal to:

[tex]Vol_{S} =\int\limits^4_0 {A(x)} \, dx =\frac{\sqrt{3} }{4} \int\limits^4_0 {(4x-x^{2})^{2} } \, dx =14.8[/tex]

c)

[tex]y=5x-x^{2} \\\frac{dy}{dx} =0\\5x-x^{2} =0\\x=5/2\\y(5/2)=25/4\\y=5x-x^{2} \\x^{2} -5x+y=0\\x=\frac{5+-\sqrt{25-4y} }{2}[/tex]

The cross section area is equal to:

[tex]A_{1} =\frac{1}{2} \pi r_{1}^{2} =\frac{1}{2} \pi (\frac{1}{2} (\frac{5+\sqrt{25-4y} }{2} -\frac{5-\sqrt{25-4y} }{2} ))^{2} =\frac{1}{8} \pi (25-4y)\\A_{2} =\frac{1}{2} \pi r_{2}^{2}=\frac{1}{2}\pi (\frac{1}{2} (y-\frac{5-\sqrt{25-4y} }{2} ))^{2} =\frac{1}{32} \pi (2y-5+\sqrt{25-4y} )^{2}[/tex]

The volume of S is equal to:

[tex]Vol_{S} =\int\limits^a_b {A_{1}(y) } \, dy+\int\limits^4_0 {A_{2}(y) } \, dy ,where-a=25/4,b=4\\Vol_{S} =\int\limits^a_b {\frac{1}{8}\pi (25-4y)} \, dy +\int\limits^a_b {\frac{1}{32}\pi (2y-5+\sqrt{25-4y} )^{2} } \, dy =5.17[/tex]

d) The cross section area is:

[tex]A_{1} =\frac{1}{2}ab=\frac{1}{2} a^{2} =\frac{1}{2} (\frac{5+\sqrt{25-4y} }{2}-\frac{5-\sqrt{25-4y}}{2} )^{2} =\frac{1}{2} (25-4y)\\A_{1}=\frac{1}{2}ab=\frac{1}{2} a^{2} =\frac{1}{2}(y-\frac{5-\sqrt{25-4y}}{2}} )^{2} =\frac{1}{8} (2y-5+\sqrt{25-4y}})^{2}[/tex]

The volume of S is equal to:

[tex]Vol_{S} =\int\limits^a_b {A_{1}(y) } \, dy +\int\limits^4_0 {A_{2}(y) } \, dy ,where-a=25/4,b=4\\Vol_{S}=\int\limits^a_b {\frac{1}{2}(25-4y) } \, dy +\int\limits^4_0 {\frac{1}{8}(2y-5+\sqrt{25-4y})^{2} } \, dy =11.33[/tex]

Answer:

We conclude that the true percentage of those in the first group who suffer a second episode is less than or equal to the true percentage of those in the second group who suffer a second episode.

Step-by-step explanation:

We are given that there are 31 people in the first group and this group will be administered the new drug. There are 45 people in the second group and this group will be administered a placebo.

After one year, 11% of the first group has a second episode and 9% of the second group has a second episode.

Let [tex]p_1[/tex] = true percentage of those in the first group who suffer a second episode.

[tex]p_2[/tex] = true percentage of those in the second group who suffer a second episode.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1-p_2\leq[/tex] 0  or  [tex]p_1\leq p_2[/tex]      {means that the true percentage of those in the first group who suffer a second episode is less than or equal to the true percentage of those in the second group who suffer a second episode}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1-p_2[/tex] > 0  or  [tex]p_1>p_2[/tex]      {means that the true percentage of those in the first group who suffer a second episode is more than the true percentage of those in the second group who suffer a second episode}

The test statistics that will be used here is Two-sample z proportion test statistics;

                              T.S. = [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex]  ~ N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of people in the first group who suffer a second episode = 11%

[tex]\hat p_2[/tex] = sample proportion of people in the second group who suffer a second episode = 9%

[tex]n_1[/tex] = sample of people in first group = 31

[tex]n_2[/tex] = sample of people in second group = 45

So, the test statistics  =  [tex]\frac{(0.11-0.09)-(0)}{\sqrt{\frac{0.11(1-0.11)}{31}+ \frac{0.09(1-0.09)}{45}} }[/tex]

                                     =  0.283

Now, at 0.1 significance level, the z table gives critical value of 1.2816 for right-tailed test. Since our test statistics is less than the critical value of z as 0.283 < 1.2816, so we have insufficient evidence to reject our null hypothesis due to which we fail to reject our null hypothesis.

Therefore, we conclude that the true percentage of those in the first group who suffer a second episode is less than or equal to the true percentage of those in the second group who suffer a second episode.

A hypothesis test can determine whether there is enough evidence to support the claim that the new drug is effective in reducing second episodes of heartburn. It involves defining null and alternative hypotheses, calculating a test statistic, and comparing it to a critical value based on the set significance level.

We start by defining our null and alternative hypotheses. In this case, we are testing against the claim that the true percentage of those in the first group who suffer a second episode is more than the true percentage of those in the second group who suffer a second episode.

So, our null hypothesis (H0) is: The percentage of heart attempts in group 1 is equal to or less than that of group 2.

And, our alternative hypothesis (Ha) is: The percentage of heart attempts in group 1 is greater than that of group 2.

We conduct the hypothesis test using a standard test of proportions. Calculating our test statistic can be done using the formula: Z = (p1 - p2)/sqrt(p(1 - p)[(1/n1) + (1/n2)])

Where, p1 and p2 are the proportions of the two groups, n1 and n2 are the sizes of the two groups, and p is the combined proportion.

Based on the information in the problem, the calculated test statistic value and the critical z-value for a one-tailed test at the significance level 0.1, we can make a decision to reject or fail to reject the null hypothesis. If the calculated absolute z-value is greater than the critical z-value, we reject the null hypothesis and conclude that there is enough evidence at the 0.1 level. Otherwise, we fail to reject the null hypothesis and conclude that there is not enough evidence to support the claim.

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Answer:

There are many possible solutions. For example,

(2^3)^4 = ((2^5)^12)/((2^6)^8) = 2^10 x 2^2 = (2^19)/(2^7)

(2^2)^5 = ((2^6)^11)/((2^7)^8) = 2^1 x 2^9 = (2^20)/(2^10)

Step-by-step explanation:

You need to fill in boxes with the digits 1 to 20 to create equations where both sides yield the same numerical result. This will involve understanding of basic arithmetic operations and a bit of trial and error.

The subject of this question is Mathematics. Specifically, it relates to the concept of equivalent expressions, which are an essential component of algebra and arithmetic. First, it's crucial to understand the concept of equivalent expressions: two expressions are considered equivalent if they share the same numerical value for each possible value of their variable(s).

Now, let's make an example with the numbers 1 to 10 (just to simplify the explanation). Consider the equations: 1+2+3+4 and 5+3+2+1. Even though the order of operations is different, both expressions yield the final numerical value of 10, making them equivalent expressions.

In the context of the question, you are being asked to fill in boxes with the digits 1-20, such that the expressions on either side of the equation sign are equivalent. This might involve a combination of operations like addition, subtraction, multiplication, and division.

It's a challenging task because it involves a bit of trial and error. Start by deciding on the operations for the expressions and then fill in the numbers. Make sure you check your results by calculating the numerical value of each expression.

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Answer:

  x = 9

Step-by-step explanation:

The perimeter is the sum of the lengths of the base and the two equal legs:

  51 = x + 2(3x -6)

  51 = 7x -12 . . . . . eliminate parentheses

  63 = 7x . . . . . . . . add 12

  9 = x . . . . . . . . . . divide by 7

The surface area of the three dimensional solid is 72 square centimeters and its three dimensional diagram is attached.

Step-by-step explanation:

The given is,

                 Detailed view or net diagram of the three dimensional diagram.

Step:1

                Three dimensional diagram of the given net diagram is attached.  

                From the three dimensional diagram given net diagram is rectangular prism.

Step:2

                 From the three dimensional diagram

                 Formula for surface area of the rectangular prism,

                                       [tex]A = 2(wl + lh + hw)[/tex]..............................(1)

                 Where, w - Width

                                l - Length

                               h - Height

                 From the attachment,

                               l = 6 cm

                              w = 2 cm

                               h = 3 cm                

                 Equation (1) becomes,

                              [tex]A = 2((6)(2) + (6)(3) + (3)(2))[/tex]

                                   = 2 ( 12 + 18 + 6 )

                                   = 2 ( 36 )

                               A = 72 squared centimeters

                                  ( or )

                 From the net diagram,

                 Surface area, A = ((6×3)+(2×3)+(2×6)+(2×3)+(3×6)+(2×6))

                                            = 18 + 6 + 12 + 6 + 18 + 12

                                            = 72

                Surface area, A = 72 squared centimeters

Result:

          The surface area of the three dimensional solid is 72 square centimeters and its three dimensional diagram is attached.

Answer:72 cm2

Step-by-step explanation:

Answer:

Type II error will be made if we conclude that the new advertising campaign does not increases the sales when in fact the sales are increased after the advertising campaign.

Step-by-step explanation:

A type II error is a statistical word used within the circumstance of hypothesis testing that defines the error that take place when one is unsuccessful to discard a null hypothesis that is truly false. It is symbolized by β i.e.  

β = Probability of accepting H₀ when H₀ is false.

In this case we need to test the hypothesis whether the new advertising campaign increases the sales or not.

The hypothesis can be defined as:

H₀: The new advertising campaign does not increases the sales.

Hₐ: The new advertising campaign increases the sales.

The confidence level wanted here is 99%.

The type II error will be made if we conclude that the new advertising campaign does not increases the sales when in fact the sales are increased after the advertising campaign.

The type II error could have been made because of the following reasons:

Thus, the type II error might have been committed because of small sample size or small significance level.

Answer:

0.2460 = 24.60% probability that the mean weight of the sample of cows would differ from the population mean by more than 11 lbs if 116 cows are sampled at random from the herd.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation(which is the square root of the variance) [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

[tex]\mu = 1217, \sigma = \sqrt{10414} = 102, n = 116, s = \frac{102}{\sqrt{116}} = 9.475[/tex]

What is the probability that the mean weight of the sample of cows would differ from the population mean by more than 11 lbs if 116 cows are sampled at random from the herd?

This is 2 multiplied by the pvalue of Z when X = 1217 - 11 = 1206. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{1206 - 1217}{9.475}[/tex]

[tex]Z = -1.16[/tex]

[tex]Z = -1.16[/tex] has a pvalue of 0.1230

2*0.1230 = 0.2460

0.2460 = 24.60% probability that the mean weight of the sample of cows would differ from the population mean by more than 11 lbs if 116 cows are sampled at random from the herd.

To calculate the probability, we can use the Central Limit Theorem. Calculate the standard error using the formula: standard error = standard deviation / sqrt(n), then use the z-score formula to find the probability.

To find the probability that the mean weight of the sample of cows would differ from the population mean by more than 11 lbs, we can use the Central Limit Theorem. Since the sample size is large (n > 30), the distribution of sample means will be approximately normally distributed. First, we calculate the standard deviation of the sampling distribution, also known as the standard error, using the formula: standard error = standard deviation / sqrt(n). In this case, the standard error is sqrt(10404)/sqrt(116).

Finally, we can use the z-score formula to calculate the probability. The z-score is given by z = (x - mean) / standard error. We want to find the probability that the mean weight differs from the population mean by more than 11 lbs, so we calculate the z-score for both 11 and -11 and use the z-table or a calculator to find the probability of z being greater than the positive z-score and less than the negative z-score. Adding these two probabilities gives us the final answer.

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Answer:

A is correct, 7 units. Hope this helps! :)

Answer:

11/5 =x

Step-by-step explanation:

3(4 – 2x) = -x+1

Distribute

12 -6x = -x+1

Add 6x to each side

12 -6x+6x = 6x-x +1

12 = 5x +1

Subtract 1 from each side

12-1 = 5x+1-1

11= 5x

Divide each side by 5

11/5 =5x/5

11/5 =x

Steps to solve:

3(4 - 2x) = -x + 1

~Distribute

(3 * 4) + (3 * -2x) = -x + 1

~Simplify

12 - 6x = -x + 1

~Subtract 12 to both sides

12 - 12 - 6x = -x + 1 - 12

~Simplify

-6x = -x - 11

~Add x to both sides

-6x + x = -x + x - 11

~Simplify

-5x = -11

~Divide -5 to both sides

-5x/-5 = -11/-5

~Simplify

x = 11/5

Best of Luck!

Answer:

Step-by-step explanation:

.01 (subtract confidence level from 100)

Answer:

a) add a dummy stroke to make the problem as an assignment problem of adding 5 strokes to 5 swimmers. see first attachment.

b) applying the Hungarian method.

   4.8      0     0.9     4.1     2.5

   10.3     0     9.1      1.6     8.7

   4.8      0     10.4    1.9     5.1

   2.8      0     3.2     2.1     4.7

      0      0      0        0       0  

Deduct the smallest element in each column from the other elements of the column.

   2      0     0       2.5    0

   7.5   0     8.2    0       6.2

   2      0     9.5    0.3    2.6

   0      0     2.3    0.5    2.2

   0      0     0       0       0  

Which implies:      

   2            8.2    2.5    6.2

   7.5         9.5    0.3    2.6

   2            2.3    0.5    2.2

33.8 + 34.7 + 28.5 + 29.2 = 126.2

David = Back Stroke

tony = Breast Stroke

Chris = Butterfly

Carl = Free Style

The question is about assigning swimmers in a team to different strokes to achieve the best total time. It's a combinatorial optimization problem which can be solved by considering all the permutations of swimmers' assignments to each stroke and selecting the one with least total time.

The subject of this question is an optimization problem in Mathematics, specifically in the field of Combinatorics. Deciding the arrangement of swimmers to minimize the total time spent can be approached using techniques from this field. Unfortunately, the information provided does not give the exact times of the swimmers, so achieving a detailed solution isn't possible. However, the problem could hypothetically be solved by enumerating all possible assignments of swimmers to strokes and selecting the assignment that has the least total time.

This problem resonates with high school level math, where students begin to tackle optimization problems and permutations.

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Answer: a) 21 cans

b) 10.83 square inches.

Step-by-step explanation:

The cans are cylinders of 4 and 1/4 inches tall (or 4.25 in)

and the diameter is 3 inches.

The surface of a cylinder is equal to:

S = pi*r^2 + h*2*pi*r

where r is the radius, half of the diameter, so we have that r = 3in/2 = 1.5 in.

h is the height, h = 4.25 in

pi = 3.14

Then the surface needed for a can is:

S = 3.14*1.5^2 + 4.25*2*3.14*1.5 = 47.1 square inches.

if the sheet is 1000 in^2, we can make an amount of:

N = 1000/47.1 = 21.23  

but we can not do a 0.23 of a can, so we need to round down.

A) we can make 21 cans out of a sheet of metal.

B) the 0.23 of a can that we removed earlier is the amount of metal leftover. The total is 0.23*47.1 in^2 = 10.83 in^2

Answer:

Step-by-step explanation:

To determine the amount of metal needed to make each can, we would determine the total surface area of each can. Since the cans are cylindrical, the formula for determining the total surface area of a cylinder is used. It is expressed as

Total surface area = πr² + 2πr

r = radius of the can

h = height of the can

π = 3.14

From information given,

Diameter = 4.25 inches

Radius = diameter/2 = 4.25/2 = 2.125 inches

Total surface area = 3.14 × 2.125² + 2 × 3.14 × 2.125 = 27.5 in²

1) since 1000 in² sheet material is available, the number of cans that can be made is

1000/27.5240625 = 36 cans

2) The amount of metal sheet left is

1000 - (36 × 27.5) = 10 in²

Answer:

where are the angles? I can't see anything

Answer:

Please provide pictures!!

Step-by-step explanation:

Answer:

The answer is d: LINE D AND LINE E

The other answer is c LINE A AND LINE B

Step-by-step explanation:

Answer: These would be my two thoughts.

Step-by-step explanation:

ANSWER #1.    15-8= 7

ANSWER #2.    3-8= -5

Answer:

$0.90 per kilogram

Step-by-step explanation:

4.5/5=.9

If a polynomial "contains", in a multiplicative sense, a factor [tex](x-x_0)[/tex], then the polynomial has a zero at [tex]x=x_0[/tex].

So, you polynomial must contain at least the following:

[tex](x-(-2)),\quad (x-0),\quad (x-3),\quad (x-5)[/tex]

If you multiply them all, you get

[tex]x(x+2)(x-3)(x-5)=x^4 - 6 x^3 - x^2 + 30 x[/tex]

Now, if you want the polynomial to be zero only and exactly at the four points you've given, you can choose every polynomial that is a multiple (numerically speaking) of this one. For example, you can multiply it by 2, 3, or -14.

If you want the polynomial to be zero at least at the four points you've given, you can multiply the given polynomial by every other function.

To find a polynomial with given zeros, each zero can be plugged into the format (x - a). Doing so with the provided zeros in this question, i.e., -2, 0, 3, and 5, represents the zeroes of the polynomial equation x(x + 2)(x - 3)(x - 5) which simplifies to  x4 - 6x3 + 3x2 + 60x.

The subject of this question is polynomial equations in mathematics. In order to find a polynomial equation that has zeroes at x = -2, x = 0, x = 3, and x = 5, you can use the fact that the equation (x - a)(x - b)(x - c)(x - d) will have zeros at a, b, c, and d.

By substituting the values for a, b, c, and d into the equation with the zeroes provided (-2, 0, 3, and 5), the polynomial equation that satisfies these zeroes can be expressed as: (x - (-2))(x - 0)(x - 3)(x - 5). Simplifying, this gives: x(x + 2)(x - 3)(x - 5).

To further simplify, we need to multiply these expressions: x*(x+2)*(-x+15)-(2*x-10),which simplifies to: x4 - 6x3 + 3x2 + 60x. This is the polynomial equation that has zeros at x = -2, x = 0, x = 3, and x = 5.

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Answer: B

Step-by-step explanation:

Can't really explain it. A tenth is .1, a hundredth is .01

Answer:

4

Step-by-step explanation:

Let's set up an equation using the formula for the area of a triangle.

Hint #22 / 3

\begin{aligned} \text{Area of a triangle} &= \dfrac12 \cdot \text{base} \cdot \text{height}\\\\ 12&= \dfrac12 \cdot 6 \cdot x \\\\ 12&= 3x \\\\ \dfrac{12}{\blueD{3}}&= \dfrac{3x}{\blueD{3}} ~~~~~~~\text{divide both sides by } {\blueD{ 3}}\\\\ \dfrac{12}{\blueD{3}}&= \dfrac{\cancel{3}x}{\blueD{\cancel{3}}}\\\\ x &=\dfrac{12}{\blueD{3}}\\\\ x &=4\end{aligned}  

Area of a triangle

12

12

3

12

​  

3

12

​  

x

x

​  

=  

2

1

​  

⋅base⋅height

=  

2

1

​  

⋅6⋅x

=3x

=  

3

3x

​  

       divide both sides by 3

=  

3

​  

3

​  

x

​  

=  

3

12

​  

=4

​  

Let x represent amount borrowed at 4.2% and y represent amount invested at 6.8%.

We have been given that Michelle borrows a total of $2500 in student loans from two lenders. We can represent this information in an equation as:

[tex]x+y=2500...(1)[/tex]

[tex]y=2500-x...(1)[/tex]

We are also told that at the end of 3 years, she will owe a total of $354 for the interest from both loans.

Amount of interest earned at a rate of 4.2% in 3 years would be [tex]0.042\cdot 3\cdot x=0.126x[/tex].

Amount of interest earned at a rate of 6.8% in 3 years would be [tex]0.068\cdot 3\cdot y=0.204y[/tex].

We can represent this information in an equation as:

[tex]0.126x+0.204y=354...(2)[/tex]

Upon substituting equation (1) in equation (2), we will get:

[tex]0.126x+0.204(2500-x)=354[/tex]

[tex]0.126x+510-0.204x=354[/tex]

[tex]-0.078x+510=354[/tex]

[tex]-0.078x+510-510=354-510[/tex]

[tex]-0.078x=-156[/tex]

[tex]\frac{-0.078x}{-0.078}=\frac{-156}{-0.078}[/tex]

[tex]x=2000[/tex]

Therefore, Michelle borrowed $2000 at 4.2%.

Upon substituting [tex]x=2000[/tex] in equation (1), we will get:

[tex]y=2500-2000=500[/tex]

Therefore, Michelle borrowed $500 at 6.8%.

She borrowed $ 2000 from the 4.2% lender and $ 500 from the 6.8% lender.

Since Michelle borrows a total of $ 2500 in student loans from two lenders, and one charges 4.2% simple interest and the other charges 6.8% simple interest, and she is not required to pay off the principal or interest for 3 yr, but at the end of 3yr, she will owe a total of $ 354 for the interest from both loans, to determine how much did she borrow from each lender, the following calculation must be performed:

Therefore, she borrowed $ 2000 from the 4.2% lender and $ 500 from the 6.8% lender.

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