Q10 Q6.) Find a set of parametric equations for the line that passes through the given points
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See picture below for the answer!
The correct answer is option A
Related Questions
9(T - 1) = 6(T + 2) - T
T = ?
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9T-9=6T+12-T
9T-9=5T+12
4T-9=12
4T=21
T=5.25
but the equation is wrong
i think that answer is T=5.25
hey can you please help me posted picture of question
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G(x) is obtained by subtracting 3 from F(x). This means G(x) is obtained by vertical translation of F(x). Since 3 is subtracted from F(x), the vertical translation is downwards.
So, we can say: G(x) is obtained by moving F(x) 3 units vertically down.
Therefore, the correct answer is option D
PLZ HELP ASAP TANGENTS OF CIRCLES WORD PROBLEMS
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70 + 90 + 90 + O = 360
O = 110 degrees.
Hey can you please help me posted picture of question
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The option B gives only such a probability which can represent a simple event. The rest of the options belong to the compound events as they are sum or product of probabilities.
So, the correct answer is option B
what has to be added to the sum of 2/3 & 3/2 to get 3? give answer as whole number or fraction <question 10 in the image>
Answers
(2/3+3/2)+x=3
Solving for x:
(2*2+3*3)/6+x=3
(4+9)/6+x=3
13/6+x=3
13/6+x-13/6=3-13/6
x=(6*3-13)/6
x=(18-13)/6
x=5/6
Answer: 5/6 has to be added to the sum of 2/3 and 3/2 to get 3
A store sells 48 count packages of Snickers candy bars for $27.50 per package, and 36 count packages of KitKat bars for $21.50 per package. Mrs. Sweettooth bought total of 204 Snickers and KitKat bars in the store and paid $119.50. How many of each candy bars did she buy?
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To find out how many Snickers and KitKat bars Mrs. Sweettooth bought, we can solve a system of equations using the count and cost information.
Explanation:Let's assume that Mrs. Sweettooth bought x packages of Snickers and y packages of KitKat bars.
From the given information, we can set up two equations:
48x + 36y = 204 (equation 1) - representing the total count of candy bars27.50x + 21.50y = 119.50 (equation 2) - representing the total cost of the candy barsTo solve this system of equations, we can use a method called substitution:
Rearrange equation 1 to solve for x: x = (204 - 36y)/48Substitute the value of x in equation 2: 27.50[(204 - 36y)/48] + 21.50y = 119.50Simplify and solve for yOnce y is found, substitute its value back into equation 1 to find the value of xBy solving this system of equations, we can determine the number of Snickers and KitKat bars that Mrs. Sweettooth bought.
Name all numbers between 67 and 113 that are a multiple of 4, 9 and 12.
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I believe that there are 2 number that are in between the given numbers and are multiples of 4, 9, and 12. The numbers are...
72 and 108.
You can find these numbers by counting by the given one digit numbers
For example...
9, 18, 27, 36, 45, 54, 63, 72
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30..., 68, 70, 72
You can do the same for 108 as well
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72..., 104, 108
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30..., 100, 102, 104, 106, 108
I hope this helps!
What’s the largest fraction in each group? a. 5⁄6 and 29⁄36 b. 5⁄12 and 3⁄8 c. 2⁄5 and 19⁄45 d. 5⁄7, 13⁄14, and 19⁄21 e. 7⁄11 and 9⁄121 f. 1⁄2, 3⁄18, and 4⁄9
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Now divide each piece in 2 halves; each one is ¼ of the cake. Witch is largest? 1:2=0,5; 1:4=0,25. 0,5>0,25.
5:6=0,83333
29:36=0,80555
0,83>0,80 so 5/6 is the largest.
Do this for each group.
a.5/6
b.5/8
c.19/45
d.13/14
e.7/11
f.1/2
Answer:
a. [tex]\frac{5}{6}[/tex],
b. [tex]\frac{5}{12}[/tex],
c. [tex]\frac{19}{45}[/tex],
d. [tex]\frac{13}{14}[/tex],
e. [tex]\frac{7}{11}[/tex],
f. [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
(a)
[tex]\frac{5}{6}\text{ and }\frac{29}{36}[/tex]
Making denominator common.
[tex]\frac{5\times 6}{6\times 6}\text{ and }\frac{29}{36}[/tex]
[tex]\frac{30}{36}\text{ and }\frac{29}{36}[/tex]
Now compare the numerators.
[tex]30>29[/tex]
[tex]\frac{30}{36}>\frac{29}{36}[/tex]
[tex]\frac{5}{6}>\frac{29}{36}[/tex]
Therefore [tex]\frac{5}{6}[/tex] is largest fraction.
(b)
[tex]\frac{5}{12}\text{ and }\frac{3}{8}[/tex]
Making denominator common.
[tex]\frac{5\times 2}{12\times 2}\text{ and }\frac{3\times 3}{8\times 3}[/tex]
[tex]\frac{10}{24}\text{ and }\frac{9}{24}[/tex]
Now compare the numerators.
[tex]10>9[/tex]
[tex]\frac{10}{24}>\frac{9}{24}[/tex]
[tex]\frac{5}{12}>\frac{3}{8}[/tex]
Therefore [tex]\frac{5}{12}[/tex] is largest fraction.
(c)
[tex]\frac{2}{5}\text{ and }\frac{19}{45}[/tex]
Making denominator common.
[tex]\frac{2\times 9}{5\times 9}\text{ and }\frac{19}{45}[/tex]
[tex]\frac{18}{45}\text{ and }\frac{19}{45}[/tex]
Now compare the numerators.
[tex]18<19[/tex]
[tex]\frac{18}{45}<\frac{19}{45}[/tex]
[tex]\frac{2}{5}<\frac{19}{45}[/tex]
Therefore [tex]\frac{19}{45}[/tex] is largest fraction.
Similarly,
(d)
[tex]\frac{5}{7}\text{ and }\frac{13}{14}\text{ and }\frac{19}{21}[/tex]
By making denominator common, we get
[tex]\frac{30}{42}\text{ and }\frac{39}{42}\text{ and }\frac{38}{42}[/tex]
By comparing the numerators, we get 39 is greatest therefore [tex]\frac{13}{14}[/tex] is largest fraction.
(e)
[tex]\frac{7}{11}\text{ and }\frac{9}{121}[/tex]
By making denominator common, we get
[tex]\frac{77}{121}\text{ and }\frac{9}{121}[/tex]
By comparing the numerators, we get 77 is greatest therefore [tex]\frac{7}{11}[/tex] is largest fraction.
(d)
[tex]\frac{1}{2}\text{ and }\frac{3}{18}\text{ and }\frac{4}{9}[/tex]
By making denominator common, we get
[tex]\frac{9}{18}\text{ and }\frac{3}{18}\text{ and }\frac{8}{18}[/tex]
By comparing the numerators, we get 9 is greatest therefore [tex]\frac{1}{2}[/tex] is largest fraction.
A company makes three purchases on July 5, one for $550, another for $250 and a third for $75. It returns merchandise costing $35. If the Company is given a discount 2/10 and pays the total amount due on July 20, how much was due?
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8/10 ($550 + $250 + $75 - $35) = $672.
The amount due is $672.
The number of cartoons watched on saturday mornings by students in mrs. kelly's first grade class is shown below. number of cartoons watched x 0 1 2 3 4 5 probability p(x) 0.15 0.20 0.30 0.10 0.20 0.05 what is the mean of the data?
a.1.37
b.2.15
c.1.89
d.1.18
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[tex]\mu =\sum \left(x\cdot p\left(x\right)\right)[/tex]
[tex]\mu =0\left(0.15\right)+1\left(0.20\right)+2\left(0.30\right)+3\left(0.10\right)+4\left(0.20\right)+5\left(0.05\right)[/tex]
[tex]\mu =2.15[/tex]
The mean is 2.15.
What is the volume of a rectangular prism with the dimensions: L = 1 in, W = 3/4 in, and H = 1/2in. V = LWH.
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V = LWH
V = (1 in.)(3/4 in.)(1/2 in.) = 3/8 in.^3 = 0.375 in.^3
Show that the curvex = 2 cos t, y = 3 sin t cos t has two tangents at (0, 0) and find their equations.
Answers
The first derivative implies that:
[tex] \frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} } [/tex]
So we need to find both derivatives as functions of the variable t, then:
[tex]\frac{dy}{dt} = 3[cos(t)cos(t)+sin(t)(-sin(t))][/tex]
[tex]\frac{dy}{dt} = 3[cos^{2} (t)-sin^{2} (t)][/tex]
[tex]\frac{dx}{dt} = -2sin(t)[/tex]
Thus:
[tex]\frac{dy}{dx} = \frac{-3[cos^{2} (t)-sin^{2} (t)]}{2sin(t)}[/tex]
At (0,0) [tex]x=0[/tex] and [tex]y=0[/tex], so:
[tex] \left \{ {{0=2cos(t)} \atop {0=3sin(t)cos(t)}} \right.[/tex]
∴[tex] \left \{ {{cos(t)=0} \atop {sin(t)cos(t)=0}} \right.[/tex]
There are two values between -π and π which satisfy these equations simultaneously, namely:
[tex]t =[/tex] π/2
[tex]t =[/tex] -π/2
The equation of a straight line given a point and its slope is
[tex]y - y_{0} = m(x- x_{0} )[/tex]
Given that the point is (0,0), then the equation can be written as:
[tex]y = mx [/tex]
So we will find two straight lines:
[tex] \left \{ {{y= m_{1}x } \atop {y= m_{2}x }} \right. [/tex]
For [tex]t = \pi /2[/tex]:
[tex] m_{1}= \frac{dy}{dx} = \frac{-3[cos^{2} ( \pi /2)-sin^{2} ( \pi /2)]}{2sin( \pi /2)} = \frac{3}{2} [/tex]
For [tex]t = -\pi /2[/tex]:
[tex]m_{2}= \frac{dy}{dx} = \frac{-3[cos^{2} ( -\pi /2)-sin^{2} ( -\pi /2)]}{2sin(- \pi /2)} = -\frac{3}{2} [/tex]
Lastly:
[tex]\left \{ {{y= \frac{3}{2} x } \atop {y= -\frac{3}{2} x }} \right. [/tex]
The radius of the circle is 7 inches what is the approximate length of AB (AB is 135 degrees
Answers
circumference=2*pi*r
for r=7 in
circumference=2*pi*7------> 14*pi in
if 360° (full circle) has a length of------------ 14*pi in
135°-----------------------------> x
x=135*14*pi/360----------> x=5.25*pi in--------> 16.49 in
the answer is
5.25*pi in or 16.49 in
if the leg of a right triangle are 3 ft and the 4ft the length of the hypotenuse is
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The Pythagorean Theorem: a² + b² = c², where c is the hypotenuse of the triangle.
Plug in the leg lengths and solve.
a² + b² = c²
3² + 4² = c²
9 + 16 = c²
25 = c²
5 = c
Answer:
The length of the hypotenuse is 5 ft.
Olivia and ray walk to school. olivia walks 1\4 of a mile to school. her walks is 2\3 of the distance that ray walks to school. waht is the total distance, in miles that ray walks to school? answer
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Olivia walks ---------> 1\4 of a mile to school
2/3 correspond to ------> 0.6666------> 66.67 %
3/3 correspond to--------> 1--------> 100%
so
if (2/3)-----------> 1/4 mile
(3/3)-------------> x
x=(1/4)/(2/3)-----> x=(1/4)*3/2-----> x=3/8------> x-0.375 miles
the answer is
Ray walks to school 3/8 miles (0.375 miles)
what is the function for point (2,2)
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The length of the major axis of the ellipse below is 14, and the length of the red line segment is 3. how long is the blue line segment?
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The length of the blue line segment is 11 units.
What is relation between sum of the distance of a point from the focus of ellipse and the length of major axis?For any point P on an ellipse, the sum of the distances from P to the two foci is equal to the length of the major axis of the ellipse. This is known as the "distance property" of an ellipse.
To see why this is true, consider an ellipse with foci F₁ and F₂ and major axis length 2a. Let P be any point on the ellipse, and let D₁ and D₂ be the distances from P to F₁ and F₂, respectively. Then, by definition of an ellipse, we know that:
D₁+ D₂ = 2a
Given that,
Two line segments
Red segments of length = 3 unit
So from the definition we know that,
The sum of segments = the length of major axis
The length of major axis = 2a
2a = D₁+ D₂
14= 3 + D₂
D₂ = 11
Therefore, the length of the blue line segment is 11 units.
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Help with this one can’t figure it out
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1. You have that the equation for calculate the area of a circle is:
A=πr²
2. You have that the formula for calculate the diameter of a circle is:
d=2r
Therefore, the radius is r=d/2
where r is the radius of the circle
3. Keeping the information above on mind, you have the correct sequence of the equations by clearing the diameter d, is shown below:
A=π(d/2)²
A=πd²/4
4A=πd²
d²=4A/π
d√(4A/π)
Therefore, as you can see, the answer is:
A=π(d/2)²
A=πd²/4
4A=πd²
d²=4A/π
d√(4A/π)
Use the spinner shown. it is equally probable that the pointer will land on any one of the six regions. if the pointer lands on a borderline, spin again. if the pointer is spun twice, find the probability that it will land on grey and then purple
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The probability of a spinner with six equally probable outcomes landing on specific colors in sequence (grey then purple) is 1/36 since the events are independent. Their individual probabilities (each 1/6) are multiplied to find the combined probability.
Explanation:The question involves a topic in probability called independent events. In this case, the spinner landing on grey in the first spin and purple in the second spin are independent events. That means, the outcome of the first event does not affect the outcome of the second event and vice versa.
Since the spinner has six regions, and landing on any one of them is equally probable, the probability of landing on grey (or any specific color) in one spin is 1/6. Similarly, the probability of landing on purple in one spin is also 1/6.
Since these events are independent, the probability of both these events happening in sequence can be found by multiplying the probabilities of each individual event happening. So, the probability of the spinner landing on grey in the first spin and then on purple in the second is (1/6)*(1/6) = 1/36.
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The probability of landing on the grey region first and then the purple region is 1/18.
Explanation:The question asks for the probability of landing on the grey region first, and then the purple region on a spinner. To find the probability, we first need to determine the total number of possible outcomes. Since the spinner has six regions, we have six possible outcomes on the first spin. If the spinner lands on a borderline, we spin again. So, on the second spin, we also have six possible outcomes. Since each spin is equally likely, the total number of possible outcomes is 6 x 6 = 36.
Next, we need to determine the number of favorable outcomes, which is the number of ways we can land on the grey region first and then the purple region. From the spinner, we can see that there are two grey regions and one purple region. So, the number of favourable outcomes is 2 x 1 = 2.
Finally, we can calculate the probability by dividing the number of favourable outcomes by the total number of outcomes: 2/36 = 1/18. Therefore, the probability of landing on the grey region first and then the purple region is 1/18.
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The access code for a car's security system consists of four digits. the first digit cannot be zero or one and the last digit must be even. how many different codes are available?
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At one store, Julia saved $10 with a coupon for 40% off her total purchase. At another store, the $29 she spent on books is 58% of her total bill. How much did Julia spend in all at the two stores?
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0.40*(original price of "a") = $10
(original price of "a") = $10/0.40 = $25.00 . . . . divide by 0.40 and evaluate
a = (original price of "a") - $10 . . . . . . Julia paid the price after the discount
a = $25.00 -10.00 = $15.00
At the other store,
$29 = 0.58b
$29/0.58 = b = $50 . . . . . . . divide by the coefficient of b and evaluate
Then Julia's total spending is
a + b = $15.00 +50.00 = $65.00
Julia spent $65 in all at the two stores.
a + 5=5a +5
[tex]a + 5 = 5a + 5 = [/tex]
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a = 5a
Now subtract both sides by a:
4a = 0
a = 0
20 points! plz help me
Answers
- 3 - 3
2a + a = 177
3a = 177
---- ---- = 59
3 3
59 is a.
find the product of 9x^2+2x-7
Answers
1. You have the following quadratic equation given in the problem:
9x^2+2x-7=0
2. When you factor it, you obtain:
(9x-7)(x+1)=0
3. Then, you have that the roots of the quadratic equation are:
(9x-7)(x+1)=0
x1=7/9
x2=-1
if there are 16 ounces in a pound how manyh are in 24 ounces
Answers
1 ounce = 1/16 pound
24 ounces = 1/6 x 24 = 4 pounds
Answer: 4 pounds
24 ounces equals 1.5 pounds, based on the conversion factor of 1 pound equals 16 ounces.
Explanation:Your question is related to unit conversion. If we know that one pound equals 16 ounces, then to convert 24 ounces to pounds, we must divide 24 ounces by the number of ounces in a pound. Here's how we can do it:
Set up the conversion: 24 oz / 16 oz/lb. Dividing these amounts gives the result: 24 / 16 = 1.5 lbs.S, this means that 24 ounces is equal to 1.5 pounds.
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4,000 is invested at 3% interest how much money must be invested at 5% interest so that the total interest from the two investments is $195 after a year
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Interest 1: I1=4,000*3%=4,000*3/100→I1=120
Money 2: x invested at 5% interest
Interest 2: I2=x*5%=x*5/100→I2=0.05x
The total interest from the two investments is $195 after a year
I1+I2=195
120+0.05x=195
Solving for x:
120+0.05x-120=195-120
0.05x=75
0.05x/0.05=75/0.05
x=1,500
Answer: $1,500 must be invested at 5% interest so that the total interest from the two investments is $195 after a year
Two men, joel and jerry, push against a wall. jerry stops after 10 min, while joel is able to push for 5.0 min longer. compare the work they do. two men, joel and jerry, push against a wall. jerry stops after 10 min, while joel is able to push for 5.0 min longer. compare the work they do. both men do positive work, but joel does 50% more work than jerry. both men do positive work, but jerry does 50% more work than joel. both men do positive work, but joel does 75% more work than jerry. both men do positive work, but joel does 25% more work than jerry. neither of them does any work.
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neither of them does any work.
Q #6 in the figure A B || C D Find the measure ГGEB
Answers
Answer: Second option 50°
the answer is b hoped i helped
Billy is making a juice that contains 3 quarts of water, 1 quart of grape juice, 1 quart of orange juice, and 2 quarts of strawberry juice. He is putting his homemade juice into a jug that can hold 2 1⁄2 gallons. How many more quarts of juice can Billy still make before filling the jug?
Answers
Billy is making a juice that contains
3 quarts of water
1 quart of grape juice
1 quart of orange juice
2 quarts of strawberry juice
total=3+1+1+2----> 7 quarts
a jug can hold 2 1⁄2 gallons-----> 2.5 gallons
we know that
1 gallon is equal to 4 quarts
2.5 gallons------> x
x=2.5*4----> x=10 quarts
so
quarts of juice can Billy still make before filling the jug=10-7---> 3 quarts
the answer is
3 quarts
Distributive Property: 2(5c-7)=1
Answers
a(b + c) = ab + ac
Steps:
so, 2(5c - 7) = 1
1.) 2(5c) - 2(7) = 1
10c - 14 = 1
2.) Add 14 to both sides:
10c - 14 + 14 = 1 + 14
3.) Simplify:
10c = 15
4.) Then, divide both sides by 10:
10c/10 = 15/10
5.) Simplify:
c = 3/2
is the answer.
Hope this helped you solve this question!!!
~Shane
Good Luck! Hope this helps! <3