Mathematics High School

Question 1. Evaluate 4 times a number q plus 25 when q=2
A. 27
B.31
C.33
D.42
Question 2. If p=8, evaluate 4 )2 / 9.3
A.2
B.3
C.6
D. 8
Question 3. If q=2, evaluate (24 + 18 .q) - (5q + 7)
A. 38
B. 79
C. 31
D. 21,

Answers

Answer 1
1. 4 times a number q plus 25 The formula this is describing is 4q + 25 When q = 2 the formula is 4*2 + 25 = 8 + 25 = 33 So C is the answer. 2. If p = 8 evaluate 4 )2/9.3 I believe you have a typo here, this is not understandable and I cannot provide an answer. 3. If q=2, evaluate (24 + 18q) - (5q + 7) Plug in 2 into the formula, so it is = (24 + 18*2) - (5*2 + 7) = (24 + 36) - (10 + 7) = 60 - 17 = 43 So the answer is not provided, either you have a typo in your formula or your teacher doesn't like you!

Related Questions

If cos thetha =-0.96 and (sec thetha)(sin thetha)>0 find the value of tan thetha

Answers

cos(theta)=-0.96 <0
=>
theta is either in the 2nd or third quadrant.

cos(theta)=-0.96
=>
sec(theta)=1/cos(theta)=-1/0.96   <0

Given sec(theta)(sin(theta)>0
=> cos(theta)sin(theta)>0
=> cos(theta) and sin(theta) have the same sign, 
=> sin(theta)<0 
=>
theta is in the third quadrant. => tan(theta)>0

Given cos(theta)=-0.96
=>
|sin(theta)|=sqrt(1-(-0.96)^2)=sqrt(0.0784)=0.28 
=> sin(theta)=-0.28

Finally, 
tan(theta)=sin(theta)/cos(theta)=-0.28/-0.96
=7/24 
=0.29167 (to the fifth decimal place)

Mara listens to audiobooks while she’s driving. She has 3 mystery, 4 fiction, and 2 humor audiobooks in her car. Summarize the data using the mode

Answers

The mode, or most commonly occurring number in this data set, would be 4. Mara, therefore, has mostly fiction titles in her car.

Answer:The mode, or most commonly occurring number in this data set, would be 4. Mara, therefore, has mostly fiction titles in her car.

Step-by-step explanation:

Two parallel lines are _____ coplanar.


never


sometimes


always


Two lines that lie in parallel planes are _____ parallel.


sometimes


always


never



Please explain the answers, I want to understand this better.

Answers

Answer:

1. always

2. sometimes

Step-by-step explanation:

Two lines are coplanar if they lie in the same plane or in parallel planes. There is  ALWAYS a plane which contains two parallel lines (see first attached image for details).

Two lines that lie in parallel planes are sometimes parallel. For example, see at second image. Planes [tex]\alpha[/tex] and [tex]\beta[/tex] are parallel. Consider pair of lines [tex]a[/tex] and [tex]a_1[/tex] - they are parallel, but if you consider the pair of lines [tex]a[/tex] and [tex]b_1[/tex], you can see they are not parallel.

Answer:

always

sometimes

Step-by-step explanation:

By definition parallel lines are lines in a plane which do not meet, that means, they have to be coplanar. Coplanar means they are included in the same plane. Then, two parallel lines are always coplanar (imagine two parallel lines in a 3d space, there is always a plane that can contain them).

Two lines that lie in parallel planes are sometimes parallel. As stated before, if there is a third plane which contains the two lines, they can be parallel or cannot, but if there is no plane which contains them, they are not parallel.

Which group of measurements could be the side lengths of a right triangle?
A.
57 in, 86 in, 95 in
B.
47 in, 76 in, 95 in
C.
57 in, 76 in, 95 in
D.
57 in, 76 in, 105 in

Answers

In right angled triangles, according to Pythagoras' theorem, squared of the hypotenuse is equal to the sum of the squares of the other 2 sides of the triangle.
if the hypotenuse is H and other 2 sides are A and B, then equation is as follows;
H² = A² + B²

1. A - 57 in. B - 86 in.
H² = A² + B²
H² = 57² + 86²
H² = 3249 + 7396
H  = √10645
    = 103.17 in.
third side given is not 103 in therefore this is not a right angled triangle 

2. A - 47 in. B - 76 in.
H² = A² + B²
H² = 47² + 76²
     = 2209 + 5776
H   = √7985
H = 89.3 in.
third side given is 95 in. therefore this is not a right angled triangle.

3. A- 57 in. + B - 76 in.
H² = A² + B²
H² = 57² + 76²
     = 3249 + 5776
H = √9025
H = 95 in.
third side given is 95 in. therefore this is a right angled triangle.

4. A - 57 in. B - 76 in.
As calculated in the third equation with the same side lengths of A and B, hypotenuse should be 95 in. however the third side length given is 105 in. so this is not a right angle triangle 

Please answer this question!! Show your work

Answers

The answer is 6.4%

When converting a decimal to a percent two places to the right.


I hope this helps!

A machine packs at a constant rate of 2/3 of a box every 1/2 minuet. What’s is the number of boxes per minute that’s the machine packs?

Answers

For this case what we can do is the following rule of three:
 2/3 of a box ------> 1/2 minutes
 x of a box ---------> 1 minute
 Clearing x we have:
 x = (1 / (1/2)) * (2/3)
 Rewriting:
 x = 2 * (2/3)
 x = 4/3
 Answer:
 the number of boxes per minute that the machine packs is:
 x = 4/3

The range of typical total prices for an American tourist traveling on the European continent is $20.70 to $25.00. What is the average price?

Answers

For this case what we should do is find an average value of the total prices for a trip to europe
 We look for the average of the prices by means of the following expression:
 P = (20.70 + 25) / (2)
 P = 22.8 $
 Answer: 
 the average price is $ 22.8

Answer:

(The other answer has missing a number.)

The full answer is: $22.85

Evaluate 2x^2 − 5y / 3x − y when x = 2 and y = -4


Answers

If you substitute all the variables with the number assigned the answer would be 18.

If a force of 60 N is exerted on a 15 kg object, calculate the acceleration that the object undergoes. ________ m/s2 4 900 0.25 40

Answers

F=m•a
Then:
a=F/m
a=60/15=4 m/s²

Answer:  The correct option is

(A) 4 m/s.

Step-by-step explanation:  We are given that a force of 60 N is exerted on a 15 kg object.

We are to calculate the acceleration that the object undergoes.

From Newton's second law of motion, we have

[tex]F=ma,[/tex] where m is the mass of the object, a is the acceleration and F is the force exerted.

For the given object, we have

F = 60 N  and  m = 15 kg.

So, we get

[tex]F=ma\\\\\Rightarrow 60=15\times a\\\\\Rightarrow a=\dfrac{60}{15}\\\\\Rightarrow a=4.[/tex]

Thus, the required acceleration that the object undergoes is 4 m/sec.

Option (A) is CORRECT.

Simplify these 12 radicals:
1) √80 2) √64
3) √45 4) √54
5) √32 6) √36
7) √150 8) √20
9) √180 10) √72
11) √8 12) √50

Answers

1)
[tex]4 \sqrt{5} [/tex]
2)
[tex]8[/tex]
3)
[tex]3 \sqrt{5} [/tex]
4)
[tex]3 \sqrt{6} [/tex]
5)
[tex]4 \sqrt{2} [/tex]
6)
[tex]6[/tex]
7)
[tex]5 \sqrt{6} [/tex]

8)
[tex]2 \sqrt{5} [/tex]
9)
[tex]6 \sqrt{5} [/tex]
10)
[tex]6 \sqrt{2} [/tex]
11)
[tex]2 \sqrt{2} [/tex]
12)
[tex]5 \sqrt{2} [/tex]

What number is between 7/11 and 7/10

which one?
76/99
23/33
77/9
25/44

???? plz be sure its 56 points

Answers

23/33 is between 7/11 and 7/10 :)

Which term describes what a manufacturer spends for goods or services?

a)cost
b)price
c)markup

Pleas help. Willl fan and medal!!

Answers

The term describing what a manufacturer spends for goods or services is cost. Cost is the expenses incurred by the manufacturer as a result of his business or undertaking. There are two types of cost of a manufacturer. The cost of goods sold and the operating expenses. The cost of goods sold are those cost incurred directly as a result of manufacturing. The operating expenses are those other expenses not indirectly involved with the manufacture of goods or services.

What are two solutions of 3 + 4 |x/2 + 3| = 11?

Answers

3 + 4abs(x/2 + 3) = 11 Subtract 3
4 abs(x/2 + 3) = 11 - 3
4 abs(x/2 + 3) = 8 Divide by 4
abs(x/2 + 3) = 8/4
abs(x/2 + 3) = 2

Solution 1
x/2 + 3 = 2 Subtract 3
x/2 = 2 - 3
x/2 = - 1 Multiply by 2
x/2 *2 = - 2
x = - 2

Solution 2
x/2 + 3 = - 2
x/2 = - 2 - 3
x/2 = - 5 Multiply by 2
x = -5 * 2
x = -10

Solutions
x = - 2 <<<< answer 1
x = -10 <<<< answer 2

A job applicant estimates that his chance of passing a qualifying examination is 2/3, and his chance of being appointed if he does pass is 1/4. What is the probability that he will receive the job?

Answers

so, basically 2
2 * 1
- -
3 * 4
so 2 /12
1/6 when simplified
Answer:

Hence, the probability that he will receive job is:

                                   1/6

Step-by-step explanation:

It is given that:

chance of passing a qualifying examination is 2/3=P

and chance of being appointed if he does pass is 1/4=P'

Now, we are asked to find the probability that he will receive the job.

We are asked to find the probability that he will receive the job.

The probability is calculated as:

Probability that he qualify exam×Probability that he is being appointed.

=P×P'

=(2/3)×(1/4)

=1/6

find the solution of this system of equations shown on the graph.

Answers

answer is (0,3)

hope it helps

If 8900 is invested at 3.8%

Answers

is this the question, i am assuming you are asking?            


If $8,900 is invested at 3.8% interest compounded quarterly, how much will the investment be worth in 13 yrs?
A.$14,551.87
B.$14,518.40
C.$14,452.92
D.$14,574.46


If it is, Here is your answer:

Just plug everything into the equation.

A(t) = P(1 + r/n)^(nt)

P is the principle (investment)
r is the interest rate expressed as a decimal
n is the number of times compounding occurs in a year
t is the number of years

A(13) = 8900(1 + 0.038/4)^(4+13) = 14551.87 

Answer is (A): 14, 551.87

Solve the system of equations

1.8x-0.5y=-6.4
0.6x+2.1y=2.4

_______________________

x= ??

y= ??

Answers

Solve the following system:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4

In the first equation, look to solve for x:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4

1.8 x - 0.5 y = (9 x)/5 - y/2 and -6.4 = -32/5:
{(9 x)/5 - y/2 = -32/5


Add y/2 to both sides:
{(9 x)/5 = 1/10 (5 y - 64)
{0.6 x + 2.1 y = 2.4

Multiply both sides by 5/9:
{x = 1/18 (5 y - 64)
{0.6 x + 2.1 y = 2.4

Substitute x = 1/18 (5 y - 64) into the second equation:
{x = 1/18 (5 y - 64)
{2.1 y + 0.0333333 (5 y - 64) = 2.4

2.1 y + 0.0333333 (5 y - 64) = 2.1 y + (0.166667 y - 2.13333) = 2.26667 y - 2.13333:
{x = 1/18 (5 y - 64)
2.26667 y - 2.13333 = 2.4

In the second equation, look to solve for y:
{x = 1/18 (5 y - 64)
{2.26667 y - 2.13333 = 2.4

2.26667 y - 2.13333 = (34 y)/15 - 32/15 and 2.4 = 12/5:
(34 y)/15 - 32/15 = 12/5

Add 32/15 to both sides:
{x = 1/18 (5 y - 64)
{(34 y)/15 = 68/15

Multiply both sides by 15/34:
{x = 1/18 (5 y - 64)
y = 2


Substitute y = 2 into the first equation:

Answer: {x = -3, y = 2

Make a the subject of the formula: v^2=u^2+2as. Please help & show working

Answers

It just means to isolate a. You can start like this::

V^2 = U^2 + 2AS
V^2 - U^2 = 2AS
(V^2 - U^2)/2S = A
A= (V^2 - U^2)/2S 

A platform has a volume of 135 cubic feet, but the concrete Joey wants to buy is sold by the cubic yard.

Answers

Not sure exactly what you're asking here, it probably cut you off and wouldn't let you type any more but I think the answer is that he needs to get a third of his original amount he was planning on buying, making it evened up to being 135 cubic feet.

The number of cubic yards of concrete does Joey need to buy is 5 cubic yards.

What is metric conversion?

Metric Conversion refers to the conversion of the given units to desired units for any quantity to be measured.

Given that, a platform has a volume of 135 cubic feet.

One cubic yard is equal to 27 cubic feet.

Now, number of cubic yards

= 135/27

= 5 cubic yards

Therefore, the number of cubic yards of concrete does Joey need to buy is 5 cubic yards.

To learn more about the metric conversion visit:

brainly.com/question/21244256.

#SPJ2

"Your question is incomplete, probably the complete question/missing part is:"

A platform has a volume of 135 cubic feet, but the concrete Joey wants to buy is sold by the cubic yard.

How many cubic yards of concrete does Joey need to buy?

Please help asap!!!! 53 points!

Answers

The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.
The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:
(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.
So one form of the equation would be:
y = -1x - 2
Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)
and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3
so we get: y-k = -1 (x--5)...
y-3 = -(x+5)... therefore D) is the correct answer:

Jax solved an equation and justified his steps as shown below. What reason would justify step 2?

3x + 5 > 2 Step 1: Given

3x > -3 Step 2: ?

x> -1 Step 3: Division Property of Equality



a. Combine Like Terms


b. Division Property of Equality


c. Subtraction Property of Equality


d. Multiplication Property of Equality

Answers

Answer: The Subtraction Property of Equality

In the problem that Jax solved he subtract 5 from both sides of the equation. This is an example of the subtraction property of equality.

The property states that if you subtract the same amount from both sides of an equation the equation remains the same.
Final answer:

Step 2 can be justified using the Multiplication Property of Equality. This property states that if we multiply or divide both sides of an inequality by the same number, the inequality will still hold true.

Explanation:

Step 2 can be justified using the Multiplication Property of Equality. This property states that if we multiply or divide both sides of an inequality by the same number, the inequality will still hold true.

In this case, Jax divided both sides of the inequality by 3. This is a valid step because dividing both sides of the inequality by a positive number does not change the inequality. So, by dividing both sides by 3, Jax found that x > -1.

WILL MARK AS BRAINLIEST
Complete the general form of the equation of a sinusoidal function having an amplitude of 1, a period of [tex]\frac{ \pi }{2} [/tex], and a vertical shift up 3 units.
y=__________

Answers

The general form for a sine function is: y = a sin(b[x + c]) + d
The amplitude is given by a, so a = 1.
The period is given by 2*pi/b, so 2*pi/b = pi/2, and b = 4.
The variable c gives the horizontal shift, of which there is none, so c = 0.
Finally, the vertical shift of 3 units means that d = 3.
So the equation is:
y = sin(4x) + 3

Answer:

y = sin(4x) + 3

Step-by-step explanation:

what is the length of the 2nd base of a trapezoid if the length of one base is 27 and the length of the midsegment is 19

Answers

1. To solve this exercise you must apply the "Trapezoid midsegment theorem", which says that the length of the midsegment is equal to half the sum of the lengths of the bases of the trapezoid. Therefore, you have:
 
 x=(a+b)/2
 
 "x" is the midsegment (x=19).
 "a" and "b" are the bases (a=27).
 
 2. When you clear the second base "b" from the formula  x=(a+b)/2 and you substitute the values, you obtain: 
 
 x=(a+b)/2
 2x=a+b
 b=2x-a
 b=2(19)-27
 b=38-27
 b=11
 
 What is the length of the 2nd base of a trapezoid?
 
 The answer is: 11

Answer: 11


Step-by-step explanation:

X=(a+b)/2

2x=a+b

B=2+-a

B=2(19)-27

B=3-27

B=11


10 POINTS + BRAINLIEST ANSWER

A box contains 30 pieces of chocolate, distributed as shown in the table below. Each piece is made of either white chocolate or dark chocolate, and each piece contains either cream filling or no filling. If one piece is selected at random, what is the probability that the piece is either white chocolate with cream filling or dark chocolate with no filling? (10 POINTS + BRAINLIEST ANSWER)

A. 8/30

B. 12/30

C. 20/30

D. 22/30

Answers

It’s A 5+3= 8
8/30
I need 20 characters

The probability of selecting a chocolate at random that is either white chocolate with cream filling or dark chocolate with no filling is [tex]\frac{8}{30}[/tex].

What is probability?

Probability is the chance of happening an event or incident.

Given, the box contains 30 chocolates.

The number of chocolates that are white chocolate with cream filling is 5.

Therefore, the probability of selecting a chocolate at random that is white chocolate with cream filling is [tex]= \frac{5}{30}[/tex].

The number of chocolates that are dark chocolate with no filling is 3.

Therefore, the probability of selecting a chocolate at random that is dark chocolate with no filling is [tex]= \frac{3}{30}[/tex].

Now, the probability of selecting a chocolate at random that is either white chocolate with cream filling or dark chocolate with no filling is

[tex]= \frac{5}{30} + \frac{3}{30} \\= \frac{8}{30}[/tex]

Learn more about probability here: https://brainly.com/question/28001361

#SPJ2

The population P(t) of a species satisfies the logistic differential equation dP/dt= P(2-(P/5000)) where the initial population 3,000 and t is the time in years. What is the lim t>infinity P(t)?

Answers

A logistic differential equation can be written as follows:
[tex] \frac{dP}{dt} = rP[1- \frac{P}{K}] [/tex]

where r = growth parameter and K = carrying parameter.

In order to write you equation in this form, you have to regroup 2:
[tex] \frac{dP}{dt} = 2P[1- \frac{P}{10000}] [/tex]

Therefore, in you case r = 2 and K = 10000

To solve the logistic differential equation you need to solve:

[tex] \int { \frac{1}{[P(1- \frac{P}{K})] } } \, dP = \int {r} \, dt [/tex]

The soution will be:

P(t) = [tex] \frac{P(0)K}{P(0)+(K-P(0)) e^{-rt} } [/tex]

where P(0) is the initial population.

In your case, you'll have:

P(t) = [tex] \frac{3E7}{3E3+7E3 e^{-2t} } [/tex]

Now you have to calculate the limit of P(t).
We know that
[tex] \lim_{t \to \infty} e^{-2t} -\ \textgreater \ 0 [/tex]

hence,

[tex] \lim_{t \to \infty} P(t) = \lim_{t \to \infty} \frac{3E7}{3E3+0} = 10^{4} [/tex]




Final answer:

The lim t>infinity P(t) is 5,000, which is the carrying capacity of the species.

Explanation:

The logistic differential equation dP/dt = P(2-(P/5000)) models the population growth of a species. To find the lim t>infinity P(t), we need to find the stable population when t becomes very large. In this equation, the population growth rate is initially exponential, but as the population approaches its carrying capacity (Q), the growth rate slows down and levels off to zero.

Solving the differential equation, we find that the equation represents logistic growth. The solution to the equation is P(t) = Q / (1 + (Q/Po)e^(-rt)), where Po is the initial population, Q is the carrying capacity, and r is the growth rate.

In this case, the initial population is given as 3,000. To find the carrying capacity (Q), we set dP/dt = 0 and solve for P. Substituting the values into the equation, we find Q = 5,000.

As t becomes very large, e^(-rt) approaches 0, and the equation simplifies to P(t) = Q. Therefore, the lim t>infinity P(t) is 5,000, which is the carrying capacity of the species.

Please help ASAP!!!! 52 points and will give brainliest for RIGHT answer!

Answers

i have made sure and the correct answer is d

PLEASE HELP QUICK!!!!

11PTS AND BRAINLIEST AVAILABLE TO CORRECT ANSWER

Answers

Your answer would be B

A sequence is defined by the recursive function f(n + 1) = f(n) – 2. If f(1) = 10, what is f(3)? 1 6 8 30

Answers

The value of f(3) would be 6.

Using our formula, we know that f(1) = 10, and f(2) = f(1) - 2 = 10-2 = 8.  That means that f(3) = f(2) - 2 = 8 - 2 = 6.

Answer:

6

Step-by-step explanation:

5x - 20 = 2x + 10 How do you solve this problem?

Answers

5x - 2x = 10 + 20

3x = 30

x is 10
x=10
5x - 20 = 2x + 10
add 20 to both sides

5x= 2x + 30
subtract 2x from both sides

3x= 30
divide both sides by 3

x= 10

Hope this helps! :)

PLS HELP QUICKLY :V) Anna brings her granddaughter to a photo studio to take spring pictures. For the picture, they have a choice of a background scene, a toy prop, and an outfit. The studio has 12 different background scene, 36 toy props, and 15 outfits to choose from.

How many possible outcomes of a background scene, a toy prop, and an outfit does Anna have?

Answers

to figure out how many different possibilities there are in total, you need to multiply all the numbers together. 36*12*15=6840

so there are 6840 possibilities, and to get a single one of these, the probability is 1/6840

To calculate the total number of possible outcomes for the photo shoot, you multiply the number of background scenes (12), toy props (36), and outfits (15), which results in 6,480 possible combinations.

The question posed involves determining the number of possible combinations of a background scene, a toy prop, and an outfit in a photo studio with a set number of each option available. To find the total number of possible outcomes, one should multiply the number of choices for each category together. In this case, Anna has 12 different background scenes, 36 toy props, and 15 outfits to choose from.

Therefore, the calculation is as follows:

Number of background scenes: 12

Number of toy props: 36

Number of outfits: 15

By multiplying these numbers, we determine the total number of possible outcomes:

12 (backgrounds) times 36 (props) times 15 (outfits) = 6,480 possible outcomes.

Other Questions
Samantha is viewing a real image formed by a lens of a diamond ring. Which must be true about the image?It could not be captured on film. It is larger than the actual ring. It was formed by a concave lens. It is upside down. The diagram FGH. Which. term decribes point J Which of the following sentences is written correctly? A-Although he didnt invent the automobile, Henry Ford developed affordable vehicles that could be mass-produced. B-Their were so many people who wanted the vehicles that Henry Ford built a larger factory in highland park Michigan.C-When was the assembly line with conveyor belts first used to assemble the vehicles.D-Cars aloud people to move away from cities that were filthy with manure from horses.E-The cars on the road was less dangerous then the horses in the city that trampled people and caused accidents. The mental representation and manipulation of information is In certain county, the number of charter schools is 4 less than twice the numbervof alternative schools. We know that there are 48 charter schools in the county. How many alternative schools are in the county? Which of these is the algebraic expression for "5 times and the sum of 2 and y?" A. 5*2 + y B.2+5*y C. 2(5+y) D.5(2+y)HELP!! Write the complete electron configuration for an atom of element 3 Who did the states' rights party nominate for president in 1948? select one:a. george wallaceb. strom thurmondc. henry wallaced. joe mccarthy? Which philosophy of u.s. management recognizes that people influence the future to a large extent and that they control their own fates? What is the perimeter of the triangle expressed as a polynomial? 8x-2 5x-4 9x-3 Ship A receives a distress signal from the north, and ship B receives a distress signal from the same vessel from the southeast. At what location is the vessel in distress located? Describe how you arrived at your conclusion using complete sentences. You must show all work in order to receive credit. The net force acting on a 5 kg discus is 50 n. what is the acceleration of the discus A nurse on an inpatient medical-surgical unit is taking care of a patient with acute gastritis. the patient has a nasogastric tube (ngt) to low-intermittent suction with bilious aspirate. upon reassessment, the nurse finds the aspirate to have become blood-tinged. what should the nurse do next? Which verb form correctly completes this conversation? Vctor: Qu hiciste ayer? Fernando: _________ tenis. Juego Juega Jugu Jug If pu perform 10 joules of work lifting a 10-N box from the floor to the shelf how high is the shelf Suppose x follows a distribution with density function: \begin{equation} f\left(x\right) = \left\{\begin{array}{rl} c\left|x - 2\right|,& 0 \le x \le 3\\ 0, & \text{otherwise}\\ \end{array}\right. \end{equation} (note: for this question you can enter your answer in decimals as well as fractions.) what must the value of c be so that f(x) is a probability density function? tries 0/5 find the cumulative distribution function of f(x) for $ 2 \leq x \leq 3 $. [ the accepted form of answer is an algebraic expression in terms of "x". all algebraically equivalent expressions to the correct answer are accepted. write product as *e.g 2*3 or 3*x, index/power as superscript,e.g 2^3 for 2 raised to the power 3, the exponential function as exp(x), the logarithm function as log(x) (and not as ln(x)) ] tries 0/5 find the median of the probability distribution of x tries 0/2 find e(x) tries 0/5 find the cumulative distribution function of f(x) for $ 0 \leq x \leq 2 $. [ the accepted form of answer is an algebraic expression in terms of "x". all algebraically equivalent expressions to the correct answer are accepted. write product as *e.g 2*3 or 3*x, index/power as superscript,e.g 2^3 for 2 raised to the power 3, the exponential function as exp(x), the logarithm function as log(x) (and not as ln(x)) ] Several general characteristics of metabolic reactions or reaction pathways are listed below. sort them into the appropriate metabolic category. note: if you answer any part of this question incorrectly, a single red x will appear indicating that one or more of the statements is incorrectly placed. In O.Henry's story "After Twenty Years,"why does "Silky Bob return to New York?A) He is planning to rob New York's biggest bank.B) Twenty years earlier, he promised to meet his best friend there. C) He wishes to live quietly in a city where nobody knows him. D) He has heard of "big Joe" Brady's restaurant and wants to eat there. According to the graph above, world population remained relatively unchanged during which time period? A. 5,000 BCE 3,000 BCE B. 3,000 BCE 1,000 BCE C. 15,000 BCE 5,000 BCE D. 2,000 BCE 1,000 BCE Point P (-3,-1) is the preimage. Point P(3,-1) is the image after a reflection is performed. Give the line of reflection.