quick computing company produces calculators they have found that the cost c(x),of making calculators is a quadratic function in terms of x the company also discovers that it costs $45 to produce 2 calculators, $143 to produce 4 calculators, and 869 to produce 10 calculators FIND THE TOTAL COST OF PRODUCING 1 CALCULATOR

Answers

Answer 1
it cost $23 to make one calculator hope this helps
Answer 2

Answer:

$23

Step-by-step explanation:

We will use a quadratic regression to solve this.

Using a graphing calculator, put the number of calculators into the first list (x) and the cost to produce into the second list (y).

Next we run the quadratic (x^2) regression.  Doing this gives us an equation in the form

y = ax²+bx+c.  The values we are given for a, b and c are

a = 8.9999999999; b = -4.999999999999; c = 18.999999999

These can be rounded to a = 9, b = -5 and c = 19.  This gives us the equation

y = 9x²-5x+19

Substituting 1 in place of x, we have

y = 9(1²)-5(1)+19 = 9(1)-5+19 = 9-5+19 = 4+19 = 23


Related Questions

Bars of soap come in packages of 6 and packages of 8. The 6-bar pack costs $7.86, and the 8-bar pack costs $8.88. Which is the better deal? What is the
price per bar of the better deal?

Answers

7.86 / 6 = 1.31 per unit
8.88 / 8 = 1.11 per unit

the 8-bar pack is the better deal

Rewrite the radical exponent as a radical

Answers

[tex]\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} \qquad \qquad \sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\ -------------------------------\\\\ \left( 5^{\frac{3}{4}} \right)^{\frac{2}{3}}\implies 5^{\frac{3}{4}\cdot \frac{2}{3}}\implies 5^{\frac{1}{2}}\implies \sqrt[2]{5^1}\implies \sqrt{5}[/tex]

Describe the graph of the following inequality: 2x - 5y ≤ 6

Answers

Final answer:

To graph the inequality 2x - 5y ≤ 6, plot the line 2x - 5y = 6 with a solid boundary, test a point to determine the solution region, and shade the region that satisfies the inequality, which is below and to the right of the boundary line.

Explanation:

To graph the inequality 2x - 5y ≤ 6, you must first draw the boundary line of the inequality. This line is created by graphing the equation 2x - 5y = 6.

Start by finding the intercepts. For the x-intercept, set y to 0 and solve for x, which gives x = 3. For the y-intercept, set x to 0 and solve for y, which gives y = -6/5. These two points can be used to draw the boundary line. Since the inequality is '≤', this line will be solid to show that points on the line satisfy the inequality.

Now you must determine which side of the line contains the solutions to the inequality. You can do this by choosing a test point that is not on the line, like (0,0). Substitute this point into the inequality: 2(0) - 5(0) ≤ 6 is true, so the area containing (0,0), which is below and to the right of the line, is the solution region. Shade this area to show all points that satisfy the inequality 2x - 5y ≤ 6.

HELP!! ASAP!!!!! Which system of equations below has infinitely many solutions?
a) y = –3x + 4 and y = –3x – 4
b) y = –3x + 4 and 3y = –9x + 12
c) y = –3x + 4 and y = -1/3+ 4
d) y = –3x + 4 and y = –6x + 8

Answers

Hello,

Answer B since
(y=-3x+4)* 3==> 3y=-9x+12 which is the second equation ==>infinity many solutions.

Answer:

The correct option is B. [tex]y=-3x+4 \ \text{and}\ \ 3y=-9x+12[/tex]

Step-by-step  explanation:

Consider the two linear equation:

[tex]a_1x+b_1y+c_1=0\ \text{and}\ \ a_2x+b_2y+c_2=0[/tex]

The pair of linear equation has infinitely many solutions when:

[tex]\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}[/tex]

Now consider the option.

Option a) [tex]y=-3x+4 \ \text{and}\ \ y=-3x-4[/tex]

The above equation can be written as:

[tex]y+3x-4=0 \ \text{and}\ \ y+3x+4=0[/tex]

Therefore,

[tex]\frac{1}{1}=\frac{3}{3}\neq\frac{-4}{4}[/tex]

Thus, this pair has no solution.

Now consider the option B. [tex]y=-3x+4 \ \text{and}\ \ 3y=-9x+12[/tex]

The above equation can be written as:

[tex]y+3x-4=0 \ \text{and}\ \ 3y+9x-12=0[/tex]

Therefore,

[tex]\frac{1}{3}=\frac{3}{9}=\frac{-4}{-12}[/tex]

Thus, this pair has infinitely many solution.

Hence, the correct option is B. [tex]y=-3x+4 \ \text{and}\ \ 3y=-9x+12[/tex]

What is the perimeter of the triangle expressed as a polynomial? 8x-2 5x-4 9x-3

Answers

Add up the three expressions to get the perimeter. The perimeter is simply the sum of all sides.

(8x-2)+(5x-4)+(9x-3)
8x-2+5x-4+9x-3
(8x+5x+9x)+(-2-4-3)
22x-9

Answer: 22x-9

Using the law of cosines, in triangle RST, if r=14 yd, s=9 yd, t=16 yd find m angle s


Help? Thank you

Answers

check the picture below.

[tex]\bf \textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)cos(C)\implies c = \sqrt{a^2+b^2-(2ab)cos(C)} \\\\\\ \cfrac{a^2+b^2-c^2}{2ab}=cos(C)\implies cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C\\\\ -------------------------------[/tex]

[tex]\bf s^2=r^2+t^2-2rt\cdot cos(S)\implies s^2-r^2-t^2=-2rt\cdot cos(S) \\\\\\ \cfrac{s^2-r^2-t^2}{-2rt}=cos(S)\implies \cfrac{r^2+t^2-s^2}{2rt}=cos(S) \\\\\\ cos^{-1}\left( \cfrac{r^2+t^2-s^2}{2rt} \right)=\measuredangle S\implies cos^{-1}\left( \cfrac{14^2+6^2-9^2}{2(14)(6)} \right)=\measuredangle S[/tex]

make sure your calculator is in Degree mode if you need ∡S in degrees.
10.05 I’m pretty sure

A customer buys an apple pie for $8.04, 6 cloves of garlic for $0./9 each, and a quarts of milk for $1.31. You are working the cash register. The customer gives you a $5 bill, six $1 bills, and a quarter. The register tells you that you ow the customer $0.16 . Round the price of each item to the nearest $0.10 to estimate how much the customer owes.

Answers

Round 0.30 each (or $1.80 for all 6 of them), the milk is $1.30. Total of estimates is $11.10
 
 The customer gave you 5 + 6 + 0.25 or $11.25, which is very close (and slightly higher) than the total of your estimates. I'd guess the register is correct.
 
Actual value is $8.04 + 6*0.29 + 1.31 = 8.04 + 1.74 + 1.31 = $11.09. The register is definitely correct.

Final answer:

To estimate the total cost, round each item to the nearest $0.10, sum them up, and subtract from the amount given by the customer. The estimated total cost is $9.80, and the estimated change to be returned is $1.45.

Explanation:

To estimate the total amount the customer owes after rounding to the nearest $0.10, we need to perform the following calculations:

Apple pie: $8.04, rounded to $8.00

6 cloves of garlic: $0.09 each, so $0.09 x 6 = $0.54, rounded to $0.50

Quart of milk: $1.31, rounded to $1.30

The estimated total cost is $8.00 (apple pie) + $0.50 (garlic) + $1.30 (milk) = $9.80.

The customer gives a total of $5 + $6 + $0.25 = $11.25.

Subtracting the estimated total cost from the amount given by the customer:
$11.25 - $9.80 = $1.45, which is the estimated change to be returned to the customer.

If there are 15 girls and 9 boys in an art class, the ____________ of girls to boys in the class is 5:3.

Answers

the ratio of girls to boys in the class is 5:3

A function that can be written in the form f(x)=ax2+bx+c, where a, b & c are real numbers and a is not equal to zero.

Answers

Hello there!

I'm not exactly sure of what answer you are looking for, however,
f(x)=ax^2+bx+c represents a quadratic function.

Quadratic functions always have their highest exponent at 2, nothing more and nothing less.

Examples of quadratic functions are...
•x^2
•3x^2
•3x^2+2
•3x^2+2x
•3x^2+2x+1

I really hope this helps!
Best wishes:)
This form would be considered as the standard form of a quadratic function.

A quadratic function seems to be a second-order polynomial function. Another quadratic function has the following general form:

[tex]f (x) = ax^2 + bx + c[/tex]

here,

a, b, and c = real numbers

and,

a ≠ 0

The quadratic formula is obtained by completing the square on some kind of quadratic equation instead in the standard format. Because the largest power equals two, it is indeed a 2nd-degree polynomial equation.

As a result, the aforementioned response is correct.

Learn more about quadratic equation here:

https://brainly.com/question/19942005

In a billiards game, Pete hits a ball that is 20in. from a wall. The ball travels 34 in. until it hits the wall and bounces to a position that is 16 in. from the wall. What proportion can be used to find the distance, x, the ball traveled after it bounces off the wall to get to the ending position? CHECK ALL THAT APPLY!

options

34/x =20/16

20/16 = 34/x

16/20 = x/34

20/16 = x/34

Answers

Hello,

Using Thales, 34/x=20/16

Answer A

To find the distance the ball traveled after it bounces off the wall, we can use the proportion 34/x = 20/16, which simplifies to x = 27.2 inches.

To find the proportion that can be used to find the distance, x, the ball traveled after it bounces off the wall, we can use the equation:

34/x = 20/16

After cross multiplying, we get:

34 × 16 = 20x

Simplifying further:

544 = 20x

Dividing both sides by 20, we find:

x = 27.2

Therefore, the distance the ball traveled after it bounces off the wall is 27.2 inches.

Carlos’s credit card has an APR of 14.78% and a grace period of 18 days, and Carlos pays his balance in full every month. If his last billing cycle ended on March 28, 2010, and he made his payment on April 13, 2010, Did he owe any interest on his last statements balance?

Answers

If Carlo’s last billing cycle ended on March 28, 2010, and he made his payment on April 13, 2010, he didn’t owe any interest on his last statement's balance because he paid within the grace period. 
THE ANSWER IS ......no, because he paid within the grace period

Solve the system of equations and choose the correct ordered pair. 2x + 6y = 6 3x – 2y = 20

Answers

(6,-1)
Multiply each equation by the value that makes the coefficients of xx opposite.(−3)⋅(2x+6y)=(−3)(6)(-3)⋅(2x+6y)=(-3)(6)(2)⋅(3x−2y)=(2)(20)(2)⋅(3x-2y)=(2)(20)Simplify.−6x−18y=−18-6x-18y=-186x−4y=406x-4y=40Add the two equations together to eliminate xx from the system.Divide each term by −22-22 and simplify.Tap for more steps...y=−1y=-1Substitute the value found for yy into one of the original equations, then solve for xx.Tap for more steps...x=6x=6The solution to the independent system of equations can be represented as a point.(6,−1)

Answer:

solution is (6,-1)

Step-by-step explanation:

[tex]2x + 6y = 6[/tex]

[tex]3x – 2y = 20[/tex]

WE use elimination method to solve for x  and y

Multiply the second equation by 3

[tex]3x – 2y = 20[/tex] times 3

[tex]9x – 6y = 60[/tex]

[tex]2x + 6y = 6[/tex] , add both equations

------------------------------

[tex]11x = 66[/tex]

Divide both sides by 11

[tex]x=6[/tex]

Plug in 6 for x in first equation

[tex]2x + 6y = 6[/tex]

[tex]2(6) + 6y = 6[/tex]

[tex]12 + 6y = 6[/tex], subtract 12 on both sides

[tex]6y = -6[/tex]

divide both sides by 6

[tex]y=-1[/tex]

[tex]x=6  \ and \ y= -1[/tex]

Describe the vertical asymptotes and holes for the graph of y=x-4/x^2+3x+2,

Answers

You have a vertical asymptote at those points where the denominator is equal to zero, you have holes at those points where both the nominator and the denominator are equal to zero at the same time.

Therefore:
x - 4 = 0  
x = 4

x² + 3x + 2 = 0
(x + 2)(x + 1) = 0
x = -2 and x = -1

There are no points in which both numerator and denominator are equal to zero, therefore there are no holes, while x = -2 and x = -1 are vertical asymptotes.


which is the directrix of parabola with equation x^2=4y

Answers

Answer:

[tex]y=-1[/tex]

Step-by-step explanation:

We have been given an equation of parabola [tex]x^2=4y[/tex]. We are asked to find the directrix of our given parabola.    

First of all, we will divide both sides of our given equation by 4.

[tex]\frac{x^2}{4}=\frac{4y}{4}[/tex]      

[tex]\frac{x^2}{4}=y[/tex]      

[tex]y=\frac{x^2}{4}[/tex]      

Now, we will compare our equation with vertex form of parabola:

[tex]y=a(x-h)^2+k[/tex], where, (h,k) represents vertex of parabola.

We can see that the value of a is [tex]\frac{1}{4}[/tex], [tex]h=0[/tex] and [tex]k=0[/tex].

Now, we will find distance of focus from vertex of parabola using formula [tex]p=\frac{1}{4a}[/tex].

Substituting the value of a in above formula, we will get:

[tex]p=\frac{1}{4*\frac{1}{4}}[/tex]

[tex]p=\frac{1}{1}=1[/tex]

We know that directrix of parabola is [tex]y=k-p[/tex].

Substituting the value of k and p in above formula, we will get:

[tex]y=0-1[/tex]

[tex]y=-1[/tex]

Therefore, the directrix of our given parabola is [tex]y=-1[/tex].

when does a rhombus have 4 congruent angles?

Answers

It sometimes. A rhombus could have 2 pairs of opposite congruent angles. That means that the 2 adjacent angles are also supplementary. Two angles could be 50 degree and other two angles could be 130.

Factor completely. x^2−3x−40

Answers

This expression is a generic quadratic expression, so the first thing we need to look at is the last term (-40). Is it negative or positive? What are the factors of it? If the last term is negative, we know that one binomial is a subtraction while the other binomial is an addition. You may be asking, "an addition or subtraction of WHAT?" A binomial factored out of a quadratic expression would look something like this: (x + ____). The blank would equal a factor of the last term. In this case, a pair of factors that would fit is 8 and 5. 
8x5 = 40 and -8 + 5 = -3.

Plug it into the binomial example I provided above and....
(x - 8)(x+5)=40

Voila! You have your factored quadratic expression, hope this helps! 



To factor the quadratic expression x² -3x -40, we find that the expression factors into (x - 8)(x + 5).

The question involves factoring the quadratic expression x² -3x -40 completely. To factor this expression, we look for two numbers that multiply to -40 and add to -3. The numbers that meet these conditions are -8 and 5, since

(-8) * 5 = -40 and

(-8) + 5 = -3.

Therefore, the expression can be factored into (x - 8)(x + 5).

A plane flies round-trip to Philadelphia. It flies to Philadelphia at 220 miles per hour and back home with a tailwind at 280 miles per hour. If the total trip takes 6.5 hours, how many miles does the plane fly round-trip? 560 miles 800.8 miles 1,300 miles 1,601.6 miles

Answers

 1,601.6 miles is correct

sum of 2x 2 + 3x - 4, 8 - 3x, and -5x 2 + 2.

Answers

 (2x² + 3x - 4) +  (8 - 3x) + (-5x² + 2)

=  2x² + 3x - 4 +  8 - 3x - 5x² + 2

= -3x² + 6

= 3(-x² + 2)

Final answer:

To sum the given polynomials, you combine like terms, resulting in the final expression of -3x^2 + 6.

Explanation:

The sum of the polynomials 2x2 + 3x - 4, 8 - 3x, and -5x2 + 2 can be found by combining like terms. This process involves adding the coefficients of terms with the same power of x.

Step 1: Identify and arrange like terms.

Terms with x2: 2x2 and -5x2Terms with x: 3x and -3xConstant terms: -4, 8, and 2

Step 2: Combine like terms.

For x2 terms: 2x2 + (-5x2) = -3x2For x terms: 3x - 3x = 0x (This term will cancel out)For constant terms: -4 + 8 + 2 = 6

Step 3: Write the sum of the polynomials.
The sum is: -3x2 + 6.

) the length of a rectangle is 5 cm less than twice the width. if the area of the rectangle is 88 , find the dimensions of the rectangle.

Answers

pretty sure its done like this, hope it helps!

A line includes the points (2, 10) and (1, 4). what is its equation in slope-intercept form?

Answers

Hi!

This problem has two parts. First you need to find the slope, so let's do that. The equation for the slope is m = y2-y1/x2-x1

We can now plug the two given points into the equation. 
m = 10-4/2-1
m = 6/1
m = 6

Now that we know the slope, and one point we can put this in slope intercept form. Slope intercept form is y=mx + b

So now we can plug in one point and the slope to find b

10 = 6(2) + b
10 = 12 + b
-2 = b

Now that we know both m and b, we can plug only those two into the equation y=mx + b, and we have the equation.

The equation is y = 6x - 2

Solve this easy question and get points!!!

There are two trains. Both trains are going to the same place, taking the same stops, and are going the exact same speed. But one train arrives in
80 Mins and the other train arrives in 1 Hour and 20 Mins. How is this possible?

Answers

They arrive at the same time, for:

1 hour = 60 minutes

60 + 20 = 80 minutes

80 minutes = 80 minutes

Therefore, your answer is "yes it is possible"

hope this helps

Multiple Choice
You can model the population of a certain city between 1945-2000 by the radical function P(x)=55,000 sqrt x-1945. Using this model, in which year was the population of that city 165,000?
A)1948
B)1951
C)1954
D)1957,

Answers

The answer is 1954. Letter C is correct
Solution:
If P(x) =  165,000
Then 
165,000 = 55,000(x - 1945)^(1/2)
 x= 1954

to check it, substitute x
165,000 = 55,000(1954 - 1945)^(1/2)
165,000 =165,000 

15 4/5% of 50

A. .79 B. 79

C. 790 D. 7.9

Answers

15 4/5 is 15.8.  The word "of" means to multiply, and of course we have to change that percent into a decimal to use it in an equation.  .158 × 50 = x is our equation.  Doing the multiplication on the left will give us our x.  x = 7.9, D from above.

"The correct answer is B. 79.

To solve the given problem, we need to calculate 15 4/5 percent of 50. First, let's convert the mixed number to an improper fraction to make the calculation easier.

 15 4/5% as a fraction is 15 + 4/5, which can be written as 75/5 + 4/5 = 79/5.

Now, to find the percentage of 50, we multiply 50 by the fraction representing the percentage:

[tex]\[ \frac{79}{5} \times 50 = \frac{79 \times 50}{5} \][/tex]

Next, we simplify the multiplication:

[tex]\[ \frac{79 \times 50}{5} = \frac{3950}{5} \][/tex]

Now, we divide 3950 by 5:

[tex]\[ \frac{3950}{5} = 790 \][/tex]

However, since we are looking for 15 4/5 percent and not 15 4/5 times 50, we need to adjust our calculation by dividing by 100 to get the correct percentage:

[tex]\[ \frac{790}{100} = 79 \][/tex]

Therefore, the final answer is B. 79."

In a class, every student knows French or German (or both). 15 students know French, and 17 students know German. What is the largest possible number of students in that class?

Answers

Solution:

we are given that

In a class, every student knows French or German (or both).

15 students know French, and 17 students know German.

Suppose there are x student who knows both French and German.

Then Total number of student in the class will be [tex] (15+17-x)=32-x [/tex]

But to guess the largest possible number of student in the class we can assume x=0

Hence the largest Possible number of Student in the class=32

The shorter leg of a right triangle is 1414 feet less than the other leg. find the length of the two legs if the hypotenuse is 3434 feet.

Answers

let the width be x ft
the length will be (x+14) ft
hypotenuse is 34 ft
given that our triangle is right triangle, using Pythagorean theorem?
c^2=a^2+b^2
substituting our values in the formula we get:
34^2=x^2+(x+14)^2
1,156=x^2+x^2+28x+196
simplifying this we get
0=2x^2+28x-960
solving the quadratic equation we get:
x=16 or x=-30
therefore the width is 16 ft and the length is 16+14=30

What is the solution of log6x+log6(x+5)=2?

Answers

Answer:4

Step-by-step explanation:just did it on edge

To solve log6(x) + log6(x + 5) = 2, combine the logarithms, rewrite in exponential form, and solve the resulting quadratic equation. The solutions are x = -9 and x = 4, but since logarithms of negative numbers are undefined, the final answer is x = 4.

To solve this logarithmic equation, follow these steps:

Combine the logarithms: Use the property of logarithms that states logb(a) + logb(c) = logb(a × c).
So, we have: log6(x) + log6(x + 5) = log6(x(x + 5)).
This simplifies to log6(x² + 5x).Set the logarithmic expression equal to 2: log6(x² + 5x) = 2.Rewrite the equation in exponential form: Using the definition of a logarithm, a logarithm logb(y) = c can be rewritten as [tex]b^{\\c[/tex] = y. Thus, we get 6² = x² + 5x.
This simplifies to 36 = x² + 5x.Solve the quadratic equation: Rewrite the quadratic equation in standard form: x² + 5x - 36 = 0.
Then, factor the quadratic: (x + 9)(x - 4) = 0.Find the solutions: Set each factor to zero and solve for x.
x + 9 = 0 → x = -9
x - 4 = 0 → x = 4.Check the solutions in the original equation: Since the logarithm of a negative number is undefined, discard x = -9.
Therefore, the solution to the equation is x = 4.

Final Answer: x = 4.

What is the average of the first n positive even numbers?

Answers

The average of all of them is the same as the average of the first and last, the same as the middle number in the group:
  1 + n

Solution:

we have been asked to find the average of the first n positive even numbers.

Let the firm n positive even numbers be

[tex] 2,4,6,8,10,12,.........2(n-1), 2n [/tex]

As we know that average of numbers[tex] =\frac{\text{Sum of Numbers }}{Total number of Numbers}\\ [/tex]

Required Average[tex] =\frac{2+4+6+2(n-1)+2n}{n}\\ [/tex]

Required Average[tex] =\frac{2(1+2+3+....+(n-1)+n)}{n} [/tex]

As we know the sum of first n terms[tex] =\frac{n(n+1)}{2} [/tex]

Required Average[tex] =\frac{2n(n+1)}{2n}=n+1 \\ [/tex]


In a tessellation, what must the sum of the angles be where the vertices meet?
90° 180° 360° 60°

Answers

the interior angles must add up to 360°
C (360 degrees) is your answer

Which of the symbols correctly relates the two numbers below? Check all that apply.

55 ? 35

A.
B.
C. <
D.
E. =
F. >
The other symbols dont want to show so if its another on plz tell me or add me on fb if you guys wanna help me i need to finish this,

Answers

>
55>35

The correct answer is > because 55 is larger than 35 and that is the sign for larger than
                                                                                                                  

Raj is 3 years older than Zia. The sum of the squares of their ages is 369. How old are they?

Answers

Let
x--------------> ages of Raj
y--------------> age of Zia

we know that
x=y+3-------------> equation 1
x²+y²=369-----------> equation 2

I substitute 1 in 2

(y+3)²+y²=369----------> y²+6y+9+y²=369---------> 2y²+6y-360=0
2y²+6y-360=0
using a graph tool-----------> to calculate the quadratic equation
see the attached figure

the solution is
y=12
x=y+3--------> x=12+3--------> x=15

the answer is
Raj is 15 years old
Zia is 12 years old

Final answer:

Zia's age is 12 and Raj's age is 15

Explanation:

To solve this problem, we can set up two equations using the given information. Let's assume Zia's age is x. Since Raj is 3 years older than Zia, Raj's age can be represented as x + 3.

The first equation is [tex]x^2 + (x + 3)^2 = 369.[/tex]

Simplifying this equation, we get [tex]x^2 + x^2 + 6x + 9 = 369.[/tex]

Combining like terms, we have [tex]2x^2 + 6x + 9 = 369.[/tex]

Next, we can rearrange the equation by subtracting 369 from both sides and combining like terms to get [tex]2x^2 + 6x - 360 = 0.[/tex]

Now, we can solve this quadratic equation for x using factoring, completing the square, or the quadratic formula. The solutions are x = -15 and x = 12.

Since age cannot be negative, Zia's age is 12 and Raj's age is 12 + 3 = 15.

Other Questions
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