Answers
let's use the conjugate of the denominator and multiply top and bottom by it, recall the conjugate of a binomial is simply the same binomial with a different sign in between.
[tex]\bf \cfrac{2\sqrt{x}-3\sqrt{y}}{\sqrt{x}+\sqrt{y}}\cdot \cfrac{\sqrt{x}-\sqrt{y}}{\sqrt{x}-\sqrt{y}}\implies \cfrac{2\sqrt{x}\sqrt{x}-2\sqrt{x}\sqrt{y}~~-~~3\sqrt{x}\sqrt{y}+3\sqrt{y}\sqrt{y}}{\underset{\textit{difference of squares}}{(\sqrt{x}+\sqrt{y})(\sqrt{x}-\sqrt{y})}} \\\\\\ \cfrac{2\sqrt{x^2}-2\sqrt{xy}-3\sqrt{xy}+3\sqrt{y^2}}{(\sqrt{x})^2-(\sqrt{y})^2}\implies \cfrac{2x-5\sqrt{xy}+3y}{x-y}[/tex]
Answer:
[tex]\dfrac{2x-5\sqrt{xy}+3y}{x-y}\\[/tex]
Step-by-step explanation:
In Rationalize the denominator we multiply both numerator and denominator by the conjugate of denominator.
In Conjugate we change the sign of middle operator.
Example: Congugate of (a + b) = a - b
Now Solving the given expression,
[tex]\dfrac{2\sqrt{x} - 3\sqrt{y}}{\sqrt{x} + \sqrt{y}} = \dfrac{2\sqrt{x} - 3\sqrt{y}}{\sqrt{x} + \sqrt{y}}\times \dfrac{\sqrt{x} - \sqrt{y}}{\sqrt{x} - \sqrt{y}}\\\\\Rightarrow \dfrac{(2\sqrt{x} - 3\sqrt{y})(\sqrt{x} - \sqrt{y})}{( \sqrt{x} + \sqrt{y}){(\sqrt{x} - \sqrt{y}})}\ \ \ \ \ \ \ \ \ \ \ [\because (a-b)(a+b)=(a^{2} +b^{2})]\\\Rightarrow \dfrac{2x-2\sqrt{xy}-3\sqrt{xy}+3y}{x-y}\\\\ \Rightarrow \dfrac{2x-5\sqrt{xy}+3y}{x-y}\\[/tex]
Related Questions
I filled 6/9 of the prescriptions for the pharmacist to review. The pharmacist returns and reviews 2/3 of the prescriptions. How many more prescriptions does the pharmacist have left to review that I filled?
Answers
[tex]\left(1-\dfrac{2}{3}\right)\cdot\dfrac{6}{9}=\dfrac{1}{3}\cdot \dfrac{2}{3}=\dfrac{2}{9}[/tex]
The pharmacist has 2 more prescriptions left to review that you filled.
To find out how many prescriptions the pharmacist has left to review, we can follow these steps:
1. Calculate the total number of prescriptions filled by you:
[tex]\[ \text{Total filled prescriptions} = \frac{6}{9} \times \text{Total prescriptions} \][/tex]
2. Calculate the number of prescriptions reviewed by the pharmacist:
[tex]\[ \text{Prescriptions reviewed by pharmacist} = \frac{2}{3} \times \text{Total filled prescriptions} \][/tex]
3. Calculate the number of prescriptions left for the pharmacist to review:
[tex]\[ \text{Prescriptions left to review} = \text{Total filled prescriptions} - \text{Prescriptions reviewed by pharmacist} \][/tex]
Let's put the numbers into these equations. Assuming there were initially 9 prescriptions:
1. Total filled prescriptions:
[tex]\[ \text{Total filled prescriptions} = \frac{6}{9} \times 9 = 6 \][/tex]
2. Prescriptions reviewed by pharmacist:
[tex]\[ \text{Prescriptions reviewed by pharmacist} = \frac{2}{3} \times 6 = 4 \][/tex]
3. Prescriptions left to review:
[tex]\[ \text{Prescriptions left to review} = 6 - 4 = 2 \][/tex]
which of the following is an equation of the line passing through the points (-1, 4) and (1, 2)?.
Answers
Answer:
y-4 =-1(x+1) point slope form
y-2 = -1(x-1)
y = -x +3 slope intercept form
Step-by-step explanation:
We have 2 points, we can find the slope
m = (y2-y1)/(x2-x1)
= (2-4)/(1--1)
(2-4)/(1+1)
-2/2
=-1
The slope is -1
Then we can use point slope form to find an equation
y-y1 =m(x-x1)
y-4 = -1(x--1)
y-4 =-1(x+1) point slope form
Using the other point
y-2 = -1(x-1)
Distribute the -1
y-2 = -1x +1
Add 2 to each side
y-2+2 = -x+1+2
y = -x +3 slope intercept form
Find the shortest distance from A to C in the diagram below.
Answers
Answer:
The shortest distance from A to C is [tex]AC=5\sqrt{13}\ units[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The shortest distance from A to C is the hypotenuse of the right triangle AYC
Applying the Pythagoras Theorem
[tex]AC^{2}=AY^{2} +YC^{2}[/tex]
step 1
Find the length YC (hypotenuse of the right triangle YBC)
Applying the Pythagoras Theorem
[tex]YC^{2}=YB^{2} +BC^{2}[/tex]
substitute the given values
[tex]YC^{2}=6^{2} +15^{2}[/tex]
[tex]YC^{2}=261[/tex]
[tex]YC=\sqrt{261}\ units[/tex]
step 2
Find the shortest distance from A to C
[tex]AC^{2}=AY^{2} +YC^{2}[/tex]
substitute the given values
[tex]AC^{2}=8^{2} +\sqrt{261}^{2}[/tex]
[tex]AC^{2}=325[/tex]
[tex]AC=\sqrt{325}\ units[/tex]
[tex]AC=5\sqrt{13}\ units[/tex]
Which sentence demonstrates the multiplicative identity?
1/2 • 2= 1
1/2• 1= 1/2
1/2 + 0 = 1/2
Answers
Answer:
1/2 • 1 = 1/2
Step-by-step explanation:
It shows that anything multiplied by 1 is itself.
Answer:
1/2· 1= 1/2
Step-by-step explanation:
When multiplying by 1, you will get the same number.
how do i solve 3/-2 x = 24
Answers
Answer:
x = -16
Step-by-step explanation:
3
(— • x) - -24 = 0
2
-24 -24 • 2
-24 = ——— = ———————
1 2
For this case we must solve the following equation:
[tex]\frac {3} {- 2x} = 24[/tex]
Multiplying by 2x on both sides of the equation:
[tex]-3 = 24 * 2x\\-3 = 48x[/tex]
Dividing between 48 on both sides of the equation:
[tex]x = - \frac {3} {48}[/tex]
We simplify:
[tex]x = - \frac {1} {16}[/tex]
Answer:[tex]x = - \frac {1} {16}[/tex]
A farmer feeds his cows 200 pounds of feed each day and has 700 pounds of feed in his barn. Another farmer feeds his cows 350 lbs of feed each day and has 1000 lbs of feed in his barn. In how many days will the two farmers have the same amount of feed left?
Answers
Answer:
The farmers will have the same amount of feed (300 lbs) in 3 days
Step-by-step explanation:
After dividing the total amounts of feed by the daily feed amounts, it’s found that the two farmers will have the same amount of feed left after approximately 3.5 days.
Explanation:To solve this problem, you need to find out how many days it takes for both farmers to run out of feed. For the first farmer, divide the total amount of feed (700 pounds) by the amount he uses each day (200 pounds). This comes to 3.5 days. For the second farmer, divide his total feed (1000 pounds) by the amount he uses each day (350 pounds), which comes to approximately 2.857 days.
Since we want to know when they will have the same amount of feed left, we look for the higher number, because the first farmer will still have feed left when the second farmer runs out. Therefore, the two farmers will have the same amount of feed left after around 3.5 days.
Learn more about Feed consumption here:https://brainly.com/question/33314430
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what is 144^1/2=12 written in logarithmic form
Answers
Answer:
[tex]\log_{144}(12)=\frac{1}{2}[/tex]
Step-by-step explanation:
First step identify the base. The base is 144.
The exponent is the logarithm.
The number not mentioned is the one that goes inside.
In other words [tex]a^x=b[/tex] is equivalent to [tex]log_a(b)=x[/tex]
There are some restrictions on what a and b can be.
You read [tex]log_a(b)=x[/tex] as log base a of b equals x
x is the exponent
a is the base
So we have log base 144 of 12 equals 1/2
[tex]\log_{144}(12)=\frac{1}{2}[/tex]
[tex](12 {x}^{2} + 13y)(4x \times 2xy)[/tex]
need help solving? can anyone help
Answers
Answer:
[tex]96x^4y+104x^2y^2[/tex]
is the simplified form of
your given problem:
[tex](12x^2+13y)(4x \times 2xy)[/tex].
Step-by-step explanation:
So the given problem is this:
[tex](12x^2+13y)(4x \times 2xy)[/tex]
I'm going to do the multiplication in the second ( ).
Nothing can be done in the first ( ) because the operation is addition and those two terms aren't like terms.
[tex](12x^2+13y)(8x^2y)[/tex]
I got x^2 because of x(x) part.
Now we get to distribute 8x^2y to both terms in the ( ).
[tex]12x^2 \cdot 8x^2y+13y \cdot 8x^2y[/tex]
Adding exponents on bases that have the same variable:
[tex]96x^4y+104x^2y^2[/tex]
What is the vertex of the parabola? Assume p > 0.
Answers
Final answer:
The vertex of a parabola in the form y = ax + bx² can be found using the vertex formula x = -b/(2a). The vertex represents the highest or lowest point on the graph depending on whether a is positive or negative.
Explanation:
The vertex of a parabola in the form y = ax + bx² can be found using the vertex formula. The vertex formula is x = -b/(2a), which gives the x-coordinate of the vertex. To find the y-coordinate of the vertex, substitute the x-coordinate into the equation y = ax + bx². The vertex of the parabola represents the highest or lowest point on the graph, depending on whether the coefficient a is positive or negative.
find the length of wire required to fence a rectangle field with three round, whose length and breadth are 150 m and 80m respectively
Answers
Answer:
1380 meters
Step-by-step explanation:
perimeter of a rectangle :2(l+b)
2(150 +80)
2(230)
460 meters of wire for one round
for three rounds :3×460=
1380 meters
Which three pairs of measurements are possible side length for the triangle?
Answers
Answer:
A, B, E, F
Step-by-step explanation:
In a 30-60-90 triangle, the hypotenuse is twice the length of the short leg.
That makes choice E possible.
In a 30-60-90 triangle, the long leg is sqrt(3) times the length of the short leg.
That makes choices A, B, and F possible.
Answer:
First option.
Option 5.
Option 6.
Step-by-step explanation:
The formula for a 30-60-90 triangle is this:
1) Side opposite to 30 will be value [tex]a[/tex].
2) Side opposite to 60 will be value [tex]a\sqrt{3}[/tex].
3) Hypotenuse will be [tex]2a[/tex].
So let's look and see:
First option: [tex]AB=4[/tex] and [tex]BC=4\sqrt{3}[/tex]
AB is opposite of the angle with 30 degree measurement.
BC is opposite of the angle with 60 degree measurement.
So [tex]a=4[/tex] here.
So the side opposite of 60 using the formula should be [tex]4 \sqrt{3}[/tex] which it is here.
So first option looks good.
Second option: [tex]BC=2\sqrt{3}[/tex] and [tex]AC=2[/tex].
We aren't given the side opposite to 30.
AC is the hypotenuse so 2a=2 which means the side opposite to 30 is a=2/2=1.
This means using the formula that the side opposite to 60 will be [tex]1\sqrt{3}=\sqrt{3}[/tex] but we don't have that.
So not option 2.
Third option: [tex]AB=3[/tex] and [tex]AC=3\sqrt{3}[/tex]
AB is the side opposite of 30, so we have [tex]a=3[/tex]
AC is the hypotenuse so that side should be [tex]2a=6[/tex] and it isn't.
Option 3 is not working.
Fourth option: [tex]BC=10[/tex] and [tex]AC=4\sqrt{3}[/tex]
So we have that [tex]2a=4\sqrt{3}[/tex] which means [tex]a=2\sqrt{3}[/tex] and so [tex]a\sqrt{3}=2\sqrt{3}\sqrt{3}=2(3)=6[/tex] but that is a contradiction because we have this value should be 10.
Not option 4.
Option 5: [tex]AB=7[/tex] and [tex]AC=14[/tex]
So we have [tex]a=7[/tex] and [tex]2a=14[/tex] so this looks good.
Option 6: [tex]AB=11[/tex] and [tex]BC=11\sqrt{3}[/tex]
[tex]a=11[/tex] so [tex]a\sqrt{3}=11\sqrt{3}[/tex] which is what we have.
Option 6 works.
If seamstress is paid 7.85 per hour and works 18.75 hours in one week, how much is she paid in one week?
Answers
Solve for x
X^2+6x+9=20
Answers
Answer:
x = 1.47 or x = -7.47
Step-by-step explanation:
x²+6x+9=20
This is a quadratic equation
x²+6x+9-20=0
x²+6x-11=0
Step 1 : Write the quadratic formula
x = -b±√b²-4(a)(c)
2a
Step 2 : Substitute values in the formula
a = 1
b = 6
c = -11
x = -6±√6²-4(1)(-11)
2(1)
x = -6±√80
2
x = -3 + 2√5 or x = -3 - 2√5
x = 1.47 or x = -7.47
!!
Answer:
x=1.472 or x=-7.472
Step-by-step explanation:
Lets begin by rearranging the equation into the format ax²+bx+c=0
The equation will be:
x²+6x+9-20=0
x²+6x-11=0
We shall use the quadratic formula to solve the equation.
x=[-b±√(b²-4ac)]/2a
=[-6±√(6²-4×1×-11)]/2
=[-6±√80]/2
=[-6±8.944]2
x= Either (-6+8.944)/2 or x= (-6-8.944)/2
Solving for x in each case gives:
x=1.472 or x=-7.472
About what percentage of Guadalupe's payments so far have gone to paying
interest?
Answers
Answer: C. 96% -------- APEX :D
Graph the given relation or equation and find the domain and range. Then determine whether the relation or equation is a function. (3.9, 5.9), (–1.1, 5.9), (–4.1, 3.9), (–4.1, –2.1)
Answers
Answer:
See attachment
The relation is not a function.
The domain is [-4.1,3.9]
The range is [-2.1,5.9]
Step-by-step explanation:
The given relation has ordered pairs (3.9, 5.9), (–1.1, 5.9), (–4.1, 3.9), (–4.1, –2.1)
It is implied in the ordered pairs that the relation is a continuous function.
We plot the points and connect them with straight lines as shown in the attachment.
The relation is not a function because its graph fails the vertical line test.
In other words, we have an x-coordinate that corresponds to more than one y-coordinate.
-4.1 corresponding to 3.9 and -2.1 at the same time.
The domain is the set of values for which the function is defined.
The domain is [-4.1,3.9]
The range refers to the corresponding y-values for which the function exists.
The range is [-2.1,5.9]
In the figure, a square is inside another bigger square.
If a = 4 units and b = 3 units, the length of the diagonal of the outside square rounded to the nearest tenth is _____
units and the length of the diagonal of the inside square rounded to the nearest tenth is _____ units.
Answers
Answer:
Part 1) The length of the diagonal of the outside square is 9.9 units
Part 2) The length of the diagonal of the inside square is 7.1 units
Step-by-step explanation:
step 1
Find the length of the outside square
Let
x -----> the length of the outside square
c ----> the length of the inside square
we know that
[tex]x=a+b=4+3=7\ units[/tex]
step 2
Find the length of the inside square
Applying the Pythagoras Theorem
[tex]c^{2}= a^{2}+b^{2}[/tex]
substitute
[tex]c^{2}= 4^{2}+3^{2}[/tex]
[tex]c^{2}=25[/tex]
[tex]c=5\ units[/tex]
step 3
Find the length of the diagonal of the outside square
To find the diagonal Apply the Pythagoras Theorem
Let
D -----> the length of the diagonal of the outside square
[tex]D^{2}= x^{2}+x^{2}[/tex]
[tex]D^{2}= 7^{2}+7^{2}[/tex]
[tex]D^{2}=98[/tex]
[tex]D=9.9\ units[/tex]
step 4
Find the length of the diagonal of the inside square
To find the diagonal Apply the Pythagoras Theorem
Let
d -----> the length of the diagonal of the inside square
[tex]d^{2}= c^{2}+c^{2}[/tex]
[tex]d^{2}= 5^{2}+5^{2}[/tex]
[tex]d^{2}=50[/tex]
[tex]d=7.1\ units[/tex]
If a = 4 units and b = 3 units, the length of the diagonal of the outside square rounded to the nearest tenth is 9.9 units
units and the length of the diagonal of the inside square rounded to the nearest tenth is 7.1 units
Let's solve its step by step
step 1
Find the length of the outside square
Let
x -----> the length of the outside square
c ----> the length of the inside square
we know that
x=a+b=4+3=7 units
step 2
Find the length of the inside square
Applying the Pythagoras Theorem
[tex]c^(2)= a^(2)+b^(2)[/tex]
substitute
[tex]c^(2)= 4^(2)+3^(2)[/tex]
[tex]c^(2)=25[/tex]
c=5 units
step 3
Find the length of the diagonal of the outside square
To find the diagonal Apply the Pythagoras Theorem
Let
D -----> the length of the diagonal of the outside square
[tex]D^(2)= x^(2)+x^(2)[/tex]
[tex]D^(2)= 7^(2)+7^(2)[/tex]
[tex]D^(2)=98[/tex]
D=9.9 units
step 4
Find the length of the diagonal of the inside square
To find the diagonal Apply the Pythagoras Theorem
Let
d -----> the length of the diagonal of the inside square
[tex]d^(2)= c^(2)+c^(2)[/tex]
[tex]d^(2)= 5^(2)+5^(2)[/tex]
[tex]d^(2)=50[/tex]
d=7.1 units
The graph shows Melissa's heart rate in beats per minute be) during the tirst few minutes other cool down after
jogging
Melissa's Heart Rate
Heart Rate -
Answers
Answer:
The domain is {1,2,3,4,5}
The range is {150,135,120,105,90}
Step-by-step explanation:
Domain is the set of x-values (x axis) and Range is the set of y-values (y axis).
Now if you look at the relation (points given), you can see the 5 points corresponds to 1,2,3,4, adn 5 in the x axis (minutes). So this is the domain - 1,2,3,4,5.
If we look at the y-axis (Heart Rate) , the values corresponding to 1,2,3,4,and 5 are 150, 135, 120, 105, and 90. These are the range.
Hence the last choice is the correct answer.
Answer: Domain = {1,2,3,4,5}
Range = {150,135, 120,105, 90}
Step-by-step explanation:
We know that,
Domain : Set of all input values .
Range : Set of output values.
In a graph, x values are the input values and y values are output values.
Given : The graph shows Melissa's heart rate in beats per minute be) during the first few minutes other cool down after jogging .
In the graph, number of minutes are shown by x-values and heart rate are shown by y-values.
Thus from graph, Domain = {1,2,3,4,5}
Range = {150,135, 120,105, 90}
The figure below is a right rectangular prism. which expression represents the volume of the prism?
Answers
Answer: The expression (equation/formula) for the volume of a:
" right rectangular prism " ; is represented by:
____________________________________________________
→ " V = L * w * h " ;
____________________________________________________
in which: all the dimensions are in the same "units of measurement" (or converted to the same "units of measurement" ;
and in which:
" V " is the "volume" of the right rectangular prism; in the "cubic units" ; or written as: "units³ " ; or, [insert the particular units used}^ ³ " ;
→ that is, [units] raised to the "3rd [third] power" ; assuming these units are the same same "fundamental units of measurement" as the "other 2 (two) values in the expression".
If we are given no specific units of measurement whatsoever, then we use the generic term, "units" as the "units of measurement" ; and we express the "volume; "V" ; of a "right rectangular prism" as: " units ³ " ; or "cubic units" ;
in our answer— if we are asked to solve for the:
"volume; "V"; of a "right rectangular prism" ;
_________________________________________________
and in which:
"L" represents the "length" of a "right rectangular prism" ;
"w" represents the "width" of a "right rectangular prism" ;
"h" represents the "height" of a "right rectangular prism" .
_________________________________________________
To given an example:
Say we have a "right rectangular prism" ; with the given measurements:
width , "w" : w = 2 units;
length, "L" : L = 3 units ;
height, "h" : h = 8 units.
_________________________________________________
We are asked to "find the volume " ; of this "right recentangular prism" .
The formula for the volume; "V" ; of this "right rectangular prism" ;
is:
_________________________________________________
→ Volume = Length * width * height ;
that is:
→ V = L * w * h ;
Solve for the volume; "V" .
_________________________________________________
→ V = L * w * h ; Now plug in the values given:
→ V = (3 units) * (2 units) * (8 units) ;
= 3 * 2 * 8 * (units) * (units) * (units) ;
= 3 * 2 * 8 * units ³ ;
= 48 units ³ .
_________________________________________________
Hope this answer— and explanation—is helpful to you!
Wishing you the best in your academic pursuits
— and within the "Brainly" community!
_________________________________________________
Answer: A
Step-by-step explanation:
The time it takes to read a book depends on the number of pages in the book
Answers
The situation "The time it takes to read a book depends on the number of pages in the book" in function notation is: A. Time(pages).
In Mathematics, a function is typically used in mathematics for uniquely mapping an input variable (domain or independent value) to an output variable (range or dependent value).
This ultimately implies that, an independent value represents the value on the x-axis of a cartesian coordinate while a dependent value represents the value on the y-axis of a cartesian coordinate.
In this context, we can logically deduce that time is a function of the number of pages, so it should be written in function notation as follows:
Time(pages).
Complete Question:
Which of the following shows the situation below in function notation?
The time it takes to read a book depends on the number of
pages in the book.
A. Time(pages)
B. Book(pages)
C.Pages(time)
D. Book(time)
- the following functions.
f = {(-4,1),(5, 1), (1, -1)}
and
8 = {(5, 1), (1,4)}
2: Find (f + g)(1).
Answers
Answer:
(f+g)(1)
equals
3
Step-by-step explanation:
(f+g)(1) is f(1)+g(1).
f(1) means what y corresponds to x=1 so f(1)=-1.
g(1) means what y corresponds to x=1 so g(1)=4.
So (f+g)(1)=f(1)+g(1)=-1+4=3.
What is the solution to the system of equations? {x=5 y=2x−1} (5, 9) (9, 5) (5, 11) (11, 5)
Answers
Answer:
(5, 9)
Step-by-step explanation:
Given the 2 equations
x = 5 → (1)
y = 2x - 1 → (2)
x = 5 is the value of the x- coordinate.
Substitute x = 5 into (2) for the corresponding value of y
y = (2 × 5) - 1 = 10 - 1 = 9
Solution is (5, 9 )
One third of the sum of 5 times a number and 3 is less than one fourth the sum of six times that number and 5
Answers
Answer:
x < 3/2.
Step-by-step explanation:
1/3( 5x + 3) < 1/4(6x + 5)
5/3 x + 1 < 3/2x + 5/4
5/3 x - 3/2 x < 5/4 - 1
1/6 x < 1/4
x < 6/4
x < 3/2.
The value of the variable x is less than 3/2.
What is the solution to the equation?The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.
Let x be the number.
One-third of the sum of 5 times a number and 3 is less than one-fourth the sum of six times that number and 5. Then the equation will be
(1/3)(5x + 3) < (1/4)(6x + 5)
Simplify the inequality, then the value of x will be
20x + 12 < 18x + 15
2x < 3
x < 3/2
The value of the variable x is less than 3/2.
More about the solution of the equation link is given below.
https://brainly.com/question/545403
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Factor 3h2 – 11h - 42
A. (3h – 7)(h + 6)
B. 3(h + 7)(h - 6)
C. (34 – 6)(h + 7)
D. (3h + 7)(h – 6)
Answers
3*-42=-126
The factors of -126 that add to -11 are 7 and -18
replace -11h with 7h-18h
3h^2 + 7h - 18h - 42
Factor the first two terms and last two terms
h(3h+7) - 6(3h+7)
See how the two parentheses are the same?
THE ANSWER IS BELOW!!
(h-6)(3h+7)
the first parentheses has the terms that were outside, and the second has the original bracketed terms
This matches option D (it just multiplies the terms backwards, which gives the same result)
Answer:
The correct answer is option D. (3h + 7)(h – 6)
Step-by-step explanation:
It is given a quadratic function ,
3h² - 11h - 42
To find the factors of given function
3h² - 11h - 42 = 3h² - 18h + 7h - 42
= 3h(h -6) + 7(h - 6)
=(h - 6)(3h + 7)
= (3h + 7)(h – 6)
The correct answer is option D. (3h + 7)(h – 6)
suppose a figure is located in Quadrant l. which of the following sequences will result in an image that is located in Quadrant lll?
Answers
Answer:
Step-by-step explanation:
A will.
Suppose the object is placed on (5,4)
If you rotate it 180o counterclockwise, the point will become (-5,-4) (both x and y will change signs.)
Moving one unit down will still leave you in quadrant III.
If you start in another quadrant, this answer will not be correct. If the point started out in quadrant 2, rotating it 180o counterclockwise will put you in quad 4. For example
Object Start: (-2,3) Starts in quad 2
Image found: (- -2, - 3) = (2, - 3) which is in quad 4.
The Rangers won 5 of their first 8 games. At this rate,how many games should the Rangers win out of 56 games? F. 28 games. G. 32 games. H. 35 games. I. 37 games.
Answers
Answer: H. 35 games
Step-by-step explanation: Set up a proportion.
5/8 = X/56
Cross multiply.
5 x 56 = 280
8 x X = 8x
The cross multiplied equation will be 280=8x.
Divide by 8 in order to isolate x.
x=35
They will win 35 games.
Answer:
The answer is H. 35 games
PLEASE HELP AGAIN WILL MARK BRAINLEST !!!!!
Answers
Answer:
3
Step-by-step explanation:
g(-1) means what is g(x) when x=-1.
So find -1 under the column labeled x and then scroll directly to the right of that and you should see what g(-1). It is 3
Here are my examples:
g(-8)=6
g(-5)=-2
g(-1)=3
g(0)=-5
Scarlett is designing a package for a candy her company makes. She has cut several cardboard equilateral triangles, squares, rectangles, and regular pentagons to try out her ideas for the package. Which 3-D figure and combination of shapes can Scarlett use? Equilateral triangle prism with one triangle and three rectangles Pentagonal prism with one pentagon and five rectangles Rectangular prism with four rectangles Square prism with six squares
Answers
Answer:
it would be the 4th option
Step-by-step explanation:
all the above are wrong except the fourth option because a 3-D square or cube is made up of 6 equal squares. I hope this helps a-lot. : )
The 3-D figure Scarlett can make and the combinations of shapes she can use is a square prism with six squares.
What is a square prism?
A square prism is a three-dimensional object that is made up of six squares.
The volume of a square prism = length x width x height.
To learn more about right square prism, please check: https://brainly.com/question/13048128
Which equation represents a line that passes through (-2, 4) and has a slope of 1/2?
Answers
Answer:
[tex]\large\boxed{y-4=\dfrac{1}{2}(x+2)\text{- point-slope form}}\\\boxed{y=\dfrac{1}{2}x+5\text{- slope-intercept form}}[/tex]
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
We have the slope [tex]m=\dfrac{1}{2}[/tex] and the point [tex](-2, 4)[/tex].
Substitute:
[tex]y-4=\dfrac{1}{2}(x-(-2))[/tex]
[tex]y-4=\dfrac{1}{2}(x+2)[/tex] - point-slope form
Convert to the slope-intercept form (y = mx + b):
[tex]y-4=\dfrac{1}{2}(x+2)[/tex] use the distributive property
[tex]y-4=\dfrac{1}{2}x+1[/tex] add 4 to both sides
[tex]y=\dfrac{1}{2}x+5[/tex] - slope-intercept form
If a triangle has one angle measuring 40 degrees and a second angle measuring 100 degrees, what is the measurement of the third angle
A. 80
B.40
C.140
D.120
Answers
Answer:
B. 40
Step-by-step explanation:
All triangle angles equal 180
100+40=140
180-140=40
B. 40 is the answer.
What is the equation in point slope form of the line passing through (-2,0) and (2,8)?
Answers
Answer:
y - 8 = 2(x - 2)Step-by-step explanation:
The point-slope of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-2, 0) and (2, 8).
Substitute:
[tex]m=\dfrac{8-0}{2-(-2)}=\dfrac{8}{4}=2[/tex]
for the point (-2, 0):
[tex]y-0=2(x-(-2))\\\\y-0=2(x+2)[/tex]
for the point (2, 8):
[tex]y-8=2(x-2)[/tex]