Answer:
The correct option to the following question is an option (D).
Explanation:
Because RPO(Recovery point objective) is the objective in which we getting the greatest level of the privacy. confidence and the important thing is security for our resources.
The best thing is that the center of activity of the RPO in on the data and the overall elasticity of the loss of your company.
A mass m is attached to the end of a rope of length r = 3 meters. The rope can only be whirled around at speeds of 1, 10, 20, or 40 meters per second. The rope can withstand a maximum tension of T = 60 Newtons. Write a program where the user enters the value of the mass m, and the program determines the greatest speed at which it can be whirled without breaking the rope.
Answer:
Explanation:
Let's do this in Python. We know that the formula for the centripetal force caused by whirling the mass is:
[tex]F = m\frac{v^2}{r}[/tex]
where v is the speed (1, 10, 20, 40) and r = 3 m is the rope length.
Then we can use for loop to try calculating the tension force of each speed
def maximum_speed(m):
for speed in [1, 10, 20, 40]:
tension_force = m*speed^2/3
if tension_force > 60:
return speed
return speed
Write a Python program where the user enters the number of elements in a list ‘n’ and those ‘n’ numbers that form the list. The user also enters a number ‘m’ by which all the elements of the list are multiplied and printed. You must print both the list before multiplying and the list after multiplied by the number ‘m’.
Answer:
lst = []
multiple = []
num = int(input('How many numbers: '))
multipleOf = int(input('Enter the number to multiply with: '))
for n in range(num):
lst.append(n)
numbers = n * multipleOf
multiple.append(numbers)
print("elements in given list is :", lst)
print("multiple in given list is :", multiple)
Explanation:
User will enter the number and then enter the number to multiply that list.
What is the difference between phishing and pharming?
A. Phishing is not illegal, pharming is illegal
B. Phishing is the right of the company, where pharming is the right of the individual
C. Phishing is a technique to gain personal information for the purpose of identity theft, and pharming reroutes requests for legitimate websites to false websites
D. All of these are correct
Answer:
Option C. Phishing is a technique to gain personal information for the purpose of identity theft, and pharming reroutes requests for legitimate websites to false websites.
is the correct answer.
Explanation:
Phishing is define as a technique to gain personal information for the purpose of identity theft that may be used by hackers. They may send you malicious email that may look like legitimate ones but are the ones that trick you.Pharming is defined as the fraudulent practice that reroutes requests for legitimate websites to false websites. It can even occur by simply clicking the authentic link or type in the website URL.i hope it will help you!
A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Consider the case of a source host connected to the source router, which is connected to the destination router, andthen to the destination host If either of the routers discards a packet, the source host eventually times out and tries again.If both host-router and router- router lines are counted as hops, what is the mean number of(a) hops a packet makes per transmission?(b) transmissions a packet makes?(c) hops required per received packet?
Answer:
a.) k² - 3k + 3
b.) 1/(1 - k)²
c.) [tex]k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }[/tex]
Explanation:
a.) A packet can make 1,2 or 3 hops
probability of 1 hop = k ...(1)
probability of 2 hops = k(1-k) ...(2)
probability of 3 hops = (1-k)²...(3)
Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)
= (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)
= k + 2k - 2k² + 3(1 + k² - 2k)
∴mean number of hops = k² - 3k + 3
b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3
if k = 0 then number of hops is 3
if k = 1 then number of hops is (1 - 3 + 3) = 1
multiple transmissions can be needed if K is between 0 and 1
The probability of successful transmissions through the entire path is (1 - k)²
for one transmission, the probility of success is (1 - k)²
for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)
for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on
∴ for transmitting a single packet, it makes:
∞ n-1
T = ∑ n(1 - k)²(1 - (1 - k)²)
n-1
= 1/(1 - k)²
c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)
from (a) above, mean number of hops when transmitting a packet = k² - 3k + 3
from (b) above, mean number of transmissions by a packet = 1/(1 - k)²
substituting: mean number of required packet = [tex]k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }[/tex]
A packet makes on average (2-p) hops per transmission, with the mean number of transmissions being 1/((1-p)^2), and hence hops required per received packet being (2-p)/((1-p)^2).
Explanation:Mean Number of Hops and Transmissions for Datagram Networks
To find the mean number of hops per transmission, consider that there are 4 hops possible (source to source router, source router to destination router, destination router to destination, and destination to destination router in the case of a retry). Assuming a retry only occurs when a packet is dropped, and each router has a probability p of dropping a packet, we have, on average, 1 successful hop from source to source router, and with probability 1-p, 1 successful hop from source router to destination router. Therefore, the mean number of hops per transmission would be 1 + (1-p) = 2-p.
For part (b), the number of transmissions a packet makes can be modeled as a geometric distribution with the probability of success being (1-p)^2, since a packet must successfully pass both routers. The mean number of transmissions is the reciprocal of this probability, 1/((1-p)^2).
Part (c) is a combination of parts (a) and (b): it is the product of the mean number of hops per transmission and the mean number of transmissions required for a packet to be successfully received, which equals (2-p)/((1-p)^2).
Which of the following statements is true of the term "FTTH"?
1. It refers to high-speed data lines provided by many firms all across the world that interconnect and collectively form the core of the Internet.
2. It refers to broadband service provided via light-transmitting fiber-optic cables.
3. It refers to the language used to compose Web pages.
4. It refers to a situation when separate ISPs link their networks to swap traffic on the Internet.
5. It refers to a system that connects end users to the Internet.
Answer:
2. It refers to broadband service provided via light-transmitting fiber-oprtics cables.
Explanation:
FTTH (which stands for Fiber-To-The-Home) is actually only one of the many similar services available, which all are identified by the acronym FTTx, where X, can be one of the following:
H = Home
C= Curb
B = Building
N= Neighborhood
This type of services are given on an all-passive network, composed only by fiber optic cables and passive splitters, carrying the broadband signal over one single fiber directly to the user, employing wave division multiplexing over a single mode fiber, in the 1310/1550/1625 nm range.
Assume that a 5 element array of type string named boroughs has been declared and initialized. Write the code necessary to switch (exchange) the values of the first and last elements of the array. So, for example, if the array's initial values were: brooklyn queens staten_island manhattan bronx then after your code executed, the array would contain: bronx queens staten_island manhattan brooklyn
Answer:
Explanation:
Let's do this in python. First we can set a placeholder variable to hold the first element of the array, then we can set that first element to the last element (5th) of that array. Then we set the last element of that array to the placeholder, which has value of the original first element of the array
placeholder = boroughs[0] # in python, 0 is the first element or arra
boroughs[0] = boroughs[-1] # -1 means the last element of the array
boroughs[-1] = placeholder
If the base address of an array is located at 0x1000FFF4, what would the following instructions be equivalent to (assume this array has the name, my_array)? li $t0, 45 li $s1, 0x1000FFF4 sw $t0, 8($s1) Group of answer choices my_array[0] = 45 my_array[1] = 45 my_array[2] = 45 my_array[8] = 45 my_array[0] = 0x1000FFF4 my_array[1] = 0x1000FFF4 my_array[2] = 0x1000FFF4 my_array[8] = 0x1000FFF4
Answer:
The correct option to the following question is my_array[2] = 45.
Explanation:
Because the offset '8' which used for the subscript 8 divided by 4 which is 2.
So, that's why my_array[2] = 45 is the correct answer to the following question.
An array is the data type in the programming languages which stores the same type of data at a time whether it an integer type or string type.
Which type of network is designed to facilitate communications between users and applications over large distances? (For example: between the various corporate offices of an international organization that are located in cities all over the world.)
Answer:
Wide area network (WAN)
Explanation:
The WAN network is a type of network that covers distances of about 100 to about 1,000 kilometers, allowing to provide connectivity to several cities or even an entire country. WAN networks can be developed by a company or an organization for private use, or even by an Internet Service Provider (ISP) to provide connectivity to all its customers. Generally, the WAN network operates point to point, so it can be defined as a switched packet network. These networks, on the other hand, can use radio or satellite communication systems.
A small tourist town is experiencing rapid beach erosion. Based on the information in the animation, what is the best solution to quickly resolve the problem for residents and visitors?
A. Allow residents to install groins.
B. Construct an offshore breakwater.
C. Build a jetty just up current from the town.
D. Invest in beach nourishment.
Answer:
The answer is Letter A.
Explanation:
Allow residents to install groins.
The best solution to quickly resolve rapid beach erosion in a small tourist town, for residents and visitors, is option D: Invest in beach nourishment.
By choosing beach nourishment, the town directly addresses the loss or lack of sand which is the primary cause of erosion. This method supplements natural processes, augments the beach with additional sand, and is more adaptable to changes in coastal processes. Structures such as groins, breakwaters, and jetties often lead to disruptions in longshore drift, causing sediment buildup on one side but exacerbating erosion on the other, leading to a cycle of continuous construction. The benefit of this "soft" solution is its ability to maintain a natural and recreational beachfront without creating lee-side erosion. Sand nourishment thus provides a more sustainable and less intrusive solution compared to hard structures that can disrupt the natural sediment movement and potentially cause more problems in adjacent areas.
What is Scrum?
1. A routine method of deploying deliverables to operations
2. A process for continuously maintaining deployment readiness
3. A lightweight process for cross-functional, self-organized teams
4. A methodology used to deliver usable and reliable solutions to the end user
Answer:
A lightweight process for cross-functional, self-organized teams.
Explanation: The process in which teams are cross functional and self organizing to complete a particular task. This term is used in software development. Progress towards well defined goal with by emphasizing on teamwork and accountability.
Scrum is option 3. a lightweight process for cross-functional, self-organized teams, emphasizing structured roles and regular, brief meetings.
Option 3. Scrum is a lightweight process for cross-functional, self-organized teams. It is widely used in the IT industry and is a focused and organized approach compared to general agile development. Scrum teams operate using defined roles, such as the Scrum Master, and follow structured activities, including daily stand-up meetings to ensure progress and address obstacles.
The process is characterized by:
Product backlogs that contain evolving requirements.Sprint backlogs that dictate tasks for each sprint, typically shorter than 30 days.Self-organizing teams that coordinate tasks independently with the support of a Scrum Master.Short, daily meetings where team members discuss their progress and challenges.Throughout the Scrum workflow, the goal is to incrementally develop and deliver functional project components, ensuring continuous improvement and stakeholder collaboration.
Create a program to deteate a program to determine whether a user-specified altitude [meters] is in the troposphere, lower stratosphere, or upper stratosphere. The program should include a check to ensure that the user entered a positive value less than 50,000. If a nonpositive value or a value of 50,000 or greater is entered, the program should inform the user of the error and terminate. If a positive value
Answer:
#include <iostream>
using namespace std;
int main()
{
float altitude;
cout<<"Enter alttitude in meter";
cin >>altitude;
if(altitude<0 || altitude > 50000)
{
cout<<"Invalid value entered";
return 0;
}
else{
if(altitude<= 10000)
{cout <<"In troposphere "<<endl;}
else if(altitude>10000 && altitude<=30000)
{cout <<"In lower stratosphere"<<endl;}
else if(altitude>30000 && altitude<=50000)
{cout <<"In upper stratosphere"<<endl;}
}
return 0;
}
Explanation:
Define a float type variable. Ask user to enter altitude in meters. Store value to altitude variable.
Now check if value entered is positive and less than 5000,if its not in the range of 0-50,000 display a termination message and exit else check if it's in less than 10000, in between 10000 and 30000 or in between 30000 and 50000.
10,000 is above sea level is troposphere.
10,000-30,000 is lower stratosphere.
30,000-50,000 is upper stratosphere.
Write definitions for the following two functions using Python:
sumN (and) returns the sum of the first n natural numbers.
sumN Cubes (and) returns the sum of the cubes of the first n natural numbers.
Then use these functions in a program that prompts a user to enter a number ‘n’ and print out the sum of the first n natural numbers, and the sum of the cubes of the first n natural numbers.
Two Python functions are defined: sumN to compute the sum of the first n natural numbers, and sumN_Cubes to compute the sum of the cubes of the first n natural numbers. A user is then prompted to input a number 'n', and the program prints out the results of both functions.
Defining Sum Functions in Python
To start with, let's define the two functions as described. The first function sumN will calculate the sum of the first n natural numbers. The second function sumN Cubes will calculate the sum of the cubes of the first n natural numbers. Then we will use these functions in a program that prompts the user for an input and prints out the results.
Here are the Python definitions:
def sumN(n):
return sum(range(1, n+1))
def sumN_Cubes(n):
return sum(x**3 for x in range(1, n+1))
n = int(input('Enter a number n: '))
print(f'Sum of the first {n} natural numbers is: {sumN(n)}')
print(f'Sum of the cubes of the first {n} natural numbers is: {sumN_Cubes(n)}')
The program first defines the functions using the def keyword. Then it prompts the user to enter a number and stores it as n. Lastly, it calculates and prints the results using the defined functions.a
Python3
Write function countLetter that takes a word as a parameter and returns a dcitionary that tells us how many times each alphabet appears in the word (no need to account for absent alphabets). Develop your logic using dictionaries only. Save the count result as a dictionary. Display your output in the main() function.
Answer:
Following are the program in the Python Programming Language:
def countLetter(words):
#set dictionary
di = {}
for i in words: #set for loop
#if key exists in di or not
if di.get(i):
#if exists count increased
di[i] += 1
else: #otherwise assign with key
di[i] = 1
# return di
return di
def main():
#get input from the user
words = input("Enter the word: ")
#store the output in function
letter = countLetter(words)
#set for loop
for i in letter:
print(i, ":", letter[i]) #print output with :
#call main method
if __name__ == "__main__":
main()
Explanation:
Here, we define the function "countLetter()" and pass the argument "words" in parameter and inside it.
we set the dictionary data type variable "di".we set the for loop and pass the condition inside it we set if statement and increment in di otherwise di is equal to 1.we return the variable di.Then, we define the function "main()" inside it.
we get input from the user in the variable "words".we store the return value of function "countLetter()" in the variable "letter".we set for loop to print the output.Finally, we call the main method.
What is the output of the code corresponding to the following pseudocode? (In the answer options, new lines are separated by commas.) Declare X As Integer Declare Y As Integer For (X = 1; X <=2; X++) For (Y = 3; Y <= 4; Y++) Write X * Y End For(Y) End For(X)
Answer:
Following are the output of the given question
3 4 6 8
Explanation:
In the following code, firstly, we have declare two integer data type "X" and "Y".
Then, set two for loop in which first one is outer loop and the second one is the inner loop, inner loop starts from 1 and end at 2 and outer loop starts from 3 and end at 4.Then, when the variable X=1 then the condition of the outer loop become true and the check the condition of the inner loop, when Y=3, than the multiplication of X and Y occur and output should be 1*3=3.Then, the value of the X will remain same at time when the value of Y become false. Thrn, second time X=1 and Y=4 and output should be 4.Then, X=2 because Y turns 5 so the inner loop will terminate and than outer loop will execute. Then again Y=3 but X=2 and output should be 6.Then, the value of the X will remain same at time when the value of Y become false. Thrn, second time X=2 and Y=4 and output should be 8.Finally, all the conditions of the loop become false and the program will terminate.
Write a loop that reads in a collection of words and builds a sentence out of all the words by appending each new word to the string being formed. For example, if the three words This, is, one are entered, your sentence would be "this", then "This is", and finally "This is one". Exit your loop when a word that ends with a period is entered or the sentence being formed is longer than 20 words or contains more than 100 letters. Do not append a word if it was previously entered
Answer:
#section 1
import re
wordcount = 0
lettercount = 0
words = ['This', 'is', 'one','one', 'great','Dream.', 'common', 'hella', 'grade','grace','honesty','diligence','format','young',]
sentence = []
#section 2
for a in words:
wordcount = wordcount + 1
for i in a:
lettercount= lettercount + 1
if a not in sentence:
sentence.append(a)
if lettercount > 100:
break
if wordcount > 20:
break
if re.search('(\w+\.$)', a):
break
sentence = ' '.join(sentence)
print(sentence)
Explanation:
The programming language used is python.
#section 1
The regular expression module is imported because we need to use it to determine if a word entered ends with a full-stop.
Two variables are initialized to hold the number of words and the number of letters and an empty list is created to hold the sentence that is going to be created.
A collection of words are placed in a list in order test the code.
#section 2
Two FOR loops and a group of IF statements are used to check if the words entered satisfy any of the conditions.
The first FOR loop counts the number of words and the second one counts the number of letters.
The first IF statement checks to make sure the word has not been added to the sentence list and adds it if not present, while the next two IF statements check the word count and letter count to ensure that they have not exceeded 20 or 100 respectively and if they exceed, the loop is broken. The last IF statement uses regular expression to check if a word ends with a full-stop and if it does, it breaks the the loop.
Finally, the sentence list is joined and the sentence is printed to the screen.
Write an expression to detect that the first character of userinput matches firstLetter. 1 import java.util.Scanner; 3 public class CharMatching 4 public static void main (String [] args) { Scanner scnr new Scanner(System.in); String userInput; char firstLetter; userInput = scnr.nextLine(); firstLetter scnr.nextLine().charAt (0); 12 13 14 15 if (/* Your solution goes here * System.out.printin( "Found match: "firstLetter); else t System.out.println("No match: " firstLetter); 17 18 19 20 21 return
Answer:
if(Character.toUpperCase(firstLetter)==Character.toUpperCase(userInput.charAt(0)))
Explanation:
The given source code is an illustration of characters and strings in Java program.
To complete the code segment, the comment /* Your solution goes here */ in the program, should be replaced with any of the following expressions:
Character.toUpperCase(firstLetter)==Character.toUpperCase(userInput.charAt(0))Character.toLowerCase(firstLetter)==Character.toLowerCase(userInput.charAt(0))Using the first instruction above
Variable firstLetter will first be converted to upper caseThe first character of userInput will then be extracted using charAt(0)The first character is then converted to upper caseLastly, both characters are comparedSo, the complete code (where comments are used to explain each line) is as follows:
//This imports the Scanner library
import java.util.Scanner;
//This defines the program class
public class Main {
//This defines the program method
public static void main (String [] args) {
//This creates a Scanner object
Scanner scnr = new Scanner(System.in);
//This declares variables userInput and firstLetter
String userInput; char firstLetter;
//This gets input for userInput
userInput = scnr.nextLine();
//This gets input for firstLetter
firstLetter = scnr.nextLine().charAt(0);
//This checks if the first letter of userInput matches with variable firstLetter
if (Character.toUpperCase(firstLetter)==Character.toUpperCase(userInput.charAt(0))){
//If yes, found match is printed
System.out.println( "Found match: "+firstLetter); }
else{
//If otherwise, no match is printed
System.out.println("No match: "+ firstLetter);
}
}
}//Program ends here
See attachment for the complete code and the sample run
Read more about java programs at:
https://brainly.com/question/2266606
Write a program that calculates and displays the number of minutes in a month. This program does not require any user input, and you can assume 30 days are in a month. NOTE: If you want to be an overachiever, you can prompt the user to enter in the number of days in the month since we know that in reality not all months have 30 days.
Answer:
Code to the answer is shown in the explanation section
Explanation:
import java.util.Scanner;
public class Question {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.println("Please enter the days of the month: ");
int daysOfMonth = scan.nextInt();
int minuteOfMonth = daysOfMonth * 60 * 24;
System.out.println(minuteOfMonth);
}
}
// 60 represents the number of minutes in one hour
// 24 represents the number of hours in a day
A user calls your help desk and says that he is trying to configure his Word document so that the text within his paragraphs is stretched from the left margin to the right margin. What is your advice?
Answer:
The best answer would be
Explanation:
To access this command ...
Select the Format tab - Properties - Paragraph properties - Bleeds and spaces
What is the darknet?
(A) An Internet for non-English speaking people
(B) The criminal side of the Internet
(C) An Internet just for law enforcement
(D) The old, IPv4 Internet that is being retired as IPv6 takes over
(E) None of the above
Answer:
B.
Explanation:
the dark net also known as the dark web is a net for criminals
Today we will be making a Caesar Cipher to encrypt and decrypt messages.A Caesar Cipher is a simple cipher that translates one letter to another via shifting the letter a few spaces in the alphabet. For example:A Caesar Cipher with a shift of 3 would turn A into D, B into E, C into F, and so on.Your task is to use string methods and two user defined functions (an encrypt function and a decrypt function) to produce an encrypted message from a "plaintext" message and a "plaintext" message from an encrypted message.The program should use a menu such as:1. Encrypt2. Decrypt3. ExitThe menu should be displayed in a loop until the user chooses to exit. When the user chooses the Encrypt option, your program should prompt the user to input a "plaintext" string. Then the program should display what the encrypted text would be.When the user chooses the Decrypt option, your program should prompt the user for an encrypted message and then display the "plaintext" version of that message to the user.For this program each message should be a single word and your cipher should use a shift of 3.Any message entered by the user should be capitalized using a user defined function that will take a string in by reference and use the toupper() function from to capitalize each letter of the string.
Answer:
#include <iostream>
#include <stdio.h>
#include <ctype.h>
using namespace std;
string
encrypt (string text, int s)
{ string resultingString = "";
for (int i = 0; i < text.length (); i++)
{ if (!isspace (text[i]))
{
if (isupper (text[i]))
resultingString += char (int (text[i] + s - 65) % 26 + 65);
else
resultingString += char (int (text[i] + s - 97) % 26 + 97);
}
else
{
resultingString += " ";
}
}
return resultingString;
}
string
decrypt (string text, int s)
{
string resultingString = "";
for (int i = 0; i < text.length (); i++)
{
if (!isspace (text[i]))
{
if (isupper (text[i]))
resultingString += char (int (text[i] + s - 65) % 26 + 65);
else
resultingString += char (int (text[i] + s - 97) % 26 + 97);
}
else
{
resultingString += " ";
}
}
return resultingString;
}
string upper(string str){
for (int i=0;i<str.length();i++){
str[i]=toupper(str[i]);
}
return str;
}
int
main ()
{
string text = "This is test text string";
int s = 3;
string cipherText = "";
string decipherText = "";
int menu=-1;
while (menu!=3){
cout<<"1. Encrypt"<<endl;
cout<<"2. Decrypt"<<endl;
cout<<"3. Exit"<<endl;
cin >>menu;
cin.ignore();
if(menu==1){
cout<<"Enter Plain string "<<endl;
getline(cin,text);
text=upper(text);
cipherText = encrypt (text, s);
cout << "cipher text: " << cipherText << endl;
}
else if(menu==2){
cout<<"Enter Encrypted string "<<endl;
getline(cin,cipherText);
cipherText=upper(cipherText);
decipherText = decrypt (cipherText, 26 - s);
cout << "decipher text: " << decipherText << endl;
}
else {
cout<<"Not valid"<<endl;
}
}
return 0;
}
Explanation:
Display menu with options 1 encrypt, 2 decrypt, 3 exit. Write a function to translate string to upper case. Iterate through string and for each index use toupper function to translate alphabet to upper case and store it back to current index of string.On exiting from loop return string. Pass upper case string to encrypt function.
In encrypt function pass string by reference and shift value. Create an empty string resultingString. Iterate through string for each character check if its space, if its a space add it to resulting string otherwise using ascii values convert char to its ascii add shift value and subtract 65 (staring ascii value for capital alphabet) take modules with 26 for new character and than add 65 to get alphabet.Now add this alphabet to resulting string. Upon loop completion return resultingString.
For decryption use same function as encryption. We are using cyclic property to decrypt using same function therefor subtract shift from 26 and pass resulting shift value to decrypt function.
Given six memory partitions of 300 KB, 600 KB, 350 KB, 200 KB, 750 KB, and 125 KB (in order), how would the first-fit, best-fit, and worst-fit algorithms place processes of size 115 KB, 500 KB, 358 KB, 200 KB, and 375 KB (in order)? Rank the algorithms in terms of how efficiently they use memory.
Answer:
In terms of efficient use of memory: Best-fit is the best (it still have a free memory space of 777KB and all process is completely assigned) followed by First-fit (which have free space of 777KB but available in smaller partition) and then worst-fit (which have free space of 1152KB but a process cannot be assigned). See the detail in the explanation section.
Explanation:
We have six free memory partition: 300KB (F1), 600KB (F2), 350KB (F3), 200KB (F4), 750KB (F5) and 125KB (F6) (in order).
Using First-fit
First-fit means you assign the first available memory that can fit a process to it.
115KB will fit into the first partition. So, F1 will have a remaining free space of 185KB (300 - 115).500KB will fit into the second partition. So, F2 will have a remaining free space of 100KB (600 - 500)358KB will fit into the fifth partition. So, F5 will have a remaining free space of 392KB (750 - 358)200KB will fit into the third partition. So, F3 will have a remaining free space of 150KB (350 -200)375KB will fit into the remaining partition of F5. So, F5 will a remaining free space of 17KB (392 - 375)Using Best-fit
Best-fit means you assign the best memory available that can fit a process to the process.
115KB will best fit into the last partition (F6). So, F6 will now have a free remaining space of 10KB (125 - 115)500KB will best fit into second partition. So, F2 will now have a free remaining space of 100KB (600 - 500)358KB will best fit into the fifth partition. So, F5 will now have a free remaining space of 392KB (750 - 358)200KB will best fit into the fourth partition and it will occupy the entire space with no remaining space (200 - 200 = 0)375KB will best fit into the remaining space of the fifth partition. So, F5 will now have a free space of 17KB (392 - 375)Using Worst-fit
Worst-fit means that you assign the largest available memory space to a process.
115KB will be fitted into the fifth partition. So, F5 will now have a free remaining space of 635KB (750 - 115)500KB will be fitted also into the remaining space of the fifth partition. So, F5 will now have a free remaining space of 135KB (635 - 500)358KB will be fitted into the second partition. So, F2 will now have a free remaining space of 242KB (600 - 358)200KB will be fitted into the third partition. So, F3 will now have a free remaining space of 150KB (350 - 200)375KB will not be assigned to any available memory space because none of the available space can contain the 375KB process.Based on the efficient use of memory, the algorithm are ranked as:
Best fit.First fit.Worst fit.
Given the following data:
M1 = 300 KB.M2 = 600 KB.M3 = 350 KB.M4 = 200 KB.M5 = 750 KB.M6 125 KB.P1 = 115 KB.P2 = 500 KB.P3 = 358 KB.P4 = 200 KB.P5 = 375 KB.What is a first-fit algorithm?A first-fit algorithm can be defined as the simplest technique of allocating memory block to processes by assigning the first available memory.
For P1 with a memory size of 115 KB, it would fit into the first memory partition.
[tex]M_1=300-115\\\\M_1=185\;KB[/tex]
For P2 with a memory size of 600 KB, it would fit into the second memory partition.
[tex]M_2=600-500\\\\M_2=100\;KB[/tex]
For P3 with a memory size of 358 KB, it would fit into the fifth memory partition.
[tex]M_5=750-358\\\\M_5=392\;KB[/tex]
For P4 with a memory size of 200 KB, it would fit into the third memory partition.
[tex]M_3=350-200\\\\M_3=150\;KB[/tex]
For P5 with a memory size of 375 KB, it would fit into the remaining fifth memory partition.
[tex]M_5=392 - 375\\\\M_5=17\;KB[/tex]
What is a best-fit algorithm?A best-fit algorithm can be defined as the technique of allocating memory block to processes by assigning the smallest partition size that can store the process.
For P1 with a memory size of 115 KB, it would best fit into the sixth memory partition.
[tex]M_6=125-115\\\\M_6=10\;KB[/tex]
For P2 with a memory size of 600 KB, it would best fit into the second memory partition.
[tex]M_2=600-500\\\\M_2=100\;KB[/tex]
For P3 with a memory size of 358 KB, it would best fit into the fifth memory partition.
[tex]M_5=750-358\\\\M_5=392\;KB[/tex]
For P4 with a memory size of 200 KB, it would best fit into the fourth memory partition.
[tex]M_3=200-200\\\\M_3=0\;KB[/tex]
For P5 with a memory size of 375 KB, it would best fit into the remaining fifth memory partition.
[tex]M_5=392 - 375\\\\M_5=17\;KB[/tex]
What is a worst-fit algorithm?A worst-fit algorithm can be defined as the technique of allocating memory block to processes by assigning the largest partition size that can store the process.
For P1 with a memory size of 115 KB, it would fit into the fifth memory partition.
[tex]M_6=750-125\\\\M_6=635\;KB[/tex]
For P2 with a memory size of 500 KB, it would fit into the remaining fifth memory partition.
[tex]M_5=635 - 500\\\\M_5=135\;KB[/tex]
For P3 with a memory size of 358 KB, it would fit into the second memory partition.
[tex]M_5=600 - 358\\\\M_5=242\;KB[/tex]
For P4 with a memory size of 200 KB, it would fit into the third memory partition.
[tex]M_3=350 - 200\\\\M_3=150\;KB[/tex]
For P5 with a memory size of 375 KB, it would best fit into any of the memory partition that is available.
Read more on memory partition here: https://brainly.com/question/24593920
What is VoIP?
A. VoIP uses IP technology to transmit telephone calls
B. VoIP offers the low cost ability to receive personal and business calls via computer
C. VoIP offers the ability to have more than one phone number
D. All of these are correct
Answer:
D. All of these are correct
Explanation:
VoIP transmits voice data packets over the internet. It is a low-cost option for receiving personal and business calls because it uses existing infrastructure that is the internet to transmit calls, unlike traditional telephone systems that require specialized equipment such as PBXs that are costly.VoIP also offers the ability to have more than one telephone number, as long as the bandwidth is enough, it allows multiple connections at any given time.
In an If-Then-Else statement, the Else clause marks the beginning of the statements to be executed when the Boolean expression is ________.
Answer:
False
Explanation:
The definition for the If-Then-Else structure is as follows:
IF (boolean_condition)
THEN (commands_for_true)
ELSE (commands_for_false)
When there is an ELSE sentence, its commands are to be executed whenever previous conditions where not evaluated as true .
Final answer:
The correct answer is False. In programming, the Else clause in an If-Then-Else statement is executed when the Boolean expression is false. It's a key component of conditional statements, directing the flow of the program when conditions are not met.
Explanation:
In an If-Then-Else statement, the Else clause marks the beginning of the statements to be executed when the Boolean expression is false. Essentially, the If-Then-Else statement is a form of conditional statement that controls the flow of execution in a program. The structure typically looks like IF X, THEN Y, ELSE Z, where X is the condition, Y is the statement block executed if the condition X evaluates to true, and Z is the statement block executed if the condition X evaluates to false. Here, X is a Boolean expression, indicating a condition that evaluates to either true or false.
An If-Then-Else statement ensures that one out of two possible paths of execution is followed in the program. If the condition in the IF clause is true, the code following the THEN keyword is executed. If the condition is false, the code following the ELSE keyword is executed, hence the critical role of the ELSE clause is to handle the scenario where the condition evaluates as false.
Which of the following is a proprietary protocol developed by Microsoft that provides a user with a graphical interface to another computer?
(A) Secure Sockets Layer (SSL)
(B) Layer 2 Tunneling Protocol (L2TP)
(C) Point-to-Point Tunneling Protocol (PPTP)
(D) Remote Desktop Protocol (RDP)
Answer:
(D) Remote Desktop Protocol (RDP)
Explanation:
Remote Desktop Protocol (RDP) is a networking protocol developed by Microsoft that provides a graphical user interface to another computer. This enables the remote user to interact with the machine as if they were working on it locally. The Secure Socket Layer (SSL) on the other hand, is a cryptographic protocol used in internet security. Then Layer 2 Tunneling Protocol (L2TP) and Point-to-Point Tunneling Protocol (PPTP) are computer networking protocol used when configuring and setting up Virtual Private Networks (VPNs) which allows a user to access a private network through a public network.
Write a recursive program that tests if a number is a prime number (returns true) or not (returns false). Use a naïve (simple) algorithm that determines that a number P is not a prime number if remainder of dividing the number P by at least one number Q, Q less than P, is zero. (There exists a Q such that Q< P and P modulo Q is O) and is a prime number otherwise. Use existing Scheme pre-defined functions for checking for remainders. (is-prime-number 19) #t (is-prime-number 27) #f
Answer:
int is-prime-number(int P){
if (Q == 1) {
return 1;
} else{
if (P%Q == 0){
return 0;
} else {
Q = Q - 1;
is-prime-number(P);
}
}
}
Explanation:
I have defined a simple function by the name of is-prime-number which takes an integer input the number to be tested whether it is prime or not and returns an integer output.if the function returns 1 (which means true) this means that the number is prime otherwise the number is not prime.Now we just need to call this function in our main function and print "Number is prime" if function returns one otherwise print "Number is not prime".Another important point to note here is that we need to define Q as Global variable since we are not passing it as a input to the function but we are using it inside the function so it needs to be declared as a Global variable.Write a filter that reads in a sequence of integers and prints the integers, removing repeated values that appear consecutively. For example, if the input is 1 2 2 1 5 1 1 7 7 7 7 1 1 1 1 1 1 1 1 1, your program should print 1 2 1 5 1 7 1.
Answer:
Following is the code for filter:
public class filter
{ public static void main(String[] args)
{ int x = StdIn.readInt();
System.out.print(" " + x + " ");
while(!StdIn.isEmpty())
{ int y = StdIn.readInt();
if(y != x)
System.out.print(" " + y + " ");
x = y;
}
}
}
Explanation:
A public class filter is used.The main function will accept a single argument as string[], it is also known as java command line argument.Now the Stdln.readInt is used to read the integers in the sequence and store it in integer x.The value stored in variable x will be printed using System.out.print Now unless the Stdln.readInt gets an empty value, check each value of sequence and store in variable y.If y is not equal to previous value x, print it and shift the value of y into x. Repeat the loop again.i hope it will help you!
Answer:
Computer
Explanation:
Why is it important to use flip-flops instead of latches to construct a finite state machine?
A. Flip-flops are the only way to provide the speed necessary for reliable finite state machine operation.
B. The reduced speed of flip-flops is necessary to ensure reliable finite state machine operation.
C. Flip-flops cost less than latches, so you have to use flip-flops to obtain the most economical implementation possible.
D. Flip-flops use less power than latches, so their use is important for optimizing battery life.
E. Flip-flops will never change state more than once per clock cycle, which is essential for designs like finite state machines where the outputs of the machine feed back into the inputs.
Answer:
The answer are letters D and E.
Explanation:
Because, Flip-flops use less power than latches, so their use is important for optimizing battery life. Flip-flops will never change state more than once per clock cycle, which is essential for designs like finite state machines where the outputs of the machine feed back into the inputs.
Create two Lists, one is ArrayList and the other one is LinkedList and fill it using 10 state names (e.g., Texas). Sort the list and print it, and then shuffle the lists at random. Please use java.util.Collections class to do sorting and shuffling.
Answer:
The program to this question can be given as:
Program:
import java.util.*; //import package
public class Main //define class main.
{
public static void main(String[] args) //define main method.
{
ArrayList<String> AL1 = new ArrayList<>(); //create ArrayList object AL1.
LinkedList<String> LL2 = new LinkedList<>(); //create LinkedList object LL2.
AL1.addAll(Arrays.asList("Bihar","Andhra Pradesh","Assam","Chhattisgarh","Arunachal Pradesh","Goa","west bangol","Gujarat","Jharkhand","Karal"));//add elements in ArrayList
LL2.addAll(Arrays.asList("Bihar","Andhra Pradesh","Assam","Chhattisgarh","Arunachal Pradesh","Goa","west bangol","Gujarat","Jharkhand","Karal"));//add elements in LinkedList
Collections.sort(AL1); //sort ArrayList
Collections.sort(LL2); //sort LinkedList
System.out.println("Sorting in ArrayList and LinkedList elements :");
System.out.println("ArrayList :\n" +AL1);
System.out.println("LinkedList :\n"+LL2);
Collections.shuffle(AL1); //shuffle ArrayList
Collections.shuffle(LL2); //shuffle LinkedList
System.out.println("shuffling in ArrayList and LinkedList elements :");
System.out.println("shuffle ArrayList:\n"+AL1);
System.out.println("shuffle LinkedList:\n"+LL2);
}
}
Output:
Sorting in ArrayList and LinkedList elements :
ArrayList :
[Andhra Pradesh, Arunachal Pradesh, Assam, Bihar, Chhattisgarh, Goa, Gujarat, Jharkhand, Karal, west bangol]
LinkedList :
[Andhra Pradesh, Arunachal Pradesh, Assam, Bihar, Chhattisgarh, Goa, Gujarat, Jharkhand, Karal, west bangol]
shuffling in ArrayList and LinkedList elements :
shuffle ArrayList:
[Chhattisgarh, Jharkhand, Gujarat, Goa, west bangol, Andhra Pradesh, Arunachal Pradesh, Assam, Karal, Bihar]
shuffle LinkedList:
[Assam, Karal, Jharkhand, Bihar, Goa, Arunachal Pradesh, Andhra Pradesh, Gujarat, west bangol, Chhattisgarh]
Explanation:
In the above java program firstly we import the package then we define the main method in this method we create the ArrayList and LinkedList object that is AL1 and LL2.
In ArrayList and LinkedList we add state names then we use the sort and shuffle function. and print all values.
The sort function is used to sort array by name. The shuffle function is used to Switching the specified list elements randomly.
Not having the computer echo the password is safer than having it echo an asterisk for each character typed, since the latter discloses the password length to anyone nearby who can see the screen. Assuming that passwords consist of upper and lower case letters and digits only, and that passwords must be a minimum of five characters and a maximum of eight characters, how much safer is not displaying anything?
Answer:
Up to 99.99958% safer
Explanation:
Assuming the attacker knows the password restrictions (upper and lower case letters and digits only)
Lets calculate the password combinations for each possible length:
Total characters possible: [a-z]+[A-Z]+[0-9] = 62
(A) Passwords of length = 8 -> [tex]62^8=218,340,105,584,896[/tex]
(B) Passwords of length = 7 -> [tex]62^7=3,521,614,606,208[/tex]
(C) Passwords of length = 6 -> [tex]62^6=56,800,235,584[/tex]
(D) Passwords of length = 5 -> [tex]62^5=916,132,832[/tex]
If length is not known, but between 5 and 8:
(E) Passwords of length = [5-8] ->
[tex]\sum_{5 \to 8} 62^{n} = \frac{62^9-62^5}{62-1}=221,919,436,559,520[/tex]
Finally, to compare how much safer is to keep the password length hidden, we'll calculate the percentage of (A) to (D) passwords against (E)
The formulas are:
[tex]1-\frac{(A)}{(E)} *100 = 1.61\% safer[/tex]
[tex]1-\frac{(B)}{(E)} *100 = 98.41\% safer[/tex]
[tex]1-\frac{(C)}{(E)} *100 = 99.97\% safer[/tex]
[tex]1-\frac{(D)}{(E)} *100 = 99.99958\% safer[/tex]
Which is true of case-based reasoning (CBR)?
a. Each problem and its corresponding solution are stored on a global network.
b. Each case in a database shares a common description and keyword.
c. It matches a new problem with a previously solved problem and its solution.
d. It solves a problem by going through a series of if-then-else rules.
Answer:
The correct option is Option C: It matches a new problem with a previously solved problem and its solution.
Explanation:
Case-based reasoning (CBR) is used when someone tries to solve new problems based on old problems that were similar. The person applying case-based reasoning would look for the solutions to these similar past problems and try to apply them to the new case. For example, a doctor who tries to treat a patient based on what was successful with a prior patient with a similar problem is applying case-based reasoning. In some instances, these problems are available in a database and ideally, that is how it is conceived, but it would depend on the field and the kind of problems. There is no universal global network dedicated to CBR as a whole (other than generic searches on the internet in general). One example of a specific CBR database is the European Nuclear Preparedness system called PREPARE.