rewrite the radical in exponential form

When angle opposite to the unknown sides and other two sides are given then we use law of cosines

Law of cosine

[tex] c^2 = a^2 + b^2 - 2ab cos(c) [/tex]

From the given diagram

[tex] AB^2 = CB^2 + AC^2 - 2(CB)(AC) cos( c) [/tex]

CB = 108

AC= 55

Angle c= 59

[tex] AB^2 = 108^2 + 55^2 - 2(108)(55) cos( 59 ) [/tex]

[tex] AB^2 = 8570.34767 [/tex]

Take square root on both sides

AB = 92.6 m

To find out angle B we use sine law

[tex] \frac{sin(a)}{a} = \frac{sin b}{b} = \frac{sin c}{c} [/tex]

[tex] \frac{sin b}{b} = \frac{sin c}{c} [/tex]

From the figure

[tex] \frac{sin B}{AC} = \frac{sin C}{AB} [/tex]

[tex] \frac{sin B}{55} = \frac{sin 59}{92.6} [/tex]

sin(B) = 0.50916647

B = [tex] sin^{-1} [/tex](0.50916647)

Angle B= 30.61 degrees

Answer:

A and C

Step-by-step explanation:

Two different ways of factoring -3x - 9 are:

A. -3(x + 3)

C. 3(-x - 3)

Factorization, also known as factoring, is the breakdown of one element into a product of other objects, or factors, which when multiplied together generate the original.

To factor -3x - 9, we can rewrite it as -3(x + 3) or 3(-x - 3).

Both of these expressions are in the form of a product of a constant and a binomial (a polynomial with two terms).

Option A, -3(x + 3), can be obtained by applying the distributive property, which states that we can multiply a constant by each term in a binomial to obtain the product.

In this case, we have -3 × x + -3 × 3 = -3x - 9.

Option C, 3(-x - 3), can also be obtained using the distributive property. In this case, we have 3 × -x + 3 ×-3 = -3x - 9.

Option B, 3(x + 3), is incorrect because the coefficient of the x term is positive, whereas in the original expression it is negative.

Option D, -3(x - 3), is also incorrect because the coefficient of the x term is negative, whereas in the original expression it is positive.

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Answer:

Use the drop-down menus to identify the key values of the box plot.

The median is

✔ C

.

The minimum is

✔ A

.

The maximum is

✔ E

.

The lower quartile (Q1) is

✔ B

.

The upper quartile (Q3) is

✔ D

.

Step-by-step explanation:

i took the test

Answer:

[tex]x^5+2x^3+6x+\frac{1}{5}[/tex]

Step-by-step explanation:

We have been given an equation [tex]x^5+2x^3+6x+\frac{1}{5}[/tex]. We are asked to write our given equation in standard form.

We know that to write an equation in standard form, we need to write the degree terms in descending order.

Upon looking at our given equation, we can see that all terms are in descending order of degree, therefore, our given equation is already writen in standard form.

A function assigns the value of each element of one set to the other specific element of another set. The statement that is not true about the function is option G.

A function assigns the value of each element of one set to the other specific element of another set.

A function from a set X to a set Y allocates precisely one element of Y to each element of X. The set X is known as the function's domain, while the set Y is known as the function's codomain.

The given following statements are about functions. Of the given four statements the one that is not correct is G. This is because if the x-value appears just for one time in a table does not mean it can not have multiple outputs.

Hence, the statement that is not true about the function is option G.

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Answer:

7c -1.5

Step-by-step explanation:

Answer:

7c -1.5

I hope this helps

50% of 80 is the number 40.

percentage, a relative value indicating hundredth parts of any quantity.

We have to find the number of  50% of 80

Convert the percentage to deicmal number.

To do this we have to divide percentage by 100.

50/100=0.5

Now multiply 0.5 with 80

0.5×80

Which we get is 40

Hence, 50% of 80 is the number 40.

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The change in the scale factor from the old scale to the new scale is option A; 3 to 1.

The ratio used to depict the relationship between the dimensions of a model or scaled figure and the corresponding dimensions of the real figure or object is called the scale. On the other hand, a scale factor is a value that is used to multiply all of an object's parts in order to produce an expanded or decreased figure.

Given, A scale drawing of a house addition shows a scale factor of 1 in. = 3.3 ft.

Since Josh decides to make the house addition smaller,

he changes the scale of the drawing to 1 in. = 1.1 ft.

Old: 1 inch = 3.3 feet.

New: 1 inch = 1.1 feet.

Old; 3.3 / 1.1 = 3.

New; 1.1 / 1.1 =  1

The change in the scale factor from the old scale to the new scale is option A; 3 to 1.

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Answer Group P has less variability in the data.

Actually you can have a d for any class because during science class in the 7th grade i had a D soo not trying to cause problems also but your grade has to be a 60 or above to pass and to fail is 59 and lower so

Step-by-step explanation:

To calculate the number of euros you will get for £280, divide £280 by £1 and then multiply by €1.17. You will get approximately €327.60.

To calculate the number of euros you will get for £280, we can use the given exchange rate of £1 = €1.17.

First, we need to find the value of 1 pound in euros by dividing £280 by £1.

This gives us 280.

Then, we can multiply 280 by €1.17 to get the number of euros you will get.

Therefore, you will get approximately €327.60 for £280.

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To find the perimeter of a figure made up of 5 identical squares with a total area of 405 square inches, you would calculate the side length of one square as 9 inches and then consider the shared sides. The perimeter would be 180 inches.

The question describes a figure made up of 5 identical squares with a total area of 405 square inches. To find the area of one square, we divide the total area by the number of squares, resulting in 405 ÷ 5 = 81 square inches per square. Knowing that the area of a square is given by the formula A = side length × side length (or A = a²), we can determine that each side of the square is

The square root of 81, which is 9 inches. Since there are 5 squares, the figure will have overlapping sides when the squares are combined. To calculate the perimeter, we need to consider that each square shares a side with another, except for the starting and ending squares in the arrangement. Therefore, the perimeter of the entire figure will be 9 inches times 4 for the first or outer square, plus 9 inches times 3 for each of the remaining squares (as one side is shared). This gives us a total perimeter of 4 × 9 + (4 × 9 × (5-1)) inches.

When calculating the perimeter of the entire figure, the formula for the perimeter is P = 4×side + 4×(number of squares - 1) × side, resulting in a final computation of P = 4×9 + 4×4 × 9, which equals 180 inches.

For rolling the dice 200 times, the same logic applies. Regardless of the number of rolls, the game with the higher probability of winning, which is the second game, is preferred.

To determine which game is more favorable for rolling the dice, we need to calculate the expected value for each game. The expected value represents the average outcome of rolling the dice.

For the first game, the possible outcomes are integers between 1 and 6. The arithmetic mean should be between 3.25 and 3.75 to win a prize. So, we need to find the probability of rolling numbers that satisfy this condition.

Let's denote [tex]\( p_1 \)[/tex] as the probability of winning the first game. To find [tex]\( p_1 \)[/tex], we calculate the probability of rolling numbers between 13 and 18 (inclusive) since the sum of these numbers falls within the range of 3.25 to 3.75.

[tex]\[ p_1 = \frac{6}{6^2} = \frac{1}{6} \][/tex]

For the second game, we need the arithmetic mean to be more than 4.5. This means the sum of the numbers should be more than [tex]\( 4.5 \times 6 = 27 \)[/tex]. Since the maximum sum of rolling six dice is 36, all outcomes satisfy this condition.

Let's denote [tex]\( p_2 \)[/tex] as the probability of winning the second game. Since all outcomes are favorable, [tex]\( p_2 = 1 \)[/tex].

Now, we calculate the expected values for each game:

[tex]\[ E_1 = p_1 \times \text{Prize amount for game 1} \][/tex]

[tex]\[ E_2 = p_2 \times \text{Prize amount for game 2} \][/tex]

Given that the prize amount is the same for both games, we can compare the expected values directly.

For rolling the dice 20 times:

[tex]\[ E_1 = \frac{1}{6} \times \text{Prize amount} \][/tex]

[tex]\[ E_2 = 1 \times \text{Prize amount} \][/tex]

Since [tex]\( \frac{1}{6} \)[/tex] is less than 1, it's better to choose the game with the higher probability, which is the second game.

For rolling the dice 200 times, the same logic applies. Regardless of the number of rolls, the game with the higher probability of winning, which is the second game, is preferred.

The complete question is:

In a six-sided dice game, a prize is won if the arithmetic mean of number rolled is 3.25-3.75. In a second game, a prize is won if the arithmetic mean is more than 4.5. In which game would you rather roll the dice 20 times or 200 times