Round off 1563385 to the nearest million?

Answers

Answer 1
1,563,385

Look at the millions place. 1 is in the millions place. 
Now look at the number to the right of 1.
Since it is 5 or greater, round 1 up to 2.
Change all the numbers after 1 to 0.

1,563,385 rounded to the nearest million is 2,000,000.
Answer 2

To round 1,563,385 to the nearest million, we look at the hundred-thousands digit (5), and since it's 5 or greater, we round up to 2,000,000.

To round off 1,563,385 to the nearest million, look at the hundred-thousands digit, which is 5 in this case.

If it is 5 or greater, we round up; if it is less than 5, we round down.

Since our hundred-thousands digit is 5, we round up, so 1,563,385 rounded to the nearest million is 2,000,000.


Related Questions

PLEASE HELP!!! REWRITE THE FOLLOWING LINEAR EQUATION IN SLOPE INTERCEPT FORM??

Answers

y=-2x-2 That is the answer
y=-2x-2 you want to use the distributive property on the right side before subtracting four from both sides
y+4=-2(x-1)
y+4=-2x+2
y(-4)=-2x+2(-4)
y=-2x-2

Find f. f ''(x) = 4 + 6x + 36x2, f(0) = 2, f (1) = 10

Answers

It has been a while since I have done differnetial equations but I think here you only need to integrate twice. 
4 + 6x + 36x^2=  2*(2+3x+18x^2) 

Integrate 2+3x+18x^2 to get 2x+3/2x^2+18/3x^3 +C = 2x +3/2x^2+6x^3 + C
Integrate again now this: 2x +3/2x^2+6x^3 + C to get x^2 + 1/2x^3+3/2x^4 +Cx +D 
Now multiply by two (as I have taken out 2 earlier) 
2x^2+x^3+3x^4+2Cx+D

Now use the initial conditions. 
f(0)=2 
D=2 
f(1)=10
2+1+3+2C+2=10
C=1

So the solution is: (ordered by power, as neat mathematicans would do) 
f(x)= 3x^4 + x^3 + 2x^2 + 2x +2

The function [tex]\( f(x) \)[/tex] is: [tex]\[ f(x) = 2x^2 + x^3 + 3x^4 + 5x + 4 \][/tex]

Given:

[tex]\[ f''(x) = 4 + 6x + 36x^2 \][/tex]

[tex]\[ f(0) = 2 \][/tex]

[tex]\[ f(1) = 10 \][/tex]

1. Integrate [tex]\( f''(x) \)[/tex] to find [tex]\( f'(x) \)[/tex]:

[tex]\[ f'(x) = \int (4 + 6x + 36x^2) \, dx = 4x + 3x^2 + 12x^3 + C_1 \][/tex]

2. Integrate [tex]\( f'(x) \)[/tex] to find [tex]\( f(x) \)[/tex]:

[tex]\[ f(x) = \int (4x + 3x^2 + 12x^3 + C_1) \, dx = 2x^2 + x^3 + 3x^4 + C_1x + C_2 \][/tex]

3. Use the initial condition [tex]\( f(0) = 2 \)[/tex] to find [tex]\( C_2 \)[/tex]:

[tex]\[ 2x^2 + x^3 + 3x^4 + C_1x + C_2 \text{ at } x=0 \][/tex]

[tex]\[ 2 = C_2 \][/tex]

[tex]\[ C_2 = 2 \][/tex]

4. Use the initial condition [tex]\( f(1) = 10 \)[/tex] to find [tex]\( C_1 \)[/tex]:

[tex]\[ f(1) = 2(1)^2 + (1)^3 + 3(1)^4 + C_1(1) + 2 = 10 \][/tex]

[tex]\[ 2 + 1 + 3 + C_1 + 2 = 10 \][/tex]

[tex]\[ 8 + C_1 = 10 \][/tex]

[tex]\[ C_1 = 2 \][/tex]

Thus, the function [tex]\( f(x) \)[/tex] is:

[tex]\[ f(x) = 2x^2 + x^3 + 3x^4 + 5x + 4 \][/tex]

The complete question is:

Find f(x). f ''(x) = 4 + 6x + 36x2, f(0) = 2, f (1) = 10

A card is selected at random from a standard 52-card deck. (a) what is the probability that it is an ace? 4/52 (b) what is the probability that it is a heart? .25 (c) what is the probability that it is an ace or a heart

Answers

Part (a) is relatively straight forward.

There are 4 aces in a standard 52-card deck. So the probability that AN ace is picked is just 4/52.

Part (b):
Note that there are 4 suits in a standard 52-card deck. So picking hearts will be 13/52 or 1/4.

Part (c):
The probability condition OR means we need to add the two probabilities because we do not want them simultaneously. So, we end up getting Pr(ace) + Pr(heart).

From part (a), we found that picking an ace had a probability of 4/52, which is reduced down to 1/13.

From part (b), we found that picking a heart had a probability of 1/4.

So, the probability of an ace OR a heart is 1/13 + 1/4 = 4/52 + 13/52 = 17/52.

What are the zeros of the function f(x) =(x^2 - 3x - 10)(x + 4)
!!Please help!!!

Answers

f(x) = (x² - 3x - 10)(x + 4) becomes (x - 5)(x + 2)(x + 4) when completely factored. Now set each binomial equal to zero. 

x - 5 = 0
x = 5

x + 2 = 0
x = - 2

x + 4 = 0
x = - 4

Your zeros are at x = - 4, - 2, and 5. Or at (- 4, 0), (- 2, 0), and (5, 0)

If output per worker is now nearly $120,000 per year, how much will the average worker produce 5 years from now if productivity improves by (use the compounding formula below to answer the question): fv1 = p(1 + r), fv2 = p(1 + r)(1 + r), fv3 = p(1 + r)(1 + r)(1 + r)… instructions: enter your responses rounded to two decimal places. (a) 2 percent per year? $ (b) 3 percent per year? $

Answers

 It takes Jane 1 hour to make a necklace and 45 minutes to make a bracelet. As If output per worker is now nearly $120,000 per year, how much will the average worker produce 5 years from now if productivity improves by (use the compounding formula below to answer the question) answer.

This is a function whose domain is a set of consecutive integers. They are finite and infinite.

Answers

The set of consecutive integers are:

[tex]z = \{...,-3, -2, -1, 0, +1, +2, +3,...\}[/tex]

If the function is finite, then there are two values [tex]a[/tex] and [tex]b[/tex], being [tex]a\ \textless \ b[/tex], in which this function is valid, then:

[tex]f(x) = x[/tex]
being [tex]x [/tex] the set of integers in the interval defined by [tex](a,b)[/tex]

If the function is infinite, the function is valid in the set of all integers then:

[tex]f(x) = x[/tex]
And -∞[tex]<x<[/tex]+∞ 

Answer:

the answer is sequence (usa test prep)

Step-by-step explanation:

To win at lotto in a certain state, one must correctly select 6 numbers from a collection of 50 numbers (one through 50). the order in which the selections is made does not matter. how many different selections are possible?

Answers

Number of different selection = 50C6
Number of different selection = 50 x 49 x 48 x 47 x 46 x 45
Number of different selection = 15 890 700

Answer: 15 890 700
The number of possible selections is
  C(50, 6) = 50!/(6!*44!) = 15,890,700

helppppp picture included

Answers

They dont represent proportional relationship!
but what are the drop down answers?

line L1, L2 and L3 are in the same plane, L1 is perpendicular to L2, and L3 is parallel to L1. which of the following statement must be true?

1. L3 is parallel to L2
2.L3 is perpendicular to L2
3.L3 intersects L2

Answers

Only Statement 2 is surely correct.
because there maybe chances that the line L1 and L3 lies above the line L2 and they can also fulfill the condition of perpendicularity so we can't be sure about statement 3 & statement 1 is clearly incorrect

The true statement will be

1. ''L3 is perpendicular to L2''

What is Parallel lines?

Parallel lines are straight lines that do not intersect at any point.

Given that;

Line L1, L2 and L3 are in the same plane,

L1 is perpendicular to L2, and L3 is parallel to L1.

Now,

Line L1 is perpendicular to L2.

And, L3 is parallel to L1.

Then, Line L3 is perpendicular to line L2

Thus, The true statements will be

1. ''L3 is perpendicular to L2'' and

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plz help and explain thanks

Answers

[tex] \dfrac{x^0}{q^{-3}} = \dfrac{5^0}{(-6)^{-3}}= \dfrac{1}{(-6)^{-3}} = (-6)^3 = -216[/tex]
hey there!:


for q = - 6 and x = 5 :

   5⁰
------
(-6)⁻³ 


Apply rule :  a⁰ = 1  , a≠0

5⁰ = 1     :    

    1
* -------
   (-6)⁻³


Apply exponent rule:  (-a)ⁿ = - aⁿ  , if  " n " is  odd :

(-6)⁻³   = -6⁻³


     1
* -------
   -6⁻³


Apply fraction rule : a/-b  = - a/b


= - 1 /  -6⁻³

Apply exponent rule: a⁻ᵇ =  1 / ab


6⁻³ = 1 / 6³

=> ( - 1/1 ) / ( 6³ )

= - 6³ / 1

Apply rule a/1  = a

= - 6³

* 6 * 6 * 6 => 216

a = -216

hope this helps!
  



Two balls are drawn in succession out of a box containing 6 red and 6 white balls. find the probability that the second ball was​ red, given that the first ball​ was:

Answers

Final answer:

The probability that the second ball is red, given the color of the first ball, is 11/22.

Explanation:

To find the probability that the second ball was red, given that the first ball was either red or blue, we need to consider two cases:

If the first ball drawn was red: In this case, there are 5 red balls and 11 balls remaining. So, the probability of drawing a red ball as the second ball is 5/11.If the first ball drawn was blue: In this case, there are 6 red balls and 11 balls remaining. So, the probability of drawing a red ball as the second ball is 6/11.

Since the first ball can be either red or blue with equal probability, we need to consider both cases. Thus, the total probability is (1/2) * (5/11) + (1/2) * (6/11) = 11/22.

REALY NEED HELP Find an equation of the line passing through the pair of points. Write the equation in the form Ax+By=C. (4,8) and (3,5)

Answers

let
A (4,8) and B (3,5)

step 1
find the slope m
m=(y2-y1)/(x2-x1)---------> m=(5-8)/(3-4)----> m=-3/-1----> m=3

step 2
with m=3 and point B (3,5) find the equation of the line
y-y1=m*(x-x1)-----> y-5=3*(x-3)----> y-5=3x-9----> 3x-y=4

the answer is
the equation in the form Ax+By=C is
 3x-y=4

see the attached figure

If the total income generated from gasoline for AER was $408 million how much would be the cost for a barrel of gasoline, gasoline 34% kerosene 14% 60 million barrels total production crude oil

Answers

The problem statement appears to be trying to tell you that 60 million barrels of crude were processed, resulting in 34% of that volume being turned into gasoline, which was then sold for a total of $408 million. You are asked for the revenue associated with 1 barrel of gasoline.

($408·10^6)/(60·10^6 bbl × 0.34) = $408/(20.4 bbl) = $20/bbl

The income from one barrel of gasoline is $20.00.

The correct answer is: $20

Explanation:

As we are interested in finding the cost for a barrel of gasoline, we need to read the percentage of gasoline from the pie-chart first—which is 34%.

Now number of barrels containing gasoline = 34% of 60 million barrels = [tex] \frac{34}{100} * 60 = 20.4 [/tex] million barrels

For all the barrels, the total income is $408 million; therefore, in order to find the per-barrel cost, we need to divide $408 by 20.4:

[tex] \frac{408}{20.4} = \$20 [/tex]

Hence the correct answer is $20.

What is 9.8 divided by 7

Answers

[tex] \frac{9.8}{7} [/tex] :    1.4

9.8 ÷ 7 = 1.4

So, the answer to your question is 1.4.

hayden delivers pizza for papa john's. His average tip is $1.50 for each pizza that he delivers. How many pizzas must he deliver to earn at least $20 in tips?

Answers

14 pizzas, you will get $20.50

let us assume that the number of pizzas he must deliver = x

The tip obtained for one pizza = $1.50

Total tips that he must earn = 20

So, we frame the equation as shown below:

1.50*x = 20

1.50x = 20

x = 20/1.5 = 13.333

So he must deliver 13.333 pizzas

Since he cannot deliver fractional pizzas, the number of pizzas he must deliver = 14 pizzas

Toysrus is having a 38% off sale. If a backpack normally costs $22, how much will it cost on sale

Answers

it will be 13.64. it is bc 38% of 22 is 8.36 and 22-8.36=13.64

The backpack will cost $13.64 during the 38% off sale at Toysrus, calculated by subtracting the discount ($8.36) from the original price ($22).

To calculate the discount amount, we multiply the original price by the discount percentage:

$22 * 0.38 = $8.36

Now, to get the sale price, we subtract the discount amount from the original price:

$22 - $8.36 = $13.64

Therefore, the backpack will cost $13.64 on sale.

The table shows the number of boys and girls that have black, blonde, brown, or red hair color. What is the probability that a girl has black hair?

Answers

Answer:

O.25

Step-by-step explanation:

Trust me on this one the answer was in the comments :/

Final answer:

The probability of a girl having black hair is determined by dividing the number of girls who have black hair by the total number of girls. Without actual numbers from the table, a specific probability cannot be calculated.

Explanation:

To find the probability that a girl has black hair, we have to first know the total number of girls, and then the number of girls who have black hair. Probability is determined by dividing the number of desired outcomes by the total number of outcomes. So in this case, if we let 'G' denote the total number of girls and 'B' be the number of girls with black hair, the formula for the probability would be P(B) = B / G. Without the actual numbers from the table, we cannot calculate the specific probability.

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5.6 times what equals 19.04

Answers

You would have to multiply 5.6 by 3.4 to get 19.04

Bristol is analyzing positive daily customer feedback on different restaurants to find the perfect place to invest. She would like to choose a restaurant with a high median of positive mark counts and a small interquartile range. She constructed box plots shown in the diagram below. Which restaurant has a median positive mark count above 75 and the smallest interquartile range? Burrito bros, pasta pals, make your own pie, pap smurfys

Answers

The Answer is A) Burrito Bros

Answer:

A. Burrito Bros

Find the surface area of the cylinder. Round to the nearest whole number.

•1,359 cm^2
•730 cm^2
•553 cm^2
•1,790 cm^2

Answers

Surface area = 2πr² + 2πrh

Surface area = 2π(7.5)² + 2π(7.5)(8)  = 730 cm² (nearest whole number)

Answer: 730 cm² 

What is the greatest common factor of 12 and 90?

Answers

Greatest common factor is 6
The greatest common factor of 12 and 90 is 6.

Greatest Common Factors are the largest shared factors between 2 or more numbers.

The factors of 12 and 90 are...
12: 1,2,3,4,6,12
90: 1,2,3,5,6,9,10,15,18,30,45,90

Thus meaning the GCF is 6.

I hope this helps!

Annie is planning a business meeting for her company. her budget is 1,325 for renting the meeting room at the local hotel and providing lunch. she expects 26 people to attend the meeting the room cost $270 which inequality show how to find the amount × Annie can spend for lunch on each person

Answers

$1325 - $270 = $1055

Annie has $1055 to spend on 26 lunches.

Let the cost of a lunch be x.

26x < 1055     

x <  $40.58

Answer: x <  $40.58

Answer:

26x + 270 ≤ 1,325

Step-by-step explanation:

Suppose x be the amount ( in dollars ) of lunch of each person,

So, the cost of lunch for 26 people = 26x,

Also, the cost of meeting room = $ 270,

Thus, the total cost = total cost of lunch + meeting room cost

= 26x + 270,

According to the question,

The budget of meeting is $ 1,325,

That is, the total cost can not exceed to $ 1325,

[tex]\implies 26+270 \leq 1325[/tex]

Which is the required inequality that will used to find the cost of each lunch.

Lisa drove 40 3/5 miles in one hour. At the same speed in how many hours could she drive in 121 4/5

Answers

She would drive c 3 hours
Hello!

[tex]\bf Answer:[/tex]

Lisa can drive 121 4/5 miles in [tex]\boxed{ \rm C.~3~hours}[/tex].

40 3/5 = 40.6

121 4/5 = 121.8

121.8 ÷ 40.6 = 3

Q # 13, write a rule for the linear function in the graph

Answers

From the two points first we need to find the slope (m)

[tex]m= \frac{3+1}{4-3}=4 [/tex]

Using the slope and a point (4,3) we can write the equation in slope intercept form as:

y - 3 = 4(x-4)

y = 4x -16 + 3

y = 4x - 13

So the correct answer is option A

The graph of the function y=x^2+2 is shown. Which equation will shift the graph of the function to the right 2 units?

Answers

y = (x-2)^2 + 2 will shift graph right 2 units .

The dance committee has a budget of $125 to decorate the gym for the spring dance. They have already spent $65. Some members want to buy helium balloons that cost $0.80 each. Write and solve an inequality to show the number of balloons that the dance committee could buy

Answers

First, we subtract the price already spent:
125 - 65 = 60
Now to find the amount of balloons:
0.8n = 60
Divide:
n = 75
The dance committee can buy 75 balloons

The dance committee could buy up to 75 helium balloons with their remaining budget of $60, after already spending $65 from their total budget of $125.

To determine the number of helium balloons that the dance committee could buy with their remaining budget, we first need to calculate how much money they have left after already spending $65. Since their total budget is $125, the remaining budget is calculated as $125 - $65 = $60.

Let's let b represent the number of balloons they can buy. The cost per balloon is $0.80, so the inequality representing the situation is 0.80b \<= 60. To solve for b, we divide both sides of the inequality by 0.80, which gives us b \<= 60 / 0.80, or b \<= 75.

Therefore, the dance committee could buy up to 75 helium balloons with their remaining budget, staying within their financial limitations.

Suppose a population proportion is .40, and 80% of the time when you draw a random sample from this population you get a sample proportion of .35 or more. how large a sample were you taking?

Answers

Final answer:

To determine the sample size needed, use the formula for sample proportion: n = (z * sqrt(p * q)) / E. Plugging in the given values, the minimum sample size required is 178.

Explanation:

To determine the sample size needed, we can use the formula for sample proportion:

n = (z * sqrt(p * q)) / E

Where:

n is the sample size

z is the z-value corresponding to the desired confidence level (in this case, 80%)

p is the population proportion (0.4)

q is 1 - p

E is the maximum allowable error (0.05)

Plugging in the values, we have:

n = (z * sqrt(p * q)) / E = (0.84 * sqrt(0.4 * (1 - 0.4))) / 0.05 ≈ 177.6

Since we cannot have a fractional number of individuals, we round up to the next whole number. Therefore, we would need a minimum sample size of 178 to be 80% confident that the population proportion is estimated to within 0.05.

the sum of two numbers is 7 five times the larger number plus four times the the smaller number is 47.

Answers

Let x and y represent the larger and smaller numbers, respectively. The problem conditions give rise to two equations:
  x + y = 7
  5x +4y = 47

You can use the first equation to write an expression for y, then substitute that into the second equation.
  y = 7 - x
  5x +4(7 -x) = 47 . . . . substitute for y
  x + 28 = 47 . . . . . . .. simplify
  x = 19 . . . . . . . . . . . . subtract 28

Using our expression for y, we have
  y = 7 -19 = -12

The larger number is 19.
The smaller number is -12.
Final answer:

The question is about solving simultaneous equations. Two equations can be set up from the statements provided: x + y = 7 (sum of two numbers is 7) and 5x + 4y = 47 (five times the larger number plus four times the smaller number equals 47). After setting up these equations, solve for x and y.

Explanation:

The subject you are asking about falls under the area of Mathematics, specifically simultaneous equations. To solve this question, we need to set up two equations based on the problem's statement and then solve these two equations together.

Given the problem that the sum of two numbers is 7 and five times the larger number plus four times the smaller number is 47, we can set it up as follows:

Let the larger number be x and the smaller number be y.The first statement gives us the equation: x + y = 7The second statement gives us the equation: 5x + 4y = 47

Subtracting the first equation from the second gives 4x + 3y = 40 so y = (40 - 4x)/3. Substituting y into the first equation gives x = 7 - (40 - 4x)/3. Solve for x to find the larger number, then substitute x into the equation y = 7 - x to find the smaller number.

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Find the distance between the points (
-
10,12) and (15,12).

Answers

The distance formula is:

[tex]d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} [/tex]

We are given two points in the form (x,y), so plug in the values to the distance formula:

[tex]d= \sqrt{(-10-15)^2-(12-12)^2} [/tex]

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

[tex]d= \sqrt{(-25)^2} [/tex]

The square and square root cancel each other out leaving us with 25.

The answer is 25.


describe the steps you would use to factor 2x ^ 3 + 5x ^ 2 - 8x - 20 completely then State the factored form. this isn't multiple choice btw

Answers

Answer:

2·x^3 + 5·x^2 - 8·x - 20 = 0

You see that the term will be 0 for x = 2

(2·x^3 + 5·x^2 - 8·x - 20) / (x - 2) = 2·x^2 + 9·x + 10 = 0

You can use the abc-formula to solve the quadratic equation.

x = -2.5 ∨ x = -2

So the factored form will be

2·x^3 + 5·x^2 - 8·x - 20 = 2·(x - 2)·(x + 2)·(x + 2.5)


Answer:

2·x^3 + 5·x^2 - 8·x - 20 = 0


You see that the term will be 0 for x = 2


(2·x^3 + 5·x^2 - 8·x - 20) / (x - 2) = 2·x^2 + 9·x + 10 = 0


You can use the abc-formula to solve the quadratic equation.


x = -2.5 ∨ x = -2


So the factored form will be


2·x^3 + 5·x^2 - 8·x - 20 = 2·(x - 2)·(x + 2)·(x + 2.5)


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