Sandy spun a spinner with 5 equal parts labeled 1-5. What is the probability she will Not spin a 4

The probability that she will not spin a 4 will be 0.80 or 4/5.

Its fundamental concept is that someone will nearly surely occur. The proportion of positive events in comparison to the total of occurrences.

Then the probability is given as,

P = (Favorable event) / (Total event)

Sandy spun a spinner with 5 equal parts labeled 1-5. Then the total number of events will be given as,

Total events = 5 {1, 2, 3, 4, 5}

Then the favorable events are given as,

Favorable events = 4 {1, 2, 3, 5}

Then the probability is given as,

P = 4 / 5

P = 0.80

The probability that she will not spin a 4 will be 0.80 or 4/5.

More about the probability link is given below.

https://brainly.com/question/795909

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Final answer:

The probability that Sandy will not spin a 4 on a spinner with 5 equal parts is 4/5 or 80%. There are 4 favorable outcomes and 5 possible outcomes in total.

Explanation:

The question asks for the probability that Sandy will not spin a 4 on a spinner that's divided into 5 equal parts, each labeled with the numbers 1-5. Since there are 5 outcomes and only one of them is the one we want to avoid, that leaves us with 4 favorable outcomes (spinning a 1, 2, 3, or 5). The probability of not spinning a 4 is therefore the number of favorable outcomes (not spinning a 4) divided by the total number of possible outcomes (spinning any number from 1 to 5).

To calculate this, we divide the favorable outcomes by the total number of outcomes. This gives us a probability of 4/5, or 80%. The calculation is as follows:

Therefore, P(not spinning a 4) = 4 favorable outcomes / 5 total outcomes = 4/5 or 0.8, which means there is an 80% chance that Sandy will not spin a 4.

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