Scientists have been able to insert genes from bacteria into the DNA of corn plants. This gives some species of corn additional resistance to pests.
This would breakthrough be beneficial to humans as " less chemical residue will be found in the air and water"
What is DNA?Deoxyribonucleic acid (DNA) is just a polymer made up of two polynucleotide chains whose coil around with each other to create a double helix which carries genetic instructions including all living things and viruses' formation, function, growth, but also reproduction.
What is chemical residue?The remnants of a chemical or even its decomposition products may remain in or on prepared produce and are referred to as chemical residues. Chemical residues could form as a result of directly processing produce with either a chemical product or as a result of chemical exposure.
Therefore, the correct answer will be option (B).
To know more about DNA
https://brainly.com/question/264225
#SPJ2
How does molecular shape affect polarity?
Answer: If the molecule is symmetric, the effect of polarity will cancel out
Explanation: Apex
What is one role that lipids play in the body?
AThey provide a quick source of energy for cells.
B-They make up the contracting structures of muscles.
C-They store coded information about heredity.
D-They make up structural parts of cell membranes.
Convert to standard
1.312x10^2
What is the equation for the base ionization constant of PO4^3-
Final answer:
The equation for the base ionization constant of PO4^3- is K_base = K_1 * K_2 * K_3.
Explanation:
The base ionization constant of the PO4^3- ion can be determined from the ionization reactions it undergoes.
The ionization reactions for the PO4^3- ion are:
HPO4^2- (aq) + H2O(l) → H2PO4^-(aq) + OH^-(aq), with a base ionization constant of K1.
H2PO4^-(aq) + H2O(l) → H3O^+(aq) + HPO4^2-(aq), with a base ionization constant of K2.
HPO4^2-(aq) + H2O(l) → H3O^+(aq) + PO4^3-(aq), with a base ionization constant of K3.
The base ionization constant for the PO4^3- ion is the product of the base ionization constants of each ionization reaction:
Kbase = K1 * K2 * K3.
How many grams of calcium chloride are needed to produce 1.50 g of potassium chloride? cacl2(aq) + k2co3(aq) → 2 kcl(aq) + caco3(aq) 1.12 g 2.23 g 0.896 g 4.47 g?
The calcium chloride needed to produce 1.5 grams of KCl is: 1.12 grams
Further explanationStoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).
Reactions that occur:
CaCl₂ (aq) + K₂CO₃ (aq) → 2 KCl (aq) + CaCO₃ (aq)
From the reaction equation above, the reaction coefficient shows the mole ratio of reagents and products
mol CaCl₂: moles of KCl = 1: 2
relative molecular mass KCl = 74.6
relative molecular mass of CaCl2 = 111
then the mole:
mole KCl = mass: relative molecular mass
mole KCl = 1.5 gram: 74.6
mole KCl = 0.020107
so that
mole CaCl₂ = 1/2. 0.020107
mole CaCl₂ = 0.0100535
So the mass of CaCl2 = mole x relative molecular mass
mass CaCl₂ = 0.0100535 x 111
mass CaCl₂ = 1.12 gram
Learn moremoles of water
https://brainly.com/question/1405182
grams of oxygen required
https://brainly.com/question/8175791
mass of copper required
https://brainly.com/question/1680090
Keywords: CaCl2, KCl, mole, mass, relative molecular mass
The mass calcium chloride needed is 1.12 g
The balanced equation for the reaction is illustrated below:
CaCl₂ + K₂CO₃ —> 2KCl + CaCO₃
Next, we shall determine the mass of CaCl₂ that reacted and the mass of KCl produced from the balanced equation.
Molar mass of CaCl₂ = 40 + (35.5×2)
= 40 + 71
= 111 g/mol
Mass of CaCl₂ from the balanced equation = 1 × 111 = 111 g
Molar mass of KCl = 39 + 35.5
= 74.5 g/mol
Mass of KCl from the balanced equation = 2 × 74.5 = 149 g
Thus,
From the balanced equation above,
111 g of CaCl₂ reacted to produce 149 g of KCl.
Finally, we shall determine the mass of CaCl₂ needed to produce 1.5 g of KCl as follow:
From the balanced equation above,
111 g of CaCl₂ reacted to produce 149 g of KCl.
Therefore, X g of CaCl₂ will react to produce 1.5 g of KCl i.e
X g of CaCl₂ = [tex]\frac{1.5 * 111}{149}[/tex]X g of CaCl₂ = 1.12 gThus, 1.12 g of calcium chloride, CaCl₂ is needed to produce 1.5 g of KCl.
Learn more: https://brainly.com/question/13143779
If 5.6 g of Copper (II) oxide are used, how many moles of copper metal will be produced?
When 5.6 g of Copper (II) oxide are used, approximately 0.07035 moles of copper metal will be produced. This is calculated using the molar mass of CuO (79.55 g/mol) and the 1:1 stoichiometric ratio in the decomposition reaction of CuO to metallic Cu.
Explanation:To determine how many moles of copper metal will be produced from 5.6 g of Copper (II) oxide, we need to use the molar mass of Copper (II) oxide (CuO). The molar mass of CuO is approximately 79.55 g/mol. By dividing the mass of Copper (II) oxide used by its molar mass, we can find the number of moles of CuO that we have.
Here is the calculation:
Number of moles of CuO = mass of CuO (g) / molar mass of CuO (g/mol)
Number of moles of CuO = 5.6 g / 79.55 g/mol
Number of moles of CuO = 0.07035 mol
Since Copper (II) oxide decomposes to copper and oxygen, and the stoichiometry of the decomposition reaction indicates a 1:1 mole ratio between CuO and metallic Cu, we can predict that the moles of copper metal produced would also be 0.07035 mol. Thus, 5.6 g of Copper (II) oxide would produce approximately 0.07035 mol of copper metal.
When an ionic compound dissolves in water: the positive end of water dipoles attract the negative ions. the solvent-solute attractive forces overcome the solute-solute attractions. the negative end of water dipoles attract the positive ions. each of the above (a, b, and
c.occurs. none of the above (a, b, or
c.occurs?
For example sodium chloride is ionic compound and strong electrolyte and dissociates in water on hydrated sodium cations and chlorine anions:
NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
In water, oxygen is negative and attract the positive ions of sodium, hydrogen is positive and attract the negative ions of chlorine.
In the alveoli and lung capillaries, co2 and o2 are exchanged by means of _____.
In the alveoli of the lungs, CO2 and O2 are exchanged with blood in the surrounding capillaries via diffusion. This passive process occurs due to the concentration gradients of the gases and is aided by the large surface area of the alveoli and the thin walls of both the alveoli and capillaries.
Explanation:In the alveoli and lung capillaries, CO2 and O2 are exchanged by means of diffusion. This process is known as pulmonary gas exchange and is crucial for respiration. Oxygen diffuses from the alveoli into the blood because there is a higher concentration of oxygen in the inhaled air than in the blood of the capillaries. Conversely, carbon dioxide, which is more concentrated in the blood, diffuses from the capillaries into the alveoli to be exhaled. This exchange occurs passively and requires no energy due to the concentration gradients between the gases in the alveoli and the blood.
The efficiency of this gas exchange is supported by the large surface area provided by the vast number of alveoli in the lungs and the thin-walled nature of the alveoli and capillaries. Constant blood flow and regular breathing maintain a steep concentration gradient for oxygen and carbon dioxide, facilitating the diffusion process.
In a self-sustaining ecosystem which component cannot be recycled
A wave has a wavelength of 12 mm and a frequency of 6 hertz. What is its speed?
What is the keq value for the following reaction at equilibrium at a temperature of 298K if the concentrations (in mol/L) of the reactants and products are [N2O4] = 0.0450 and [NO2] = 0.0161?
N2O4(g) <--> 2NO2(g)
Which represent correct variations of the formula for speed? Check all that apply. t = s = t = s = dt d = st d =
Answer: t = d/s , s= d/t d= st
Explanation:
I did the assignment (Also Ikix don´t take this down again)
The correct variations of the speed formula are d = st, representing the calculation of distance, and t = d/s, representing the calculation of time. The options s = t and s = dt don't seem to be valid variations of the speed formula.
Explanation:The formula for speed is typically represented as s = d/t, where s is speed, d is distance, and t is time. The variations of this formula would then be d = st, which gives us the distance traveled if we know the speed and time, and t = d/s, which gives us the time taken if we know the distance and speed. These variations are crucial in different parts of physics, primarily when dealing with motion-related problems.
In the question, the terms d = st and t = d/s are correct variations, while s = t and s = dt don't seem to be valid in the context of speed formula. In speed calculations, it's always important to remember units of measurement, as speed could be recorded in terms such as miles per hour or meters per second, depending upon the context.
Learn more about Speed Formula Variations here:https://brainly.com/question/16242493
#SPJ2
a solution containing 1.1 g NaOH in 325 ml , water is titrated with 444 mL HCL. what is the concentration of HCL in the original solution ?
Which of these properties would be possessed by both acids and bases? note: we do not mean mixing both in the same solution. we mean comparing a solution of an acid and a solution of a base. 1. they would taste bitter, if you were unwise enough to taste them. 2. they would react with metals and produce hydrogen gas. 3. they conduct electricity. 4. they turn litmus green. 5. they have a ph greater than 7. site:.com?
An Arrhenius base is a
substance that dissociates in water to form hydroxide ions (OH⁻).
In this example lithium hydroxide is an Arrhenius base:
LiOH(aq) → Li⁺(aq) + OH⁻(aq).
An Arrhenius acid is a
substance that dissociates in water to form hydrogen ions or protons (H⁺).
For example hydrochloric acid: HCl(aq) → H⁺(aq) + Cl⁻(aq).
4) red litmus turn blue whe base is drop on it and blue litmus turn red when acid is drop on it.
5) bases have pH greater than 7, acids have pH less than 7.
The properties that would possess by both acids and bases is they conduct electricity.
What is acid and base?Acids are sour in taste and turn blue litmus paper to red.
They react with metals to liberate hydrogen.
Bases are solution that accept electron pair bonds.
NaOH is a base and HCl is an acid.
Thus, the correct option is 3, they conduct electricity.
Learn more about acids
https://brainly.com/question/1515003
How many moles of Pb are required if 8 moles of PbCl2 are produced
Milk of magnesia, a suspension of mg(oh)2 in water, reacts with stomach acid (hcl) in a neutralization reaction. mg(oh)2(s) + 2 hcl(aq) −→ 2 h2o(ℓ) + mgcl2(aq) what mass of mgcl2 will be produced if 1.82 g of mg(oh)2 reacts? answer in units of g.
Final answer:
To find the mass of MgCl₂ produced from the reaction of milk of magnesia with stomach acid, the mass of Mg(OH)₂ is converted to moles, which is then used to calculate the moles and subsequently the mass of MgCl₂ formed, resulting in 2.97 grams.
Explanation:
The neutralization of stomach acid by milk of magnesia, which contains magnesium hydroxide (Mg(OH)2), can be represented by the following chemical reaction:
Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(ℜ) + MgCl₂(aq)
To determine the mass of MgCl₂ produced when 1.82 g of Mg(OH)₂ reacts, we will follow these steps:
Calculate the molar mass of Mg(OH)₂.Convert the mass of Mg(OH)₂ to moles.Use the stoichiometry of the balanced equation to find the moles of MgCl₂ produced.Convert the moles of MgCl₂ to grams.Step 1: Molar mass of Mg(OH)₂ = 24.31 (Mg) + 2(16.00 (O) + 1.01 (H)) = 58.33 g/mol
Step 2: Moles of Mg(OH)₂ = 1.82 g / 58.33 g/mol = 0.0312 mol
Step 3: From the reaction stoichiometry, 1 mol of Mg(OH)₂ produces 1 mol of MgCl₂.
So, moles of MgCl₂ produced = 0.0312 mol
Step 4: Molar mass of MgCl₂ = 24.31 (Mg) + 2(35.45 (Cl)) = 95.21 g/mol
Mass of MgCl₂ = 0.0312 mol * 95.21 g/mol = 2.97 g
Thus, 2.97 g of MgCl₂ will be produced.
When 80 g of sodium hydroxide, naoh, are dissolved in enough water to make 500 ml of solution, the molarity of the solution is — a 1 m b 2 m c 4 m d 8 m?
Answer is: molarity of sodium hydroxide solution is c. 4 M.
m(NaOH) = 80.0 g.
n(NaOH) = m(NaOH) ÷ M(NaOH).
n(NaOH) = 80 g ÷ 40 g/mol.
n(NaOH) = 2 mol.
V(NaOH) = 500 mL ÷ 1000 mL/L = 0.5 L.
c(NaOH) = n(NaOH) ÷ V(NaOH).
c(NaOH) = 2 mol ÷ 0.5 L.
c(NaOH) = 4 mol/L.
n - amount of substance.
The molarity of the solution indicates the concentration of the solute dissolved in the solution. The molarity of the 500 mL solution is 4M. Thus, option c is correct.
What is molarity?Molarity is the ratio of the moles of the solute that were dissolved in a solvent to make a liter of solution. The molar concentration is calculated as:
Molarity (M) = moles ÷ volume
Given,
The mass of sodium hydroxide = 80 gm
Volume of solution = 500 mL
Molar mass of sodium hydroxide = 39.997 g/mol
Moles of sodium hydroxide is calculated as:
Moles = mass ÷ molar mass
= 80 ÷ 40
= 2 moles
Molarity is calculated as:
M = n ÷ V
= 2 moles ÷ 0.5 L
= 4 M
Therefore, option c. the molarity of sodium hydroxide solution is 4 M.
Learn more about molarity here:
https://brainly.com/question/14317742
#SPJ2
Identify the oxidized substance, the reduced substance, the oxidizing agent, and the reducing agent in the redox reaction. mg(s)+cl2(g)⟶mg2+(aq)+2cl−(aq)
Magnesium is an oxidized substance (Mg). Substance Reduced: chlorine gas (Cl₂(g)). Chlorine gas (Cl₂(g)) is an oxidizing agent. Magnesium (Mg) is a reducing agent.
In the demonstrated redox reaction:
Cl₂(g) + Mg(s) →Mg₂⁺(aq) + 2Cl(aq).
These things can be found:
Magnesium (Mg) is the substance that oxidizes, losing electrons in the process. It transitions from its ionic form, Mg₂⁺(aq), to its elemental form, Mg(s). Therefore, the oxidized substance is magnesium (Mg).
Chlorine gas (Cl₂(g)) is the chemical that goes through reduction and obtains electrons. It transforms from its diatomic elemental form, Cl₂(g), to chloride ions, 2Cl(aq). As a result, the reduced substance is chlorine (Cl₂(g)).
Oxidizing Agent: The species that oxidizes another substance is known as an oxidizing agent. The oxidizing agent in this instance is chlorine gas (Cl₂(g)), which takes electrons from magnesium (Mg) during the process.
Reducing Agent: The species that results in the decrease of another substance is known as a reducing agent. Due to the fact that it provides electrons to chlorine gas (Cl₂(g)) during the reaction, magnesium (Mg) is the reducing agent in this instance.
So, to sum up:
Magnesium is an oxidized substance (Mg).
Substance Reduced: chlorine gas (Cl₂(g))
Chlorine gas (Cl₂(g)) is an oxidizing agent.
Magnesium (Mg) is a reducing agent.
To know more about Oxidizing Agent:
https://brainly.com/question/11952578
#SPJ3
Rubbing alcohol is 70.0% isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a full 1 pint (473 ml) container?
Hello!
Rubbing alcohol is 70.0% isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a full 1 pint (473 ml) container?
We have the following information:
% V/V (percentage of volume per volume) = 70
V1 (solute volume) = ? (in mL)
V (volume of the solution) = 473 mL
We apply the data to the formula of volume percentage of the solute per volume of solution, we will have:
[tex]\%\:v/v = \dfrac{v_1}{v} *100[/tex]
[tex]70 = \dfrac{v_1}{473}*100[/tex]
[tex]70*473 = 100*v_1[/tex]
[tex]33110 = 100\:v_1[/tex]
[tex]100\:v_1 = 33110[/tex]
[tex]v_1 = \dfrac{3311\diagup\!\!\!\!0}{10\diagup\!\!\!\!0}[/tex]
[tex]\boxed{\boxed{v_1 = 331.1\:mL\:of\:isopropyl\:alcohol}}\Longleftarrow(solute\:volume)\:\:\:\:\:\:\bf\purple{\checkmark}[/tex]
Answer:
331.1 ml of isopropyl alcohol
________________________
[tex]\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}[/tex]
The concentration terms are molality, normality and mole fraction and percent by volume. Therefore, 331.1ml of isopropyl alcohol are in a full 1 pint (473 ml) container.
What is percent by volume?The percent by volume formula calculates the concentration of the solution by using the volume of the solute (the dissolved content in the solvent) and the volume of the solution. It is represented as (v/v%).
Mathematically,
percent by volume=(volume of solute÷ volume of solution)×100
% V/V (percentage of volume per volume) = 70
V1 (solute volume) = ? (in mL)
V (volume of the solution) = 473 mL
Substituting all the given values in the given formula, we get
70 =(volume of solute÷ 473 )×100
volume of solute=331.1ml
Therefore, 331.1ml of isopropyl alcohol are in a full 1 pint (473 ml) container.
To know more about percent by volume, here:
https://brainly.com/question/15461083
#SPJ2
After measurements or observations are made in a scientific investigation, it is most appropriate to
After observations are made, it is crucial to record and present results properly, discuss findings, and formulate hypotheses for further testing in the scientific investigation process.
After measurements or observations are made in a scientific investigation, it's most appropriate to record your observations and present your results in a suitable format, such as tables and graphs. Discussing findings with group members is also important, coupled with formulating a relevant central idea. If a scientist develops a new idea based on their observations of nature, the next step would be to make a new hypothesis, which can then be tested through experiments.
As part of the scientific method, it's essential not to force data to fit a hypothesis. Instead, draw conclusions from the experiment results objectively. If data fits, you should repeat the experiment to verify results, or if it does not, conduct more background research and refine the hypothesis.
Static charges can be applied to neutral objects by friction, induction or conduction. What do all of these methods utilize to create this charge?
a.protons
b.electrons
c.heat energy
What monomers are found in DNA and RNA?
A-amino acids
B-nucleotides
C-fatty acids
D-saccharides
The questions refer to the following graphs of mechanical waves.
A
B
C
The wave with the longest wavelength is (A,B,C). The wave with the smallest amplitude is (A,B,C). The wave with the most energy is (A,B,C).
A is the wave with the longest wavelength. The graph clearly shows this since wave A has a larger wavelength than waves B and C. Wave A has the longest wavelength when compared to the other two waves.
What is the C wave ?C is the wave with the least amplitude. The graph shows this since wave C has a significantly lesser amplitude than waves A and B. Wave C has the least amplitude when compared to the other two waves. B is the most energetic wave.
The graph shows this because wave B has a larger amplitude than waves A and C. Wave B has the greatest amplitude when compared to the other two has the more energy in comparison to the two.
The longest wavelength wave has the lowest frequency and the lowest energy. A wave's wavelength is inversely related to its frequency, which implies that as the wavelength grows, so does the frequency. Because energy is proportional to frequency, the wave with the longest wavelength has the least energy.
The wave with the smallest amplitude has the least amount of energy. The largest displacement of a wave from its equilibrium position is referred to as its amplitude. The energy of a wave is exactly proportional to its amplitude, therefore as the amplitude falls, so does the energy.
Learn more about displacement at:
https://brainly.com/question/11934397
#SPJ2
Write a balanced nuclear equation for the beta decay of protactinium
The balanced nuclear equation for the beta decay of protactinium is 231Pa → 231U + β- + ν. In this equation, a protactinium-231 nucleus decays into a uranium-231 nucleus through the emission of a beta particle (β-) and an electron neutrino (ν).
Explanation:The balanced nuclear equation for the beta decay of protactinium is:
231Pa → 231U + β- + ν
In this equation, a protactinium-231 nucleus decays into a uranium-231 nucleus through the emission of a beta particle (β-) and an electron neutrino (ν). The atomic number of the nucleus increases by one, from 91 to 92, due to the gain of a proton.
Question 2
Which of the following is an endothermic reaction?
Question 2 options:
dissolving sugar in water
iron rusting
campfire burning
ice melting
many grams of aluminum are required to produce 3.5 moles Al2O3 in the presence of excess O2?
To produce 3.5 moles of aluminum oxide (Al₂O₃), you need 188.86 grams of aluminum (Al) in the presence of excess oxygen (O₂).
This is determined using the balanced chemical equation and molar masses.
To determine how many grams of aluminum (Al) are required to produce 3.5 moles of aluminum oxide (Al₂O₃) in the presence of excess oxygen (O₂), you need to use stoichiometry and the molar masses of the compounds involved.
The balanced chemical equation for the formation of aluminum oxide is:
4Al + 3O₂ → 2Al₂O₃
From the equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (Al₂O₃). This means that 2 moles of Al₂O₃ are produced from 4 moles of Al.
To find out how many moles of Al are needed for 3.5 moles of Al₂O₃, set up the proportion:
(4 moles Al / 2 moles Al₂O₃) = (x moles Al / 3.5 moles Al₂O₃)
Solving for x:
x = (4/2) * 3.5 = 7 moles of Al
The molar mass of Al is approximately 26.98 g/mol. To find the mass of 7 moles of Al:
7 moles Al * 26.98 g/mol = 188.86 g Al
Thus, 188.86 grams of aluminum are required to produce 3.5 moles of aluminum oxide in the presence of excess oxygen.
What is the number of oxygen atoms in the ring portion of the haworth structure of glucose?
Who discovered neutrons?
A. James Chadwick
B. Ernest Rutherford
C. John Dalton
D. J. J. Thompson
It is necessary to have a 40% antifreeze solution in the radiator of a certain car. the radiator now has 70 liters of 20% solution. how many liters of this should be drained and replaced with 100% antifreeze to get the desired strength?
To achieve the desired 40% antifreeze solution, you should drain 70 liters of the 20% solution and replace it with 70 liters of 100% antifreeze.
To get a 40% antifreeze solution in the radiator, we need to drain a certain amount of the 20% solution and replace it with 100% antifreeze. Let's break down the problem step by step:
1. Calculate the amount of antifreeze in the original 70-liter 20% solution:
- The original solution is 20% antifreeze, so 20% of 70 liters is (20/100) * 70 = 14 liters of antifreeze.
2. Determine how much antifreeze we need in the final solution:
- We want a 40% antifreeze solution, so the final solution should have (40/100) * (70 liters) = 28 liters of antifreeze.
3. Find the amount of solution to drain:
- The difference between the desired and current amount of antifreeze is 28 liters - 14 liters = 14 liters.
- Since the original solution is 20% antifreeze, we can equate 14 liters to 20% of the total solution, and solve for the total amount of solution.
- Let's represent the total solution as "x" liters. So, (20/100) * x = 14 liters.
- We can solve this equation by dividing both sides by 20/100: x = 14 liters / (20/100) = 70 liters.
4. Calculate the amount of solution to drain and replace with 100% antifreeze:
- We need to replace 70 liters of the 20% solution with 100% antifreeze.
- So, we should drain and replace 70 liters of the original solution with 70 liters of 100% antifreeze.
Therefore, to achieve the desired 40% antifreeze solution, you should drain 70 liters of the 20% solution and replace it with 70 liters of 100% antifreeze.
Final answer:
To determine how many liters of a 20% antifreeze solution should be drained and replaced with 100% antifreeze to make a 40% solution in a 70-liter system, we set up and solve an equation based on the volume and concentration of antifreeze before and after draining and adding pure antifreeze.
Explanation:
Let's denote the amount of solution to be drained and replaced with 100% antifreeze as 'x' liters. The amount of antifreeze in the original solution is 20% of 70 liters, or 0.2 × 70 = 14 liters. When 'x' liters of this solution are removed, 'x' liters of pure antifreeze are added, so the new volume of antifreeze in the solution will be (14 - 0.2x + x) liters. The total volume of the solution remains 70 liters, and we want it to be a 40% antifreeze solution. So, we set up the equation:
0.40 × 70 = 14 - 0.2x + xSolving for 'x', we find the amount of solution to be replaced with 100% antifreeze to obtain the 40% solution desired.
If the H+ in a solution is 1x10^-1 mol/L what is the OH-
the concentration of [tex]\( \text{OH}^- \)[/tex] ions in the solution is [tex]\( 1.0 \times 10^{-3} \, \text{mol/L} \)[/tex].
To find the concentration of [tex]\( \text{OH}^- \)[/tex] ions [tex](\( [\text{OH}^-] \))[/tex] in a solution given the concentration of [tex]\( \text{H}^+ \)[/tex] ions [tex](\( [H^+] \))[/tex], we can use the fact that in water at [tex]\( 25^\circ \text{C} \)[/tex] [tex](\( 298 \text{K} \))[/tex], the product of [tex]\( [\text{H}^+] \)[/tex] and [tex]\( [\text{OH}^-] \)[/tex] is constant and equal to [tex]\( 1.0 \times 10^{-14} \, \text{mol/L} \)[/tex]. This is known as the ion product of water [tex](\( K_w \)).[/tex]
[tex]\[ K_w = [\text{H}^+] \times [\text{OH}^-] \][/tex]
Given [tex]\( [\text{H}^+] = 1 \times 10^{-1} \, \text{mol/L} \)[/tex], we can rearrange the equation to solve for [tex]\( [\text{OH}^-] \)[/tex]:
[tex]\[ [\text{OH}^-] = \frac{K_w}{[\text{H}^+]} \][/tex]
Substitute the given values:
[tex]\[ [\text{OH}^-] = \frac{1.0 \times 10^{-14} \, \text{mol/L}}{1 \times 10^{-1} \, \text{mol/L}} \][/tex]
[tex]\[ [\text{OH}^-] = 1.0 \times 10^{-14} \, \text{mol/L} \times \frac{1}{1 \times 10^{-1}} \, \text{mol/L} \][/tex]
[tex]\[ [\text{OH}^-] = 1.0 \times 10^{-14} \times 10^{1} \, \text{mol/L} \][/tex]
[tex]\[ [\text{OH}^-] = 1.0 \times 10^{-3} \, \text{mol/L} \][/tex]
Therefore, the concentration of [tex]\( \text{OH}^- \)[/tex] ions in the solution is [tex]\( 1.0 \times 10^{-3} \, \text{mol/L} \)[/tex].