Answer:
Hypothalamic-hypophyseal portal veins (a network of blood vessels)
Explanation:
The hypothalamus- pituitary secretory complex can be referred to as the "command center" of the endocrine system. This is because the complex regulates the synthesis and secretion of hormones by other glands.
The anterior pituitary secretes a battery of hormones that collectively influence virtually all physiological responses in the body. This function makes the pituitary gland be referred to as the"master gland" of the body. This is true but the hypothalamus is responsible for regulating the synthesis of these hormones by the pituitary. Some neurons in the hypothalamus secrete hormones that controls the secretion of hormones by the anterior pituitary. These hypothalamic hormones are referred to as releasing and inhibiting hormones depending on whether they stimulate or inhibit secretion of hormones by the anterior pituitary.
The hypothalamus releasing/inhibiting hormone are carried directly to the anterior pituitary through a network of blood vessels in the infundibulum called hypothalamic-hypophyseal portal veins.
Specific hypothalamic hormones bind to receptors on specific anterior pituitary cells, thereby regulating the release/inhibition of the hormone they produce.
The mechanism of transportation from the hypothalamus to the anterior pituitary gland is through the hypophyseal portal system, a network of blood vessels.
Explanation:The transport of hormones from the hypothalamus to the anterior pituitary gland is through the hypophyseal portal system. This system is a network of blood vessels that allows for direct transport between these two glands. The hypothalamus secretes releasing and inhibiting hormones into this portal system which travels down to the anterior pituitary triggering or preventing the release of certain hormones respectively.
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What were the first hominins? What was the evolutionary fate of the first hominins?
Drag the descriptions to the appropriate hominin lineages.
A) Pre-australopithecinerobust.
B) Australopithecinesgenus Homo.
Answer:
A) Pre-australopithecinerobust.
B) Australopithecinesgenus Homo.
Explanation:
Pre-australopithecinerobust.
The few findings indicate that he walked with his back straight, but the shape of the foot, with the big toe directed inward (as in the hands) instead of being parallel to the others, indicates that he should walk leaning on the outside of his feet and he couldn't travel great distances
Australopithecinesgenus Homo.
The first hominids that are certain that they were completely biped are the members of the Australopithecus genus, this type of hominin thrived in the wooded savannas of East Africa between 4 and 2.5 million years ago with remarkable ecological success, as evidenced by the radiation he experienced, with at least five different species scattered from Ethiopia and Chad to South Africa.
Gender role socialization... is the process by which social institutions shape expectations of acceptable behaviors for men and women. makes anti-discrimination and equal pay legislation more effective. results in men preparing for non-traditional jobs for men. None of the above.
Answer:
gender role socialization is the process by which social institutions shape expectations of acceptable behaviours for men and women
Gender role socialization is the process by which societal expectations of acceptable behaviors for men and women are shaped, involving agents like family and media. It enforces stereotypes and limits personal freedom, but understanding it can lead to more inclusive societies.
Gender role socialization is the process by which social institutions shape expectations of acceptable behaviors for men and women. This includes how individuals are taught to behave, perceive, and interact within their societal roles based on their gender. The primary agents of gender socialization are family, education, peer groups, and mass media, each reinforcing gender roles and creating normative expectations for gender-specific behavior. This process begins early in life, leading individuals to often subconsciously conform to these roles, believing their actions to be natural rather than the result of societal constructs.
Gender socialization plays a critical role in shaping the lives of individuals by dictating the behaviors, attitudes, and opportunities deemed appropriate based on one's gender. Unfortunately, this often enforces stereotypes and limits personal freedom and expression, contributing to a cycle of gender-based discrimination and inequality. Understanding and challenging these constructed roles can lead to more inclusive and diverse societies, where individuals are valued for their unique abilities rather than their adherence to prescribed gender roles.
If organisms A, B, and C belong to the same class but to different orders and if organisms C, D, and E belong to the same order but to different families, which of the following pairs of organisms would be expected to show the greatest degree of structural homology?
A) A and D
B) B and D
C) B and C
D) D and E
Answer:
The right answer is D) D and E
Explanation:
All the organisms are classified into seven major groups or there are seven levels of classification in which organisms are divided. These are Kingdom, phylum, class, order, family, genus, and species.
So here kingdom is the highest level of classification and species is the lowest level of classification. So as we move from kingdom towards species the homology increase and if we move from lower to higher level the homology between organism decreases.
So as the order is at the lower level than class therefore organisms in class will show the greatest degree of structural homology therefore D and E would be expected to show higher structural homology.
You cross a plant that makes smooth peas with a plant that makes wrinkled peas (rr). If half of the offspring from that cross are smooth and half are wrinkled, what is the genotype of the smooth pea producing parent plant?
Answer:
Rr
Explanation:
This cross is a typical example of a test cross. A test cross is a cross between a heterozygous F1 progeny (different alleles) and a homozygous recessive parent in order to determine the actual genotype of the dominant parent i.e. whether homozygous or heterozygous dominance. In a test cross, if any of the offsprings show a recessive phenotype, it means the dominant parent is heterozygous
In this case, the allele for smooth pea (R) is dominant over that of wrinked pea (r).
If a cross between a smooth pea plant and a wrinkled pea plant gave rise to 50% phenotypical wrinkled pea plants (rr genotype, because the wrinkled shape can only express itself if it is in a homozygous state), it means that the smooth pea parent plant is heterozygous for pea shape (Rr) i.e. the allele for smooth shape was masking that of wrinkled shape in the smooth pea parent plant.
If a double-stranded DNA sample were composed of 10% thymine, what would be the percentage of guanine?a. 10%b. 20%c. 40%d. 80%
Answer:
c. 40%
Explanation:
DNA is composed of smaller subunits called nucleotides.
Structure of a nucleotide contains a 5-carbon sugar (Deoxyribose), phosphate group and one of the four nitrogenous bases.
Adenine and Thymine are nitrogenous bases found in DNA. Other nitrogenous bases are cytosine, guanine and uracil.
Adenine, Thymine, Guanine and Cytosine are found in DNA whereas in RNA, Uracil is present instead of Thymine.
DNA is a double stranded structure.
In DNA, adenine of one strand always pairs with thymine of the other strand (complementary). Similarly, guanine of one strand pairs with cytosine of complementary strand. Adenine pairs with Thymine via 2 hydrogen bonds whereas cytosine pairs with guanine via 3 hydrogen bonds. This hydrogen bonding maintains the double helix structure of DNA.
It is implied that for every thymine present in DNA there will be adenine on the complementary stand with which it will bind via 2 hydrogen bonds.
So if a double stranded DNA sample contains 10% Thymine, then it will also contain 10% adenine. This makes the combined contribution of adenine and thymine to be 20%. The left over 80% of DNA will contain equal amounts of cytosine and guanine as each guanine binds with cytosine via 3 hydrogen bonds. So if we divide 80% into 2 equal parts then it is 40%. Hence, there is 40% guanine, 40% cytosine, 10% adenine and 10% thymine.
The percentage of guanine in a double-stranded DNA sample with 10% thymine is 40%, due to base pairing rules where adenine equals thymine and guanine equals cytosine.
Explanation:The question is focused on understanding the relationship between the different nucleotide bases in a DNA molecule. According to Chargaff's rules, the amount of adenine (A) is equal to thymine (T), and the amount of guanine (G) is equal to cytosine (C). Given that the DNA sample is composed of 10% thymine, it follows that it must also be composed of 10% adenine since A pairs with T. Therefore, since adenine and thymine together make up 20% of the DNA bases (10% + 10%), and the total amount of DNA bases must equal 100%, the remaining 80% of the bases are guanine and cytosine. Because guanine pairs with cytosine, their percentages must be equal. So, guanine and cytosine will each account for half of the remaining 80%, which is 40%. Thus, the percentage of guanine in this DNA sample is 40%.
Which trophic level generates the most dead organic material in most ecosystems?
Answer:
1st trophic level
Explanation:
Trophic levels are each of the sets of organisms in an ecosystem that obtain matter and energy in the same way, so they occupy an equivalent place in the food chain.
The energy that living beings need to perform vital functions (nutrition, relationship and reproduction) comes from the Sun. Plants are responsible, through photosynthesis, for transforming inorganic matter into organic. This matter and energy will pass to the rest of the organisms in the ecosystem, such as herbivorous and carnivorous animals. Finally, the decomposing organisms will be responsible for breaking down this organic matter into inorganic, closing the cycle so that it can be restarted.
Therefore, we can distinguish three trophic levels:
- Producing organizations (autotrophs) or 1st trophic level
- Consumer organisms (herbivores, carnivores, scavengers).
- Decomposing and transforming organisms (break down organic matter into inorganic).
Producing organisms are autotrophs (plants, algae and some bacteria). They are capable of manufacturing their own organic matter from inorganic matter (water, mineral salts and carbon dioxide) and the energy of the sun, which is why they are called producers.
Producing organisms constitute the lowest trophic level, being the basis on which the higher levels are based. They are the only ones that, through photosynthesis, are capable of capturing solar energy and transforming it into chemical energy. They are also the ones that generate the greatest amount of dead organic matter in the ecosystem.
Calico cats are nearly all females because the alleles for the different colors that appear are carried on the X chromosomes. Males are rarely multicolored, because they can only carry one form of the allele. What is this an example of?
Answer:
This is example of Inactivation of X chromosome.
Explanation:
In calico cats, Fur color is carried on Chromosome X. Female cats have two X chromosomes. When they have two X chromosomes, some of these X chromosomes in some cells throughout the body are INACTIVATED and they are seen as black dots under microscope. These black dots are called Barr Bodies. Normally calico cats have brown and white fur color, and also black color due to this barr bodies. X in activation or the formation of barr bodies are not observed in males because they have only one X chromosome.
Peer-raised macaques show neurological differences from those macaques raised by adults; they have less developed neural networks using the neurotransmitter serotonin. This is an example of a/an
This is an example of an Epigenetic effect.
Explanation:
It is the study of heritable changes in the expression of genes, that are not involved in the changes present in DNA sequence. It is regular and naturally occurred, sometimes factors are responsible like age, lifestyle and disease state.
At times it leads to more damaging effect that can cause cancer. So this is also related to various fatal disease. During adulthood epigenetic effect remains stable. It does not occur in mother womb, but during the lifespan. This epigenetic effect can be reversed.
In bacteria, the antibiotic chloramphenicol prevents amino acids from bonding. The MOST likely reason that bacteria die from treatment with chloramphenicol is because the antibiotic
Answer& explanation:
The mechanism of action of chloramphenicol can be explained as follows:
Chloramphenicol binds to the 50S subunit of the ribosome, inhibiting the protein synthesis of the bacteria, thus having bacteriostatic action (inhibiting the growth of bacteria, preventing their proliferation).
In addition, chloramphenicol can be bactericidal (destroys bacteria) when in high concentrations, or when used against highly sensitive microorganisms, such as Haemophilus influenzae and Streptococcus pneumoniae. The mechanism of action for these bacteria, however, is not yet elucidated.
A part of the promoter found in Archaea and Eukaryotes, called the TATA box, is said to be highly conserved in evolution. What could this indicate?A. The sequence evolves very rapidly.B. The sequence does not mutate.C. Any mutation in the sequence is selected against.
Answer:
The sequence does not mutate.
Explanation:
The conserved sequences may be defined as the identical or the similar DNA sequences that shows similarity in different group of organism. TATA box sequences is the example of conserved sequences.
These conserved sequences has been maintained by the phenomena of the natural selection. These sequences remain conserved throughout the evolution process. The conserved sequences cannot be mutated easily and present from the different geologic time.
Thus, the correct answer is answer is option (B).
This group of enzymes digests the majority of ingested fat.
a. pancreatic lipases.
b. pepsin and stomach acid.
c. bile salts.
d. lingual lipases.
Answer:
Option A
Explanation:
Undigested fats include all those fatty acid and lipids which do not have the ability to dissolve in water. This inability makes them difficult elements for digestion. All this undigested fat accumulates and reaches the intestine for digestion as globs. Globs are emulsified by the bile salts and are broken down into smaller fat droplets. The smaller fat droplets have large surface area and hence now they can be acted upon by the fat-digesting enzyme pancreatic lipase. Thus, the first set of enzymes that act upon the undigested fats in the intestine are pancreatic lipase
Hence, option A is correct
The enzymes that digest the majority of ingested fat are pancreatic lipases.
Explanation:The enzyme group that digests the majority of ingested fat is pancreatic lipases. These enzymes are produced and secreted by the pancreas and work primarily in the small intestine, where they break down dietary fats into simpler compounds like fatty acids and glycerol. This is an essential part of the digestion and absorption process for fats in our diet. The option pepsin and stomach acid refers to the digestion of proteins in the stomach, while bile salts are produced in the liver and help to emulsify fats, preparing them for digestion by lipases. The lingual lipases, meanwhile, are secreted by the salivary glands and start the digestion of fats in the mouth, but their contribution to overall fat digestion is relatively minor.
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Which of the following correctly displays the sequence of developmental milestones?A) blastula → gastrula → cleavageB) cleavage → gastrula → blastulaC) cleavage → blastula → gastrulaD) gastrula → blastula → cleavage
Cleavage → blastula → gastrula correctly displays the sequence of developmental milestones
Explanation:
In first step of developmental milestone, the zygote undergoes cell cleavage to form a spherical balls of cells, that are known a blastula. This blastula are filled with fluid called blastoderm at the centre. Later the balausta arranges itself in double layer out of which the inner one becomes the zygote and the outer one is placenta. After this stage the blastula folds itself into several layers i.e. germ layers which will give rise to the internal structure of living being. These germ layers are ectoderm, endoderm, mesoderm.
C) The sequence of developmental milestones in embryonic development is cleavage, blastula, and then gastrula.
Initially, the cleavage is the series of mitotic cell divisions of a fertilized egg, or zygote, that leads to a multicellular stage. After cleavage, these cells rearrange to form a hollow ball of cells known as the blastula. The blastula then undergoes a process known as gastrulation, where it folds inward to form a three-layered structure called the gastrula, which will further differentiate into various tissues and organs during the subsequent stages of development.
During embryonic development, unique cell layers develop and differentiate during a stage known as the gastrula stage. These layers, termed germ layers, give rise to the different organs and tissues in the body.
Some butterflies can ingest toxic chemicals from the milkweed plants they feed on and then canstore those chemicals in their body. Because toxins stored in the butterflies are toxic to birds, thebirds avoid eating the butterflies. Which of the following is the best explanation for this situation?
A) Any butterfly allele that allowed milkweed toxin storage would be likely to persist becausebutterflies that had it were more likely to survive.
B) Butterflies developed a mutation that led them to be able to store the chemical because theyneeded to avoid being eaten.
C) Milkweed plants wanted the butterflies to ingest the chemical so they would no longer feedon the plant, but the butterflies fooled the milkweed by storing the toxic chemicals.
D) Butterflies that stored the chemicals were never eaten by predators, so those butterfliessurvived.
Answer:
A) Any butterfly allele that allowed milkweed toxin storage would be likely to persist because butterflies that had it were more likely to survive.
Explanation:
Butterflies are natural preys to birds. Over time, some butterflies evolved adaptive strategy such as developing an allele which enables storage of toxin from milkweed as a form of defense mechanism. This stored toxins repel birds from eating the butterflies having this allele giving rise to the survival of these butterflies overtime. Butterflies that had it are likely to be highly favored for survival against predatory birds, while those butterflies without this allele are likely to be heavily preyed upon by birds.
While biodiversity includes the number of species in a given area, it also includes:
- overall number of trophic levels in a food web.
- unique phylogenetic lineages.
- abiotic factors that define the community.
- amount of primary productivity.
Answer:
Unique phylogenetic lineages. (Ans. B)
Explanation:
Biodiversity: It is defined as the total species or variety of species present in a place on earth. This variety common measurement is known as species richness, it is defined as the count of species present in an area.
It is helping in to measure variation at the species, genetic, and ecosystem level. Phylogenetic lineage showing the relationship (evolutionary) between different biological species. Their phylogeny is determined by the differences and similarities in their genetic characters.
''Unique phylogenetic lineages.'' is the correct answer.
What is biodiversity?Biodiversity is the total number of species that are present in a place.
Biodiversity helps in the measuring of variation at the species, genetic, and ecosystem level. Phylogenetic lineage shows the relationship between different biological species so we can conclude that ''Unique phylogenetic lineages.'' is the right statement.
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. The trait that would be least useful in a phylogenetic analysis would be one that A) is detectable only in observations of early development. B) involves genetically inherited behaviors. C) is altered easily by small changes in diet. D) can be studied only in museum specimens. E) is heritable but is determined by many genes.
Answer:
A trait that is altered easily by small changes in diet.
Explanation:
The phylogenetic tree explains the evolutionary relationship between the organisms. The phylogeny of the organisms will depend on the difference and similarities in their genetic or physical characters.
The traits that are used in phylogeny must be constant and present in the ancestors or in atleast a group. The trait that can be easily modified or changed cannot be used for the study of the evolutionary relationship. Hence, trait which is altered by diet cannot be used in phylogenetic analysis.
Thus, the correct answer is option (C).
What type of arthropod appendage is comprised of a single series of segments attached end-to-end
Answer:
The correct answer is - uniramous.
Explanation:
The appendages are present on each body segment of all arthropods. Each segment generally has a pair of end to end appendages. The appendages of the arthropods may be either uniramous or biramous depending on their number of branches in segments.
Uniramous appendages are the appendages that comprise the single series of the end to end attached together, whereas biramous appendages have two branches and each branch has a series of the end to end segments.
Thus, the correct answer is - Uniramous appendages.
Oxidative phosphorylation is the third step in cellular respiration. It is composed of two smaller steps (electron transport chain and chemiosmosis). What molecules are donating their energy to power the proteins in the ETC?
Answer:
NADH and FADH2
Explanation:
Oxidative phosphorylation is the last step of cellular respiration involving two smaller steps; Electron transport chain (ETC) and chemiosmosis.
ETC is a series of proteins and organic molecules present in the cristae of the mitochondria. Electrons are passed from one member of the transport chain to another in a series of reduction-oxidation reactions (redox). Energy released is captured as a proton gradient.
All the electrons that are supplied into the transport chain are donated by NADH and FADH2 molecules (reduced electron carriers) produced in the previous stages of respiration. As the electrons are passed down the chain, they move from a higher to a lower energy level, releasing energy in the process. The released energy is used by several of the protein complexes to pump protons from the matrix of the mitochondria to the intermembrane space, forming a proton gradient.
The electrons donated by NADH are at a higher energy level i.e. NADH is a very good donor of electrons in redox reactions. This attribute allows NADH to transfer its electrons directly to Complex I, where energy is released and the complex uses this energy to pump protons across the membrane.
FADH2, on the other hand, is not a good donor of electrons. Thus, its electrons are at a lower energy level, making it unable to transfer its electrons to ComplexI. It feeds them through Complex II instead, which does not pump protons across the membrane.
This factor (Complex I bypass) causes FADH2 molecules to contribute less to the proton gradient than NADH molecules.
N.B: the energy stored in the proton gradient is subsequently used to produce ATP in Chemiosmosis.
Final answer:
In the electron transport chain part of oxidative phosphorylation, the molecules NADH and [tex]FADH_2[/tex] donate high-energy electrons to power the protein complexes and create ATP. These electron carriers are produced during earlier steps of cellular respiration.
Explanation:
Oxidative phosphorylation is the third and final step of aerobic cellular respiration and it includes two processes: the electron transport chain (ETC) and chemiosmosis. In the ETC, energy is provided by two molecules, NADH and [tex]FADH_2[/tex], which are the reduced forms of the electron carriers NAD+ and FAD.
These molecules are produced during earlier stages of cellular respiration and donate their high-energy electrons to power the protein complexes within the ETC. As the electrons flow through the chain, they release energy used to pump protons across the mitochondrial membrane, creating an electrochemical gradient.
During chemiosmosis, the accumulated protons flow back into the mitochondrial matrix through an enzyme called ATP synthase, which synthesizes ATP from ADP and inorganic phosphate. The flow of protons provides the energy necessary for ATP production, culminating in the highly efficient generation of ATP, essential for cellular processes.
In a species of ground finch that inhabits the Galápagos Islands, the average beak size increased over several generations from 9 mm to 10 mm after a drought that left only large hard seeds for the finches' food source. This is an example of_________.a. stabilizing selectionb. genetic driftc. disruptive selectiond. directional selection
Answer:
d. directional selection
Explanation:
Directional selection is a form of natural selection that occurs when a particular extreme phenotype of a species is highly favored and thrives more than the other extreme phenotype. This is particularly influenced by environmental changes resulting in differences in the survival between both extreme phenotypes.
In the Galapagos Islands during drought, the seeds to be fed on by finches are mostly large in size, giving rise to the survival of only finches with large beak size of 9 mm to 10 mm as against finches with small beak size. Finches with large beak sizes are favored over finches with phenotypic traits of small beak sizes.
To see patterns in the data from an experiment like this, it is helpful to graph the data. A bar graph is used instead of a line graph because each type of liver cell was independent of the others. But first, you must determine which variable should go on each axis of the graph.
What variable did the researchers intentionally vary in the experiment, and what are the units for this variable?
Answer:
From the information you provided, the information intentionally varied is the type of liver cells and there should not be any units for this variable unless the liver cells were categorised by a quantitative feature. The y axis would be the axis of the dependent variable measured and the x axis would be the axis of the independent variable measured.
Explanation:
Only the fibrous layer can be observed in its entirety from the superficial surface of the cow eye. True or False
Answer:
True
Explanation:
Three layers are found in a given mammalian eye and since cow is also a mammal the same applies to it.
The three layers are as follows :
1. Fibrous layers - it is the outermost layer that consists of the sclera and the cornea.
2. The vascular layer - it is the middle layer and is vascularized. it consists of the iris, the ciliary body, and the choroid.
3. The neural layer- it is the innermost layer that consists of the retina.
In a cow's eyes, these three layers are present however only the uppermost fibrous layer is visible from the superficial surface because the vascular and the neural layers lie deep to the fibrous layer.
Answer:
True
Explanation:
The fibrous layer is the external layer of eyeball wall. The fibrous layer is a connective tissue that is not connected with blood supply thus it is avascular tissue. This tissue contains eyeball contents. The opaque sclera consist of around 90% of posterior side of fibrous layer. The cornea consist of around 10% of fibrous anterior portion of eye. The layers like neural and fibrous are deep. Thus, it is not possible to observe these layers. So, only the fibrous layer can be observed in its entirety from the superficial surface of the cow eye.
An elephant and a mouse are running in full sunlight, and both overheat by the same amount above their normal body temperatures. When they move into the shade and rest, which animal will cool down faster?
A. The elephant will because it has the higher surface-area-to-volume ratio.
B. The elephant will because it has the lower surface-area-to-volume ratio.
C. The mouse will because it has the higher surface-area-to-volume ratio.
D. They will cool at the same rate because they overheated by the same amount
Answer:
The mouse will because it has the higher surface-area-to-volume ratio.
Explanation:
The living organisms maintain their homeostasis by maintaining their internal constant environment as external environment changes. These organisms are known as exothermic animal.
The surface area to volume ratio in case of living organisms plays an important role. The small species has high surface area to volume ratio as compared to the larger species. The diffusion, cooling and other process is faster in the small size species. The mouse body will get cool faster than elephant species.
Thus, the correct answer is option (3).
Biologists have found more than 500 species of fruit flies on the various Hawaiian islands, all apparently descended from a single ancestor species. When this ancestor colonized the island chain, it found few competitors: Many insect and fly families present in other regions are absent from the isolated Hawaiian Islands. This example illustrates _____.
Answer:
Adaptive radiation
Explanation:
Adaptive radiation occurs when an ancestral species move to a new environment that has various resources that are necessary for survival and also has environmental conditions that would ensure its offspring adapt well over time. In this new environment, the ancestral species would produce offspring with different traits and behaviors that will allow them to survive in this new environment while occupying their various niches. Over a relatively short time, different species arising from the common ancestor would occupy the new environment.
Which of the following would be a reasonable experimental strategy to prevent translation of a particular prokaryotic mRNA without targeting the ribosome? Which of the following would be a reasonable experimental strategy to prevent translation of a particular prokaryotic mRNA without targeting the ribosome? Inhibit termination factors. Inhibit the sigma factor. Add suppressor tRNA molecules to the cell. Mutate or remove the Shine-Dalgarno sequence on the mRNA.
Answer:
The correct answer is "Mutate or remove the Shine-Dalgarno sequence on the mRNA".
Explanation:
The Shine-Delgarno sequence is a fragment of bacterial and archaeal messenger RNA that helps to recruit the messenger RNA to the ribosome to initiate protein synthesis by translation. Mutating or removing the Shine-Dalgarno sequence on the mRNA will prevent translation of a particular prokaryotic mRNA. Therefore, this is a reasonable experimental strategy to achieve this effect without targeting the ribosome, but the prokaryotic mRNA.
Haploid Vs Diploid, respond Quick!!!!!
Answer:
Haploid: Haploid is the quality of a cell or organism having a single set of chromosomes. A haploid cell only has one set of chromosomes, and most of the time that refers to the sex cells, either eggs or sperm.
Diploid: Most animal cells and plant cells are diploid. The reason they're diploid is because they got one chromosome from their mother and one chromosome from their father. "Di" means two, of course.
Explanation:
There is a critical transition from a diploid cell to a haploid cell to allow normal reproduction to occur, so that when these two haploid cells come together with a single set of genetic information, they can come together into a zygote (made of when the egg cell and the sperm cell come together) that then reconstitutes a diploid cell, which can then become a new individual.
I don't know much about biology and stuff, but I hope the notes from my notebook help. Good luck!
Answer: Diploid cells contain two comlete sets of chromosomes and haploid only contain half.
Explanation:
One character in peas that Mendel studied was yellow versus green seeds. A cross between a homozygous yellow line (YY) and a homozygous green line (yy) will result in F1 plants that are heterozygous (Yy) for this trait and produce yellow seeds.
Answer:
The statement is true.
Explanation:
Gregor Mendel, the Father of Genetics, used pea plants as a model to study inheritance for several reasons, but mainly because they possess a diversity of phenotypic traits, such as different colors and shapes.
Mendel analyzed the inheritance patterns of parental genes in regard to how these genetic traits appeared in the phenotype of the offspring, he categorized these traits as dominant (two capital letters; AA) or recessive (two low-case letters; aa). To test this in the experiments, he selected yellow and green pea plants.
When he crossed yellow and green pea plants, he observed that the first generation exhibited the yellow phenotype. This indicated that the color yellow (YY) was the dominant one, while the green (yy) was, consequently, recessive.
Therefore, if we cross a homozygous yellow line (YY) with a homozygous green line (yy), the result of the First Generation (F1) will result in heterozygous plants with a yellow phenotype as demonstrated in the Punnett Square below:
Y Y
y Yy Yy
y Yy Yy
YY: Yellow
yy: Green
Yy: Yellow
The embryos of all animals undergo gastrulation, a dramatic reorganization of cells critical to formation of the animal body. Do you understand all the terms associated with gastrulation?
Answer:
Terms associated with gastrulation includes blastula, gestation, germ layers, endoderm, mesoderm, ectoderm e.t.c
Explanation:
Gastrulation is a process involving a complex series of cell shape changes and cell movement that occurs in the blastula. It occurs during the development inside the womb over a period of time before birth.
The period of development is known as Gestation. These cells move and rearrange dramatically in the blastula creating the embryonic tissue layers which in turn produces the tissue and organs of the adult animal.
Blastula is an animal embryo or egg at the early stage an early stage of development when the cells are still in the shape of balls.
Germ layers: the formation of the embryonic tissue
During the gastrulation process, three germ layers are formed
1) Endoderm: the inner most layer
2) Mesoderm: Middle layer
3) Ectoderm: outermost layer
Cells that are tightly attached to each other via junctions will move as cell sheets
Invagination – Cell sheet dents inward
Involution – Cell sheet rolls inward
Delamination – Cell sheet splits in two
Ingression – Cells break away from cell sheet and migrate as individual cells
Archenteron- or embryonic gut/digestive cavity of the embrayo which eventually becomes the digestive tract
Blastoderm: is a single layer of embryonic tissue that later develops to the blastula and divides into the three germ layers from which the embrayo develops
Two species of frogs belonging to the same genus occasionally mate, but the offspring fail to develop and hatch. What is the mechanism for keeping the two frog species separate?
A) the postzygotic barrier called hybrid inviability
B) the postzygotic barrier called hybrid breakdown
C) the prezygotic barrier called hybrid sterility
D) gametic isolation
Answer:D
Gametic isolation is a type of prezygotic barrier where the gametes (egg and sperm) come into contact, but no fertilization takes place. Gametes may be unable to recognize one another in different species.
The phylum Cycliophora was discovered in 1995. They are tiny organisms that live in large numbers on the outsides of the mouthparts and appendages of lobsters. The feeding stage permanently attaches to the lobster via an adhesive disk and collects scraps of food from its host's feeding by capturing the scraps in a current created by a ring of cilia. The body is saclike and has a U-shaped intestine that brings the anus close to the mouth. Cycliophorans are coelomates, do not molt (though their host does), and their embryos undergo spiral cleavage. Basing your inferences on information in the paragraph, to which clades should cycliophorans belong?
A) Eumetazoa and BilateriaB) Eumetazoa and LophotrochozoaC) Deuterostomia and EcdysozoaD) Deuterostomia and Lophotrochozoa
Answer:
The answer is letter B. Eumetazoa and Lophotrochozoa
Explanation:
Eumetazoa and Lophotrochozoa
Because the phylum Cycliophora neither helps or harms its lobster host.
Your objective is to design an observational study to help answer the question_______.What was the determining factor for areas that escaped the worst impacts of the fire, compared to areas that were severely burned?
The life-threatening food allergy reaction of anaphylactic shock is most often caused by: a. almonds, yeast breads and oranges. b. tomatoes, yeast breads and bananas. c. peanuts, milk and shellfish. d. soy, fish and strawberries.
Anaphylactic shock, a severe and life-threatening allergic reaction, is most often caused by peanuts, milk, and shellfish.
Explanation:Anaphylactic shock is a life-threatening allergic reaction that can occur when a person with a food allergy is exposed to the allergen. The most common food allergens that can trigger anaphylaxis are peanuts, milk, and shellfish. These foods contain proteins that can elicit an immune response in individuals with allergies, leading to symptoms such as difficulty breathing, rapid pulse, and decreased blood pressure.
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Anaphylactic shock is most often caused by peanuts, milk, and shellfish, triggering a rapid immune response and severe symptoms. Epinephrine is used to counteract the effects of anaphylaxis.
Explanation:Anaphylactic shock, a life-threatening food allergy reaction, is most often caused by peanuts, milk, and shellfish.
When an individual with a severe allergy consumes or comes into contact with these allergens, it triggers a rapid immune response. This immune response leads to the release of histamine and other chemicals, causing symptoms such as swelling, difficulty breathing, and a drop in blood pressure.
Epinephrine is used to counteract the effects of anaphylaxis and can be life-saving. It is important for individuals with known severe allergies to carry automatic epinephrine injectors at all times.
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