Answer:
[tex](6g)(11g)=\bigg((6)(11)\bigg)(gg)=66g^2[/tex]
Graph the functions on the same coordinate axis. {f(x)=−2x+1g(x)=x2−2x−3
What are the solutions to the system of equations?
select each answer
(2, 3)
(−2, 5)
(2, −3)
(2, 5)
(−2, −3)
Answer:
(2,-3) and (-2,5)
Step-by-step explanation:
Let us graph the two equations one by one.
1. [tex]f(x)=-2x+1[/tex]
If we compare this equation with the slope intercept form of a line which is given as
[tex]y=mx+c[/tex]
we see that m = -1 and c =1
Hence the slope of the line is -2 and the y intercept is 1. Hence one point through which it is passing is (0,1) .
Let us find another point by putting x = 1 and solving it for y
[tex]y=-2(1)+1[/tex]
[tex]y=-2+1 = -1[/tex]
Let us find another point by putting x = 2 and solving it for y
[tex]y=-2(2)+1[/tex]
[tex]y=-4+1 = -3[/tex]
Hence the another point will be (2,-3)
Let us find another point by putting x = -2 and solving it for y
[tex]y=-2(-2)+1[/tex]
[tex]y=+1 = 5[/tex]
Hence the another point will be (-2,5)
Now we have two points (0,1) ,(1,-1) , (2,-3) and (-2,5) we joint them on line to obtain our line
2.
[tex]g(x)=y=x^2-2x-3[/tex]
[tex]y=x^2-2x+1-1-3[/tex]
[tex]y=(x-1)^2-4[/tex]
[tex](y+4)=(x-1)^2[/tex]
It represents the parabola opening upward with vertices (1,-4)
Let us mark few coordinates so that we may graph the parabola.
i) x=0 ; [tex]y=y=(0)^2-2(0)-3=0-0-3=-3[/tex] ; (0,-3)
ii)x=-1 ; [tex]y=(-1)^2-2(-1)-3=1+2-3=0[/tex] ; (-1,0)
iii) x=2 ; [tex]y=(2)^2-2(2)-3 = 4-4-3 =-3[/tex] ;(2,-3)
iii) x=1 ; [tex]y=(1)^2-2(1)-3 = 1-2-3 =-4[/tex] ;(1,-4)
iii) x=-2 ; [tex]y=(-2)^2-2(-2)-3 = 4+4-3 =5[/tex] ;(-2,5)
Now we plot them on coordinate axis and line them to form our parabola
When we plot them we see that we have two coordinates (2,-3) and (-2,5) are common , on which our graphs are intersecting. These coordinates are solution to the two graphs.
Answer:
so you dont have to suffer lol heres a screenshot
Step-by-step explanation:
which function represents exponential decay?
a)y=14(0.95)^x
b)y=14(1.95)^x
c)y=14x^1.95
d)y=14/0.95
Answer:
a
Step-by-step explanation:
We are looking for an exponential function [tex]y=a(r)^x[/tex] where r is less than 1.
a works because it is in the form [tex]y=a(r)^x[/tex] where r is less than 1.
b is in the form [tex]y=a(r)^x[/tex] but r is more than 1.
c. and d. are not even exponential functions.
c. is a polynomial
d. is a constant polynomial (no variable)
does the point (3,-1) lie on the circle (x+1)^2 + (y-1)^2=16
Answer:
No.
Step-by-step explanation:
The circle of that equation lies on the point (3,1) as its furthest point to the right (x-axis) and therefore could never also lie on the point (3,-1).
Your equation is in center radius form, which is as follows:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Noting that your radius is 4 (since your radius squared is 16).
To graph your circle, simply go to your origin (h, k) which in this case is (-1, 1) and then count out in any direction (up, down, left, or right -- no diagonals) 4 units (since your radius is 4). This will give you the four outermost edges of your circle. Simply fill in the gaps from there, and you'll have sketched your circle.
No. The circle of that equation lies on the point (3,1) as its furthest point to the right (x-axis) and thus could never lie on the point (3,-1).
What is a circle?A circle is a shape consisting of all points in a plane that are given the same distance from a given point called the center.
The equation is in center radius form, which is as follows:
(x - h)² + (y - k)² = r²
the radius is 4 (since your radius squared is 16).
Substituting 3 for x and -1 for y:
(3 + 1)^2 + (-1 - 1)^2 = 16
4^2 + (-2)^2 = 16
16 + 4 = 16
20 = 16
Hence, we can see 20 is clearly not equal to 16, so we know the point (3, -1) can’t lie on that circle.
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an airplane travels 475 miles in 5 hours how far will the airplane travel in 9 hours
The airplane traveled 855 miles in 9 hours.
Based on the given conditions, formulate 9x 475-:5
Reduce the fraction to the lowest term by canceling the
greatest common factor: 9x95
Calculate the first two terms: 855
The answer is 855 miles.
What is problem-solving?Problem-solving is the act of defining a problem; figuring out the purpose of the trouble; identifying, prioritizing, and selecting alternatives for an answer; and imposing an answer.
Problem-solving starts with identifying the issue. As an example, a trainer may need to parent out a way to improve a scholar's overall performance on a writing talent test. To do that, the instructor will overview the writing exams looking for regions for improvement.
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PLEASE HELP FAST!
what is the value of tanX
A) 7/18
B 18/7
The answer is:
The value of Tan(x) is:
[tex]\frac{7}{24}[/tex]
Why?Since we want to know the value of Tan(x), we need to use the following formula:
[tex]Tan(x)=\frac{Opposite}{Adjacent(XZ)}[/tex]
We already know the opposite side, but we need to find the value of the distance "XZ",so, we can calculate it using the Pythagorean Theorem since it's a right triangle.
Let be:
[tex]a=25\\b=7[/tex]
Then, finding "XZ" we have:
[tex]a^{2}=b^{2}+c^{2}\\ \\25^{2}=7^{2}+c^{2} \\\\c^{2}=625-49\\\\c=\sqrt{576}=24[/tex]
Now, finding the value of Tan(x), we have:
[tex]Tan(x)=\frac{opposite}{adjacent}\\\\Tan(x)=\frac{7}{24}[/tex]
Hence, we have that the value of Tan(x) is:
[tex]\frac{7}{24}[/tex]
Have a nice day!
Answer:
Tan X = 7/24
Step-by-step explanation:
From the figure we can see a right angled triangle XYZ.
XY = 25 and YZ = 7
To find value of XZ
XZ² = XY² - YZ²
= 25² - 7²
= 625 - 49
= 576
XZ = √576 = 24
To find the value of X
Tan X = YZ/XZ
= 7/24
The altitude of an isosceles triangle is the same segment in the triangle as
the
A. hypotenuse
B. median
c. bisector
D. leg
B -median
Hypotenuse is only right triangles and legs are sides of a triangle. A bisector divides something in half evenly . Altitude is height of a triangle and median is the same segment
:
The altitude of an isosceles triangle is the same segment in the triangle as the bisector.
What is a bisector?The bisector is a line that divides a line or an angle into two equivalent parts. The bisector of a segment always contains the midpoint of the segment.
In an isosceles triangle,
Bisector of vertex angle = midline of base side = altitude
The altitude of an isosceles triangle is the same segment in the triangle as the bisector.
Option C is correct.
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What is the distance between the polnts (3, 2) and (15, 16) on a coordinate plane?
Answer:
C. 15 unitsStep-by-step explanation:
The formula of a distance between two points:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
We have the points (3, 7) and (15, 16). Substitute:
[tex]d=\sqrt{(15-3)^2+(16-7)^2}=\sqrt{12^2+9^2}=\sqrt{144+81}=\sqrt{225}=15[/tex]
Determine whether each triangle should be solved by beginning with the Law of Sines or the Law of Cosines. Then solve each triangle. Round measures of sides and angles to the nearest tenth after calculating. a = 8, b = 7, c = 4 Question 3 options: Law of Cosines; A ≈ 89°, B ≈ 61°, C ≈ 30° Law of Sines; A ≈ 89°, B ≈ 61°, C ≈ 30° Law of Sines; A ≈ 30°, B ≈ 61°, C ≈ 89° Law of Cosines; A ≈ 61°, B ≈ 89°, C ≈ 30°
Answer:
Law of Cosines; A ≈ 61°, B ≈ 89°, C ≈ 30°
Step-by-step explanation:
In this problem the given values are the length sides of the triangle, therefore, the triangle should be solved by beginning with the Law of Cosines
step 1
Applying the law of cosines find the value of angle C
we know that
[tex]c^{2}=a^{2}+b^{2}-2(a)(b)cos(C)[/tex]
we have
[tex]a = 8, b = 7, c = 4[/tex]
substitute the values and solve for cos(C)
[tex]4^{2}=8^{2}+7^{2}-2(8)(7)cos(C)[/tex]
[tex]16=64+49-112cos(C)[/tex]
[tex]16=113-112cos(C)[/tex]
[tex]112cos(C)=113-16[/tex]
[tex]cos(C)=97/112[/tex]
[tex]C=arccos(97/112)=30\°[/tex]
step 2
Applying the law of cosines find the value of angle B
we know that
[tex]b^{2}=a^{2}+c^{2}-2(a)(c)cos(B)[/tex]
we have
[tex]a = 8, b = 7, c = 4[/tex]
substitute the values and solve for cos(B)
[tex]7^{2}=8^{2}+4^{2}-2(8)(4)cos(B)[/tex]
[tex]49=64+16-64cos(B)[/tex]
[tex]49=80-64cos(B)[/tex]
[tex]64cos(B)=80-49[/tex]
[tex]cos(B)=31/64[/tex]
[tex]B=arccos(31/64)=61\°[/tex]
step 3
Find the measure of angle A
we know that
The sum of the interior angles of a triangle must be equal to 180 degrees
so
[tex]A+B+C=180\°[/tex]
we have
[tex]C=30\°[/tex]
[tex]B=61\°[/tex]
substitute and solve for A
[tex]A+61\°+30\°=180\°[/tex]
[tex]A+91\°=180\°[/tex]
[tex]A=180\°-91\°=89\°[/tex]
Given: m∠AEB = 45°
∠AEC is a right angle.
Prove: bisects ∠AEC.
Proof:
We are given that m∠AEB = 45° and ∠AEC is a right angle. The measure of ∠AEC is 90° by the definition of a right angle. Applying the gives m∠AEB + m∠BEC = m∠AEC. Applying the substitution property gives 45° + m∠BEC = 90°. The subtraction property can be used to find m∠BEC = 45°, so ∠BEC ≅ ∠AEB because they have the same measure. Since divides ∠AEC into two congruent angles, it is the angle bisector.
The segment bisects \AEC because \AEB and \BEC are both 45\u00b0, proven using the Angle Addition Postulate and the Subtraction Property of equality.
Explanation:To prove that the segment bisects \AEC, begin by acknowledging the given information that m\AEB = 45\u00b0 and \AEC is a right angle with a measure of 90\u00b0. According to the Angle Addition Postulate, m\AEB + m\BEC = m\AEC. Substitute the known values to get 45\u00b0 + m\BEC = 90\u00b0. Utilizing the Subtraction Property of equality allows us to solve for m\BEC, finding it to also be 45\u00b0. This means that \BEC ≅ \AEB which leads us to conclude that since they have equal measures, the segment indeed bisects \AEC.
Find the number of the different ways, for 3 students to sit on 7 seats in one row.
a. 840
b. 35
c. 210
d. 30
Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
What is the volume of a rectangular prism with a length of 2.2 cm, a width of 3.1 cm and a height of 1.2 cm
To find the volume of a rectangular prism, multiply the length by the width by the height.
Volume = 2.2 x 3.1 x 1.2 = 8.184 cm^3
All the dimensions are one decimal place, so if you round the answer to one decimal place it would be 8.2 cm^3
To find the volume of a rectangular prism, multiply the length by the width by the height.Volume = 2.2 x 3.1 x 1.2 = 8.184 cm^3All the dimensions are one decimal place, so if you round the answer to one decimal place it would be 8.2 cm^3
what is the slope of the line shown below? (4, 8) (2, 4)
Answer:
Slope = 2
Step-by-step explanation:
Slope is the change in y/change in x. So (8-4)/4-2)=2.
Answer: Using the formula below you will get -4/-2 which is slope of 2
Step-by-step explanation:
So you would use the slope formula which is y_{2}- y_{1} / x_{2}-x_{1}
Simplify this algebraic expression completely.
7x-5(x+6)
Answer:
8x+1
Step-by-step explanation:
Answer:
x=15
Step-by-step explanation:
7x−5(x+6)
=7x+(−5)(x)+(−5)(6)
=7x+−5x+−30
=7x+−5x+−30
=(7x+−5x)+(−30)
=2x+−30
-2x=-30
x=15
Piecewise defined function.
f(x) = {-x^2+2x+2 if
[tex]x \leqslant - 5[/tex]
{-3/4x+3 if
[tex]x > 1[/tex]
find what f(-5) =
Answer:
f(-5) = -33
Step-by-step explanation:
f(x) = {-x^2+2x+2 if x ≤ - 5
{-3/4x+3 if x > 1
find what f(-5) =
If x=-5, we use the first equation
f(-5) = -x^2+2x+2 since it has the equal to part
= - (-5)^2 +2(-5) +2
= -25 -10+2
= -35+2
=-33
Write (1/3i)-(-6+2/3i) as a complex number in standard form
Answer:
[tex]6+\frac{i}{3}[/tex]
Step-by-step explanation:
[tex]\frac{1}{3\imath}-(-6+\frac{2}{3\imath})[/tex]
[tex]\frac{1}{3\imath}+6-\frac{2}{3\imath}[/tex]
taking like terms together
[tex]\frac{1}{3\imath}-\frac{2}{3\imath}+6[/tex]
taking LCM
[tex]\frac{1-2}{3\imath}+6[/tex]
[tex]\frac{-1}{3\imath}+6[/tex]
taking LCM
[tex]\frac{-1+18\imath}{3\imath}[/tex]
splitting the term
[tex]\frac{-1+18\imath}{3\imath}[/tex]
splitting the term
[tex]-\frac{1}{3\imath}+\frac{18\imath}{3\imath}[/tex]
[tex]-\frac{1\times3\imath}{3\imath \times \imath}+6[/tex]
[tex]-\frac{i}{3\imath^2}+6[/tex]
we know that
[tex]\imath^2=-1[/tex]
putting this value in above equation
[tex]\frac{\imath}{3}+6[/tex]
10. What's the area of a slice of pizza from a large pizza with radius 9 inches cut into 6 slices?
A. 9π inches2
B. 13.5π inches2
C. 9 inches2
D. 54 inches2
The area of the slice of the pizza will be 13.5π square inches. So the correct answer is option B.
What is an area?The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.
Given that:-
slice of pizza from a large pizza with a radius of 9 inches cut into 6 slices
The area of the slice will be 1 / 6 th of the total area of the pizza since the pizza is cut into six parts.
Area of slice = ( 1 / 6 ) x π ( 9² )
Area of slice = 13.5π square inches.
Therefore the area of the slice of the pizza will be 13.5π square inches.
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Which of the following is equation of a line that passes through (-2,1) and (-4,-3)?
Answer:
y = 2x + 5Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
=======================================
We have the points (-2, 1) and (-4, -3). Substitute:
[tex]m=\dfrac{-3-1}{-4-(-2)}=\dfrac{-4}{-2}=2[/tex]
[tex]y=2x+b[/tex]
Put the coordinates of the point (-2, 1) to the equation:
[tex]1=2(-2)+b[/tex]
[tex]1=-4+b[/tex] add 4 to both sides
[tex]5=b\to b=5[/tex]
Finally:
[tex]y=2x+5[/tex]
A football coach is trying to decide: when a team ahead late in the game, which strategy is better?
A)
B)
C)
or D)
APEX
Answer: B
Step-by-step explanation:
graph the line with slope -2/3 passing through the point (-3,5)
Answer:
[tex]\large\boxed{y-5=-\dfrac{2}{3}(x+3)}[/tex]
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point on a line
We have the slope [tex]m=-\dfrac{2}{3}[/tex] and the point [tex](-3,\ 5)[/tex].
Substitute:
[tex]y-5=-\dfrac{2}{3}(x-(-3))\\\\y-5=-\dfrac{2}{3}(x+3)[/tex]
Jacob is solving the equation below using successive approximations.2^x-4=3^-x-2 He started from a graph where he found the solution to be between 1 and 2. Using the lower and upper bounds from the graph, Jacob did the following work for the first iteration. Step 1 Rewrite the equation so that it equals zero on one side. Step 2 Evaluate the rewritten equation at the lower and upper bounds. To find the solution that lies between 1 and 2, set these values as the lower and upper bounds while finding the solution. Step 3 Take the average of the lower and upper bounds. Step 4 Evaluate the rewritten equation at x = . Step 5 Since this value is positive, replace the previous lower bound so that the bounds are now x = and x = 2. Where did Jacob make a mistake, and what was the error?
Answer:
For plato users
D. Jacob made a mistake at step 5. He should have used x = 3/2 as the new upper bound.
Step-by-step explanation:
The mistake made by Jacob is; D: Jacob made a mistake at step 5. He should have used x=32 as the new upper bound.
How to Solve Successive Approximations?In Mathematics, successive approximation can be defined as a classical method that is used in Calculus for solving integral equations or initial value problems.
In this question, Jacob started the first iteration of successive approximation by using the lower and upper bounds of the graph. However, we can deduce that Jacob made a mistake instep 5 because he should have used x = 3/2 as the new upper bound.
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Write a decimal between 2.34 and 2.341.
[tex]\bf \begin{cases} 2.34\\ 2.341 \end{cases}\implies \begin{cases} 2.340\\ 2.341 \end{cases}\implies \begin{cases} 2.3400\\ 2.3410 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \boxed{2.3400}\rule[0.35em]{8em}{0.25pt}2.3403\rule[0.35em]{10em}{0.25pt}\boxed{2.3410}[/tex]
The reciprocal of -7 is: -7 7 -1/7 1/7
Answer: -1/7
Step-by-step explanation: The reciprocal of -7 is -1/7. Flip -7 to get the answer. -7 is the same as -7/1, so flip the numbers to find the reciprocal.
Find the slope of the line that passes through the points (-2,3) and (2,7)
Answer:
[tex]\large\boxed{\frac{1}{1}\,\text{or}\,1}[/tex]
Step-by-step explanation:
In this question, we're trying to find the slope with the given points.
To find the slope, we're going to need to sue the slope formula.
Slope formula:
[tex]\text{Slope}=\frac{y2-y1}{x2-x1}[/tex]
You would plug in the coordinates to its right spot.
Plug in -2 to x1, 3 in y1, 2 in x2, and 7 in y2.
Your equation should look like this:
[tex]\text{Slope}=\frac{7-3}{2-(-2)}[/tex]
Now, you will solve:
[tex]\text{Slope}=\frac{7-3}{2-(-2)}\\\\\text{Slope}=\frac{4}{2-(-2)}\\\\\text{Carry the minus sign over to the -2, turning it to a positive 2}\\\\\text{Slope}=\frac{4}{2+2}\\\\\text{Slope}=\frac{4}{4}\\\\\text{Divide}\\\\\text{Slope}=\frac{1}{1}=1[/tex]
When you're done solving, you should get 1.
This means that the slope of the line is 1/1 or 1
I hope this helped you out.Good luck on your academics.Have a fantastic day!Finding the slope using two points:
The formula for slope is
[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
In this case...
[tex]y_{2} =7\\y_{1} =3\\x_{2} =2\\x_{1} =-2[/tex]
^^^Plug these numbers into the formula for slope...
[tex]\frac{7-3}{2 - (-2)}[/tex]
[tex]\frac{4}{4}[/tex]
^^^This can be further simplified down to...
1
^^^This is your slope
Hope this helped!
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Martina begins a dive at sea level. She dives down 20 feet, and then rises 7 feet.
She dives again, going down 9 more feet. How far below sea level is Martina?
Answer:
22 feet below sea level
Step-by-step explanation:
If she goes down by 20 and back up by 7 the overall effect is going down by 13 and then going down 9 more feet makes it a total of 22 feet.
Answer:22
Step-by-step explanation:
-20+7-9= -22 ft, or 22 ft below sea level
Find the length of the side labeled x. Round intermediate values to the nearest tenth. Use the rounded values to calculate the next value. Round your final answer to the nearest tenth.
A. 69.4
B. 61.1
C. 57.9
D. 36.9
Answer:
Step-by-step explanation:
Givens
Tan(60) = opposite / adjacent
adjacent = 26
Cos(39) = adjacent / hypotenuse
Solution
Tan(60) = opposite (which is the height) / 26 Multiply both sides by 26
26*tan(60) = opposite Multiply the left.
tan60 = 1.732
26 * 1.732 = opposite
45.033
====================
Cos(39) = adjacent / hypotenuse
cos(39) = 0.7771
0.7771 = 45.0333 / x Multiply both sides by x
0.7771*x = 45.0333 Divide by 0.7771
x = 45.0333 / 0.7771
x = 57.94
Answer:
option C
Step-by-step explanation:
We have to find the value of x
[tex]tan\theta=\frac{perpendicular side}{base}[/tex]
[tex]tan60^{\circ}=\frac{height}{26}[/tex]
We know that [tex] tan60^{\circ}=\sqrt3[/tex]
[tex]\sqrt3=\frac{height}{26}[/tex]
[tex]height=1.732\times 26[/tex]
Where [tex]\sqrt3=1.732[/tex]
Height=45.032
Height=45.0
[tex]cos\theta=\frac{bas}{hypotenuse}[/tex]
[tex] cos 39^{\circ}=\frac{45}{x}[/tex]
[tex]0.777=\frac{45}{x}[/tex]
[tex]x=\frac{45}{0.777}[/tex]
x=57.9
Hence, option C is true.
The equation of a line is y=-2x+1. What is the equation of the line that is parallel to the first line and passes through (2,2)?
Answer:
The equation in slope-intercept form is y=-2x+6.
The equation in standard form is 2x+y=6.
The equation in point-slope form is y-2=-2(x-2).
Step-by-step explanation:
The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.
Parallel lines will have the same slope and different y-intercept.
Anyways the slope of y=-2x+1 is -2.
So the equation of our line we are looking for is -2.
So we know our equation is in the form y=-2x+b.
We must inf b using y=-2x+b with (x,y)=(2,2).
y=-2x +b with (x,y)=(2,2)
2=-2(2)+b
2=-4+b
Add 4 on both sides:
2+4=b
Simplify:
6=b
The equation is y=-2x+6.
Now it didn't say what form it wanted.
There are some forms I can give you like standard and point-slope form.
There is also general form but it is not too much different from standard form.
Standard form is ax+by=c where a,b, and c are integers if possible.
Point-slope form is y-y1=m(x-x1) where (x1,y1) is a point on the line and m is the slope.
So let's go for standard form (ax+by=c) first:
y=-2x+6
add 2x on both sides:
2x+y=6
This is standard form because it is in the form
ax+by=c.
Ok we know point (2,2) is on our line and we also know we have slope,m, is -2.
Point-slope form is
y-y1=m(x-x1)
y-2=-2(x-2)
Insert parenthesis () to make the following problem true: 3+6-2x4=19
Answer:
3+(6-2)*4=19
Step-by-step explanation:
Due to PEMDAS, it would first be required to do "6-2", which is 4.
Then, the 4 in the parenthesis is multiplied by the 4 on the outside, making 16.
Finally, 3 would be added to 16, making 19.
You graph the function f(x)=-|×|-12
in the
standard viewing window of -10 to 10. Will you be
able to see the graph? Explain.
Answer:
See attachment
Step-by-step explanation:
We want to graph [tex]f(x)=|x|-12[/tex] on the interval -10 to 10.
Let [tex]g(x)=|x|[/tex] be the parent absolute value function.
We can easily graph [tex]f(x)=|x|-12[/tex], if we use translation.
When the parent function is shifted downwards by 12 units, we obtain the graph of [tex]f(x)=|x|-12[/tex].
The parent function is a v-shaped graph with vertex at the origin.
We shift the parent function down so that its vertex is now at (0,-12) to get the graph of [tex]f(x)=|x|-12[/tex] .
See attachment for the graph of [tex]f(x)=|x|-12[/tex] on the specified interval.
Answer:
Which of the following did you include in your response?
No, you will not see the graph.
When x is 0, y is –12, which is outside the viewing window.
Because the function has been reflected, it opens down.
From x = –10 to x =10, the y-values range from –22 to –12.
Step-by-step explanation:
richard cuts a peice of wood for a project the first cut is shown and can be represented by the equation y=1/2x+2 the second cut need to be parellel to the first it will pass through the point (0,-7) identify the equation that represents richards second cut
Answer:
B)
Step-by-step explanation:
First, lets try to build the second equation, it has the general shape
[tex]y=m *x+b[/tex]
Where b is a constant (a number) and m the slope, another constant.
Using the given condition (0,-7) you can find the first constant of our second equation, just put "0" where you see "x", and put -7 where there is a "y".
That gives us that b is equals to -7.
Now we only need to know that the condition for 2 linear equations to be parallels is that their slope have to be the same or multiple between each others, this means that "m" of our second equation has to be equal to 1/2
thus, our second equation is [tex]y=\frac{1}{2}*x-7[/tex]
Another way to see this is that you can compare two linear equations y1=m1*x1 + b1, and y2=m2*x2+b2, if these two intersect in somewhere, this condition should meet:
X= (b1-b2)/(m2-m1).
If the slopes are the same, the above equation gives us an error, meaning that the linear equations are, in fact parallels.
Solve for x: x5 + x4 − 7x3 − 7x2 − 144x − 144 = 0
[tex]x^5 + x^4 - 7x^3 - 7x^2 -144x - 144 = 0 \\x^4(x+1)-7x^2(x+1)-144(x+1)=0\\(x^4-7x^2-144)(x+1)=0\\\\x+1=0\Rightarrow x=-1\\\\x^4-7x^2-144=0\\x^4-16x^2+9x^2-144=0\\x^2(x^2-16)+9(x^2-16)=0\\(x^2+9)(x^2-16)=0\\(x^2+9)(x-4)(x+4)=0\\\\x^2+9=0\vee x-4=0 \vee x+4=0\\x=4 \vee x=-4\\\\x\in\{-4,-1,4\}[/tex]
Answer:
{ -1, -3i,3i,4,-4}
Step-by-step explanation:
I'm going to try to get the Rational Root Theorem to work for us.
Since the coefficient of leading term is 1 we just need to look at the factors of the constant.
Possible rational zeros are going to be the factors of -144.
So here are some possible rational zeros: 1,2,3,4,6,8,9,12,16,18,24,36,48,72 and also the negative version of these numbers are numbers we must consider.
I'm going to see if -1 works.
(-1)^5+(-1)^4-7(-1)^3-7(-1)^2-144(-1)-144
-1 + 1 +7 -7 +144 -144=0
So -1 is a zero so x+1 is a factor. I'm going to use synthetic division to see what multiplies to x+1 that will me the initial polynomial expression we had.
-1 | 1 1 -7 -7 -144 -144
| -1 0 7 0 144
| ________ __________________
1 0 -7 0 -144 0
So the (x+1)(x^4-7x^2-144)=0
The cool thing is that other factor is a sort of quadratic in disguise. That is it becomes a quadratic if you let u=x^2. So let's do that.
u^2-7u-144=0
(u+9)(u-16)=0
u=-9 or u=16
So x^2=-9 or x^2=16.
Square rooting both sides gives us:
[tex] x= \pm 3i \text{ or } x=\pm 4 [/tex]
So the solution set is { -1, -3i,3i,4,-4}