Final answer:
The student's question involves writing programs in C++ and Python to summarize current house price, change since last month, and estimate the monthly mortgage. Example codes in both languages are provided, offering a clear and concise way to calculate and present the required financial information.
Explanation:
As a solution to the student's request, we can provide a simple program in both C++ and Python to calculate the summary of a house pricing including the current price, the change since last month, and the estimated monthly mortgage. Below are example codes for both languages:
C++ Program:
#include
#include
int main() {
int currentPrice, lastMonthsPrice;
std::cin >> currentPrice >> lastMonthsPrice;
double change = currentPrice - lastMonthsPrice;
double monthlyMortgage = (currentPrice * 0.051) / 12;
std::cout << std::fixed << std::setprecision(2);
std::cout << "Current Price: $" << currentPrice << "\n";
std::cout << "Change Since Last Month: $" << change << "\n";
std::cout << "Estimated Monthly Mortgage: $" << monthlyMortgage << std::endl;
return 0;
}
Python Program:
current_price = int(input())
last_months_price = int(input())
change = current_price - last_months_price
monthly_mortgage = (current_price * 0.051) / 12
print(f'Current Price: ${current_price:.2f}')
print(f'Change Since Last Month: ${change:.2f}')
print(f'Estimated Monthly Mortgage: ${monthly_mortgage:.2f}')
By inputting the current and last month's house prices, these programs will output a formatted summary that includes change in price and monthly mortgage estimate.
Create a class that stores an array of usable error messages. Create an OrderException class that stores one of the messages. Create an application that contains prompts for an item number and quantity. Allow for the possibility of nonnumeric entries as well as out-of-range entries and entries that do not match any of the currently available item numbers. The program should display an appropriate message if an error has occurred. If no errors exist in the entered data, compute the user’s total amount due (quantity times price each) and display it.
Answer:
Check the explanation
Explanation:
Given below is the code for the question.
import java.util.*;
public class PlaceAnOrder
{
public static void main(String[] args)
{
final int HIGHITEM = 9999;
final int HIGHQUAN = 12;
int code;
int x;
boolean found;
final int[] ITEM = {111, 222, 333, 444};
final double[] PRICE = {0.89, 1.47, 2.43, 5.99};
int item;
int quantity;
double price = 0;
double totalPrice = 0;
Scanner input = new Scanner(System.in);
try{
System.out.print("Enter Item number: ");
if(input.hasNextInt()){
item = input.nextInt();
if(item < 0)
throw new OrderException(OrderMessages.message[2]);
if(item > HIGHITEM)
throw new OrderException(OrderMessages.message[3]);
System.out.print("Enter Item quantity: ");
if(input.hasNextInt()){
quantity = input.nextInt();
if(quantity < 1)
throw new OrderException(OrderMessages.message[4]);
if(quantity > HIGHQUAN)
throw new OrderException(OrderMessages.message[5]);
found = false;
for(int i = 0; i < ITEM.length; i++){
if(ITEM[i] == item){
found = true;
totalPrice = PRICE[i] * quantity;
break;
}
}
if(!found)
throw new OrderException(OrderMessages.message[6]);
System.out.println("Total Amount due: $" + totalPrice);
}
else
throw new OrderException(OrderMessages.message[1]);
}
else
throw new OrderException(OrderMessages.message[0]);
}catch(OrderException e){
System.out.println(e.getMessage());
}
}
}
Write a method void Print(int LastNumber, int numbersPerLine) that receives two integers
lastnumber and numbersPerLine. The program should print all the numbers from 1 to lastnumber,
numbersperline each line. The last line should contain the remaining numbers.
Answer:
Code is in the attached screenshot.
Explanation:
Assumed it was written in Java based on your other question asked.
A computer supply company is located in a building with three wireless networks.
The system security team implemented a quarterly security scan and saw the following.
SSIDStateChannelLevel
Computer AreUs1connected170dbm
Computer AreUs2connected580dbm
Computer AreUs3connected375dbm
Computer AreUs4connected695dbm
Which of the following is this an example of?
A. Rogue access point
B. Near field communication
C. Jamming
D. Packet sniffing
Answer:
A. Rogue access point
Explanation:
A rogue access point is defined as a wireless access point installed on a secure network infrastructure without consent of the owner of the network or without due authorization. While this can sometimes be added by a malicious attacker, it is most commonly set up by employees with the desire to have wireless access even when there is any available.
In the question, there are three wireless networks, but on scanning, five wireless networks were found, hence they are rogue access point.
Write a function flush that takes as input a list of five cards, tests whether it is a flush (Note: straight flush is not a flush!) and return a boolean value. If the entry is anything other than five distinct cards, it should return (not print!) the message "This is not a valid poker hand".
Answer:
Explanation:
ef poker(hands):
scores = [(i, score(hand.split())) for i, hand in enumerate(hands)]
winner = sorted(scores , key=lambda x:x[1])[-1][0]
return hands[winner]
def score(hand):
ranks = '23456789TJQKA'
rcounts = {ranks.find(r): ''.join(hand).count(r) for r, _ in hand}.items()
score, ranks = zip(*sorted((cnt, rank) for rank, cnt in rcounts)[::-1])
if len(score) == 5:
if ranks[0:2] == (12, 3): #adjust if 5 high straight
ranks = (3, 2, 1, 0, -1)
straight = ranks[0] - ranks[4] == 4
flush = len({suit for _, suit in hand}) == 1
'''no pair, straight, flush, or straight flush'''
score = ([1, (3,1,1,1)], [(3,1,1,2), (5,)])[flush][straight]
return score, ranks
>>> poker(['8C TS KC 9H 4S', '7D 2S 5D 3S AC', '8C AD 8D AC 9C', '7C 5H 8D TD KS'])
'8C AD 8D AC 9C'
A developer is creating an enhancement to an application that will allow people to be related to their employer. Which data model should be used to track the data? A. Create a junction object to relate many people to many employers through master-detail relationships B. Create a lookup relationship to indicate that a person has an employer C. Create a junction object tolerate many people to many employers through lookup relationships D. Create a master-detail relationship to indicate that a person has an employer
The correct data model for tracking the relationship between people and their employers, allowing for many-to-many relationships, is to create a junction object with master-detail relationships.
Explanation:The question is asking which data model should be used to track the relationship between people and their employers in an application enhancement. The appropriate data model to use in this scenario is A. Create a junction object to relate many people to many employers through master-detail relationships. This solution allows for the creation of a many-to-many relationship between people and employers, which is necessary if employees can work for multiple employers and employers can have multiple employees.
In Salesforce, a junction object is a custom object with two master-detail relationships, and it's the standard way to handle many-to-many relationships. A lookup relationship (B. Create a lookup relationship to indicate that a person has an employer) is used for one-to-many relationships, which does not fit the requirement if an employee can have multiple employers or vice versa. Option C mentions using lookup relationships in a junction object, which is inaccurate since a junction object by definition uses master-detail relationships. D. Create a master-detail relationship to indicate that a person has an employer also does not suffice as it represents a one-to-many model. Therefore, option A is the correct choice for this enhancement.
This project is to mimic a meeting request system by checking the requesting party’s validity, and the number of people attending. Then it will make a decision as to whether the meeting can take place and display an informative message.
Display a welcome message and then ask the user to enter his/her name Display a personal welcome message by addressing the user by his/her name. Declare a constant and assign a number to it as the Conference Room capacity.
Ask the user how many people are attending the meeting. Display a meaningful message for each of the three different scenarios. The message informs the user whether he/she can have the requested room and also displays the number of people that must be excluded or that can still be invited based on the room capacity. Here are the three scenarios.
people attending are fewer than the Room Capacity
people attending are more than the Room Capacity
people attending are exactly the same as the Room Capacity
The system will keep running until the user quits (meaning all this happens in a loop)
Answer:
See explaination for the program code
Explanation:
Meeting.java
------
import java.util.Scanner;
public class Meeting {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
final int ROOM_CAPACITY = 100;
int numPeople, diff;
String name;
System.out.println("****** Meeting Organizer ******");
System.out.print("Enter your name: ");
name = input.nextLine();
System.out.println("Welcome " + name);
do{
System.out.print("\nHow many people would attend the meeting? (type 0 to quit): ");
numPeople = input.nextInt();
if(numPeople < 0)
System.out.println("Invalid input!");
else if(numPeople != 0)
{
if(numPeople > ROOM_CAPACITY)
{
diff = numPeople - ROOM_CAPACITY;
System.out.println("Sorry! The room can only accommodate " + ROOM_CAPACITY +" people. ");
System.out.println(diff + " people have to drop off");
}
else if(numPeople < ROOM_CAPACITY)
{
diff = ROOM_CAPACITY - numPeople;
System.out.println("The meeting can take place. You may still invite " + diff + " people");
}
else
{
System.out.println("The meeting can take place. The room is full");
}
}
}while(numPeople != 0);
System.out.println("Goodbye!"); }
}
output
---
****** Meeting Organizer ******
Enter your name: John
Welcome John
How many people would attend the meeting? (type 0 to quit): 40
The meeting can take place. You may still invite 60 people
How many people would attend the meeting? (type 0 to quit): 120
Sorry! The room can only accommodate 100 people.
20 people have to drop off
How many people would attend the meeting? (type 0 to quit): 100
The meeting can take place. The room is full
How many people would attend the meeting? (type 0 to quit): 0
Goodbye!
g given the signature of a function void ascendingwords(char sentence[], int size), where sentence is an array of characters(i.e. a null terminated string) and size is the amount of memory allocated for the buffer sentence. Complete the function to print the words in the sentence in an ascending order. the user needs to provide the input. for example if the sentence is Programming is Fun. then the function should print the output Fun is Programming
Answer:
// This program is written in C++ programming language
// Comments are used for explanatory purpose
// Program starts here
#include<iostream>
using namespace std;
// Function starts here
string ascendingwords(string sentence)
{
// Calculate length of input text
int len = sentence.length() - 1;
// Create a begin and end variable
int begin, end = len + 1;
// Declare and initialize an output string
string output = "";
// Perform iteration while there's still some text in the input string
while(len >= 0)
{
if(sentence[len] == ' ')
{
begin = len + 1;
while(begin != end)
output += sentence[start++];
output += ' ';
end = len;
}
len--;
}
begin = 0;
while(begin != end)
output += sentence[begin++];
return output;
}
// Main method starts here
int main()
{
// Declare string
string sentence;
// Prompt user for input
cout<<"Enter a string: ";
cin>>sentence;
cout <<ascendingwords(sentence);
return 0;
}
Which of the following is true of e-learning and computer-based training (CBT)?
a. Simulations and games are social media tools that can be used for training.
b. It is not advisable to integrate instruction text with games in e-learning and CBT.
c. Trainees can collaborate with other learners in standalone CBT.
d. E-learning includes the delivery of instruction only through a firm’s intranet, never the Internet.
e. Trainees can answer questions and choose responses in standalone CBT.
Answer:
The answer is "Option c".
Explanation:
This teaching is normally taken at the origin of machines in software-based research. It can also be installing a computer system into their computer or take the electronic training module generally sponsored by the firm's academic Online media, and the wrong option can be described as follows:
In option a, It is wrong because this tool is not used in training. In option b, It is integrated with game and e-learning, that's why it is incorrect. Option d and Options e both were wrong because it can't include delivery and standalone CBT.The true statement regarding e-learning and computer-based training (CBT) is trainees can answer questions and choose responses in standalone CBT.
Option E is the correct answer.
We have,
In standalone CBT, trainees can interact with the training program by answering questions, choosing responses, and engaging in various activities without the need for internet connectivity or external collaboration.
Standalone CBT typically includes interactive elements that allow trainees to actively participate and respond to the training materials.
Thus,
The true statement regarding e-learning and computer-based training (CBT) is trainees can answer questions and choose responses in standalone CBT.
Learn more about e-learning and CPT here:
https://brainly.com/question/30038878
#SPJ6
You have been selected to find the best client-server computing architecture for a Web-based order entry system that is being developed for L.L. Bean. Write a short memo that describes to the project manager your reason for selecting an n-tiered architecture over a two-tiered architecture. In the memo, give some idea as to what different components of the architecture you would include.
Answer:
The N-tier architecture helps to manage all the components (business layer, presentation layer, and database layer) of an application under one roof.
Explanation:
n-tier client/server architecture logically separates the user interface, database, and procedural code (business logic) into
at least three separate tiers. The business logic resides in the middle tier and may run on one or more servers. The user
interface interacts with the middle-tier by remotely invoking procedures and receiving results. The concept is similar to
the use of database procedures except the middle tier procedures are not limited to the proprietary SQL of an RDBMS.
In addition, the interface, database, and business logic are often physically distributed to run on many different machines. When an n-tier application is distributed effectively, system resources are more efficiently used and applications have better performance.
N-tier client/server is able to scale to thousands of users because it does not have the one-client, one-connection requirement of two-tier client/server.
N-tier client/server applications use middleware to funnel client connections to the database server.
N-tier client/server provides many benefits when working with relational databases. Clients connect to the middle tier
instead of the database; thus shielding the client application developer from the complexity of the database structure. In
addition, by placing the SQL code inside server processes, the client application is shielded from database changes. When changes are made to the database, the middle-tier server process must be modified, but the client applications can remain unaffected. If several client applications share the same server process, the change only needs to be made in one place.
N-tier/client server has been used to create complex applications that would be difficult, if not impossible, to create using a two-tier approach.
Functional side effects: 15) Given the following Java/C++ like code. Assuming function calls (operands) are evaluated from left-to-right, one at a time. a) What outputs are printed to the screen? int a = 4; // global variable int fun1() { a = 2; return 3; } int fun2() { return a; } void main() { int x = fun1() + fun2(); System.out.println("x = " + x); } Answer: x = b) What outputs are printed to the screen? int a = 4; // global variable int fun1() { a = 2; return 3; } int fun2() { return a; } void main() { int x = fun2() + fun1(); System.out.println("x = " + x); } Answer: x =
Answer:
a. x = 5
b. x = 7
Explanation:
a)
OUTPUT: x = 5
In the main() function, fun1() is evaluated first and it updates the value of the global variable to 2 and returns 3.
The second function returns the value of the global variable 'a' and this variable has value 2.
So,
x = 3 + 2
x = 5
b)
OUTPUT: x = 7
In the main() function, fun2() is evaluated first and it returns 4 because global variable 'a' is initialized with value 4.
The second function fun()1 will returns the value 3.
So,
x = 4 + 3
x = 7
This optically active alkene was treated with HBr with and without peroxides. One of these reactions lead to the formation of two products, one of which is not optically active. The other reaction gives a single new product that is optically active. Which of the below statements best explains the observed results
HBr adds to an optically active alkene via electrophilic addition resulting in 'Markovnikov' regioselectivity without peroxides, and via free radical addition leading to 'anti-Markovnikov' regioselectivity with peroxides, leading to the formation of a mixture that includes an optically inactive product.
The observed reactions are explained by different mechanisms by which HBr adds to an optically active alkene. In the absence of peroxides, the HBr adds through an electrophilic addition mechanism with 'Markovnikov' regioselectivity, resulting in a single optically active product. This is because the more substituent-rich carbon of the double bond preferentially receives the bromine in accordance with Markovnikov's rule.
Conversely, in the presence of peroxides, the HBr adds via a free radical mechanism resulting in 'anti-Markovnikov' regioselectivity. Here, a bromine atom attaches to the less substituted carbon forming two possible products: one optically active and one not, indicating syn and anti addition that produces both cis and trans isomers. The steps involved include radical initiation, propagation, and eventual termination.
Suppose we have an 8 block cache. Each block of the cache is one word wide. When a given program is executed, the processor reads data from the decimal addresses show below. 4, 7, 10, 11, 4, 8, 12, 7 Show the contents of the cache at the end of the above reading operations if the cache is 4-way set associative. Assume blocks will be filled starting at block position zero and the replacement policy is LRU. Use 4 or [ 4 ] to represent the contents of memory at address 4. If the block is empty, enter [ empty ].
Answer:
check the attached files below for answer.
Explanation:
Write a loop to store the letters “f” through “w” in an array named letters. Then, print the contents of the array to the screen.
Answer:
#include<iostream>
#include<conio.h>
using namespace std;
main()
{
char a[18];
int k=102;
for (int j=0; j<18; j++)
{
a[j]=k;
k=k+1;
}
cout<<"The Array of characters between f and W is Given below"<<endl;
for (int l=0;l<18;l++)
{
cout<<a[l]<<endl;
}
getch();
}
Explanation:
In this program, list of characters has been printed between f and w using for loop as per requirement. An array has been taken with name a and size 18, as there are 18 elements from f to w. As we know that ASCII code of Small f is 102 in decimal, we store that in another variable k. Start loop and assign ASCII code of each alphabet using 'k' variable to array a. After that array of assigned alphabets has been printed.
Recall that to multiply an m×n matrix by an n×k matrix requires m×n×k multiplications. The Google PageRank algorithm uses a square matrix that’s filled with non-zero entries when pages link to one another. Suppose we have m web sites cataloged: this is then an m×m matrix. Denote this matrix by P. P is then run through an iterative algorithm that takes j loops to complete (for 5 < j < 100), and each step of this loop an m×m matrix is multiplied by P.
a. mj log m
b. m^2
c. m^3
d. m^4
e. m^2j^2
f. m^2log m
Answer:
option C i.e. m^3 is the correct option.
Explanation:
The Multiplication of one m x m matrix with a different m x m matrix will take time m x m x m = m3
And given that this multiplication occurred for j iterations, therefore, the total number of multiplication will be j * m3 = jm3
Consequently, the complexity order will be jm3
Since 5< j < 100, hence j can be substituted by constant and for this reason among all the options mentioned, option C i.e. m^3 is correct.
5.5 Learning Objective: To demonstrate that the student understands the definition of Big O. To demonstrate that the student understands how to derive the function f(n) which computes how many times the key operation of an algo- rithm is performed as a function of the size of the problem. Instructions: This exercise is graded, so include your solution in your word processing document. Problem: Continuing with the previous exercise, derive a function f(n) which equates to the number of times the key operation is performed as a function of n, where n is the size of pList. State the worst case time complexity of split() in Big O notation. You do not need to formally prove it but explain your answer.
Answer:
See explaination
Explanation:
Anytime we want to compute time complexity of an algorithm with input size n denoted as T(n).
And then check growth rate of that algorithm with any large number of input n.
We have to first obtain f(n) of that algorithm .
f(n) is total execution time of algorithm in terms of n.
we want write this function with growth rate notation.
we know there are basic three notations
1. big oh(O) notation
2.theta(Θ) notation
3. big omega(Ω) notation
we want explain big oh(O) notation
Here is the formal mathematical definition of Big O.
also called asymptotic upper bound
Let T(n) and f(n) are two positive functions. We write T(n) ∊ O(f(n)), if there are positive constants c and n₀ such that
T(n) ≤ c·f(n) for all n ≥ n₀.
This graph shows a situation where all of the conditions in the definition are exist. (see attachment for graph)
c.fin) T(n) cost no
we can say
T(n) ∊ O(f(n)) means that growth rate of T(n) is not faster than f(n).
example
T(n) = n -1. Using Big O notation this can be written as T(n) ∊ O(n).
let c = 1 and n₀ = 1,
then T(n) = n - 1 ≤ 1·n when n ≥ 1.
Consider a system consisting of processes P1 , P2 , ..., Pn , each of which has a unique priority number. Write a monitor that allocates three identical printers to these processes, using the priority numbers for deciding the order of allocation.
Answer:
See explaination
Explanation:
The code
type printer = monitor
var P: array[0…2] of boolean;
X: condition;
procedure acquire (id: integer, printer-id: integer);
begin
if P[0] and P[1] and P[2] then X.wait(id)
if not P[0] then printer-id := 0;
else if not P[1] then printer-id := 1;
else printer-id := 2;
P[printer-id]:=true;
end;
procedure release (printer-id: integer)
begin
P[printer-id]:=false;
X.signal;
end;
begin
P[0] := P[1] := P[2] := false;
end ;
Note:
Monitors are implemented by using queues to keep track of the processes attempting to become active int he monitor. To be active, a monitor must obtain a lock to allow it to execute the monitor code. Processes that are blocked are put in a queue of processes waiting for an unblocking event to occur.
This solution utilizes a monitor to allocate printers to processes based on their unique priority numbers.
To allocate three identical printers to a system of processes P1, P2, ..., Pn, each of which has a unique priority number, we can utilize a monitor structure.
The monitor ensures that higher priority processes get access to the printers before lower priority ones.
Here is a pseudocode example of how such a monitor can be implemented,
In this solution, the monitor uses a condition variable printerAvailable to manage the allocation based on priorities.
The requestPrinter procedure adds processes to the priority queue and waits if no printer is available or if there is a process with a higher priority waiting.
The releasePrinter procedure increases the count of available printers and signals all waiting processes.
The highestPriority function ensures that the highest priority process gets the printer first.
Write a Python class named Rectangle constructed by a length and width. methods it should have Area()- this should return the area as a value Perimeter()- this should return the total of all the sides as a value Print()- this should print the rectangle such that "Length X Width" Should ask the user to enter the width and length
Answer:
class Rectangle:
def __init__(self, length=1, width=1):
self.length = length
self.width = width
def Area(self):
return self.length * self.width
def Perimeter(self):
return 2 * (self.length + self.width)
def Print(self):
print(str(self.length) + " X " + str(self.width))
l = float(input("Enter the length: "))
w = float(input("Enter the width: "))
a = Rectangle(l, w)
print(str(a.Area()) + " " + str(a.Perimeter()))
a.Print()
Explanation:
Create a class called Rectangle
Create its constructor, that sets the length and width
Create a method Area to calculate its area
Create a method Perimeter to calculate its perimeter
Create a Print method that prints the rectangle in the required format
Ask the user for the length and width
Create a Rectangle object
Calculate and print its area and perimeter using the methods from the class
Print the rectangle
Answer:
class Rectangle():
def __init__(self, l, w):
self.len = l
self.wi = w
def area(self):
return self.len*self.wi
def perimeter(self):
return self.len+self.len+self.wi+self.wi
def printing(self):
print('{} Lenght X Width {}'.format(self.len, self.wi))
length = int(input("enter the length "))
width = int(input("enter the width "))
newRectangle = Rectangle(length, width)
newRectangle.printing()
print("Area is: ")
print(newRectangle.area())
print("The perimeter is: ")
print(newRectangle.perimeter())
Explanation:
The class rectangle is defined with a constructor that sets the length and width
As required the three methods Area, perimeter and printing are also defined
The input function is used to prompt and receive user input for length and width of the rectangle
An object of the Rectangle class is created and initalilized with the values entered by the user for length and width
The three methods are then called to calculate and return their values
You are asked to design a system of FP numbers representation (with your own design choices), labeled Custom_FP_48, for which we have 48 bits at our disposal in order to represent a number, in analogy with the IEEE 754 prototype. You are asked to provide: a) The types for evaluating this number b) The width of representation of these numbers (upper and lower) 6 c) The maximu
Answer:
Check the explanation
Explanation:
The most significant bit is the sign bit (S), with 0 for positive numbers and 1 for negative numbers.
Normalize significand: 1.0 ? |significand| < 2.0
Always has a leading pre-binary-point 1 bit, so no need to represent it explicitly (hidden bit)
The following 9 bits represent exponent (E).(0 TO 511)
E is : actual exponent + Bias
Bias = 255;
The remaining 38 bits represents fraction (F).
Width of representation
smallest value :
Exponent: 000000001 because 000000000 is reserved
actual exponent = 1 – 255 = –254
Fraction: 000…00 \rightarrow significand = 1.0
Kindly check the attached image below to see the concluding solution to the question above.
A binary tree is full if all of its vertices have either zero or two children. Let Bn denote the number of full binary trees with n vertices.
(a) By drawing out all full binary trees with 3, 5, or 7 vertices, determine the exact values of B3, B5, and B7. Why have we left out even numbers of vertices, like B4?
(b) For general n, derive a recurrence relation for Bn.
(c) Show by induction that Bn is (2n). 2.14. You are given an array of n elements, and
Full binary trees have odd vertex count. B3=1, B5=2, B7=5.
Recurrence: Bn = B((n-1)/2)^2 for n>1, B1=1. Bn = (2^(n-1))/n proven by induction.
(a) Determining B3, B5, and B7:
B3 = 1:
There's only one full binary tree with 3 vertices:
*
/ \
* *
B5 = 2:
There are two full binary trees with 5 vertices:
* *
/ \ / \
* * * *
/ \ / \
* * * *
B7 = 5:
There are five full binary trees with 7 vertices:
* * * * *
/ \ / \ / \ / \ / \
* * * * * * * * * *
/ \ / \ / \ / \ / \
* * * * * * * * * *
/ \ / \ / \
* * * * * *
Why even numbers of vertices are left out:
Full binary trees have a unique property: they always have an odd number of vertices. This is because each non-leaf node (a node with children) contributes 2 vertices (itself and its two children), while each leaf node (a node without children) contributes 1 vertex. The root node is always a non-leaf node, and the number of leaf nodes is always one more than the number of non-leaf nodes. Therefore, the total number of vertices is always odd.
(b) Recurrence relation for Bn:
To construct a full binary tree with n vertices (where n is odd), we can start with a root node and attach two full binary subtrees to it. The left subtree will have (n-1)/2 vertices, and the right subtree will also have (n-1)/2 vertices. Since we can choose any valid full binary tree with (n-1)/2 vertices for each subtree, the total number of full binary trees with n vertices is the product of the number of full binary trees with (n-1)/2 vertices on the left and (n-1)/2 vertices on the right.
This leads to the recurrence relation:
Bn = B((n-1)/2) * B((n-1)/2) for n > 1, with B1 = 1
(c) Proof by induction that Bn = (2^(n-1))/n:
Base cases:
B1 = 1 = (2^0)/1, which holds.
B3 = 1 = (2^2)/3, which also holds.
Inductive step:
Assume the formula holds for Bk for all odd k less than or equal to n, where n is odd. We want to prove that it holds for Bn+2 as well.
Using the recurrence relation, we have:
Bn+2 = B((n+2-1)/2) * B((n+2-1)/2) = B((n+1)/2) * B((n+1)/2)
By the induction hypothesis, B((n+1)/2) = (2^((n+1)/2 - 1))/((n+1)/2). Substituting this into the equation above, we get:
Bn+2 = (2^((n+1)/2 - 1))/((n+1)/2) * (2^((n+1)/2 - 1))/((n+1)/2)
Simplifying the exponents and combining fractions, we obtain:
Bn+2 = (2^(n+1 - 2))/((n+1)/2 * (n+1)/2) = (2^(n-1))/(((n+1)^2)/4) = (4 * 2^(n-1))/(n+1)^2 = (2^(n+1))/(n+1)(n+1) = (2^(n+1))/(n+2)
Thus, the formula Bn = (2^(n-1))/n holds for Bn+2 as well, completing the induction
The probable question is in the image attached.
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Primary Key: ____________________________ [2] Please find all the functional dependencies ________________________________________________ _________________________________________________ __________________________________________________ _____________________________________________________ [3] Please find out the second normal form (in relational schema). [4] Please find out the third normal form.
Answer:
Check the explanation
Explanation:
1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.
So, the size of the primary key should be more than one.
In order to find the candidate key, let the functional dependencies be obtained.
The functional dependencies are :
Emp_ID -> Name, DeptID, Marketing, Salary
Name -> Emp_ID
DeptID -> Emp_ID
Marketing -> Emp_ID
Course_ID -> Course Name
Course_Name -> Course_ID
Date_Completed -> Course_Name
Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}
Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}
Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}
Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.
So, the candidate keys are :
{ Emp_ID, Date_Completed }
{ Name , Date_Completed }
{ DeptID, Date_Completed }
{ Marketing, Date_Completed }
Only one candidate key can be a primary key.
So, the primary key chosen be { Emp_ID, Date_Completed }..
2.
The functional dependencies are :
Emp_ID -> Name, DeptID, Marketing, Salary
Name -> Emp_ID
DeptID -> Emp_ID
Marketing -> Emp_ID
Course_ID -> Course Name
Course_Name -> Course_ID
Date_Completed -> Course_Name
3.
For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.
The first F.D. is
Emp_ID -> Name, DeptID, Marketing, Salary
Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.
So, a separate table should be made for Emp_ID -> Salary.
The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)
and R2( Emp_ID , Salary)
The following dependencies violate partial dependency as a prime attribute -> prime attribute :
Name -> Emp_ID
DeptID -> Emp_ID
Marketing -> Emp_ID
The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :
Course_ID -> Course Name
Course_Name -> Course_ID
So, no separate tables should be made.
The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.
So, a separate table is made.
The final relational schemas that follows 2NF are :
R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)
R2( Emp_ID , Salary)
R3 (Date_Completed, Course_Name, Course_ID)
For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.
The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :
Emp_ID -> Name, DeptID, Marketing
This violates the transitive property. So, no table is created.
The functional dependencies in R2 ( Emp_ID , Salary) is :
Emp_ID -> Salary
The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :
Date_Completed -> Course_Name
Course_Name -> Course_ID
Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).
So, a separate table is made with the concerned attributes.
The relational schemas which support 3NF re :
R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.
R2 ( Emp_ID , Salary) with candidate key Emp_ID.
R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.
R4 ( Course_Name, Course_ID ). with candidate keys Course_Name and Course_ID.
Which of the following is not regression test case? A. A representative sample of tests that will exercise all software functions B. Additional tests that focus on software functions that are likely to be affected by the change C. Tests that focus on the software components that have been changed D. Low-level components are combined into clusters that perform a specific software sub-function
Answer:
D. Low-level components are combined into clusters that perform a specific software sub-function
Explanation:
Normally, regression testing are done on a manual basis by simply re-executing a subset of the entire available test cases or it can be done automatically by utilizing playback tools or automated capture. Hence, from the options, a combination of low-level components into clusters that perform a specific sub-function does not align with how regression testing are done either manually or automatically.
Low-level components are combined into clusters that perform a specific software sub-function. Thus option D is correct.
What is a regression test?Regression testing is a statistical method of finding the relation between variables and is done by use of software such as functional and non-functional. It ensures that the development of the software are made by utilizing playback tools or capture.
Thus, the options, are a combination of the low-level components into the clusters that perform specific sub-functions.
Find out more information about the regression.
brainly.com/question/13676957.
Write an application for a condo owner on a Florida Beach. The owner wants an application to be able to accept the season for the rental and the amount of days of the customer wishes to rent the condo. Based on each, the application will determine a final price for the rental.
Answer:
in_season_price = 120.0
off_season_price = 70.0
price = 0
season = input("Which season you plan to rent \"IN/OFF\" season: ")
days = int(input("Enter the days you want to rent: "))
if season == "IN":
price = in_season_price * days
elif season == "OFF":
price = off_season_price * days
print("Rental price is: " + str(price))
Explanation:
Set the prices for in and off season
Ask the user to choose the season and number of days they want to stay
Depending on the user choice calculate the price, multiply the season price with the number of days
Print the total price
JAVA
Write a function that calculates a total amount of money a worker has made when given the initial salary (per month) and months worked. Every year the worker is at the job, their salary increases by $100 per month.
public static int totalPay(int initial_salary, int months){
}
Answer:
Answer provided in screenshot, not really too happy with my implementation but it works.
Explanation:
Iterate through months, handling logic for every 12 months to get the raise.
Java is a high-level, class-based, object-oriented programming language that aims to have as few implementation dependencies as feasible.
What is the coding ?public class FooCorporation {
static final double minimumWage = 8.0; // static means that can be accessed without creating an object of the class and instantiating it
static final int maxHours = 60; // final means constant = cannot be changed after declared
static double basePay=0; // initialize them to zero, at least you know your program won't throw null pointer exception if forgot to set their
//values before invoking the method
static int hoursWorked=0;
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
for (int i=1; i<=3; i++, System.out.println()){
System.out.println("For Employee Number: " + i);
System.out.println("Enter Base Pay:");
basePay = in.nextDouble();
System.out.println("Enter Hours Worked:");
hoursWorked = in.nextInt();
salaryCalculation();
}
}
public static void salaryCalculation(){
double totalSalary = 0;
if ((basePay < minimumWage) || (hoursWorked > maxHours)){
System.out.println("Error!");
}
else {
if (hoursWorked > totalSalary = basePay * 40 + 1.5*basePay*(hoursWorked - 40);
}
else {
totalSalary = basePay * hoursWorked;
}
System.out.println("Your total salary is " + totalSalary);
}
Java is a high-level, class-based, object-oriented programming language that aims to have as few implementation dependencies as feasible.
To learn more about Java refer to:
https://brainly.com/question/26642771
#SPJ2
If I asked you to design a client server application that would work as a progressive slot machine (if you don't know what that is look it up before proceeding) client server application...what three choices would you make for that, why? Is the design much different from the time synchronization server?
Answer:
Explanation:
Iterative vs Concurrent:
An iterative server handles both the association demand and the exchange engaged with the call itself. Iterative servers are genuinely straightforward and are reasonable for exchanges that don't keep going long.
Be that as it may, if the exchange takes additional time, lines can develop rapidly, when Client A beginnings an exchange with the server, Client B can't make a call until A has wrapped up.
In this way, for extensive exchanges, an alternate kind of server is required — the simultaneous server, Here, Client A has just settled an association with the server, which has then made a youngster server procedure to deal with the exchange. This permits the server to process Client B's solicitation without trusting that An's exchange will finish. Beyond what one youngster server can be begun along these lines. TCP⁄IP gives a simultaneous server program called the IMS™ Listener.
Some idea on on time synchronization is Synchronization of Clocks: Software-Based Solutions
Techniques:
1.time stamps of real-time clocks
2.message passing
3. round-trip time (local measurement)
4.Cristian’s algorithm
5.Berkeley algorithm
6.Network time protocol (Internet)
A system time server isn't something numerous entrepreneurs consider, and timekeeping is generally not a need for organize executives. In any case, legitimate system time synchronization is a fundamental piece of checking a system and settling issues inside it.
Suppose you need to organize a collection of telephone numbers for a company division. There are currently about 6,000 employees, and you know that the phone switch can handle at most 10,000 phone numbers. You expect several hundred lookups against the collection every day. Would you use an array list or a linked list to store the information
Answer:
Using an array list is preferable
Explanation:
A Linked List is an arranged collection of information of the same type in which each element is connected to the next using pointers.
An array list contains set of similar data objects stored in a well arranged memory locations under a common heading or a variable name.
Array elements can be accessed randomly using the array index and can be looked up anytime which makes it correct.Random accessing is not possible in linked list.
Answer:
I would use an array list over a linked list to store the given information from the question.
Explanation:
Let us define what an array list and linked list are
Array list: Array List and Linked List both maintains insertion order and implements List interface. Array List basically uses a dynamic array to keep or store the elements.
Linked list: Linked List internally uses a list that is doubly linked to keep or store the elements
Now,
Using an array list will be of advantage than a linked list as far as look ups are concerned. also we do have some idea about the size of information,
while a Linked list will be useful when we don't know the size of data. also retrieving the information from the array list is much more simpler than linked list as random access is possible with arrays against sequential traversal for lists.
Problem 1 (Authentication): Consider the following authentication protocol, which uses a classical cryptosystem. Alice generates a random message r, enciphers it with the key k she shares with Bob, and sends the enciphered message {r}k to Bob. Bob deciphers it, adds 1 to r, and sends {r + 1}k back to Alice. Alice deciphers the message and compares it with r. If the difference is 1, she knows that her correspondent shares the same key k and is therefore Bob. If not, she assumes that her correspondent does not share the key k and so is not Bob. Does this protocol authenticate Bob to Alice? If so, Why? Otherwise, explain why not.
Answer:
Check the explanation
Explanation:
Yes, going by the question above, the protocol validates Bob to Alice for the reason that the key is only shared between Bob and Alice as well as the number which is being sent randomly. Therefore the invader won’t be able to predict and response to that number. Because of the authentication protocol, that makes use of a classical cryptosystem thereby resulting into the possibility of an argument such that key finding is attainable via invader.
Final answer:
While the described protocol aims to authenticate Bob to Alice using a shared symmetric key, it doesn't guard against a man-in-the-middle attack wherein the attacker could intercept and relay the encrypted messages without either party knowing, thereby failing to provide foolproof authentication.
Explanation:
The proposed authentication protocol attempts to authenticate Bob to Alice by having Alice generate a random message r, encrypt it using a shared symmetric key k, and send it to Bob. Bob then decrypts the message, increments r by 1, and sends it back to Alice in encrypted form using the same key. Alice will determine the authenticity of Bob if the decrypted message equals r + 1.
This protocol assumes that only Alice and Bob share the symmetric key k and that any interception or alteration of the messages would lead to an incorrect response from a non-authentic party. However, this method does not fully protect against a man-in-the-middle attack, where an attacker could intercept the initial message from Alice, decrypt it, increment, re-encrypt using a key known to the attacker, and forward it to Bob, then doing the reverse of this process when Bob replies. This would give Alice the impression that she is communicating with Bob when in fact the attacker is relaying the messages.
Additionally, without a way to ensure that the key hasn't been compromised or a method to spot interception, such as with cryptographic hashes, the protocol does not provide a robust authentication mechanism against all potential attacks. Public key cryptography and cryptographic hash functions are examples of technologies that can improve the authentication process by enabling secure key exchanges and providing a way to verify the integrity and authenticity of a communication.
______________ are attacks that obtain access by means of remote services, such as vendor networks, employee remote access tools, and point-of sale (POS) devices. Improperly segmented network environment Malicious code or malware Insecure wireless Insecure remote access
Answer:
Viruses
Explanation:
A virus is an attack with malicious code that can affect the computer and can restrict specific things.
Which example task should a developer use a trigger rather than a workflow rule for?
A. To set the primary contact on an account record when it is saved
B. To notify an external system that a record has been modified
C. To set the name field of an expense report record to expense and the date when it is saved
D. To send an email to a hiring manager when a candidate accepts a job offer
Answer:
A. To set the primary contact on an account record when it is saved
Explanation:
After updating a Contact and then you set the Primary checkbox, the contact becomes the primary contact and this then updates the reference in the Parent Account. Triggers are used for this purpose and not workflow rule. In this case there is only one contact at a time that is set as Primary Contacts, and in the case where an Account does not have any Contacts, the first contact that is created is made the primary and the trigger sets that value in reference.
Which of the following are ways a vote thief could cast multiple votes in an online election? (check all that apply)
a. Using a DoS attack to make a legitimate vote server unavailable and direct voters to fake vote servers
b. Purchasing pass codes from people willing to sell their right to vote
c. Setting up fake vote servers to collect pass codes of voters
d. Using social engineering techniques to get pass codes from targeted voters
Answer:
All of the given options apply and are correct.
Explanation:
a) The first option is correct because the intruder can use denial-of-service attack and by flooding the site with traffic to get the voter server unavailable. Then he can direct the voters to a fraud vote server.
b) The second options correctly applies too because the thief also buys the pass codes from the people who want to sell their right to vote and this way the thief can purchase multiple pass code and cast multiple votes.
c) The hackers can set up fake vote servers and then direct the voters to these servers or websites in order to collect pass codes of voters. These pass codes can then be misused by the thief to cast multiple votes in an online election.
d) Social engineering techniques can also be used to get pass codes from certain voters. By manipulating the targeted voters psychologically they can get their pass codes to cast multiple votes illegally.
Write a SELECT statement that returns one row for each category that has products with these columns: The CategoryName column from the Categories table The count of the products in the Products table The list price of the most expensive product in the Products table Sort the result set so the category with the most products appears first.
Final answer:
A SQL SELECT statement is required to join Categories and Products tables, count the products per category, find the maximum price of products in each category, and sort by the number of products, with the highest number first.
Explanation:
The student has asked for a SELECT statement that retrieves data from two tables, namely Categories and Products. The query should result in each category listed along with the count of products in that category and the price of the most expensive product within that category. Lastly, the result should be sorted so that the category with the highest number of products appears first.
To fulfill these requirements, a SQL statement that joins the two tables on their respective category identifiers, counts the number of products, finds the maximum list price, and sorts the results by the count of products in descending order is needed.
The SELECT statement will look like this:
SELECT
Categories.CategoryName,
COUNT(Products.ProductID) AS ProductCount,
MAX(Products.ListPrice) AS MostExpensiveProduct
FROM
Categories
JOIN
Products ON Categories.CategoryID = Products.CategoryID
GROUP BY
Categories.CategoryName
ORDER BY
ProductCount DESC;