Answer:
-4.3 kgm/s
Explanation:
Impulse which the soccer ball experiences is equal to the change in momentum of a body.
It is given mathematically as:
Impulse = m*Δv = [tex]mv - mu[/tex]
Initial momentum of soccer ball = 2 kgm/s
Final momentum of the soccer ball = -2.3 kgm/s
Therefore, Impulse will be:
Impulse = [tex]-2.3 - 2[/tex]
Impulse = [tex]-4.3 kgm/s[/tex]
The impulse put on the soccer ball by the kicker is -4.3 kgm/s.
When you swim, your hands apply a force backward on the water. The reaction to this force is________
Explanation:
THERE FORE THE REACTION IS FRICTION FORCE.
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It should be pushing because when you swim you are pushing yourself
A small sphere of mass m is launched horizontally over a body of water from a height h above the water and with a launch speed v0. Determine expressions for the following in terms of m, v0, h, and g. Air resistance is negligibly small.
(a) W is the amount work done by the force of gravity on the projectile during its flight.
W =
−mgh
For a conservative force, how does the work done by the force compare to the change in potential energy associated with the force?
Answer:
a) W = m g h , b) W / U = 1
Explanation:
a) work is defined by
W = F. dy
in this case the force of gravity goes down and the displacement of the particle is down, so the two are parallel and the scalar product is reduced to the algebraic product
W = F y
strength is the weight of the body
F = m g
W = m g h
where h is the distance the body descends
b) the only force acting on the body is the weight of the work and we calculated them in part a, the potential energy is
U = m g h
to compare the two magnitudes of let's find their relationship
W / U = mgh / mgh
W / U = 1
Which part of the motor is responsible for reversing the flow of current?
Answer:
Commutator.
Explanation:
It is electrical switch and consist of cylinder. Split rings are two halves of a ring that act as a Commutator. When current in the coil is Zero and is about to change the direction.
Why do some quasars have red shifts greater than 1?
A) They are made of tachyons and thus are able to move away from us faster than the speed of light.
B) They are made of different elements than any other objects in the universe.
C) They are moving towards us, which throws off our spectrometers.
D) Einstein proved it is impossible to have a redshift greater than 1; these are all due to gravitational lensing tricking us
Answer:
D) Einstein proved it is impossible to have a redshift greater than 1; these are all due to gravitational lensing tricking us
Explanation:
By Einstein's theory of relativity the maximum value of the red shift is 1. This correspond to a case in which the observed frequency equals the emitted frequency:
[tex]z=\frac{f_e-f_o}{f_o}[/tex]
in other cases the red shift is lower than one.
Hence, the gravitational lens change the measurements of the observed frequency and because of that we calculate a greater red shift.
Hence, the answer is:
D) Einstein proved it is impossible to have a redshift greater than 1; these are all due to gravitational lensing tricking us
hope this helps!!
Calculate the Kinetic Energy when the mass of the car is 1,200kg and the speed
is 2.78 m/s.
Answer:
Kinetic energy of the car = 4637.04 J
Explanation:
Mass of the car (m) =1200 kg
speed of the car (v) = 2.78 m/sec
Kinetic energy =[tex]\frac{1}{2}mv^{2}[/tex]
Putting the values of m and v,
Hence, Kinetic Energy of the car =[tex]\frac{1}{2}1200\cdot 2.78^{2}[/tex] = 4637.04 J
The kinetic energy of a 1,200kg car traveling at a speed of 2.78 m/s is calculated using the formula KE = ½ mv², yielding a kinetic energy of 4,634.88 joules.
To calculate the kinetic energy (KE) of a car with a mass of 1,200kg traveling at a speed of 2.78 m/s, we need to use the kinetic energy formula KE = ½ mv². Plugging in the given values, we have:
KE = ½ (1,200 kg) × (2.78 m/s)²
KE = ½ × 1,200 kg × 7.7284 m²/s²
KE = 4,634.88 J
Therefore, the kinetic energy of the car is calculated to be 4,634.88 joules.
What type of bond results from the side‑on overlap of orbitals?
Answer:
A pi bond
Explanation:
A pi bond is a type of covalent bond that results from the formation of a molecular orbital by the side-to-side overlap of atomic orbitals along a plane perpendicular to a line connecting the nuclei of the atoms.
If a gas is compressed isothermally, which of the following statements is true? Energy is transferred into the gas by heat. No work is done on the gas. The temperature of the gas increases. The internal energy of the gas remains constant. None of those statements are true.
Answer:
The internal energy of the gas remains constant,
Explanation:
The isothermal process can be defined as a thermodynamic process in which the temperature of the system remains constant.In isothemal process the process of transfer of heat energy from the surrounding to the system or to the system from the surrounding takes place at constant temperature.
in isothermal process internal energy of the system remains unchanged or constant.
For ideal gas internal energy of the system depends on the temperature.
For ideal gas when it is compressed the work is done by the surrounding on the gas is positive and heat added to the system is negative .When the heat energy is absent,both temperature and internal energy increases. As it is a isothermal process and temperature remains constant the gas must transfer the positive amount of heat to the system.
Hence internal energy of the system of gas remains constant.
Final answer:
During an isothermal compression of a gas, energy is transferred into the gas by heat to maintain its constant temperature, while work is done on the gas and its internal energy remains constant.
Explanation:
When a gas is compressed isothermally, specific events related to energy take place. Isothermal processes occur at a constant temperature, implying that the thermal energy of the gas does not change. If we refer to the first law of thermodynamics, stating that the change in internal energy (\(\Delta E_{int}\)) is equal to heat added to the system (Q) minus the work done by the system (W), we can understand these events. Since the temperature remains constant during an isothermal compression, the internal energy of an ideal gas, which depends only on temperature, also remains constant (\(\Delta E_{int} = 0\)). Work is done on the gas during compression, meaning that there is a transfer of energy into the gas by way of work (W > 0).
To maintain the constant temperature, heat must be removed from the gas equal to the work done on it (Q = W), so there is effective energy transfer into the gas by heat to maintain isothermality. Therefore, the correct statement among the given options is: Energy is transferred into the gas by heat.
Which law can be used to calculate the number of moles of a contained gas?
Two identical 9.60-g metal spheres (small enough to be treated as particles) are hung from separate 500-mm strings attached to the same nail in a ceiling. Surplus electrons are added to each sphere, and then the spheres are brought in contact with each other and released. Their equilibrium position is such that each string makes a 17.0 ∘ angle with the vertical.How many surplus electrons are on each sphere?
Answer:
1.349 × 10¹² electrons
Explanation:
At equilibrium, the tension T in the string is resolved into horizontal and vertical components. Tcos17 being the vertical component and Tsin17 the horizontal component. The electrostatic force of repulsion at equilibrium, F = kq²/r² where q = excess charge on sphere and r = distance apart at equilibrium,F acts horizontally to the left and its weight, mg acts vertically downwards.
For equilibrium, sum of horizontal components = 0 and sum of horizontal components = 0. So, Tsin17 - F = 0
Tsin17 = F ⇒ Tsin17 = kq²/r² (1)
Also Tcos17 - mg = 0 ⇒ Tcos17 = mg (2)
Dividing (1) by (2), we have
Tsin17/Tcos17 = kq²/r² ÷ mg
tan17 = kq²/mgr²
q = r√(mgtan17/k)
We find r using cosine rule r = √(500² + 500² -2 × 500²cos 2 × 17) since the string and the masses form an isosceles triangle at equilibrium.
r = √(2 × 500² -2 × 500²cos34) = 500√2(1 - cos 34) = 500√2 × 0.1710 =120.89 mm = 0.1209 m
substituting m = 9.60 g = 9.6 × 10⁻³ g, k = 9 × 10⁹ Nm²/C² and r into q, we have,
q = r√(mgtan17/k)
= 0.1209 m√(9.6 × 10⁻³ g × 9.8 m/s² × tan17/9 × 10⁹ Nm²/C²)
= 0.1209 m√(28.76 × 10⁻³ N/9 × 10⁹ Nm²/C²)
= 0.1209 m√(3.195 × 10⁻¹² C²/m²)
= 0.1209 m × 1.7877 × 10⁻⁶ C/m
= 0.2161 × 10⁻⁶ C
= 2.161 × 10⁻⁷ C
To find the number of surplus electrons, n on each sphere, we divide q by e the electron charge.
So, n = q/e = 2.161 × 10⁻⁷ C ÷ 1.602 × 10⁻¹⁹ C = 0.6825 × 10¹² = 1.349 × 10¹² electrons
The number of surplus electrons on each sphere : 3.27 * 10¹²
Given data :
Mass of metal spheres = 9.60 g
length of string = 500 mm
Angle made by each string with the vertical ( ∅ ) = 17°
Determine the number of surplus electrons on each sidewe will apply the formula below
number of surplus electrons ( n ) = [tex]\frac{q}{e}[/tex] ----- ( 1 )
whereby :
Considering The forces acting on the metal spheres
Tan ∅ = [tex]\frac{q^{2} }{4\pi e_{o}mgr^{2} }[/tex] ----- ( 2 )
First step : Determine the distance between the spheres
r = 2l * sin∅
= 2 * 0.500 * sin17°
= 0.2924 m
Next step : Determine the charge on each sphere
Back to equation ( 2 )
Tan 17° = [tex]\frac{(8.99*10^{9}) * q^{2} }{(9.60 * 10^{-3})*(9.81)*(0.2924 )^{2} }[/tex]
q² = [ ( 0.3057 ) * ( 9.60 * 10⁻³ ) * ( 9.81 ) * ( 0.2924 )² ] / ( 8.99 * 10⁹ )
= 0.00246 / 8.99 * 10⁹
= 2.7364 * 10⁻¹³
Charge on each sphere ( q ) = √ ( 2.7364 * 10⁻¹³ ) = 5.23 * 10⁻⁷ C
Final step : The number of surplus electrons on each sphere
Back to equation ( 1 )
n = q / e
= ( 5.23 * 10^-7 ) / ( 1.6 * 10^-19 )
= 3.27 * 10¹²
Hence we can conclude that the number of surplus electrons on each sphere : 3.27 * 10¹².
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Two musicians are comparing their trombones. The first produces a tone that is known to be 438 hz. When the two trombones play together they produce 6 beats every 2 seconds. Which statement is true about the second trombone?
Answer:
The second trombones might produce frequency of 435 Hz or 441Hz.
Explanation:
Beat frequency is defined as number of beats produced per second and numerically equal to the difference between the frequency of super imposing waves.The sound waves interfere constructively.
Beat is the phenomena of interference.
The frequency of the resultant wave is given by
F = f₁ - f₂ eqn 1
where f₁ , f₂ are frequency of waves.
The frequency of first trombones is 438Hz, 6 beats are heard every 2 second,
Beat frequency is F = [tex]\frac{6}{2}[/tex] = 3Hz.
Substituting in eqn 1 , we get two possible solution for frequency of second trombones.
f₂ =f₁ -F = 438 -3 =435Hz
f₂ = f₁ +F = 438+3 =441 Hz.
The second trombones might produce frequency of 435 Hz or 441Hz.
How did the lab activities help you answer the lesson question: How do environmental changes affect both living and nonliving things in a watershed? What conclusions can you make based on your observations?
Answer:
In the lab activity, I used a virtual watershed to demonstrate how pollutants enter and flow through the watershed. I constructed food chains to show how biotic factors are related. I also predicted and modeled how human activity affected the biotic factors in an ecosystem. Based on my observations, I can conclude that biotic and abiotic factors are closely linked and that human activity that changes the environment, like pollution, can affect all the other parts of an ecosystem in a negative way.
Explanation:
Answer:
In the lab activity, I used a virtual watershed to demonstrate how pollutants enter and flow through the watershed. I constructed food chains to show how biotic factors are related. I also predicted and modeled how human activity affected the biotic factors in an ecosystem. Based on my observations, I can conclude that biotic and abiotic factors are closely linked and that human activity that changes the environment, like pollution, can affect all the other parts of an ecosystem in a negative way.
Your system engineer has started making negative comments during your weekly team meeting. He has had a heated argument with the marketing manager, and you have heard from various team members that he has become difficult to work with. What is the best course of action for you to take?
A. You should write a memo to the system engineer's functional manager and request a replacement as soon as possible.
B. The system engineer is critical to the project, so you should give him some slack and wait to see whether the behavior stops.
C. You should confront the system engineer openly at the next team meeting. Let him know that his behavior is unacceptable and that he will be replaced if there is not an immediate change.
D. You should schedule an individual meeting with the system engineer to determine whether he has issues with the project that need to be resolved. Get his perspective on how the project is progressing and how he feels about his role.
Answer: D. To address the issue, you need to understand what is behind the system engineer's current behavior. He may have been given additional work that you are not aware of, or he may misunderstand the project goals, to name just a couple of possibilities. The situation cannot be ignored, no matter how valuable the person is, and it should be handled in private.
Answer :
D. You should schedule an individual meeting with the system engineer to determine whether he has issues with the project that need to be resolved. Get his perspective on how the project is progressing and how he feels about his role.
A billiard ball is moving in the x-direction at 30.0 cm/s and strikes another billiard ball moving in the y-direction at 40.0 cm/s. As a result of the collision, the first ball moves at 50.0 cm/s, and the second ball stops. What is the change in kinetic energy of the system as a result of the collision
Explanation:
Given that,
Initial speed of the billiard ball 1, u = 30i cm/s
Initial speed of another billiard ball 2, u' = 40j cm/s
After the collision,
Final speed of first ball, v = 50 cm/s
Final speed of second ball, v' = 0 (as it stops)
Let us consider that both balls have same mass i.e. m
Initial kinetic energy of the system is :
[tex]K_i=\dfrac{1}{2}mu^2+\dfrac{1}{2}mu'^2\\\\K_i=\dfrac{1}{2}m(u^2+u'^2)\\\\K_i=\dfrac{1}{2}m((30)^2+(40)^2)\\\\K_i=1250m\ J[/tex]
Final kinetic energy of the system is :
[tex]K_f=\dfrac{1}{2}mv^2+\dfrac{1}{2}mv'^2\\\\K_f=\dfrac{1}{2}m(v^2+v'^2)\\\\K_f=\dfrac{1}{2}m((50)^2+(0)^2)\\\\K_f=1250m\ J[/tex]
The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :
[tex]\Delta K=K_f-K_i\\\\\Delta K=1250m-1250m\\\\\Delta K=0[/tex]
So, the change in kinetic energy of the system as a result of the collision is equal to 0.
Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructions on the box said to twist the pack until the liquids mix. Which type of energy contained in the pack is responsible for producing the heat?
Answer:
Chemical
Explanation:
Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructions on the box said to twist the pack until the liquids mix. Chemical energy contained in the pack is responsible for producing the heat.
What is chemical energy ?Chemical energy is the energy that is released when chemical substances engage in a chemical reaction and change into other substances. Batteries, food, and gas are a few examples of chemical energy storage mediums.
Chemical energy is the energy held in atom and molecule bonding. Chemical energy can be found in things like batteries, biomass, oil, natural gas, and coal. When humans burn fuel in a car's engine or wood in a fireplace, chemical energy is transformed into thermal energy.
Around the world, we generate heat and power using chemical energy. Methane, natural gas, oil, and petroleum are examples of fossil fuels that we burn to create steam that turns turbines to generate power.
Thus, Chemical energy contained in the pack is responsible for producing the heat.
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Which electromagnet is the strongest
Answer:
Picture C
Explanation:
Two blocks of masses 6 kg and 10 kg are placed on a horizontal, frictionless surface. A light spring is attached to one of them, and the blocks are pushed together with the spring between them. A cord holding them together is burned, after which the block of mass 10 kg moves to the right with a speed of 3.4 m/s. What is the velocity of the other mass in
Answer:
5.67 m/s ( towards left)
Explanation:
We are given that
[tex]m_1=6 kg[/tex]
[tex]m_2=10 kg[/tex]
Speed of mass 10 kg=3.4 m/s
We have to find the velocity of other mass.
When there is no external force applied the the linear momentum will be conserved
[tex]-m_2v_2=m_1v_2[/tex]
Substitute the values
[tex]10\times 3.4=6v_1[/tex]
[tex]v_1=-\frac{10\times 3.4}{6}[/tex]
[tex]v_1=-5.67 m/s[/tex]
The mass 6 kg moves to the left with speed 5.67 m/s.
A 3.70-mm-long, 520 kgkg steel beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 73.0 kgkg construction worker stands at the far end of the beam.What is the magnitude of the torque about the point where the beamis bolted into place?
Answer:
the magnitude of the torque about the point where the beam is bolted into place 12.32kNm
Explanation:
N/B The units given in the question are meant to be m, kg and kg respectively
Given data
Length of beam 3.7m
Mass of beam 520kg
Mass of construction worker 73kg
Torque is expressed as the moment or turning effect brought about by a couple
T= F*d
Where d=perpendicular distance
F= force
Converting The mass of the beam and the worker to force we have
520*10= 5200N
73*10=730N
Note that the force due to the mass of the beam is acting at the center of the beam
See the free body diagram attached
Taking moments about point O
Torque =Σ Fxd
Torque =5200x1.85+7x3.7
=9620+2701
=12321 Nm
=12.32kNm
What are the wavelengths of electromagnetic wave in free space that have the following frequencies?
(a) 4.00 1019 Hz
(b) 5.50 109 Hz
Explanation:
Given that,
(a) Frequency, [tex]f_1=4\times 10^{19}\ Hz[/tex]
All electromagnetic wave moves with the speed of light. It is given by :
[tex]c=f\lambda[/tex]
[tex]\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{4\times 10^{19}}\\\\\lambda_1=7.5\times 10^{-12}[/tex]
(b) Frequency, [tex]f_2=5.5\times 10^{1=9}\ Hz[/tex]
All electromagnetic wave moves with the speed of light. It is given by :
[tex]c=f\lambda[/tex]
[tex]\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{5.5\times 10^{9}}\\\\\lambda_2=0.054\ m[/tex]
Hence, this is the required solution.
Two particles, each of charge Q, are fixed at opposite corners of a square that lies in the plane of the page. A positive test charge q is placed at a third corner. If F is the magnitude of the force on the q test charge due to only one of the other charges, what is the magnitude of the net force acting on the test charge due to both of these charges?
Answer:
The magnitude of the net force is √2F.
Explanation:
Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:
[tex]F_N=\sqrt{F^{2}+F^{2}}\\\\F_N=\sqrt{2F^{2}}\\\\F_N=\sqrt{2}F[/tex]
Then, it means that the net force acting on the test charge has a magnitude of √2F.
The net force on the test charge q due to the two charges Q is calculated using vector addition and the Pythagorean theorem. Because the two forces act at a right angle, the total force is the vector sum and is equal to F√2.
Explanation:The magnitude of the net force acting on the test charge due to both of these charges can be calculated using the principles of vector addition in Physics. When a charge q is placed at the corner of a square, the forces exerted by the two charges, Q and Q, at the opposite corners are equal in magnitude but act along different directions. Because these charges are placed at a right angle with respect to charge q, the total force is the vector sum of individual forces, which results in a diagonal force directed along the line joining the charge q and the empty corner of the square. Therefore, the magnitude of the net force is given by the Pythagorean theorem, √(F^2 + F^2), which simplifies to F√2.
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Question:
PLEASE HELP! IF YOU ANSWER ALL PARTS TO MY QUESTION I WILL DO ANY 20 OF YOUR QUESTIONS AT ANY TIME!!! I WILL EVEN DO A TEST FOR YOU!
We all know the formula for work: W = FD. But what about t the work-energy theorem? This theorem involves kinetic energy, which of course is implied in the formula for work as well. (1) What is the work energy theorem? (2) Write the formula for the theorem. (3) Use the formula to answer the question: According to the work-energy theorem, between what two points does the roller coaster car do the most work? The roller coaster car has mass 20 kg.
Final answer:
The work-energy theorem states that the work done by all forces on a particle equals the change in the particle's kinetic energy, expressed as W = ΔKE = ½m( [tex]vf^2 - vi^2[/tex]). The most work is done between the points where kinetic energy changes the most.
Explanation:
The work-energy theorem states that the work done by all forces acting on a particle is equal to the change in the particle's kinetic energy. In formula form, this can be expressed as W = ΔKE, where W is the work done by the forces, and ΔKE is the change in kinetic energy, often written as ΔKE = KEf - KEi, with KEf denoting the final kinetic energy and KEi the initial kinetic energy. For a roller coaster car, the point where it does the most work is where the change in kinetic energy is greatest, typically between the top of the highest hill (where kinetic energy is lowest) and the bottom of the following descent (where kinetic energy is highest).
The formula representing the work-energy theorem is W = ΔKE = ½m( [tex]vf^2 - vi^2[/tex]), where m represents the mass of the object, vf the final velocity, and vi the initial velocity.
What color of light has the most energy?
A. Blue
B. Red
C. Green
Two objects are dropped from rest from the same height. Object A falls through a distance [tex]d_A[/tex] during a time [tex]t[/tex], and object [tex]B[/tex] falls through a distance [tex]d_B[/tex] during a time [tex]2t[/tex]. If air resistance is negligible, what is the relationship between [tex]d_A[/tex] and [tex]d_B[/tex]?
Answer is [tex]d_A=\frac{1}{4} *d_B[/tex]
Please show me how I can get the answer. Thank you.
Answer:
The answer to your question is given below
Explanation:
Since both object A and B were dropped from the same height and the air resistance is negligible, both object A and B will get to the ground at the same time.
From the question, we were told that object A falls through a distance to dA at time t and object B falls through a distance of dB at time 2t.
Remember, both objects must get to the ground at the same time..!
Let the time taken for both objects to get to the ground be t.
Time A = Time B = t
But B falls through time 2t
Therefore,
Time A = Time B = 2t
Height = 1/2gt^2
For A:
Time = 2t
dA = 1/2 x g x (2t)^2
dA = 1/2g x 4t^2
For B
Time = t
dB = 1/2 x g x t^2
Equating dA and dB
dA = dB
1/2g x 4t^2 = 1/2 x g x t^2
Cancel out 1/2, g and t^2
4 = 1
4dA = dB
Divide both side by 4
dA = 1/4 dB
What is the slit spacing of a diffraction necessary for a 600 nm light to have a first order principal maximum at 25.0°?
Explanation:
Given that,
Wavelength of light, [tex]\lambda=600\ nm=6\times 10^{-7}\ m[/tex]
Angle, [tex]\theta=25^{\circ}[/tex]
We need to find the slit spacing for diffraction. For a diffraction, the first order principal maximum is given by :
[tex]d\sin\theta=n\lambda[/tex]
n is 1 here
d is slit spacing
[tex]d=\dfrac{\lambda}{\sin\theta}\\\\d=\dfrac{6\times 10^{-7}}{\sin(25)}\\\\d=1.41\times 10^{-6}\ m\\\\d=1.41\ \mu m[/tex]
So, the slit spacing is [tex]1.41\ \mu m[/tex].
An inverted image of an object is viewed on a screen from the side facing a converging lens. An opaque card is then introduced covering only the upper half of the lens. What happens to the image on the screen?
Answer:
d) The image would be dimmer
Explanation:
When inverted image of an object is viewed on a screen from the side facing a converging lens, the
lens focuses the diverging, and blurred light rays from the distance object through refraction of the rays two times.Then the rays is converge by the double bending cl at a focal point behind the lens inorder for a sharper image to be be observed.
But when an opaque card is then introduced to cover only the upper half of the lens then the image becomes dimmer because of the reduction in the light intensity on the screen by 50%
When the opaque card should be introduced so here the image should be considered as the dimmer.
Inverted image:At the time when the inverted image should be viewed on the screen that faced the converging lens so here the lens should be focused on the diverging also there should be blurred light rays from the distance object via the refraction of the rays.
However, at the time there is the opaque card so here the image should be dimmer since there is the decrease in the light intensity by 50%/
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An archer tests various arrowheads by shooting arrows at a pumpkin
that is suspended from a tree branch by a rope, as shown to the right.
When struck head‐on by the arrow, the pumpkin swings upward on the
rope. The maximum angle θ that the rope makes with the vertical is
different for each arrowhead that the archer tests. Each arrow, including
its arrowhead, has the same mass m and is shot with the same velocity
vo toward the right.
The arrowheads are made of different materials, however, and each
behaves differently when it strikes the pumpkin, as described below.
Embedded arrow: Strikes the pumpkin and remains embedded,
while the pumpkin swings to angle θemb
Pass arrow: Passes all the way through the pumpkin and continues traveling away from the archer, while the
pumpkin swings to angle θpass
Bounce arrow: Bounces off the pumpkin back toward the archer, while the pumpkin swings to angle θbounce
(a) Rank the three angles θemb, θpass, θbounce from greatest to least in the spaces indicated below. Use “1” for the greatest
angle, “2” for the next greatest, and so on. If any two or all three angles are the same, use the same number for their
ranking.
(b) In a clear, coherent, paragraph‐length response that may also contain figures and/or equations, justify your ranking
a. The greatest angle will be bouncing, then embedded and finally the least is passing angle.
b. The Momentum is greatest when the arrow bounces and least when the arrow passes. This justify the obtained ranking of angles.
The given problem is based on the concept of momentum and angle made at various instance. Momentum is defined as an impact caused due to applied force. It is expressed as the product of mass and velocity of an object, with respect to the direction. Taking forward direction of arrow as positive then backward direction will be negative.
From the law of conservation of linear momentum, the sum of initial and final momentum should be equal.
When the arrow moves forward then bounces, it means the pumpkin will have positive momentum while arrow during bouncing will have negative energy. When the arrow is embedded in the pumpkin, both pumpkin and arrow will have same momentum. Finally, when the arrow passes through the pumpkin, it means it will have positive momentum hence pumpkin momentum is very little.
Thus we can conclude that by ranking the angles, consider that the maximum angle that the pumpkin reaches depends on the speed of the pumpkin. The greatest angle will be bouncing, then embedded and finally the least is passing angle.
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The High Speed Industrial Drill With Diameter Of 98 Cm Develops 5.85hp At 1900 Rpm. What Torque And Force Is Applied To The Drill Bit? This problem has been solved! See the answer. The high speed industrial drill with diameter of 98 cm develops 5.85hp at 1900 Rpm. What torque and force is applied to the drill bit?
Answer:
The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.
Explanation:
Given:-
- The diameter of the drill bit, d = 98 cm
- The power at which drill works, P = 5.85 hp
- The rotational speed of drill, N = 1900 rpm
Find:-
What Torque And Force Is Applied To The Drill Bit?
Solution:-
- The amount of torque (T) generated at the periphery of the cutting edges of the drilling bit when it is driven at a power of (P) horsepower at some rotational speed (N).
- The relation between these quantities is given:
T = 5252*P / N
T = 5252*5.85 / 1900
T = 16.171 Nm
- The force (F) applied at the periphery of the drill bit cutting edge at a distance of radius from the center of drill bit can be determined from the definition of Torque (T) being a cross product of the Force (F) and a moment arm (r):
T = F*r
Where, r = d / 2
F = 2T / d
F = 2*16.171 / 0.98
F = 33 N
Answer: The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.
Answer:
1) Torque = 21.934 Nm
2) force = 44.76 N
Explanation:
Power = 5.88 hp
1 hp = 746 W
Power = 5.88 x 746 = 4364.1 W
Angular speed in Rpm = 1900 rpm
But angular speed w = (2¶N)/60 rad/s
= (2 x 3.142 x 1900)/60 = 198.968 rad/s
From,
1) Power P = T x w
Where T = torque
T = P/W = 4364.1/198.968 = 21.934 Nm
2) diameter of drill = 98 cm
Radius = 98/2 = 49 cm = 49x10^-2 m
From torque T = Force x radius
Force = Torque /radius
F = 21.934/49x10^-2 = 44.76 N
A car passes the Eiffel tower driving at a constant rate of 60 km per hour. A second car, traveling at a constant rate of 75 km per hour, passes the Eiffel tower a while later and then follows the first car. It catches the first car after traveling a distance of 75 km past the Eiffel tower. How many minutes after the first car passed the Eiffel tower did the second car pass the Eiffel tower
Answer:
300 minutes.
Explanation:
Given,
Speed of car 1 = 60 Km/h
Speed of car 2 = 75 Km/h
distance travel by car 2 to catch car 1 = 75 Km
time taken to catch the car = ?
Relative velocity between the car = 75 - 60 = 15 Km/h
[tex]time = \dfrac{distance}{speed}[/tex]
[tex]time = \dfrac{75}{15}[/tex]
t = 5 hrs
t = 5 x 60 = 300 minutes.
Two cars passing a point at different speeds can be calculated using time, distance, and speed formulas.
A car passes the Eiffel Tower driving at a constant rate of 60 km per hour. A second car, traveling at a constant rate of 75 km per hour, passes the Eiffel Tower later and catches the first car after traveling 75 km past the tower.
To calculate the time difference between the two cars passing the Eiffel Tower, we can use the formula: Time = Distance / Speed. The second car passes the tower 15 minutes after the first car.
A single star in the process of forming starts by spinning slowly (while it is quite large and relatively cool.) As the star collapses under the pull of its own gravity, its size decreases. As a result, its rate of spinning:_____
a. will either increase or decrease depending on the star's temperature
b. will decrease
c. will stay the same
d. will increase
Answer:
d. will increase
Explanation:
The process is spinning is known as stellar rotation, it is the rotation of a star about it axis in an angular direction. Now, A single star in the process of forming starts by spinning slowly which is as a result of its size but as the star collapses under the pull of its own gravity, the radius of the size shrinks and reduces, then the spinning rate escalate and increases.
Choose all correct sentences a. The power (equation 8) is maximum when the value of the impedance is greater than the value of the resistance. b. Resonance occurs when ω2 = 1/ LC c. At resonance, the power is maximum and the impedance is minimum. d. At resonance, R2- LC e. The quality factor L/ C f. The quality factor Q = g. The impedance Z is always larger than the resistance R.
Answer:
Note: Check the attached image for a clearer question
From the attached image, the answers are 2,3,6,7
Explanation:
Maximum power occurs at resonance, i.e. [tex]X_{L} = X_{C}[/tex], not when impedance is greater than resistance
Resonance occurs when the Inductive reactance equals the capacitive reactance, i.e. [tex]X_{L} = X_{C}[/tex], not [tex]R^{2} = (X_{L} - X_{C} ) ^{2}[/tex]
and when, [tex]w = \frac{1}{\sqrt{LC} }[/tex]
Therefore, option B is correct
Since the formula for impedance is [tex]Z = \sqrt{R^{2} + (X_{L}-X_{C}) ^{2} }[/tex], at resonance, Z = R i.e. the impedance is minimum
At resonance, there is maximum power and minimum impedance
Thew Quality Factor, [tex]Q = \frac{w_{0}L }{R} = \frac{1}{R} \sqrt{\frac{L}{C} }[/tex]
The impedance Z is always larger than the resistance R, note that it is not stated that this condition is at Resonance, that makes it correct.
[tex]Z = \sqrt{R^{2} + X^{2} }[/tex]
Use the drop-down menus to complete the sentences. A is a seasonal wind___that blows in the opposite direction of normal winds. A wind___ is a wind that blows mainly from a single general direction. Seasonal winds that blow in the opposite direction of normal winds often cause____ in the winter.
The following sentences are completed and explained below
Explanation:
A is a seasonal wind known as monsoon wind that blows in the opposite direction of normal winds.
Prevailing winds are the wind that blows mainly from a single general direction.
Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.
The monsoon winds are seasonal winds that refers to wind systems that have a pronounced seasonal reversal of direction.
The winds that blow from single direction over a specific area of the earth is known as prevailing winds.
1. Monsoon wind: a seasonal wind that blows in the opposite direction of normal winds.
2. Prevailing wind: it is a wind that blows mainly from a single (one) general direction.
3. Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.
A wind can be defined as the natural movement of air and its constituent gases blowing in a particular with respect to a planet's surface.
Based on the location of occurrence and periodicity, winds are classified into three (3) main categories and these are:
1. Local winds: these include bora, foehn, loo, mistral, etc.
2. Secondary winds: these include mountain and valley breeze, monsoon wind, etc.
3. Primary winds: polar easterlies, trade winds, westerlies, etc.
In this exercise, you're required to complete the given sentences as follows:
Monsoon wind: a seasonal wind that blows in the opposite direction of normal winds.Prevailing wind: it is a wind that blows mainly from a single (one) general direction.During winter, droughts are typically caused by the seasonal winds that blow in the opposite direction of normal winds.Read more: https://brainly.com/question/15520014