Answer:
D. potassium and rubdium
A balloon contains 0.158 mol of gas and has a volume of 2.46 l. if an additional 0.113 mol of gas is added to the balloon (at the same temperature and pressure), what is its final volume?
Answer is: final volume is 4.21 liters.
Use Avogadro's Law (the Volume Amount Law): If the amount of gas in a container is increased, the volume increases.
The volume-amount fraction will always be the same value if the pressure and temperature remain constant.
V₁ / n₁ = V₂ / n₂.
2.46 l / 0.158 mol = V₂ / 0.271 mol.
V₂ = 4.21 l.
To find the final volume of the balloon, we can use the combined gas law equation. The initial pressure is calculated using the number of moles and volume. This pressure, along with the final number of moles, initial volume, and constant temperature, can be used to find the final volume.
Explanation:To solve this problem, we can use the combined gas law equation (P1V1/T1 = P2V2/T2) which relates the pressure, volume, and temperature of a gas. Since the temperature and pressure remain constant, we can use the equation to find the final volume. First, calculate the initial pressure by dividing the number of moles by the volume. Then substitute the initial pressure, final number of moles, and initial volume into the equation, and solve for the final volume.
Given:
N1 = 0.158 mol
N2 = 0.113 mol
V1 = 2.46 L
V2 = ?
P1 = N1/V1
Substituting the values:
P1 = 0.158 mol / 2.46 L = 0.0642 atm
Now, substitute the values into the combined gas law equation:
P1V1/T1 = P2V2/T2
Solving for V2:
V2 = (P1V1T2) / (P2T1)
Since the temperature and pressure remain constant, we can write the equation as:
V2 = (P1V1) / P2
Substituting the values:
V2 = (0.0642 atm * 2.46 L) / (0.113 mol) = 1.396 L
The final volume of the balloon is 1.396 L.
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_______ is the change of state of a substance from solid to vapor without passing through the liquid state.
#1: In the electromagnetic spectrum, which of the following types of radiation has less energy than visible light?
A. microwaves
B. ultraviolet
C. X rays
D. gamma rays
**my answer: A. microwaves
Microwaves have lower energy than visible light in the electromagnetic spectrum. Infrared radiation is used by heat-sensitive cameras to detect heat loss, and is also the type of radiation that can be felt as heat by our skin. Radio waves have the longest wavelengths and hence the lowest energy within the electromagnetic spectrum.
The answer to the question 'which of the following types of radiation has less energy than visible light?' is A. microwaves. Microwaves are part of the electromagnetic spectrum with longer wavelengths and thus lower energy than visible light. In contrast, ultraviolet (B), X-rays (C), and gamma rays (D) all have shorter wavelengths and higher energy than visible light. The electromagnetic spectrum ranges from radio waves, which have the longest wavelengths and lowest energy, to gamma rays, which have the shortest wavelengths and highest energy. Microwaves are in between these two extremes but still have lower energy compared to visible light.
Answering question 3, the waves used to show heat loss with heat sensitive cameras are A- Infrared radiation. Infrared waves are emitted as heat by objects and can be detected by thermal cameras to show heat patterns.
For question 4, the rays that can be felt as heat are B- Infrared Radiation. These are the same waves that are commonly used in heat sensing devices and contribute to the natural warmth felt from sunlight.
Question 2 asks about electromagnetic waves with the longest wavelengths; the answer here is D- radio waves. They are at the opposite end of the spectrum compared to gamma rays, with the lowest frequencies and energy levels.
Which is an advantage of using chemical indicators?
A. They are inexpensive to use.
B. They have very limited use.
C. They require the use of electricity.
D. They change color at specific temperatures.,
Answer: The answer is A....... they are inexpensive to use
Explanation: got it right on Edge
When writing 6,020,000 in scientific notation, it is correctly written as: 6.02 x 106 6.02 x 10-6 602. x 106 0.602 x 10-8
6.02 x 10^6 is correct it's not negative because youre moving in the positive direction in terms of sci not.
The mass of an object is found by _____.
comparison with standard mass units
weighing the object
displacing water
measuring the object
that's the answer comparison with standard mass units
Hello!
comparison with standard mass units
is your answer
Who wants a metal?
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
Both have the same molar mass.
Both have the same number of ions.
Both are made up of 6.02 x 10^23 molecules.
Both are made up of 6.02 x 10^23 formula units.,
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
A. Both have the same molar mass.
B. Both have the same number of ions.
C. Both are made up of 6.02 mc014-1 1023 molecules.
D. Both are made up of 6.02 mc014-2 1023 formula units.
The correct answer on E.D.G is ---Both are made up of 6.02 mc014-2 1023 formula units. D
Answer: Option (d) is the correct answer.
Explanation:
A formula unit is basically empirical formula of a compound which tells us how many atoms of one element are combining with how many atoms of another element.
For example, empirical formula of sodium chloride is NaCl. So, basically it shows that one atom of sodium is reacting with one atom of chlorine.
Also according to Avogadro, there are [tex]6.022 \times 10^{23}[/tex] atoms present in 1 mole of each substance.
Thus, we can conclude that both are made up of [tex]6.022 \times 10^{23}[/tex] formula units best compares 1 mol of sodium chloride to 1 mol of aluminum chloride.
Consider the following reaction. 2Fe2O3 --> 4Fe + 3O2 deltaH = +824.2KJ The formation of 42.0 g of O2 results in? 1) the absorption of 361 kJ of heat. 2) the absorption of 11500 kJ of heat. 3) the absorption of 1080 kJ of heat.
The formation of oxygen in the reaction, the absorption of 361 kJ of heat takes place.
The heat of formation of oxygen will be
[tex]\rm \Delta H[/tex] is +824.2 kJ.
The positive sign of H denotes that the reaction accepts energy from the surroundings. It is an endothermic reaction.
In the reaction the % formation of Oxygen is :
Total product formed = 7 moles
Oxygen formed = 3 moles
% Oxygen formed = [tex]\rm \frac{3}{7}\;\times\;100[/tex]
% oxygen formed = 42.85 %
The total enthalpy for the formation of product is +824.2 kJ.
The enthalpy for the formation of 42.85 % Oxygen = +824.2 [tex]\times[/tex] 42.85 / 100 kJ.
The enthalpy of the formation of oxygen in the reaction will be 353.22 kJ.
The closest is 361 kJ.
So, for the formation of oxygen in the reaction, the absorption of 361 kJ of heat takes place.
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Covalent bonds form between hydrogen and oxygen atoms in a water molecule as a result of:
Based on the entries in the following table, which element is most commonly bonded to the acidic hydrogen? table some weak acids in water at 25 ∘c
Final answer:
Hydrogen bonding in acids, solvation energy terms, and the impact of strong acids on conjugate bases are crucial concepts in understanding acid dissociation and acid-base behavior in solution.
Explanation:
Hydrogen bonding occurs when a hydrogen atom, part of a polar covalent bond, is bonded to a more electronegative atom. In the case of acids, hydrogen bonds form between the hydrogen atom of the acid (H-A) and water molecules. This results in the acid dissociation process, where the acid molecule becomes an anion.
Solvation energy terms play a crucial role in driving hydrogen ion transfer in solution. Despite thermodynamic considerations indicating that most strong Brønsted acids should not act as acids towards water, solvation energy terms, aided by entropic effects, drive hydrogen ion transfer in solution.
In general, strong acids form very weak conjugate bases, while weak acids form stronger conjugate bases. Water has a leveling effect on dissolved acids, generating hydronium and hydroxide ions, the strongest acid and base in water.
If 3.0 moles of x and 4.0 moles of y react according to the hypothetical reaction below, how many moles of the excess reactant will be left over at the end of the reaction? x + 2 y yields xy2
For which of the following reactions is ΔH∘rxn equal to ΔH∘f of the product(s)?
You do not need to look up any values to answer this question.
Check all that apply.
Check all that apply.
C(s,graphite)+O2(g)→CO2(g)
Li(s)+12F2(l)→LiF(s)
CO(g)+12O2(g)→CO2(g)
BaCO3(s)→BaO(s)+CO2(g)
2Li(s)+F2(g)→2LiF(s)
Li(s)+12F2(g)→LiF(s)
inal answer:
The reaction C(s, graphite) + O2(g) → CO2(g) is the one where ΔH°rxn equals the ΔH°f of the product, CO2(g), because it forms carbon dioxide from its constituent elements in their standard states. Option A
Explanation:
For an element or compound, the enthalpy change (ΔH) of a reaction that forms it from its elements in their standard states is called the standard enthalpy of formation (ΔH°f).
Therefore, ΔH°rxn is equal to ΔH°f for a reaction that produces a compound directly from its constituent elements in their most stable forms at 1 atm pressure and 25°C (298 K). Examining the provided reactions, the one that fits this description is:
C(s, graphite) + O2(g) → CO2(g)
This reaction forms carbon dioxide (CO2) directly from its elements, carbon in the form of graphite (the most stable form of carbon at standard conditions) and oxygen gas, both of which are in their standard states. Thus, ΔH°rxn for this reaction is equivalent to the ΔH°f of carbon dioxide.
Other reactions listed may be formation reactions, but they introduce compounds like fluorine in liquid form (F2(l)), which is not the standard state of fluorine at 25°C; hence, they do not meet the criteria. Option A
I need Chemistry help (Connections Unit 6 Lesson 3)
1. A sample of gold (Au) has a mass of 35.12 g.
a. Calculate the number of moles of gold (Au) in the sample and record in
Table 1. Show your work.
b. Calculate the number of atoms of gold (Au) in the sample and record
in Table 1. Show your work.
2. A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.
a. Calculate the number of moles of C12H22O11 contained in the sample
and record in Table 1. Show your work.
Answer:
For 1a: The number of moles of gold are 0.178 moles.
For 1b: There are [tex]1.071\times 10^{23}[/tex] atoms of gold.
For 2: The number of moles of [tex]C_{12}H_{22}O_{11}[/tex] are 0.0035 moles.
Explanation:
To calculate the number of moles, we use the following formula:
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
For 1a:We are given:
Given mass of Au = 35.12g
Molar mass of Au = 196.97 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of Gold}=\frac{35.12g}{196.97g/mol}=0.178moles[/tex]
Hence, the number of moles of gold are 0.178 moles.
For 1b:To calculate the number of atoms in 0.178 moles of gold, we follow mole concept.
According to mole concept:
1 mole of an element contains [tex]6.022\times 10^{23}[/tex] number of atoms.
So, 0.178 moles of gold will contain [tex]0.178\times 6.022\times 10^{23}=1.071\times 10^{23}[/tex] atoms.
Hence, there are [tex]1.071\times 10^{23}[/tex] atoms of gold.
For 2:We are given:
Given mass of [tex]C_{12}H_{22}O_{11}[/tex] = 1.202g
Molar mass of [tex]C_{12}H_{22}O_{11}[/tex] = 342 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of }C_{12}H_{22}O_{11}=\frac{1.202g}{342g/mol}=0.0035moles[/tex]
Hence, the number of moles of [tex]C_{12}H_{22}O_{11}[/tex] are 0.0035 moles.
in the reaction mg(s)+2hcl(aq)→mgcl2(aq)+h2(g) + MgCl2 (aq) how many grams of hydrogen gas will be produced from 125.0 milliliters of a 6.0 M HCI in an excess of Mg
0.756g
Explanation:I am assuming that 6.0MHCl is a typo, and that it should be 6.0molL−1HCl , since that makes sense in the equation.
First we have to find the amount of HCl in the solution. We use the formula n=cV where n is the amount of substance in moles, c is the concentration of the solution in moles per liter, and V is the volume of the substance in liters.
n(HCl)=6.0molL−1×0.125L=0.75mol
Then we find out how many moles of hydrogen gas (H2 ) are produced. In the formula we see 2HCl , and H2 . This means there is 1 mole of H2 for every 2 moles of HCl so to find the amount of H2 we use:
n(H2)=12×0.75mol=0.375mol
Now we find the molar mass of the H2 molecules, by adding together the atomic weights of the constituent molecules. In this case: 1.008+1.008=2.016 . Then we use the formula m=nM where m is the mass of the substance in grams, and M is the molar mass of the substance in grams per mole.
m(H2)=0.375mol×2.016gmol−1=0.756g
Among teenagers, what is the most commonly used substance?
what is this ch3ch2ch2ch2ch2ch3 ???
CH3CH2CH2CH2CH2CH3 represents Hexane, a chemical compound in the alkane family, which are hydrocarbons with only single bonds. Hexane has six carbon atoms and 14 hydrogen atoms.
Explanation:The formula CH3CH2CH2CH2CH2CH3 represents a compound called Hexane. It follows a chain structure with six carbon atoms and 14 hydrogen atoms. The prefix 'hex-' denotes six, indicating six carbon atoms, and '-ane' denotes a single bond between the carbon atoms. The molecule is classified as an alkane, a member of a group of hydrocarbons (compounds made up of hydrogen and carbon) in which there are only single bonds. Alkanes are also known as saturated hydrocarbons.
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What characteristic property did arrhenius attribute to acids and bases?
Word equation for Cu(s)+O2(g)=CuO(s)
Answer:
Copper solid plus oxygen gas giving solid cupric oxide
Explanation:
The given reaction is:
[tex]Cu(s) +O2(g)\rightarrow CuO(s)[/tex]
The balanced equation is:
[tex]2Cu(s) +O2(g)\rightarrow 2CuO(s)[/tex]
The formula name of the reactants and products are:
Cu (s) = copper in the solid phase
O2 (g) = oxygen in the gas phase
CuO (s) = copper (II) oxide or cupric oxide
The word equation would be:
Copper solid plus oxygen gas giving solid cupric oxide
Word equations are the representation of the element names in the place of symbols. Copper (s) + Oxygen (g) → Cupric oxide (s) is the word equation for Cu(s) + O₂(g) → CuO(s).
What is a word equation?The reaction in which the molecules are added to give one or more compounds and also undergoes increases in oxidation number of the species are called oxidative addition reaction.
The chemical reaction given is,
[tex]\rm Cu (s) + O_{2} (g) \rightarrow CuO(s)[/tex]
The equation can be balanced as:
[tex]\rm 2Cu (s) + O_{2} (g) \rightarrow 2CuO(s)[/tex]
The word or the chemical names of the reactants and products are given as:
Cu (s) = copper (solid phase)
[tex]\rm O_{2} (g)[/tex] = oxygen (gas phase)
CuO (s) = cupric oxide or copper (II) oxide
Inserting the chemical names in the reaction:
[tex]\rm Copper (s)+ Oxygen (g) \rightarrow \rm Cupric\; oxide (s)[/tex]
Therefore, [tex]\rm Copper (s)+ Oxygen (g) \rightarrow \rm Cupric\; oxide (s)[/tex] is the word equation.
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What is the difference between anthropocentrism and biocentric views of the environment
Explanation:
Biocentrism is the thought of considering all the living beings in the bio diversity and the nature to be the main source and aims at the well being of all as a whole.
While anthropocentrism or homocentrism or sometimes called as altruistic is the philosophical thought that human beings are the most significant or important entities in this world and all should strive for the over all development in the interest of the humans.
Biocentric is more life centered while anthropocentrism is more human centered.
why are more massive atoms smaller?
Can someone help me please?
If 75.0 g of silderite ore (FeCO3) is heated with an excess of oxygen, 45.0 g of ferric oxide (Fe2O3) is produced.
4feCO3(s) + O2(g) -> 2fe2O3(s) + 4CO2(g)
what is the percent of yield of this reaction?,
A mothball, composed of naphthalene (c10h8), has a mass of 1.64 g . part a how many naphthalene molecules does it contain?
Which best describes the reducing agent in the reaction below?
Cl2(aq)+2Br-(aq)-------->2Cl-(aq)+Br2(aq)
A.Bromine (Br) loses an electron, so it is the reducing agent.
B.Bromine (Br) gains an electron, so it is the reducing agent.
C.Chlorine (Cl) loses an electron, so it is the reducing agent.
D.Chlorine (Cl) gains an electron, so it is the reducing agent.
Answer:
A on edg is the correct answer
Explanation:
SHOW WORK!!!!!!!
a) how many meters are there in 5 kilometers.
b) Find the number of milligrams in 0.5 kilograms.
c) Convert 5 meters to kilometers.
d) Find the number of millimeters in 6.98 centimeters.
e) how many meters are equal to 2700. millimeters.
If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, which of these choices shows a hydrogen bond?
-O...H-C-
-N...H-O-
-C...H-F-
H-H
The correct option that shows a hydrogen bond is -N...H-O-, as it fits the criterion of hydrogen being covalently bonded to a highly electronegative atom (N) and attracted to a lone pair on another electronegative atom (O) in a neighboring molecule.
Explanation:If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, the choice that shows a hydrogen bond is -N...H-O-. This is because hydrogen bonds are a type of dipole-dipole interaction that occurs when a hydrogen atom is covalently bonded to a highly electronegative atom, such as nitrogen (N), oxygen (O), or fluorine (F), and is attracted to a lone pair of electrons on an atom in a neighboring molecule.
Hydrogen bonds are particularly strong among dipole-dipole interactions, although they are much weaker compared to a covalent bond. Therefore, the correct answer is the one where hydrogen is bonded to nitrogen (which is highly electronegative) and is attracted to oxygen from another molecule, hence forming a hydrogen bond.
what astronomical equiptment did hypatia use?
What's the difference between cracking and pyrolysis? (in organic chemistry).,
what type of rock is sandstone
Sandstone is a type of sedimentary rock. It is formed when sand particles are compacted and cemented together over time. These processes typically occur in sedimentary basins where sand accumulates through various natural actions such as water or wind transportation.
Sandstone forms through a geological process known as lithification. Initially, sand grains are deposited in a variety of earth environments, such as beaches, deserts, or the beds of rivers and oceans. Over time, these grains become buried under layers of more sediment. As the sediment builds up, the weight from the layers above exerts pressure, causing the sand grains to compact tightly. Meanwhile, minerals like silica or calcite present in the water flowing through the spaces between the grains can act as a natural cement, binding the particles together to form a solid rock. Thus, the unique characteristics of sandstone reflect the conditions in which it formed, including the size and composition of the sand grains, and the nature of the cement. Sandstones are particularly noteworthy as they can also serve as reservoirs for water, oil, and gas due to their porosity and permeability.
0 ml of a 1.20 m solution is diluted to a total volume of 228 ml. a 114-ml portion of that solution is diluted by adding 111 ml of water. what is the final concentration? assume the volumes are additive.
The final concentration of the solution after the described dilution process is approximately 0.00855 M.
Let's first ascertain the original dilution's concentration. Using the dilution equation:
[tex]C_1V_1 = C_2V_2[/tex]Where:
C₁ = 1.20 M (initial concentration)V₁ = 0 mlV₂ = 228 mlC₂ = final concentration after the first dilutionSince 0 ml is a typo, let us assume the starting volume V₁ is enough such as 1 mL. Plugging in the values:
(1.20 M)(1 ml) = (C₂)(228 ml)C₂ = 1.20 / 228Now, calculate the concentration after the second dilution:
V₁ = 114 mlV₂ = 114 ml + 111 ml = 225 mlUsing the intermediate solution:
[tex]C_1V_1 = C_2V_2[/tex]
The final concentration after the second dilution is about 0.00855 M.
Write a formula for the compound that forms from potassium and chromate.
The formula for the compound that forms from potassium and chromate is K2CrO4, and the balanced equation for its dissolution in water is K2CrO4(s) → 2K+(aq) + CrO42-(aq) with the solubility product expression as Ksp = [K+]2 × [CrO42-].
Explanation:The compound that forms from potassium and chromate has the formula K2CrO4. When this compound dissolves in water, it dissociates into ions. The balanced chemical equation representing the dissolution of potassium chromate is:
K2CrO4(s) → 2K+(aq) + CrO42-(aq)
The solubility product expression (Ksp) for this dissolution can be written as follows:
Ksp = [K+]2 × [CrO42-]
The relationship signifies the product of the squared concentration of potassium ions and the concentration of chromate ions is constant at a given temperature. This equilibrium expression is vital in predicting the solubility behavior of the compound in aqueous environments, guiding our understanding of its potential to form precipitates based on ion concentrations in solution.
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