Solids,liquids,and gases are three forms of matter that?

Answers

Answer 1
There are 3

Matter can exist in one of three main states: solid, liquid, or gas.
Solid matter is composed of tightly packed particles. ...
Liquid matter is made of more loosely packed particles. ...
Gaseous matter is composed of particles packed so loosely that it has neither a defined shape nor a defined volume.
Answer 2
Solids are composed tightly
Liquids are composed a little more loose
And gases are loose

Related Questions

you push a 560 mm radius bicycle wheel, which is approximately hoop shaped, along a flat region until it reaches a speed of 5.01 m/s. It then goes up a smooth hill of irregular shape and height 0.6 m before falling off the vertical face on the opposite side.

What is its speed at the top of the hill?

Answers

Answer:

The speed at the top of the hill is 4.38 m/s

Explanation:

Here we have total Kinetic = KE (translational) +KE (rotational)

=0.5 m v² + 0.5m·r²v²/r² = m·v²

Therefore at height 0.6 m we have

0.6 mg = mv²

When v = 5.01 m/s maximum height is

m·g·h=m·5.01²

or h = 2.56 m

Therefore at 0.6 m we have 2.56 - 0.6 more height energy to climb

which gives

1.96·m·g = m v₂²

or v₂² = 19.22

v₂ = 4.38 m/s.

Two balls collide with each other. Ball 1 experiences a high acceleration as a result of the collision, while Ball 2 experiences a small acceleration. What can you conclude about Ball 2?

Answers

Answer:

We conclude that ball 2 has a larger mass.

Explanation:

This is because the internal forces at collision are an action reaction pair. The force on ball 1 due to ball 2 equals the force on ball 2 due to ball 1. Since these forces are equal in magnitude, let's denote it by F. So

For each ball, F = ma and a = F/m. Since F is the same for both balls, if follows that the acceleration of each ball is inversely proportional to its mass. That is, a ∝ 1/m.

Since ball 1 has a higher acceleration, it has a lower mass. Also ball 2 has a small acceleration, so it has a higher mass.

Answer:

See explanation

Explanation:

Solution:-

- Denote the following:

  mass of ball 1 = m1

  initial velocity of ball 1 = vi,1

  Final velocity of ball 1 = vf,1

  mass of ball 2 = m2

  initial velocity of ball 2 = vi,2

  Final velocity of ball 2 = vf,2

- Since there are no external forces acting on the system containing the two balls then we can say that the linear momentum of the system is conserved.

- The conservation of linear momentum says that the momentum before or after the collision remains conserved:

                                    Pi = Pf

Where,                        p = m*v

- The conservation of momentum for the given system:

                    m1*vi,1 + m2*vi,2 = m1*vi,1 + m2*vi,2  

- Since no information is given about the initial conditions. We will consider the internal force (F) that acts when two balls come in contact. Then apply Newton's second law of motion on both balls individually:

                                F = m*a

Where,             m: Mass of object

                        a: Acceleration of the object

- For ball 1:

                               F1 = m1*a1

- For ball 2:

                              F2 = m2*a2

Given that a1 > a2, and the the internal force that acts on both balls during collision obeys Newton's 3rd Law i.e for every action there is an equal but opposite reaction: So , F1 = F2

                             F = m1*a1

                             F = m2*a2

                             m1*a1 = m2*a2

- Since, a1 > a2 for above equation to hold true then m1 < m2. That is the mass of ball 1 is quite less compared to ball 2.

                             

A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I_1 is the moment of inertia of this object with respect to an axis passing through the center of the rod and perpendicular to it and l_2 is the moment of inertia with respect to an axis passing through one of the masses, it follows that l_1 = l_2. l_l > l_2. l_2 > l_1

Answers

Answer:[tex]I_2>I_1[/tex]

Explanation:

Given

Shape of the object is dumbbell shaped

Moment of Inertia w.r.t an axis passing through center and perpendicular to it

[tex]I_1=m(\frac{r}{2})^2+m(\frac{r}{2})^2[/tex]

[tex]I_1=\frac{mr^2}{2}[/tex]

For the axis which passes through one of the masses

[tex]I_2=mr^2[/tex]

so [tex]I_2>I_1[/tex]

A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward. If the contact time with the sidewalk is 1 800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Answer in units of N.

Answers

Correct question:

A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward. If the contact time with the sidewalk is 1/800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Answer in units of N.

Answer:

The magnitude of the average force exerted on the superball by the sidewalk is 592.8 N

Explanation:

Given;

mass of the superball, m = 57 g = 0.057 kg

initial velocity of the superball, u = 24 m/s

final velocity of the superball, v = 11  m/s

contact time with the sidewalk, t =  1 / 800 s

To determine the magnitude of the average force exerted on the superball by the sidewalk, we apply Newton's second law of motion;

F = ma

[tex]But, a = \frac{v-u}{t} \\\\Thus, F = m(\frac{v-u}{t} )\\\\F = 0.057(\frac{11-24}{1/800} )\\\\F = 0.057(\frac{-13}{1/800})\\\\F = -0.057(\frac{800*13}{1})\\\\ F = -592.8 \ N\\\\Magnitude \ of \ the \ force \ is \ 592.8 \ N[/tex]

Therefore, the magnitude of the average force exerted on the superball by the sidewalk is 592.8 N

What are characteristics that enable plants to protect themselves from herbivores include

Answers

Answer:

All of the above!

Explanation:

All of the answers are true! I hope I helped!

Two quakes of equal measurements on all scales occur in two different areas. In earth quake 1, the damage is severe but in earthquake 2, the damage is minimal. Explain some reasons why this is possible.

Answers

Answer:

See explanation

Explanation:

Depth: Earthquakes can happen anywhere from at the surface to 700 kilometers below. In general, deeper earthquakes are less damaging because their energy dissipates before it reaches the surface. So it is highly likely that the earthquake 1 was shallower than earthquake 2.

Distance from the epicenter: The epicenter is the point at the surface right above where the earthquake originates and is usually the place where the earthquake's intensity is the greatest. Plausible that earthquake 1 might have been closer to its epicenter as compared to earthquake 2.

Local geologic conditions: The nature of the ground at the surface of an earthquake can have a profound influence on the level of damage. Loose, sandy, soggy soil, like in Mexico City, can liquefy if the shaking is strong and long enough, for example. That doesn't bode well for any structures on the surface. Plausible that the area around the earthquake 1 might have poorer geologic conditions as compared to area of earthquake 2.

Technician A says that in any type of fluid coupling not equipped with a mechanical lock-up some slippage exists resulting in a difference between input and output speeds. Technician B says that in torque converter coupling phase impeller and turbine rpms match. Who is correct

Answers

Final answer:

Technician A is correct, as there is slippage between input and output speeds in fluid couplings without a mechanical lock-up. Technician B is incorrect, as the impeller and turbine rpms do not match in a torque converter coupling.

Explanation:

Technician A is correct. In any type of fluid coupling without a mechanical lock-up, there is always some slippage between the input and output speeds. This means that the output speed will be less than the input speed, resulting in a difference between them.

Technician B is incorrect. In a torque converter coupling, the impeller and turbine do not have matching rpm (revolutions per minute). The impeller rpm is higher than the turbine rpm, which allows the torque converter to efficiently transfer power from the engine to the transmission.

A light bulb produces light with frequency = 4.65 x 1014 Hz. What is the wavelength of light the bulb produces?

6.45 x 10-7 meters

1.55 x 106 meters

6.45 x 1021 meters

1.395 x 1023 meters

Answers

Answer:

6.45 x 10-7 meters

Explanation:

Taking speed of light as 300000000 m/s

We know that speed of light is product of wavelength and frequency and expressed as

s=fw

Where s represent speed, f is frequency and w is wavelength

Substituting 4.65*10^14 Hz for frequency then the wavelngth will be given by

300000000=4.65*10^14 *w

w=300000000÷4.65*10^14

w=6.451612903225*10^-7 m

Rounded off, the wavelength is 6.45 x 10-7 meters

500 kg cannon and is at rest on a horizontal, frictionless surface on a clear and sunny day. When a crazy cool 100 kg clown decided to show how the cannon works they decided to get fired horizontally from the barrel of the cannon and the cannon recoils with a speed of 5 m/s. A very inquisitive Physics student figured out how fast the clown was traveling when leaving the cannon. What value did they come up with?

Answers

Answer:

Explanation:

Given that,

Mass of cannon

M1= 500kg and initially at rest

U1 = 0m/s

Mass of clown

M2 = 100kg

so it was initial at rest before this time, therefore, U2 = 0

Recoils speed of cannon V1 =5m/s, the recoils speed is after the cannon has left the barrel.

Using construction of linear momentum

Momentum before collision is equal to momentum after collision

The initial momentum is zero since the two bodies are until at rest

And the final momentum is

M1•V1 + M2•V2

Then,

P(initial) = P(final)

0 = M1•V1 + M2•V2

0 = 500 × 5 + 100 × V2

0 = 2500 +100•V2

100•V2 = -2500

V2 = -2500/100

V2 = —25m/s

So, the final velocity of the clown is -25m/s, opposite direction of the cannon

what is electrical circuit​

Answers

Path for transmitting electric current. An electric circuit includes a device that gives energy to the charged particles constituting the current, such as battery or a generator; devices that use current, such as lamps, electric motors, or computers; and the connecting wires or transmission lines

Two blocks of masses 6 kg and 10 kg are placed on a horizontal, frictionless surface. A light spring is attached to one of them, and the blocks are pushed together with the spring between them. A cord holding them together is burned, after which the block of mass 10 kg moves to the right with a speed of 3.4 m/s. What is the velocity of the other mass in

Answers

Answer:

5.67 m/s ( towards left)

Explanation:

We are given that

[tex]m_1=6 kg[/tex]

[tex]m_2=10 kg[/tex]

Speed of mass 10 kg=3.4 m/s

We have to find the velocity of other mass.

When there is no external force applied the the linear momentum will be conserved

[tex]-m_2v_2=m_1v_2[/tex]

Substitute the values

[tex]10\times 3.4=6v_1[/tex]

[tex]v_1=-\frac{10\times 3.4}{6}[/tex]

[tex]v_1=-5.67 m/s[/tex]

The mass 6 kg moves to the left with speed 5.67 m/s.

When you swim, your hands apply a force backward on the water. The reaction to this force is________

Answers

Explanation:

THERE FORE THE REACTION IS FRICTION FORCE.

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It should be pushing because when you swim you are pushing yourself

Use the drop-down menus to complete the sentences. A is a seasonal wind___that blows in the opposite direction of normal winds. A wind___ is a wind that blows mainly from a single general direction. Seasonal winds that blow in the opposite direction of normal winds often cause____ in the winter.

Answers

The following sentences are completed and explained below

Explanation:

A is a seasonal wind known as monsoon wind that blows in the opposite direction of normal winds.

Prevailing winds are the wind that blows mainly from a single general direction.

Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.

The monsoon winds are seasonal winds that refers to wind systems that have a pronounced seasonal reversal of direction.

The winds that blow from single direction over a specific area of the earth is known as prevailing winds.

1. Monsoon wind: a seasonal wind that blows in the opposite direction of normal winds.

2. Prevailing wind: it is a wind that blows mainly from a single (one) general direction.

3. Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.

A wind can be defined as the natural movement of air and its constituent gases blowing in a particular with respect to a planet's surface.

Based on the location of occurrence and periodicity, winds are classified into three (3) main categories and these are:

1. Local winds: these include bora, foehn, loo, mistral, etc.

2. Secondary winds: these include mountain and valley breeze, monsoon wind, etc.

3. Primary winds: polar easterlies, trade winds, westerlies, etc.

In this exercise, you're required to complete the given sentences as follows:

Monsoon wind: a seasonal wind that blows in the opposite direction of normal winds.

Prevailing wind: it is a wind that blows mainly from a single (one) general direction.

During winter, droughts are typically caused by the seasonal winds that blow in the opposite direction of normal winds.

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Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructions on the box said to twist the pack until the liquids mix. Which type of energy contained in the pack is responsible for producing the heat?

Answers

Answer:

Chemical

Explanation:

Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructions on the box said to twist the pack until the liquids mix. Chemical energy contained in the pack is responsible for producing the heat.

What is chemical energy ?

Chemical energy is the energy that is released when chemical substances engage in a chemical reaction and change into other substances. Batteries, food, and gas are a few examples of chemical energy storage mediums.

Chemical energy is the energy held in atom and molecule bonding. Chemical energy can be found in things like batteries, biomass, oil, natural gas, and coal. When humans burn fuel in a car's engine or wood in a fireplace, chemical energy is transformed into thermal energy.

Around the world, we generate heat and power using chemical energy. Methane, natural gas, oil, and petroleum are examples of fossil fuels that we burn to create steam that turns turbines to generate power.

Thus, Chemical energy contained in the pack is responsible for producing the heat.

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What would happen if a person who is wearing a heavy winter jacket were to place a thermometer inside the jacket next to his or her skin? What would happen if we took the same jacket, after it had been hanging in a closet, and placed a thermometer inside?

Answers

Answer:

Explained.

Explanation:

Let me explain the two cases in by one.

(1) When Person wearing a jacket, heat from his or her body is going to get trapped inside his or her jacket to keep this person warm when a thermometer is placed inside, it would indicate a higher temperature on the scale.

(2) When Jacket is Hanging in a closet, its temperature would be roughly close to room temperature and when we would place a thermometer it would not indicate any change on its scale.

What condition is necessary for the flow of heat? What analogous condition is necessary for the flow of charge?

Answers

Temperature difference; voltage difference

Batteries have potential energy in their
energy stores. What one word completes the sentence?

Answers

Answer:

Chemical

Explanation:

Answer:

The right answer is "chemical"

Explanation:

Batteries store energy in the chemical bonds in the metals inside them.

Let the magnitudes of two displacement vectors be 4 m and 8 m, respectively. If the two vectors are added, the magnitude of the resultant vector. A. is exactly equal to 4 m. B. is exactly equal to 12 m. C. is greater than 12 m. D. could be as small as 4 m, and as large as 12 m

Answers

Answer:

D. Could be as small as 4 m, and as large as 12 m.

Explanation:

Since the magnitudes are vectors instead of scalars, their sum is not just the sum of their magnitudes; their directions must be taken in account. The maximum possible magnitude of the resultant occurs when both vectors have the same direction; in that case the resultant magnitude is the sum of the individual magnitudes (in this case, 12 meters). In the other hand, the minimum possible magnitude is when the vectors have opposite directions; in that case the magnitude of the resultant is the substraction of one magnitude to another (in this case, 4 meters). Finally, the right answer is D, because the possible values range from 4m to 12m.

Final answer:

The magnitude of the resultant vector when adding two displacement vectors of 4 m and 8 m can be as small as 4 m if they are in opposite directions or as large as 12 m if they are collinear and in the same direction.(Option D)

Explanation:

The question asks about the magnitude of the resultant vector when two displacement vectors are added. A displacement vector has both magnitude and direction, and when two vectors are combined, their resultant depends on both their magnitudes as well as the angle between them. When two vectors are added, the magnitude of the resulting vector can vary depending on this angle. If the vectors are collinear and in the same direction, the magnitude of the resultant will be the sum of the magnitudes of the individual vectors, which is the maximum possible magnitude.

However, vectors can also be in opposite directions, in which case the resultant magnitude will be the difference between the two, representing the minimum magnitude. Therefore, given two displacement vectors with magnitudes of 4 m and 8 m, the magnitude of the resultant vector upon addition can range from 4 m to 12 m. This occurs because if the vectors are in the same direction, their magnitudes add up (to 12 m); if they are opposite, the resultant is the difference (to 4 m). In any other scenario of different angles between the vectors, the resultant will fall somewhere between 4 m and 12 m.

What is your prediction on the effects of drinking 20oz of sports drink vs. 20oz of water? What would happen to urine volume

Answers

Answer:

Drinking 20oz of sports drinks decrease the urine volume compared to 20oz of water

Explanation:

Sport drinks typically used by athletes contain water,carbs and electrolytes which helps to replenish the lost minerals from the body during exercises.

Electrolytes an important ingredients of sports drinks is typically sodium and potassium they help the body to retain water,hence less volume of urine is released from the body.

The diagram shows a transformer. Based on the diagram the voltage at the second winding is ____ v

Answers

Answer:

60V

Explanation:

240V/12 loops = 20 volts per loop.

20 * 3 = 60 volts  

Answer:

60V

Explanation:

On classical Hall mobility: In a semiconductor sample, the Hall probe region has a dimension of 0.5 cm by 0.25 cm by 0.05 cm thick. For an applied electric field of 1.0 V/cm, 20 mA current flows (through the long side) in the circuit. When a 10 kG magnetic field is applied, a Hall voltage of 10 mV is developed. What is the Hall mobility of the sample and what is the carrier density

Answers

Answer:

hall mobility = 139.8 x 10 ∧3

carrier density = 83.1 x 10 ∧14

Explanation:

The pictures attached below shows the full explanation

1. In the picture below, energy is being converted to heat water. What type of energy transformations take place in this model?

Answers

Kinetic energy is formed when water is heated.

Explanation:

Suppose in an electric kettle there is water , when water is boiled the electrical energy changes into thermal energy when heating is done.The thermal energy then gets transferred to the water . When the boiling takes place in the water the energy gets transformed into sound. Lastly at the end the gravitational potential energy finally changes to the kinetic energy.

There are three types of energy transformations taking place

(i) conversion of kinetic energy to rotational energy

(ii) conversion of rotation energy to electrical energy

(iii) conversion of electrical energy to heat energy

As seen in the image attached, there is running water that is falling on the blades of a small turbine and makes it rotate. The turbine is connected to the heating system with wires.

Now, the energy transformations that take place in heating water are described as follows:

The flowing tap water is falling on the blades of the turbine which produces torque and makes the blade rotate. Hence, the kinetic energy of the tap water is converted into rotational energy.Now the turbine is connected to the heating system with wire, which means it must produce electricity. Here, The rotation energy is converted into electrical energy. Lastly, the electrical energy produced by the turbine is being converted into heat energy by the heating system to warm water.  

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A single star in the process of forming starts by spinning slowly (while it is quite large and relatively cool.) As the star collapses under the pull of its own gravity, its size decreases. As a result, its rate of spinning:_____
a. will either increase or decrease depending on the star's temperature
b. will decrease
c. will stay the same
d. will increase

Answers

Answer:

d. will increase

Explanation:

The process is spinning is known as stellar rotation, it is the rotation of a star about it axis in an angular direction. Now, A single star in the process of forming starts by spinning slowly which is as a result of its size but as  the star collapses under the pull of its own gravity, the radius of the size shrinks and reduces, then the  spinning rate escalate and increases.

A particle with mass 1.81×10−3 kgkg and a charge of 1.22×10−8 CC has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^v→=(3.00×104m/s)j^. What are the magnitude and direction of the particle’s acceleration produced by a uniform magnetic field B⃗ =(1.63T)i^+(0.980T)j^B→=(1.63T)i^+(0.980T)j^?

Answers

Answer:

-(0.330m/s² ) kˆ

Explanation:

given data:

Mass of particle 'm'= 1.81 x [tex]10^{-3}[/tex] kg

Velocity 'v'= (3.00 x[tex]10^{4}[/tex] m/s)j

Charge of particle 'q'= 1.22 x [tex]10^{-8}[/tex] C

Uniform magnetic field 'B' = (1.63iˆ + 0.980jˆ )T

In order to calculate particle's acceleration, we'll use Newton's second law of motion i.e F=ma

Also,the force a magnetic field exerts on a charge q moving with velocity v is called the magnetic Lorentz force. It is given by:

F = qv × B

F= ma = qV x B

a= [tex]\frac{q(v*B)}{m}[/tex] --->eq(1)

Lets determine the value of (v x B) first

v x B= (3.00 x[tex]10^{4}[/tex] m/s)j x (1.63iˆ + 0.980jˆ )

v x B= 4.89 x [tex]10^{4}[/tex]

Plugging all the required values in eq(1)

a= [1.22 x [tex]10^{-8}[/tex] x (4.89 x [tex]10^{4}[/tex]kˆ)] / 1.81 x [tex]10^{-3}[/tex]

a=  -(0.330m/s² ) kˆ

-ve sign is representing the opposite direction

Which features do sound waves have the ocean and light waves do not

Answers

Compressions and rarefactions
Final answer:

Sound waves spread out and bend around corners, while light waves behave like rays and do not bend around corners.

Explanation:

The difference between sound waves and light waves when passing through an opening is that light waves behave like rays and do not bend around corners, while sound waves spread out and bend around corners due to their longer wavelengths.

Light waves have very short wavelengths, which allows them to act like rays and create sharp shadows when passing through openings. On the other hand, sound waves have longer wavelengths, on the order of the size of the opening, and can bend around corners.

For example, when light shines through an open door into a dark room, we expect to see a sharp shadow of the doorway on the floor and no light bending around corners. However, when sound passes through a door, we expect to hear it everywhere in the room, indicating that sound waves spread out and bend around corners.

A spring (k=15.19kN/m)is is compresses 25cm and held in place on a 36.87° incline. A block (M=10kg) is placed on the spring. When the spring is released the block slides up and off the end of the ramp. The block travels 1.12m along the ramp where the co efficient of kinetic friction is 0.300. Determine the maximum vertical displacement of the block after it becomes airborne relative to it's initial position on the spring

Answers

Answer:

The maximum vertical displacement is 2.07 meters.

Explanation:

We can solve this problem using energy. Since there is a frictional force acting on the block, we need to consider the work done by this force. So, the initial potential energy stored in the spring is transferred to the block and it starts to move upwards. Let's name the point at which the block leaves the ramp "1" and the highest point of its trajectory in the air "2". Then, we can say that:

[tex]E_0=E_1\\\\U_e_0=K_1+U_g_1+W_f_1[/tex]

Where [tex]U_e_0[/tex] is the elastic potential energy stored in the spring, [tex]K_1[/tex] is the kinetic energy of the block at point 1, [tex]U_g_1[/tex] is the gravitational potential energy of the block at point 1, and [tex]W_f_1[/tex] is the work done by friction at point 1.

Now, rearranging the equation we obtain:

[tex]\frac{1}{2}kx^{2}=\frac{1}{2}mv_1^{2}+mgh_1+\mu Ns_1[/tex]

Where [tex]k[/tex] is the spring constant, [tex]x[/tex] is the compression of the spring, [tex]m[/tex] is the mass of the block, [tex]v_1[/tex] is the speed at point 1, [tex]g[/tex] is the acceleration due to gravity, [tex]h_1[/tex] is the vertical height of the block at point 1, [tex]\mu[/tex] is the coefficient of kinetic friction, [tex]N[/tex] is the magnitude of the normal force and [tex]s_1[/tex] is the displacement of the block along the ramp to point 1.

Since the force is in an inclined plane, the normal force is equal to:

[tex]N=mg\cos\theta[/tex]

Where [tex]\theta[/tex] is the angle of the ramp.

We can find the height [tex]h_1[/tex] using trigonometry:

[tex]h_1=s_1\sin\theta[/tex]

Then, our equation becomes:

[tex]\frac{1}{2}kx^{2}=\frac{1}{2}mv_1^{2}+mgs_1\sin\theta+\mu mgs_1\cos\theta\\\\\implies v_1=\sqrt{\frac{2(\frac{1}{2}kx^{2}-mgs_1\sin\theta-\mu mgs_1\cos\theta)}{m}}=\sqrt{\frac{kx^{2}}{m}-2gs_1(\sin\theta+\mu \cos\theta)}[/tex]

Plugging in the known values, we get:

[tex]v_1=\sqrt{\frac{(15190N/m)(0.25m)^{2}}{10kg}-2(9.8m/s^{2})(1.12m)(\sin36.87\°+(0.300) \cos36.87\°)}\\\\v_1=8.75m/s[/tex]

Now, we can obtain the height from point 1 to point 2 using the kinematics equations. We care about the vertical axis, so first we calculate the vertical component of the velocity at point 1:

[tex]v_1_y=v_1\sin\theta=(8.75m/s)\sin36.87\°=5.25m/s[/tex]

Now, we have:

[tex]y=\frac{v_1_y^{2}}{2g}\\\\y=\frac{(5.25m/s)^{2}}{2(9.8m/s^{2})}\\\\y=1.40m[/tex]

Finally, the maximum vertical displacement [tex]h_2[/tex] is equal to the height [tex]h_1[/tex] plus the vertical displacement [tex]y[/tex]:

[tex]h_2=h_1+y=s_1\sin\theta +y\\\\h_2=(1.12m)\sin36.87\°+1.40m\\\\h_2=2.07m[/tex]

It means that the maximum vertical displacement of the block after it becomes airborne is 2.07 meters.

Although blood cells are contained within a special liquid called plasma, the cells themselves are___________.

Answers

Answer:

Solid

Explanation:

The plasma is the liquid part of blood, it is 90% and accounts for 55% of blood volume. It is what red blood cells, white blood cells, and platelets move around in. These cells remain solid within the plasma. I hoped this helped!

Although blood cells are contained within a special liquid called plasma, the cells themselves are suspended in plasma.

Blood is a fluid tissue that is made up of plasma, red blood cells, white blood cells, and platelets. Plasma is the liquid part of blood that makes up about 55% of blood volume.

Red blood cells make up about 45% of blood volume and are responsible for carrying oxygen to the tissues. White blood cells make up about 1% of blood volume and are responsible for fighting infection. Platelets are responsible for clotting blood.

The cells are suspended in the plasma because they are too small to sink to the bottom of the blood. The plasma also helps to transport the cells throughout the body.

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what voltage would be required to run a 600-watt motor with a current of 400 amperes​

Answers

Answer:

Voltage can be calculated in various ways but I am a easier solution to it:

Explanation:

V=I×R instead of this formula I use:

P=I×V

600=400×V

600=400V

Divide both sides by 400

V=3÷2

V=1.5 J/C

1volt=1coulomb or joule

Answer:1.5V

Explanation: power =IV

Where I= current

V= voltage

Therefore Voltage=power/current

V= 600/400= 1.5

A typical incandescent light bulb consumes 75 W of power and has a mass of 30 g. You want to save electrical energy by dropping the bulb from a height great enough so that the kinetic energy of the bulb when it reaches the floor will be the same as the energy it took to keep the bulb on for 1.0 hour. From what height should you drop the bulb, assuming no air resistance and constant g?

Answers

Answer:

The height will be 917431.2 m.

Explanation:

Power of bulb = 75 W

Time kept on 1 hr = 60 x 60 = 3600 sec

Energy of bulb = power x time

E = 75 x 3600 = 270000 J

From conservation of energy, kinetic energy of the bulb is equal to the potential energy of the bulb due to its height of fall.

Potential energy = m x g x h

Where g = acceleration due to gravity 9.81 m/s2

m = mass = 30 g = 0.03 kg

PE = 0.03 x 9.81 x h = 0.2943h

Equating withe the energy of bulb (still obeying energy conservation)

270000 = 0.2943h

h = 270000/0.2943 = 917431.2 m

The incandescent bulb would have to be dropped from a height of approximately 918,367.35 meters to have its kinetic energy equal to the energy consumed in one hour of use.

To determine from what height you should drop a 75-watt incandescent bulb so that upon reaching the floor, its kinetic energy will equal the energy used to power it for 1.0 hour, we use the formula for gravitational potential energy (PE) and kinetic energy (KE), where PE = mgh and KE = ½ mv². The power consumption of the bulb indicates how much energy it uses per second, so we first calculate the energy consumed in one hour (E = power × time). Since the bulb is 75 watts, and there are 3600 seconds in an hour, it uses 75 W × 3600 s = 270,000 joules in one hour. This is the energy we want the bulb to have as kinetic energy when it hits the ground. To find the height, we set this equal to the potential energy at the start (mgh) and solve for h:

E = mgh

270000 J = (0.03 kg)(9.8 m/s²)(h)

h = 270000 J / (0.03 kg × 9.8 m/s²)

h = 918367.35 m

Thus, the bulb would have to be dropped from a height of approximately 918367.35 meters to have the same energy when it impacts the ground as it uses in one hour of being lit.

In a double-slit arrangement the slits are separated by a distance equal to 100 times the wavelength of the light passing through the slits. What is the angular separation in radians between the central maximum and an adjacent maximum?

Answers

Answer:

0.01 rad

Explanation:

For a double-slit experiment, we have that dsinθ = nλ. The separation between the central maximum and an adjacent maximum is when n = 1

dsinθ = λ

The angular separation θ = sin⁻¹(λ/d)

now d = 100λ

θ = sin⁻¹(λ/100λ) = sin⁻¹(0.01) = 0.573°

θ = 0.573° × π/180 = 0.01 rad

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