(c)
given the inequality | P | > a then the solution is always of the form
P < - a or P > a
for | P | > 3 , then
P < - 3 or P > 3
Find the unknown length of y. Please help ASAP!!!!!!!! :(
We assume the slope is a constant, so the rise is proportional to the run.
... y/(4 ft) = (31 ft)/(3 ft)
... y = (4/3)·(31 ft)
... y = 41 1/3 ft = 41 ft 4 in
Need help, thanks. :)
Answer:
f(2) = 0
Step-by-step explanation:
Plug x = 2 into the formula for f(x):-
f(2) = 2(2) - 4
= 4 - 4
= 0
f(2) = 0
substitute x = 2 into f(x)
f(2) = (2 × 2 ) - 4 = 4 - 4 = 0
Many medications are determined by the weight of the patient in kilograms. When a patient’s weight is measured in pounds, the doctor must then convert the weight to kilograms. The table shows conversions for common units of weight.
Answer:
70.2
Step-by-step explanation:
Multiply the weight in pounds by the conversion factor.
[tex]156\,lb\times\dfrac{0.45\,kg}{1\, lb}=70.2\,kg[/tex]
Answer:
70.2 kilograms
Step-by-step explanation:
In order to calculate this you just have to do a rule of three, where you use the equivalence of the pounds by the kilograms, in the table you see that 1 pound equals .45 kilograms, so you use that for your equivalence:
[tex]\frac{1pound}{.45kilograms}= \frac{156 pounds}{x}[/tex]
[tex]x=\frac{165*.45}{1 pound}[/tex]
[tex]x=70.2 kilos[/tex]
So we know that the patient weights 70,2 kilograms.
- 2/3 + (3/4 + 5/3)
The commutative property of addition lets you rearrange this to
(3/4 +5/3) - 2/3
The associative property of addition lets you regroup this to
3/4 + (5/3 -2/3)
= 3/4 + 3/3
= 1 3/4 . . . . take your pick of the final form
= 7/4
= 1.75
1. Refer to the equation 2x − 6y = 12.
(a) Create a table of values for at least 4 points. Show your work.
(b) Use the table of values to graph the line. Use a straightedge or ruler to draw the line.
Answer:
Answer:
x 6 0 3 -3
y 0 -2 -1 -3
Step-by-step explanation:
We substitute x value in the equation and find y.
When x =0, -6y = 12 or y =-2
Likewise all pairs are found out.
Similarly put y =0: x = 6
When x =3, 2(3)-6y =12 :y =-1
When x=-3, 2(-3)-6y=12 or y = -3
Plot these on a graph and join the line.
Graph is attached below:
a. 2x-6y=12: y = (12-2x)/6.
b. Graph the line using (0,2) and (3,0).
(a) To create a table of values for at least 4 points, we can solve the equation for y in terms of x:
y = (12 - 2x) / 6
We can then choose different values for x and plug them into the equation to find the corresponding y values.
Here is a table of values for at least 4 points:
x y
0 2
3 0
-3 4
6 -2
(b) To graph the line, we can use the two points from the table of values that are closest to each other.
In this case, we will use the points (0, 2) and (3, 0).
First, plot the two points on the coordinate plane.
Then, use a straightedge or ruler to draw a line that passes through both points.
Here is the graph of the line 2x − 6y = 12:
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when multipling signed numbers how do you know wether the number is positive or neagitive
If an odd number of minus signs are involved in a product or quotient, the sign of the result is negative. Otherwise, it is positive.
Examples:
(-1)(-1) = 1
(-1)(-1)(-1) = -1
(-1)/(-1) = 1
(-1)(-1)/(-1) = -1
The product of two positive numbers is positive: (+)(+) = (+).
The product of one positive number and one neg number is neg: (+)(-) = (-).
The product of two negative numbers is positive: (-)(-) = (+)
a moving truck charges $250 to rent a truck and $0.40 for each mile driven. mr.lee paid a total of $314. which equation can be used to find m, the number of miles he drove the moving truck?
help please! thanks!
Answer:
The edge length of the storage cube is 30 centimeters.
Step-by-step explanation:
All sides/edges of a cube has equal length.
Let's take the length of a edge as [tex]a[/tex] centimeters.
The volume a the cube = Height * Width * Length
All height, width and length are equal([tex]a[/tex] centimeters).
Now we can write the equation again as,
The volume a the cube = [tex]a*a*a[/tex]
Volume of the cube is given as 27,000 cubic centimeters.
Therefore,
[tex]a*a*a=27,000[/tex]
[tex]a=\sqrt[3]{27,000}[/tex]
[tex]a=30[/tex]
Therefore, the edge length of the storage cube is 30 centimeters.
there are 200 students in the 7th grade 98% of the students in the greater going on the field trip how many students are going on the field trip show your work and I will mark brainiest
30 percent
22% of 200 is 44, 44 students play football
12 of 200 is 24, 24 students play baseball
44+24=68
The teams have a total of 68 players
because 8 play both sports you subract 8
68-8=60
The answer is a tolal of 60 students play sports
I think the answer is 60
X+3x-2=6x-12 please help
A student bought a juice pouch for $2.50 and three bags of chips the total cost was $5.05 right and solve an equation to determine the cost of a bag of chips, c
The total amount of the purchase was ...
... $2.50 + 3c = $5.05
This equation can be solved by subtracting 2.50 and dividing by 3. Both these operations are done to both sides of the equation in accordance with the rules of equality.
... 3c = $2.55
... c = $0.85
The cost of a bag of chips was $0.85.
The cost of a bag of chips can be found by subtracting the juice price from the total cost and then dividing by the number of chip bags. This gives us an answer of $0.85 per bag.
Explanation:To solve this problem, we need to subtract the cost of the juice from the total cost, then divide that answer by the total number of chip bags bought to find the cost of one bag. First, we subtract the juice price ($2.50) from the total spent ($5.05), which gives us $2.55. This is the total cost of the chips. Then, we divide that $2.55 by the number of chip bags bought (which is three) to find the cost of one bag. This can be represented by the equation: c = (total cost - juice price) / number of chip bags, or c = ($5.05 - $2.50) / 3. Calculating this, we find that c equals $0.85, so a bag of chips costs $0.85.
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Daniela bought a car for $24,000. Each year the value of the car decreases by $1750. a. Write a function that shows the value of the car after y years.
I hope this might be able to help you.
Since the value of the car slowly decreases each year and each year is represented by y, the function is 24,000-1750y=f(x).
A number, n, is multiplied by -3/8. The product is -0.1. What is the value of n?
Rewriting this symbolically, (-3/8)n = -0.1. Let's solve for n. To do this, multiply both sides of the equation by (-8/3). This results in n = 8/30, or n= 4/15.
Can anyone transform a vertex form equation into a standard form?
y= -0.3(x-0)^2+3
If you can show work.
the standard form of a quadratic is : y = ax² + bx + c : (a ≠ 0 )
note that (x - 0 )² = x²
distributing by - 0.3 gives
y= - 0.3x² + 3 ← in standard form
with a = - 0.3, b = 0 and c = 3
need help finding the x, y, and z. please and thank you
The first step in any problem is to look at what you are given. When solving systems of linear equations, it is often helpful to eliminate one or more of the variables by adding or subtracting a multiple of one equation with a multiple of another. It is convenient when at least one of the multipliers is 1.
Here, we can cancel the y-terms in the 2nd and 3rd equations simply by adding them together. This gives
... (5x +y -4z) +(-3x -y +5z) = (41) +(-45)
... 2x +z = -4 . . . . simplified
Likewise, we can add 3 times the second equation to the first to cancel y in that sum.
... 3(5x +y -4z) +(2x -3y +z) = 3(41) + (-1)
...15x +3y -12z +2x -3y +z = 123 -1
...17x -11z = 122 . . . . simplified
Now that we have 2 equations in x and z, we can go through the same process. We observe that the coefficient of z is +1 in the first equation and -11 in the second. The means we can cancel the z terms by adding 11 times the first equation to the second:
... 11(2x +z) +(17x -11z) = 11(-4) +122
...22x +17x = 78 . . . . . . simplify a little bit
... x = 78/39 = 2 . . . . . . divide by 39
From above, we find
... z = -4 -2x = -4 -2·2 = -8
... y = 41 -5x +4z = 41-5(2) +4(-8) = 41 -42 = -1
The solution is (x, y, z) = (2, -1, -8).
_____
The method of elimination used here will vary with the system of equations. If you want to employ a consistent method, you can use Cramer's Rule, Gaussian elimination, or matrix methods. Since you apparently don't mind help from technology, learning to do this on your graphing calculator can also be a good idea.
In triangle ΔABC, ∠C is a right angle and CD is the height to AB . Find the angles in ΔCBD and ΔCAD if: Chapter Reference a m∠A = 20° Answer: m∠CDB = m∠CBD = m∠BCD = m∠CDA = m∠ CAD= m∠ACD =
In triangle ABC, when ∠A = 20°, then ∠B = 70°, ∠C = 90°. In triangle CAD, when ∠CAD = 20° and ∠CDA = 90°, ∠ACD = 70°. In triangle CBD, with ∠CBD = 90° and ∠BCD = 70°, ∠CDB = 20°.
Explanation:In triangle ΔABC, ∠C is a right angle and CD is the height to AB. Considering ∠A = 20°, by the angles sum property of a triangle, ∠B = 180° - ∠A - ∠C = 180° - 20° - 90° = 70°.
Moving on to triangle ΔCAD, this is a right triangle with ∠CDA=90°. ∠CAD is given as 20° (the same as ∠A of triangle ΔABC). Therefore, ∠ACD = 180° - ∠CAD - ∠CDA= 180° - 20° - 90° = 70°.
For triangle ΔCBD, ∠CBD is 90°, and ∠BCD corresponds to ∠B of triangle ΔABC, which we've determined as 70°. Hence, ∠CDB = 180° - ∠CBD - ∠BCD = 180° - 90° - 70° = 20°.
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In triangle ΔCBD, the angles are: m∠CDB = m∠CBD = 90° and m∠BCD = 90°. In triangle ΔCAD, the angles are: m∠CDA = 70° and m∠CAD = 70°. Finally, m∠ACD = 40°.
Explanation:In triangle ΔCBD, since ∠C is a right angle, ∠CBD = 90° and ∠BCD = 90°.
In triangle ΔCAD, using the fact that the sum of angles in a triangle is 180°, we can find that ∠CDA = 90° - ∠CBD = 90° - 20° = 70°.
Similarly, ∠CAD = 90° - ∠BCD = 90° - 20° = 70°.
Finally, since ∠CDA = ∠CAD, ∠ACD = 180° - ∠CDA - ∠CAD
= 180° - 70° - 70°
= 40°.
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What is the value of y in the solution to the following system of linear equations?
2x+2=y
2y=5x-1
A) 3
B) 5
C) 8
D) 12
ANSWER
[tex]y=12[/tex]
EXPLANATION
One way is to make x the subject in one equation and substitute into the other.
[tex]2x+2=y[/tex]
[tex]\Rightarrow 2x=y-2[/tex]
[tex]\Rightarrow x=\frac{y}{2}-1--(1)[/tex]
The second equation is
[tex]2y=5x-1--(2)[/tex]
Let us put equation 1 in 2
[tex]\Rightarrow 2y=5(\frac{y}{2}-1)-1[/tex]
[tex]\Rightarrow 2y=\frac{5y}{2}-5-1[/tex]
[tex]\Rightarrow 2y=\frac{5y}{2}-6[/tex]
Multiplying through by 2 gives;
[tex]\Rightarrow 4y=5y-12[/tex]
[tex]\Rightarrow 4y-5y=-12[/tex]
[tex]\Rightarrow -y=-12[/tex]
[tex]\Rightarrow y=12[/tex]
D
given the 2 equations
2x + 2 = y → (1)
2y = 5x - 1 → (2)
Substitute y = 2x + 2 into (2)
2(2x + 2) = 5x - 1
4x + 4 = 5x - 1 ( subtract 5x from both sides )
- x + 4 = = - 1 ( subtract 4 from both sides )
- x = - 5 ( multiply through by - 1 )
x = 5
substitute x = 5 into (1)
y = (2 × 5 ) + 2 = 10 + 2 = 12 → D
Solve the literal equation |ax+b|=c for x.
Try this solution; note, this way is not the shortest one.
The solutions for the modular equation are:
[tex]x = \frac{c - b}{a}[/tex] or [tex]x = -\frac{c + b}{a}[/tex]
-----------------------
A modular equation |f(x)| = a means that:
[tex]f(x) = a[/tex] or [tex]f(x) = -a[/tex]
-----------------------
The equation given is:
[tex]|ax + b| = c[/tex]
Which means that:
[tex]ax + b = c[/tex]
[tex]ax = c - b[/tex]
[tex]x = \frac{c - b}{a}[/tex]
Or
[tex]ax + b = -c[/tex]
[tex]ax = -c - b[/tex]
[tex]ax = -(c+b)[/tex]
[tex]x = -\frac{c + b}{a}[/tex]
The solutions are [tex]x = \frac{c - b}{a}[/tex] or [tex]x = -\frac{c + b}{a}[/tex]
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What is another way to name ∠QRS ? Select each correct answer. ∠R ∠S ∠Q ∠QSR ∠SRQ ∠RSQ
<SRQ Because if you go any other way other than its opppsite you would get a different angle.
Another way to name ∠QRS is ∠SRQ as R is the vertex of the angle.
What is a vertex?A vertex is a common endpoint between two rays that forms an angle.
We know when an angle is represented by three letters the vertex of the angle is the middle letter.
∴ Another name ∠for QRS is ∠SRQ because here R is the vertex of the angle and we can not place R in the first or the third place as it would completely change the vertex of the angle which are not the same angles, of Ofcourse their measure can be same but they are different.
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How do I get the revised bill rate ?
The initial pay rate is $16.00. It is also mentioned that the price is marked up by 78.7%. It means that the prices are increased by 78.7%. Also, there is a profit of 10% too. So, the pay rates after mark up will be
$16.00 + (78.7% of 16.00)
= $16.00 + $12.592
=$28.592
And the pay rates after estimated profit is
$28.592 + (10% of $28.592)
= $28.592 + $2.8592
= $31.4512
Hence, the revised bill rate, rounded to the nearest cent is $31.45.
If i leave my house at 6:52 am and run 1 mile at an easy pace (8:15 per mile), then 3 miles at tempo (7:12 per mile) and 1 mile at easy pace again, what time do i get home for breakfast?
Running 2 miles at 8:15 per mile takes 16:30 minutes.
Running 3 miles at 7:12 per mile takes 21:36 minutes.
The total running time is 16:30 + 21:36 = 38:06 minutes. That length of time after 6:52 am is 7:30:06 am.
You get home for breakfast at 6 seconds past 7:30 am.
By adding the times spent on each individual run to your start time, you should arrive home at approximately 7:30 am.
Explanation:To begin with, this is a question about time calculation, where you need to know exactly how to calculate time durations. First, you start running at 6:52 am. Your easy pace is 8 minutes 15 seconds, or 8.25 minutes, per mile and you do this once before and once after your tempo run. So, for 2 miles, it's 2*8.25 = 16.5 minutes.
Then you have a tempo pace at 7 minutes 12 seconds, or 7.2 minutes, per mile. You run 3 miles at tempo pace, so that's 3*7.2 = 21.6 minutes.
Adding these two results together, you have a total running time of 38.1 minutes (16.5 minutes easy pace + 21.6 minutes tempo pace). Adding this to your start time of 6:52 am gives you a rough end time of 7:30 am. Please note that this estimation rounds your running time to the nearest minute.
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At the annual dog show chantel noticed that there were 3 more scotties than schnauzers. She also realized that the number of wirehaired terriers was 5 less than the number of schnauzers. If there were 78 dogs in all ( counting schnauzers scotties and terriers) how many schnauzers were there? Write and solve equation
x + x - 3 + 2x - 3 = 78
4x = 84
x = 21
Answer: 21 Schnauzers.
if P(a)=0.60 and P(b)=0.30, then a and b are independent events if
Answer: [tex]\text{P(A or B)}=0.90[/tex]
[tex]\text{P(A and B)}=0.18[/tex]
Step-by-step explanation:
Given : P(A)=0.60 and P(B)=0.30
We will say A and B are independent events if :
[tex]\text{P(A or B)=P(A)+P(B)}\\\\=0.60+0.30=0.90[/tex]
[tex]\text{P(A and B)=P(A) x P(B)}\\\\=0.60\times0.30=0.18[/tex]
Thus , A and B are independent events if :
[tex]\text{P(A or B)}=0.90[/tex]
[tex]\text{P(A and B)}=0.18[/tex]
Answer: P( A and B)= 0.18
Trish plans to sell off 40% of her fast food restraunt business. If the business has been appraised for 350,000 dollars how much money does she expect to raise
40% of $350, 000
40% = [tex]\frac{40}{100}[/tex] = 0.4, hence
expected amount = 0.4 × $350, 000 = $140, 000
At 3:00 p.m., Jasmine leaves her house and drives north to her parent’s home. She arrives at 6:00 p.m. Also leaving at 3:00 p.m. from Jasmine’s house is her friend Jewel who leaves and drives south to her parent’s home. She arrives at 5:00 p.m. The driving distance between both parents’ homes is 300 mi. Jasmine and Jewel drove at the same speed. What was their speed? *
I think you need to think about the problem carefully. My guess is 1,that's my guess. sorry i couldn't give an accurate answer or you divide 300 by 5
Answer:
60
Step-by-step explanation:
To get the color dove-white, Ken mixed black paint and white paint in a ratio of 5:3. He used 20 gallons of black paint. How much white paint did he use?
12 gallons of white paint
divide 20 gallons by 5 to obtain 1 part of the ratio
[tex]\frac{20}{5}[/tex] = 4 gallons ← 1 part
white paint = 3 × 4 = 12 gallons ← 3 parts
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The graph of the tangent function approaches vertical asymptotes at x=±π/2. The inverse function will have horizontal asymptotes of y=±π/2. The only viable choice among your graphs is ...
... Graph C
_____
The graph of the inverse of a function is the function's graph with the x- and y-coordinates swapped. Essentially, the graph is reflected across the line y=x. The graph of the tangent function has a vertical aspect. Its inverse has a horizontal aspect.
Pls help will mark brainliest
4x+2y=6
x-3y=5
SOLVE BY ELIMINATION METHOD PLS
Answer:
y=-1
Step-by-step explanation:
The first step to solving this problem is to write it out like this-->
4x+2y=6
x-3y=5
Next you want to eliminate the X's or the Y's, I chose to elininate the X's-->
4x+2y=6
-4(x-3y=5) [You MUST distribute the -4 to each of the numbers in the equation]
Then you get--->
4x+2y=6
-4x+12y=-20 Then you add them top to bottom--->
0x+14y=-14 [At this point you dont have to write the X]Next you solve for y-->
14y=-14 Divide both sides by 14, in order to get the y by itself-->
y=-1 And theres your answer hope it helps :D
we have the 2 equations
4x + 2y = 6 → (1)
x - 3y = 5 → (2)
multiply (2) by 4
4x - 12y = 20 → (3)
(3) - (1) to eliminate the terms in x
- 14y = 14 ( divide both sides by - 14 )
y = - 1
substitute y = - 1 into (1) and solve for x
4x - 2 = 6 ) add 2 to both sides )
4x = 8 ( divide both sides by 4 )
x = 2
solution is x = 2, y = - 1
Anyone good with Literal Expressions?
Answer:
[tex]\boxed{F=\dfrac{9}{5}c+32}[/tex]
Step-by-step explanation:
[tex]\dfrac{5(F-32)}{9}=c\qquad\text{multiply both sides by 9}\\\\5(F-32)=9c\qquad\text{divide both sides by 5}\\\\F-32=\dfrac{9}{5}c\qquad\text{add 32 to both sides}\\\\\boxed{F=\dfrac{9}{5}c+32}[/tex]
Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°
We have to break each degree in terms of 90
A) [tex]sin180^\circ=sin(90\times2+0)[/tex]
Which is in third quadrant, therefore sine is negative hence
[tex]sin(90\times2+0)= -sin0 ^\circ = 0[/tex]
B) [tex]cos180^\circ =cos(90\times2+0)[/tex]
Which is in third quadrant, therefore cosine is negative hence
[tex]cos(90\times2+0)= -cos0^\circ = -1 [/tex]
C) [tex] tan180^\circ=tan(90\times2+0)[/tex]
Which is in third quadrant, therefore tangent is positive hence
[tex]tan(90\times2+0)= tan0^\circ = 0[/tex]
D) [tex]csc180^\circ=csc(90\times2+0)[/tex]
Which is in third quadrant, therefore cosec is negative hence
[tex]cosec(90\times2+0)= -csc0^\circ =[/tex]not defined
E)[tex]sec180^\circ=sec(90\times2+0)[/tex]
Which is in third quadrant, therefore secant is negative hence
[tex]sec(90\times2+0)= -sec0^\circ = -1 [/tex]
F) [tex] cot180^\circ=cot(90\times2+0)[/tex]
Which is in third quadrant, therefore tangent is positive hence
[tex]cot(90\times2+0)= cot0^\circ = [/tex] not defined
Hence only [tex] cos 180^\circ [/tex] and
[tex] sec180^\circ [/tex] have value -1
Hope this will help
Answer:
Cos and Sec
Step-by-step explanation:
thats the short of the guy above