Some farmers leave a strip of land around the edge of each field which they do
not spray with chemicals.

Suggest two reasons why this will lead to an increase in the number of partridges
on these farms.

Answer:

1.24 atm is the new pressure

Explanation:

We may solve this question with the Ideal Gases Law that must be used, twice. → P . V = n . R . T

Total pressure = Partial pressure of gas A + Partial pressure of gas B

Total pressure = 0.298 atm + 0.589 atm → 0.887 atm

We convert the T° to Absolute value  → 55°C + 273 = 328K

0.887 atm . 9.80L = n . 0.082 . 328K

(0.887 atm . 9.80L) /(0.082 . 328K) = 0.323 moles

These are the moles from the initial mixture, but we add 0.130 moles

Total new moles are 0.323 + 0.130 = 0.453 moles

P = (0.453 mol . 0.082 . 328K) / 9.80L

P = 1.24 atm

Notice, that the pressure was increased. As we add a third gas, the pressure is correctly increased because the molecules from all of the gases   collide more with the walls of the vessel.

Answer : The amount of energy absorbed is, 81.2 kJ

Explanation :

The process involved in this problem are :

[tex](1):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(2):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)[/tex]

The expression used will be:

[tex]Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{vap}][/tex]

where,

[tex]Q[/tex] = heat required for the reaction = ?

m = mass of liquid = 30.3 g

[tex]c_{p,l}[/tex] = specific heat of liquid water = [tex]4.18J/g^oC[/tex]

[tex]\Delta H_{vap}[/tex] = enthalpy change for vaporization = [tex]40.79kJ/mol=\frac{40790J/mol}{18.02g/mol}=2263.6J/g[/tex]

Now put all the given values in the above expression, we get:

[tex]Q=[30.3g\times 4.18J/g^oC\times (100-0)^oC]+[30.3g\times 2263.6J/g][/tex]

[tex]Q=81252.48J=81.2kJ[/tex]

Therefore, the  amount of energy absorbed is, 81.2 kJ

Answer:

39.446L

Explanation:

since helium is ideal gas, we can use PV = nRT

P = pressure

V = volume

n = moles

R = gas constant

T = temperature in Kelvin

we are solving for V

V = [tex]\frac{nRT}{P}[/tex]

C to K temp transfer: K = C + 273, so K = 290 since C = 17

our gas constant is 0.08206 atm L/mol K, this gas constant r will change depending on what unit of pressure you are using (mmHg, atm, etc).

plug and chug

V = [tex]\frac{(2.3mol)(290K)(\frac{0.08206 atmL}{molK}) }{1 atm}[/tex]

canceling out units

V = [tex]\frac{2.3 * 209 * 0.08206L}{1}[/tex] = 39.446

Answer:

mass = 172.78 grams Na₂CO₃(s) formed

Explanation:

6Na°(s) + Fe₂(CO₃)₃ => 3Na₂CO₃(s) + 2Fe°(s)

moles Na°(s) = 15g/23g/mol = 3.26 mole Na°(s)

From stoichiometry of reaction equation, 3.26 mole Na°(s) => 3/6(3.26) mole Na₂CO₃(s) = 1.63 mole Na₂CO₃(s) x 106 g/mole = 172.78 grams Na₂CO₃(s)

Answer:

Explanation:

q = (mass) (temp change) (specific heat)

q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ

154 kJ / 2220 kJ/mol = 0.069369369 mol

0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)

answer choice 4

The heat of combustion ([tex]\Delta[/tex]Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions.

3.05988g. grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C.

q=m*c*(change of T)

q=10000g(0.385J/g*c)*(65.0C-25.0C)or (338.2 K-298.2K)

q=154000J

154000J*(1 mol/2220 KJ)=69.36936 x [tex]10 ^-3[/tex] mol

here's where I'm stuck

0.069369 mol

and i know that for every 1 mol there is 44.11g of C3H8.

0.069369 mol* (44.11g C3H8)/1mol = 3.05988g.

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Answer:

The answer to your question is 82g

Explanation:

Data

Molecule: Sodium acetate  Na(C₂H₃O₂)

Molar mass = ?

Process

Look for the atomic mass of each element, multiply this number by the subscript and add the results.

Sodium = 23 g

Carbon = 2 x 12 = 24 g

Hydrogen = 1 x 3 = 3 g

Oxygen = 2 x 16 = 32 g

Sum up the result

Molar mass = 23 + 24 + 3 + 32

                   = 82 g

Answer:

Mf = MiVi / Vf

Explanation:

To obtain the answer to the question given, let us obtain the equation for the final concentration.

This can be obtained from the dilution equation as shown below :

MiVi = MfVf

Mi is the initial concentration

Mf is the final concentration

Vi is the initial volume

Vf is the final volume.

Making Mf the subject of the above equation, we can obtain the equation which can be used to calculate the final concentration. This is illustrated below:

MiVi = MfVf

Divide both side by Vf

Mf = MiVi / Vf

Therefore, the equation which can be used to calculate the final concentration is Mf = MiVi / Vf

The first part to this question is:

What is the final volume? 150.0

the second part:

Which equation should you use to find the final concentration?  3rd option

The 3rd part:

What is the new concentration?  0.125 M NaCl

Explanation:

On edg..  Good Luck!!

Answer:

no2

Explanation:

Nitrogen N and Oxygen O2 combine to form NO2

Answer:

It were added 1.17 moles of gas

Explanation:

We use the Ideal Gases Law to propose both situations:

P . V = n . R . T

For initial situation → P₁ . V₁ = n₁ . R . T₁

For the second situation → P₂ . V₂ = n₂ . R . T₂

R is a constant and V remains constant, so we cancel from the equations.

(n₁  . T₁) / P₁ = (n₂ . T₂) / P₂

Notice that n₂ = n₁ + x where n₁ = 1.45 moles.

Let's make the conversions for the units

25°C + 273 = 298 K (T₁)  and 50°C  + 273 = 323K (T₂)

408 Torr . 1 atm / 760 Torr = 0.537 atm (P₁)

800 Torr . 1 atm / 760 Torr = 1.05 atm (P₂)

Let's replace and find the x

(1.45 mol . 298K) / 0.537 atm = (( x + 1.45mol) . 323K) / 1.05 atm

(1.45 mol . 298K) / 0.537 atm . 1.05 atm = ( x + 1.45mol) . 323K

845 mol. K = 323 x K + 468.35 mol.K

845 mol.K - 468.35 mol.K = 323 x K

376.65 mol.K / 323 K = x

1.17 mol = x

Answer:

C. NaCl

Explanation: The answer is C because the products are water and salt. Hydrochloric acid is a strong acid and NaOH ( sodium hydroxide is also a strong acid) are the reactants.

Answer:

NaCI

Explanation:

Answer:

Vapor pressure of solution is 736mmHg

Explanation:

Vapor pressure of an ideal solution follows Raoult's law:

[tex]P_{solution} = X_{solvent}P_{solvent}[/tex]

Where P is vapor pressure and X is mole fraction

Moles of glucose are:

48.4g × (1mol / 180.156g) = 0.2687mol glucose

Moles of water:

151.2g × (1mol / 18.1g) = 8.354 mol water

Thus, mole fraction of water (Solvent) is:

8.354 mol / (8.354 mol + 0.2687mol) = 0.9688

Vapor pressure of a solvent at boiling point is equal to atmospheric pressure (760mmHg). Replacing in Raoult's law:

[tex]P_{solution} = 0.9688*760mmHg[/tex]

Vapor pressure of solution is 736mmHg

The vapor pressure of the solution will be "736 mmHg".

According to the question,

Sample of glucose = 48.4 g

Mass of water = 151.2 g

Temperature = 100°C

Now,

Moles of glucose will be:

= 48.4 × ([tex]\frac{1 \ mol}{180.156}[/tex])

= 0.2687 mol

Moles of water will be:

= 151.2 × ([tex]\frac{1 \ mol}{18.1}[/tex])

= 8.354 mol

Water's moles fraction will be:

= [tex]\frac{Moles \ of \ water}{Moles \ of \ water +Glucose}[/tex]

By substituting the values,

= [tex]\frac{8.354}{8.354+0.2687}[/tex]

= 0.9688

hence,

By using Raoult's Law,

→ [tex]P_{solution}[/tex] = [tex]X_{solvent} P_{solvent}[/tex]

By substituting the values,

                = 0.9688 × 760

                = 736 mmHg

Thus the above solution is correct.55

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Answer:

180 g/mol

Explanation:

M(HC₉H₇O₄) = M(H) + 9M(C) + 7M(H) + 4M(O) = 1+ 9*12 +7*1 + 4*16= 180

The molar mass of Aspirin (C9H8O4) is calculated as 180.17 g/mol, by summing the individual contributions of the atomic masses of carbon, hydrogen, and oxygen.

The molar mass of acetylsalicylic acid, commonly known as Aspirin, can be calculated by adding the atomic masses of its constituent atoms. Aspirin has the molecular formula C9H8O4. To calculate the molar mass, we sum the atomic masses as follows:

Adding these contributions together, we get:

Molar mass of Aspirin (C9H8O4) = 108.09 + 8.08 + 64.00 = 180.17 g/mol

This value is slightly different from the reference value of 180.15 g/mol, likely due to rounding differences in the atomic masses used.

 Explanation:

answer is b

Answer:

1. The energy escapes your home and heats the outside.

Explanation:

Final answer:

The energy used to heat your home ultimately dissipates into the environment, adhering to the First Law of Thermodynamics, which states that energy is neither created nor destroyed. Thus, we can say option A is correct.

Explanation:

When you pay for energy to heat your home, the energy initially heats your home. Over time, this energy eventually dissipates into the environment, resulting in what we perceive as loss of heat. Contrary to the idea of energy vanishing or turning into mass, the First Law of Thermodynamics assures us that energy is neither created nor destroyed but simply changes form. For instance, the heat produced by your furnace or heat pump eventually escapes to the outside. This process is an inherent part of nearly all energy usage; energy used for work or heating almost always winds up as thermal energy in the end.

Answer:

0.00579 M

Explanation:

Concentration of acid CA= 0.0338 M

Volume of acid VA= 12.0mL

Concentration of base CB= ??????

Volume of base VB= 35.00mL

Now we must write the equation of the reaction:

Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)

We can now write the number of moles of acid and base

Number of moles of acid NA= 2

Number of moles of base NB= 1

From:

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB= CA VA NB/ VB NA

CB=0.0338 × 12.0 × 1/ 35.0 × 2

CB= 0.00579 M

Answer:

[NaCl]: 2M

Explanation:

This solution is made of NaCl therefore:

Our solute is NaCl

Moles of solute: 4

Our solution's volume is 2L

Molarity are the moles of solute contained in 1L of solution (mol/L)

[NaCl]: 4 mol /2L = 2M

We can also make a rule of three:

In 2 L we have 4 moles of solute

So, In 1 L we must have (1 . 4) /2 = 2 M

The molarity of the solution is 2.0 M (moles per liter).

To determine the molarity of a solution, one must use the formula:

[tex]\[ \text{Molarity (M)} = \frac{\text{Number of moles of solute (n)}}{\text{Volume of solution (V)}} \][/tex]

Given that the solution contains 4.0 moles of NaCl (solute) and has a total volume of 2.0 liters, we can plug these values into the formula:

[tex]\[ \text{Molarity (M)} = \frac{4.0 \text{ moles}}{2.0 \text{ L}} \] \[ \text{Molarity (M)} = 2.0 \text{ M} \][/tex]

Therefore, the molarity of the solution is 2.0 moles per liter. This means that there are 2.0 moles of NaCl dissolved in every liter of the solution.

Answer: A change in the sequence of DNA bases--> Joining amino acids in sequence --> Appearance of characteristics

Explanation:

A mutation is a permanent shift or change from the normal DNA sequence that makes up a gene and affect traits which makes the sequence becomes different from what is commonly found in people. Mutations vary from distortion of a single DNA building block to a large segment of a chromosome.

When mutation occurs in a cell, for the mutation to affect the traits expressed by the particular cell, it must follow this sequence directly:

A change in the sequence of DNA bases--> Joining amino acids in the sequence --> Appearance of characteristics.

The correct sequence is: D) A change in the sequence of DNA bases --->Joining amino acids in sequence ----> Appearance of characteristic

The correct sequence for a mutation to affect cell traits is: a change in the DNA sequence, then joining amino acids in sequence, and finally the appearance of the characteristic.

The correct sequence is:

This sequence follows the principle that mutations in DNA alter the nucleotide sequence, which in turn changes the amino acid sequence in the proteins produced.

For example, in the case of Sickle Cell Anemia, a single base-pair substitution in the hemoglobin gene results in a different amino acid sequence, altering the shape and function of red blood cells.

Correct question is: A mutation occurs in a cell. Which sequence best represents the correct order of the events involved for this mutation to affect the traits expressed by this cell?
A) a change in the sequence of DNA bases ----> joining amino acids in sequence appearance of characteristic
B) joining amino acids in sequence ---> a change in the sequence of DNA bases appearance of characteristic
C) appearance of characteristic rarr joining amino acids in sequence ---> a change in the sequence of DNA bases
D) a change in the sequence of DNA bases ----> appearance of characteristic ---> joining amino acids in sequence

Answer:

NH3 and NH4+

Explanation:

NH4+ is the conjugate acid of the base NH3.

The example of base-conjugate acid pair is B. NH3 and NH4+.

A base-conjugate acid pair simply means a pair that consist of two substances that only differ by the presence of a proton (H+).

In this case, the example of base-conjugate acid pair is NH3 and NH4+ because bNH4+ is the conjugate acid of the base NH3.

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Answer:

A. 1 AgNO3 + 1 KCl ⇒ 1 AgCl + 1 KNO3 double replacement

B. 1 H2O + 1 SO3 ⇒ 1 H2SO4 synthesis

C. 2 KI + 1 Cl2 ⇒ 2 KCl + 1 I2 single replacement

D. 2 NaHCO3 ⇒ 1 Na2CO3 + 1 H2O + 1 CO2 decomposition

E. 1 Zn + 2 HCl ⇒ 1 ZnCl2 + 1 H2 single replacement

F. 1 BaCl2 + 1 Na2SO4 ⇒ 1 BaSO4 + 2 NaCl double displacement

G. 1 C3H8 + 5 O2 ⇒ 3 CO2 + 4 H2O combustion

H. 2 Al + 3 CuCl2 ⇒ 2 AlCl3 + 3 Cu single displacement

Explanation:

Use algebra to make sure you have the same amount of each element on each side (Reactants and Products) and only change the coefficients of the compounds and elements!

double displacement: AB + CD ⇒ AD + CB

single replacement: AB + C ⇒ A + CB

decomposition: A ⇒ B + C

synthesis: A + B ⇒ C

combustion: any reaction that involve oxygen and don't follow any of the previous reactions

To balance a chemical reaction equation, the number of atoms of each element on both sides of the reaction equation must be the same.

A chemical reaction equation has a right hand side (reactants side) and a left hand side (products side). The reactants combine to give the products. The number of atoms of each element on the reactants side must be exactly the same as the number of atoms of the same element on the products side.

The balanced chemical reaction equation for each of the reactions is shown below;

If there is no molar coefficient written in front of any of the species then the molar is 1.

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The answer for the following problem is mentioned below.

Explanation:

Given:

Initial volume ([tex]V_{1}[/tex]) = 230 ml

Final volume ([tex]V_{2}[/tex]) = 860 ml

Initial moles ([tex]n_{1}[/tex]) = 3.8 ×[tex]10^{-4}[/tex] moles

To find:

Final moles ([tex]n_{2}[/tex])

We know;

According to the ideal gas equation;

    P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of the moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

So;

    V ∝ n

[tex]\frac{V_{1} }{V_{2} }[/tex] = [tex]\frac{n_{1} }{n_{2} }[/tex]

where,

([tex]V_{1}[/tex]) represents the initial volume of the gas

([tex]V_{2}[/tex]) represents the final volume of the gas

([tex]n_{1}[/tex]) represents the initial  moles of the gas

([tex]n_{2}[/tex]) represents the final moles of the gas

Substituting the above values;

   [tex]\frac{230}{860}[/tex] = [tex]\frac{3.8 * 10^-4}{n_{2} }[/tex]

  [tex]n_{2}[/tex] = 14.2 × [tex]10^{-4}[/tex] moles

Therefore the final  moles of the gas is 14.2 × [tex]10^{-4}[/tex] moles.

Answer:

1.0 × 10-4 mol

Or just A. The first one

Explanation:

Just did it on eg

Answer:

      [tex][SOCl_2]=0.0218M[/tex]

Explanation:

The equations for a first order reaction are:

      [tex]\dfrac{d[A]}{dt}=-k[A][/tex]

      [tex][A]=[A_0]e^{-kt}[/tex]

      [tex]t\frac{1}{2}=\dfrac{\ln 2}{k}[/tex]

1. Calculate the constant of reaction, k:

Use the equation

                                [tex]t\frac{1}{2}=\dfrac{\ln 2}{k}[/tex]

     [tex]8.75h=\dfrac{\ln 2}{k}[/tex]

     [tex]k=\dfrac{\ln 2}{8.75h}[/tex]

     [tex]k\approx 0.0792168h^{-1}[/tex]

2. Calculate the concentration after 17.0 hours

Use the equation

                               [tex][A]=[A_0]e^{-kt}[/tex]

      [tex][SOCl_2]=0.0837M\cdot e^{-0.0792168h^{-1}\times 17.0h}[/tex]

      [tex][SOCl_2]=0.0218M[/tex]

Answer: [tex]t=\frac{Q}{I}[/tex]

Explanation:

[tex]I=\frac{Q}{t}[/tex]

Multiply by t on both sides.

[tex]t*I=\frac{Q}{t}*t[/tex]

[tex]tI=Q[/tex]

Now divide by I to isolate t.

[tex]\frac{tI}{I}=\frac{Q}{I}[/tex]

[tex]t=\frac{Q}{I}[/tex]

Final answer:

To solve for time t in the equation I = Q/t, multiply both sides by t to get t × I = Q, and then divide both sides by I to obtain[tex]t=\frac{Q}{I}[/tex].

Explanation:

To solve the equation, [tex]I= \frac{Q}{t}[/tex] for the variable t, you need to isolate t on one side of the equation. This can be done by rearranging the equation algebraically. Here's how it is done step-by-step:

Multiply both sides of the equation by t to get t × I = Q.

Next, divide both sides of the equation by I to solve for t, so we have [tex]t=\frac{Q}{I}[/tex].

Through these steps, we've successfully isolated t and found that the time (t) is equal to the charge (Q) divided by the current (I).

Answer:

0.64 L

Explanation:

Recall that

n= CV where n=m/M

Hence:

m/M= CV

m= given mass of solute =152g

M= molar mass of solute

C= concentration of solute in molL-1 = 1.5M

V= volume of solute =????

Molar mass of potassium permanganate= 158.034 g/mol

Thus;

152 g/158.034 gmol-1= 1.5M × V

V= 0.96/1.5

V= 0.64 L

Answer:

The volume of KMnO4 produced is = 16,013.7 Litres

Explanation:

Concentration = mass (in moles) ÷ volume (in litres)

1g = 158.03 moles

152g = 24,020.56 moles of KMnO4

1.5 M = mass (in moles) ÷ vol

⇒ Volume =  [tex]\frac{24,020.56} {1.5}[/tex]

= 16,013.7 Litres

Answer:

An amphoteric substance

Explanation:

Answer:

An atmospheric substance

For example is an aluminum hydroxide is atmospheric because it can act as a base and neutralize strong acids

Answer:

pH = 0.81

Explanation:

HCl reacts with aniline, thus:

C₆H₅NH₂ + HCl → C₆H₅NH₃⁺ + Cl⁻

Moles of HCl are:

0.085L × (0.35mol HCl / L) = 0.02975mol HCl

Moles of aniline are:

0.030L × (0.40mol HCl / L) = 0.012mol aniline

Thus, after reaction, will remain:

0.02975mol - 0.012mol = 0.01775mol HCl

Moles of HCl in solution are equal to moles of H⁺, thus, moles of H⁺ are: 0.01775mol H⁺

As total volume is 85.0mL + 30.0mL = 115.0mL ≡ 0.115L

0.01775mol / 0.115L = 0.1543M

pH of solution = -log[H⁺]

pH = -log 0.1543M

pH = 0.81

Answer:

pH = 0.81

Explanation:

Step 1: Data given

Volume of a 0.35 M HCl solution = 85.0 mL

Volume of a 0.40 M aniline solution = 30.0 mL

Kb of aniline = 3.8 * 10^-10

Step 2: The balanced equation

C6H5NH2 + HCl → C6H5NH3+ + Cl-

Step 3: Calculate moles

Moles = molarity * volume

Moles HCl = 0.35 M * 0.085 L

Moles HCl = 0.02975 moles

Moles aniline = 0.40 M * 0.030 L

Moles aniline = 0.012 moles

Step 4: Calculates limiting reactant

Aniline is the limiting reactant. It will completely be consumed (0.012 mole)

HCl is in excesS. There will react 0.012 moles. There will remain 0.02975 - 0.012 = 0.01775 moles

Step 5: Calculate molarity HCl

Molarity HCl = moles HCl / total volume

Molarity HCl = 0.01775 moles / 0.115 L

Molarity HCl = 0.154 M

Step 6: Calculate pH

pH = -log[H+]

pH = -log[0.154]

pH = 0.81

Answer:

The answer is 20.6 grams.

Explanation:

Molality describes the concentration of a solution. It can be defined as the number of moles of a solute dissolved in 1 kilogram of solvent. Then it is equal to the moles of solute (the substance that dissolves) divided by the kilograms of solvent (the substance used to dissolve):

[tex]Molality=\frac{number of moles of solute}{kilogram of solvent}[/tex]

The molality is expressed in units ([tex]\frac{moles}{kg}[/tex]).

So, you can apply the following rule of three with the solution being 0.5 molal: if in 1 kg of solution there are 0.5 moles of solute, in 0.4 kg (400 g, being 1kg = 1000g) how many moles of solute are there?

[tex]moles=\frac{0.4 kg*0.5 moles}{1 kg}[/tex]

moles=0.2 moles

Now, you know:

Then, The molar mass of sodium bromide NaBr is

NaBr= 23 g/mole + 80 g/mole= 103 g/mole

Now a new rule of three applies, if in 1 mole of sodium bromide there are 103 grams, in 0.2 mole how much mass is there?

[tex]mass=\frac{0.2 moles*103 grams}{1 mole}[/tex]

mass= 20.6 grams

The answer is 20.6 grams.

Answer:

52.80 % is the percent yield of the reaction.

Explanation:

Mass of nitrogen gas = 38.0 g

Moles of nitrogen = [tex]\frac{38.0g}{17 g/mol}=2.235 mol[/tex]

[tex]3H_2+N_2\rightarrow 2NH_3[/tex]

According to reaction, 1 moles of nitrogen gas gives 2 moles of ammonia, then 2.235 moles of nitrogen  will give:

[tex]\frac{2}{1}\times 2.235mol=4.470 mol[/tex]  ammonia

Mass of 4.470  moles of ammonia

= 4.470 mol × 17 g/mol = 75.99 g

Theoretical yield of ammonia = 217.8 g

Experimental yield of ammonia = 40.12 g

The percentage yield of reaction:

[tex]=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100[/tex]

[tex]=\frac{40.12 g}{75.99 g}\times 100=52.80\%[/tex]

52.80 % is the percent yield of the reaction.

Answer : The new pressure if the volume changes to 560.0 mL is, 280 mmHg

Explanation :

According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure = 560.00 mmHg

[tex]P_2[/tex] = final pressure = ?

[tex]V_1[/tex] = initial volume = 280 mL

[tex]V_2[/tex] = final volume = 560.0 mL

Now put all the given values in the above formula, we get:

[tex]560.00mmHg\times 280 mL=P_2\times 560.0 mL[/tex]

[tex]P_2=280mmHg[/tex]

Therefore, the new pressure if the volume changes to 560.0 mL is, 280 mmHg

Answer:

In compartment A, the solution will be concentrated with respect to compartment B, however, over time both compartments will have the same concentration. In compartment B it houses the cathode.

the voltage of the cell is 0.0315 V

Explanation:

Given:

Electrolyte in compartment A is 0.10 M

Electrolyte in compartment B is 0.87 M

Questions:

Which half-cell houses the cathode?

What is the voltage of the cell, V = ?

In both compartments, the reactions are:

A: Sn → Sn²⁺ + 2e⁻

B: Sn²⁺ + 2e⁻ → Sn

In compartment A, the solution will be concentrated with respect to compartment B, however, over time both compartments will have the same concentration. In compartment B it houses the cathode.

The voltage of the cell

[tex]V=E_{in} -\frac{0.0592}{nlog(C_{A} /C_{B} )}[/tex]

Here

n = 2 due the two electrons transferred

Ein = 0

Substituting values:

[tex]V=0-\frac{0.0592}{2*log(0.1/0.87)} =0.0315V[/tex]

Answer:

At 468.57 atm pressure the gas volume would change to 28 L.

Explanation:

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant.

This law can be expressed mathematically as:

P · V = k

where P is pressure, V is volume and k is a constant.

This formula can be used to determine the change in pressure or volume during an isothermal transformation (i.e. the temperature is constant) as follows:

P1 · V1 = P2 · V2

In this case,

Replacing:

410 atm*32L= P2*28 L

Solving:

[tex]P2=\frac{410 atm*32 L}{28L}[/tex]

P2=468.57 atm

At 468.57 atm pressure the gas volume would change to 28 L.