Sound travels through water at a speed of 1500 m/s. If the frequency of a sound is 1000 Hz, what is the wavelength?

Answer:

(a)  277.05 Ω

(b) 15.39 Ω

(c) 3.76 W

Explanation:

(a)

Applying,

P = V²/R.......................... Equation 1

Where P = Power dissipated by the string. V = Voltage source, R = equivalent resistance of the light string

Make R the subject of the equation

R = V²/P................... Equation 2

Given: V = 130, P = 61  W

Substitute into equation 2

R = 130²/61

R = 277.05 Ω

(b) The resistance of a single light is given as

R' = R/18 (since the light are connected in series and the are identical)

Where R' = Resistance of the single light.

R' = 277.05/18

R' = 15.39 Ω

(c)

Heat dissipated in a single light is given as

P' = I²R'..................... Equation 3

Where P' = heat dissipated in a single light, I = current flowing through each light.

We can calculate for I using

P = VI

make I the subject of the equation

I = P/V

I = 61/130

I = 0.469 A.

Also given: R' = 15.39 Ω

Substitute into equation 3

P' = 0.496²(15.39)

P' = 3.76 W

(a)The equivalent resistance of the light string is 277.05 Ω

(b)The power is dissipated in a single ligh15.39 Ω

(c)The resistance of the light string now3.76 W

(a) P is = V²/R.......................... Equation 1

Where P is = Power dissipated by the string.

Then V = Voltage source,

After that R is = the equivalent resistance of the light string

Now Make R the subject of the equation

R is = V²/P................... Equation 2

Then Given: V = 130,

P = 61 W

After that Substitute into equation 2

Then R = 130²/61

Therefore, R = 277.05 Ω

(b) When The resistance of a single light is given as

R' is = R/18 (since the light are connected in series and are identical)

Now Where R' is = Resistance of the single light.

R' is = 277.05/18

Therefore, R' is = 15.39 Ω

(c) When Heat dissipated in a single light is given as

P' is = I²R'..................... Equation 3

Where P' is = heat dissipated in a single light,

Then I = current flowing through each light.

Now We can calculate for I using

P is = VI

Now we make I the subject of the equation

After that I = P/V

Then I = 61/130

I is = 0.469 A.

Also given: R' is = 15.39 Ω

Then Substitute into equation 3

P' is = 0.496²(15.39)

Therefore, P' is = 3.76 W

Find more information about power is dissipates here:

https://brainly.com/question/104895

Answer:

[tex]\frac{g_{2}}{g_{1}} = \frac{1}{4}[/tex]

Explanation:

The period of the simple pendulum is:

[tex]T = 2\pi\cdot \sqrt{\frac{l}{g} }[/tex]

Where:

[tex]l[/tex] - Cord length, in m.

[tex]g[/tex] - Gravity constant, in [tex]\frac{m}{s^{2}}[/tex].

Given that the same pendulum is test on each planet, the following relation is formed:

[tex]T_{1}^{2}\cdot g_{1} = T_{2}^{2}\cdot g_{2}[/tex]

The ratio of the gravitational constant on planet CornTeen to the gravitational constant on planet Earth is:

[tex]\frac{g_{2}}{g_{1}} = \left(\frac{T_{1}}{T_{2}} \right)^{2}[/tex]

[tex]\frac{g_{2}}{g_{1}} = \left(\frac{2\,s}{4\,s} \right)^{2}[/tex]

[tex]\frac{g_{2}}{g_{1}} = \frac{1}{4}[/tex]

Answer:

d) The proper time interval depends upon the speed of the observer

Explanation:

Proper time is the time as measured by a clock moving with the body in motion.

The proper time interval between two events on a world line is the change in proper time, and it depends on the events and the world line connecting them, and also on the motion of the clock between the events.

Answer:

Explanation:

Given that,

Mass support is

M = 0.95g= 0.95/1000 = 0.00095kg

Radius of circle R = 0.205mm

r = 0.205/1000 = 0.000205m

Then, area of the circle can be determined using

A = πr²

A = π × 0.000205²

A = 1.32 × 10^-7 m²

From pressure definitions

Pressure = Force / Area

The force is perpendicular to the area

Force = weight = mg

F = mg = 0.00095 × 9.8

F = 9.31 × 10^-3 N

Then,

Pressure = Force / Area

P = F/A

P = 9.31 × 10^-3 / 1.32 × 10^-7

P = 70,530.30 N/m²

Since 1 pascal = 1 N/m²

Then,

P = 70,530.30 Pascals

To find the pressure exerted by the phonograph needle, multiply the weight of the needle by the gravitational constant to get the force, calculate the area of the needle tip using the given radius, and divide the force by the area using the pressure formula P = F / A.

The pressure exerted by the needle on the record can be calculated using the formula for pressure P = F / A, where F is the force (in this case the weight of the needle) and A is the area over which the force is applied (in this case the area of the needle tip).

First, you need to convert the weight of the needle into a force. Since weight is a force caused by gravity acting on a mass, you can find it by multiplying the mass of the needle by the acceleration due to gravity (g = 9.8 m/s²). So, F = 0.95 g * 9.8 m/s². However, you need to convert grams to kilograms (as 1g = 0.001kg). Hence, F = 0.95 * 0.001 kg * 9.8 m/s².

Next, you find the area of the very tip of the needle. Since the tip is circular, we use the formula for the area of a circle, A = πr², where r is the radius of the needle tip. Substituting r = 0.205 mm = 0.205 * 10^-3 m (since 1mm = 10^-3m) into the formula will give you the area.

Finally, substitute F and A into the formula P = F / A to find the pressure.

https://brainly.com/question/34682597

#SPJ11

Answer:

First of all note that The magnetic field produced by the vertical wire will be into on the right hand side and it will be out of the page on the left hand side

Assuming that the electron beam is coming from the right hand side of the page parallel to the wire, The direction of the velocity vector(V) is left and the direction of magnetic field due the wire(B) is into the page. If u use right hand rule, you will get the direction downwards but as the formula also depends on q , the charge on electron is negative .Therefore the direction will be inverted i.e Upwards.

If you assume the electron beam coming from left hand side.Then also u will get the same answer.

So, the angle α between the velocity of the electron and the magnetic field of the wire is 90°.

Explanation:

For an electron traveling parallel to a wire carrying an upward direction current, the angle between its velocity and the magnetic field of the wire, according to the right-hand rule, is 90 degrees.

The setting of this problem involves a vertical wire carrying an upward direction current and an electron traveling parallel to it. According to the right-hand rule in magnetism, which states that if your thumb points in the direction of the current, then your fingers will curl in the direction of the magnetic field, the magnetic field of the wire would form concentric circles around the wire.

For an electron traveling parallel to the wire, according to this rule, it would be always at a right angle or 90 degrees to the magnetic field as it moves along the circumference of these imaginary concentric circles. Therefore, the angle alpha (ααalpha) between the velocity of the electron and the magnetic field of the wire is 90 degrees.

https://brainly.com/question/36936308

#SPJ11

Answer:

see the attachment

Explanation:

In frequency spectrum there is no change in value of frequency of signal. However, The amplitude of signal after modulation increases. The fourier transform of sinwct is

1/2(F(w+wc) - F(w-wc))

For 2sinwct, the fourier transform is,

(F(w+wc) - F(w-wc))

In frequency domain, in AM only amplitude changes. Frequency remains same

Answer:

The linear mass  density is of the string  [tex]\mu= 5.51*10^{-3} kg / m[/tex]

Explanation:

    From the question we are told that

            The distance between wall and pulley is [tex]d = 0.405m[/tex]

            The mass on the hook is [tex]m = 25.4\ kg[/tex]

            The frequency of oscillation is  [tex]f = 261.6 Hz[/tex]

    Generally, the frequency of oscillation is mathematically  represented as

            [tex]f = \frac{1}{2d} \sqrt{\frac{T}{\mu} }[/tex]

Where T is the tension mathematically represented as

                T = mg

Substituting values

             [tex]T = 25.4 *9.8[/tex]

                [tex]=248.92N[/tex]

   [tex]\mu[/tex] is the mass linear density

Making  [tex]\mu[/tex] the subject of the formula above

            [tex]\mu = \frac{T}{(2df)^2}[/tex]

Substituting values

         [tex]\mu = \frac{248.92}{(2 * 0.405 * 261.6)^2}[/tex]

           [tex]\mu= 5.51*10^{-3} kg / m[/tex]

Answer:

0.005550 Kg/m

Explanation:

The picture attached below shows the full explanation

Answer:

The temperature reported by a thermometer is never precisely the same as its surroundings

Explanation:

In this experiment to determine the specific heat of a material the theory explains that when a heat interchange takes place between two bodies that were having different temperatures at the start, the quantity of heat the warmer body looses is equal to that gained by the cooler body to reach the equilibrium temperature. This is true only if no heat is lost or gained from the surrounding. If heat is gained or lost from the surrounding environment, the temperature readings by the thermometer will be incorrect. The experimenter should therefore keep in mind that for accurate results, the temperature recorded by the thermometer is similar to that of the surrounding at the start of the experiment and if it differs then note that there is either heat gained or lost to the environment.

When measuring the specific heat of a material, it is crucial to remember that thermometers require time to come into equilibrium with their surroundings for accurate temperature measurements. This ensures that the temperature readings accurately represent the material's temperature, which is essential for precise specific heat calculations.

The statement, "It may take a few minutes for a thermometer to come into equilibrium with its surroundings," is arguably the most helpful to keep in mind when conducting an experiment to measure the specific heat of a material. This principle is essential because it underlines the importance of allowing time for a thermometer to accurately reflect the temperature of the material it is measuring. Thermal equilibrium is a critical concept in thermodynamics, emphasizing that for accurate temperature measurement, both the thermometer and the material being tested must reach a state where no net heat flow occurs between them. This ensures that the temperature reading is actually representative of the material's temperature, rather than being influenced by initial differences in temperature between the thermometer and the material.

Understanding this concept is vital when measuring specific heat because specific heat calculations rely on accurate temperature measurements before and after a heat transfer occurs. If the thermometer does not accurately reflect the material's temperature due to inadequate time for equilibrium, the calculated specific heat could be significantly off.

Answer:

Δx = 3.477 x 10⁻³ m = 3.477 mm

Explanation:

The distance between two consecutive dark fringes is given by the following formula, in Young's Double Slit experiment:

Δx = λL/d

where,

Δx = distance between two consecutive dark fringes = ?

λ = wavelength of light = 4.9 x 10² nm = 4.9 x 10⁻⁷ m

L = Distance between slits and screen = 2.2 m

d = slit separation = 0.31 mm = 0.31 x 10⁻³ m

Therefore,

Δx = (4.9 x 10⁻⁷ m)(2.2 m)/(0.31 x 10⁻³ m)

Δx = 3.477 x 10⁻³ m = 3.477 mm

The distance (in mm) between the first and second dark fringes of the

interference pattern is 3.477 mm

This is calculated by using the formula in Young's Double Slit experiment:

Δx = λL/d

where,

Δx = distance between two consecutive dark fringes which is unknown

λ which is wavelength of light = 4.9 x 10² nm = 4.9 x 10⁻⁷ m

L which is distance between slits and screen = 2.2 m

d which is slit separation = 0.31 mm = 0.31 x 10⁻³ m

We then substitute them into the equation

Δx = (4.9 x 10⁻⁷ m ×2.2 m)/(0.31 × 10⁻³ m)

Δx = 3.477 x 10⁻³ m = 3.477 mm

Read more on https://brainly.com/question/15857255

Answer:

Explanation:

Given that,

Distance between speaker

L = 4.5m

Minimum intensity at L1 = 0.21m

Speed of sound is

V = 340m/s

A. Frequency of sound f?

The path difference Pd

Distance from the first speaker when you are 0.21m away

d1 = 2.25 + 0.21 = 2.46m

Distance from the second speaker when you move 0.21m closer

d2 = 2.25—0.21 = 2.04m

So, path difference is

Pd = ∆d = d1 — d2

Pd = 2.46—2.04 = 0.42m

Using the destructive interference condition

∆d = (m + ½)λ

m = 0,1,2,3....

When m= 0

∆d = ½λ

0.42 = ½λ

λ = 0.84

Then, using wave equation

v = fλ

Then, f = v / λ

f = 340 / 0.84

f = 404.76Hz

B. Incorrect question

If he is to remain at his initial positions then it is 0.21m from the center.

Then,

Constructive interference is given as

∆d = mλ

Where m = 0,1,2,3

So when m= 1

∆d = λ

And we already got the path difference to be 0.42m

So, ∆d = λ

λ = 0.42

So, applying wave equation

V = fλ

F = v/λ

F = 340/0.42

F = 809.52 Hz

But if we are to use the data given in part B

0.35m from the center..

Following the same principle as part A, the path difference will be 0.35

Therefore, since ∆d = λ

Then, λ = 0.35

So, f, = v/λ

F = 340 /0.35

F = 971.43 Hz

Answer:

option (b)

Explanation:

mass of proton, mp = m

mass of deuteron, md = 2m

charge on proton, qp = q

charge on deuteron, qd = q

The magnetic force on the charged particle when it is moving is given by

F = q v B Sinθ

where, θ is the angle between the velocity and magnetic field.

Here, θ = 90°

Let v is the velocity of both the particle when they enters in the magnetic field.

The force on proton is given by

Fp = q x v x B ...... (1)

The force on deuteron is

Fd = q x v x B .... (2)

Divide equation (1) by equation (2)

Fp / Fd = 1

Thus, the ratio of force on proton to the force on deuteron is 1 : 1.

Thus, option (b) is correct.

Answer:

The answer is: c. It does not move

Explanation:

Because the gravitational force is characterized by being an internal force within the Earth-particle system, in this case, the object of mass M. And since in this system there is no external force in the system, it can be concluded that the center of mass of the system will not move.

As the object is dropped at a constant downward force, the center mass of the object-Earth system does not move.

In the absence of an external force, the center mass of the object-Earth system will remain constant as the object fall to the ground.

The force of attraction on the object above the surface of the Earth is given as;

[tex]F = \frac{Gm_1 m_2}{R^2}[/tex]

where;

Thus, as the object is dropped at a constant downward force, the center mass of the object-Earth system does not move.

Learn more about center mass here: https://brainly.com/question/20877552

Answer:

the density of a blue block is ___twice _____ the density of a red block.

Explanation:

If both blocks have the same mass, then the block with the lesser volume will be more densely packed when compared to the block with the larger volume. This is because the molecules are more closely packed.

Check the image below for detailed calculations for proof

If the blue block and red block have the same mass but different volumes - specifically, the blue block's volume is half that of the red block - then the density of the blue block is twice that of the red block.

Given the blocks weigh the same, their masses are equal. Density is defined as mass per unit volume (mass/volume), meaning the density is influenced by both the mass and the volume of an object. As the red and blue blocks have different volumes, their densities must be different if their masses are the same.

In the case of the blue block and the red block, the blue block has half the volume of the red block but the same mass. Thus, because the blue block's volume is half that of the red block but the mass is the same, the density of the blue block is twice the density of a red block, not half. This is because the proportion of mass to volume in the blue block is larger than in the red block. In other words: Density of blue block = 2 * Density of red block.

https://brainly.com/question/29775886

#SPJ3

Answer:

Explanation: check the attached document for step by step solution.

Answer:

Electric potential is associated with electric fields due to static charges but not with induced electric fields.

Explanation:

An electric potential is the amount of work needed to move a unit charge from a reference point to a specific point inside the field without producing an acceleration. Typically, the reference point is the Earth or a point at infinity. Induced electricity is as a result of changing magnetic flux linkage (no charge is involved)

Electric potential is related to the electrostatic field created by static charges and is given by V = kQ/r; it is not related to induced electric fields or magnetic fields because they are nonconservative.

Electric potential is associated with electric fields due to static charges but not with induced electric fields.

This is because electric potential is defined for conservative fields, such as those produced by static charges, where the potential difference is related to the work done in moving a charge between two points in the field.

For point charges, the electric potential is given by the equation V = kQ/r, which clearly illustrates that electric potential depends on the charge and the distance from it.

On the other hand, induced electric fields are produced by changing magnetic fields and are nonconservative.

Nonconservative fields do not have a well-defined electric potential because the work done to move a charge can vary depending on the path taken, unlike the work done in a conservative electrostatic field.

Therefore, electric potential cannot be associated with induced electric fields or magnetic fields.

The correct question is;

An object of mass m attached to a spring of force constant K oscillates with simple harmonic motion. The maximum displacement from equilibrium is A and the total mechanical energy of the system is E.

What is the system's potential energy when its kinetic energy is equal to ¾E?

Answer:

P.E = ⅛KA²

Explanation:

From conservation of energy, the total energy in the system is given as the sum of potential and kinetic energy.

Thus,

Total Energy; E = K.E.+P.E.

In simple harmonic motion, the total energy is given by;

E = ½KA²

We are told that kinetic energy is ¾E.

Thus, ½KA² = ¾(½KA²) + P.E

P.E = ½KA² - ⅜KA²

P.E = ⅛KA²

Final answer:

A longitudinal wave, like a transverse wave, has properties of amplitude, frequency, wavelength, and speed. These characteristics define the wave's physical behavior and are related by the equation v = fλ, where 'v' is wave speed, 'f' is frequency, and 'λ' is wavelength. Option 2 is correct.

Explanation:

Like a transverse wave, a longitudinal wave has amplitude, frequency, wavelength, and speed. Both types of waves have these fundamental properties, but the way they propagate through mediums is different. In longitudinal waves, the particles of the medium move parallel to the wave's direction of travel, while in transverse waves, particles move perpendicular to the direction of the wave's travel. An example of a transverse wave is a wave on a string, like when playing a guitar. In contrast, sound waves in air are longitudinal waves.

The wavelength (λ) is the distance between adjacent identical parts of the wave, which can be considered from one compression to the next in the case of longitudinal waves. Wave speed (v) is the rate at which the wave travels through the medium. The frequency (f) is the number of wave cycles that pass a given point per unit time, and amplitude refers to the maximum displacement from the equilibrium position within the wave cycle.

It's important to remember that all these properties are related: the speed of a wave is given by the product of its frequency and wavelength (v = fλ).

Answer:

how large a magnetic field would you experience = 8.16 x 10∧-4T

Explanation:

I = 20KA = 20,000A

r = 4.9 m

how large a magnetic field would you experience =  u.I/2πr

how large a magnetic field would you experience = (4π x10∧-7) × 20000/2π × 4.9

how large a magnetic field would you experience = 8.16 x 10∧-4T

Answer: 8.16*10^-4 T

Explanation:

Given

Current of the lightening bolt, I = 20 kA

Distance from the strike of the lightening bolt, r = 4.9 m

To solve, we use the formula

B = [μ(0) * I] / 2πr, where

B = magnetic field of the lightening

μ = permeability constant = 4π*10^-7 N/A²

I = current of the lightening

r = distance from the lightening strike

B = [(4 * 3.142*10^-7) * 20*10^3] / (2 * 3.142 * 4.9)

B = (12.568*10^-7 * 20*10^3) / 6.284 * 4.9

B = 0.025 / 30.79

B = 8.16*10^-4 T

The magnetic field to be experienced would be 8.16*10^-4 T large

Answer:They established the laws of planetary motion.(option B)

Answer:

They established the laws of planetary motion

Explanation:

i did it on edge

Answer:

Explanation:

d.All of the above

Final answer:

All the listed devices -- bathroom scale, spring scale, and force sensor -- can be used to measure force. Bathroom and spring scales measure the weight of an object, which is a force, and display it typically in kilograms after calibration while force sensors provide direct measurement in newtons.

Explanation:

Devices that can be used to measure force include a bathroom scale, a spring scale, and a force sensor. All of these devices measure force, which can be the weight of an object (the force due to gravity acting on the object). A bathroom scale, for example, measures the normal force exerted by a person standing on it and gives a reading in kilograms by dividing the force in newtons by the acceleration due to gravity (9.80 m/s2). However, it is calibrated to display mass. A spring scale uses the extension of a spring under load to measure force which is typically indicated in newtons or pounds. Lastly, a force sensor is a more general device that can directly measure the force exerted on it in newtons and is often used for more precise scientific measurements.

If you stood on a bathroom scale in an elevator, the reading would change depending on the elevator's motion. The scale would display a higher value when the elevator starts moving upward (accelerating) due to the increase in the normal force. However, when the elevator moves at a constant speed, the scale would read your normal weight as no additional normal force is required once you're moving at constant velocity.

To solve this problem we must find the values of the equivalent resistances in both section 1 and section 2. Later we will calculate the total current and the total voltage. With the established values we can find the values of the currents in the 3 Ohms resistance and the power there.

The equivalent resistance in section 1 would be

[tex]R_{eq1} = \frac{(3\Omega)(6\Omega)}{(3+6)\Omega}[/tex]

[tex]R_{eq1} = 2\Omega[/tex]

The equivalent resistance in section 2 would be

[tex]R_{eq2} = R_{eq1} +4\Omega[/tex]

[tex]R_{eq2} = 6\Omega[/tex]

Now the total current will be,

[tex]I_t = \frac{V_t}{R_{eq2}}[/tex]

[tex]I_t = \frac{12V}{6\Omega}[/tex]

[tex]I_t = 2.0A[/tex]

Finally the total Voltage will be,

[tex]V = IR_{eq1}[/tex]

[tex]V = (2.0A)(2.0\Omega)[/tex]

[tex]V = 4V[/tex]

Since the voltage across the 3 and 6 Ohms resistor is the same, because they are in parallel, the current in section 3 would be

[tex]I_{3.0\Omega} = \frac{V}{R}[/tex]

[tex]I_{3.0\Omega} = \frac{4.0V}{3.0\Omega}[/tex]

[tex]I_{3.0\Omega} = 1.3A[/tex]

Finally the power ratio is the product between the current and the voltage then,

[tex]P_{3.0\Omega} = I_{3.0\Omega} V[/tex]

[tex]P_{3.0\Omega} = (1.3A)(4.0V)[/tex]

[tex]P_{3.0\Omega} = 5.3W[/tex]

Therefore the correct answer is D.

Final answer:

To find the power dissipated in the 3.0-Ω resistor, calculate the total resistance and current, then apply Ohm's law to find the voltage across and current through the resistor. Finally, use the power formula P = V²/R, resulting in a power dissipation of (a) 12 W for the 3.0-Ω resistor.

Explanation:

The question deals with finding the power dissipated in the 3.0-Ω resistor. To answer this, we first need to find the total resistance of the circuit and the current through the circuit. We then apply this current to the parallel resistors to find the voltage across and the current through the 3.0-Ω resistor before calculating its power dissipation.

First, calculate the resistance of the resistors in parallel. Using the formula for resistors in parallel:

1/Rparallel = 1/R₁ + 1/R₂

1/Rparallel = 1/3.0 + 1/6.0

1/Rparallel = 1/3 + 1/6 = 2/6 + 1/6 = 3/6

1/Rparallel = 1/2

Rparallel = 2.0 Ω

Now, add the series resistor to find the total resistance:

Rtotal = Rparallel + Rseries

Rtotal = 2.0 + 4.0 = 6.0 Ω

Then, using Ohm's law, calculate the total current from the battery:

I = V/Rtotal

I = 12V/6.0Ω

I = 2.0 A

The current through the 3.0-Ω resistor in parallel is the same as the total current, so we use Ohm's law V = IR to find the voltage across the 3.0-Ω resistor:

V3.0-Ω = 2.0 A × 3.0 Ω = 6.0 V

Finally, calculate the power dissipated by the 3.0-Ω resistor:

P = V2/R

P = (6.0 V)2/3.0 Ω

P = 36 W/3.0 Ω

P = 12 W

Therefore, the power dissipated in the 3.0-Ω resistor is 12 W, which corresponds to choice (a).

To solve this problem we will apply the concepts related to the principle of destructive and constructive interference. Mathematically this expression can be given as

[tex]2nt = m\lambda[/tex]

Here,

n = Index of refraction

t = Thickness

m = Order of the reflection

[tex]\lambda[/tex] = Wavelength

We have all of this values, therefore replacing,

[tex]2(1.28)t = (1)(600nm)[/tex]

[tex]t = 233nm[/tex]    

Therefore the thickness of the oil slick is 233nm

Answer:

(a)  change in the internal energy of the gas is zero

(b) the work done by the gas is 16.93 kJ

(c) the heat flow is 16.93 kJ, which is into the gas

Explanation:

Given;

number of moles of gas, n = 6.35 moles

temperature of the gas, T = 320 K

initial volume of the gas, V₁ = 1.45 L

final volume of the gas, V₂ = 3.95 L

Part (a)

For isothermal expansion, temperature is constant and internal energy will also be constant.

Therefore, change in the internal energy of the gas is zero since the gas expanded isothermally (constant temperature).

ΔU = Q - W

where;

ΔU is change in internal energy

Q is heat transferred to the system

W is the work done by the system

Thus, Q = W

ΔU = 0

Part (b)

the work done by the gas

[tex]W = nRTln{[\frac{V_2}{V_1}][/tex]

where;

R is gas constant = 8.314 J/mol.K

[tex]W = (6.35)(8.314)(320)ln{[\frac{3.95}{1.45}]}\\\\W =16930.4\ J\\\\W = 16.93\ kJ[/tex]

Part (c)

the heat flow into or out of the gas

Q = ΔU + W

Q = 0 + 16.93 kJ

Q = 16.93 kJ

Since the heat flow is positive, then it is heat flow into the gas.

To solve this problem we will use the concepts related to the electromagnetic force related to the bases founded by Coulumb, the mathematical expression is the following as a function of force per unit area:

[tex]\frac{F}{L} = \frac{kl_1l_2}{d}[/tex]

Here,

F = Force

L = Length

k = Coulomb constant

I =Each current

d = Distance

Force of the wire one which is located along the line y to 0.47m is [tex]305*10^{-6}N/m[/tex] then we have

[tex]l_2 = \frac{F}{L} (\frac{d}{kl_1})[/tex]

[tex]l_2 = (305*10^{-6}N/m)(\frac{0.470m}{(2*10^{-7})(25A))})[/tex]

[tex]l_2 = 28.67A[/tex]

Considering the B is zero at

[tex]y = y_1[/tex]

[tex]\frac{kI_2}{2\pi y} =\frac{kI_1}{2\pi y_1}[/tex]

[tex]\frac{(4\pi*10^{-7})(28.67)}{2\pi (y_1)} = \frac{(4\pi *10^{-7})(25)}{2\pi (0.47-y_1)}[/tex]

[tex]y_1 = 0.25m[/tex]

Therefore the value of y for the line in the plane of the two wires along which the total B is zero is 0.25m

Answer:

Explanation:

Given that,

Initial speed of the girl is

u = 1.4m/s

Height she is going is

H = 2.45m

Incline plane she will pass to that height

L = 12.4m

Mass of girl and bicycle is

M=60kg

Frictional force that oppose motion is

Fr = 41N

Speed at lower end of inclined plane

V2 = 6.7m/s

Work done by the girl when the car travel downward

Using conservation of energy

K.E(top) + P.E(top) + work = K.E(bottom) + P.E(bottom) + Wfr

Where Wfr is work done by friction

Wfr = Fr × d

P.E(bottom) is zero, sicne the height is zero at the ground

K.E is given as ½mv²

Then,

½M•u² + MgH + W = ½M•V2² + 0 + Fr×d

½ × 60 × 1.4² + 60×9.8 × 2.45 + W = ½ × 60 × 6.7² + 41 × 12.4

58.8 + 1440.5 + W = 1855.1

W = 1885.1 —58.8 —1440.5

W = 355.8 J

Answer:

Explanation:

Given that,

Current in wire is

I = 10A

And the current makes an angle of 30° with respect to the magnetic field

Then, θ = 30°

And the magnetic field is

B = 0.3 T

Length of the wire is

L = 0.5m

Force on the wire F?

The force on the wire in calculated using

F = iL × B

Where

The magnitude of the cross produce of L and B is

L × B = LB•Sinθ

Then, force becomes

F = iLB•Sinθ

F = 10 × 0.5 × 0.3 × Sin30

F = 0.75 N

The force on the wire is 0.75 Newton

Answer:

The magnitude of the magnetic force on the wire is 0.75 N

Explanation:

Given;

current in the wire, I = 10 A

angle of inclination to magnetic field, θ = 30°

magnetic field strength, B = 0.30-T

length of the wire, L = 0.50-m

The magnitude of magnetic force acting on the wire is given as;

F = BILSinθ

where;

B is magnetic field strength

I is the current in the wire

L is length of the wire

θ is the angle of inclination

F = 0.3 x 10 x 0.5 x sin(30)

F = 0.3 x 10 x 0.5 x 0.5

F = 0.75 N

Therefore,  the magnitude of the magnetic force on the wire is 0.75 N

Answer:

The total length of the spring would be 0.65 m

Explanation:

The Concept

Hooke's law evaluates the increment of  spring in relation to the force acting on the body. Hooke's law states that for a spring undergoing deformation, the  force applied is directly proportional to the deformation experienced by the spring. Hooke's law is represented thus;

F = k x ..................1

where F is the force applied to the spring

k is the spring constant

x is the spring stretch or extension

Step by Step Calculations

We have to obtain x before adding it to the nominal length, We make x the subject formula in equation 1;

x = F/k

but F = m x g

so, x = (m x g)/k

given that, the mass of the person m =150 kg

g is the acceleration due to gravity = 9.81 m/[tex]s^{2}[/tex]

k is the spring constant = 10000 N/m

then x = (9.81 m/[tex]s^{2}[/tex] x 150 kg)/10000 N/m

x = 0.14715 m

the extension experienced by the spring after the compression is 0.14715 m

The total length of the spring would be;

L = 0.14715 m + 0.5 m = 0.64715

L ≈  0.65 m

Therefore the total length of the spring would be 0.65 m

Answer:

Intensity will be equal to [tex]3.07\times 10^{-6}W/m^2[/tex]

Explanation:

We have given power P = 197 kW = 197000 watt

Distance R = 101 km

Area of the hemisphere will be [tex]A=2\pi R^2[/tex]

[tex]A=2\times 3.14\times 101000^2=6.4\times 10^{10}m^2[/tex]

We have to find the intensity

Intensity is equal to [tex]I=\frac{P}{A}[/tex]

[tex]I=\frac{1.97\times 10^5}{6.4\times 10^{10}}=3.07\times 10^{-6}W/m^2[/tex]

So intensity will be equal to [tex]3.07\times 10^{-6}W/m^2[/tex]

Complete Question

 The complete question is shown on the first uploaded image

Answer:

The magnetic field is [tex]B_{net} = \frac{1}{4} * mT[/tex]

And the direction is  [tex]-\r k[/tex]

Explanation:

      From the question we are told that

                 The magnetic field at the center is [tex]B = 1mT[/tex]

Generally magnetic field is mathematically represented as

              [tex]B = \frac{\mu_o I}{2R}[/tex]

We are told that it is equal to 1mT

So

                [tex]B = \frac{\mu_o I}{2R} = 1mT[/tex]

From the first diagram we see that the effect of the current flowing in the circular loop is  (i.e the magnetic field generated)

                         [tex]\frac{\mu_o I}{2R} = 1mT[/tex]

 This implies that the effect of a current flowing in the smaller semi-circular loop is (i.e the magnetic field generated)

                   [tex]B_1 = \frac{1}{2} \frac{\mu_o I}{2R}[/tex]

and  for the larger semi-circular loop  is

                 [tex]B_2 = \frac{1}{2} \frac{\mu_o I}{2 * (2R)}[/tex]

Now a closer look at the second diagram will show us that the current in the semi-circular loop are moving in the opposite direction

    So the net magnetic field would be

                   [tex]B_{net} = B_1 - B_2[/tex]

                        [tex]= \frac{1}{2} \frac{\mu_o I}{2R} -\frac{1}{2} \frac{\mu_o I}{2 * (2R)}[/tex]

                        [tex]=\frac{\mu_o I}{4R} -\frac{\mu_o I }{8R}[/tex]

                        [tex]=\frac{\mu_o I}{8R}[/tex]

                        [tex]= \frac{1}{4} \frac{\mu_o I}{2R}[/tex]

Recall  [tex]\frac{\mu_o I}{2R} = 1mT[/tex]

    So  

             [tex]B_{net} = \frac{1}{4} * mT[/tex]

Using the Right-hand rule we see that the direction is into the page which is [tex]-k[/tex]