In a collision between two 300 kg spaceships, one at rest and the other moving at 6 m/s, the final velocity after they stick together is 2 m/s.
When two objects with masses of 300 kg collide and stick together, their momentum is conserved. Utilizing the principle of conservation of momentum, we can calculate their final velocity after the collision.
In this case, since both spaceships have equal masses and one is at rest while the other moves with a known speed, the final velocity after the collision would be 2 m/s.
The business practice of hiring workers in another country is known as globalization. insourcing. subcontracting. outsourcing.
The business practice of hiring workers in another country is known as outsourcing.
What is outsourcing?
Outsourcing is a business practice of hiring worker from outside country. This practice is done with the aim getting cheap labour force, or getting efficient labour force.
This business practice (outsourcing) can also be seen as transferring of employees and assets from one firm to another.
Thus, the business practice of hiring workers in another country is known as outsourcing.
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The business practice of hiring workers in another country is known as outsourcing. Hence, option D is correct.
What is outsourcing?Outsourcing is the business practice of hiring a party to perform services and goods. It results in the globalization of markets and it drives maximum profits.
It is also defined as a company hiring a third party or a company to perform their task and to provide service for the company. Examples of outsourcing are advertising, website development, etc.
Outsourcing can help to reduce labor costs and enable them to work for less money. It helps the company to focus on the core aspects of the business. The outsourcing process leads to running a successful business model.
Outsourcing has the biggest advantage in time and money savings. Adapting outsourcing helps in gaining profit, increasing efficiency, and can control costs.
Hence, the business practice of hiring workers in another country is known as outsourcing. Thus, the correct option is D.
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If Mary is 3m from her reflection, how far is mary from the mirror?
Final answer:
Mary is 1.5m from the mirror, as the distance to her reflection, which is 3m, includes the distance to the mirror and the equal distance from the mirror to the reflection.
Explanation:
If Mary is 3m from her reflection in a mirror, it implies that she is 1.5m from the mirror itself. This is because the law of reflection states that the distance from the object to the mirror is equal to the distance from the mirror to the image of that object. Therefore, in this case, the 3m distance is double the actual distance between Mary and the mirror since it includes the path to the mirror and the equal path from the mirror to the image.
How does universal gravitation affect you and objects around you?
Answer:
Newton proposed the "law of Universal Gravitation". He said that gravity is universal in nature and it affects all the objects. Gravity is present between you and every object having mass around you. The "Strength of the gravity" between two objects with mass is depends on the product of masses and distance between the objects.
The "Gravitational force" increases with the increase in mass of the objects and decreases with the increase in distance between the objects. The gravity exerts a force on every object. The direction of force of gravity is towards the centre of the Earth.
Which are examples of convection currents ? Select three options.
marshmallows toasting over a campfire
a pot being heated by an electric burner
rice moving in a pot of water that is being heated
a radiator that emits warm air and draws in cool air
a hot air balloon rising and falling in the atmosphere
Answer:
(B) A pot being heated by an electric burner
(D) A radiator that emits warm air and draws in cool air
(E) A hot air balloon rising and falling in the atmosphere
These are some of the examples of the convection currents.
Explanation:
Earlier, electrons were believed to have positive charges and then electric current were discovered. But later after the invention of electric current and current which is termed to be the flow of electrons and is usually flows from negative to positive terminal. But its convention is not discarded in which current moves from positive terminal to negative and it is called convention current. The direction of current shown in the circuit is said to be the convention current.
Hence, the following are the examples of convention current.
1. Boiling water - The energy travels into the pot from the burner, boiling down the water. Then this warm water is accumulating on the top and colder one is heading down to absorb it, triggering a circular motion.
2. Radiator - Place hot air at the peak and pull cool air at the bottom.
3. Hot air balloon - The air is warmed up by a heating element within the balloon, so the air jumps upwards. This induces the balloon to increase in size due to the inside trapping of the warm air. He removes a few of the warm air when the pilot commences to dive, and cold air takes place, enabling the parachute to drop.
Your answer is.
(B) a pot being heated by an electric burner
(D) a radiator that emits warm air and draws in cool air
(E) a hot air balloon rising and falling in the atmosphere
Hope this helps you and you pass your test good luck my friend!
A 42 kg object is 2.5 m from a 55kg object. How much is the force of attraction between them?
Answer:
Force of attraction is 2,46*10^-8N[tex]F= G*(m1*m2/r^2)\\where \\\\G=6,67*10^-11 (N*m^2/kg^2)\\m1=42kg\\m2=55kg\\r=2,5m\\therefore\\F=6,67*10^-11*(42*55/2.5^2)\\
F=2,46*10^-8 N[/tex]
Explanation:
Using the Law of Universal Gravitation, proposed by Newton.
Two mechanical waves that have positive displacements from the equilibrium position meet and coincide. What kind of
interference occurs?
a constructive
C. complete destructiv
b. destructive
none
When two mechanical waves that have positive displacements from the equilibrium position meet and coincide, a constructive interference occurs.
Option A
Explanation:Considering the principle of superposition of waves; the resultant amplitude of an output wave due to interference of two or more waves at any point is given by individual addition of their amplitudes at that point. Two waves with positive displacements refer to the fact that crest of the both the waves are on the same side of displacement axis, either both are positive or both are negative, similarly with their troughs.
If such two waves with their crest on crest meet at any point, by superposition principle. their individual amplitude gets added up and hence the resultant wave after interference is greater in amplitude that both the individual waves. This is termed as a constructive interference. Destructive interference on the other hand is a condition when one of the two waves has a positive displacement and other has a negative displacement (a condition of one’s crest on other’s trough); resulting in amplitude subtraction.
Which of the following is a scalar quantity?
a. 35m
b. 20 m to the right
c. 30 m to the North
d. All of the above
The only scalar quantity is a. 35 m
Explanation:
In physics, there are two types of quantities:
- Scalar: a scalar quantiy is a quantity having only a magnitude, so it is just a number followed by a unit. Examples of scalar quantities in physics are:
Speed
Energy
Distance
Time
- Vector: a vector quantity is quantity having both a magnitude and a direction. Examples of vector quantities in physics are:
Velocity
Force
Acceleration
Displacement
Let's now analyze each given option, to evaluate if it is a scalar or a vector:
a. 35m --> it is only a unit (no direction), so it is a scalar
b. 20 m to the right --> it has a direction, so it is a vector
c. 30 m to the North --> it has a direction, so it is a vector
So, the only correct option is a).
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When using the right-hand rule to determine the direction of the magnetic field around a current-carrying wire, which part of the
right hand points in the direction of the magnetic field?
-palm
-fingers
-back
-thumb
Answer:
Fingers
Explanation:
The index finger shows the moving charge, while your middle finger shows the magnetic field line.
Answer: Palm
Explanation: When you have a wire, you must point your thumb in the direction in which the electricity is going, and now you close your palm, in the direction in which you closed your hand is in the direction in which points the magnetic field.
Then the correct option is the first one, the palm points in the direction of the magnetic field.
How far does a ca4 go
Answer:
as far as the car can withstand
Explanation:
What scientific question does Isaac Asimov most clearly address with his
story "Runaround"?
A. Should robots be allowed to marry?
B, should robots be treated as members of the family?
C. Can robots be trained to follow a moral code?
D.
Can robots be trained to be the sole caretakers of children?
Answer: C. can robots be trained to follow a moral code?
Explanation:
Answer:
Its C
Explanation:
23. Challenge: A gas is heated so that it expands from a volume of 1.0L to a volume of 1.5 l. If the
initial temperature of the gas was 5.0°C, then what is the final temperature of the gas?
417 K is the “final temperature” of the gas.
Explanation:
According to “Charles law” the change in “volume” of a given mass of gas expanded is “directly proportional” to the “temperature” of the given gas expanded. When we keep “pressure” of the gas as constant. Mathematically,
[tex]v \alpha T[/tex]
[tex]\frac{v}{T}=\text { constant }[/tex]
If gas is expanded from initial volume to final volume and initial temperature to final temperature then,
[tex]\frac{v_{1}}{T_{1}}=\frac{v_{2}}{T_{2}}[/tex]
[tex]\begin{array}{l}{\text { Where, } v_{1} \text { and } v_{2} \text { are the initial and final volumes of the gas expanded recpectively,}} \\ {T_{1} \text { and } T_{2} \text { are the initial and final temperatures of the gas expanded recpectively }}\end{array}[/tex]
Given that,
Initial volume is 1.0L
Final volume is 1.5L
[tex]\text { Initial temperatureis } 5.0^{\circ} \mathrm{C}=5+273=278 \mathrm{K}[/tex]
To find final temperature of the gas
Substitute the given values,
[tex]\frac{1}{278}=\frac{1.5}{T_{2}}[/tex]
[tex]T_{2}=1.5 \times 278[/tex]
[tex]T_{2}=417 K[/tex]
Therefore, final temperature of the gas after expanding is 417 K.
To calculate the final temperature of an expanding gas, you can use Charles's Law, which relates volume and temperature. By substituting the given values into the Charles's Law equation and solving for the final temperature in Kelvin, and then converting it to Celsius, you can find the final temperature of the gas.
Explanation:To find the final temperature of a gas that has expanded, we can use Charles's Law. This law states that at constant pressure, the volume of a given mass of an ideal gas increases or decreases by the same factor as its temperature (in Kelvin) increases or decreases. The formula is: V1/T1 = V2/T2, where V is volume and T is temperature (in Kelvin).
The initial volume (V1) is 1.0L, and the final volume (V2) is 1.5L. The initial temperature (T1) is 5.0°C, which is 278.15K. To find the final temperature in Kelvin (T2), rearrange the formula to get T2 = V2*T1/V1. Substituting in the values gives T2 = (1.5L * 278.15K) / 1.0L. Calculating this gives us a value for T2. To convert T2 back to Celsius, subtract 273.15 from the Kelvin temperature.
A 55 kg person is sitting in a car that hits a concrete floor.The car was moving at 30 m/s and came to a halt in 0.35s.What is the average force that the seatbelt exerts on the person.
Answer:
-4714.28N
Explanation:
Given
Mass of person, m= 55 kgCar speed initially ,u =30[tex]\frac{m}{sec}[/tex]Car speed finally, v=0(car comes to a halt)Duration for the car to come halt,t=0.35 secThis question is based on the concept of Impulse
Impulse is the force acting in a time interval(usually very short)
it is equal to force multiplied with time and also equal to change in momentum of body
⇒[tex]F\times t= mv-mu\\F \times0.35= 55\times (0-30)\\F\times 0.35= -1650\\F= -4714.28 N[/tex]
Therefore the seat belt exerts a force of -4718.28N on the person
The negative sign signifies that seat belt exerts force in opposite direction of Force
The average force exerted by the seatbelt on a 55 kg person in a car that decelerates from 30 m/s to a halt in 0.35s is 4714.05 N, acting in the direction opposite to the motion.
To calculate the average force that the seatbelt exerts on a person, we can use the formula derived from Newton's Second Law of Motion:
F = ma
However, since acceleration is not directly given, we can find it using the formula for acceleration (a) in terms of velocity change (∆v) and time (∆t):
a = ∆v / ∆t
In this case:
The velocity change (∆v) is 30 m/s (since the car stops, the final velocity is 0 and initial velocity is 30 m/s).The time (∆t) over which the velocity change occurs is 0.35s.Now, we will calculate the acceleration experienced by the person:
a = -30 m/s / 0.35s = -85.71 m/s² (The negative sign indicates deceleration).
Using the calculated acceleration and the person's mass (55 kg), we can find the force:
F = 55 kg imes -85.71 m/s² = -4714.05 N
The negative sign indicates the direction of the force is opposite to the direction of motion. The average force exerted by the seatbelt on the person is therefore 4714.05 N.
Adding a ___ to an electric circuit would increase the magnetic field around a wire
Answer: solenoid
Explanation: solenoid: increase strength around electromagnetic fields
Two carts, one of mass 2m and one of mass m, approach each other with the same speed, v. When the carts collide, they
hook together. Assume that positive momentum is to the right.
When two carts collide and hook together, their momenta combine according to the law of conservation of momentum.
Explanation:The subject of this question is Physics and the grade level is High School.
In this scenario, we have two carts of different masses approaching each other with the same speed. When the carts collide, they hook together and move as a single system. The total momentum before the collision is equal to the total momentum after the collision, according to the law of conservation of momentum.
The equation for conservation of momentum in this case would be: (2m * v) + (m * (-v)) = (3m * v'), where v' is the final velocity of the hooked carts.
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v' = 0. The combined cart comes to a complete rest.
Let's analyze the scenario of two carts colliding and hooking together:
Initial Conditions:
Cart 1 (mass 2m) has velocity v to the right (positive momentum)
Cart 2 (mass m) has velocity v to the left (negative momentum)
Collision and Resulting Motion:
Upon collision, the carts hook together, forming a single system with a combined mass of 3m. The carts will then move together with a common velocity, v'.
Since the collision is inelastic, kinetic energy is not conserved. Some of the kinetic energy is converted into other forms, such as heat or sound.
Conservation of Momentum:
Despite the loss of kinetic energy, momentum is conserved in an isolated system. The total momentum before the collision must equal the total momentum after the collision.
Initial momentum = (2m * v) + (-m * v) = 0
Final momentum = (3m * v')
Therefore, v' = 0. The combined cart comes to a complete rest.
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If only 10 pounds is required to lift a 500-lb block, how much chain must be played out to lift the engine 3.0 inches?
0.060 in
150 in
290 in
6.0 in
need help on more asap
Answer:
150 inches (12.5 ft)
Explanation:
The work done to lift the 500 pound block 3 inches should be the same as that to lift the 10 pond object a given distance.
The following is the equation one needs to solve:
[tex]10 \,lb\,* \,x\,=\,500\,lb\,*\,3\,in\\10 \,lb\,* \,x\,=\,1500\,lb\,in\\[/tex]
therefore solving for the distance "x" gives as the answer (in inches):
[tex]10 \,lb\,* \,x\,=\,1500\,lb\,in\\x\,=\,\frac{1500\,lb\,in}{10\,lb} \\\\x\,=150\,in[/tex]
which can also be given in feet as: 12.5 ft
Answer:
150 in"
Explanation:
The autumnal _______ occurs in September when the days start getting shorter and the nights are longer in the Northern Hemisphere. During a new moon phase, spring tides produce the _______ difference between high and low tides. Tides are caused by _______ pulling the water of the oceans and causing it to bulge toward the large masses of the moon and sun. During a lunar eclipse, the moon briefly passes through the _______, where it receives much less sunlight causing the moon to appear dim. When the moon passes between the sun and the earth a/an _______ eclipse occurs which momentarily blocks the sun's rays from reaching certain areas of the earth.
1. Equinox
2. Greatest
3. Gravity
4. Penumbra
5. Solar
6. Earth's atmosphere refracts sunlight toward the moon when the moon passes through the umbria. The atmosphere scatters blue light from the sun, but red light is refracted and bent toward the moon.
Answer:
1. Equinox
2. Greatest
3. Gravity
4. Penumbra
5. Solar
6. Earth's atmosphere refracts sunlight toward the moon when the moon passes through the umbria. The atmosphere scatters blue light from the sun, but red light is refracted and bent toward the moon.
A force of 350N is applied to a body. If the work done is 40kJ, what is the distance through which the body moved?
The distance covered by the body is 114.3 m
Explanation:
The work done by a force exerted on an object is given by
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
For the object in this problem, we have
F = 350 N is the force applied
[tex]W=40 kJ = 40,000 J[/tex] is the work done
[tex]\theta=0^{\circ}[/tex] if we assume that the force is applied parallel to the motion of the object
Solving for d, we find the distance covered by the object:
[tex]d=\frac{W}{F cos \theta}=\frac{40,000}{(350)(cos 0)}=114.3 m[/tex]
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Jessica stretches her arms out 0.8 m from the center of her body while holding a 2.0 kg mass in each hand. She then spins around on an ice rink at 1.2 m/s.
a. What is the combined angular momentum of the masses?
b. If she pulls her arms in to 0.12 m, what is her new linear speed?
Answer:
a) L = 3.84 kg m² / s, b) v = 0.96 m / s
Explanation:
a) the angular momentum is
L = I w
Linear and angular magnitudes are related
v = w r
w = v / r
The moment of inertia of a point mass is
I = m r²
We replace
L = 2 m r² v / r
The two is because they are two masses
L = 2 m r v
L = 2 2.0 0.8 1.2
L = 3.84 kg m² / s
b) The girl reduces the distance to 0.12 m
In this case the system is isolated, so the angular momentum is preserved
Initial moment,
L₀ = 3.84 kg m² / s
Final after shrugging arms
[tex]L_{f}[/tex] = I [tex]w_{f}[/tex]
L₀ = [tex]L_{f}[/tex]
3.84 = 2 2.0 0.12 wf
[tex]w_{f}[/tex] = 3.84 / 0.48
[tex]w_{f}[/tex] = 8 rad / s
Linear velocity is
v = w r
v = 8 0.12
v = 0.96 m / s
The combined angular momentum of the masses that Jessica is holding is 3.84 kg·m^2/s. After she pulls her arms in, her new linear speed is 3.84 m/s, calculated by the conservation of angular momentum, which states that L_initial = L_final.
Explanation:Calculating Angular Momentum and Linear Speed
To calculate the combined angular momentum of the masses that Jessica holds in her hands while spinning on the ice rink, we use the formula L = mvr, where L is the angular momentum, m is the mass, v is the linear velocity, and r is the radius or the distance from the center of her body to the mass.
Given:
m (mass) = 2.0 kg for each hand (two masses),
v (linear velocity) = 1.2 m/s,
r (radius) = 0.8 m.
The angular momentum for one mass is L = 2.0 kg × 1.2 m/s × 0.8 m. For both masses, we simply double this value:
L = 2(mvr) = 2(2.0 kg × 1.2 m/s × 0.8 m) = 3.84 kg · m^2/s.For part b, as Jessica pulls her arms in, her moment of inertia decreases and, according to the conservation of angular momentum, her linear speed must increase since angular momentum is conserved in the absence of external torques. The new radius r is now 0.12 m.
Let the new linear speed be v'. Using the conservation of angular momentum:
L_initial = L_finalmv_initialr_initial = mv'_finalr_finalv' = (mv_initialr_initial) / (mr_final)v' = (2.0 kg × 1.2 m/s × 0.8 m) / (2.0 kg × 0.12 m)v' = 3.84 m/s. So, the new linear speed is 3.84 m/s.Learn more about Angular Momentum here:https://brainly.com/question/37906446
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Which statement best describes how reproduction leads to natural selection in a population?
Organisms do not produce many offspring, so all of them can survive and pass on their traits.
Organisms overproduce offspring; consequently, all of them are likely to survive and pass on traits.
Organisms overproduce offspring, so only some survive and pass on their traits.
Organisms do not overproduce offspring; therefore, those that are produced will develop the best traits.
Organisms overproduce offspring, so only some survive and pass on their traits.
Natural selection is the fitting of a population to its environment.
Explanation:
Most organisms produce more than two or more offspring in their lifetime. Therefore the subsequent generations ideally have more individuals than the previous. However, naturally, the population size does not grow indefinitely. This is because some individuals do not survive to pass their genes to the next generation. Natural selection chooses the best fit individuals to habitat, and these live long enough to pass their traits to the next generation. Natural selection powers the evolution of a population even as environment changes
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Answer:
The answer is C) Organisms overproduce offspring, so only some survive and pass on their traits
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The angle between the two force of magnitude 20N and 15N is 60 degrees (20N force being horizontal) determine the resultant in magnitude and direction
A. If the force are pull
B. The 15N force is a push and 20N force is a pull
A) The resultant force is 30.4 N at [tex]25.3^{\circ}[/tex]
B) The resultant force is 18.7 N at [tex]43.9^{\circ}[/tex]
Explanation:
A)
In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.
The two forces are:
[tex]F_1 = 20 N[/tex] at [tex]0^{\circ}[/tex] above x-axis
[tex]F_2 = 15 N[/tex] at [tex]60^{\circ}[/tex] above y-axis
Resolving each force:
[tex]F_{1x}=F_1 cos \theta = (20)(cos 0)=20 N\\F_{1y}=F_1 sin \theta =(20)(sin 0)=0 N[/tex]
[tex]F_{2x}=F_2 cos \theta = (15)(cos 60)=7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 60)=13.0 N[/tex]
So, the components of the resultant are:
[tex]F_x = F_{1x}+F_{2x}=20+7.5 = 27.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N[/tex]
And the magnitude of the resultant is:
[tex]F=\sqrt{F_x^2+F_y^2}=\sqrt{27.5^2+13.0^2}=30.4 N[/tex]
And the direction is:
[tex]\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{27.5})=25.3^{\circ}[/tex]
B)
In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is
[tex]\theta=180^{\circ}-60^{\circ}=120^{\circ}[/tex]
So we have:
[tex]F_{2x}=F_2 cos \theta = (15)(cos 120)=-7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 120)=13.0 N[/tex]
So, the components of the resultant this time are:
[tex]F_x = F_{1x}+F_{2x}=20-7.5 = 12.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N[/tex]
And the magnitude is:
[tex]F=\sqrt{F_x^2+F_y^2}=\sqrt{13.5^2+13.0^2}=18.7 N[/tex]
And the direction is:
[tex]\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{13.5})=43.9^{\circ}[/tex]
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which of the following materials has the lowest resistance copper wood plastic
Final answer:
Copper has the lowest resistance among the given materials.
Explanation:
Copper has the lowest resistance among the given materials: copper, wood, and plastic.
In a series circuit, the total resistance is the sum of individual resistances. The circuit element with the lowest resistance would contribute the least to the overall resistance.
In a parallel circuit, the total resistance is less than the smallest individual resistance due to the combined effect of multiple paths for current flow.
It's important to note that resistance in most materials increases with temperature. So, achieving the lowest possible resistance often involves using superconducting materials at extremely low temperatures or selecting materials with inherently low resistance characteristics for specific applications.
an unbalanced force of 2 N ask on a 3 kg object for six seconds the magnitude of the objects change in velocity is
yes 1)18m/s 2)2m/s 3)36m/s 4)4.0m/s
The change in velocity is 4) 4.0 m/s
Explanation:
First of all, we can find the acceleration of the object, by applying Newton's second law:
[tex]F=ma[/tex]
where
F = 2 N is the net force on the object
m = 3 kg is the mass of the object
a is the acceleration
Solving for a,
[tex]a=\frac{F}{m}=\frac{2}{3}=0.67 m/s^2[/tex]
The motion of the object is a uniformly accelerated motion, so we can use the suvat equation:
[tex]v=u+at[/tex]
where
u is the initial velocity
v is the final velocity
[tex]a=0.67 m/s^2[/tex] is the acceleration
t = 6 s is the time elapsed
Therefore, the change in velocity is
[tex]v-u = at=(0.67)(6)=4.0 m/s[/tex]
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What acceleration will you give to a 24.3 kg box if you push it horizontally with a force of 85.5 N? Please show work.
The acceleration of a 24.3 kg box being pushed with a force of 85.5 N is approximately 3.52 m/s². This is determined through the application of Newton's Second Law (F=ma) where acceleration (a) is obtained when the applied force (F) is divided by the mass (m).
Explanation:The subject of the question is Physics, specifically the concept of Newton's Second Law. This law states that the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. It is represented by the formula F = ma, where F is the force, m is the mass, and a is the acceleration.
In this case, we have the force F = 85.5 N and the mass m = 24.3 kg. You're asked to find out the acceleration, denoted by 'a'. You can find the acceleration by rearranging the formula to a = F/m. Substituting the given values into the formula gives a = 85.5 N / 24.3kg, resulting in an acceleration of approximately 3.52 m/s².
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You want to make a ride so you do not want to exceed 1.1g’s, if the radius of the turns are 10m, then what is the maximum speed the ride can go at?
The maximum speed is 10.4 m/s
Explanation:
For a body in uniform circular motion, the centripetal acceleration is given by:
[tex]a=\frac{v^2}{r}[/tex]
where
v is the linear speed
r is the radius of the circular path
In this problem, we have the following data:
- The maximum centripetal acceleration must be
[tex]a=1.1 g[/tex]
where [tex]g=9.8 m/s^2[/tex] is the acceleration of gravity. Substituting,
[tex]a=(1.1)(9.8)=10.8 m/s^2[/tex]
- The radius of the turn is
r = 10 m
Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:
[tex]v=\sqrt{ar}=\sqrt{(10.8)(10)}=10.4 m/s[/tex]
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Final answer:
To find the maximum speed that a ride can go without exceeding 1.1g's with a turn radius of 10m, the centripetal acceleration formula is used, and the calculation results in a maximum speed of approximately 10.44 m/s.
Explanation:
To calculate the maximum speed at which a ride can go without exceeding 1.1g's of acceleration, we use the formula for centripetal acceleration a = v^2 / r, where a is the centripetal acceleration, v is the speed, and r is the radius of the turn, which is given as 10m.
We want to keep the acceleration a at no more than 1.1 times the gravitational acceleration g (9.8 m/s^2). Thus, we have: 1.1g = v^2 / r. Plugging in the numbers, we get 1.1 × 9.8 m/s^2 = v^2 / 10 m. To find the maximum speed v, we solve for v, which gives us v = √(1.1 × 9.8 m/s^2 × 10 m). After calculating, we find the maximum speed to be approximately 10.44 m/s.
help asap!!! Describe the distinction between speed and velocity. Be sure to include
examples of each.
The distinctions between speed and the velocity is as follows:
Speed:
“Speed” is a “scalar quantity”. “Speed” of the “vehicle” says that “rate of the distance traveled” by “the vehicle”. For example, consider that a car is moving with “the speed 5 Km/h”. It informs that the “car can move 5 Km in one hour”.Velocity:
“Velocity” is a “vector quantity”. “Velocity” of the “vehicle” says that “rate of the distance traveled” and “the direction of the vehicle”. For example, consider a car is moving with “5 km/h west”. It informs that car is traveling in “direction of west” it covers “5 Km in one hour”.which letter represent the location of the resister in this diagram?
Answer:
Letter which represent the resistance in this circuit diagram isDExplanation:
Here in this circuit diagram we know that
A = Battery
B = switch
C = connecting Wire
D = Resistance
This zig zag shape is represented as Resistance in all circuits
Answer:
D
Explanation:
Dane is holding an 8 kilogram box 2 metres above the ground. How much energy is in the box's gravitational potential energy store? Assume Dane is on Earth, where g = 10 N/kg.
Answer:160j
Explanation:
PE=mgh
m=8kg
g=10N/kg
h=2m
PE=8*10*2
PE=160j
2. Does the amount of iron in the water affect plant growth?
Hypothesis:
use if and then
Answer:
Yes, the amount of Iron can affect the growth of plant.
Explanation:
Iron is essential micro-nutrient for the growth of plant but it is required only in small amount. Iron is required when plant produces chlorophyll and this gives plants oxygen and healthy green color but if a plant is suffering from iron deficiency then the plant's growth becomes stunted and leaves color changes to yellow. For plants requirement of iron is just 1 to 1.5 lb per acre whereas, requirement of nitrogen is 75 to 200 lb per acre.
The amount of iron in the water affects plant growth, with both deficiency and excess having potential negative impacts. A testable hypothesis using the 'if...then' structure could predict improved growth at optimal iron levels, or decreased health at excessive levels, with measurable outcomes such as plant height and foliage health.
Explanation:The amount of iron in the water does indeed affect plant growth. Iron is a crucial nutrient for plants, involved in the creation of chlorophyll and essential for some enzymes and cellular functions. However, iron levels must be balanced because both deficiency and excess can lead to plant health issues. Iron deficiency can cause chlorosis, a condition where leaves become pale or yellow because they don't have enough chlorophyll. On the other hand, excess iron, particularly in the ferrous state (Fe2+), can become toxic to plants, especially in waterlogged, anaerobic soil conditions.
To frame a hypothesis regarding the effect of iron on plant growth, using an 'if...then' format, one might say: "If the amount of iron in the water available to plants is increased to optimal levels, then the plants will show improved growth and healthier foliage compared to those receiving suboptimal levels." Conversely, if investigating the negative aspects: "If the amount of iron in the water exceeds optimal levels, then the plants may show signs of toxicity and decreased health."
It is important for the hypothesis to be testable and include measurable variables. For example, plant height, leaf color, and biomass could be measured to determine the impact of iron in water on plant growth.
3. A -4.00-uC charge lies 20.0cm to the right of a 2.00-uC charge on the x axis. What is the force on the 2.00-uC charge?
Answer:
The force on the 2.00-uC charge is [tex]36 \times 10^{10} \mathrm{N}[/tex]
Explanation:
We know that force between two charges is given by Coulomb’s law,
[tex]\mathrm{F}=\mathrm{k} \frac{q 1 q 2}{r * r}[/tex]
Where k = Coulomb’s constant =
[tex]9.0 \times 10^{9} \mathrm{Nm}^{2} \mathrm{C}^{-2}[/tex]
And q1 and q2 are the charges given to be = -4.00-uC and 2.00-uC charges
And r = distance between the charges = 20 cm = 0.2 m
Substituting the given values in the formula we get force applied on [tex]2.00\ \mu C[/tex] charge,
F = [tex]36 \times 10^{10} \mathrm{N}[/tex] attractive force which is the required answer.
The force on the 2.00-uC charge is 1.8N towards the right.
Let us assume Q = -4.00μC and charge q = 2.00μC. Distance between them is r = 0cm = 0.2m
Coulomb's Law:According to Coulomb's law, the electrostatic force between two charges Q and q separated by a distance r is given by:
[tex]F=k\frac{Qq}{r^2}[/tex]
where k is Coulomb's constant
[tex]F=\frac{9\times10^9\times4\times10^{-6}\times2\times10^{-6}}{0.20\times0.20} N\\\\F=1.8N[/tex]
Since we are calculating the force on the q which is positive, due to Q which is negative. The direction of the force will be towards the right since the electric field for the negative charge will be directed towards the charge, which is towards the right.
So the net force is 1.8N towards right.
Learn more about Coulomb's Law;
https://brainly.com/question/506926?referrer=searchResults
A 5kg mass at rest on the ground is rised up to 15m. Find the work that was done on the object.
A. E before=___ Work=___ E after=___
B. Conservation of Energy equation:
C. Solve.
Answer:
E before = 0 J Work = 735.75 J E after= 735.75 J
Explanation:
The work that was done on the object is calculated as follows:
W = m*g*h
where m refers to the mass of the object, g to gravitational acceleration (9.81 m/(s^2)) and h to the hight that the object was raised up. Replacing with data into the equation (units are ommited):
W = 5*9.81*15
W = 735.75 J
Taking the ground as heigth = 0 m, then both potential and kinetic energy of the object before the lift was zero (notice that it was resting). Conservation energy equation states that the change of energy of an object is equal to the work applied on the object (like this case) or done by the object. That is:
ΔE = W
where ΔE = Energy after - Energy before
Therefore:
Energy after = W = 735.75 J
The potential energy after the lift is also calculated as m*g*h, so the energy after the lift is all potential energy gained by the object due to the work applied on it.