State the converse, contrapositive, and inverse of each of these conditional statements a) If it snows tonight, then I will stay at home. b) I go to the beach whenever it is a sunny summer day. c) When I stay up late, it is necessary that I sleep until noon.

Answer:

equation of plane, 5x+3y-z-36=0

Distance of point (2,2,2) from plane = 4.05 units

Step-by-step explanation:

Given,

Plane passing through the point = (8, -2, 0)

Let's say, [tex]x_1\ =\ 8[/tex]

               [tex]y_1\ =\ -2[/tex]

                [tex]z_1\ =\ 0[/tex]

Plane perpendicular to the vector, a= 5i + 3j- k

Since, the vector is perpendicular to the plane, hence the equation of plane can be given by

[tex](5i + 3j- k).((x-x_1)i+(y-y_1)j+(z- z_1)k)=\ 0[/tex]

[tex]=>(5i + 3j- k).((x-8)i+(y+2)j+(z-0)k)=\ 0[/tex]

[tex]=>\ 5(x-8)+3(y+2)-z=0[/tex]

[tex]=>\ 5x\ -\ 40\ +\ 3y\ +\ 6\ -\ z\ =\ 0[/tex]

[tex]=>\ 5x\ +\ 3y\ -\ z\ -\ 36\ =\ 0[/tex]

Hence, the equation of plane can be given by, 5x+3y-z-36=0

Now, we have to calculate the distance of the point O(2,2,2) from the plane 5x+3y-z-36=0

Let's say,

a= 5, b= 3, c= -1, d=-36

[tex]x_0=2,\ y_0=2,\ z_0=2[/tex]

So, distance of a point from the plane can be given by,

[tex]d=\dfrac{ax_0+by_0+cz_0+d}{\sqrt{a^2+b^2+c^2}}[/tex]

 [tex]=\dfrac{\left |5\times 2+3\times 2+(-1)\times 2-36\right |}{\sqrt{5^2+3^2+(-1)^2}}[/tex]

 [tex]=\dfrac{24}{\sqrt{35}}[/tex]

  = 4.05 units

So, the distance of the point O(2,2,2) from the given plane will be 4.05 units.

Answer: There are 4.8 grams in 100 mL of Drug A

Step-by-step explanation:

In order to determinate how many grams are in 100 mL of Drug A you can multiply and divide the expression of the concentration by 10 (To obtain 100 mL in the denominator)

Notice that the value remains unaltered.

(475 mg/10 mL )(10/10) = 4750 mg/ 100 mL

But the question is how many grams are in 100 mL, so you have to convert the value from mg to g.

The prefix m (mili) is equivalent to 0,001 so you can use 0.001 instead of the prefix

4750(0.001) g/ 100 mL

4.75 g/ 100 mL

The rounded result is 4.8 g/ 100 mL

Answer: 0.9575465

Step-by-step explanation:

Let the random variable X is normally distributed with mean [tex]\mu=50[/tex] and standard deviation[tex]\sigma=7[/tex] .

Using the formula , [tex]z=\dfrac{x-\mu}{\sigma}[/tex] , we have the z-value for x= 34

[tex]z=\dfrac{34-50}{7}\approx-2.29[/tex]

For x= 63

[tex]z=\dfrac{63-50}{7}\approx1.86[/tex]

P-value : P(34<x<63)=P(-2.29<z<1.86)

[tex]=P(z<1.86)-P(z<-2.29)\\\\=0.9685572-(1-P(z<2.29))\\\\1=0.9685572-(1-0.9889893)\\\\=0.9575465[/tex]

Hence, the required probability = 0.9575465

Answer: I'm sure its 2/21

Step-by-step explanation: you just need to multiply cross sides then divide by any number that works on both of them.

I hope that I answer your question.

Answer:

The output for NAND gate is false if all the inputs are true. it is true if either A or B is False.

Step-by-step explanation:

Step1

NAND operator:

NAND is a logic or Boolean expression and is a combination of NOT and AND Gate.

NAND gate is built using various junction diodes and transistors.

Step2

The output of NAND can be 0 or 1. Here, LOW (0) and HIGH (1). 0 or 1 is commonly named as FALSE or TRUE respectively.

It is basically the complement of AND gate. If all its inputs are True or 1, then the output is False or 0 else if either A or B is 0 or 1 then it will give the output as TRUE.

Step3

Here, A and B are 2 inputs used to make the truth table for NAND.

In 1st row, when A and B are both 0, the output for NAND is 1.

Likewise, in 2st row and 3rd row, when either A or B is 0 or 1, the output for NAND is 1 that is TRUE.

But in last row, when both inputs A and B are true, then the output for NAND gate is FALSE or 0.

The diagram and truth table for NAND is shown below.

Final answer:

A truth table for the NAND logical operator lists all possible binary input combinations of variables A and B, applies the AND operation, and then negates the output to present the NAND result. The resulting truth table will show that a NAND gate outputs true for all cases except when both inputs are true.

Explanation:

Constructing a truth table for the logical operator NAND is a way to visualize how this operator works with different input values.

The NAND operator is essentially the negation of the AND operator, meaning that it outputs the opposite of what an AND gate would. Here is how you construct a truth table for NAND:

The resulting truth table for the NAND operation is as follows:

A B A AND B A NAND B

false false false true

false true false true

true false false true

true true true false

Answer:

[tex]f(x) = 4sin(\frac{\pi}{2}x) - 3[/tex], the third one

Step-by-step explanation:

Explaining the sine function:

The sine function is defined by:

[tex]S = Asin(p(x - x_{0})) + V[/tex]

In which A is the amplitude, [tex]p = \frac{2\pi}{N}[/tex] is the period, [tex]x_{0}[/tex] is the horizontal shift and V is the vertical shift.

So, in your problem:

The amplitude is 4, so A = 4.

The period is [tex]\frac{\pi}{2}[/tex], so [tex]p = \frac{\pi}{2}[/tex].

There is no horizontal shift, so [tex]x_{0} = 0[/tex].

The vertical shift is −3, so V = -3.

The sine function that represents these following conditions is

[tex]f(x) = 4sin(\frac{\pi}{2}x) - 3[/tex], the third one

Answer: 1503

Step-by-step explanation:

Given : Significance level : [tex]\alpha:1-0.98=0.02[/tex]

Critical value : [tex]z_{\alpha/2}=2.326[/tex]

Margin of error : [tex]E=\pm0.03[/tex]

We know that the formula to find the sample size (the prior true proportion is not available) is given by :-

[tex]n=0.25(\dfrac{z_{\alpha/2}}{E})^2[/tex]

i.e. [tex]n=0.25(\dfrac{2.326}{0.03})^2=1502.85444444\approx1503[/tex]

Hence, the minimum sample size should be 1503.

Answer:

a) There are 3,628,800 different strings.

b) There are 28,800 different strings if the letters ad digits must alternate.

c)There are 86,400 different string if all five letters must be adjacent in each string.

Step-by-step explanation:

There are 10 digits.

Our strings have the following format:

C1 - C2 - C3 - C4 - C5 - C6 - C7 - C8 - C9 - C10

repitition of letters is not allowed.

a) How many different strings are there?

C1 can be any of the 10, C2 can be 9, C3 can be 8, ...

So in total there are:

[tex]T = 10*9*8*7*6*5*4*3*2*1 = 3,628,800[/tex]

There are 3,628,800 different strings.

b) How many different strings are there if the letters, i.e. A, E, I, O, U and the digits, i.e. 1,3, 5, 7, 9 must alternate?

There are the following possiblities:

5(l) - 5(d) - 4(l) - (4d) - ...

Or

5(d) - 5(l) - 4(d) - 4(l) - ...

So:

[tex]T = 2*(5*5*4*4*3*3*2*2*1*1) = 28,800[/tex]

There are 28,800 different strings if the letters ad digits must alternate.

c) How many different strings are there if all five letters must be adjacent in each string?

L - L - L - L - L - D - D - D - D - D

D - L - L - L - L - L - D - D - D - D

D - D - L - L - L - L - L - D - D - D

D - D - D - L - L - L - L - L - D - D

D - D - D - D - L - L - L - L - L - D

D - D - D - D - D - L - L - L - L - L

There are [tex]T = 6*(5*5*4*4*3*3*2*2*1*1) = 86,400[/tex]

There are 86,400 different string if all five letters must be adjacent in each string.

Answer: 0.1038

Step-by-step explanation:

We assume that oil in each container is filled will normal distribution.

Given : Population mean : [tex]\mu=12[/tex]

Standard deviation: [tex]\sigma=0.25[/tex]

Sample size : [tex]n=40[/tex]

Let x be the random variable that denotes the amount of oil filled in container.

z-score : [tex]z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]

For x= 12.05

[tex]z=\dfrac{12.05-12}{\dfrac{0.25}{\sqrt{40}}}=1.26491106407\approx1.26[/tex]

Now by using the standard normal table for z, we have the probability that the sample mean,X is greater  then 12.05:-

[tex]P(z>1.26)=1-0.8961653=0.1038347\approx0.1038[/tex]

Hence, the probability that the sample mean,X is greater  then 12.05 = 0.1038

Answer: 0.0475

Step-by-step explanation:

Given : The amount of money spent on red balloon in a certain college town when the football team is in town is a normal random variable with

[tex]\mu=\$50000[/tex] and [tex]\sigma=\$3000[/tex]

Let x be the random variable that represents the  amount of money spent on red balloon.

Using formula [tex]z=\dfrac{x-\mu}{\sigma}[/tex], the z-score corresponding to x= 45000 will be :_

[tex]z=\dfrac{45000-50000}{3000}\approx-1.67[/tex]

Now, by using the standard normal distribution table for z, we have

P value : [tex]P(z<-1.67)=1-P(z<1.67)=1-0.9525=0.0475[/tex]

∴The proportion of home football game days in this town is less than $45000 worth of red balloons sold = 0.0475

Answer:

The equation to find the number of gallons purchased is:

[tex]C(n) = 3.05n[/tex]

You purchased 12 gallons of gasoline

Step-by-step explanation:

This problem can be modeled by the following first order function

[tex]C(n) = P_{G}n[/tex]

Where C(n) is the cost in function to the number of gallons, P is the price of the gallon and n is the number of gallons

The problem states that the price of gasoline is $3.05 per gallon, so P = 3.05

The equation to find the number of gallons purchased is:

[tex]C(n) = 3.05n[/tex]

If you pay $36.60, you have C = 36.60, and want to find n, so:

[tex]36.60 = 3.05n[/tex]

[tex]n = \frac{36.60}{3.05}[/tex]

[tex]n = 12[/tex]

You purchased 12 gallons of gasoline

The confidence interval for population mean is given by :-

[tex]\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

, where [tex]\hat{p}[/tex] is the sample proportion, n is the sample size , [tex]z_{\alpha/2}[/tex] is the critical z-value.

The  values needed to calculate a confidence interval at the 99% confidence level are :

Given : Significance level : [tex]\alpha:1-0.99=0.01[/tex]

Sample size : n=450

Critical value : [tex]z_{\alpha/2}=2.576[/tex]

Sample proportion: [tex]\hat{p}=\dfrac{280}{450}\approx0.62[/tex]

Now, the  99% confidence level will be :

[tex]\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.62\pm(2.576)\sqrt{\dfrac{0.62(1-0.62)}{450}}\\\\\approx0.62\pm0.023\\\\=(0.62-0.023,\ 0.62+0.023)=(0.597,\ 0.643)[/tex]

Hence, the  99% confidence interval is [tex](0.597,\ 0.643)[/tex]

To calculate a 99% confidence interval for the true proportion, find the values needed and apply the formula. In this case, the confidence interval is between 0.5601 and 0.6811.

1. Sample proportion [tex](\( \hat{p} \))[/tex]:

[tex]\[ \hat{p} = \frac{x}{n} = \frac{280}{450} \approx 0.6222 \][/tex]

2. Margin of error  E :

For a 99% confidence level, z = 2.576.

[tex]\[ E = z \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \]\[ E = 2.576 \times \sqrt{\frac{0.6222 \times (1-0.6222)}{450}} \]\[ E = 2.576 \times \sqrt{\frac{0.6222 \times 0.3778}{450}} \]\[ E = 2.576 \times \sqrt{\frac{0.235052}{450}} \]\[ E \approx 2.576 \times \sqrt{0.00052233} \]\[ E \approx 2.576 \times 0.022854 \]\[ E \approx 0.058893 \][/tex]

3. Confidence interval:

[tex]\[ \text{Confidence interval} = \hat{p} \pm E \]\[ \text{Confidence interval} = 0.6222 \pm 0.0589 \][/tex]

Therefore, the confidence interval for the percentage of elementary school children who have a social media account at the 99% confidence level is approximately (0.5633, 0.6811) .

Answer:  21

Step-by-step explanation:

Given : A bag containing five red marbles, two green ones, one transparent one, four yellow ones, and two orange ones .

Total marbles other than red or green = 1+4+2=7

Now, the number of combinations to select five marbles from the set of 7 will be :-

[tex]7C_5=\dfrac{7!}{5!(7-5)!}=\dfrac{7\times6\times5!}{5!\times2!}=21[/tex]

Hence, the number of  possible sets of five marbles are there in which none of them are red or green =21

Answer:

  The digit 6 in February is worth 1/100 of its value in January.

Step-by-step explanation:

The value of a given digit in a number can be found by setting the other digits to zero.

In February, the digit 6 has a value of 00600 = 600.

In January, the digit 6 has a value of 060000 = 60,000.

The ratio of the value in February to the value in January is ...

  600/60000 = 1/100

The digit 6 in February is one hundredth of the digit 6 in January.

Answer:

The rabbit should be fed:

[tex]6 + 2z[/tex] grams of food A

[tex]12 - 3z[/tex] grams of food B

[tex]z[/tex] grams of food C

For [tex]z \leq 4[/tex].

Step-by-step explanation:

This can be solved by a system of equations.

I am going to say that x is the number of grams of food A, y is the number of grams of food B and z is the number of grams of Food C.

The problem states that:

A researcher wants to provide a rabbit exactly 162 units of ​protein:

There are 5 units of protein in each gram of food A, 11 units of protein in each gram of food B and 23 units of protenin in each gram of food C. So

[tex]5x + 11y + 23z = 162[/tex]

A researcher wants to provide a rabbit exactly 72 units of carbohydrates:

There are 2 units of carbohydrates in each gram of food A, 5 units of carbohydrates in each gram of food B and 11 units of carbohydrates in each gram of food C. So:

[tex]2x + 5y + 11z = 72[/tex]

A researcher wants to provide a rabbit exactly 30 units of Vitamin A:

There is 1 unit of Vitamin A in each gram of food A, 2 units of Vitamin A in each gram of food B and 4 units of Vitamin A in each gram of food C. So:

[tex]x + 2y + 4z = 30[/tex].

We have to solve the following system of equations:

[tex]5x + 11y + 23z = 162[/tex]

[tex]2x + 5y + 11z = 72[/tex]

[tex]x + 2y + 4z = 30[/tex].

I think that the easier way to solve this is reducing the augmented matrix of this system.

This system has the following augmented matrix:

[tex]\left[\begin{array}{cccc}5&11&23&162\\2&5&11&72\\1&2&4&30\end{array}\right][/tex]

To help reduce this matrix, i am going to swap the first line with the third

[tex]L_{1} <-> L_{3}[/tex]

Now we have the following matrix:

[tex]\left[\begin{array}{cccc}1&2&4&30\\2&5&11&72\\5&11&23&162\end{array}\right][/tex]

Now i am going to do these following operations, to reduce the first row:

[tex]L_{2} = L_{2} - 2L_{1}[/tex]

[tex]L_{3} = L_{3} - 5L_{1}[/tex]

Now we have

[tex]\left[\begin{array}{cccc}1&2&4&30\\0&1&3&12\\0&1&3&12\end{array}\right][/tex]

Now, to reduce the second row, i do:

[tex]L_{3} = L_{3} - L_{2}[/tex]

The matrix is:

[tex]\left[\begin{array}{cccc}1&2&4&30\\0&1&3&12\\0&0&0&0\end{array}\right][/tex]

This means that z is a free variable, so we are going to write y and x as functions of z.

From the second line, we have

[tex]y + 3z = 12[/tex]

[tex]y = 12 - 3z[/tex]

From the first line, we have

[tex]x + 2y + 4z = 30[/tex]

[tex]x + 2(12 - 3z) + 4z = 30[/tex]

[tex]x + 24 - 6z + 4z = 30[/tex]

[tex]x = 6 + 2z[/tex]

Our solution is: [tex]x = 6 + 2z, y = 12 - 3z, z = z[/tex].

However, we can not give a negative number of grams of a food. So

[tex]y \geq 0[/tex]

[tex]12 - 3z \geq 0[/tex]

[tex]-3z \geq -12 *(-1)[/tex]

[tex]3z \leq 12[/tex]

[tex]z \leq 4[/tex]

The rabbit should be fed:

[tex]6 + 2z[/tex] grams of food A

[tex]12 - 3z[/tex] grams of food B

[tex]z[/tex] grams of food C

For [tex]z \leq 4[/tex].

Answer: 200 mm

Step-by-step explanation:

The perimeter of rectangle is given by :-

[tex]P=2(l+w)[/tex], where l is length and w is width of the rectangle.

Given : Two sides of a rectangle are 4 cm in length. The other two sides are 6 cm in length.

The perimeter of the rectangle will be :_

[tex]P=2(4+6)=2(10)=20\ cm[/tex]

We know that 1 cm = 10 mm

Therefore,  perimeter of the rectangle = [tex]20\times10=200\ mm[/tex]

Step-by-step explanation:

Consider the provided information.

We have given that H and k are the subgroups of orders 5 and 8, respectively.

We need to prove that H∩K = {e}.

As we know "Order of element divides order of group"

Here, the order of each element of H must divide 5 and every group has 1 identity element of order 1.

1 and 5 are the possible order of 5 order subgroup.

For subgroup order 8: The possible orders are 1, 2, 4 and 8.

Now we want to find the intersection of these two subgroups.

Clearly both subgroup H and k has only identity element in common.

Thus, H∩K = {e}.

Answer:

1mL should be administered to provide a 25-mg dose of aminophylline.

Step-by-step explanation:

The problem states that one 20-mL ampul contains 0.5 g of aminophylline, and asks how many milliliters should be administered to provide a 25-mg dose of aminophylline.

The first step is converting 0.5g to mg.

Each g has 1000mg, so:

1g - 1000mg

0.5g - xmg

x = 1000*0.5

x = 500mg.

Now we have that one 20-mL ampul contains 500mg of aminophylline. How many milliliters should be administered to provide a 25-mg dose of aminophylline?

As the dose increases, so does the quantity of aminophylline. It means that we have a direct rule of a three, there is a cross multiplication. So:

20mL - 500mg

x mL - 25mg

500x = 500

[tex]x = \frac{500}{500}[/tex]

x = 1 mL

1mL should be administered to provide a 25-mg dose of aminophylline.

Final answer:

1 mL of the aminophylline solution should be administered to provide a 25-mg dose. This calculation was made by first converting the total amount of aminophylline to milligrams and then establishing the amount per milliliter to solve for the necessary volume.

Explanation:

To determine how many milliliters of aminophylline should be administered to provide a 25-mg dose, we need to use the following information:

First, we need to convert 0.5 g of aminophylline to milligrams:

0.5 g × 1000 mg/g = 500 mg

Now that we have the total amount of aminophylline in milligrams, we can determine the amount per milliliter:

500 mg / 20 mL = 25 mg/mL

To find the volume that contains 25 mg, we set up a proportion:

(25 mg of aminophylline) / (X mL) = (25 mg/mL)

By solving for X, we find:

X = 1 mL

So, 1 mL of the aminophylline solution should be administered to provide a 25-mg dose.

Step-by-step explanation:

We will prove by mathematical induction that, for every natural n,  

[tex](x-y)(x^{n}+x^{n-1}y+...+xy^{n-1}+y^{n})=x^{n+1}-y^{n+1}[/tex]

We will prove our base case (when n=1) to be true:

Base case:

[tex](x-y)(x^{n}+x^{n-1}y+...+xy^{n-1}+y^{n})=(x-y)(x^{1}+y^{1})=x^2-y^2=x^{1+1}-y^{1+1}[/tex]

Inductive hypothesis:  

Given a natural n,  

[tex]x^{n+1}-y^{n+1}=(x-y)(x^{n}+x^{n-1}y+...+xy^{n-1}+y^{n})[/tex]

Now, we will assume the inductive hypothesis and then use this assumption, involving n, to prove the statement for n + 1.

Inductive step:

Observe that, for y=0 the conclusion is clear. Then we will assume that [tex]y\neq 0.[/tex]

[tex](x-y)(x^{n+1}+x^{n}y+...+xy^{n}+y^{n+1})=(x-y)y(\frac{x^{n+1}}{y}+x^{n}+...+xy^{n-1}+y^{n})=(x-y)y(\frac{x^{n+1}}{y})+(x-y)y(x^{n}+...+xy^{n-1}+y^{n})=(x-y)y(\frac{x^{n+1}}{y})+y(x^{n+1}-y^{n+1})=(x-y)x^{n+1}+y(x^{n+1}-y^{n+1})=x^{n+2}-yx^{n+1}+yx^{n+1}-y^{n+2}=x^{n+2}-y^{n+2}\\[/tex]

With this we have proved our statement to be true for n+1.    

In conlusion, for every natural n,

[tex](x-y)(x^{n}+x^{n-1}y+...+xy^{n-1}+y^{n})=x^{n+1}-y^{n+1}[/tex]

Answer:

$ 30

Step-by-step explanation:

Let x be the cost of tie ( in dollars ),

∵ The  shirt costs $21 more than the tie,

So, the cost of shirt = x + 21

Thus, the cost of a tie and a shirt = x + x + 21 = 2x + 21,

According to the question,

2x + 21 = 57

2x = 57 - 21

2x = 36

x = 18

Hence, the cost of the shirt = 18 + 12 = $ 30

The problem is solved using Polya's four-step problem-solving process. By setting up two equations based on the problem, we determine that the tie costs $18 and the shirt costs $39 which is confirmed by substitution into the original problem statement.

According to Polya's four-step problem solving strategy, we first need to understand the problem. We know that a shirt and tie cost $57 together, and the shirt costs $21 more than the tie.

Step two of Polya's strategy involves devising a plan. In this case, we can write two expressions to represent the cost of the two items: S (the cost of the shirt) and T (the cost of the tie). The total cost (S+T) equals $57. We also know that S (the cost of the shirt) is T (the cost of the tie) plus $21.

For step three, we carry out the plan. We can substitute S from the second expression into the first expression: (T + $21) + T = $57. Solving for T gives us T = $18. Hence, the tie costs $18.

Finally, for step four, we review our answer. We can plug T back into the second expression to get S = T + $21 = $18 + $21 = $39. So, the shirt costs $39, which sounds reasonable given that the shirt is supposed to be more expensive than the tie.

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Answer:

4 rows

Step-by-step explanation:

It is given that two statements two be connected with AND, the statements may be either true or false.

The output of the AND will be true if both the statements will be true otherwise false.

We can construct the table as follows:

statement 1            statement 2         output

false                        false                        false

false                         true                         false

true                          false                        false

true                          true                          true

Hence, the number of rows the truth will have = 4

Answer:

The basis for the null space of A is [tex]{\left[\begin{array}{c}-1&-1&1&0\end{array}\right],\left[\begin{array}{c}-1&1&0&1\end{array}\right]}[/tex]

Step-by-step explanation:

[tex]\left[\begin{array}{cccc}1&0&1&1\\3&2&5&1\\0&4&4&-4\end{array}\right][/tex]

[tex]\left[\begin{array}{cccc}1&0&1&1\\0&2&2&-2\\0&4&4&-4\end{array}\right][/tex]

[tex]\left[\begin{array}{cccc}1&0&1&1\\0&2&2&-2\\0&0&0&0\end{array}\right][/tex]

[tex]\left[\begin{array}{cccc}1&0&1&1\\0&1&1&-1\\0&0&0&0\end{array}\right][/tex]

    2. Convert the matrix equation back to an equivalent system and solve the matrix equation

[tex]1x_{1} +x_{3} +1x_{4}=0\\ 1x_{2} +x_{3} -1x_{4}=0\\0=0[/tex]

[tex]\left[\begin{array}{cccc}1&0&1&1\\0&1&1&-1\\0&0&0&0\end{array}\right] \left[\begin{array}{c}x_{1} &x_{2} &x_{3}&x_{4} \end{array}\right]=\left[\begin{array}{c}0&0&0\end{array}\right][/tex]

If we take [tex]x_{3}=t, x_{4}=s[/tex] then [tex]x_{1}=-s-t,x_{2}=s-t,x_{3}=t,x_{4}=s[/tex]

Therefore,

[tex]\boldsymbol{x}=\left[\begin{array}{c}-s-t&s-t&t&s\end{array}\right]=\left[\begin{array}{c}-1&-1&1&0\end{array}\right]t+\left[\begin{array}{c}-1&1&0&1\end{array}\right]s\\\boldsymbol{x}=\left[\begin{array}{c}-1&-1&1&0\end{array}\right]x_{3} +\left[\begin{array}{c}-1&1&0&1\end{array}\right]x_{4}[/tex]

The null space has a basis formed by the set {[tex]{\left[\begin{array}{c}-1&-1&1&0\end{array}\right],\left[\begin{array}{c}-1&1&0&1\end{array}\right]}[/tex]}

Answer:

A simple random sample.

Step-by-step explanation:

A simple random sample is an statistical sample in which each member of a group has the same probability of being chosen. Since the researcher doesn't really have specific characteristics added to the sample other than being from public or private universities, this would be a simple random sample.

Answer:

Net Present Value = - $99,360

Step-by-step explanation:

As provided,

Cash outlay = $65,000 each year for 10 years

Since the first outlay will be immediately, the cumulative discounting factor for cash outlay will be @ 16% = 1 for year 0 + 4.606 for 9 years = 5.606

Therefore, cumulative present value of total cash outlay = $65,000 [tex]\times[/tex] 5.606 = $364,390

Cash inflows beginning in year 11 = $170,000 for another continuous 20 years.

these cash flow will occur in the beginning of year 11 and end of year 10

Discounting factor will be [tex]\frac{1}{(1+0.16)^1^0}[/tex] = 0.2267

For, consecutive 20 years = 1.559

Therefore, value of inflows = $170,000 [tex]\times[/tex] 1.559 = $265,030

Net Present Value = Present Value of Cash Inflows - Present Value of Cash Outflows = $265,030 - $364,390 = - $99,360

Answer:

$5265.71

Step-by-step explanation:

We have been given that you deposit $3000 into a money-market savings account which pays 4.8% compounded quarterly.

We will use future value formula to solve our given problem.

[tex]FV=C_0\times (1+r)^n[/tex], where,

[tex]C_0=\text{Initial amount}[/tex],

r = Rate of return in decimal form,

n = Number of periods.

[tex]4.8\%=\frac{4.8}{100}=0.048[/tex]

[tex]n=3\times 4=12[/tex]

[tex]FV=\$3,000\times (1+0.048)^{12}[/tex]

[tex]FV=\$3,000\times (1.048)^{12}[/tex]

[tex]FV=\$3,000\times 1.7552354909370114[/tex]

[tex]FV=\$5265.7064\approx \$5265.71[/tex]

Therefore, there will be $5265.71 in your account at the end of those 3 years.

Answer:

No, whole numbers are numbers that are whole, which would mean that they are not a decimal or a fraction. This is because a fraction or a decimal is a portion of a number, which would mean that the decimal or fraction is not complete/ not whole!

Answer:

[tex]\frac{25}{8}[/tex]

Step-by-step explanation:

A fraction is a part of a whole .

A proper fraction is a fraction whose numerator is less than denominator .

For example [tex]\frac{2}{3}\,,\,\frac{3}{4}[/tex]

An improper fraction is a fraction whose numerator is greater than denominator .

For example [tex]\frac{5}{4}\,,\,\frac{8}{7}[/tex]

A mixed fraction is made up of whole number and a proper fraction .

Given : [tex]4\frac{1}{6}\,,1\frac{1}{3}[/tex]

Solution :

[tex]4\frac{1}{6}=\frac{4\times 6+1}{6}=\frac{25}{6}\\1\frac{1}{3}=\frac{3\times 1+1}{3}=\frac{4}{3}[/tex]

We need to divide [tex]4\frac{1}{6}[/tex] by [tex]1\frac{1}{3}[/tex] .

[tex]4\frac{1}{6}\div 1\frac{1}{3}=\frac{25}{6}\div\frac{4}{3} \\\Rightarrow 4\frac{1}{6}\div 1\frac{1}{3}= \frac{25}{6}\times \frac{3}{4}=\frac{25}{8}[/tex]

Answer:

5 + 2          

Step-by-step explanation:

We have to rewrite the given statement in addition form.

The integers have  property of:

Negative(-)  Negative(-) = Positive(+)

Positive(+)  Positive(+)  = Positive(+)

Positive(+)  Negative(-) = Negative(-)

Negative(-) Positive(+)  = Negative(-)

The given statement is:

5-(-2)

Since we have two negative together, it is converted into a positive.

Thus, the given statement can be written in positive form as

5 + 2

Answer:

y+0.5x-2=0

Step-by-step explanation:

Given,

X-intercept of line = 4

So, the line intersect the x axis at (4,0)

Y-intercept of the line = 2

So, the line intersect the y axis at (0,2)

So, the slope of the line can be given by

[tex]m\ =\ \dfrac{y_2-y_1}{x_2-x_1}[/tex]

    [tex]=\ \dfrac{2-0}{0-4}[/tex]

      = -0.5

Hence, the equation of line can be given by

y=mx+c

where, m=slope of the line

             c= y-intercept of line

So, after putting the value of m and c in above equation, the equation of line will be

y = -0.5x + 2

=> y+0.5x-2=0

So, the equation of line will be y+0.5x-2=0.

Answer: In fraction : [tex]\dfrac{373}{500}[/tex]

In Decimal :  0.746

Step-by-step explanation:

Given : A ream of paper contains 500 sheets of paper.

Norm has 373 sheets of paper left from a ream.

Then, the fraction of ream Norm has will be :-

[tex]\dfrac{\text{Number of sheets left from ream }}{\text{Total sheets in a ream }}\\\\=\dfrac{373}{500}[/tex]

To convert in decimal we divide 373 by 500, we get 0.746.

Hence, The portion of a ream Norm has as = [tex]\dfrac{373}{500}[/tex] or 0.746