Stoichiometry!

Please note:

- Use 6.022x1023 for avogadro’s number

- Ignore sig figs and do not round the final answer.

- Keep it to 1 decimal place.

Answer:

5C + 6O₂ → 5CO + 7/2 O₂

Explanation:

According to the question the reaction is between carbon and oxygen molecule . The reactant side was given as 5 moles of carbon reacting with 6 moles of oxygen molecules.   The chemical reaction between carbon and excess oxygen will form carbon dioxide but with limited oxygen it will form carbon monoxide.  

Now let us write and balance the actual chemical equation as required from the question. In limited oxygen the reaction will be

The reactant said 5 moles of carbon which is 5 atoms of carbon reacting with 12 atoms of oxygen.  The number of atoms of element on both sides of the chemical equation need to be balance . The balanced equation when oxygen is limited is written as

5C + 6O₂ → 5CO + 7/2 O₂

The product will be 5 moles of carbon monoxide and 3.5 moles of oxygen molecules(7 atoms) since the oxygen is limited . The carbon monoxide later reacts with more oxygen to form carbon dioxide.

Limiting reactant is the reactant that stops the reaction when it is completely consumed.  The product of the given reaction is Carbon dioxide.

Balanced Reaction:

A reaction in which the number of moles of atoms in reactants is equal to the number of moles of the atoms in the product.

The given reaction,

[tex]\bold{5C + 6O_2 \rightarrow 5CO_2 \\\\}[/tex]

Therefore, the product of the given reaction is Carbon dioxide.

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Answer:

Explanation:

The dilution equation is:

Where C₁ and C₂ are concentrations and V₁ and V₂ are volumes of the concentrated and diluted solutions.

First, convert the 75. mL volume into liters:

Now, substitute the data into the dilution formula:

The molarity of the new 2.0 L solution made by diluting 75 mL of 17.6M acetic acid is 0.66M, calculated using the dilution equation M1 x V1 = M2 x V2.

To calculate the molarity of the diluted acetic acid solution, we can use the concept of dilution, which is described by the equation

M1 x V1 = M2 x V2, where:

Using the provided information, M1 = 17.6M, V1 = 75 mL, and V2 = 2,000 mL (as 2.0 L is equivalent to 2,000 mL). We need to solve for M2, the molarity of the new solution:

M1 x V1 = M2 x V2

17.6M * 75 mL = M2 * 2,000 mL

M2 = (17.6M * 75 mL) / 2,000 mL

M2 = 0.66M (rounded to two decimal places)

Therefore, the molarity of the diluted acetic acid solution is 0.66M.

Answer: punnet square

Explanation:

Answer:

THE CORRECT ANSWER TO THE QUESTION ABOVE IS " UREA"

Explanation:

SOLUTE is defined as solid, liquid, or gas that is dissolved in a solution.

URINE is a by-product of metabolism that is produced by the kidneys in their process of blood purification. URINE contains of water, urea, chloride, sodium, potassium, dissolved ions, and inorganic and organic compounds.

Physical characteristics of URINE include color, smell, pH, density and turbidity.

UREA (also known as carbamide) is a non-toxic molecule, it is made up of ammonia and carbon and is the major organic component of human urine. UREA in urine is 9.3 g/L.

Answer:

BeO

Explanation:

The chemical formula for beryllium oxide is BeO, following the combination of beryllium (Be2+) cations with oxide (O2-) anions in a 1:1 ratio, reflecting the stoichiometry of the compound and its ionic character.

The chemical formula for beryllium oxide is BeO. Beryllium oxide forms when beryllium, an alkaline earth metal with an atomic number of 4, combines with oxygen. Each beryllium atom releases two electrons, forming a Be2+ cation to Oxide2-. The resultant ionic compound, BeO, is a reflection of this 1:1 charge balance between beryllium and oxygen.

Beryllium compounds generally exhibit a significant degree of covalency. In particular, beryllium forms covalent bonds in different environments, as seen in compounds like beryllium hydride (BeH2) and basic beryllium acetate [tex](Be_{4} O(CH_{3}CO_{2} )_6)[/tex].

Although beryllium's tendency to form covalent bonds might suggest a preference for complex molecular structures, BeO is a simple, stable compound with each beryllium atom adopting an electron configuration similar to that of helium, the noble gas that precedes it in the periodic table.

The final temperature of the gas is 234K. As the volume of the increases to the given value, the temperature of the gas also increases.

Charle's law states that the volume of an ideal gas is directly proportional to the absolute temperature provided pressure is kept at constant.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

Initial volume V₁ = 62.0mL = 0.062L

Initial temperature T₁ = 175K

Final volume V₂ = 82.9mL = 0.0829L

Final temperature T₂ = ?

To calculate the final temperature, we subtsitute our given values into the expression above.

V₁/T₁ = V₂/T₂

V₁T₂ = V₂T₁

T₂ = V₂T₁ / V₁

T₂ = ( 0.0829L × 175K ) / 0.062L

T₂ = 14.5075LK / 0.062L

T₂ = 234K

The final temperature of the gas is 234K. As the volume of the increases to the given value, the temperature of the gas also increases.

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Answer:

Temperature increase with the increasing Kinetic energy of the molecule.

Explanation:

When Kinetic energy of the molecule increases, the number of collisions increases between the molecule. Hence, By speeding up the molecule temperature increases.

The term associated with the solution is saturated.

The term associated with a solution that is saturated at 25°C and then slowly cooled to 20°C with no change to its appearance is saturated.

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Answer:

The amount (mass) of water we will have is 17.869 grams

Explanation:

The molar mass of hydrogen gas H₂ = 2.016 grams/mole

The molar mass of oxygen gas = 31.999 g/mol

Therefore, 2.00 g of hydrogen will give;

2.00/2.016 = 0.9921 moles of H₂ gas and

15.87 g of O₂ will give;

15.87/31.999 = 0.49595 moles

The reaction is as follows;

2H₂ (g) + O₂ (g) → 2H₂O (l)

Two moles of H₂ react with one mole of O₂ to produce two moles of H₂O

Therefore 0.9921 moles of H₂ will react with 0.9921/2 or 0.49595 moles of O₂ to produce 0.9921 moles of H₂O

From the above we note that all the H₂ and O₂ are completely consumed to form 0.9921 moles of H₂O

Molar mass of H₂O = 18.01528 g/mol

Number of moles = Mass/(Molar mass)

∴ Mass of H₂O = (Molar mass) × (Number of moles)

= 18.01528 g/mol × 0.9921 moles = 17.869 grams

Therefore the amount (mass) of water we will have = 17.869 grams.

Answer:

78 mmHg is the partial pressure of the nitrogen.

Explanation:

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

[tex]P=p_{1}+p_{2}+p_{3}[/tex]

where,

[tex]P[/tex] = total pressure of the gas mixture = 456 mmHg

[tex]p_{1}[/tex] = partial pressure of hydrogen gas = 230 mmHg

[tex]p_{2}[/tex] = partial pressure of oxygen gas = 148 mmHg

[tex]p_{3}[/tex] = partial pressure of nitrogen gas = ?

Now put all the given values is expression, we get the partial pressure of the nitrogen gas i.e.  [tex]p_3[/tex] .

[tex]456 mmHg=230 mmHg+148 mmHg+p_3[/tex]

[tex]p_3=456 mmHg-230 mmHg-148 mmHg=78 mmHg[/tex]

78 mmHg is the partial pressure of the nitrogen.

Answer:

heated crude oil enters a tall fractionating column , which is hot at the bottom and gets cooler towards the top.

vapours from the oil rise through the column.

vapours condense when they become cool enough.

liquids are led out of the column at different heights.

sorry for bad spelling i think this is right

hope this helps :)

Heated crude oil needs to enter a tall fractionating column that is hot at the bottom and cools as it ascends. The oil vapors rise through the column. When vapors cool sufficiently, they condense.

A mixture of liquids is boiled in a fractional distillation, and the resulting vapors travel up a glass tube known as a "fractionating column" and separate.

The fractionating column, which is positioned between the flask containing the mixture and the "Y" adaptor, improves the separation of the liquids being distilled.

In general, the distillation process consists of three major steps: The process of converting a desired liquid from a mixture into vapor. The purified liquid's condensation. The condensed liquid collection.

Heated crude oil enters a tall fractionating column, which is hot at the bottom and cools as it ascends.

The oil vapors rise through the column. When vapors cool sufficiently, they condense. At various heights, liquids are led out of the column.

Thus, these are the steps involved in fractional distillation that used to refine crude oil.

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Final answer:

The symbol notation for the silicon isotope with 16 neutrons is ¹⁴Si, where 14 is the atomic number and 30 is the mass number (sum of protons and neutrons).

Explanation:

The silicon isotope that contains 16 neutrons has a symbol notation that includes the element's atomic number, which is 14 for silicon (Si), and its mass number. The mass number is the sum of the number of protons and neutrons in the nucleus. For this isotope of silicon with 14 protons and 16 neutrons, the mass number is 14 + 16 = 30. Therefore, the symbol notation for this isotope is ¹⁴Si.

The solution with a pH of 2 has 100 times more protons in it than the solution with a pH of 4.

The pH scale is a logarithmic scale that quantifies a solution's acidity or alkalinity based on the concentration of hydrogen ions (protons) in it. Each unit on the pH scale reflects a tenfold change in hydrogen ion concentration. When compared to a solution with a pH of 4, a solution with a pH of 2 has a larger concentration of hydrogen ions. In particular, for every pH unit reduction, the concentration of hydrogen ions increases by a factor of ten. As a result, a pH 2 solution contains 102 (100) times more hydrogen ions than a pH 4 solution.

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A solution with a pH of 2 has a hundred times more protons than a solution with a pH of 4. PH measures the concentration of hydrogen ions (protons) in a solution in a logarithmic scale, where each unit decrease indicates a tenfold increase.

The pH scale is a logarithmic measure of the concentration of hydrogen ions (protons) in a solution. A solution with a pH of 2 has a hundred times (102) more protons than a solution with a pH of 4, because each unit decrease on the pH scale represents a tenfold increase in proton concentration. Therefore, a decrease from pH 4 to pH 2 constitutes a hundredfold increase in proton concentration.

Answer:

Your answer is ANION

Answer:

P₃ = 594.1 mmHg

Explanation:

Given data:

Total pressure of container = 1439 mmHg

Partial pressure of 1st gas = 523.3 mmHg

Partial pressure of 2nd gas = 509.8 mmHg

Partial pressure of 3rd gas = ?

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this  problem by using this law.

P(total) = P₁ + P₂ + P₃

439 mmHg =  523.3 mmHg +  509.8 mmHg + P₃

439 mmHg =  1033.1 mmHg + P₃

P₃ = 1033.1 mmHg -439 mmHg

P₃ = 594.1 mmHg

In the precipitation reaction, the ion that would NOT be present in the complete ionic equation is the iodide ion (I-).

In the precipitation reaction Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq), the ions Pb2+ and NO3- are present in the complete ionic equation because they are soluble in water and dissociate into ions. However, the solid PbI2 that forms is insoluble in water and does not dissociate into ions. Therefore, the iodide ion (I-) is the ion that would NOT be present in the complete ionic equation.

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In the given precipitation reaction, all ions mentioned would be present in the complete ionic equation because soluble compounds turn into ions in such reaction. However, the potassium ion (K+) and the nitrate ion (NO3-) do not partake in the formation of the solid lead iodide, so they are omitted from the net ionic equation.

The question is asking about a precipitation reaction, which is when an insoluble compound forms in an aqueous solution. For the reaction given (2KI(aq) + Pb(NO3)2(aq) → PbI₂ (s) + 2KNO3(aq)), the insoluble compound that forms is lead iodide (PbI₂), which is why it is denoted with an (s) for solid. Soluble compounds break down into ions in aqueous solutions, meaning Pb(NO3)2(aq) becomes Pb²⁺ + 2NO3⁻, and 2KI(aq)  becomes 2K⁺ + 2I⁻. The products would then be K⁺ + NO3⁻ from KNO3(aq) and PbI₂(s), which stays unbroken because it is insoluble. Therefore, the complete ionic equation would be Pb²⁺(aq) + 2NO3⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → PbI₂(s) + 2K⁺(aq) + 2NO3⁻(aq).

In such an equation, the ions that are on both sides of the equation (i.e., do not participate in generating the solid) are spectator ions and can be omitted to achieve the net ionic equation. For our reaction, the spectator ions are K⁺ and NO3⁻. Thus, they would NOT be present in the net ionic equation, but they would still be present in the complete ionic equation.

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Answer:

ATCCGAT

Explanation:

A always matches with T

G always matches with C

Answer:

M or mol/[tex]dm^{3}[/tex]

Explanation:

Answer:

Mol/kg

Explanation:

Ape-x

Answer:

P(Ar) = 27 Kpa

Explanation:

Given data:

Total pressure of tire = 150.0 Kpa

Partial pressure of O₂ = 43.5 Kpa

Partial pressure of Ar  = ?

Partial pressure of N₂ = 79.5 kPA

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this  problem by using this law.

P(total) = PO₂ +  PN₂ + P(Ar)

150.0 Kpa = 43.5 Kpa + 79.5 Kpa + P(Ar)

150.0 Kpa = 123 Kpa + P(Ar)

P(Ar) = 150.0 Kpa - 123 Kpa

P(Ar) = 27 Kpa

Answer:200 c

Explanation:

Final answer:

To raise the temperature of 20 grams of water from 30°C to 40°C, 200 calories of heat are required.

Explanation:

To calculate the amount of heat required to raise the temperature of water, we can use the equation:

heat = mass * specific heat * temperature change

In this case, the mass of water is 20 grams, the specific heat of water is 1 calorie/gram °C, and the temperature change is 10 °C. Substituting these values into the equation:

heat = 20 g * 1 calorie/g °C * 10 °C = 200 calories

Therefore, 200 calories of heat are required to raise the temperature of 20 grams of water from 30 °C to 40 °C.

Answer: All of them are right there’s no wrong answer

Explanation:

Masses for the metal and the water in the calorimeter, temperature changes for the water and the metal, and the known specific heat of the water.

First, the masses of both the metal and the water within the calorimeter are crucial, as they determine the amount of substance undergoing the temperature change. Second, the temperature changes (Tw, final​ −Tw, initial​  and T metal, final −T metal, initial​ ) are necessary to quantify the heat exchange during the experiment. Lastly, the known specific heat of water (C water​ ) plays a role in the calculation, as it is a fundamental constant representing the amount of heat needed to raise the temperature of water.

The first law of thermodynamics, which states that the heat lost by the metal equals the heat gained by the water, and the ability of heat to flow from a hot object to a cooler one are overarching principles guiding the experimental setup and the interpretation of results. However, these principles are not directly inputted into the formula but are fundamental concepts in calorimetry and thermodynamics that inform the experimental design and the interpretation of the calculated specific heat values.

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Answer:

Explanation:

A Brönsted-Lowry acid is defined as any substance that has the ability to lose, or "donate a proton" [H +].

A Brönsted-Lowry base is a substance capable of gaining or "accepting a proton" [H +].

Then a proton transfer occurs, which requires the presence of a proton donor, that is, an acid and a base that accepts them.

This theory has the disadvantage of leaving out several substances that are acidic and that do not have protons.

Thiocyanic acid is a chemical compound that can be considered, but not a Bronsted Lowry base, giving up the proton and generating the anion [SCN] -

Answer:

It can be a bronsted Lowry acid but not a bronsted Lowry base

Explanation:

Bronsted Lowry acid are proton donors, and HSCN can donate a proton, but it cannot accept a proton, hence not a bronsted Lowry base

Answer:

c

Explanation:

Answer:

d. stimulus generalization

Explanation:

Stimulus generalization consists of the appearance of the unconditional response to conditioned stimuli that had never been paired with it but that have a similarity to it.

Answer : The volume of oxygen occupy at 173° would be, 703.2 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.

[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.

We are given:

[tex]V_1=473mL\\T_1=27^oC=(27+273)K=300K\\V_2=?\\T_2=173^oC=(173+273)K=446K[/tex]

Now put all the given values in above equation, we get:

[tex]\frac{473mL}{300K}=\frac{V_2}{446K}\\\\V_2=703.2mL[/tex]

Therefore, the volume of oxygen occupy at 173° would be, 703.2 mL

Answer:

The answer to your question is 0.57 moles

Explanation:

Data

volume = 1.9 L

[NaCl] = 0.3

moles of NaCl = ?

Process

1.- To solve this problem use the formula of Molarity.

Molarity = moles/ volume (l)

-Solve for moles

moles = Molarity x volume

-Substitution

 moles = 0.3 x 1.9

-Result

 moles = 0.57

-Conclusion

There are 0.57 moles of NaCl in 1.90 L of a 0.3 M solution.

Answer : The limiting reagent in this reaction is, [tex]Al_2(SO_4)_3[/tex] and number of moles of excess reagent is, 1.69 moles

Explanation : Given,

Mass of [tex]Al_2(SO_4)_3[/tex] = 500.0 g

Mass of [tex]Ca(OH)_2[/tex] = 450.0 g

Molar mass of [tex]Al_2(SO_4)_3[/tex] = 342.15 g/mol

Molar mass of [tex]Ca(OH)_2[/tex] = 74.1 g/mol

First we have to calculate the moles of [tex]Al_2(SO_4)_3[/tex] and [tex]Ca(OH)_2[/tex].

[tex]\text{Moles of }Al_2(SO_4)_3=\frac{\text{Given mass }Al_2(SO_4)_3}{\text{Molar mass }Al_2(SO_4)_3}[/tex]

[tex]\text{Moles of }Al_2(SO_4)_3=\frac{500.0g}{342.15g/mol}=1.461mol[/tex]

and,

[tex]\text{Moles of }Ca(OH)_2=\frac{\text{Given mass }Ca(OH)_2}{\text{Molar mass }Ca(OH)_2}[/tex]

[tex]\text{Moles of }Ca(OH)_2=\frac{450.0g}{74.1g/mol}=6.073mol[/tex]

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

[tex]Al_2(SO_4)_3(aq)+3Ca(OH)_2(aq)\rightarrow 2Al(OH)_3(s)+3CaSO_4(s)[/tex]

From the balanced reaction we conclude that

As, 1 mole of [tex]Al_2(SO_4)_3[/tex] react with 3 mole of [tex]Ca(OH)_2[/tex]

So, 1.461 moles of [tex]Al_2(SO_4)_3[/tex] react with [tex]1.461\times 3=4.383[/tex] moles of [tex]Ca(OH)_2[/tex]

From this we conclude that, [tex]Ca(OH)_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]Al_2(SO_4)_3[/tex] is a limiting reagent and it limits the formation of product.

Number of moles of excess reagent = 6.073 - 4.383 = 1.69 moles

Therefore, the limiting reagent in this reaction is, [tex]Al_2(SO_4)_3[/tex] and number of moles of excess reagent is, 1.69 moles

Answer:

The correct answer is option a.

Explanation:

When aluminum hydroxide reacts with of nitrous acid it gives of aluminum nitrite and of water.

[tex]Al(OH)_3+3HNO_2\rightarrow Al(NO_2)_3+3H_2O[/tex]

According to above reaction ,when 1 mole of aluminum hydroxide reacts with 3 moles of nitrous acid it gives 1 mole of aluminum nitrite and 3 moles of water.

Hence, the correct answer is option a.