there are 8 hooks in a display of pens. Each hook can hold 3 packages of pens and there are 3 pens in each package. If the display is completely full, how many pens does it hold?
Use the quadratic formula to solve the equation. if necessary, round to the nearest hundredth. a rocket is launched from atop a 101-foot cliff with an initial velocity of 116 ft/s.
a. substitute the values into the vertical motion formula h = −16t2 + vt +
c. let h = 0.
b. use the quadratic formula find out how long the rocket will take to hit the ground after it is launched. round to the nearest tenth of a second.
You spin the spinner shown. Find the sample space for this experiment.
Solve the inequality and find the solution set. y-6 ≥12
which polynomial is a quadratic factor of 27x^3+64
The solution is that 27x^3+64 factors into (3x+4)(9x^2-12x+16).
The 2nd factor is the quadratic factor that you wanted.
What are Polynomials?Polynomials are sums of k-xⁿ terms, where k can be any number and n can be any positive integer.
3x+2x-5, for example, is a polynomial.
here, we have,
we know that,
In general, a^3+b^3 = (a+b)(a^2-ab+b^2).
given that,
27x^3+64
now, we have to factorize the given expression.
using the above formula, we get,
27x^3+64
= (3x+4)(9x^2-12x+16)
Hence, The solution is that 27x^3+64 factors into (3x+4)(9x^2-12x+16).
The 2nd factor is the quadratic factor that you wanted.
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Eight car dealerships reported the number of cars they sold last month. Car Dealership Number of Cars Sold GMC 84 Chevrolet 81 Nissan 92 Toyota 92 Ford 95 Honda 94 Hyundai 80 Acura 72 What is the interquartile range of this set of data?
Answer:
upper quartile is 93
lower quartile is 80.5
Step-by-step explanation:
I got a 100 on quiz
Need this geometry answer
Suppose you have two hyperbolas that are the same except that the transverse axis and conjugate axis are switched. How does switching the axes affect the equations of the asymptotes for the two hyperbolas? Why?
Final answer:
Switching the axes of two hyperbolas affects the equations of the asymptotes.
Explanation:
When the transverse axis and conjugate axis are switched in two hyperbolas, it affects the equations of the asymptotes. The equations of the asymptotes are determined by the ratio of the coefficients of x² and y² in the hyperbola equation. When the axes are switched, this ratio changes, resulting in different equations for the asymptotes.
For example, let's consider two hyperbolas with equations:
1) 8x² + 10xy - 3y² - 2x - 4y - 2 = 0
2) 8y² + 10xy - 3x² - 2x - 4y - 2 = 0
In the first hyperbola, the ratio of the coefficients of x² and y² is 8/(-3), which determines the equation of the asymptotes. In the second hyperbola, the ratio is (-3)/8, leading to different equations for the asymptotes.
If you prove that ∆WXZ is congruent to ∆YZX, which general statement best describes what you have proved?
A.Diagonals of a parallelogram bisect each other.
B. Diagonals of a parallelogram are congruent.
C. Opposite sides of a parallelogram are congruent.
D. The diagonal of a parallelogram connects two non-consecutive vertices.
Proving that ΔWXZ is congruent to ΔYZX does not directly prove any of the provided statements about a parallelogram without additional context. Likely, it could imply that diagonals of a parallelogram bisect each other, but more information is needed.
Explanation:If you prove that ΔWXZ is congruent to ΔYZX, you have demonstrated the congruence of triangles within a geometric figure, likely referencing elements of a parallelogram. However, the specific elements such as sides or diagonals are not indicated in the proof of congruence between the triangles in question.
From the options you have provided and general geometric principles, proving congruent triangles within a figure doesn't necessarily directly prove any of those statements without additional context. If we assume ΔWXZ and ΔYZX are created by a diagonal of a parallelogram, congruent triangles might imply that diagonals of a parallelogram bisect each other (Option A). However, it could also relate to the congruence of opposite sides depending on the specifics of the figure, not the diagonals being congruent (Option B), because congruence of triangles does not guarantee equal length of diagonals, just segments within the triangles.
Given sin z=4/5 and cos x=3/5. What is the ratio for tan z? Enter your answer in the boxes as a fraction in simplest form.
For f(x)=3x+1 and g(x)=x²-6, find (f o g)(4)
Write a point-slope equation for the line that has slope 4 and passes through the point (11,7). Do not use parentheses on the y side.
Would someone Please answer this question please will be thanked and also will pick brainly!! (please be honest)
The GRE is an entrance exam that many students are required to take in order to apply to graduate school. In 2014, the combined scores for the Verbal and Quantitative sections were approximately normally distributed with a mean of 310 and a standard deviation of 12.
What is the probability that a randomly selected score is greater than 334? Write your answer as a decimal.
The probability that a randomly selected score is greater than 334 is 0.0228
How to get the z scores?If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.
If we have [tex]X \sim N(\mu, \sigma)[/tex]
(X is following normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] )
then it can be converted to standard normal distribution as
[tex]Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)[/tex]
(Know the fact that in continuous distribution, probability of a single point is 0, so we can write
[tex]P(Z \leq z) = P(Z < z) )[/tex]
Also, know that if we look for Z = z in z tables, the p value we get is
[tex]P(Z \leq z) = \rm p \: value[/tex]
For this case, we're given that:
Combined scores were approximately normally distributed with mean of 310 and a standard deviation of 12.If we take:
X = a randomly selected score obtained in the GRE exam.
Then, by the given data, we have:
[tex]X \sim N(\mu = 310, \sigma = 12)[/tex]
And therefore, we can write:
Probability that a randomly selected score is greater than 334 = P(X > 334)
Converting X to standard normal distribution:
[tex]Z = \dfrac{X - \mu}{\sigma} = \dfrac{X - 310}{12}[/tex]
The probability we need can be calculated as:
[tex]P(X > 334) = 1 - P(X \leq 334)\\P(X > 334) = 1 - P(Z \leq \dfrac{334 - 310}{12})\\\\P(X > 334) = 1 - P(Z \leq 2)[/tex]
From the z-tables, the p-value for Z = 2 is 0.9772
Thus, we get [tex]P(Z \leq 2) = 0.9772[/tex], and therefore,
[tex]P(X > 334) = 1 - P(Z \leq 2) = 1- 0.9772 = 0.0228[/tex]
Thus, the probability that a randomly selected score is greater than 334 is 0.0228
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The first five terms of a sequence are 8, 9, 10, 11, and 12. How are the terms of the sequence generated?
A. by adding 7 to the term number
B. by multiplying the term number by 7
C. by adding 8 to the term number
D. by multiplying the term number by 8
Answer:
A
Step-by-step explanation:
n1=8. 7+1=8
n2=9. 7+2=9
n3=10. 7+3=10
n4=11. 7+4=11
n5=12. 7+5=12
Stella divides 12/8 on her calculator and gets 1.5. Assuming that Stella has not adjusted the calculator's settings, what do the displayed digits tell you about the answer?
A) Stella made an error.
B) The answer is exactly 1.5.
C) The calculator rounded the answer.
D) The calculator truncated the answer.
Stella divided 12/8.
If we divide 12 by 8, we get exactly 1.5.
Let us check given options one by one .
A) Stella made an error : Stella didn't made an error because it's just division of two numbers.
B) The answer is exactly 1.5. : On dividing 12 by 8, we get exactly 1.5, so this option is correct.
C) The calculator rounded the answer. : On dividing 12 by 8, we get exactly 1.5. So, no rounding is required.
D) The calculator truncated the answer. : On dividing 12 by 8, we get exactly 1.5. So, no truncation in the answer.
Therefore, correct option is B) The answer is exactly 1.5.
How many ounces of water should you drink for every 20 minutes of activity? 12?
The picture below shows a container that Rene uses to freeze water: A cylinder is shown with base diameter of 6 centimeters and the height as 8 centimeters. What is the minimum number of identical containers that Rene would need to make 2000 cm3 of ice? (Use π = 3.14.)
The cylinder has base diameter of 6 centimeters and the height, [tex] h [/tex], of 8 centimeters.
Since the base diameter of the cylinder is 6 cm, therefore, it's radius, [tex] r [/tex], will be 3 cm.
Now, we know that the volume, [tex] V [/tex], of such a cylinder will be:
[tex] V=\pi r^2h [/tex]
Plugging in the values given we get the volume to be:
[tex] V=\pi(3)^2\times 8=3.14\times9\times8=226.08 [/tex] [tex] cm^3 [/tex]
Since Rene needs to make 2000 [tex] cm^3 [/tex] of ice and one cylinder's volume is 226.08 [tex] cm^3 [/tex], Rene would need...
[tex] \frac{2000}{226.08}\approx8.846\approx\boldsymbol{9} [/tex] such identical cylindrical containers.
Final answer:
To make 2000 cm3 of ice, Rene would need a minimum of 9 identical containers, given the volume of one container is 226.08 cm3.
Explanation:
To determine the number of identical cylindrical containers needed to make 2000 cm3 of ice, we must first calculate the volume of one container. Given that the diameter of the base is 6 centimeters, the radius (r) is half of that, which is 3 centimeters. We're also given the height (h) of 8 centimeters. We can use the formula for the volume of a cylinder, V = πr2h.
Plugging in the values, we get:
V = 3.14 × (3 cm)2 × 8 cm
which simplifies to V = 3.14 × 9 cm2 × 8 cm = 226.08 cm3.
Now we can divide the total volume of ice Rene wants to make by the volume of one container:
2000 cm3 ÷ 226.08 cm3 = approx 8.85.
Since Rene cannot use a fraction of a container, she would need a minimum of 9 identical containers to make at least 2000 cm3 of ice.
52 -п(2.5)^2
PLZ I NEED HELP IMEDIATELY
In the equation 2x - y = 4, the x-intercept is 2 and the y-intercept is -4.
how do you solve #3?
The quotient of two numbers is negative. It must be true that _____.
If the markup formula is 40% of cost and selling price of an item is 4999 what is the cost
simplify the expression 36^1/2
Explain why the graph of quadratic function could not contain both a minimum vertex and a maximum vertex at the same time.
Your explanation should be 3-4 sentences and include at least 6 of the following words/phrase.
-parabola
- u-shaped graph
- vertex
- minimum
- maximum
- y-value of the vertex
- x-value of the vertex
- quadratic function
To survey a town about traffic concerns, Henry divided the town into eight regions and randomly chose 10 households from each region. What type of sample did she form?
Answer:
Simple Random answer
Step-by-step explanation:
It says that he divided town into eight regions and randomly chose 10. The sample she formed was the Simple Random Answer.
Using the following set of data, calculate the lower quartile, the upper quartile, and the interquartile range. 20, 22, 25, 28, 29, 30, 32, 33, 34.
Be sure to show your work for finding:
The lower quartile
The upper quartile
The interquartile range
PLs help
According to the information we can infer that the Lower Quartile is 23.5, the upper quartile is 32,5, and the interquartile range is 9.
How to calculate these information?Arrange the data in ascending order: 20, 22, 25, 28, 29, 30, 32, 33, 34.
Calculate the position of the lower quartile using the formula: (n + 1) / 4, where n is the number of data points.
(9 + 1) / 4 = 10 / 4 = 2.5Since 2.5 falls between the 2nd and 3rd data points, you need to find the average of these two values:
(22 + 25) / 2 = 47 / 2 = 23.5Upper Quartile (Q3):
Calculate the position of the upper quartile using the formula: 3 * (n + 1) / 4.
3 * (9 + 1) / 4 = 30 / 4 = 7.5Since 7.5 falls between the 7th and 8th data points, find the average of these two values:
(32 + 33) / 2 = 65 / 2 = 32.5Interquartile Range (IQR):
Calculate the IQR by subtracting Q1 from Q3:
IQR = Q3 - Q1 = 32.5 - 23.5 = 9.So, the lower quartile (Q1) is 23.5, the upper quartile (Q3) is 32.5, and the interquartile range (IQR) is 9.
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Using the following diagram, solve for x.
Answer:
[tex]x=10.5[/tex]
Step-by-step explanation:
Use Thales' Theorem which says: If two lines, not necessarily parallel, are cut by a system of parallel lines, then the segments that result on one of the two lines are proportional to the corresponding segments obtained on the other.
Take a look at the picture I attached you, from it, It is true that:
[tex]\frac{AB}{A'B'} =\frac{BC}{B'C'}[/tex]
Hence:
[tex]\frac{12}{6} =\frac{21}{x}[/tex]
Solving for x:
[tex]x=\frac{21}{2} =10.5[/tex]
Tom bought 7 books. He has space only for 3 books in his bookshelf. In how many ways can he arrange the 3 books?
The required, Tom can arrange the 3 books in the combination of 35 different ways on his bookshelf.
The number of ways to choose a subset of 3 books from a set of 7 books can be calculated using the combination formula:
C(n, k) = n! / (k!(n-k)!)
Where n is the total number of items and k is the number of items we want to choose.
In this case, Tom wants to arrange 3 books out of a set of 7 books. Using the combination formula, we have:
C(7, 3) = 7! / (3!(7-3)!)
= 7! / (3!4!)
Calculating the factorials:
7! = 7 * 6 * 5 * 4 * 3 * 2 * 1 = 5040
3! = 3 * 2 * 1 = 6
4! = 4 * 3 * 2 * 1 = 24
Substituting these values into the formula:
C(7, 3) = 5040 / (6 * 24)
= 5040 / 144
= 35
Therefore, Tom can arrange the 3 books in 35 different ways on his bookshelf.
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Triangle RST was dilated by a scale factor of 1/2. The image, triangle R'S'T', is an isosceles triangle, with each leg measuring 8 units. What is the length of a leg of the pre-image, triangle RST?
Answer:
16 units
Step-by-step explanation:
RST was dilated by a scale factor of 1/2. This means R'S'T' has sides that are 1/2 the length of the sides of RST.
Since the legs of R'S'T' are 8 units, this gives us the equation
8 = 1/2x
Divide both sides by 1/2:
8÷1/2 = x
8 × 2/1 = x
16 = x
Each leg in RST is 16 units.