Suppose a dolphin sends out a series of clicks that are reflected back from the bottom of the ocean 80 m below. How much time elapses before the dolphin hears the echoes of the clicks? (The speed of sound in seawater is approximately 1530 m/s.)

Explanation:

THERE FORE THE REACTION IS FRICTION FORCE.

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It should be pushing because when you swim you are pushing yourself

Answer:

Drinking 20oz of sports drinks decrease the urine volume compared to 20oz of water

Explanation:

Sport drinks typically used by athletes contain water,carbs and electrolytes which helps to replenish the lost minerals from the body during exercises.

Electrolytes an important ingredients of sports drinks is typically sodium and potassium they help the body to retain water,hence less volume of urine is released from the body.

Explanation:

Given that,

Initial speed of the billiard ball 1, u = 30i cm/s

Initial speed of another billiard ball 2, u' = 40j cm/s

After the collision,

Final speed of first ball, v = 50 cm/s

Final speed of second ball, v' = 0 (as it stops)

Let us consider that both balls have same mass i.e. m

Initial kinetic energy of the system is :

[tex]K_i=\dfrac{1}{2}mu^2+\dfrac{1}{2}mu'^2\\\\K_i=\dfrac{1}{2}m(u^2+u'^2)\\\\K_i=\dfrac{1}{2}m((30)^2+(40)^2)\\\\K_i=1250m\ J[/tex]

Final kinetic energy of the system is :

[tex]K_f=\dfrac{1}{2}mv^2+\dfrac{1}{2}mv'^2\\\\K_f=\dfrac{1}{2}m(v^2+v'^2)\\\\K_f=\dfrac{1}{2}m((50)^2+(0)^2)\\\\K_f=1250m\ J[/tex]

The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :

[tex]\Delta K=K_f-K_i\\\\\Delta K=1250m-1250m\\\\\Delta K=0[/tex]

So, the change in kinetic energy of the system as a result of the collision is equal to 0.    

The following sentences are completed and explained below

Explanation:

A is a seasonal wind known as monsoon wind that blows in the opposite direction of normal winds.

Prevailing winds are the wind that blows mainly from a single general direction.

Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.

The monsoon winds are seasonal winds that refers to wind systems that have a pronounced seasonal reversal of direction.

The winds that blow from single direction over a specific area of the earth is known as prevailing winds.

1. Monsoon wind: a seasonal wind that blows in the opposite direction of normal winds.

2. Prevailing wind: it is a wind that blows mainly from a single (one) general direction.

3. Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.

A wind can be defined as the natural movement of air and its constituent gases blowing in a particular with respect to a planet's surface.

Based on the location of occurrence and periodicity, winds are classified into three (3) main categories and these are:

1. Local winds: these include bora, foehn, loo, mistral, etc.

2. Secondary winds: these include mountain and valley breeze, monsoon wind, etc.

3. Primary winds: polar easterlies, trade winds, westerlies, etc.

In this exercise, you're required to complete the given sentences as follows:

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Answer:

the magnitude of the torque about the point where the beam is bolted into place 12.32kNm

Explanation:

N/B The units given in the question are meant to be m, kg and kg respectively

Given data

Length of beam 3.7m

Mass of beam 520kg

Mass of construction worker 73kg

Torque is expressed as the moment or turning effect brought about by a couple

T= F*d

Where d=perpendicular distance

F= force

Converting The mass of the beam and the worker to force we have

520*10= 5200N

73*10=730N

Note that the force due to the mass of the beam is acting at the center of the beam

See the free body diagram attached

Taking moments about point O

Torque =Σ Fxd

Torque =5200x1.85+7x3.7

=9620+2701

=12321 Nm

=12.32kNm

Answer:

Note: Check the attached image for a clearer question

From the attached image, the answers are 2,3,6,7

Explanation:

Maximum power occurs at resonance, i.e. [tex]X_{L} = X_{C}[/tex], not when impedance is greater than resistance

Resonance occurs when the Inductive reactance equals the capacitive reactance, i.e. [tex]X_{L} = X_{C}[/tex], not [tex]R^{2} = (X_{L} - X_{C} ) ^{2}[/tex]

and when, [tex]w = \frac{1}{\sqrt{LC} }[/tex]

Therefore, option B is correct

Since the formula for impedance is [tex]Z = \sqrt{R^{2} + (X_{L}-X_{C}) ^{2} }[/tex], at resonance, Z = R i.e. the impedance is minimum

At resonance, there is maximum power and minimum impedance

Thew Quality Factor, [tex]Q = \frac{w_{0}L }{R} = \frac{1}{R} \sqrt{\frac{L}{C} }[/tex]

The impedance Z is always larger than the resistance R, note that it is not stated that this condition is at Resonance, that makes it correct.

[tex]Z = \sqrt{R^{2} + X^{2} }[/tex]

Answer:

Picture C

Explanation:

Explanation:

Given that,

Wavelength of light, [tex]\lambda=600\ nm=6\times 10^{-7}\ m[/tex]

Angle, [tex]\theta=25^{\circ}[/tex]

We need to find the slit spacing for diffraction. For a diffraction, the first order principal maximum is given by :

[tex]d\sin\theta=n\lambda[/tex]

n is 1 here

d is slit spacing

[tex]d=\dfrac{\lambda}{\sin\theta}\\\\d=\dfrac{6\times 10^{-7}}{\sin(25)}\\\\d=1.41\times 10^{-6}\ m\\\\d=1.41\ \mu m[/tex]

So, the slit spacing is [tex]1.41\ \mu m[/tex].

a.  The greatest angle will be bouncing, then embedded and finally the least is passing angle.

b. The  Momentum is greatest when the arrow bounces and least when the arrow passes.  This justify the obtained ranking of angles.

The given problem is based on the concept of momentum and angle made at various instance. Momentum is defined as an impact caused due to applied force. It is expressed as the product of mass and velocity of an object, with respect to the direction. Taking forward direction of arrow as positive then backward direction will be negative.

From the law of conservation of linear momentum, the sum of initial and final momentum should be equal.

Thus we can conclude that by ranking the angles, consider that the maximum angle that the pumpkin reaches depends on the speed of the pumpkin. The greatest angle will be bouncing, then embedded and finally the least is passing angle.

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Answer:

Kinetic energy of the car = 4637.04 J

Explanation:

Mass of the car (m) =1200 kg

speed of the car (v) = 2.78 m/sec

Kinetic energy =[tex]\frac{1}{2}mv^{2}[/tex]

Putting the values of m and v,

Hence, Kinetic Energy of the car =[tex]\frac{1}{2}1200\cdot 2.78^{2}[/tex] =  4637.04 J

The kinetic energy of a 1,200kg car traveling at a speed of 2.78 m/s is calculated using the formula KE = ½ mv², yielding a kinetic energy of 4,634.88 joules.

To calculate the kinetic energy (KE) of a car with a mass of 1,200kg traveling at a speed of 2.78 m/s, we need to use the kinetic energy formula KE = ½ mv². Plugging in the given values, we have:

KE = ½ (1,200 kg) × (2.78 m/s)²

KE = ½ × 1,200 kg × 7.7284 m²/s²

KE = 4,634.88 J

Therefore, the kinetic energy of the car is calculated to be 4,634.88 joules.

Explanation:

Given that,

(a) Frequency, [tex]f_1=4\times 10^{19}\ Hz[/tex]

All electromagnetic wave moves with the speed of light. It is given by :

[tex]c=f\lambda[/tex]

[tex]\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{4\times 10^{19}}\\\\\lambda_1=7.5\times 10^{-12}[/tex]

(b) Frequency, [tex]f_2=5.5\times 10^{1=9}\ Hz[/tex]

All electromagnetic wave moves with the speed of light. It is given by :

[tex]c=f\lambda[/tex]

[tex]\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{5.5\times 10^{9}}\\\\\lambda_2=0.054\ m[/tex]

Hence, this is the required solution.

Answer:

The internal energy of the gas remains constant,

Explanation:

The isothermal process can be defined as a thermodynamic process in which the temperature of the system remains constant.In isothemal process the process of transfer of heat energy from the surrounding to the system or to the system from the surrounding takes place at constant temperature.

in isothermal process internal energy of the system remains unchanged or constant.

For ideal gas internal energy of the system depends on the temperature.

For ideal gas when it is compressed the work is done by the surrounding on the gas is positive and heat added to the system is negative .When the heat energy is absent,both temperature and internal energy increases. As it is a isothermal process and temperature remains constant the gas must transfer the positive amount of heat to the system.

Hence internal energy of the system of gas remains constant.

Final answer:

During an isothermal compression of a gas, energy is transferred into the gas by heat to maintain its constant temperature, while work is done on the gas and its internal energy remains constant.

Explanation:

When a gas is compressed isothermally, specific events related to energy take place. Isothermal processes occur at a constant temperature, implying that the thermal energy of the gas does not change. If we refer to the first law of thermodynamics, stating that the change in internal energy (\(\Delta E_{int}\)) is equal to heat added to the system (Q) minus the work done by the system (W), we can understand these events. Since the temperature remains constant during an isothermal compression, the internal energy of an ideal gas, which depends only on temperature, also remains constant (\(\Delta E_{int} = 0\)). Work is done on the gas during compression, meaning that there is a transfer of energy into the gas by way of work (W > 0).

To maintain the constant temperature, heat must be removed from the gas equal to the work done on it (Q = W), so there is effective energy transfer into the gas by heat to maintain isothermality. Therefore, the correct statement among the given options is: Energy is transferred into the gas by heat.

Answer :

D. You should schedule an individual meeting with the system engineer to determine whether he has issues with the project that need to be resolved. Get his perspective on how the project is progressing and how he feels about his role.

Final answer:

The work-energy theorem states that the work done by all forces on a particle equals the change in the particle's kinetic energy, expressed as W = ΔKE = ½m( [tex]vf^2 - vi^2[/tex]). The most work is done between the points where kinetic energy changes the most.

Explanation:

The work-energy theorem states that the work done by all forces acting on a particle is equal to the change in the particle's kinetic energy. In formula form, this can be expressed as W = ΔKE, where W is the work done by the forces, and ΔKE is the change in kinetic energy, often written as ΔKE = KEf - KEi, with KEf denoting the final kinetic energy and KEi the initial kinetic energy. For a roller coaster car, the point where it does the most work is where the change in kinetic energy is greatest, typically between the top of the highest hill (where kinetic energy is lowest) and the bottom of the following descent (where kinetic energy is highest).

The formula representing the work-energy theorem is W = ΔKE = ½m( [tex]vf^2 - vi^2[/tex]), where m represents the mass of the object, vf the final velocity, and vi the initial velocity.

Answer:

In the lab activity, I used a virtual watershed to demonstrate how pollutants enter and flow through the watershed. I constructed food chains to show how biotic factors are related. I also predicted and modeled how human activity affected the biotic factors in an ecosystem. Based on my observations, I can conclude that biotic and abiotic factors are closely linked and that human activity that changes the environment, like pollution, can affect all the other parts of an ecosystem in a negative way.

Explanation:

Answer:

In the lab activity, I used a virtual watershed to demonstrate how pollutants enter and flow through the watershed. I constructed food chains to show how biotic factors are related. I also predicted and modeled how human activity affected the biotic factors in an ecosystem. Based on my observations, I can conclude that biotic and abiotic factors are closely linked and that human activity that changes the environment, like pollution, can affect all the other parts of an ecosystem in a negative way.

Answer:

The magnitude of the net force is √2F.

Explanation:

Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:

[tex]F_N=\sqrt{F^{2}+F^{2}}\\\\F_N=\sqrt{2F^{2}}\\\\F_N=\sqrt{2}F[/tex]

Then, it means that the net force acting on the test charge has a magnitude of √2F.

The net force on the test charge q due to the two charges Q is calculated using vector addition and the Pythagorean theorem. Because the two forces act at a right angle, the total force is the vector sum and is equal to F√2.

The magnitude of the net force acting on the test charge due to both of these charges can be calculated using the principles of vector addition in Physics. When a charge q is placed at the corner of a square, the forces exerted by the two charges, Q and Q, at the opposite corners are equal in magnitude but act along different directions. Because these charges are placed at a right angle with respect to charge q, the total force is the vector sum of individual forces, which results in a diagonal force directed along the line joining the charge q and the empty corner of the square. Therefore, the magnitude of the net force is given by the Pythagorean theorem, √(F^2 + F^2), which simplifies to F√2.

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Answer:

5.67 m/s ( towards left)

Explanation:

We are given that

[tex]m_1=6 kg[/tex]

[tex]m_2=10 kg[/tex]

Speed of mass 10 kg=3.4 m/s

We have to find the velocity of other mass.

When there is no external force applied the the linear momentum will be conserved

[tex]-m_2v_2=m_1v_2[/tex]

Substitute the values

[tex]10\times 3.4=6v_1[/tex]

[tex]v_1=-\frac{10\times 3.4}{6}[/tex]

[tex]v_1=-5.67 m/s[/tex]

The mass 6 kg moves to the left with speed 5.67 m/s.

Answer:

D. Could be as small as 4 m, and as large as 12 m.

Explanation:

Since the magnitudes are vectors instead of scalars, their sum is not just the sum of their magnitudes; their directions must be taken in account. The maximum possible magnitude of the resultant occurs when both vectors have the same direction; in that case the resultant magnitude is the sum of the individual magnitudes (in this case, 12 meters). In the other hand, the minimum possible magnitude is when the vectors have opposite directions; in that case the magnitude of the resultant is the substraction of one magnitude to another (in this case, 4 meters). Finally, the right answer is D, because the possible values range from 4m to 12m.

Final answer:

The magnitude of the resultant vector when adding two displacement vectors of 4 m and 8 m can be as small as 4 m if they are in opposite directions or as large as 12 m if they are collinear and in the same direction.(Option D)

Explanation:

The question asks about the magnitude of the resultant vector when two displacement vectors are added. A displacement vector has both magnitude and direction, and when two vectors are combined, their resultant depends on both their magnitudes as well as the angle between them. When two vectors are added, the magnitude of the resulting vector can vary depending on this angle. If the vectors are collinear and in the same direction, the magnitude of the resultant will be the sum of the magnitudes of the individual vectors, which is the maximum possible magnitude.

However, vectors can also be in opposite directions, in which case the resultant magnitude will be the difference between the two, representing the minimum magnitude. Therefore, given two displacement vectors with magnitudes of 4 m and 8 m, the magnitude of the resultant vector upon addition can range from 4 m to 12 m. This occurs because if the vectors are in the same direction, their magnitudes add up (to 12 m); if they are opposite, the resultant is the difference (to 4 m). In any other scenario of different angles between the vectors, the resultant will fall somewhere between 4 m and 12 m.

Answer:

300 minutes.

Explanation:

Given,

Speed of car 1 = 60 Km/h

Speed of car 2 = 75 Km/h

distance travel by car 2 to catch car 1 = 75 Km

time taken to catch the car = ?

Relative velocity between the car = 75 - 60 = 15 Km/h

[tex]time = \dfrac{distance}{speed}[/tex]

[tex]time = \dfrac{75}{15}[/tex]

t = 5 hrs

t = 5 x 60 = 300 minutes.

Two cars passing a point at different speeds can be calculated using time, distance, and speed formulas.

A car passes the Eiffel Tower driving at a constant rate of 60 km per hour. A second car, traveling at a constant rate of 75 km per hour, passes the Eiffel Tower later and catches the first car after traveling 75 km past the tower.

To calculate the time difference between the two cars passing the Eiffel Tower, we can use the formula: Time = Distance / Speed. The second car passes the tower 15 minutes after the first car.

Answer:

1.349 × 10¹² electrons

Explanation:

At equilibrium, the tension T in the string is resolved into horizontal and vertical components. Tcos17 being the vertical component and Tsin17 the horizontal component. The electrostatic force of repulsion at equilibrium, F = kq²/r² where q = excess charge on sphere and r = distance apart at equilibrium,F acts horizontally to the left and its weight, mg acts vertically downwards.

For equilibrium, sum of horizontal components = 0 and  sum of horizontal components = 0. So, Tsin17 - F = 0

Tsin17 = F ⇒ Tsin17 = kq²/r² (1)

Also Tcos17 - mg = 0  ⇒ Tcos17 = mg (2)

Dividing (1) by (2), we have

Tsin17/Tcos17 = kq²/r² ÷ mg

tan17 = kq²/mgr²

q = r√(mgtan17/k)

We find r using cosine rule r = √(500² + 500² -2 × 500²cos 2 × 17) since the string and the masses form an isosceles triangle at equilibrium.

r = √(2 × 500² -2 × 500²cos34) = 500√2(1 - cos 34) = 500√2 × 0.1710 =120.89 mm = 0.1209 m

substituting m = 9.60 g = 9.6 × 10⁻³ g, k = 9 × 10⁹ Nm²/C² and r into q, we have,

q = r√(mgtan17/k)

  = 0.1209 m√(9.6 × 10⁻³ g × 9.8 m/s² × tan17/9 × 10⁹ Nm²/C²)

  = 0.1209 m√(28.76 × 10⁻³ N/9 × 10⁹ Nm²/C²)

  =  0.1209 m√(3.195 × 10⁻¹² C²/m²)

  =  0.1209 m × 1.7877 × 10⁻⁶ C/m

  = 0.2161 × 10⁻⁶ C

  = 2.161 × 10⁻⁷ C

To find the number of surplus electrons, n on each sphere, we divide q by e the electron charge.

So, n = q/e = 2.161 × 10⁻⁷ C ÷ 1.602 × 10⁻¹⁹ C = 0.6825 × 10¹² = 1.349 × 10¹² electrons

The number of surplus electrons on each sphere : 3.27 * 10¹²

Given data :

Mass of metal spheres = 9.60 g

length of string = 500 mm

Angle made by each string with the vertical ( ∅ )  = 17°

we will apply the formula below

number of surplus electrons ( n  ) = [tex]\frac{q}{e}[/tex]  ----- ( 1 )

whereby :

Considering The forces acting on the metal spheres

Tan ∅ = [tex]\frac{q^{2} }{4\pi e_{o}mgr^{2} }[/tex]   ----- ( 2 )

First step : Determine the distance between the spheres

r = 2l * sin∅

 = 2 * 0.500 * sin17°

 = 0.2924 m

Next step : Determine the charge on each sphere

Back to equation ( 2 )

Tan 17° = [tex]\frac{(8.99*10^{9}) * q^{2} }{(9.60 * 10^{-3})*(9.81)*(0.2924 )^{2} }[/tex]

q² = [ ( 0.3057 ) * ( 9.60 * 10⁻³ ) * ( 9.81 ) * ( 0.2924 )² ] / ( 8.99 * 10⁹ )

    = 0.00246 / 8.99 * 10⁹

    = 2.7364 * 10⁻¹³

Charge on each sphere ( q ) = √ (  2.7364 * 10⁻¹³ ) = 5.23 * 10⁻⁷ C

Final step : The number of surplus electrons on each sphere

Back to equation ( 1 )

n = q / e

  = ( 5.23 * 10^-7 ) / ( 1.6 * 10^-19 )

  = 3.27 * 10¹²

Hence we can conclude that the number of surplus electrons on each sphere : 3.27 * 10¹².

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Answer:

0.01 rad

Explanation:

For a double-slit experiment, we have that dsinθ = nλ. The separation between the central maximum and an adjacent maximum is when n = 1

dsinθ = λ

The angular separation θ = sin⁻¹(λ/d)

now d = 100λ

θ = sin⁻¹(λ/100λ) = sin⁻¹(0.01) = 0.573°

θ = 0.573° × π/180 = 0.01 rad

Answer:

Explanation:

Given that,

Mass of cannon

M1= 500kg and initially at rest

U1 = 0m/s

Mass of clown

M2 = 100kg

so it was initial at rest before this time, therefore, U2 = 0

Recoils speed of cannon V1 =5m/s, the recoils speed is after the cannon has left the barrel.

Using construction of linear momentum

Momentum before collision is equal to momentum after collision

The initial momentum is zero since the two bodies are until at rest

And the final momentum is

M1•V1 + M2•V2

Then,

P(initial) = P(final)

0 = M1•V1 + M2•V2

0 = 500 × 5 + 100 × V2

0 = 2500 +100•V2

100•V2 = -2500

V2 = -2500/100

V2 = —25m/s

So, the final velocity of the clown is -25m/s, opposite direction of the cannon

Answer:

a)   W = m g h , b)     W / U = 1

Explanation:

a) work is defined by

        W = F. dy

in this case the force of gravity goes down and the displacement of the particle is down, so the two are parallel and the scalar product is reduced to the algebraic product

        W = F y

strength is the weight of the body

         F = m g

        W = m g h

where h is the distance the body descends

b) the only force acting on the body is the weight of the work and we calculated them in part a, the potential energy is

     U = m g h

to compare the two magnitudes of let's find their relationship

    W / U = mgh / mgh

    W / U = 1

Answer:

The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.

Explanation:

Given:-

- The diameter of the drill bit, d = 98 cm

- The power at which drill works, P = 5.85 hp

- The rotational speed of drill, N = 1900 rpm

Find:-

What Torque And Force Is Applied To The Drill Bit?

Solution:-

- The amount of torque (T) generated at the periphery of the cutting edges of the drilling bit when it is driven at a power of (P) horsepower at some rotational speed (N).

- The relation between these quantities is given:

                         T = 5252*P / N

                         T = 5252*5.85 / 1900

                         T = 16.171 Nm

- The force (F) applied at the periphery of the drill bit cutting edge at a distance of radius from the center of drill bit can be determined from the definition of Torque (T) being a cross product of the Force (F) and a moment arm (r):

                          T = F*r

Where,   r = d / 2

                          F = 2T / d

                          F = 2*16.171 / 0.98

                          F = 33 N

Answer: The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.

Answer:

1) Torque = 21.934 Nm

2) force = 44.76 N

Explanation:

Power = 5.88 hp

1 hp = 746 W

Power = 5.88 x 746 = 4364.1 W

Angular speed in Rpm = 1900 rpm

But angular speed w = (2¶N)/60 rad/s

= (2 x 3.142 x 1900)/60 = 198.968 rad/s

From,

1) Power P = T x w

Where T = torque

T = P/W = 4364.1/198.968 = 21.934 Nm

2) diameter of drill = 98 cm

Radius = 98/2 = 49 cm = 49x10^-2 m

From torque T = Force x radius

Force = Torque /radius

F = 21.934/49x10^-2 = 44.76 N

Answer:

Chemical

Explanation:

Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructions on the box said to twist the pack until the liquids mix. Chemical energy contained in the pack is responsible for producing the heat.

Chemical energy is the energy that is released when chemical substances engage in a chemical reaction and change into other substances. Batteries, food, and gas are a few examples of chemical energy storage mediums.

Chemical energy is the energy held in atom and molecule bonding. Chemical energy can be found in things like batteries, biomass, oil, natural gas, and coal. When humans burn fuel in a car's engine or wood in a fireplace, chemical energy is transformed into thermal energy.

Around the world, we generate heat and power using chemical energy. Methane, natural gas, oil, and petroleum are examples of fossil fuels that we burn to create steam that turns turbines to generate power.

Thus, Chemical energy contained in the pack is responsible for producing the heat.

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Answer:

d. will increase

Explanation:

The process is spinning is known as stellar rotation, it is the rotation of a star about it axis in an angular direction. Now, A single star in the process of forming starts by spinning slowly which is as a result of its size but as  the star collapses under the pull of its own gravity, the radius of the size shrinks and reduces, then the  spinning rate escalate and increases.

Answer:

The second trombones might produce frequency of 435 Hz or 441Hz.

Explanation:  

Beat frequency is defined as number of beats produced per second and numerically equal to the difference between the frequency of super imposing waves.The sound waves interfere constructively.

Beat is the phenomena of interference.

The frequency of the resultant wave is given by

F = f₁ - f₂ eqn 1

where f₁ , f₂ are frequency of waves.

The frequency of first trombones is 438Hz, 6 beats are heard every 2 second,

Beat frequency is F = [tex]\frac{6}{2}[/tex] = 3Hz.

Substituting in eqn 1 , we get two possible solution for frequency of second trombones.

f₂ =f₁ -F = 438 -3 =435Hz

f₂ = f₁ +F = 438+3 =441 Hz.

The second trombones might produce frequency of 435 Hz or 441Hz.

Answer:

A pi bond

Explanation:

A pi bond is a type of covalent bond that results from the formation of a molecular orbital by the side-to-side overlap of atomic orbitals along a plane perpendicular to a line connecting the nuclei of the atoms.

Answer:

The answer to your question is given below

Explanation:

Since both object A and B were dropped from the same height and the air resistance is negligible, both object A and B will get to the ground at the same time.

From the question, we were told that object A falls through a distance to dA at time t and object B falls through a distance of dB at time 2t.

Remember, both objects must get to the ground at the same time..!

Let the time taken for both objects to get to the ground be t.

Time A = Time B = t

But B falls through time 2t

Therefore,

Time A = Time B = 2t

Height = 1/2gt^2

For A:

Time = 2t

dA = 1/2 x g x (2t)^2

dA = 1/2g x 4t^2

For B

Time = t

dB = 1/2 x g x t^2

Equating dA and dB

dA = dB

1/2g x 4t^2 = 1/2 x g x t^2

Cancel out 1/2, g and t^2

4 = 1

4dA = dB

Divide both side by 4

dA = 1/4 dB