Answer:
The mean of X is 122.5 and the standard deviation is 7.9.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they believe that the overall state of moral values is poor, or they do not believe this. The probability of an adult believing this is independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
In this problem, we have that:
[tex]n = 250, p = 0.49[/tex]
So
[tex]E(X) = np = 250*0.49 = 122.5[/tex]
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{250*0.49*0.51} = 7.9[/tex]
The mean of X is 122.5 and the standard deviation is 7.9.
Suppose we have a collection of the heights of all students at your college. Each of the 250 people taking statistics randomly takes a sample of 40 of these heights and constructs a 95% confidence interval for mean height of all students at the college. Which of the following statements about the confidence intervals is most accurate?
A. About 95% of the heights of all students at the college will be contained in these interval
B. About 95% of the time, a student’s sample mean height will be contained in his or her interval.
C. About 95% of the intervals will contain the population mean height.
D. About 95% of the intervals will be identical.
Answer:
Correct option: (C)
Step-by-step explanation:
The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.
Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.
Or, if n such (1 - α)% confidence intervals are constructed then (1 - α)% of these interval will consist of the true parameter value.
It is provided that each of the 250 people taking statistics randomly takes a sample of 40 of these heights and constructs a 95% confidence interval for mean height of all students at the college.
So there sill be n = 250, 95% confidence intervals for mean height of all students at the college.
Then 95% of these 250 confidence intervals for mean will consist of the true mean height of the college students.
Thus, the correct option is (C).
1 of 6
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Peter rolls 2 fair dice and adds the results from each.
Work out the probability of getting a total of 11.
Answer:
1/18
Step-by-step explanation:
Total 11: (5,6) (6,5)
2/36
1/18
60x-24=__(__)
35pts!!!!!
Answer:
Step-by-step explanation:
Answer:
12(5x−2)
Step-by-step explanation:
i think this is the answer plz tell me if im wrong
A test contains twenty true false questions. A student either knows the answer to a question, or guesses at random if he does not know the answer. On any question, the student knows the answer with probability .7. What is the probability that he gets exactly 2 of the twenty questions wrong, if his performance on different questions is independent
Answer:
2.78% probability that he gets exactly 2 of the twenty questions wrong
Step-by-step explanation:
For each question, there are only two possible outcomes. Either he knows the answer, or he does not. The probability of him knowing the answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
On any question, the student knows the answer with probability .7.
This means that [tex]p = 0.7[/tex]
What is the probability that he gets exactly 2 of the twenty questions wrong, if his performance on different questions is independent
2 of 20 wrong, 20-2 = 18 correctly. So this is P(X = 18).
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 18) = C_{20,18}.(0.7)^{18}.(0.3)^{2} = 0.0278[/tex]
2.78% probability that he gets exactly 2 of the twenty questions wrong
Gabriel finds some wooden boards in the backyard with lengths of 5 feet, 2.5 feet and 4 feet. He decides he wants to make a triangular garden in the yard and uses the triangle inequality rule to see if it will work.
PLEASE ANSWER IMMEDIATELY Which sums prove that the boards will create a triangular outline for the garden? Select all that apply.
5 + 2.5 > 4
5 + 2.5 < 4
4 + 2.5 > 5
4 + 2.5 < 5
4 + 5 > 2.5
first one to answer will get brainliest
Answer:
Third one
4 + 2.5 > 5
Step-by-step explanation:
To form a triangle, the longest side should be less than the sum of the two shorter sides (triangular inequality)
Longest side < sum of the shorter ones
Longest side: 5
Shorter ones: 2.5 & 4
5 < 2.5 + 4
This is the same as:
4 + 2.5 > 5
Answer:
1 3 5
Step-by-step explanation:
The shares of the U.S. automobile market held in 1990 by General Motors, Japanese manufacturers, Ford, Chrysler, and other manufacturers were, respectively, 36%, 26%, 21%, 9%, and 8%. Suppose that a new survey of 1,000 new-car buyers shows the following purchase frequencies:
GM Japanese Ford Chrysler Other
193 384 170 90 163
(a) Show that it is appropriate to carry out a chi-square test using these data.
(b) Determine whether the current market shares differ from those of 1990. Use α = .05.
Answer:
Step-by-step explanation:
Hello!
The objective is to test if the purchase frequencies of new-car buyers follow the distribution of the shares of the U.S. automobile market for 1990.
You have one variable of interest:
X: Brand a new-car buyer prefers, categorized: GM, Japanese, Ford, Chrysler and Other
n= 1000
Observed frequencies
GM 193
Japanese 384
Ford 170
Chrysler 90
Other 163
a) The test to use to analyze if the observed purchase frequencies follow the market distribution you have to conduct a Goodness to Fit Chi-Square test.
The conditions for this test are:
- Independent observations
In this case, we will assume that each buyer surveyed is independent of the others.
- For 3+ categories: each expected frequency (Ei) must be at least 1 and at most 20% of the Ei are allowed to be less than 5.
In our case we have a total of 5 categories, 20% of 5 is 1, only one expected frequency is allowed to have a value less than 5.
I'll check this by calculating all expected frequencies using the formula: Ei= n*Pi (Pi= theoretical proportion that corresponds to the i-category)
E(GM)= n*P(GM)= 1000*0.36= 360
E(Jap)= n*P(Jap)= 1000*0.26= 260
E(Ford)= n*P(Ford)= 1000*0.21= 210
E(Chrys)= n*P(Chrys)= 1000*0.09= 90
E(Other)= n*P(Other)= 1000*0.08= 80
Note: If all calculations are done correctly then ∑Ei=n.
This is a quick way to check if the calculations are done correctly.
As you can see all conditions for the test are met.
b) The hypotheses for this test are:
H₀: P(GM)= 0.36; P(Jap)= 0.26; P(Ford)= 0.21; P(Chrys)= 0.09; P(Other)= 0.08
H₁: At least one of the expected frequencies is different from the observed ones.
α: 0.05
[tex]X^2= sum \frac{(Oi-Ei)^2}{Ei} ~~X^2_{k-1}[/tex]
k= number of categories of the variable.
This test is one-tailed right this mean you'll reject the null hypothesis to high values of X²
[tex]X^2_{k-1;1-\alpha }= X^2_{4;0.95}= 9.488[/tex]
Decision rule using the critical value approach:
If [tex]X^2_{H_0}[/tex] ≥ 9.488, reject the null hypothesis
If [tex]X^2_{H_0}[/tex] < 9.488, don't reject the null hypothesis
[tex]X^2_{H_0}= \frac{(193-360)^2}{360} + \frac{(384-260)^2}{260} + \frac{(170-210)^2}{210} + \frac{(90-90)^2}{90} + \frac{(163-80)^2}{80} = 230.34[/tex]
The value of the statistic under the null hypothesis is greater than the critical value, so the decision is to reject the null hypothesis.
Using a 5% level of significance, there is significant evidence to conclude that the current market greatly differs from the preference distribution of 1990.
The chi-square test can be used to determine if there is a significant difference between the observed frequencies and the expected frequencies based on the shares of the U.S. automobile market in 1990. A calculated chi-square statistic greater than the critical value would indicate a significant difference between the current market shares and those of 1990.
Explanation:The first step in the process is to calculate the expected counts for each category based on the shares of the U.S. automobile market in 1990. The expected counts for GM, Japanese manufacturers, Ford, Chrysler, and other amounts to 360, 260, 210, 90, and 80, respectively.
Given the observed frequencies, the chi-square statistic X² can be calculated. The formula for the chi-square test is X² = Σ[(O-E)²/E], where O represents the observed frequency and E represents the expected frequency. Using this formula, the chi-square statistic is calculated.
Finally, using a chi-square distribution table with 4 degrees of freedom (5 categories - 1), and an alpha level of 0.05, you can compare the calculated chi-square statistic to the critical value (9.488). If the chi-square statistic is larger than the critical value, you would reject the null hypothesis and conclude that the current market shares do differ from those of 1990. If the chi-square statistic is smaller than the critical value, you would not reject the null hypothesis and conclude that the current market shares do not significantly differ from those of 1990.
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which expressions are equivalent to the one below? Check all that apply 10^x
The statement equivalent to 10^x is A,C and F.
We have to find the expression equivalent to 10^x.
What is the meaning of the equivalent statement?Equivalent Statements are statements that are written differently but hold the same logical equivalence.
[tex]A.(50/5)^x\\=10^x[/tex]
This is equivalent to the 10^x.
[tex]10 \times 10^x-1\\=10 \times 10^x\times 10^-1\\=10^x[/tex]
This is equivalent to the 10^x.
[tex]50^x / 5^x\\=10^x[/tex]
This is equivalent to the 10^x.
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The expression 10^x represents a form of exponential notation, which includes any expression that has 10 as the base in the format a x 10^x. This is often used in scientific notation to conveniently write very small or large numbers. Such an expression could also be manipulated using rules of exponential arithmetic.
Explanation:The expression 10^x is equivalent to any expression with exponential notation where 10 is the base. This includes expressions like 1.23 x 10^x or 3.6 x 10^-x, where the 'x' in the exponent can be replaced by any number. This introduces the concept of scientific notation, which allows very large and small numbers to be written compactly. For example, 1,230,000,000 can be written 1.23 x 10^9, and 0.00000000036 can be written 3.6 x 10^-10. Exponential Arithmetic further explains how these notations can simplify arithmetic operations. It explains that to multiply two numbers written in exponential form, one should multiply the numbers in the front and add the exponents.
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Which of the following illustrates the product rule for logarithmic equations?
1.log2 (4x) = log2(4) / log2(x)
2.log2 (4x) = log2(4)x log2(x)
3.log2 (4x) = log2(4)-log2 (x)
4.log2 (4x) = log2(4)+log2 (x)
Answer:log2 (4x) = log2(4)+log2 (x) it is D
Step-by-step explanation:
Which on of the following expression can be used to find the area of the polygon? Select all that apply
Answer:
Choices A, C, D, and E are the right choices.
Step-by-step explanation:
Area of the given figure = [tex]174 \:ft^2[/tex]
Option A = 174
Option B = 150
Option C = 174
Option D = 174
Option E = 174
The manufacturer of a machine to package soap powder claimed that her machine could load cartons at a given weight with a range of no more than 0.4 ounce. The mean and variance of a sample of eight 3-pound boxes were found to equal 3.5 and 0.015, respectively. Test the hypothesis that the variance of the population of weight measurements is σ2 = 0.01 against the alternative that σ2 > 0.01.
Answer:
Please see the attached file for the complete answer.
Step-by-step explanation:
Please use mean = 3.5 instead of 3.1 and varience = 0.015 instead of 0.018 in the solution.
A crate is 2 feet in length, 5 feet in height, and has a volume of 40 cubic feet. What is the width of the crate?
Answer: 4 feet
Step-by-step explanation:
The formula for volume is length x width x height
Answer:
The answer to your question is 4 ft
Step-by-step explanation:
Data
length = 2 ft
height = 5 ft
Volume = 40 ft³
width = ?
Process
A crate is a rectangular prism, so to calculate the volume we use
Volume of a rectangular prism = height x length x width
-Solve for width
width = Volume / height x length
-Substitution
width = 40 / (5 x 2)
-Simplification
width = 40/10
-Result
width = 4 ft
2/-3 ÷(−1 2/7) ……...
Answer:0.518518519
Step-by-step explanation:
A bookstore had 45 copies of a magazine. Yesterday, it sold 23 of them. Today, it sold 15 of what remained. How many copies does the bookstore have left?
Answer:
45 original books then 23 is sold = 22
next day 15 is sold so
23-15=7
7 books remain
Step-by-step explanation:
45-23-15=7
"The CEO of a large electric utility claims that 80% of all his customers are very satisfied with the service they receive. To test this claim, the local newspaper surveyed 100 customers, using simple random sampling. Among the sampled customers, 73% say they are very satisfied. Were these surveyed customers less likely to be satisfied than all the CEO’s customers ( \alpha =0.05)?"
Answer:
The claim made by the CEO was correct.
Step-by-step explanation:
The CEO of a large electric utility claims that 80% of all his customers are very satisfied with the service they receive.
A one-proportion z-test can be used to determine whether the claim made by the CEO of a large electric utility is correct or not.
The hypothesis can be defined as:
H₀: The proportion of customers that are very satisfied with the service they receive is 80%, i.e. p = 0.80.
Hₐ: The proportion of customers that are very satisfied with the service they receive is not 80%, i.e. p ≠ 0.80.
The information provided is:
[tex]\hat p[/tex] = 0.73
n = 100
α = 0.05
Compute the test statistic as follows:
[tex]z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.73-0.80}{\sqrt{\frac{0.80(1-0.80)}{100}}}=-1.75[/tex]
The test statistic value is -1.75.
The decision rule is:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Compute the p-value of the two-tailed test as follows:
[tex]p-value=2\times P(Z<-1.75)\\=2\times [1-P(Z<1.75)]\\=2\times [1-0.95994]\\=0.08012 \\\approx 0.08[/tex]
*Use a z-table for the probability.
The p-value of the two-tailed test is 0.08.
p-value = 0.08 > α = 0.05
The null hypothesis was failed to be rejected at 5% level of significance.
Thus, it can be concluded that the claim made by the CEO was correct. The proportion of customers that are very satisfied with the service they receive is 80%.
The following 5 questions are based on this information. An economist reports that 47% (p¯=0.47p¯=0.47) of a random sample of 1200 middle-income American households actively participate in the stock market. The goal is to construct a 95% confidence interval of the proportion (pp) of all middle-income Americans who actively participate in the stock market. The standard error (SE) of p¯p¯ is Select one:
a. 0.47
b. 0.047
c. 0.021
d. 0.014
Answer:
Option D) 0.014
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 1200
Sample proportion =
[tex]\hat{p} = 0.47[/tex]
We have to make a 95% confidence interval.
Formula for standard error:
[tex]S.E = \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]
Putting the values, we get:
[tex]S.E = \sqrt{\dfrac{0.47(1-0.47)}{1200}} = 0.014[/tex]
Thus, the correct answer is
Option D) 0.014
Really confused can someone please help me with this?
Step-by-step explanation:
4x + 7° = 5x - 1°
5x - 4x = 7° + 1°
x = 8°
As OR~=OS
Which type of number is 0.46?
A Whole
B Natural
c Terminating and rational
D Terminating and irrational
Answer:
terminating and rational
Step-by-step explanation:
Answer:
C: Terminating and Rational
Step-by-step explanation:
A whole number is a number with no decimal places so the answer is not A.
A natural number is a whole number which is equal to or greater than 0, and since 0.46 is not a whole number, the answer is not B either.
A terminating number is a number which does not go on forever, like 3.86. A rational number is a number which can be expressed as a fraction, and 0.46 can be expressed as 46/100. Thus 0.46 is both terminating and rational, making C the answer.
PLEASE HELP I WILL GIVE YOU BRAINLIEST
Your friend earns $10.50 per hour.This is 125% of her hourly wage last year. How much did your friend earn per hour last year?
Let your friend's hourly wage last year be $x.
125% of x = 10.50
[tex]\frac{125}{100}[/tex] x = 10.5
[tex]\frac{5}{4}[/tex] x = 10.5
5x = 42
x = $8.40
Your friend's hourly wage last year was $8.40.
I hope this helps! If you have any doubts, feel free to ask.
Answer:
it is $8.40
Step-by-step explanation:
sorry my answer got deleted :(
R=1/6 the problem is 3r2
Step-by-step explanation:
Putting the value of r
3 ( 1/6) 2
So 3 × (1/6) = 0.5 × 2 = 1
Find the quotient of 4/7 and 3/5
Give your answer as a fraction in its simplest form.
The quotient of [tex]\frac{4}{7} $ and $ \frac{3}{5}[/tex] is [tex]\frac{20}{21}[/tex]
Recall:
The quotient of two quantities or values is the result you get by dividing one with the other.
Therefore, the quotient of [tex]\frac{4}{7} $ and $ \frac{3}{5}[/tex] is solved as shown below:
[tex]\frac{4}{7} \div \frac{3}{5} \\[/tex]
Change the division sign to multiplication sign and turn the second fraction upside down
[tex]\frac{4}{7} \times \frac{5}{3} \\[/tex]
Multiply both fractions together
[tex]= \frac{4 \times 5}{7 \times 3}\\= \frac{20}{21}[/tex]
Therefore the quotient of [tex]\frac{4}{7} $ and $ \frac{3}{5}[/tex] is [tex]\frac{20}{21}[/tex]
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The quality-control manager at a compact fluorescent light bulb (CFL) factory needs to determine whether the mean life of a large shipment of CFLs is equal to 7 comma 5137,513 hours. The population standard deviation is 1 comma 080 hours1,080 hours. A random sample of 8181 light bulbs indicates a sample mean life of 7 comma 2137,213 hours. a. At the 0.050.05 level of significance, is there evidence that the mean life is different from 7 comma 513 hours question mark7,513 hours? b. Compute the p-value and interpret its meaning. c. Construct a 9595% confidence interval estimate of the population mean life of the light bulbs. d. Compare the results of (a) and (c). What conclusions do you reach?
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 7463
For the alternative hypothesis,
µ ≠ 7463
This is a 2 tailed test
Since the population standard deviation is given, z score would be determined from the normal distribution table. The formula is
z = (x - µ)/(σ/√n)
Where
x = sample mean
µ = population mean
σ = population standard deviation
n = number of samples
From the information given,
µ = 7463 hours
x = 7163 hours
σ = 1080 hours
n = 81
b) z = (7163 - 7463)/(1080/√81) = - 2.5
Looking at the normal distribution table, the probability corresponding to the z score is 0.02
Recall, population mean is 7463
The difference between sample sample mean and population mean is 7463 - 7163 = 300
Since the curve is symmetrical and it is a two tailed test, the x value for the left tail is 7463 - 300 = 7163
the x value for the right tail is 7463 + 300 = 7763
These means are higher and lower than the null mean. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area. We already got the area below z as 0.02
We would double this area to include the area in the right tail of z = 2.5. Thus
p = 0.02 × 2 = 0.04
It means that in a sample of size 81 light bulbs, we would observe a sample mean of 300 hours or more away from 7463 about 4% of the time by chance alone.
c) Confidence interval is written in the form,
(Sample mean - margin of error, sample mean + margin of error)
The sample mean, x is the point estimate for the population mean.
Margin of error = z × σ/√n
To determine the z score, we subtract the confidence level from 100% to get α
α = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025
This is the area in each tail. Since we want the area in the middle, it becomes
1 - 0.025 = 0.975
The z score corresponding to the area on the z table is 1.96. Thus, z score for 95% confidence level is 1.96
Margin of error = 1.96 × 1080/√81
= 235.2
Confidence interval = 7163 ± 23.2
a) Since alpha, 0.05 > than the p value, 0.04, then we would reject the null hypothesis. Therefore, at a 5% level of significance, there is evidence that the mean life is different from 7463 hours
Comparing the results of a and c, it is true that the population mean life is not 7463 hours.
You are offered the following gamble based on coin flips. If the first heads occurs on the first flip, you get $2. If the first heads occurs on the second flip, you get $4, and so on, so that if the first heads is on the Nth flip, you get $2N. The game continues until there is a heads. Which of the following best represents the expected value of this gamble in dollars? e 0 π [infinity] When offered, most people say they would pay only less than $10 to play this game.
Answer:
infinity
Step-by-step explanation:
a) the expected value of this gamble in dollars is Infinity
i.e
expected value = [tex]\frac{1}{2}*2 + \frac{1}{4}*4 + \frac{1}{8}*8 + \frac{1}{16}*16 + ... + \to \infty (infinty) \\[/tex]
= [tex]1+1+1+1+1 + ... = \infty[/tex]
b)
When offered, most people say they would pay only less than $10 to play this game.
What are two reasons why people are willing to pay so much less than the expected value?
These people are ready to pay less than $10 to play this game due to the fact that people usually overlook the unlikely event when making decisions. In a bid to that logic, they gamble in order to double their amount of money and the probability that heads may never come is ignored by these people and they may hope for a likely event i.e a head every time they play the game.
Also, the expected value is so humongous that if and only if that the first head appears after a long series of tails which is very less certain to occur, because mostly people would think that on an average the length of a series of tails ( or heads) is somewhat near 10 or so, but definitely infinity.
Solve equation by using the quadratic formula.
8x^2+5x=3
Help plzzz
Answer:
x=−1, 3/8
Step-by-step explanation:
Answer:
x= 3/8 or x=-1
Step-by-step explanation:
Step 1: Subtract 3 from both sides.
8x2+5x−3=3−3
8x2+5x−3=0
Step 2: Factor the left side of the equation.
(8x−3)(x+1)=0
Step 3: Set factors equal to 0.
8x−3=0 or x+1=0
x=3/8 or x=-1
NEED HELP ASAP!! FILL IN THE BLANKS!! I'LL MARK YOU BRAINLIEST IF YOU ANSWER RIGHT!!!
Answer:
(x+8)^2 = 127
Step-by-step explanation:
Raj has a full deck of 52 cards. Sydney chooses the queen of clubs and holds onto it. Then Yolanda chooses a card. What is the total number of possible outcomes for Yolanda’s card?
The total number of possible outcomes for Yolanda’s card is 51.
What is Probability?A branch of mathematics concerned with the analysis of random phenomena, or occurrence of things.
Given that, Raj has a full deck of 52 cards. Sydney chooses the queen of clubs and holds onto it. Then Yolanda chooses a card.
Since, there is only 1 queen of clubs in a deck of cards, so, after choosing 1 card from deck there will be remaining only 51 cards.
Therefore, there will be 51 cards remaining for Yolanda to choose.
Hence, The total number of possible outcomes for Yolanda’s card is 51.
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The arch beneath a bridge is semi-elliptical, a one-way roadway passes under the arch. The width of the roadway is 38 feet and the height of the arch over the center of the roadway is 12 feet. Two trucks plan to use this road. They are both 8 feet wide. Truck 1 has an overall height of 11 feet and Truck 2 has an overall height of 12 feet. Draw a rough sketch of the situation and determine which of the trucks can pass under the bridge.
Answer:
Only truck 1 can pass under the bridge.
Step-by-step explanation:
So, first of all, we must do a drawing of what the situation looks like (see attached picture).
Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:
[tex] \frac{x^2}{a^2}+\frac{y^2}{b^2}[/tex]
where:
a= wider side of the ellipse
b= shorter side of the ellipse
in this case:
[tex] a=\frac{38}{2}=19ft[/tex]
and
b=12ft
so we can go ahead and plug this data into the ellipse formula:
[tex] \frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}[/tex]
and we can simplify the equation, so we get:
[tex] \frac{x^2}{361}+\frac{y^2}{144}[/tex]
So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.
in order to do this let's solve the equation for y:
[tex] \frac{y^{2}}{144}=1-\frac{x^{2}}{361}[/tex]
[tex] y^{2}=144(1-\frac{x^{2}}{361})[/tex]
we can add everything inside parenthesis so we get:
[tex] y^{2}=144(\frac{361-x^{2}}{361})[/tex]
and take the square root on both sides, so we get:
[tex] y=\sqrt{144(\frac{361-x^{2}}{361})}[/tex]
and we can simplify this so we get:
[tex] y=\frac{12}{19}\sqrt{361-x^{2}}[/tex]
and now we can evaluate this equation for x=4 (half the width of the trucks) so:
[tex] y=\frac{12}{19}\sqrt{361-(8)^{2}}[/tex]
y=11.73ft
this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.
Truck 1 and Truck 2 can both pass under the bridge.
Explanation:To determine which truck can pass under the bridge, we need to compare the height of the truck to the height of the arch over the center of the roadway. The height of the arch is given as 12 feet. Truck 1 has an overall height of 11 feet, so it can pass under the bridge. Truck 2 has an overall height of 12 feet, which is equal to the height of the arch, so it can also pass under the bridge.
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For a large supermarket chain in a particular state, a women's group claimed that female employees were passed over for management training in favor of their male colleagues. The company denied this claim, saying it picked the employees from the eligible pool at random to receive this training. Statewide, the large pool of more than 1000 eligible employees who can be tapped for management training is 30% female and 70% male. Since this program began, 39 of the 50 employees chosen for management training were male and 11 were female. Complete parts a through d. LOADING... Click the icon to view the results of using technology. a. The company claims that it selected employees for training according to their proportion in the pool of eligible employees. Define a parameter of interest and state this claim as a hypothesis. Explain why this hypothesis is a no-effect hypothesis. Define a parameter of interest. Choose the correct answer below.
Answer:
Step-by-step explanation:
Hello!
Tha claim is those female employees have less probability of being selected for management training than the males employees of a supermarket chain.
The company denies this claim and assures that the employees are picked at random from an eligible pool, i.e. that there is no gender bias in the manager selection
If you consider the variables:
X₁: Number of female employees selected for management training
X₂: Number of male employees selected for management training
The parameter of interest would be
p₁: population proportion of female employees selected for management training
p₂: population proportion of male employees selected for management training
If the company claims that there is no gender bias in the management selection is true, then the proportion of female employees selected for management training and the proportion of male employees selected for management training should be the same, symbolically: p₁ = p₂
If the company's claim is incorrect, then these proportions should be different: p₁ ≠ p₂
I hope this helps!
Lily paid $19.16 for a 1 kg Apple basket this amount includes the tax of 3% what was the cost of the Apple before tax
Answer:
0.57 or 0.6
Step-by-step explanation:
Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N intersects the circle at point M. The length of P N is 32, the length of Q N is x, the length of L M is 22, and the length of M N is 14. In the diagram, the length of the external portion of the secant segment PN is . The length of the entire secant segment LN is . The value of x is .
Answer:
In the diagram, the length of the external portion of the secant segment PN is x. The length of the entire segment LN is 36. The value of x is 17.75.
Step-by-step explanation:
I just did it on Edge.
I need help please?!!
Answer:
No, the expression is not linear because the highest power of x is 2.
Answer:
No it isn't it is Quadratic