Suppose that a stove and a freezer together weigh at least 370 pounds. The weight of the stove is 170 pounds. Which inequality correctly describes these conditions for the weight of the freezer,

The slope of the line is 2/3

To find the slope of the line, first choose two points that are on the line. For this example we'll use (0, -4) and (6, 0). Now use the slope formula with these two points to find the slope.

m(slope) = (y2 - y1)/(x2 - x1)

m = (0 - -4)/(6 - 0)

m = (0 + 4)/(6 - 0)

m = 4/6

m = 2/3

[tex]Given \ function : \ f(x) = 2x^6-2x^2-5[/tex]

In order to find the end behavior of the graph, we need to find the degree of the given function and the leading coefficent.

Degree of the given function is the highest power of the variable.

We have variable x there.

Highest power of x is 6.

So, we can say:

Degree = 6 ( an even degree)

And leading coefficent is the coefficent of highest power term.

We have highest power term is 2x^6.

So, the leading coefficent is : 2 (Positive number)

For even degree and positive leading coefficent, end behaviour is

x --> ∞  f(x) = +∞

x-->-∞   f(x) = +∞

Answer:

The answer is A on edg

Step-by-step explanation:

just took the test

The digit 4 in 6,296.04 is in the hundredths place, representing four hundredths or 4/100. This can also be expressed in scientific notation as 4 x 10⁻².

The place value of the digit 4 in 6,296.04 is in the hundredths position. This is because the digit 4 is two places to the right of the decimal point. In a decimal number, the first place to the right of the decimal point is the tenths place, the second is the hundredths place, and it continues with thousandths, ten-thousandths, and so on. Therefore, in the number 6,296.04, the 4 represents four hundredths, or 4/100, which can also be written in scientific notation as 4 × 10⁻².

The graphs of sine and cosine functions have similarities with the swinging motion such as repeating patterns at equal time intervals and smoothness.

The graphs of sine and cosine functions have several similarities with the swinging motion you observe:

These similarities are because simple harmonic motion, which includes swinging, is closely related to sine and cosine waves.

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Answer:

Number is 23.

Step-by-step explanation:

We have been given the information when a number is divided by 22 the remainder is 1.

And when it is added to 5  it will give us an even number.

So, the number 23 if we take when divided by 22 it will give the remainder 1.

And when added to 5 it will give 23+5=28 which is an even number.

So, the number is 23.

A number cube is rolled 120 times. The number 4 comes up 47 times.

We have to determine the experimental probability of rolling a 4.

The formula to evaluate probability of an event is given by:

Probability  = [tex] \frac{Favourable outcomes}{Total outcomes} [/tex]

So, Probability of rolling a 4 = [tex] \frac{ Total number of times when 4 appears}{Total number of times number cube rolled} [/tex]

= [tex] \frac{47}{120} [/tex]

Now, we have to find the theoretical probability of rolling a 4.

Total number of outcomes of number cube = {1,2,3,4,5,6}

Probability of rolling a 4 = [tex] \frac{1}{6} [/tex]

So, Option B is the correct answer.

Final Answer:

The probability that at least one of the four randomly selected people has been vaccinated is approximately 0.9606.

Explanation:

To find the probability that at least one of the four randomly selected people has been vaccinated, we can use the complement rule. The complement of "at least one person vaccinated" is "none of the people vaccinated." Then, we subtract the probability of none of them being vaccinated from 1.

Given that 61% of the population has been vaccinated, the probability that a randomly selected person has been vaccinated is [tex](P(\text{vaccinated}) = 0.61\)[/tex].

So, the probability that a randomly selected person has not been vaccinated is [tex]\(P(\text{not vaccinated}) = 1 - P(\text{vaccinated}) = 1 - 0.61 = 0.39\).[/tex]

Now, we can find the probability that none of the four randomly selected people has been vaccinated:

[tex]\[P(\text{none vaccinated}) = (0.39)^4\][/tex]

And the probability that at least one of them has been vaccinated is the complement of this:

[tex]\[P(\text{at least one vaccinated}) = 1 - P(\text{none vaccinated}) = 1 - (0.39)^4\][/tex]

Let's calculate it:

[tex]\[P(\text{at least one vaccinated}) = 1 - (0.39)^4\][/tex]

[tex]\[P(\text{at least one vaccinated}) \approx 1 - 0.0394179 \][/tex]

[tex]\[P(\text{at least one vaccinated}) \approx 0.9605821\][/tex]

So, the probability that at least one of the four randomly selected people has been vaccinated is approximately 0.9606.

The probability that at least one of the 4 randomly selected people has been vaccinated is calculated using the complement rule and is found to be 0.9769.

To determine the probability that at least one of the 4 randomly selected people has been vaccinated, we can use the complement rule. The probability of an individual not being vaccinated is 1 - 0.61 = 0.39.

We need to calculate the probability that none of the 4 selected people are vaccinated and subtract this from 1:

Thus, the probability that at least one of them is vaccinated is:

1 - 0.0231 = 0.9769

Therefore, the probability that at least one of the 4 randomly selected people has been vaccinated is 0.9769.

volume of the rectangular prism = base area * height

base area = length * breadth

volume of the rectangular prism = length * breadth * height

volume of the rectangular prism = 5*8*2 = 80 inches ^3

volume of taken up by the eraser = 5.5 inches^3

volume that is not take-up by the eraser = 80-5.5 = 74.5 inches^3