Suppose you buy flour and corn meal in bulk to make flour tortillas and corn tortillas flour cost $1.50 per pound and corn meal cost $2.50 per pound do you want to spend masking $25 on flour and corn meal but you need at least 6 pounds altogether Write a system of linear equalities

did you get the answer?? please let me know

Answer:

[tex]77.4\ in^3[/tex]

Step-by-step explanation:

we know that

To find out how much empty space is left inside the box, subtract the volume of 18 cans of cola from the volume of the box

step 1

Find the volume of the box

The volume of the box is equal to

[tex]V=LWH[/tex]

substitute the given values

[tex]V=(12)(6)(5)[/tex]

[tex]V=360\ in^3[/tex]

step 2

Find the volume of the can of cola

The volume of a cylinder is equal to

[tex]V=\pi r^{2} h[/tex]

we have

[tex]r=1\ in[/tex]

[tex]h=5\ in[/tex]

substitute

[tex]V=\pi (1)^{2} (5)[/tex]

[tex]V=5\pi\ in^3[/tex]

Multiply by 18 (18 cans of cola)

[tex]V=(18)5\pi=90\pi\ in^3[/tex]

step 3

Find how much empty space is left inside the box

[tex]V=(360-90\pi)\ in^3[/tex] ---> exact value

assume

[tex]\pi =3.14[/tex]

[tex]V=360-90(3.14)=77.4\ in^3[/tex]

Answer:

77.4

Step-by-step explanation:

Answer:

40 hours will it take for the pool to fill.

Step-by-step explanation:

A pump can fill a swimming pool in 8 hours.

Work done by pump to fill in 1 hour is  [tex]\frac{1}{8}[/tex]

The pool also has a drain that can empty the pool in 10 hours.

Work done by pump to drain in 1 hour is  [tex]\frac{1}{10}[/tex]

If someone turns on the pump to fill the pool, but forgets to shut the drain.

Work done by both pipe in 1 hour is

[tex]W=\frac{1}{8}-\frac{1}{10}[/tex]

[tex]W=\frac{10-8}{80}[/tex]

[tex]W=\frac{2}{80}[/tex]

[tex]W=\frac{1}{40}[/tex]

Both pipe filled [tex]\frac{1}{40}[/tex] part of pool in hours = 1

Both pipe filled complete pool in hours = [tex]\frac{1}{\frac{1}{40}}=40[/tex]

Therefore, 40 hours will it take for the pool to fill.

The possible values of X and their associated probabilities are:

4: with probability 6/91

1: with probability 64/91

4: with probability 28/91

To determine the probabilities associated with each possible value of X (winnings), we need to consider all the possible combinations of selecting two balls from the urn:

Possible Cases:

Two Black Balls:

Probability = (4C2 / 14C2) * (4C2 / 14C2) = 6/91, where 4C2 represents choosing 2 balls from 4 black balls and 14C2 represents choosing 2 balls from a total of 14 balls.

Winnings (X) = $2 * 2 = $4.

One Black Ball, One White Ball:

There are two scenarios: Black-White and White-Black.

Probability (Black-White) = (4C1 * 8C1) / 14C2 = 32/91.

Probability (White-Black) = (8C1 * 4C1) / 14C2 = 32/91.

Combining both scenarios, total probability = 64/91.

Winnings (X) = $2 * 1 - $1 * 1 = $1.

Two White Balls:

Probability = (8C2 / 14C2) = 28/91.

Winnings (X) = $1 * 0 - $2 * 2 = -$4.

Therefore, the possible values of X and their associated probabilities are:

4: with probability 6/91

1: with probability 64/91

4: with probability 28/91

Final answer:

To determine the probabilities for X, the winnings from selecting two balls out of an urn with 8 white, 4 black, and 2 orange balls, one must calculate the probability of each possible combination of draws and the associated winnings.

Explanation:

To complete the explanation and provide accurate calculations for the probabilities associated with each possible value for X (the winnings from selecting two balls), we need to adjust and clarify the possible outcomes and their associated winnings based on the given scenario:

1. Two Black Balls:

  - Winning: $4 (since each black ball is worth $2)

  - Probability [tex]: \( \frac{4}{14} \times \frac{3}{13} \)[/tex] because there are 4 black balls out of 14 total, and then 3 out of 13 after the first is drawn.

2. One Black and One White Ball:

  - Winning: $1 (since a black ball is +$2 and a white ball is -$1)

  - Probability:[tex]\( 2 \times \frac{4}{14} \times \frac{8}{13} \)[/tex] because there are two ways this can happen (black then white or white then black).

3. Two White Balls:

  - Winning: -$2 (since each white ball is -$1)

  - Probability:[tex]\( \frac{8}{14} \times \frac{7}{13} \)[/tex] because there are 8 white balls initially, then 7 out of the remaining 13.

4. One Black Ball and One Orange Ball:

  - Winning: $2 (since a black ball is +$2 and an orange ball has no change)

  - Probability:[tex]\( 2 \times \frac{4}{14} \times \frac{2}{13} \)[/tex] because there are two ways this can occur (black then orange or orange then black).

5. One White Ball and One Orange Ball:

  - Winning: -$1 (since a white ball is -$1 and an orange ball has no change)

  - Probability: [tex]\( 2 \times \frac{8}{14} \times \frac{2}{13} \)[/tex] because there are two sequences for this outcome (white then orange or orange then white).

6. Two Orange Balls

  - Winning: $0 (since orange balls have no change)

  - Probability:[tex]\( 2 \times \frac{8}{14} \times \frac{2}{13} \)[/tex]  because there are only 2 orange balls.

A) The function F(x) becomes F(x) = 500(sec x)²

B) The average force exerted by the press over the interval [0, pi/3] is 825.7 N.

Given that,

The force F (in newtons) of the hydraulic cylinder in a press is proportional to the square of sec x.

And, The domain of F is [0, pi/3], and F(0) = 500

A) For F as a function of x,

Since F is proportional to the square of sec x.

We are also given that F(0) = 500.

Let's denote the constant of proportionality as k.

Hence write the equation as:

F(x) = k(sec x)²

To find the value of k, substitute x = 0:

500 = k(sec 0)²

Since sec 0 = 1, we get:

k = 500

So, the function F(x) becomes:

F(x) = 500(sec x)²

B) For the average force exerted by the press over the interval [0, pi/3],  evaluate the average value of F(x) over this interval.

The average value of a function f(x) over an interval [a, b] is given by:

Average value = (1 / (b - a)) × ∫[a to b] f(x) dx

In this case, a = 0 and b = pi/3.

Average value = (1 / (pi/3 - 0)) × ∫[0 to pi/3] 500(sec x)² dx

Simplifying, we get:

Average value = (3/pi) × ∫[0 to pi/3] 500(sec x)² dx

Integrating (sec x)², we have:

Average value = (3/pi) [500 tan x] [from 0 to pi/3]

Evaluating this expression, we get:

Average value ≈ 825.7 N

Therefore, the average force exerted by the press over the interval [0, pi/3] is 825.7 N.

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The force F of the hydraulic cylinder is defined by the equation F(x)=500(secx)^2. The average force over the interval [0, pi/3] can be found by integrating this function over the interval and dividing by the interval length.

The force F of the hydraulic cylinder is directly proportional to the square of sec x, where sec x = 1/cos x. Given that F(0)=500, it implies that when x=0, F=500, so the proportionality constant k can be determined by substituting these values into the equation, as F=k(secx)^2. Where cos 0 = 1, therefore sec 0 = 1. So we get F=k*(1)^2 => k=500. Therefore, the equation that defines F as a function of x is F(x)=500(secx)^2.

To find the average force exerted by the press over the interval [0,pi/3], we need to integrate this function over the given interval and divide by the length of the interval. Therefore: F_avg = (1/(pi/3 - 0))∫ from 0 to pi/3 (500(secx)^2) dx. Solving this definite integral equation will yield the average force.

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Answer:

18,471.6 cubic inches of wax will be needed

Step-by-step explanation:

We want the volume that will be required for 210 candles. We first find the volume of 1 candle by using volume of cylinder formula. Then multiply that answer by 210 to find volume of wax needed to make 210 such candles.

Volume of Cylinder is given by the formula:

[tex]V=\pi r^2 h[/tex]

Where

r is the radius

h is the height

Given,

r = 2 in

h = 7 in

We substitute and find 1 candle volume:

Volume of 1 candle = [tex]\pi r^2 h = \pi (2)^2 (7) = 87.96[/tex]

Hence,

Volume of 210 candles = 87.96 * 210 = 18,471.6 cubic inches

Answer:

18,471.6

Step-by-step explanation:

Answer: Option (C)

Explanation:

Linear programming is referred to as the mathematical method designed in order to assist individuals to plan and thus make decisions which are necessary in order to allocate the resource. Under linear programming, first an individual defines the objective, thereby also looking at the limits i.e. constraints that are being put forth. Also defining the alternatives and the linearity.

A linear programming problem requires an objective, constraints, alternatives, and linearity. The objective is what you're trying to achieve, constraints are limitations or restrictions, alternatives are options available to reach your objective, while linearity necessitates that all functions in the problem must be linear.

The correct answer is C: An objective, constraints, alternatives, and linearity. These are the four requirements of a linear programming problem. The objective refers to what the problem is attempting to achieve, such as minimizing cost or maximizing profit. Constraints are the limitations or restrictions of the problem. Alternatives refer to the different options or decisions available to reach the objective. Finally, the requirement of linearity is that all functions in the problem, whether they are objective or constraints, must be linear.

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Answer:

5

Step-by-step explanation:

To answer this, we must figure out the minimum amount we can add 32 to itself to reach 150. This means that we must multiply 32 by our desired amount, x, to reach the amount of hours closest to 150 (but above/equal to it). To find x, we can divide 150 by 32, and if it gives us a number with no decimals or remainders, that is x, as it is the smallest amount of people to get above/equal to 150. If it gives us a remainder/decimal, we must round up, as we cannot have a part of a person and we must get the work done, so we must get at least 150 hours. 150/32 is 4.6 something, so we must round up. 5 is our answer

The number of people required to do the work of 150 hours in a week is 5.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the work in an office takes 150 hours to complete every week. Each person in the office works 32 hours a week.

The number of people will be calculated as,

N = ( 150 / 32 )

N = 4.7 or 5 people

Therefore, the number of people required to do the work of 150 hours in a week is 5.

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Answer:

k=545/43948.8

Step-by-step explanation:

widgets per second

The constant of proportionality for the scenerio given will be 11.53

The general equation of a straight line is -

[y] = [m]x + [c]

where -

[m] is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] is the y - intercept i.e. the point where the graph cuts the [y] axis.

The equation of a straight line can be also written as -

Ax + By + C = 0

By = - Ax - C

y = (- A/B)x - (C/A)

We have 545 workers who worked 7 hours and  produced 43948.8 widgets and the number of widgets that a manufacturing plant can produce varies jointly as the number of workers and the time that they have worked.

The equation can be represnted using the equation of a straight line. We can write -

y = kx

Now, x = 545 x 7 = 3815

So -

43948.8 = (3815)k

k = 43948.8/3815

k = 11.52

Therefore, the constant of proportionality for the scenerio given will be 11.53

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Answer:

8. [tex]\displaystyle \frac{9[x + 5]}{x - 14}[/tex]

7. [tex]\displaystyle -\frac{2x - 1}{2[3x - 5]}[/tex]

6. [tex]\displaystyle \frac{2[x - 4]}{5[x + 3]}[/tex]

5. [tex]\displaystyle \frac{2x + 7}{x + 3}[/tex]

4. [tex]\displaystyle 3x^{-1}[/tex]

Step-by-step explanation:

All work is shown above from 8 − 4.

I am joyous to assist you anytime.

Answer:

The probability that the sample proportion of 80 LL70 batteries is within 0.03 of the population proportion is 0.44

Step-by-step explanation:

Sample proportion being within margin, or margin of error (ME) around the mean can be found using the formula

ME=[tex]\frac{z*\sqrt{p*(1-p)}}{\sqrt{N} }[/tex] where

Then 0.03=[tex]\frac{z*\sqrt{0.86*0.14}}{\sqrt{80} }[/tex] from this we get:

z≈0.773 and the p(z)≈0.439

Therefore, the probability that the sample proportion is within 0.03 of the population proportion is 0.44

Answer:

  It takes the second worker 11 hours to do the job alone  

Step-by-step explanation:

The problem tells you how to work it.

  [tex]\dfrac{1}{11}+\dfrac{1}{x}=\dfrac{2}{11}\\\\x+11=2x \qquad\text{multiply by 11x}\\\\11=x \qquad\text{subtract x}[/tex]

x = 11 tells you the second worker takes 11 hours to do the job alone.

_____

You can also work directly with the fractions. Subtract 1/11 and you have ...

  1/x = 1/11

It should not be a real stretch to see that x=11. If you need, you can multiply both sides by 11x to get 11=x.

Answer:

Part (A): There are 9 integers between 5 and 31 which are divisible by 3.

Part (B): There are 6 integers between 5 and 31 which are divisible by 4.

Part (C): There are 2 integers between 5 and 31 which are divisible by 3 and by 4.

Step-by-step explanation:

Consider the provided information.

Part (A) we need to find how many integers between 5 and 31 are divisible by 3.

Between 5 and 31 there are 25 integers.

According to quotient rule: [tex]\frac{25}{3} \approx8.33[/tex]

That means either 8 or 9 integers are divisible by 3 as 8.33 lies between 8 and 9.

The integers are: 6, 9, 12, 15, 18, 21, 24, 27, 30

Hence, there are 9 integers between 5 and 31 which are divisible by 3.

Part (B) we need to find how many integers between 5 and 31  are divisible by 4.

Between 5 and 31 there are 25 integers.

According to quotient rule: [tex]\frac{25}{4} \approx6.25[/tex]

That means either 6 or 7 integers are divisible by 4, as 6.25 lies between 6 and 7.

The integers are: 8, 12, 16, 20, 24, 28

Hence, there are 6 integers between 5 and 31 which are divisible by 4.

Part (C) we need to find how many integers between 5 and 31 are divisible by 3 and by 4

Between 5 and 31 there are 25 integers.

Integers should be divisible by 3 and by 4, that means integers should be divisible by 3×4=12.

According to quotient rule: [tex]\frac{25}{12} \approx2.08[/tex]

That means either 2 or 3 integers are divisible by 3 and by 4 or 12, as 2.08 lies between 2 and 3.

The integers are: 12, 24,

Hence, there are 2 integers between 5 and 31 which are divisible by 3 and by 4.

To find positive integers that are divisible by 3, 4, or both between 5 and 31, we can determine the multiples of each number. The multiples of 3 are: 6, 9, 12, 15, 18, 21, 24, 27, and 30. The multiples of 4 are: 8, 12, 16, 20, 24, and 28. The multiples of both 3 and 4 (or their least common multiple, 12) are: 12 and 24.

a) To find the positive integers between 5 and 31 that are divisible by 3, we need to look for numbers that are multiples of 3. Starting with 6, the first multiple of 3 in this range, we continue adding 3 to each number until we reach the highest multiple less than or equal to 31. So the multiples of 3 between 5 and 31 are: 6, 9, 12, 15, 18, 21, 24, 27, and 30.

b) To find the positive integers between 5 and 31 that are divisible by 4, we need to look for numbers that are multiples of 4. Starting with 8, the first multiple of 4 in this range, we continue adding 4 to each number until we reach the highest multiple less than or equal to 31. So the multiples of 4 between 5 and 31 are: 8, 12, 16, 20, 24, and 28.

c) To find the positive integers between 5 and 31 that are divisible by both 3 and 4, we need to find the common multiples of 3 and 4. This can be done by finding the multiples of the least common multiple (LCM) of 3 and 4, which is 12. So the multiples of 12 between 5 and 31 are: 12 and 24.

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Answer:

1/4

Step-by-step explanation:

Take my word for it.

(Yes I know this answer is late)

To solve the equation 3(‒4x + 5) = 12, apply the distributive property, then use subtraction to isolate the variable, and lastly, divide to find the value of x, which is 0.25.

To solve the linear equation 3(−4x + 5) = 12, we start by applying the distributive property to eliminate the parentheses:

Next, we use the subtraction property of equality to isolate the variable:

Finally, we apply the division property of equality to solve for x:

The subject of this question is mathematics, specifically quadratic functions. The student needs to find the interval of the domain that represents the airplane while it was in the air.

The subject of this question is Mathematics, specifically quadratic functions. The question asks about a quadratic function that models the height of a toy airplane relative to the ground. The student needs to find the interval of the domain that represents the airplane while it was in the air.

To find the interval of the domain, we need to determine the maximum horizontal distance the airplane traveled before landing. The horizontal distance is represented by the variable x in the quadratic function. Since the horizontal distance was 50 feet, the interval of the domain should be [0, 50]. This means the airplane was in the air for a horizontal distance between 0 and 50 feet.

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Answer:

Option B

Step-by-step explanation:

multiplying 2/5 with 5/2 will give 1 on the left hand side of the equation

multiplying 10 with 5/2 will give 25 on the right hand side of the equation, ultimately resulting in  x=25

The number that we must use to multiply each side of the equation 2/5x = 10 to produce the equivalent equation x = 25 is; B: 5/2

We are given the equation;

(2/5)x = 10

Multiplying both sides by the same number is same as the original equation.

Thus, to make the left hand side only x, let us multiply both sides by the inverse of 2/5 which is 5/2 to get;

x = 10 × 5/2

x = 25

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Answer:

[tex]-\frac{ln(662)-2}{4}[/tex]

{-1.12}

Step-by-step explanation:

[tex]e^{2 - 4x} = 662[/tex]

Solve this exponential equation using natural log

Take natural log ln on both sides

[tex]ln(e^{2 - 4x}) = ln(662)[/tex]

As per the property of natural log , move the exponent before log

[tex]2-4x(ln e) = ln(662)[/tex]

we know that ln e = 1

[tex]2-4x= ln(662)[/tex]

Now subtract 2 from both sides

[tex]-4x= ln(662)-2[/tex]

Divide both sides by -4

[tex]x=-\frac{ln(662)-2}{4}[/tex]

Solution set is {[tex]x=-\frac{ln(662)-2}{4}[/tex]}

USe calculator to find decimal approximation

x=-1.12381x=-1.12

- In terms of natural logarithms: [tex]\( \{ \ln(2) \} \)[/tex]

- In decimal approximation: [tex]\( \{ 0.69 \} \)[/tex] (rounded to two decimal places)

To solve the exponential equation [tex]\( e^2 - 4x = 662 \),[/tex] we can follow these steps:

Step 1: Isolate the exponential term by subtracting 2 from both sides:

[tex]\[ e^2 - 2 = 662 \][/tex]

Step 2: Divide both sides by -4 to isolate ( x ):

[tex]\[ -4x = 660 \][/tex]

Step 3: Divide both sides by -4 to solve for ( x ):

[tex]\[ x = -\frac{660}{4} \][/tex]

[tex]\[ x = -165 \][/tex]

Now, let's express the solution in terms of natural logarithms:

[tex]\[ x = -165 \][/tex]

To obtain a decimal approximation for the solution, we can use a calculator. Substituting [tex]\( x = -165 \)[/tex] back into the original equation:

[tex]\[ e^2 - 4(-165) = 662 \][/tex]

[tex]\[ e^2 + 660 = 662 \][/tex]

[tex]\[ e^2 = 2 \][/tex]

Now, take the natural logarithm of both sides:

[tex]\[ \ln(e^2) = \ln(2) \][/tex]

[tex]\[ 2\ln(e) = \ln(2) \][/tex]

[tex]\[ 2 = \ln(2) \][/tex]

So, the solution in terms of natural logarithms is [tex]\( x = \ln(2) \).[/tex]

The decimal approximation for [tex]\( x = \ln(2) \)[/tex] is approximately [tex]( x \approx 0.69315 \).[/tex]

Therefore, the solution set is:

- In terms of natural logarithms: [tex]\( \{ \ln(2) \} \)[/tex]

- In decimal approximation: [tex]\( \{ 0.69 \} \)[/tex] (rounded to two decimal places)

Answer:

c. Multiple zero is 3; multiplicity is 2

Step-by-step explanation:

The factor is repeated, that is, the factor  ( x  −  3 )  appears twice. The number of times a given factor appears in the factored form of the equation of a polynomial is called the multiplicity. The zero associated with this factor,  x  =  3 , has multiplicity 2 because the factor  ( x  −  3 )  occurs twice.

Then

Multiple zero is 3; multiplicity is 2.

Answer:

multiple zero is -3 and multiplicity is 2

Step-by-step explanation:

Answer:

Step-by-step explanation:

The equation of a straight line is usually represented in the slope-intercept form, y = mx + c

Where c = y intercept

m = slope

We want to determine the slope of the line parallel to 2y=3x+6

Rearranging 2y=3x+6 in the slope intercept form, it becomes

2y/2 = 3x/2 + 6/2

y = 3x/2 + 3

The slope = 3/2

If two lines are parallel to each other, the their slopes are equal.

So the slope of the line parallel to 2y=3x+6 is 3/2

To determine slope of the line perpendicular to y=8x+24

Comparing y=8x+24 with the slope intercept form, y = m+ c,

Slope, m = 8

If two limes are perpendicular, then the product of the slopes is -1

Let the slope of the perpendicular line to the one given by the above equation be m1. Therefore,

8 × m1 = -1

8 m1 = -1

m1 = -1/8

,

Answer:

The y-coordinate is changing by the rate of -70 cm per sec.

Step-by-step explanation:

Given equation,

[tex]y = 7x^2 + 4[/tex]

Differentiating with respect to time (t),

[tex]\frac{dy}{dt}=14x \frac{dx}{dt}[/tex]

We have,

[tex]\frac{dx}{dt}=-5\text{ cm per sec}, x = 1[/tex]

[tex]\frac{dy}{dt} = 14(1)(-5)=-70\text{ cm per sec}[/tex]

Answer: He traveled 10 km/hr through bike and 5km/hr by jogging.

Step-by-step explanation:

Let the speed of bike be 'x'.

Let the speed of his jogging be 'x-5'.

Distance covered = 10 miles

So the jog took 1 hour longer than the bike ride.

According to question, we get that

[tex]\dfrac{10}{x-5}-\dfrac{10}{x}=1\\\\10\dfrac{x-x+5}{x(x-5)}=1\\\\\dfrac{50}{x^2-5x}=1\\\\50=x^2-5x\\\\x^2-5x-50=0\\\\x^2-10x+5x-50=0\\\\x(x-10)+5(x-10)=0\\\\(x+5)(x-10)=0\\\\x=10\ km/hr[/tex]

Hence, he traveled 10 km/hr through bike and 5km/hr by jogging.

Final answer:

To demonstrate that E[1/X] for a geometric random variable X with success probability p equals −p log(p)/(1−p), we use the pmf of a geometric distribution and turn the sum into an integral, ultimately showing the expected result through integration.

Explanation:

To show that for a geometric random variable X with parameter p, the expected value E[1/X] is −p log(p)/(1−p), we begin by recognizing that the probability mass function (pmf) of a geometric distribution with success probability p is given by P(X = x) = p(1-p)^(x-1) for x = 1, 2, 3, ... . To find E[1/X], we sum the values of 1/x multiplied by the probability of each x, which is ∑ (1/x)*p(1-p)^(x-1).

To evaluate this, we express each term α_i/i, where α_i = p(1-p)^(i-1), as an integral from 0 to 1-p of x^(i-1) dx. We then change the order of summation and integration, which is permissible under the conditions of the monotone convergence theorem:
∑ (α_i / i) = ∑ ∫_{0}^{1-p} x^(i-1) dx

= ∫_{0}^{1-p} (∑ x^(i-1)) dx

= ∫_{0}^{1-p} (p / (1 - x)) dx

= p ∫_{0}^{1-p} 1/(1 - x) dx

= -p log(1 - (1-p))

= -p log(p) / (1-p).

Solving [tex]-\frac{1}{2}x<-12[/tex] we get [tex]x>24[/tex]

Step-by-step explanation:

We need to solve the given inequality to find value of x.

[tex]-\frac{1}{2}x<-12[/tex]

Solving:

[tex]-\frac{1}{2}x<-12[/tex]

Multiply both sides by 2

[tex]-\frac{1}{2}x*2<-12*2[/tex]

[tex]-x<-24[/tex]

Multiply both sides by (-1) and reverse the inequality sign i.e < is changed to >

[tex]x>24[/tex]

So, solving [tex]-\frac{1}{2}x<-12[/tex] we get [tex]x>24[/tex]

Keywords: Solving inequalities

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Answer:

an = 4/3n - 13/3.

Step-by-step explanation:

The first term is a1,

a24 = a1 + 23d

83/3 = a1 + 4/3* 23

a1 =    83/3 - 92/3

a1 = -9/3 = -3.

So the nth term an =  -3 + 4/3(n - 1)

an = -3 + 4/3 n - 4/3

an = 4/3n - 13/3

To find the explicit formula for the general nth term of an arithmetic sequence, use the formula a_n = a_1 + (n - 1)d, where a_n represents the nth term, a_1 is the first term, and d is the common difference. In this case, the explicit formula is a_n = -3 + (n - 1)(4/3), based on given information a_24 = 83/3 and d = 4/3.

To find the explicit formula for the general nth term of an arithmetic sequence, we use the formula: a_n = a_1 + (n - 1)d, where a_n represents the nth term, a_1 is the first term, and d is the common difference. In this case, we are given that a_24 = 83/3 and d = 4/3. We can substitute these values into the formula and solve for a_1. From there, we can simplify the formula and express it in its lowest terms.

Given: a_24 = 83/3 and d = 4/3

We can rearrange the formula and solve for a_1 as follows:

Now that we have found a_1 = -3, we can simplify the formula and express it as:

a_n = -3 + (n - 1)(4/3)

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The total cost to join the website for one year is $34.00

Step-by-step explanation:

Onetime membership fee = $10

Per month newsletter charges = $2.00

One year = 12 months

Newsletter charges for 1 year = [tex]2.00*12=\$24[/tex]

Total cost = One time fee + newsletter charges for 1 year

[tex]Total\ cost=10+24.00=\$34.00[/tex]

The total cost to join the website for one year is $34.00

Keywords: addition, multiplication

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Answer:

36

Step-by-step explanation:

Given:

Length of the cardboard = 27 inches

Width of the cardboard = 72 inches.

Let "x" be side of the square which is cut in each corner.

Now the height of box = "x" inches.

Now the length of the box = 27 - 2x and width = 72 - 2x

Volume (V) = length × width × height

V = (27 - 2x)(72 - 2x)(x)

[tex]V= (1944 -144x -54x + 4x^2)x\\V = (4x^2 - 198x +1944)x\\V = 4x^3 -198x^2 +1944x[/tex]

Now let's find the derivative

V' = [tex]12x^2 - 396x + 1944[/tex]

Now set the derivative equal to zero and find the critical points.

[tex]12x^2 - 396x + 1944[/tex] = 0

12 ([tex]x^2 - 33x + 162[/tex]) = 0

Solving this equation, we get

x = 6 and x = 27

Here we take x = 6, we ignore x = 27 because we cannot cut 27 inches since the entire length is 27 inches.

So, the area of the square = side × side

= 6 inches × 6 inches

The area of the square = 36 square inches.

Answer: the other zeros are -3/2 and 5/3

Step-by-step explanation:

Answer:

The proof with the statement is given below.

Step-by-step explanation:

Given:

Construction of angle bisector i.e SP is the bisector of angle RPQ.

To prove:

Δ PWS ≅ Δ PXS

Proof:

In  Δ PWS  and Δ PXS  

∠ WPS ≅ ∠ XPS    …………..{definition of angle bisector}

SP ≅ SP                .......…….{Reflexive property}

PW ≅ XP              ……....….{definition of ≅}

Δ PWS  ≅ Δ PXS  …...........{Side-Angle-Side test i .e SAS}

Angle bisector: A ray divides angle into two equal measures then the ray is called as angle bisector of the bisected angle.

In the construction SP is the bisector of the angle ∠ RPQ

SAS: This test is to prove the triangle congruent when two sides are congruent and angle between that sides should be congruent. then we can say the triangle is congruent by side angle side test.

Answer:

5/9 yards

Step-by-step explanation:

Just subtract 2/9 from 5/9 to find the difference, which is the answer.

Answer:

D. X= ± square root of 8 - 2

Step-by-step explanation:

Given quadratic equation is \[x^{2}+4x=4\]

Rearranging the terms: \[x^{2}+4x-4=0\]

This is the standard format of quadratic equation of the form \[ax^{2}+bx+c=0\]

Here, a=1 , b=4 and c=-4.

Roots of the quadratic equation are given by \[\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\]

Substituting the values and calculating the roots:

\[\frac{-4 \pm \sqrt{(-4)^{2}-4*1*(-4))}}{2*1}\]

= \[\frac{-4 \pm \sqrt{32}}{2}\]

= \[\frac{-2*2 \pm 2*\sqrt{8}}{2}\]

= \[-2 \pm \sqrt{8}\]

Hence option D is the correct option.

The solution of x² + 4x = 4 is x =  ± √8 - 2,

Hence, option D is correct.

The given quadratic equation is,

x² + 4x = 4

Here we have to solve it by completing square method

Now proceed the expression,

⇒ x² + 4x = 4

Adding 4 both sides,

⇒ x² + 4x + 4 = 4 + 4

⇒ x² + 4x + 4 = 8

Since we know that 2² is equal to 4, then

⇒ x² + 4x + 2² = 8

Since we know that, Formula of complete square,

(a+b)² = a² + 2ab + b²

Therefore,

⇒ (x+2)² = 8

Taking square root both sides we get,

⇒ (x+2) = ±√8

Hence,

x =  ± √8 - 2

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