The mass of strawberries after freeze-drying would be significantly less than their original mass, given that most of the water content is removed during the process. For 100 kg of fresh strawberries, the approximate mass after freeze-drying would be about 8.4 kg, assuming 91.6% water content.
The approximate mass of strawberries after freeze-drying can be calculated by considering the water content in the fresh strawberries. Fresh strawberries consist of about 91.6% water. During the freeze-drying process, most of this water is removed, hence reducing the mass significantly.
To estimate this change in mass, we can subtract the mass of water (91.6% of the original mass) from the total mass of the fresh strawberries (100 kg). Thus, the dried strawberries would approximately be 8.4% of their original mass, since the mass of fructose and other non-water components remain. This is an estimation and the actual number can be slightly higher or lower depending on the exact freeze-drying process and the specifics of the strawberries.
Therefore, after freeze-drying 100 kg of fresh strawberries, which originally consist of 91.6% water, the approximate mass of the strawberries would be about 8.4 kg.
If a spacecraft that seems to be motionless in deep space is given some type of quick push, what will happen?
A. The spacecraft will not move because it only works on earth.
B. The spacecraft will move and will not stop until it is stopped by an equal or opposite force.
C. The spacecraft will not move due to air resistance.
D. The spacecraft will move and then slowly come to a stop on its own.
the answer i believe is B
Answer:
B. The spacecraft will move and will not stop until it is stopped by an equal or opposite force.
Explanation:
From the first law of motion (given by Newton), a body continues to be in state of rest or motion, unless and until an unbalanced external force acts on it. This is also known as law of inertia.
So, according to this law, the spacecraft which is motionless would move when a push is given to it. It will now keep on moving until an equal and opposite force acts on it and stops it.
Thus, option B is correct.
What type of power plant used heat from underground to make electricity
That's called "Geothermal" energy.
"Geo ..." always means something about the Earth.
"Thermal ..." always means something about heat.
Geothermal energy is used in places where there's a lot of heat that's not too far under the ground, like in places above ancient volcanos.
The system is built with pipes running deep down into the ground and then back up again, and then running water is pumped through the pipes. The water picks up heat from down under and brings the heat up to the surface, where it can be used to heat homes and buildings, and turn steam turbines to generate electricity.
Geothermal is the MAIN source of energy in Iceland.
The type of power plant that uses heat from underground to make electricity is called a geothermal power plant.
Geothermal power plants harness the heat stored in the Earth's crust to generate electricity. This heat energy is typically obtained from geothermal reservoirs, which are areas where hot water or steam is trapped beneath the Earth's surface. The heat is extracted through wells and used to drive turbines connected to generators, converting the thermal energy into electrical energy.
Geothermal power plants are a renewable and sustainable energy source as they rely on the natural heat of the Earth.
To know more about the geothermal power plant:
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a mosquito flaps its wings 600 times per second. find its time period. pls i want the answer fast.
As
Mosquito flaps its wings in one sec= 600 times.
Time Period = Time required to flap wings one time
So Time period = 1/ 600
Time period =0.00167 sec
Time period = 1.7×10³ sec
You are driving at the speed of 27.7 m/s (61.9764 mph) when suddenly the car in front of you (previously traveling at the same speed) brakes and begins to slow down with the largest deceleration possible without skid- ding. Considering an average human reaction, you press your brakes 0.507 s later. You also brake and decelerate as rapidly as possible without skidding. Assume that the coefficient of static friction is 0.868 between both cars’ wheels and the road. The acceleration of gravity is 9.8 m/s2 . Calculate the acceleration of the car in front of you when it brakes. Answer in units of m/s2.
Here when car in front of us applied brakes then it is slowing down due to frictional force on it
So here we can say that friction force on the car front of our car is given as
[tex]F_f = \mu m g[/tex]
So the acceleration of car due to friction is given as
[tex]F_{net} = - \mu mg[/tex]
[tex]a = \frac{F_{net}}{m}[/tex]
[tex]a = -\mu g[/tex]
now it is given that
[tex]\mu = 0.868[/tex]
[tex]g = 9.81 m/s^2[/tex]
so here we have
[tex]a = -0.868 * 9.81[/tex]
[tex]a = -8.52 m/s^2[/tex]
so the car will accelerate due to brakes by a = - 8.52 m/s^2
The acceleration of the car when it was front of him is [tex]\\\rm \bold { -8.52 m/s^2}[/tex].
Given here,
[tex]\rm \bold{ \mu = 0.868}\\\rm \bold{ g =9.81 m/s^2}[/tex]
The friction force applied on car is
[tex]\rm \bold { F_f= \mu mg}\\[/tex]
[tex]\rm \bold { F_n_e_t= - \mu mg}\\[/tex]
The acceleration due to friction
[tex]\rm \bold { a = \frac{F_n_e_t}{m} }\\\\\rm \bold { a = -\mu g}[/tex]
[tex]\rm \bold { a = -0.868\times 9.81}\\\rm \bold { a = -8.52 m/s^2}[/tex]
Hence, we can conclude that the acceleration of the car when it was front of him is [tex]\\\rm \bold { -8.52 m/s^2}[/tex].
To know more about acceleration, refer tot the link:
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A 5.0-kg block of wood is placed on a 2.0-kg aluminum frying pan. How much heat is required to raise the temperature of both the wood and the pan from 20°C to 45°C? (Note: The specific heat wood is 1700 J/kg ·°C and of aluminum is 900 J/kg ·°C.)
Heat required to raise the temperature of a given system is
[tex]Q = ms\Delta T[/tex]
here we know that
m = mass
s = specific heat capacity
[tex]\Delta T[/tex] = change in temperature
now as we know that
mass of wood = 5 kg
mass of aluminium pan = 2 kg
change in temperature = 45 - 20 = 25 degree C
specific heat capacity of wood = 1700 J/kg C
specific heat capacity of aluminium = 900 J/kg C
now here we will find the total heat to raise the temperature of both
[tex]Q = m_1s_1\Delta T_1 + m_2s_2\Delta T_2[/tex]
[tex]Q = 5 * 1700 * 25 + 2 * 900 * 25[/tex]
[tex]Q = 212500 + 45000[/tex]
[tex]Q = 257500 J[/tex]
So heat required to raise the temperature of the system is 257500 J
It is difficult to observe 1-nanometer, 1 millimeter, and 100 meter radiation with ground-based telescopes. What are the reasons for each?
Explanation:
1 nano-meter radiations are very difficult to observe from the ground based telescope because most of this range of radiation is absorbed through ozone layer. A very small amount of this range escape out of the ozone layer. This remaining few radiations are very difficult to track from the ground base telescope.
1 millimeter range of radiation comprises of infrared. It has range from 710 nano-meter to 1 millimeter. Infrared radiation can be easily absorbed from water and carbon di oxide molecules present in the atmosphere. So, it is absorbed by water and carbon di oxide molecules in the atmosphere. Thus, it is difficult to observe from the ground based telescope.
100 meter radiations are are radio-waves. The charged particle present in the uppermost layer of atmosphere absorbs these radio waves. So, these waves are absorbed by charged particle in the upper atmosphere. Thus, it is difficult to observe from the ground based telescope.
why do you choose MCB in place of a fuse？
It protects the electrical appliance and the person from electrical shocks/faults.
Hope it Helped!