Suppose you have $1,950 in your savings account at the end of a certain period of time. You invested $1,700 at a 6.88% simple annual interest rate. How long, in years, did you invest your money? State your result to the nearest hundredth of a year.

Answer:

The total result of the investment after 4 years is $395.98

Step-by-step explanation:

Great Question, since we are talking about compounded interest we can use the Exponential Growth Formula to calculate the total value of the investment after 4 years. The Formula is the following,

[tex]y = a*(1+\frac{x}{n})^{nt}[/tex]

Where:

Now we can plug in the values given to us in the question and solve for the total amount (y).

[tex]y = 300*(1+\frac{0.07}{4})^{4*4}[/tex]

[tex]y = 300*(1.0175)^{16}[/tex]

[tex]y = 300*1.3199[/tex]

[tex]y = 395.98 [/tex] ... rounded to the nearest hundredth

Now we can see that the total result of the investment after 4 years is $395.98

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Answer:  

The converse and contrapositive of the given conditional statement are :

Converse : "If x is an even number, then 2 divides x".

Contrapositive : "If x is not an even number, then 2 does not divide x."

Step-by-step explanation:  We are given to write the converse and contrapositive of the following conditional statement :

"If 2 divides x, then x is an even number."

Let us consider that

p : 2 divides x

and

q : x is an even number.

We know that

the CONVERSE of a conditional statement p ⇒ q is written as q ⇒ p.

So, the converse of the given statement is

"If x is an even number, then 2 divides x".

The CONTRAPOSITIVE of the conditional statement  p ⇒ q is written as ~q ⇒ ~p (where ~p stands for the negation of p).

So, the contrapositive of the given statement is

"If x is not an even number, then 2 does not divide x."

Thus, the converse and contrapositive of the given statement are :

Converse : "If x is an even number, then 2 divides x".

Contrapositive : "If x is not an even number, then 2 does not divide x."

Answer:

$29,721

Step-by-step explanation:

We have been given that Wyatt is investing money into a savings account that pays 2% interest compounded annually, and plans to leave it there for 15 years. We are asked to find the amount deposited by Wyatt in order to have a balance of $40,000 in his savings account after 15 years.

We will use compound interest formula to solve our given problem.

[tex]A=P(1+\frac{r}{n})^{nT}[/tex], where,

A = Final amount after T years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

T = Time in years.

Let us convert our given interest rate in decimal form.

[tex]2\%=\frac{2}{100}=0.02[/tex]

Upon substituting our given values in compound interest formula, we will get:

[tex]\$40,000=P(1+\frac{0.02}{1})^{1*15}[/tex]

[tex]\$40,000=P(1+0.02)^{15}[/tex]

[tex]\$40,000=P(1.02)^{15}[/tex]

[tex]\$40,000=P\times 1.3458683383241296[/tex]

Switch sides:

[tex]P\times 1.3458683383241296=\$40,000[/tex]

[tex]\frac{P\times 1.3458683383241296}{ 1.3458683383241296}=\frac{\$40,000}{1.3458683383241296}[/tex]

[tex]P=\$29,720.5891995[/tex]

Upon rounding our answer to nearest dollar, we will get:

[tex]P\approx \$29,721[/tex]

Therefore, Wyatt will have to invest $29,721 now in order to have a balance of $40,000 in his savings account after 15 years.

The solutions of the given equation are:

              x=0,1,4 and 9

We are asked to find the solution of the equation:

[tex]x^2-x=0\ \text{mod}\ 12[/tex]

i.e. we have to find the possible values of x such that the equation is true.

then

[tex]x^2-x=0-0\\\\i.e.\\\\x^2-x=0[/tex]

Hence, x=0 is the solution of the equation.

then

[tex]x^2=1\\\\Hence,\\\\x^2-x=1-1\\\\i.e.\\\\x^2-x=0[/tex]

Hence, x=1 is  a solution.

then

[tex]x^2=4[/tex]

i.e.

[tex]x^2-x=4-2\\\\i.e.\\\\x^2-x=2\neq 0[/tex]

Hence, x=2 is not  a solution.

then

[tex]x^2=9[/tex]

i.e.

[tex]x^2-x=9-3\\\\i.e.\\\\x^2-x=6\neq 0[/tex]

Hence, x=3 is not  a solution.

then

[tex]x^2=16=4\ \text{mod}\ 12[/tex]

i.e.

[tex]x^2-x=4-4\\\\i.e.\\\\x^2-x=0[/tex]

Hence, x=4 is a solution to the equation.

then

[tex]x^2=25=1\ \text{mod}\ 12[/tex]

i.e.

[tex]x^2-x=1-4\\\\i.e.\\\\x^2-x=-3=9\ \text{mod}\ 12[/tex]

i.e.

[tex]x^2-x=9\neq 0[/tex]

Hence, x=5 is not a solution.

then

[tex]x^2=36\\\\i.e.\\\\x^2=0\ \text{mod}\ 12\\\\i.e.\\\\x^2=0[/tex]

Hence,

[tex]x^2-x=0-6\\\\i.e.\\\\x^2-x=-6=6 \text{mod}\ 12\\\\i.e.\\\\x^2-x=6\neq 0[/tex]

Hence, x=6 is not a solution

then,

[tex]x^2=49=1\ \text{mod}\ 12\\\\i.e.\\\\x^2=1[/tex]

Hence,

[tex]x^2-x=1-7\\\\i.e.\\\\x^2-x=-6=6\ \text{mod}\ 12\\\\i.e.\\\\x^2-x=6\neq 0[/tex]

Hence, x=7 is not a solution.

then,

[tex]x^2=64=4\ \text{mod}\ 12[/tex]

i.e.

[tex]x^2-x=4-8\\\\i.e.\\\\x^2-x=-4=8\ \text{mod}\ 12[/tex]

i.e.

[tex]x^2-x=8\neq 0[/tex]

Hence, x=8 is not a solution.

then,

[tex]x^2=81=9\ \text{mod}\ 12[/tex]

i.e.

[tex]x^2=9[/tex]

Hence,

[tex]x^2-x=9-9\\\\i.e.\\\\x^2-x=0[/tex]

Hence, x=9 is a solution.

then,

[tex]x^2=100=4\ \text{mod}\ 12[/tex]

i.e.

[tex]x^2-x=4-10\\\\i.e.\\\\x^2-x=-6=6\ \text{mod}\ 12\\\\i.e.\\\\x^2-x=6\neq 0[/tex]

Hence, x=10 is not a solution.

then,

[tex]x^2=121=1\ \text{mod}\ 12[/tex]

i.e.

[tex]x^2-x=1-11\\\\x^2-x=-10=2\ \text{mod}\ 12\\\\i.e.\\\\x^2-x=2\neq 0[/tex]

Hence, x=11 is not a solution.

Answer:

We have a normal distribution with a mean of 267 days and a standard deviation of 15 days. To solve this proble we're going to need the help of a calculator.

a. The probability of a pregnancy lasting 309 days or longer is:

P(z>309) = 0.0026 or 0.26%

b. The lowest 4% is separeted by the 240.74 days. The probability of pregnancy lasting 240.74 days is 4%.

Answer:

a) 0.26% probability of a pregnancy lasting 309 days or longer.

b) A pregnancy length of 241 days separates premature babies from those who are not premature.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 267, \sigma = 15[/tex]

a. Find the probability of a pregnancy lasting 309 days or longer.

This is 1 subtracted by the pvalue of Z when X = 309. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{309 - 267}{15}[/tex]

[tex]Z = 2.8[/tex]

[tex]Z = 2.8[/tex] has a pvalue of 0.9974

So there is a 1-0.9974 = 0.0026 = 0.26% probability of a pregnancy lasting 309 days or longer.

b. If the length of pregnancy is in the lowest 4​%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

This is the value of X when Z has a pvalue of 0.04. So X when Z = -1.75

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.75 = \frac{X - 267}{15}[/tex]

[tex]X - 267 = -1.75*15[/tex]

[tex]X = 240.75[/tex]

A pregnancy length of 241 days separates premature babies from those who are not premature.

Answer: a) 8359  b) 384

Step-by-step explanation:

Given : Significance level : [tex]\alpha=1-0.95=0.05[/tex]

Critical value : [tex]z_{\alpha/2}}=\pm1.96[/tex]

Margin of error : [tex]E=0.01[/tex]

a) If previous estimate of proportion : [tex]p=0.32[/tex]

Formula to calculate the sample size needed for interval estimate of population proportion :-

[tex]n=p(1-p)(\frac{z_{\alpha/2}}{E})^2[/tex]

[tex]\Rightarrow\ n=0.32(1-0.32)(\frac{1.96}{0.01})^2=8359.3216\approx 8359[/tex]

Hence, the required sample size would be 8359 .

b) If she does not use any prior estimate , then the formula to calculate sample size will be :-

[tex]n=0.25\times(\frac{z_{\alpha/2}}{E})^2\\\\\Rightarrow\ n=0.25\times(\frac{1.96}{0.05})^2=384.16\approx384[/tex]

Hence, the required sample size would be 384 .

The ODE is exact because [tex]M_y=N_x[/tex]. Then

[tex]F_x=8x+8y\implies F(x,y)=4x^2+8xy+g(y)[/tex]

[tex]F_y=8x+g'(y)=8x+4y\implies g'(y)=4y\implies g(y)=2y^2+C[/tex]

So we have

[tex]F(x,y)=4x^2+8xy+2y^2=C[/tex]

Final answer:

The given differential equation is exact because the partial derivatives My and Nx are equal, both being 8. Integrating and finding the potential function F(x, y), we get F(x, y) = 4x² + 8xy + 2y².

Explanation:

The equation given is (8x + 8y)dx + (8x + 4y)dy = 0. To determine if this differential equation is exact, we will compare the partial derivatives of M with respect to y (My) and N with respect to x (Nx). In this case, we have M(x, y) = 8x + 8y and N(x, y) = 8x + 4y. Calculating the partial derivatives, we get My = 8 and Nx = 8. Since My equals Nx, the differential equation is exact, implying there is a function F(x, y) such that its differential dF = M dx + N dy.

To find F(x, y), we integrate M with respect to x, yielding F(x, y) = 4x² + 8xy + h(y), where h(y) is an arbitrary function of y. To determine h(y), we differentiate F(x, y) with respect to y and equate it to N: Fy = 8x + h'(y) = 8x + 4y. From this equation, it follows that h'(y) = 4y, so integrating with respect to y gives h(y) = 2y². Therefore, the potential function F(x, y) that makes the differential exact is F(x, y) = 4x² + 8xy + 2y².

The confidence interval for mean of the "before-after" differences is [tex]\fbox{(-0.4037,1.8037)}[/tex]

Further explanation:

Find the difference between the before pain and the after pain.

Difference = before-after

Kindly refer to the Table for the difference of between the before and after pain.

Sum of difference = [tex]5.6[/tex]

Total number of observation = [tex]8[/tex]

Mean of difference = [tex]0.7[/tex]

Sample standard deviation [tex]s[/tex] = [tex]1.3201[/tex]

Level of significance = [tex]5\%[/tex]

Formula for confidence interval = [tex]\left( \bar{X} \pm t_{n-1, \frac{\alpha}{2}\%} \frac{s}{\sqrt{n}} \right)[/tex]

confidence interval = [tex]\left( 0.7 \pm t_{8-1, \frac{5}{2}\%} \frac{1.3201}{\sqrt{8}} \right)[/tex]

confidence interval = [tex]\left( 0.7 \pm t_{7, \frac{5}{2}\%} \frac{1.3201}{\sqrt{8}} \right)[/tex]

From the t-table.

The value of [tex]t_{7, \frac{5}{2}\%[/tex]=[tex]2.365[/tex]

Confidence interval = [tex]( 0.7 \pm 2.365}\times \frac{1.3201}{\sqrt{8}}) \right)[/tex]

Confidence interval = [tex]\left( 0.7 - 2.365}\times \0.4667,0.7 + 2.365}\times \0.4667) \right[/tex]

Confidence interval = [tex](0.7-1.1037,0.7+1.1037)[/tex]

Confidence interval = [tex]\fbox{(-0.4037,1.8037)}[/tex]

The [tex]95\%[/tex] confidence interval tells us about that [tex]95\%[/tex] chances of the true mean or population mean lies in the interval.

Yes, the hypnotism appear to be effective in reducing pain as confidence interval include includes the positive deviation from the mean.

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Answer Details:

Grade: College Statistics

Subject: Mathematics

Chapter: Confidence Interval

Keywords:

Probability, Statistics, Speed dating, Females rating, Confidence interval, t-test, Level of significance , Normal distribution, Central Limit Theorem, t-table, Population mean, Sample mean, Standard deviation, Symmetric, Variance.

Answer:

The 95% confidence interval for the mean of the “before-after” difference is (-0.4039,1.8039)

No, Hypnotism doesn’t appear to be effective in reducing pain.

Further explanation:

Given: The table of measure the effectiveness of hypnotism in reducing pain.

Before : 6.4    2.6    7.7   10.5    11.7    5.8    4.3    2.8

After    : 6.7    2.4    7.4     8.1     8.6    6.4    3.9    2.7

we make the table of difference between “before-after”

(Before-After) :

6.4-6.7  2.6-2.4  7.7-7.4  10.5-8.1  11.7-8.6  5.8-6.4  4.3-3.9  2.8-2.7

   -0.3        0.2       0.3         2.4         3.1        -0.6       0.4         0.1

Now, we find the sample mean and sample standard deviation of above table.

[tex]\text{Sample Mean, }\bar{x}=\dfrac{\text{Sum of number}}{\text{number of observation}}[/tex]

[tex]=\dfrac{-0.3+0.2+0.3+2.4+3.1-0.6+0.4+0.1}{8}[/tex]

[tex]=\dfrac{5.6}{8}=0.7[/tex]

[tex]\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}[/tex]

[tex]=\sqrt{\dfrac{(-0.3-0.7)^2+(0.2-0.7)^2+(0.3-0.7)^2 ...+(0.1-0.7)^2}{8-1}}[/tex]

[tex]=\dfrac{12.2}{7}=1.3201[/tex]

For 95% confidence interval [tex]\mu_d[/tex] using t-distribution

[tex]\text{Marginal Error, E}=t_{\frac{\alpha}{2},df}\times \dfrac{s}{\sqrt{n}}[/tex]

Where,

For critical value,

[tex]\Rightarrow t_{\frac{\alpha}{2},df}[/tex]

[tex]\Rightarrow t_{\frac{0.05}{2},7}[/tex]

[tex]\Rightarrow t_{0.025,7}[/tex]

using t-distribution two-tailed table,

[tex]t_{0.025,7}=2.365[/tex]

Substitute the values into formula and calculate E

[tex]E=2.65\times \dfrac{1.301}{\sqrt{8}}[/tex]

Therefore, Marginal error, E=1.1039

95% confidence interval given by:

[tex]=\bar{x}\pm E[/tex]

[tex]=0.7\pm 1.1039[/tex]

Therefore, 95% confidence interval using t-distribution: (-0.4039,1.8039)

This interval contains 0

Therefore, Hypnotism doesn’t appear to be effective in reducing pain.  

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Keywords:  

T-distribution, Sample mean, sample standard deviation, Critical value of t, degree of freedom, t-test, confidence interval, significance level.  

Answer:

The correct option is A.

Step-by-step explanation:

The formula of probability is

[tex]P=\frac{a}{b}[/tex]

Where, a≤b, a is total favorable outcomes and b is total possible outcomes.

If an event is certain to occur, then a=b and the probability of an event that is certain to occur is

[tex]P=\frac{a}{a}=1[/tex]

If an event is impossible, then a=0 and the probability of an impossible event is

[tex]P=\frac{0}{a}=0[/tex]

Since total favorable outcomes a and total possible outcomes b can not be negative, a is always less than of equal to b. So,

[tex]0\leq \frac{a}{b}\leq 1[/tex]

[tex]0\leq P\leq 1[/tex]

Therefore the probability of any event is between 0 and 1 inclusive.

All events are not equally likely in any probability procedure. So, the statement "All events are equally likely in any probability procedure" is not true.

Therefore the correct option is A.

The statement 'All events are equally likely in any probability procedure' is NOT a fundamental principle of probability. Events in a probability procedure can have different probabilities based on the situation.

The question is asking to identify which of the given options is NOT a principle of probability. Here, the principles of probability suggest that the probability of an event that is certain to occur is 1 (option B), the probability of an impossible event is 0 (option C), and that the probability of any event is between 0 and 1 inclusive (option D). These are well-established principles of probability and hold true in most situations.

However, option A, 'All events are equally likely in any probability procedure', is NOT a fundamental principle of probability. This is not always true as the likelihood of events can vary greatly depending on the scenario. For instance, if you roll a fair six-sided dice, the probability of landing a 1 is 1/6, but in sampling with or without replacement, probabilities of different outcomes can differ. Thus, it is not a rule that all outcomes are always equally likely in any probabilistic process.

A simple real-life application of this can be seen in card games. If you draw one card from a standard deck of 52, the probability of drawing a heart is 1/4, not equal to the probability of drawing a specific number card like the 7 of clubs, which is 1/52. Therefore, the statement that 'all events are equally likely in any probability procedure' is not always true.

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Answer:

Below.

Step-by-step explanation:

To prove this for mathematical induction, we will need to prove:

Part 1)  That [tex]7^n-1[/tex] is a multiple of 6 for n=1.

Part 2) That, if by assuming [tex]7^{n}-1[/tex] is a multiple of 6, then showing [tex]7^{n+1}-1[/tex] is a multiple of 6.

----------------------------------------------------------------------------------------------

Part 1) If n=1, we have [tex]7^n-1=7^1-1=7-1=6[/tex] where 6 is a multiple of 6 since 6 times 1 is 6.

Part 2) A multiple of 6 is the product of 6 and k where k is an integer.  So let's assume that there is a value k such that [tex]7^n-1=6k[/tex] for some number natural number [tex]n[/tex].

We want to show that [tex]7^{n+1}-1[/tex] is a multiple of 6.

[tex]7^{n+1}-1[/tex]

[tex]7^n7^1-1[/tex]

[tex](7)7^n-1[/tex]

[tex](7)7^{n}-7+6[/tex]

[tex]7(7^{n}-1)+6[/tex]

[tex]7(6k)+6[/tex] (this is where I applied my assumption)

[tex]6[7k+1][/tex] (factoring with the distributive property)

Since 7k+1 is an integer then 6(7k+1) means that [tex]7^{n+1}-1[/tex] is a multiple of 6.

This proves that [tex]7^n-1[/tex] is a multiple of 6 for all natural n.

Parameterize this surface (call it [tex]S[/tex]) by

[tex]\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(9-u^2)\,\vec k[/tex]

with [tex]0\le u\le3[/tex] and [tex]0\le v\le2\pi[/tex]. Take the normal vector to [tex]S[/tex] to be

[tex]\vec r_u\times\vec r_v=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k[/tex]

Then the area of [tex]S[/tex] is

[tex]\displaystyle\iint_S\mathrm dA=\iint_S\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv[/tex]

[tex]=\displaystyle\int_0^{2\pi}\int_0^3u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv[/tex]

[tex]=\displaystyle2\pi\int_0^3u\sqrt{1+4u^2}\,\mathrm du=\boxed{\frac{37\sqrt{37}-1}6\pi}[/tex]

Answer:

The relator recived $8,186.4

Step-by-step explanation:

What you have to do is find the 60% of the commission. Commission is 4% of $341,100 (100%)

First do a cross multiplication to find 4% of $341,100

100% ___ $341,100

4%______x:

[tex]x=(4*341,100)/100=13,644[/tex]

So, the 4% of $341,100 is $13,466

Now you have to find the 60% of $13,466

100% ___ $13,466

60%______x:

[tex]x=(60*13,466)/100=8,186.4[/tex]

The answer is: $8,186.4

Answer: The description are as follows:

Step-by-step explanation:

Correlation coefficients is a statistical measure that measures the relationship between the two variables.

(a) r = 1, it means that there is a Perfect positive relationship between the two variables. If there is positive increase in one variable then other variable also increases with a fixed proportion.

(b) r = -1, it means that there is a perfect negative relationship between the two variables. If there is positive increase in one variable then other variable decreases with a fixed proportion.

(c) r = 0, this is a situation which shows that there is no relationship between the two variables.

(d) r = 0.86, this is a situation  which shows that there is a fairly strong positive relationship between the two variables.

(e) r = 0.06, it is nearly zero which represents that either there is a very minor positive relationship between the two variables or there is no relationship between them.

(f) r = -0.89,  this is a situation  which shows that there is a fairly strong negative relationship between the two variables.

Final answer:

The correlation coefficient, r, measures the strength and direction of the linear relationship between x and y values in a sample.

Explanation:

The correlation coefficient, r, measures the strength and direction of the linear relationship between x and y values in a sample. Let's analyze each correlation coefficient:

a. r=1: This indicates a perfect positive correlation between x and y values, meaning that as x increases, y also increases at a constant rate. All the data points fall on a straight line with a positive slope.

b. r=-1: This indicates a perfect negative correlation between x and y values, meaning that as x increases, y decreases at a constant rate. All the data points fall on a straight line with a negative slope.

c. r=0: This indicates no linear relationship between x and y values. The data points are scattered randomly, and there is no consistent pattern or trend between the variables.

d. r=0.86: This indicates a strong positive correlation between x and y values. As x increases, y also increases, but not at a perfect constant rate. The data points approximately fall on a line with a positive slope.

e. r=0.06: This indicates a weak positive correlation between x and y values. As x increases, y also increases, but the relationship is not very strong. The data points have a scattered pattern around a slightly positive sloped line.

f. r=-0.89: This indicates a strong negative correlation between x and y values. As x increases, y decreases, but not at a perfect constant rate. The data points approximately fall on a line with a negative slope.

a. Since [tex]i=e^{i\pi/2}[/tex], we have

[tex]i^i=(e^{i\pi/2})^i=e^{i^2\pi/2}=e^{-\pi/2}[/tex]

b. Since [tex]1=e^0[/tex], we have

[tex]-1^{-i}=-(e^0)^{-i}=-(e^0)=-1[/tex]

c. Yes, for the reason illustrated in part b. [tex]1=e^0[/tex], and raising this to any power [tex]z\in\mathbb C[/tex] results in [tex]e^{0z}=e^0=1[/tex].

4 pizzas with 3 toppings each

only 12 toppings and 3 toppings per pizza

You have to do 12/3=4

Answer:

80

Step-by-step explanation:

Answer:

50% of students has a score less than 85

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 85, \sigma = 20[/tex]

What percentage of students has a score less than 85?

This is the pvalue of Z when X = 85. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{85 - 85}{20}[/tex]

[tex]Z = 0[/tex]

[tex]Z = 0[/tex] has a pvalue of 0.5

50% of students has a score less than 85

Answer:

Construct validity

Step-by-step explanation:

Construct validity is the most important and outmost validity that is used in scientific methods. Construct validity tells us how an experiment or a test is performed well and how well is the outcome of the experiment, How can the experiments can be measured upto its claims. Construct validity is not concerned about the simple question or the factual question that if an experiment measures an attribute. Construct validity is thus an evaluation of the quality of the experiment.

Answer:

a. construct validity

Step-by-step explanation:

Construct validity refers to whether a particular test actually measures what it claims to be measuring. This is one of the main types of validity evidence. It has become the overriding objective in validity, subsuming all other types of validity evidence. Construct validity answers whether a particular measure behaves in the way that the theory says a measure of that construct should behave.

reflexive

NO -  e.g. 1+1=2 which is not a multiple of 4

irreflexive

NO - e.g. 2+2=4 which is multiple of 4

symmetric

YES - If [tex]a+b[/tex] is a multiple of 4, then [tex]b+a[/tex] is all multiple of 4, because addition is commutative.

antysymmetric

NO, because it's symmetric.

transitive

NO - e.g. 1+3=4 , 3+5=8 , 1+5=6 and 6 is not a multiple of 4.

3(-3 + 5x) -1 (4 - 4x)

Simplify each term by first using the distributive property with each set of parenthesis:

3*-3 + 3*5x - 1*4 -1* -4x

Now do the multiplications:

-9 + 15x -4 + 4x

Combine like terms

15x +4x - 9 -4

19x - 13

Answer: 1.8 servings of soybean and 1.2 servings rice will be needed.

Step-by-step explanation:

Let x be the number of soybeans and y be the number of rice.

Then , According to the question , we have

[tex]14x+4y=30\\\Rightarrow\ 7x+2y=15..................................(1)\\\\ 8x+\frac{1}{2}y = 15\\\Rightarrow\ 16x+y=30.............................(2)[/tex]

Multiply 2 on both the sides of equation (2), we get

[tex]32x+2y=60................................(3)[/tex]

Subtract equation (2) from equation (3), we get

[tex]25x=45\\\\\Rightarrow\ x=1.8[/tex]

Put x = 1.8 in equation (2), we get

[tex]16x+y=30\\\\\Rightarrow\ y=30-16x\\=30-16(1.8)=1.2[/tex]

Hence, 1.8 servings of soybean and 1.2 servings rice will be needed.

Answer:

[tex]\frac{x-8}{x+3}[/tex]

Step-by-step explanation:

Given expression,

[tex]\frac{x^2-9x+8}{x^2+2x-3}[/tex]

[tex]=\frac{x^2-(8+1)x+8}{x^2+(3-1)x-3}[/tex]

[tex]=\frac{x^2-8x-x+8}{x^2+3x-x-3}[/tex]

[tex]=\frac{x(x-8)-1(x-8)}{x(x+3)-1(x+3)}[/tex]

[tex]=\frac{(x-1)(x-8)}{(x-1)(x+3)}[/tex]

[tex]=\frac{x-8}{x+3}[/tex]

Since, further simplification is not possible,

Hence, the given rational expression in lowest terms is,

[tex]\frac{x-8}{x+3}[/tex]

The summand (R?) is missing, but we can always come up with another one.

Divide the interval [0, 1] into [tex]n[/tex] subintervals of equal length [tex]\dfrac{1-0}n=\dfrac1n[/tex]:

[tex][0,1]=\left[0,\dfrac1n\right]\cup\left[\dfrac1n,\dfrac2n\right]\cup\cdots\cup\left[1-\dfrac1n,1\right][/tex]

Let's consider a left-endpoint sum, so that we take values of [tex]f(\ell_i)={\ell_i}^3[/tex] where [tex]\ell_i[/tex] is given by the sequence

[tex]\ell_i=\dfrac{i-1}n[/tex]

with [tex]1\le i\le n[/tex]. Then the definite integral is equal to the Riemann sum

[tex]\displaystyle\int_0^1x^3\,\mathrm dx=\lim_{n\to\infty}\sum_{i=1}^n\left(\frac{i-1}n\right)^3\frac{1-0}n[/tex]

[tex]=\displaystyle\lim_{n\to\infty}\frac1{n^4}\sum_{i=1}^n(i-1)^3[/tex]

[tex]=\displaystyle\lim_{n\to\infty}\frac1{n^4}\sum_{i=0}^{n-1}i^3[/tex]

[tex]=\displaystyle\lim_{n\to\infty}\frac{n^2(n-1)^2}{4n^4}=\boxed{\frac14}[/tex]

The limit  expression for the area under the curve y = x³ as n approaches infinity is; ¹/₄

The given definition is area A of the region S that lies under the graph of the continuous function which is the limit of the sum of the areas of approximating rectangles.

The expression for the area under the curve y = x³ from 0 to 1 as a limit is;

[tex]\lim_{n \to \infty} \Sigma^{n} _{i = 1} (\frac{i}{n})^{3} * \frac{1}{n} }[/tex]

From the expression above, when we factor out 1/n⁴, we will get;

[tex]\lim_{n \to \infty} \frac{1}{n^{4} } \Sigma^{n} _{i = 1} \frac{i}{n} }[/tex]

This is further broken down to get;

[tex]\lim_{n \to \infty} \frac{1}{n^{4} } (\frac{n(n + 1)}{2} )^{2} } }[/tex]

This will be simplified to;

[tex]\lim_{n \to \infty} \frac{1}{n^{4} } \frac{(n^{4} + 2n^{3} + n^{2}) }{2}[/tex]

This would be simplified to;

[tex]\lim_{n \to \infty} \frac{1}{4} + \frac{1}{2n} + \frac{1}{4n^{2} }[/tex]

At limit of n approaches ∞, we have;

Limit = ¹/₄

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There is a loss of $4,400 on retirement. So option (b) is correct.

To calculate the gain or loss on retirement of the bonds, we need to compare the carrying value of the bonds with the price at which they are being called.

Given:

Par value of the bonds = [tex]$121,000$[/tex]

Carrying value of the bonds = [tex]$109,900$[/tex]

Call price = [tex]$105,500$[/tex]

The gain or loss on retirement is calculated as the difference between the carrying value and the call price.

Loss on retirement = Carrying value - Call price

Substitute the given values:

Loss on retirement = $109,900 - $105,500

Loss on retirement = $4,400

However, since the call price is lower than the carrying value, the loss is incurred by the company. Thus, the correct answer is a [tex]$\$4,400$[/tex] loss.

So, the correct option is: (b) $4,400 loss.

Clabber Company has bonds outstanding with a par value of [tex]$\$ 121,000$[/tex] and a carrying value of [tex]$\$ 109,900$[/tex]. If the company calls these bonds at a price of [tex]$\$ 105,500$[/tex], the gain or loss on retirement is:

Multiple Choice

(a) [tex]$\$ 15,500$[/tex] loss.

(b) [tex]$\$ 4,400$[/tex] loss.

(c) [tex]$\$ 11,100$[/tex] loss.

(d) [tex]$\$ 4,400$[/tex] gain.

The gain on retirement is $15,500.

To calculate the gain or loss on retirement of the bonds, we first need to understand the definitions involved:

1. Par value: This is the face value of the bonds, which is $121,000 in this case.

2. Carrying value: This is the book value of the bonds on the company's balance sheet, which is $109,900.

3. Call price: This is the price at which the company is redeeming (calling) the bonds, which is $105,500.

Now, let's calculate the gain or loss:

- Gain/Loss = Par Value - Call Price

If the call price is less than the carrying value, it results in a gain. If the call price is greater than the carrying value, it results in a loss.

Given:

- Par value = $121,000

- Carrying value = $109,900

- Call price = $105,500

[tex]\[ \text{Gain/Loss} = \text{Par Value} - \text{Call Price} \]\[ \text{Gain/Loss} = \$121,000 - \$105,500 \]\[ \text{Gain/Loss} = \$15,500 \][/tex]

Since the call price is less than the carrying value, it results in a gain.

Answer:

[tex]\frac{208}{1091}[/tex]

Step-by-step explanation:

To find probability of x, we need to find the number of x divided by total number.

Here,

Total = 208 + 552 + 331 = 1091

Number of help dash wanted ad = 208

Hence, the probability that the ad for a specific week is a help dash wanted ad = 208/1091

Final answer:

The rate constant, k, can be found using the formula k = ln(1 + r), where r is the growth rate. In this case, the growth rate is 2.5%. The rate constant is approximately 0.0253. The exponential growth function is P(t) = 66,000 * e^(0.0253t). To find in what year the population will reach 176,000, we solve the equation 176,000 = 66,000 * e^(0.0253t) and find that it will take approximately 42 years.

Explanation:

To find the rate constant, we can use the formula:

k = ln(1 + r)

where k is the rate constant and r is the growth rate as a decimal.

In this case, the growth rate is 2.5%, which is equivalent to 0.025 as a decimal.

Using the formula, we have:

k = ln(1 + 0.025) = ln(1.025) ≈ 0.0253

Therefore, the rate constant k is approximately 0.0253.

To devise an exponential growth function, we can use the formula:

P(t) = P0 * ekt

where P(t) is the population at time t, P0 is the initial population, k is the rate constant, and t is the time in years.

In this case, the initial population P0 is 66,000 and we already found that the rate constant k is 0.0253.

So, the exponential growth function is:

P(t) = 66,000 * e0.0253t

To find in what year the population will reach 176,000, we can set up the following equation:

176,000 = 66,000 * e0.0253t

Divide both sides by 66,000:

176,000 / 66,000 = e0.0253t

Simplify:

2.6667 = e0.0253t

To solve for t, we can take the natural logarithm of both sides:

ln(2.6667) = 0.0253t

Divide both sides by 0.0253:

t = ln(2.6667) / 0.0253 ≈ 41.71

Therefore, the population will reach 176,000 in approximately 41.71 years, which can be rounded to 42 years.

Answer:

at the end of 1st year we pay $ 11756

at the end of 2nd year we pay $ 24217

at the end of 3rd year we pay $ 37426

at the end of 4th year we pay $ 51427

at the end of 5th year we pay $ 66269

at the end of 6th year we pay $ 82001

Step-by-step explanation:

Given data

rate ( i ) = 6%

Future payment  = $82000

no of time period ( n ) = 6

to find out

size of all of 6 payments

solution

we know future payment formula i.e.

future payment = payment per period ( [tex](1 + rate)^{n}[/tex] - 1 )   / rate

put all these value and get payment per period

payment per period = future payment × rate  /  ( [tex](1 + rate)^{n}[/tex] - 1 )   / rate

payment per period = 82000 × 0.06  /  ( [tex](1 + 0.06)^{6}[/tex] - 1 )   / rate

payment per period = 82000 × 0.06 / 0.4185

payment per period = $ 11756.27

at the end of 1st year we pay $ 11756

and at the end of 2nd year we pay $ 11756 × ( 1  + 0.06) + 11756

and at the end of 2nd year we pay $ 24217

and at the end of 3rd year we pay $ 24217 × ( 1  + 0.06) + 11756

and at the end of 3rd year we pay $ 37426

and at the end of 4th year we pay $ 37426 × ( 1  + 0.06) + 11756

and at the end of 4th year we pay $ 51427

and at the end of 5th year we pay $ 51427 × ( 1  + 0.06) + 11756

and at the end of 5th year we pay $ 66269

and at the end of 6th year we pay $ 66269 × ( 1  + 0.06) + 11756

and at the end of 6th year we pay $ 82001

Answer:

static value come under the rejection value because it is less than critical value

Step-by-step explanation:

Given data

test = 300

wrong test = 30

significance level = 0.01

claim for wrong  = 10 %

to find out

test the claim that less than 10 percent of the test results are wrong

solution

we take test claim null hypo thesis  = 10 % = 0.10

and and alternate hypo thesis < 10% i.e. <0.10

and we know proportion of sample is = result/ test

sample proportion = 30/300 = 0.10

so the statistics of this test will  be = sample proportion - hypothesis / [tex]\sqrt{hyro(1-hypo)/test}[/tex]

so statistics of this test  = 0.10 - 0.10 / [tex]\sqrt{0.10(1-0.10)/300}[/tex]

so statistics of this test  =  0

and α = tail area critical value for  Z (0.01)  = 2.33

so here static value come under the rejection value because it is less than critical value

To test the claim that less than 10 percent of the test results are wrong, we'll use a hypothesis test with a 0.01 significance level. The calculated test statistic z will determine whether to reject or fail to reject the null hypothesis.

To test the claim that less than 10 percent of the test results are wrong, we'll use a hypothesis test with a 0.01 significance level. Let p represent the proportion of wrong test results. The null hypothesis is that p is greater than or equal to 0.10, and the alternative hypothesis is that p is less than 0.10.

We'll calculate the test statistic z = (x - np) / sqrt(np(1-p)), where x is the number of wrong test results and n is the total number of tested subjects. Using the given information, x = 30 and n = 300.

Using a z-table or calculator, we can find the z-score corresponding to a significance level of 0.01. If the calculated test statistic z is less than the z-score from the table, we reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.

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Answer:

Step-by-step explanation:

Let's simplify step-by-step.

4x3−6x2−24x+(7)(−23)

=4x3+−6x2+−24x+−161

Answer:

=4x3−6x2−24x−161

Answer:

x ≥ -2

Step-by-step explanation:

We need to solve 3 x plus 10 greater than or equal to 4

3x + 10 ≥ 4

Solving and finding the value of x

Adding -10 on both sides

3x + 10 -10 ≥ 4 -10

3x ≥ -6

Divide by 3

3x/3 ≥ -6/3

x ≥ -2

So, the solution is x ≥ -2

Answer:

x [tex]\geq[/tex] - 2

Step-by-step explanation:

We need to solve 3 x plus 10 greater than or equal to 4

3x + 10 ≥ 4

Solving and finding the value of x

Adding -10 on both sides

3x + 10 -10 ≥ 4 -10

3x ≥ -6

Divide by 3

3x/3 ≥ -6/3

x ≥ -2

So, the solution is x ≥ -2