The product of x and 8 is less than or equal to 19
Substitute
-3x-8y=4
-2x+7y=15
What is the solution to the equation g(x) = 3?
x = 3
3 < x < 5
3 ≤ x ≤ 4
3 ≤ x < 5
An airplane has a maximum capacity of 118 passengers. The flight attendant has loaded 40 passengers. Which inequality represents the solution set that shows the number of passengers, p, that can still load the plane? A) p ≥ 68 B) p ≤ 68 C) p ≤ 78 D) p ≥ 78
Answer:
Its C
Step-by-step explanation:
It is C because you can only load 78 more passengers
Answer:
c
Step-by-step explanation:
If p = the number of passengers that can still load the plane, then p + 40 ≤ 118.
Therefore,
p + 40 ≤ 118
p + 40 − 40 ≤ 118 − 40
p ≤ 78
A scout troop planned to take a bus for an overnight trip to a campground in a nearby state. The bus will cost $360 to rent. The bus company told them that if they could get 3 more troop members to join in the trip each person could pay $6 less to go on the trip. If the troop was able to find the 3 additional people to join the trip, which answer is the most reasonable for the number of members that went on the trip?
A grid map marks the plot of Harold’s garden in meters. The coordinates of the quadrilateral-shaped property are G(–8, 3), A(4, 8), R(10, 0), and D(–2, –5). He wants to build a short fence around the garden. The perimeter of his garden is meters.
Answer:
46, i did the assignment on edge hope this helps! :)
Step-by-step explanation:
On a coordinate plane, quadrilateral D G A R is shown. Point G is at (negative 8, 3), point A is (4, 8), point R is at (10, 0), and point (negative 2, negative 5).
A grid map marks the plot of Harold’s garden in meters. The coordinates of the quadrilateral-shaped property are G(–8, 3), A(4, 8), R(10, 0), and D(–2, –5). He wants to build a short fence around the garden.
The perimeter of his garden is meters. 46
The Perimeter of garden as shown in the quadrilateral 46 units
Distance
The distance between two points is the amount of space between the points. From the quadrilateral:
[tex]AG=\sqrt{(8-3)^2+(4-(-8))^2}=13 \ units\\\\AR=\sqrt{(8-0)^2+(4-10)^2}=10 \ units\\\\GD=\sqrt{(-5-3)^2+(-2-(-8))^2}=10 \ units\\\\RD=\sqrt{(-5-0)^2+(-2-10)^2}=13 \ units\\[/tex]
Perimeter of garden = AG + AR + GD + RD = 13 + 10 + 13 + 10 = 46 units
The Perimeter of garden as shown in the quadrilateral 46 units
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The ratio of the measures of the sides of a triangle is 9:15:5. If the perimeter of the triangle is 130 feet, find the measures of the sides.
whats the value of x??im really confused i thought it was 7 but that doesnt make sense can someone please help me!!!
SIMPLIFY the radical expression: square root of 75 + square root of 3
Write the equation of a circle with a center at (15, –35) and a diameter of 100.
(x – 15)2 + (y + 35)2 = 250
(x – 15)2 + (y + 35)2 = 50
(x – 15)2 + (y + 35)2 = 2500
(x – 15)2 + (y + 35)2 = 100
The newspapers cover page is 3/8 text and photographs filled the rest if 2/5 of the text is an article about endangered species, what fraction of the cover page is the article about endangered species
The article about endangered species is ³/₂₀ of the cover page
Further explanationOrder of Operations in Mathematics follow this following rule :
ParenthesesExponentsMultiplication and DivisionAddition and SubtractionThis rule is known as the PEMDAS method.
In working on a mathematical problem, we first calculate operation that is in parentheses, follow by exponentiation, then multiplication or division, and finally addition or subtraction.
Let us tackle the problem !
Given:
Total Area of Cover Page = X
Text Section is 3/8 the newspapers cover page
[tex]\texttt{Text Section Area} = \frac{3}{8} \times \texttt{Total Area of Cover Page}[/tex]
[tex]\texttt{Text Section Area} = \boxed {\frac{3}{8}X}[/tex]
The rest of cover page is Photographs Section
[tex]\texttt{Photographs Section Area} = (1 - \frac{3}{8}) \times \texttt{Total Area of Cover Page}[/tex]
[tex]\texttt{Photographs Section Area} = \boxed {\frac{5}{8}X}[/tex]
2/5 of the text is an article about endangered species.
[tex]\texttt{Endangered Species Article Section Area} = \frac{2}{5} \times \texttt{Text Section Area}[/tex]
[tex]\texttt{Endangered Species Article Section Area} = \frac{2}{5} \times \frac{3}{8}X[/tex]
[tex]\texttt{Endangered Species Article Section Area} = \frac{2 \times 3}{5 \times 8}X[/tex]
[tex]\texttt{Endangered Species Article Section Area} = \frac{6}{40}X[/tex]
[tex]\texttt{Endangered Species Article Section Area} = \frac{6 \div 2}{40 \div 2}X[/tex]
[tex]\texttt{Endangered Species Article Section Area} = \boxed {\frac{3}{20}X}[/tex]
Learn moreInfinite Number of Solutions : https://brainly.com/question/5450548System of Equations : https://brainly.com/question/1995493System of Linear equations : https://brainly.com/question/3291576Answer detailsGrade: Middle School
Subject: Mathematics
Chapter: Percentage
Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point , Multiplication , Division , Exponent , PEMDAS , percentange , percent
Joaquim is baking giant cookies for the school bake sale. They will be sold for $20 for one large cookie or $20 for three small cookies. Which offer is the better buy? Explain your reasoning.
Three small cookies for $20 is a better buy than one large cookie for $20 because the cost per small cookie is cheaper ($6.67 per small cookie). You get more cookies for the same price.
To determine which offer is the better buy, let's compare the cost in terms of cookies:
One large cookie: $20 for 1 large cookie.Three small cookies: $20 for 3 small cookies.Next, let's find the cost per small cookie:
For the large cookie: $20 / 1 large cookie = $20 per large cookie.For the small cookies: $20 / 3 small cookies = $6.67 per small cookie (approximately).Therefore, since $6.67 per small cookie is less than $20 for 1 large cookie, the offer of three small cookies for $20 is the better buy. This way, you get three cookies for the same price as one large cookie.
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Given the geometric sequence where a_1 = 3 and r = √2 find a_9
A.] 48
B.] 48√2
C.] 64
D.] 64√2
If a piece of licorice is to be cut into 10 equal-side pieces. If the length of the piece of licorice is 2/3 yard, how long will each piece of licorice be?
Given this proportion, what ratio completes the equivilent proportion a/8?
[tex] \frac{a}{b}= \frac{8}{15} [/tex]
Please show your work so that I know how to do this.
In 2008 Melvin thought that he was making a sound investment by buying $100,000 worth of Alpha Biotechnology stock. Unfortunately, his investment has depreciated, losing 13% of its current value each year.
In the diagram, KL ≅ NR and JL ≅ MR. What additional information is needed to show ΔJKL ≅ ΔMNR by SAS?
A. ∠J ≅ ∠M
B. ∠L ≅ ∠R
C. ∠K ≅ ∠N
D.∠R ≅ ∠K
Answer:
B. <L=<R
Step-by-step explanation:
^^^Just too test got 100%
559 tickets were sold 59 more student tickets were sold than adult tickets how many adult tickets were sold
The number of adult tickets sold will be 250.
How to form an equation?Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.
In other words, an equation is a set of variables that are constrained through a situation or case.
Suppose the number of student tickets is S while adult tickets are A.
As per the given,
59 more student tickets were sold than adult tickets.
S = A + 59
S - A = 59
Total tickets S + A = 559
Add both equations as
S - A + S + A = 559 + 59
2S = 618
S = 309
A = 309 - 59 = 250
Hence "The number of adult tickets sold will be 250".
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Which of the following is equal to the expression below?
(160 * 243)^1/5
A. [tex] 6 \sqrt[5]{5} [/tex]
B.96
C.80
D.5[tex] 5 \sqrt[5]{5}
[/tex]
(160 * 243)^1/5
To simplify the above expression first step is to factor the numbers. Therefore,
[tex] (160*243)^{\frac{1}{5}} = ((2*2*2*2*2*5)*)(3*3*3*3*3)^{\frac{1}{5}} [/tex]
=[tex] (2^5*5*3^5)^{\frac{1}{5}} [/tex]
= [tex] (2^5)^{\frac{1}{5}} *(5)^{\frac{1}{5}} *(3^5)^{\frac{1}{5}} [/tex]
=[tex] 2 * (5)^{\frac{1}{5}} *3 [/tex]
= [tex] 6*(5)^{\frac{1}{5}} [/tex]
= [tex] 6\sqrt[5]{5} [/tex]
So, correct choice is A.
A scale drawing of an automobile has a scale of 1 in.
The actual width of the car is 8 ft. What is the width on the scale drawing?
PLEASE HELP
7.01
1. Find the first six terms of the sequence.
a1 = 4, an = an-1 + 8
A) 0, 8, 16, 24, 32, 40
B) 12, 20, 28, 36, 44, 52
C) 4, 12, 20, 28, 36, 44
D) 4, 8, 16, 24, 32, 40
2. Find the first six terms of the sequence.
a1 = -8, an = 5 an-1
A) -8, -40, -200, -1000, -5000, -25,000
B) -8, -40, -35, -30, -25, -20
C) 0, 5, -40, -35, -30, -25
D) -40, -200, -1000, -5000, -25,000, -125,000
3. Find an equation for the nth term of the arithmetic sequence.
8, 6, 4, 2, ...
A) an = 8 + -2(n)
B) an = 8 - 2
C) an = 8 + -2(n + 1)
D) an = 8 + -2(n - 1)
4. Find an equation for the nth term of the arithmetic sequence.
-17, -12, -7, -2, ...
A) an = -17 + 5(n + 2)
B) an = -17 + 5(n + 1)
C) an = -17 + 5(n - 1)
D) an = -17 x 5(n - 1)
5. Find an equation for the nth term of the arithmetic sequence.
a19 = -58, a21 = -164
A) an = 896 - 53(n - 2)
B) an = 896 - 53(n - 1)
C) an = 896 + 53(n + 1)
D) an = 896 - 53(n + 1)
6. A certain species of tree grows an average of 0.5 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 200 centimeters tall.
The answers identified are: (C) for the first sequence question, (A) for the second sequence question, (D) for the arithmetic sequence with a start of 8 and difference -2, (C) for the arithmetic sequence starting from -17, (B) for the arithmetic sequence question with given a19 and a21, and finally an = 200 + 0.5n for the tree growth question.
Explanation:The correct answers are as follows:
For the first question, you start with 4 (a1 = 4) and each subsequent term is the previous term plus 8 (an = an-1 + 8). This gives the sequence 4, 12, 20, 28, 36, 44, which matches option (C).For the second question, starting at -8 (a1 = -8) and then multiplying the previous term by 5 gives you -8, -40, -200, -1000, -5000, -25,000, which matches option (A).For the third question, the common difference between consecutive terms is -2 and the first term is 8, which gives an = 8 - 2(n - 1) (option D)For the fourth question, the common difference is +5 and the first term is -17, so the equation for the nth term is an = -17 + 5(n - 1) (option C). For the fifth question, the common difference can be calculated from the problem as 53. Hence the equation for the nth term is an = 896 - 53(n - 1) (option B).For the last question, if the tree grows at a rate of 0.5 cm per week and the initial height is 200 cm, the height of the tree each week is represented by an = 200 + 0.5n.Learn more about Arithmetic Sequences here:https://brainly.com/question/35880655
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Which table of ordered pairs represents a proportional relationship
Answer:
The second table.Step-by-step explanation:
In this case, "a proportional relationship" refers to the presence of a constant of variation between variables, that is, variables must variate at the same rate, where such rate is call the constant of proportionality.
Notice that the second table fulfils this definion, because x-variable variates 2 units, while y-variable variates ten units. To find the constant of proportionality, we just need to divide
[tex]k=\frac{10}{2}=5[/tex]
Which means that y-variable represents five times x-variable, let's evalute to prove this
[tex]2 \times 5=10\\4 \times 5 = 20\\6 \times = 30[/tex]
Notice that we got all y-values.
Therefore, the right table is the second one, it presents a proportional relationship.
jami can now mow 1/6 acre in 8 minutes. if her rate is constant, can jami mow 1 and 1/2 acres in one hour? explain ur reasoning.
❤️ Kinda fuzzy but can anyone help?
Answer:
thats to hard
Step-by-step explanation:
get a calculater
∆ABC has side lengths of 10 units, 20 units, and 24 units. ∆XYZ is similar to ∆ABC, and the length of its longest side is 60 units. The perimeter of ∆XYZ is units. If the height of ∆ABC, with respect to its longest side being the base, is 8 units, the area of ∆XYZ is square units. NextReset
Final answer:
The perimeter of ΔXYZ is 25 units and the area of ΔXYZ is 40 square units.
Explanation:
In this problem, we are given that ΔABC has side lengths of 10 units, 20 units, and 24 units, and ΔXYZ is similar to ΔABC. We are also given the length of the longest side of ΔXYZ as 60 units. To find the perimeter of ΔXYZ, we need to add up the lengths of all its sides. Since the longest side of ΔABC is 24 units, and the longest side of ΔXYZ is 60 units, we can set up the following proportion:
24/10 = 60/x
Cross-multiplying gives us:
24x = 600
x = 600/24 = 25 units
Therefore, the perimeter of ΔXYZ is 25 units.
Now, to find the area of ΔXYZ, we can use the proportional relationship between the areas of similar triangles. Since the ratio of the longest sides is 60/24 = 5/2, the ratio of the areas will be (5/2)^2 = 25/4. Since the area of ΔABC is 1/2 times the base times the height, we can use the same formula for ΔXYZ with the corresponding measurements:
Area of ΔXYZ = (1/2) * 10 * 8 = 40 square units
The main arena hall has dimensions 200 m by 85 m. On a large diagram on the office wall the scale is 1:40. What are the dimensions of the floor space on the diagram?
Answer:
500 cm by 212.5 cm
Step-by-step explanation:
Using the scale 1:40 on the 200 m dimension, we have 200/40 = 5 m. Each meter is 100 cm; this makes this 5(100) = 500 cm.
Using the scale on the 85 m dimension, we have 85/40 = 2.125 m. Each meter is 100 cm; this makes this 2.125(100) = 212.5 cm.
Answer:
500 cm by 212.5 cm
Step-by-step explanation:
Given :
The main arena hall has dimensions 200 m by 85 m.
On a large diagram on the office wall the scale is 1:40.
To Find: What are the dimensions of the floor space
Solution :
Length of arena hall = 200 m
Scale is 1:40
So, the length of the floor = [tex]\frac{200\times 1}{40}[/tex]
= [tex]5m[/tex]
Since 1 m = 100 cm
So, 5 m = 100*5 = 500 cm
Width of arena hall = 85 m
So, width of floor = [tex]\frac{85\times 1}{40}[/tex]
= [tex]2.125m[/tex]
Now 1 m = 100 cm
So, 2.125 m = 212.5 cm
Thus the dimensions of floor is 500 cm by 212.5 cm
If you have 240 homies and the Crips rolls up on your block poppin 128 of yo homies, how many homies do ya got left?
Answer:
You'll have 112 blood homies left
240b-128b=112b
112
Which equation is quadratic in form 2(x+5)^2+8x+5+6=0, x^6+6x^4+8=0, 7x^6+36x^3+5=0, 4x^9+20x^3+25=0?
Equation 2(x+5)² + 8x + 5 + 6 = 0 or 2x² + 28x + 61 = 0 is the equation in quadratic form.
What is a quadratic equation?A quadratic equation is an equation of second order. Quad implies the square power, it is also called equation of degree 2.
The standard form of a quadratic equation is ax² + bx + c = 0.
Where a, b and c are constants.
In the given equation,
2(x+5)² + 8x + 5 + 6 = 0
2 (x² + 25 + 10x) + 8x + 11 = 0
2x² + 50 + 20x + 8x + 11 = 0
2x² + 28x + 61 = 0
This is the quadratic equation.
Rest of the equation are in the higher degree power, only equation 2x² + 28x + 61 = 0 is second power equation.
Hence, 2x² + 28x + 61 = 0 is a quadratic equation.
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