Suppose you want to build a rectangular sandbox where the width is 5 feet less than the length and the diagonal is 5 feet longer than the length. what are the dimensions of the sandbox?

Answers

Answer 1
Let L = length
     W = L - 5 ←5 feet less than (reverse order - ) the length (L)
     D = L + 5
These 3 lengths form a right triangle with D being the hypotenuse, c.
Using the Pythagorean Theorem, a² + b² = c²
L² + (L - 5)² = (L + 5)²
L² + L² - 10L + 25 = L² + 10L + 25
L² - 20L = 0
L = 0 (can't use this answer) or L = 20 (this is a usable answer)
Dimensions of the sandbox 20 ft by 15 ft 
Length = 20 ft
Width = 15 ft
Diagonal = 25 ft

Related Questions

Jacob drove from town a to town b at an average rate of x miles per hour, then returned along the same route at y miles per hour. if he then drove back to town b at z miles per hour along the same route, what was jacob's average rate of speed for the entire trip, in miles per hour?

Answers

The answer is 1,000 miles

EASY 14 POINTS, PLEASE HELP ASAP.

Go into a dark room with a flashlight and face the beam toward a wall. Change the flashlight's distance from the wall as well as the way you hold the flashlight. Which conic sections can you form? Explain.

Describe how you formed different conic sections with your flashlight. Take and upload digital pictures as needed. Look at other students' descriptions and pictures and tell whether you agree with them.

What other simple tasks can you do in your home to form any of the conic sections? Again, describe these and/or take pictures to share with other students.

Answers

Well really it would have to depend on the flashlight. Is it an led bulb or a regular bulb?

Well really it would have to depend on the flashlight. Is it an led bulb or a regular bulb?

Consider the function f(x)=(x-9)/(x^3-81x)

Find the vertical asymptote(s) of f(x)

Answers

Answer:

Its A

x=0, -9

Step-by-step explanation:

just got it correct

Final answer:

The function f(x)=(x-9)/(x^3-81x) has three vertical asymptotes at x = 0, x = 9, and x = -9.

Explanation:

To find the vertical asymptote(s) of the function f(x) = (x-9)/(x^3-81x), we need to determine the values of x for which the denominator equals zero. Setting the denominator equal to zero and solving for x, we get:

x^3 - 81x = 0x(x^2 - 81) = 0x(x - 9)(x + 9) = 0

Therefore, the function has three vertical asymptotes at x = 0, x = 9, and x = -9.

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Fifty-eight boys were asked if they play football and/or baseball. Thirty-one of them said they do not play baseball. Sixteen of them said they play football. Twenty of them said they do not play baseball or football.

Enter your answers in the boxes to complete the two-way table based on the given data.

Answers

The two-way table is attached.

We start out placing 31 in the Total column beside the Don't Play Baseball row.  We then place 16 in the Total row under the Play Football column.  20 goes in the Don't Play Baseball row under the Don't Play Football column.

Since there are 31 people that do not play baseball, and 20 of them don't play football, this leaves us with 31-20=11 that do not play baseball and play football.

There are 58 people total, so this goes in the Total row under the Total column.

There are 58 people, and 31 of them do not play baseball; this leaves us 58-31=27 total that play baseball.

16 total people play football, and 11 of them don't play baseball.  This leaves us 16-11=5 people that play football and play baseball.

There are 58 people, and 16 of them play football; this leaves us 58-16=42 total that don't play football.

42 people don't play football, and 20 of them don't play baseball; this leaves us 42-20=22 people that don't play football and play baseball.

5 people play baseball and play football, and 22 people play baseball and don't play football; this gives us 5+22=27 people total that play baseball.

Complete the equation of the line through (-6,5) and (-3,-3) Use exact numbers. y=

Answers

(-6,5) and (-3,-3) 
slope = (5+3)/(-6 + 3) = 8/-3 = -8/3

y = mx + b
b = y - mx
b = -3 - (-8/3)(-3)
b = -3 - 8
b = -11

equation
y = -8/3 x - 11

hope it helps

The equation of the line passing through the points (-6,5) and (-3,-3) will be y = -(8/3)x - 11.

What is the equation of a line passing through two points?

Let the equation of the line pass through (x₁, y₁) and (x₂, y₂).

Then the equation of the line is given as,

[tex]\rm (y - y_2) = \left (\dfrac{y_2 - y_1}{x_2 - x_1} \right ) (x - x_2)[/tex]

The points are given below.

(-6,5) and (-3,-3)

Then the equation of the line passing through the points (-6,5) and (-3,-3) will be

[tex]\rm (y + 3) = \left (\dfrac{-3-5}{-3+6} \right ) (x + 3)[/tex]

Simplify the equation, then the equation of the line will be

y + 3 = -(8/3)(x + 3)

y = -(8/3)x - 8 - 3

y = -(8/3)x - 11

Then the equation of the line passing through the points (-6,5) and (-3,-3) will be y = -(8/3)x - 11.

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How do you simplify # (x+3)/(x^2+7x+12)#?

Answers

hey friend your answer



hope it is helpful
By using the method of factorization

A city has a population of 260,000 people. Suppose that each year the population grows by 6.75% . What will the population be after 7 years? Use the calculator provided and round your answer to the nearest whole number.

Answers

Final answer:

The population of the city after 7 years will be approximately 393,574.

Explanation:

To find the population after 7 years, we'll use the formula for exponential growth:

P = P0(1 + r)t

Where P is the future population, P0 is the initial population, r is the growth rate as a decimal, and t is the number of years.

In this case, P0 = 260,000, r = 6.75% = 0.0675 (decimal form), and t = 7.

Plugging in these values, we have:

P = 260,000(1 + 0.0675)7

Using a calculator, the population after 7 years is approximately 393,574.

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Simplify 72x6 y7 z .

Answers

Nothing further can be done to this topic

Use the x-intercept method to find all real solutions of the equation. x^3-9x^2+20x-12=0

Answers

For this case we have the following function:
 x ^ 3-9x ^ 2 + 20x-12 = 0
 Rewriting we have:
 (x-6) * (x-2) * (x-1) = 0
 Therefore, the solutions are given by:
 Solution 1:
 x-6 = 0
 x = 6
 Solution 2:
 x-2 = 0
 x = 2
 Solution 3:
 x-1 = 0
 x = 1
 Answer:
 
x = 6
 
x = 2
 
x = 1

Answer:

D= 1,2,or 6

Step-by-step explanation:

Selecting a red pen and then a blue pen, when selecting 2 pens from a bag of 10 red pens

Answers

What? That’s not possible because there’s no blue pens. If that’s the awnser?

BRAINLIESTTT ASAP!

please help

Answers

Width = x
Length = 2x+1

1/2 the permiter = l + w

1/2 perimeter = 176 /2 = 88
 so we have x + 2x+1 = 88

combine like terms:
3x +1 = 88

subtract 1 from both sides:
3x = 87
 divide both sides by 3
x = 87 / 3 = 29

with = 29 feet
 length = 29 x 2 = 58 +1 = 59 feet

check: 59 +59 +29+29 = 176


What are the trigonometric ratios of a right triangle ABC that has its right angle at C? AC=12 and BC=5

Answers

There are 3 trigonometric ratios:
Sine = opposite/hypotenuse, 
Cosine = adjacent/hypotenuse and
tangent = opposite/adjacent
Since in the question we have not been given the hypotenuse, we calculate it first. 
So, hypotenuse = √(12²+5²) = √(144+25) = √169 = 13.

Now we can find the trigonometric ratios; 
Sin A = Cos B = 5/13
Sin B = Cos A = 12/13
Tan A = 5/12
Tan B= 12/5  

 

can someone please explan how I got this wrong?
Solve for x in the triangle
using laws of cosine

Answers

[tex]\bf \textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)cos(C)\implies c = \sqrt{a^2+b^2-(2ab)cos(C)} \\\\\\ \cfrac{a^2+b^2-c^2}{2ab}=cos(C)\implies cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C\\\\ -------------------------------\\\\ \begin{cases} x=24\\ a=25\\ b=19 \end{cases}\implies cos^{-1}\left(\cfrac{25^2+19^2-24^2}{2(25)(19)}\right)=\measuredangle x \\\\\\ cos^{-1}\left( \cfrac{41}{95} \right)=\measuredangle x\implies 64.432194^o\approx \measuredangle x[/tex]

A bag contains 6 red, 7 blue, and 5 green coins. If 3 coins are randomly selected in succession, what is the probability of selecting a red coin, then a blue coin, and then a green coin, if replacement occurs each time?

Answers

Total coins = 6 + 7 + 5 = 18
Red = 6
Blue = 7
Green = 5

P(Red, then blue, then green) = (6/18)(7/18)(5/18) = 35/972

Answer: 35/972
[tex]|\Omega|=18^3=5832\\ |A|=6\cdot7\cdot5=210\\\\ P(A)=\dfrac{210}{5832}=\dfrac{35}{972}\approx3.6\%[/tex]

Frazier has $1,200 in savings. He works because he is saving money for college, and he earns $9 an hour. If Frazier saves 25 percent of his net pay, after 20 percent is taken out for tax, identify the expression which represents Frazier's savings.

A) 1.8x + 1,200
B) 3.6x + 1,200
C) 7.2x + 1,200
D) 9x + 1,200

Answers

the correct answer is A..!! I think...:(



Answer:  The correct option is (A) [tex]1.8x+1200.[/tex]

Step-by-step explanation:  Given that Frazier is saving money for college and has $1200 in savings. He earns $9 per hour. He saves 25% of his net pay after 20% taken out for tax.

We are to identify the expression that represents Frazier's savings.

Let, x represents the number of hours for which Frazier works.

So, the net pay of Frazier = $ 9x.

Since 20% of the net pay is taken out for tax, so total pay of Frazier after taking out tax is given by

[tex]I_t=9x-20\%\times 9x=9x-\dfrac{20}{100}\times 9x=9x-\dfrac{9x}{5}=\dfrac{36x}{5}.[/tex]

Now, Frazier's savings from his net pay is given by

[tex]I_s=25\%\times \dfrac{36x}{5}=\dfrac{25}{100}\times \dfrac{36x}{5}=\dfrac{9x}{5}=1.8x.[/tex]

Since Frazier has $1200 already in savings, so the equation representing Frazier's savings will be

[tex]1.8x+1200.[/tex]

Thus, the required equation is [tex]1.8x+1200.[/tex]

Option (A) is CORRECT.

You choose a marble at random from a bag containing 8 brown marbles 6 yellow marbles and one purple marble. You replace the marble and then choose again.find p (both yellow)

Answers

Pick 1: 6 yellow out of 15 total marbles = 6/15 = 2/5
Pick 2: 6 yellow out of 15 total marbles = 6/15 = 2/5

Pick 1 AND Pick 2
   2/5     x       2/5    = 4/25

A normal distribution has a mean of 0.40 and standard deviation of 0.028. What percentage of observations will lie between 0.372 and 0.428?

Answers

Solution:
To evaluate for P(0.372<x<0.428) we shall proceed as follows:
z-score is given by:
z=(x-μ)/σ
thus when x=0.372:
z=(0.372-0.4)/0.028
z=-1
thus
P(x<0.372)=P(z<-1)=0.1587

when x=0.428
z=(0.428-0.4)/(0.028)=1
P(x<0.428)=P(z<1)=0.8413
thus
P(0.372<x<0.428) =P(z<1)-P(z<-1)=0.8413-0.1587=0.6826
Final answer:

To find the percentage of observations between two values in a normal distribution, we can convert the values to z-scores and use a z-table to find the corresponding areas. In this case, the percentage of observations between 0.372 and 0.428 is 68.26%.

Explanation:

To find the percentage of observations that will lie between 0.372 and 0.428 in a normal distribution with a mean of 0.40 and standard deviation of 0.028, we need to find the area under the curve between these two values.

Using a standard normal distribution table or z-table, we can convert the values to z-scores by subtracting the mean and dividing by the standard deviation. The z-score for 0.372 is (0.372 - 0.40) / 0.028 = -1, and the z-score for 0.428 is (0.428 - 0.40) / 0.028 = 1.

By looking up the corresponding area for these z-scores in the z-table, we find that the area to the left of -1 is 0.1587 and the area to the left of 1 is 0.8413. To find the percentage between -1 and 1, we subtract the smaller area from the larger area: 0.8413 - 0.1587 = 0.6826 or 68.26%.

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Anyone know this geometry question? 10 min left! Will give brainiest

Answers

Angle 3 and angle 6 are corresponding angles, which means they are equal. In order for the lines to remain parallel, angle 3 and angle 6 would need to remain equal. If something is done to angle 6, then it would have to be done to angle 3 as well in order to keep the angles equal. So, if angle 6 is doubled, angle 3 would also have to be doubled. 

The answer is B. m< 3 would need to double.

Hope this helps =)

Find the equation of a line perpendicular to y - 12 = 2x – 8 that passes through the point (2, 3). (answer in slope-intercept form)

Answers

First, we can add 12 to both sides to get..
y=2x+4 
To get a perpendicular line, we have to take the reciprocal of the current slope and turn it to the opposite sign (ex: if it is positive, make it negative, if it is negative, make it positive) 
y= -(1/2)x+4
To make sure it passes through the points (2,3) we substitute x=2 and y=3 (x,y) 
3= -(1/2)2 +4
3= (-1) + 4
3=3
Now we know the equation is working
y= -(1/2)x + 4

The equation of the line perpendicular to y - 12 = 2x – 8 that passes through the point (2, 3) is y = (-1/2)x + 4.

What is the general equation of straight line? What is a mathematical function, equation and expression?straight line : The general equation of a straight line is -

        [y] = mx + c

function : In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.expression : A mathematical expression is made up of terms (constants and variables) separated by mathematical operators.equation : A mathematical equation is used to equate two expressions.

Given is to find the equation of a line perpendicular to y - 12 = 2x – 8 that passes through the point (2, 3).

The given equation is -

y - 12 = 2x - 8

y = 2x - 8 + 12

y = 2x + 4

Assume the equation of the line to be -

y = mx + c

Now -

m = -1/2                              {m (1) x m (2) = - 1 → for perpendicular lines}

So, the equation can be written as -

3 = - 1/2 x 2 + c

c = 3 + 1

c = 4

Therefore, the equation of the line perpendicular to y - 12 = 2x – 8 that passes through the point (2, 3) is y = (-1/2)x + 4.

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In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8; a4b4; a8; ab7; a6b

Answers

Answers are: 
a^5b^3
b^8
a^4b^4
a^8
ab^7
(there are 5 answers)

==================================================

The exponents for the variable terms must add to 8, which is the original outer exponent of the expression given (3a+4b)^8

For something like a^8, we don't have any other exponent so we don't have to worry about it. If you wanted, you can think of a^8 as a^8b^0 and then note how 8+0 = 8. So the rule still applies

For ab^7, we would write it as a^1b^7 and the rule works here as well (1+7 = 8). 

--------------------------

Something like a^2b^3 is a non-answer because the exponents add to 2+3 = 5
Same goes for ab^8 = a^1b^8 because we have the exponents add to 1+8 = 9
And for a^6b = a^6b^1 we have the sum of exponents being 6+1 = 7

The [tex]a^5b^3[/tex], [tex]ab^8[/tex], [tex]b^8[/tex], [tex]a^4b^4[/tex], [tex]a^8[/tex], and [tex]ab^7[/tex] are the possible variable terms and this can be determined by using the arithmetic operations.

Given :

Expression  ---  [tex]\rm (3a + 4b)^8[/tex]

The following calculation can be used in order to determine the possible variables from the given expression.

The given expression can be written as:

[tex]\rm (3a + 4b)^8=(3a+4b)^2(3a+4b)^2(3a+4b)^2(3a+4b)^2[/tex]

[tex]\rm (3a + 4b)^8=(9a^2+16b^2+12ab)(9a^2+16b^2+12ab)(9a^2+16b^2+12ab)(9a^2+16b^2+12ab)[/tex]

Now, further simplify the above expression.

[tex]\rm (3a + 4b)^8=(81a^4+144a^2b^2+108a^3b+144a^2b^2+256b^4+192a^3b+108a^3b+192ab^3+144a^2b^2)(81a^4+144a^2b^2+108a^3b+144a^2b^2+256b^4+192a^3b+108a^3b+192ab^3+144a^2b^2)[/tex]

So, from the above calculation, it can be concluded that [tex]a^5b^3[/tex], [tex]ab^8[/tex], [tex]b^8[/tex], [tex]a^4b^4[/tex], [tex]a^8[/tex], and [tex]ab^7[/tex] are the possible variable terms.

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Let 40 x 55 = n. Which of the choices shown is also equal to n?
A) (550 x 40)
B) (4 x 50) + (40 x 5)
C) (50 x 40) + (50 x 40)
D) (10 x 55) + (10 x 55) + (10 x 55) + (10 x 55)

Answers

D) (10 x 55) + (10 x 55) + (10 x 55) + (10 x 55)

use distributive rule to factor out 55:
55 (10+10+10+10) = 55×40

WILL MAKE BRAINLIEST!!!!!!!The arc length of a sector is equal to twice the radius. Express the arc length s as a function of the area a of the sector.
s=

Answers

The area of a circular sector is . 

==>  
Since r = s/2, it follows that , or , or 
.

The arc length as a function of the area of the sector is  l=2√A.

What is the area of a sector?

Area of a sector = 1/2 * arc length(l) * radius(r)

[tex]A=[/tex] [tex]\frac{1}{2} l*r[/tex]......(1)

It is given that the arc length of a sector is equal to twice the radius.

This means [tex]l=2r\\[/tex]

So, [tex]r=\frac{l}{2}[/tex]

Putting the value of r in (1)

[tex]A = \frac{l^{2} }{4}[/tex]

[tex]l^{2} =4A[/tex]

[tex]l=2\sqrt{A} \\[/tex]

So, the required function is l=2√A

Hence, the arc length as a function of the area of the sector is  l=2√A.

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Please help asap, 70 points, THREE questions (:

Answers

[tex]9x^2=17\ \ \ |:9\\\\x^2=\dfrac{17}{9}\to x=\pm\sqrt{\dfrac{17}{9}}\\\\\boxed{Answer:\ x\approx-1.37\ \vee\ x=1.37}[/tex]


[tex]ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta > 0\ then\ the\ equation\ has\ 2\ solutions\\if\ \Delta=0\ then\ the\ equation\ has\ 1\ solution\\if\ \Delta < 0\ then\ the\ equation\ has\ no\ solution[/tex]

[tex]x^2+5x+7=0\\a=1;\ b=5;\ c=7\\\\Delta=5^2-4\cdot1\cdot7=25-28=-3 < 0\\\\\boxed{Answer:\ 0}[/tex]


[tex]5y^2-8y=2\ \ \ |-2\\\\5y^2-8y-2=0\\\\a=5;\ b=-8;\ c=-2\\\\b^2-4ac=(-8)^2-4\cdot5\cdot(-2)=64+40=104\\\\\sqrt{b^2-4ac}=\sqrt{104}\approx10.198\\\\y_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ y_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\y_1=\dfrac{-(-8)-10.198}{2\cdot5}\approx-0.22\\\\y_2=\dfrac{-(-8)+10.198}{2\cdot5}\approx1.82\\\\\boxed{Answer:\ 1.82,\ -0.22}[/tex]

Answer:

the answer for number 1 is 1.82

Step-by-step explanation:

How to find two numbers that sum equal 15 and product are maximized?

Answers

x - the first number15 - x - the second numberx(15 - x) - the product of the our numbers 
f(x) = -x^2 + 15x

The maximum value is in the vertex of parabola (h; k).
For ax² + bx + c:
[tex]h=\dfrac{-b}{2a};\ k=f(h)=\dfrac{b^2+4ac}{4a}[/tex]
We have: a = -1; b = 15; c = 0
substitute:
[tex]h=\dfrac{-15}{2\cdot(-1)}=\dfrac{15}{2}=7.5[/tex]
15 - 7.5 = 7.5
Answer: 7.5 and 7.5.

Anyone know this? Will give brainiest

Answers

I believe the answer is C,
Hope this helps

If you answer 110 questions and get a 94% how many did you get wrong

Answers

STEP 1:
Set up a ratio.

x= number correct out of 110

x/110= 94/100
cross multiply

(x * 100)= (110 * 94)
100x= 10,340

divide both sides by 100
x= 103.4


STEP 2:
subtract number correct in step 1 from total number of questions

=110 - 103.4
=6.6 questions wrong


ANSWER: There were exactly 6.6 questions wrong on the test. Since you cannot have a partial question (unless otherwise stated), but only whole questions, round up to 7 whole questions wrong.

Hope this helps! :)

if it takes 18 gallons of gas to go 400 miles how many gallons would it take to go 300 miles

A. 5.5 gallons

B. 13.5 gallons

C. 16.6 gallons

D. 22.2 gallons

E. 24 gallons

Answers

We will use the ratio and proportion method ( an equation formed with two ratios that are equal) to solve the question “if it takes 18 gallons of gas to go 400 miles,  how many gallons would it take to go 300 miles?”

Let x= the number of gallons for the gas  to go 300 miles

18:400=X:300

400x=300*18

400x=5400

X=5400/400

X=13.5 so the answer is B.

Answer:

B

Step-by-step explanation:

its 13.5 gallons

simplify 15r+7r+9r-7s

Answers

yo edges a** 56789123456

15r + 7r + 9r - 7r
 12r      +    2r
         14r
_____________________

12r + 2r = simplified

answer is 14r

______________________

Hope this helps,
QueenBeauty666

The path of a rocket ship is given by the parametric equations x(t)=3t and y(t)=4t^2+1, where t is the time in seconds after launch. Where is the ship after 10 seconds?
A.) (3,4)
B.) (3,5)
C.) (30,401)
D.) (30,501)

Answers

x(t)=3t
y(t)=4t^2+1

Time (seconds):

Where is the ship after 10 seconds?
t=10→Position: Point: P=(x(t), y(t))=(x(10), y(10))=?

t=10→x(10)=3(10)→x(10)=30
t=10→y(10)=4(10)^2+1=4(100)+1=400+1→y(10)=401

Position: P=(x(10), y(10))=(30, 401)

Answer: Option C.) (30, 401) 

Please Help!!!


Let ​ x2−12x=61 .​ What values make an equivalent number sentence after completing the square?

Answers

I did the math and there were two answers 1. 15.849 2. 3.849

The given equation is [tex] x^2-12x=61 [/tex]. Add 36 to both the sides of the equation, then

[tex] x^2-12x+36=61+36 [/tex].

The equation becomes,

[tex] x^2-12x+6^2=97\\
(x-6)^2=97 [/tex]

Other Questions
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