Answer:
an electronic symbol is a pictogram used to represent various electrical and electronic devices or functions such as wires batteries resistors and transistors in a symptomatic diagram of an electrical or electronic circuit.
Explanation:
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Final answer:
Electrical circuit diagrams use specific standardized symbols to represent various components like wires, batteries, resistors, ground, and capacitors. Symbols for wire, resistor, and battery are straightforward, while capacitors have variations depending on type. ANSI and IEC provide different standard symbol guidelines.
Explanation:
Symbols for Components of Electrical Circuits
Electrical circuit diagrams use standardized symbols to represent different components. The wire is depicted as a thin black line and is assumed to be a perfect conductor in diagrams, although in reality it is not perfect but typically close enough for practical purposes. A battery or voltage source is represented by a set of parallel lines, with the longer line denoting the positive terminal and the shorter line the negative terminal. The resistor is illustrated with a zigzag symbol, which includes any resistance within the circuit connections. Ground is typically shown as a set of one to three horizontal lines, sometimes with one of the lines angled towards the bottom.
When it comes to alternating current (AC) sources, the symbol is a sine wave enclosed in a circle. This shows the oscillating nature of the AC voltage. Capacitors are represented with two parallel lines for a fixed capacitor; an electrolytic capacitor is shown with one curved line indicating the negative terminal and one straight line for the positive terminal. A variable-capacitance capacitor is represented with an arrow through the parallel lines, signifying adjustability.
Standards such as the American National Standard Institute (ANSI) and the International Electrotechnical Commission (IEC) provide guidelines for these symbols. While the ANSI standard is widely used for its recognizability, the IEC standard might be preferred for more complex circuits due to its cleaner presentation.
Which two kinds of energy are associated with flames?
Answer: Light and thermal (heat) energy.
Explanation: Flames give off heat and light.
Answer:
Light and thermal (heat) energy are the two kinds of energy associated with flames
Explanation:
An ordinary egg can be approximated as a 5.5-cm diameter sphere. The egg is initially at a uniform temperature of 8°C and is dropped into boiling water at 97°C. Taking the properties of the egg to be r 1020 kg/m3 and cp 3.32kJ/kg · °C, determine (a) how much heat is transferred to the egg by the time the average temperature of the egg rises to70°C and (b) the amount of entropy generation associated with this heat transfer process.
Answer:
a) [tex]Q_{in} = 13.742\,kW[/tex], b) [tex]\Delta S = 370.15\,\frac{kJ}{K}[/tex]
Explanation:
a) The heat transfered to the egg is computed by the First Law of Thermodynamics:
[tex]Q_{in} +U_{sys,1} - U_{sys,2} = 0[/tex]
[tex]Q_{in} = U_{sys,2} - U_{sys,1}[/tex]
[tex]Q_{in} = \rho_{egg}\cdot \left(\frac{4\pi}{3}\cdot r^{3}\right)\cdot c \cdot (T_{2}-T_{1})[/tex]
[tex]Q_{in} = \left(1020\,\frac{kg}{m^{3}}\right)\cdot \left(\frac{4\pi}{3}\right)\cdot (0.025\,m)^{3}\cdot \left(3.32\,\frac{kJ}{kg\cdot ^{\textdegree}C} \right)\cdot (70\,^{\textdegree}C - 8\,^{\textdegree}C)[/tex]
[tex]Q_{in} = 13.742\,kW[/tex]
b) The amount of entropy generation is determined by the Second Law of Thermodynamics:
[tex]\Delta S = \frac{Q_{in}}{T_{in}}[/tex]
[tex]\Delta S = \frac{13.742\,kJ}{370.15\,K}[/tex]
[tex]\Delta S = 370.15\,\frac{kJ}{K}[/tex]
The heat transferred to the egg is approximately 18.24 kJ. The entropy generation associated with this heat transfer is about 5.68 kJ/K.
To determine how much heat is transferred to the egg, we use the following formula for heat transfer in a substance:
Q = m × cp × (T_final - T_initial)
Given data:
Initial temperature, T_initial: 8°CFinal temperature, T_final: 70°CDensity, ρ: 1020 kg/m³Specific heat, cp: 3.32 kJ/kg·°CDiameter of the egg: 5.5 cm (radius is 2.75 cm or 0.0275 m)The volume of the egg as a sphere is:
V = (4/3) × π × r³ = (4/3) × π × (0.0275)³ ≈ 8.72 × 10⁻⁵ m³
The mass of the egg is then:
m = ρ × V = 1020 kg/m³ × 8.72 × 10⁻⁵ m³ ≈ 0.0889 kg
Now, calculate the heat transferred:
Q = m × cp × (T_final - T_initial) = 0.0889 kg × 3.32 kJ/kg·°C × (70°C - 8°C) ≈ 18.24 kJ
(b) Calculating Entropy Generation:
Using the formula for entropy change, we have:
ΔS = m × cp × ln(T_final/T_initial)
Temperatures in Kelvin:
T_initial = 8°C + 273.15 = 281.15 KT_final = 70°C + 273.15 = 343.15 KThen:
ΔS = 0.0889 kg × 3.32 kJ/kg·°C × ln(343.15 / 281.15) ≈ 5.68 kJ/K
Hence, the amount of entropy generated during the process is approximately 5.68 kJ/K.
The speed of sound in air is 320 ms-1 and in water it is 1600 ms-1. It takes 2.5 s for sound to reach a certain distance from the source placed in air. a. Find the distance. b. How much time will it take for sound to travel the same distance when the source is in water?
Answer:
Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.
Explanation:
Given:
Speed of sound in air = 320 m/s
Speed of sound in water = 1600 m/s
Time taken to reach certain distance in air = 2.5 sec
a.
We have to find the distance traveled by sound in air.
Distance = Product of speed and time.
⇒ [tex]Distance = Speed\times time\ taken[/tex]
⇒ [tex]Distance = 320\times 2.5[/tex]
⇒ [tex]Distance = 800[/tex] meters.
b.
Now we have to find how much time the sound will take to travel in water.
⇒ Time = Ratio of distance and speed
⇒ [tex]Time =\frac{distance}{speed}[/tex]
⇒ [tex]Time =\frac{800}{1600}[/tex] ...distance = 800 m and speed = 1600 m/s
⇒ [tex]Time =\frac{1}{2}[/tex]
⇒ [tex]Time =0.5[/tex] seconds.
Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.
Try to have the equipotential lines equally spaced in voltage. Then, use an E-Field Sensor to measure the electric field at a few points while looking at the relationship between the electric field and the equipotential lines.
Which of the following statements is true?
1.The electric field strength is greatest where the voltage is the smallest.
2.The electric field strength is greatest where the equipotential lines are very close to each other.
3.The electric field strength is greatest where the voltage is the greatest.
Answer:
2 The electric field strength is greatest where the equipotential lines are very close to each other.
Explanation:
Equipotential lines are contour lines which trace the lines of identical altitudes. In physics, they trace out lines of equal electric potential or voltage.
Equipotential lines are always perpendicular to the electric field. The closer the equipotential lines to each other, the greater the strength of the electric field.
These mystery elements are at the top of their families on the periodic table. An element that is in the same family as element C is likely to have which properties?
1.) The atomic radius of the elements in a group or family increase from the top to the bottom.
2.) The ionization energy decrease going down from the top to the bottom of the group.
3.) Electron affinity becomes less negative from the top to the bottom
4.) Element with high ionization energy has high electronegativity. Therefore, electronegativity decreases from top to the bottom of the group.
Periodic table tells us of the arrangement of elements and also the periodic properties of the elements as they are arranged in groups, periods and families.
some of the properties are :
1. Atomic radius
2. Ionization Energy
3. Electron Affinity
4. Electronegativity
5. Metallic character
6. e.tc
1.) The atomic radius of the elements in a group or family increase from the top to the bottom.
2.) The ionization energy decrease going down from the top to the bottom of the group.
3.) Electron affinity becomes less negative from the top to the bottom
4.) Element with high ionization energy has high electronegativity. Therefore, electronegativity decreases from top to the bottom of the group.
Due to the reason mention above, i can conclude the mystery elements are at the top of their families on the periodic table. An element that is in the same family as element C is likely to have all properties mentioned above.
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The voltage V in a circuit that satisfies the law V = IR is slowly dropping as the battery wears out. At the same time, the resistance R is increasing as the resistor heats up. Use the equation dV dt = ∂V ∂I dI dt + ∂V ∂R dR dt to find how the current I is changing at the instant when R = 600 ohms, I = 0.04 amps, dR/dt = 0.5 ohms/sec, and dV /dt = −0.01 volts/sec. Hint: We need to find the rate of change of I, with respect to time. Find the partial derivatives of V with respect to I and R, then substitute into the equation for dV /dt.
Answer:
[tex]-0.5\times 10^{-4} A/s[/tex]
Explanation:
We are given that
[tex]\frac{dV}{dt}=-0.01 V/s[/tex]
R=600 ohms
I=0.04 A
[tex]\frac{dR}{dt}=0.5ohm/s[/tex]
[tex]V=IR[/tex]
[tex]\frac{dV}{dt}=\frac{\partial V}{dI}\frac{dI}{dt}+\frac{\partial V}{dR}\frac{dR}{dt}[/tex]
[tex]\frac{dV}{dt}=R\frac{dI}{dt}+I\frac{dR}{dt}[/tex]
Substitute the values
[tex]-0.01=600\times \frac{dI}{dt}+0.04\times 0.5[/tex]
[tex]-0.01-0.04\times 0.5=600\frac{dI}{dt}[/tex]
[tex]-0.03=600\frac{dI}{dt}[/tex]
[tex]\frac{dI}{dt}=\frac{-0.03}{600}=-0.5\times 10^{-4}A/s[/tex]
Final answer:
The student's question concerns finding the rate of change of current in a circuit as described by Ohm's law. By finding partial derivatives of the voltage with respect to current and resistance and applying the provided rates, you solve for the rate of change of current.
Explanation:
The student is asking how the current I is changing over time in a circuit with a given resistance R, current I, and rates of change dR/dt and dV/dt according to Ohm's law. To solve this, we need to find the partial derivatives of voltage V with respect to current I and resistance R, and then use the given differential equation dV dt = ∂V ∂I dI dt + ∂V ∂R dR dt.
Using Ohm's law, we can express the voltage as V = IR. The partial derivative of V with respect to I is R, and with respect to R is I. Substituting these derivatives and the given values into the differential equation, we have: -0.01 = 600 dI dt + 0.04 * 0.5. Solving for dI dt, we get the rate at which the current is changing over time, which is the answer the student is looking for.
Which element is the most prevalent in the human body?
nitrogen
hydrogen
carbon
oxygen
The most prevalent in the human body by mass is oxygen.
To find the answer, we need to know more about the elemental composition in human body.
What is the elemental composition in human body?The element that is most prevalent in the human body by mass is oxygen. This makes sense if you think about it because the majority of the human body is made up of water, or H2O. The bulk of the human body is composed of 61–65% oxygen. Your body has considerably more hydrogen than oxygen atoms, but each oxygen atom is 16 times heavier than a hydrogen atom.The second prevalent element in the body is carbon. It is about 18%.Thus, we can conclude that, the most prevalent in the human body by mass is oxygen.
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Answer:B I think
Explanation:
At t=0 a grinding wheel has an angular velocity of 28.0 rad/s. It has a constant angular acceleration of 25.0 rad/s2 until a circuit breaker trips at time t = 1.90 s. From then on, it turns through an angle 436 rad as it coasts to a stop at constant angular acceleration.
(a) Through what total angle did the wheel turn between t= 0 and the time it stopped?
(b) At what time does the wheel stop?
(c)What was the wheel's angular acceleration as it slowed down? Express your answer in radians per second per second.
Answer:
(a) 534.324 rad
(b) 13.45 s
(c) -6.45 rad/s2
Explanation: Please see the attachments below
Final answer:
The grinding wheel's total angle of turn, time to stop, and angular acceleration are calculated using its initial angular velocity, time accelerated, and the angle it turned while coasting.
Explanation:
Calculating Angular Motion of a Grinding Wheel
A grinding wheel starts with an angular velocity of 28.0 rad/s and accelerates for 1.90 s at a constant angular acceleration of 25.0 rad/s2. After a circuit breaker trips, it coasts to a stop through 436 rad.
To find the total angle the wheel turns, calculate the angle turned during the acceleration phase and add the 436 rad it turns while coasting.
The time for the wheel to stop is found by calculating the time from start to when the circuit breaker trips plus the time it takes to coast to a stop.
The angular acceleration during the deceleration phase is determined using the kinematic equations of rotational motion.
Describe how the properties of water contribute to two of the following. Transpiration thermoregulation in endotherms plasma membrane structure
Answer:
Explanation:
The contributions of water properties in Thermoregulation in endotherms and in the plasma membrane structure.
A) Thermoregulation in endotherms: Water contributes to thermoregulation by its property of High specific heat. Water's high specific heat acts as a heat buffer, it is much harder to cool down/heat up, therefore, it will make warmer than the cold environment around it or colder than the hot environment around it. Thermoregulation works in humansas well. Recall Homeostasis which is the body's way of regulating our temperature.
B) Plasma membrane structure:
The property of water, polarity, contributes to the plasma membrane because it creates the arrangement of phospholipids making it a semi-permeable membrane.
Recall that the Plasma Membrane has a hydrophilic end on the outside that is charged and likes water and a hydrophobic end on the inside that has no charge and doesn't like water.
The membrane that separates the interior of the cell from the external environment is known as the plasma membrane, sometimes known as the cell membrane, and it is present in all cells. A cell wall is affixed to the plasma membrane on the exterior of bacterial and plant cells.
What is transpiration?Like all other living things, plants need an excretory system to remove extra water from their bodies. Transpiration is the term for this process of removing extra water from the body of the plant. Typically, it is the evaporation of water from the leaf surface.
Now, according to the question :
(A) Thermoregulation in endotherms :
Water helps regulate body temperature since it has a high specific heat. Due to its high specific heat, which acts as a heat buffer, water will either make an area warmer than the surrounding cold environment or colder than the surrounding hot environment. Humans are capable of thermoregulation as well. Remember that the body uses homeostasis to control our body temperature.
(B) Plasma membrane structure:
Because it forms the arrangement of phospholipids that makes the plasma membrane a semi-permeable membrane, water's polarity contributes to the plasma membrane.
Remember that the Plasma Membrane has an exterior hydrophilic end that is charged and prefers water, and an interior hydrophobic end that is uncharged and dislikes water.
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A step-down transformer is used for re-charging the batteries of portable devices such as tape players. The ratio of turns inside the transformer is 10:1, and it is used with 120 V (rms) household service. A particular ideal transformer draws 0.350 A from the house outlet.
A) What are the voltage.
B) What are the current supplied to a tape player from the transformer?
C) How much power is delivered?
Answer with Explanation:
We are given that
[tex]\frac{N_1}{N_2}=10[/tex]
[tex]V_1=120 V[/tex]
[tex]I_1=0.350 A[/tex]
a.[tex]\frac{V_1}{V_2}=\frac{N_1}{N_2}[/tex]
Using the formula
[tex]\frac{120}{V_2}=\frac{10}{1}[/tex]
[tex]V_2=\frac{120}{10}=12 V[/tex]
b.[tex]\frac{I_2}{I_1}=\frac{N_1}{N_2}[/tex]
[tex]\frac{I_2}{0.350}=10[/tex]
[tex]I_2=0.350\times 10=3.5 A[/tex]
c.Power delivered,P=[tex]I_2V_2=I_1V_1[/tex]
[tex]P=120\times 0.350=42 W[/tex]
Technician A says that the evacuation process will remove dirt and debris from the refrigerant system. Technician B says that the evacuation process will remove moisture and air from the refrigerant system. Who is correct?
Answer: Technician B is right.
Explanation:
Evacuation process is used in refrigeration systems to remove moisture, air and non-profit condensable gases in order to achieve maximum function of the system.
vacuum pump is used to draw the sealed AC system into a vacuum. Evacuation of a refrigerant system also helps to maintain pressure, this is so as pulling a vacuum on the system is simply removing matter (mostly air and nitrogen) from inside the system so that the pressure inside drops below atmospheric pressure.
A British bicycle light company advertises flashing bicycle lights that require no batteries and produce no resistance to riding. A magnet attached to a spoke on the bicycle tire moves past a generator coil on the bicycle frame, inducing an emf that causes a light to flash. The magnet and coil never touch. Does this lighting system really produce no resistance to riding? Justify your answer.
Answer:
Lenz's law is responsible for the resistance to advance due to the change in magnetic flux
Explanation:
This system produces electricity by Faraday's law,
E = - d / dt B.A
Where the electromotive force is generated by the change of the field strength maintained due to the circular movement of the wheel.
As this field changes when Lenz's law increases or decreases, it creates a field that opposes this change, this field is applied to the bicycle and is in the opposite direction to movement, so it is an effect that creates resistance to the advance of the bike.
In summary Lenz's law is responsible for the resistance to advance due to the change in magnetic flux
A dog has a mass of 60kg and an acceleration of 2m/s/s. What is the force of the dog?
Answer:
120 N
Explanation:
F=ma therefore 60kg times 2m/s^2 is 120 N
An inventor claims to have developed a heat pump that produces 200 kW of heating for a 293 K heated zone whilst only using 75 kW of power and a heat source at 273 K. Using the max. theoretical efficiency of this device, justifythe validity of this claim. [5]
Answer:
Answer is 14.65
Refer below.
Explanation:
Refer to the picture for brief explanation.
What percentage of the intensity gets through both polarizers?
Answer:
if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero
Explanation:
The incident light is generally random, that is, it does not have a polarization plane, when the first polarized stops by half, this already polarized light arrives at the second polarizer and the causticity passes
I = I₀ cos² θ
therefore if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero
Density: Two blocks, A and B, are put in a tank of water. Block A has a density of 1.21 g/cm³. Block B has a density of 1.37 g/cm³. Which will float higher in the water?
Answer:
Block A
Explanation:
Block A will float higher in the water compared to the second Block.
The density of water is 1g/cm³.
According to the principle of floatation "an object that floats in a liquid will displace equal amount of fluid to the weight of the object".
A body will become more submerged in water if it has more density because density is the mass per volume of body.
An object with a higher density than another will sink in the liquid of the one with lesser density.
Object A has lesser density and will float higher up and displace very little water. Object B has higher density and will be more submerged.Suppose that a comet has a very eccentric orbit that brings it quite close to the Sun at closest approach (perihelion) and beyond Mars when furthest from the Sun (aphelion), but with an average distance (semi-major axis) of 1 AU. How long will it take to complete an orbit and where will it spend most of its time
Answer:
16.63min
Explanation:
The question is about the period of the comet in its orbit.
To find the period you can use one of the Kepler's law:
[tex]T^2=\frac{4\pi}{GM}r^3[/tex]
T: period
G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2
r: average distance = 1UA = 1.5*10^11m
M: mass of the sun = 1.99*10^30 kg
By replacing you obtain:
[tex]T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min[/tex]
the comet takes around 16.63min
The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity as measured in W/m2 changes by a multiplicative factor. The number of decibels increases by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is
β=10log(II0)dB,
where I0 is a reference intensity. For sound waves, I0 is taken to be 10−12W/m2. Note that log refers to the logarithm to the base 10.
Part A) What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity (i.e., I=10I0)?
Part B) What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity (i.e. I=100I0)?
Express the sound intensity numerically to the nearest integer.
β = dB
One often needs to compute the change in decibels corresponding to a change in the physical intensity measured in units of power per unit area. Take m to be the factor of increase of the physical intensity (i.e., I=mI0).
Part C) Calculate the change in decibels ( Δβ2, Δβ4, and Δβ8) corresponding to m=2, m=4, and m=8.
Give your answers, separated by commas, to the nearest integer--this will give an accuracy of 20%, which is good enough for sound.
Answer:
a) 10 dB, b) 20dB, c) 10², 10⁴, 10⁸
Explanation:
The logarithmic scale has a great advantage when measuring magnitudes of a large number of scales, since it converts these values to linear, allowing easier viewing.
Part A
Let's look for decibels for an intensity I = 10 Io
We calculate
β = 10 log (10Io / Io)
β = 10 dB
Part b
Let's find the intensity for I = 100 Io
We calculate
β = 10 log (100Io / Io)
β = 10 log 100
β = 10 2
β = 20 db
Part c
Δβ2 corresponds to an intensity change of 10² Io, therefore it corresponds to an intensity increase of 10²
Δβ4 corresponds to a change in intensity of 10⁴Io
Δβ8 is an intensity change of 10⁸ Io
The sound intensity level in decibels can be calculated using the formula β = 10log(I/I_0). For a sound wave with intensity 10 times the reference intensity, the sound intensity level is 10 dB. For a sound wave with intensity 100 times the reference intensity, the sound intensity level is 20 dB.
Explanation:Part A: To find the sound intensity level when the intensity is 10 times the reference intensity, we use the formula β = 10log(I/I_0). Plugging in the values, β = 10log(10I_0/I_0) = 10log(10) = 10 x 1 = 10 dB.
Part B: Similarly, when the intensity is 100 times the reference intensity, we get β = 10log(100I_0/I_0) = 10log(100) = 10 x 2 = 20 dB.
Part C: To calculate the change in decibels for different intensities (m), we use the formula Δβ = 10log(m). For m = 2, Δβ2 = 10log(2) = 10 x 0.3 = 3 dB. For m = 4, Δβ4 = 10log(4) = 10 x 0.6 = 6 dB. And for m = 8, Δβ8 = 10log(8) = 10 x 0.9 = 9 dB.
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A wheel 1.70 m in diameter lies in a vertical plane and rotates about its central axis with a constant angular acceleration of 3.60 rad/s2. The wheel starts at rest at t = 0, and the radius vector of a certain point P on the rim makes an angle of 57.3° with the horizontal at this time. At t = 2.00 s. What is the tangential speed, total acceleration, and angular position of point P.
Final answer:
To calculate the tangential speed, total acceleration, and angular position of point P on the wheel at t = 2.00 s, we can use the formulas for tangential speed, total acceleration, and angular position. By substituting the given values into these equations, we can find the required values.
Explanation:
To calculate the tangential speed of a point on the wheel, we can use the formula:
Tangential Speed = Angular Velocity x Radius
In this case, the angular velocity is given by the equation:
Angular Velocity = Initial Angular Velocity + (Angular Acceleration x Time)
Substituting the given values and solving the equations, we can find the tangential speed, which is the speed of the point P on the rim at time t = 2.00 s.
To find the total acceleration, we can use the formula:
Total Acceleration = Tangential Acceleration + Radial Acceleration
The tangential acceleration can be calculated using the equation:
Tangential Acceleration = Angular Acceleration x Radius
The radial acceleration can be calculated using the equation:
Radial Acceleration = (Angular Velocity x Angular Velocity) x Radius
By substituting the given values into these equations, we can find the total acceleration at time t = 2.00 s.
To find the angular position of point P at time t = 2.00 s, we can use the equation:
Angular Position = Initial Angular Position + (Initial Angular Velocity x Time) + (0.5 x Angular Acceleration x Time x Time)
Substituting the given values, we can find the angular position of point P at t = 2.00 s.
A horizontal wooden beam sags a bit when supported at its ends. In between the top and bottom surfaces is a region of
Answer: neither tension nor compression
Explanation:
The tension in the form of load or forces
And also compression in the form of weight or load since the sagging is negligible as interpreted from the question which say that - horizontal wooden beam sags a bit when supported at its ends.
A toy cannon uses a spring to project a 5.24-g soft rubber ball. The spring is originally compressed by 5.01 cm and has a force constant of 8.08 N/m. When the cannon is fired, the ball moves 15.8 cm through the horizontal barrel of the cannon, and the barrel exerts a constant friction force of 0.031 0 N on the ball.With what speed does the projectile leave the barrel of the cannon?
Answer:
Speed will be equal to 1.40 m/sec
Explanation:
Mass of the rubber ball m = 5.24 kg = 0.00524 kg
Spring is compressed by 5.01 cm
So x = 5.01 cm = 0.0501 m
Spring constant k = 8.08 N/m
Frictional force f = 0.031 N
Distance moved by ball d = 15.8 cm = 0.158 m
Energy gained by spring
[tex]KE=\frac{1}{2}kx^2=\frac{1}{2}\times 8.08\times 0.0501^2=0.0101J[/tex]
Energy lost due to friction
[tex]W=Fd=0.031\times 0.158=0.0048J[/tex]
So remained energy to move the ball = 0.0101 - 0.0048 = 0.0052 J
This energy will be kinetic energy
[tex]\frac{1}{2}mv^2=0.0052[/tex]
[tex]\frac{1}{2}\times 0.00524\times v^2=0.0052[/tex]
v = 1.40 m/sec
The toy cannon's projectile leaves the barrel at approximately 1.42 m/s.
To find the speed at which the 5.24-g soft rubber ball leaves the barrel of the toy cannon, we follow these steps:
1.) Determine the Potential Energy in the Compressed Spring:
The potential energy stored in the spring when it is compressed can be calculated using the formula:
Potential Energy = (1/2) * k * x²where
k is the spring constant (8.08 N/m) and x is the compression distance (5.01 cm = 0.0501 m). Potential Energy = (1/2) * 8.08 N/m * (0.0501 m)²
Potential Energy = 0.01017504 J
2.) Calculate the Work Done by Friction:
Friction force is constant at 0.0310 N over a distance of 15.8 cm (0.158 m):
Work = Friction Force * DistanceWork = 0.0310 N * 0.158 mWork = 0.004898 J3.) Find the Net Energy Available:
Net Energy = Potential Energy - Work done by friction:Net Energy = 0.01017504 J - 0.004898 JNet Energy = 0.00527704 J4.) Calculate the Speed of the Ball:
Using the energy conservation principle where Net Energy is converted into kinetic energy:
Kinetic Energy = (1/2) * m * v²The ball's mass (m) = 5.24 g = 0.00524 kg.Solving for velocity (v):
0.00527704 J = (1/2) * 0.00524 kg * v²Thus, the speed at which the ball leaves the barrel of the cannon is approximately 1.42 m/s.
Most of the asteroids in our solar system are located between the orbits of what two objects?
Answer:
Jupiter and Mars.
The asteroid belt is located between those two celestial objects.
:)
An electron is accelerated from rest by a potential difference of 412 V. It then enters a uniform magnetic field of magnitude 188 mT with its velocity perpendicular to the field. Calculate (a) the speed of the electron and (b) the radius of its path in the magnetic field.
Explanation:
Given that,
Potential difference, V = 412 V
Magnitude of magnetic field, B = 188 mT
(a) The potential energy of electron is balanced by its kinetic energy as :
[tex]eV=\dfrac{1}{2}mv^2[/tex]
v is speed of the electron
[tex]v=\sqrt{\dfrac{2eV}{m}} \\\\v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 412}{9.1\times 10^{-31}}} \\\\v=1.2\times 10^7\ m/s[/tex]
(b) When the charged particle moves in magnetic field, it will move in circular path. The radius of the circular path is given by :
[tex]r=\dfrac{mv}{eB}\\\\r=\dfrac{9.1\times 10^{-31}\times 1.2\times 10^7}{1.6\times 10^{-19}\times 188\times 10^{-3}}\\\\r=3.63\times 10^{-4}\ m[/tex]
Hence, this is the required solution.
when all else remains the same, what effect would decreasing the focal have known a convex lens
Answer:
when all else remains the same, what effect would decreasing the focal have known a convex lens
Explanation:
It would cause the lens to produce only real images
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Technician A says that if the yellow warning lamp is illuminated indicating a fault in the electronic brake control system, you should retrieve the diagnostic trouble codes and follow the procedure listed in the service information. Technician B says that once the fault has been corrected, clear the diagnostic code and verify that it does not reset. Who is correct?
A)A only
B)B only
C)Both A and B
D)Neither A nor B
Answer: C) Both A and B
Explanation:
The ABS system is disabled when the ABS yellow warning lamp is on. And when the warning lamp is on the base brake system will work normally but without ABS function
And if the yellow warning lamp is illuminated indicating a fault in the electronic brake control system, you should retrieve the diagnostic trouble codes and follow the procedure listed in the service information. Once the fault has been corrected, clear the diagnostic code and verify that it does not reset
Pesticides and cancer drugs are both created by:
selective breeding
hybridization
recombinant DNA
cloning
A cell membrane consists of an inner and outer wall separated by a distance of approximately 10nm. Assume that the walls act like a parallel plate capacitor, each with a charge density of 10^(−5) C/m^2, and the outer wall is positively charged. Although unrealistic, assume that the space between cell walls is filled with air.
(A) What is the magnitude of the electric field between the membranes?
a) 1×10^6 N/C
b) 1×10^15 N/C
c) 5×10^5 N/C
d) 9×10^2 N/C
(B) What is the magnitude of the force on a K+ ion between the cell walls?
a) 2×10^13 N
b) 9×10^13 N
c) 2×10^11 N
d) 3×10^12 N
(C) What is the potential difference between the cell walls?
a) 6×10^3 V
b) 1×10^7 V
c) 10 V
d) 1×10^2 V
(D) What is the direction of the electric field between the walls?
a) There is no electric field.
b) Toward the inner wall.
c) Parallel to the walls.
d) Toward the outer wall.
Answer:
1) A
2) A
3) D
Explanation:
For parallel plates,the electric field E is given by:
E = σ / ε(o), where
E = Electric Field
σ = surface charge density
E = 10^-5 / 8.85*10^-12
E= 1.13*10^6 which is approximately 1*10^6 N/C, option A
B) K has a charge of 1.6*10^-19
F= q*E= (1.13*10^6) * (1.6*10^-19)
F= 1.8*10^-13 Which is approximately 2*10^-13 N, option A
C) Potential difference ,V = Ed
d = 10 nm= 1*10^-9
V = 1.13*10^6 * 1**10^-9
V = 0.0113 v
V = 1.13×10^-2 which is approximately 1x10^-2v, option D
The answers are 1) 1×10^6 N/C, 2) 2×10^13 N, 3) 6×10^3 V, 4) Toward the inner wall.
1) The magnitude of the electric field between the membranes can be calculated using the formula for electric field strength in a parallel plate capacitor:
E = σ / ε₀ = 10^(-5) C/m^2 / (8.85 x 10^(-12) F/m)
= 1.13 x 10^6 N/C.
Therefore, the answer is (a) 1×10^6 N/C.
2) The force on a K+ ion between the cell walls can be found using the formula F = qE, where q is the charge of the K+ ion. As K+ has a +1 charge, the force will be 1.13 x 10^6 N/C × 1.6 x 10^(-19) C
= 1.80 x 10^(-13) N.
Therefore, the answer is 2×10^13 N.
3) The potential difference between the cell walls can be calculated by multiplying the electric field strength by the distance between the walls:
V = Ed = 1.13 x 10^6 N/C × 10 x 10^(-9) m
= 1.13 x 10^4 V = 11.3 kV.
Therefore, the answer is (a) 6×10^3 V.
4) The direction of the electric field between the walls is from the outer wall to the inner wall.
Therefore, the answer is (b) Toward the inner wall.
what is the solvent in air
Answer:
The majority component is the solvent so In the air nitrogen is found more.
So Nitrogen is the solvent in air.
1. What will happen to the brightness of the light bulb if the switch in this circuit is suddenly closed?
Answer:
There is no closed-loop path for the current to flow through the circuit.When the switch is closed,the light bulb operates since the current flows through the circuit.The bulb glows at its full brightness since its receives its full 120 volts and has the design current flow.
Explanation:
An electron moves with a speed of 8.0 × 10^{6} m/s along the +x-axis. It enters a region where there is a magnetic field of 2.5 T, directed at an angle of 60° to the +x-axis and lying in the xy-plane. What is the magnitude of the magnetic force of the electron?
Answer:
The magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N
Explanation:
Given;
speed of the electron, v = 8.0 × 10⁶ m/s
magnetic field strength, B = 2.5 T
angle of inclination of the field, θ = 60°
The magnetic force experienced by the electron in the magnetic field is given as;
F = qvBsinθ
where;
q is charge of electron = 1.6 x 10⁻¹⁹ C
B is strength of magnetic field
v is speed of the electron
Substitute the given values and solve for F
F = (1.6 x 10⁻¹⁹)( 8.0 × 10⁶)(2.5)sin60
F = 2.77 x 10⁻¹² N
Thus, the magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N
The magnitude of the magnetic force on the electron is approximately 2.06 x 10^-13 N.
Explanation:In this scenario, the magnitude of the magnetic force on the electron can be calculated using the equation F = qvBsinθ, where q is the charge of the electron (+1.6 x 10-19 C), v is its velocity (8.0 x 106 m/s), B is the magnetic field (2.5 T), and θ is the angle between the velocity and the magnetic field (60°). Plugging in the values, we get:
F = (1.6 x 10-19 C)(8.0 x 106 m/s)(2.5 T)sin(60°)
Using the trigonometric identity sin(60°) = sqrt(3)/2, we can simplify the equation and calculate the magnitude of the magnetic force to be approximately 2.06 x 10-13 N.
Learn more about magnetic force on an electron here:https://brainly.com/question/16638636
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