Takt time is the rate at which a factory must produce to satisfy the customer's demand. a)- True b)- False

Answers

Answer 1

Answer: a)True

Explanation: Takt time is defined as the average time difference between  the production of the two consecutive unit of goods by the manufacturer and this rate is matched with the demand of the customer. This is the time which is calculated to find the acceptable time for which the goods unit must be produced  by the factory to meet the needs of the customer. Therefore , the statement is true that takt time is the rate at which a factory must produce to satisfy the customer's demand.


Related Questions

What is the Thermodynamic (Absolute) temperature scale?

Answers

Answer:

0 K

Explanation:

The thermodynamic absolute temperature is that temperature  at which there is an infinite cooling and so there is no movement of any molecules or particles it is given by kelvin. 0 K is that temperature at which there is no movement of molecule so 0 K or -273°C in degree Celsius is the absolute temperature in thermodynamic temperature scale.  

Define the terms (a) thermal conductivity, (b) heat capacity and (c) thermal diffusivity

Answers

Explanation:

(a)

The measure of material's ability to conduct thermal energy (heat) is known as thermal conductivity. For examples, metals have high thermal conductivity, it means that they are very efficient at conducting heat. The SI unit of heat capacity is W/m.K.

The expression for thermal conductivity is:

[tex]q=-\kappa \bigtriangledown T[/tex]

Where,

q is the heat flux

[tex]\kappa[/tex] is the thermal conductivity

[tex] \bigtriangledown T[/tex] is the temperature gradient.

(b)

Heat capacity for a substance is defined as the ratio of the amount of energy required to change the temperature of the substance and the magnitude of temperature change. The SI unit of heat capacity is J/K.

The expression for Heat capacity is:

[tex]C=\frac{E}{\Delta T}[/tex]

Where,

C is the Heat capacity

E is the energy absorbed/released

[tex]\Delta T[/tex] is the change in temperature

(c)

Thermal diffusivity is defined as the thermal conductivity divided by specific heat capacity at constant pressure and its density. The Si unit of thermal diffusivity is m²/s.

The expression for thermal diffusivity is:

[tex]\alpha=\frac{\kappa}{C_p \times \rho}[/tex]

Where,

[tex]\alpha[/tex] is thermal diffusivity

[tex]\kappa[/tex] is the thermal conductivity

[tex]C_p[/tex] is specific heat capacity at constant pressure

[tex]\rho[/tex] is density

A gear pump has a 4.25in outside diameter, a 3.25in inside diameter, and a 2in width. If the actual pump flow rate is 1800rpm and rated pressure is 29gpm, what is the volumetric efficiency?

Answers

Answer:

volumetric efficeincy = 0.315%

Explanation:

Given data:

outside diameter = 4.25 inch

inside diameter = 3.25 inch

flow rate V = 1800 rpm

actual flow rate Qa = 29gpm = 6699 inch3/min

volume of pump can be determine by using below formula

[tex]VOLUME = \frac{\pi}{4}*(D_{0}^{2}-D_{1}^{2})L[/tex]

              [tex]=\frac{\pi}{4}*(4.25^{2}-3.25^{2})2[/tex]

[tex]VOLUME = 11.78 inc^{3}[/tex]

theoretical flow rate is given as Qt

[tex]Q_{T} = V.N[/tex]

         = 11.78*1800

         =[tex]21204 inch ^{3}/ min[/tex]

[tex]volumetric efficeincy = \frac{Q_{A}}{Q_{T}}[/tex]

                                   [tex]=\frac{6699}{21204}[/tex]

volumetric efficeincy = 0.315%

What is the advantage to use a multistage compression refrigeration system over a single stage compression system?

Answers

Answer:

the advantages of using multistage compression refrigeration system over a single stage compression system are as follows:

Explanation:

It results in increased volumetric efficiency of compressor due to decrease in pressure ratio in each stage.Cost of operation is comparatively lowUniformity in torque is achieved thus reducing the size of the flywheel.Reduced size of condensor as a result of heat removal during condensationLower temperature at the end of compression resulting in effective lubrication and increased compressor life.

If 100 J of heat is added to a system so that the final temperature of the system is 400 K, what is the change in entropy of the system? a)- 0.25 J/K b)- 2.5 J/K c)- 1 J/K d)- 4 J/K

Answers

Answer:

0.25 J/K

Explanation:

Given data in given question

heat (Q) = 100 J

temperature (T) = 400 K

to find out

the change in entropy of the given system

Solution

we use the entropy change equation here i.e  

ΔS = ΔQ / T           ...................a

Now we put the value of heat (Q) and Temperature (T) in equation a

ΔS is the entropy change, Q is heat and T is the temperature,  

so that

ΔS = 100/400 J/K

ΔS = 0.25 J/K

The use of zeroes after a decimal point are an indicator of accuracy. a)True b)- False

Answers

Answer:

True.

Explanation:

Yes, zeroes indicates the precision  after the decimal point.

For smallest of the calculation in to get the precise value is very important for that the calculation can have very minute changes in decimal point as more accurate the calculation  is more zeroes will be in the decimal value .

Most of the instrument calculating weights is said to precise by how much decimal they can calculate.

The Poisson effect does not apply to shear strains. a)True b)- False

Answers

Answer:

true

Explanation:

Shear strains and direct strains are independent components in a strain tensor at a point. Also the poisson ratio is defined as

μ = - [tex]\frac{lateral strain}{longitudinal strain}[/tex]

Which is independent of shear strains Thus this affect does not apply on shear strains

A cubic transmission casing whose side length is 25cm receives an input from the engine at a rate of 350 hp. If the vehicle's velocity is such that the average heat transfer coefficient is 230 W/m'K and the efficiency of the transmission is n=0.95 (i.e. the remainder is heat), calculate the surface temperature if the ambient temperature is 15°C. Assume that heat transfer only occurs on one face of the cube. NOTE: 1 hp=745 W

Answers

Answer:

The surface temperature is 921.95°C .

Explanation:

Given:

   a=25 cm ,P=350 hp⇒P=260750 W

Power transmitted [tex]0.95\times 260750[/tex]W and remaining will lost in the form of heat.This heat transmitted to air by the convection.

 h=230[tex]\frac{W}{m^2-K},\eta =0.95[/tex]

Actually heat will be transmit by the convection.

In convection Q=hA[tex]\Delta T[/tex]

So [tex]P=\Delta T\times Q[/tex]

[tex]0.05\times 260750=230\times0.25^2\(T-15)[/tex]

T=921.95°C

So the surface temperature is 921.95°C .

To measure the voltage drop across a resistor, a _______________ must be placed in _______________ with the resistor. Ammeter; Series Ammeter; Parallel Voltmeter; Series Voltmeter; Parallel

Answers

Answer:

The given blanks can be filled as given below

Voltmeter must be connected in parallel

Explanation:

A voltmeter is connected in parallel to measure the voltage drop across a resistor this is because in parallel connection, current is divided in each parallel branch and voltage remains same in parallel connections.

Therefore, in order to measure the same voltage across the voltmeter as that of the voltage drop across resistor, voltmeter must be connected in parallel.

List irreversibilities

Answers

Answer:

Some of the irreversibilities are listed below:

Plastic deformation of solidsTransfer of heat over finite difference of temperatureWhen two fluids are mixed together the process is irreversibleCombustion of a gasCurrent flowing through a finite resistor Diffusion and free compression or expansion of gasRelative motion of body with force of frictionProcesses involving chemical reactions(spontaneous)

List fabrication methods of composite Materials.

Answers

Answer:

Fabrication method of composite materials varies for one product of material to other product. It is basically developed to meet the product requirement.

The fabrication of composite parts are depends upon different factors that are:

Depend on the Characteristics of strengthening and matrices. The details of the product and the shape and size also.Application or end uses.

Types of fabrication methodologies are :

Press moldingCompression moldingContact moldOpen molding Tube rolling

A student checks her car's tyre air pressure at a petrol station and finds it is 31 psi. Re-express this as an absolute pressure in kpa. Note any assumptions you make.

Answers

Answer:

Absolute Pressure=315.06256 kPa

Explanation:

Gauge pressure= 31 psi

Atmospheric Pressure at Sea level= 1 atm=101.325 kPa

[tex]1\ psi=6.89476\ kPa\\\Rightarrow 31\ psi=31\times 6.89476\\\Rightarrow 31\ psi=213.73756\ kPa=Gauge\ Pressure\\Absolute\ Pressure=Gauge\ Pressure+Atmospheric\ Pressure\\\Rightarrow Absolute\ Pressure=213.73756+101.325\\\therefore Absolute\ Pressure=315.06256\ kPa[/tex]

An alternating current E(t) =120 sin(12t) has been running through a simple circuit for a long time. The circuit has an inductance of L = 0.2 henrys, a resistor of R = 5 ohms and a capacitor of capcitance C = 0.043 farads. What is the amplitude of the current I?

Answers

Answer:

Explanation:

we have given E(t)=120 sin(12t)

R=5 ohm

L=0.2 H

ω=12 ( from expression of E)

[tex]X_L=0.2\times 12=2.4[/tex] ohm

[tex]X_C=\frac{1}{\omega \times C}=\frac{1}{12\times 0.043}=1.9379\ ohm[/tex]

[tex]Z=\sqrt{R^2+\left ( \omega L-\frac{1}{\omega C} \right )^2}[/tex]

[tex]Z=\sqrt{5^2+\left ( \2.4-1.9379 )^2}[/tex]

=5.021 ohm

so amplitude of current =  [tex]\frac{v}{z}=\frac{120}{5.021}=23.89[/tex]

What is the output of a system having the transfer function G = 2/[(s + 3) x(s + 4)] and subject to a unit impulse?

Answers

Answer:

output=[tex]\frac{2}{(s+3)(s+4)}[/tex]

Explanation:

output =transfer function ×input

here transfer function G=[tex]\frac{2}{(S+3)(S+4)} {}[/tex]

input = unit impulse

in S domain unit impulse =1

so output =[tex]\frac{2}{(S+3)(S+4)} {}[/tex]

=[tex]\frac{2}{(s+3)(s+4)}[/tex]

The equation of motion is not valid without the assumption of an inertial frame. a) True b)- false

Answers

Answer:

True

Explanation:

when we write equation of motion we have to assume frame of reference as because frame of reference  is the property that in frame of reference the body is not accelerated and net force acting on the body is zero.

when body is assumed to be any frame of reference we can assume the body is at rest and moving with constant speed.

Answer:

true

Explanation:

hope this helped , God bless

The turbine blade tip speed v for r=1m and 5 rev/sec is a) 5 m/s b) 0.25 m/s c) 0.20 m/s

Answers

Answer:

(a) 5 m/sec

Explanation:

we have given r=1 meter

angular velocity ω =5 revolution/sec

we have to find the velocity of turbine blade tip

the velocity of turbine blade tip is given by v =rω

where v = velocity of turbine blade tip

           r = radius

          ω = angular velocity

so v =5×1= 5 meter/sec

so the option (a) will be the correct option as in option (a) velocity is given as 5 meter/sec

Describe the basic types of chips produced in metal-cutting operations.

Answers

Answer:

Chips are of three types --

1. Continuous chip

2. Discontinuous or segmental chip

3.  Continuous chip with built up edge

Explanation:

Conventional machining process always removes some excess part of the metal in the form of Chips. Every machinist should be well aware of the type of chip formed as it gives the knowledge of the machining process. The chips forms give the knowledge of --

1. Dimension of tool

2. feed rate

3. cutting speed

4. nature of tool

5. Friction between tool and work piece

the different types of chips are :

1. Continuous chips :

  Continuous chips are long ribbon like coil that are bonded together. The continuous chips undergoes plastic deformation continuously. This is the most desirable form of chip produced. When such chips are formed, the  cutting is smooth with good surface finish. Mostly ductile material forms continuous chips.

2. Discontinuous chips :

   Discontinuous chips are formed when metals are machined and the material gets deformed easily. Brittle materials forms discontinuous chips. Discontinuous chips are in the form of loose broken chips that are not continuous. Discontinuous chips are formed when depth of cut and feed is large and cutting sped is low.

3. Continuous chips with built up edge :

   These chips are similar to the continuous chips where surface finish is not smooth. When ductile materials are machined at low cutting speed, a portion of work material tends tends to stick at the rake face of the tool due to the friction between the tools and the chip. This is known as built up edge.

A spherical steel container 3 feet in diameter is buried in a land fill. The container is filled with a chemical that keeps the outer surface of the container at 100°F, whereas the earth's surface is at 50°F. Determine the heat transfer from the container if it is buried under 3 feet of earth.

Answers

Answer:

Q = 378.247 Bt/hr

Explanation:

given data:

diameter of container = 3 m

so r =  1.5 m

T1 = 50°C

T2 = 100°C

depth y = 3 ft

Heat transfer is given as Q

[tex]Q = SK\Delta T[/tex]

Where

S =  Shape factor for the object

[tex]S = \frac{4\pi r}{1-\frac{r}{2y}}[/tex]

[tex]S = \frac{4\pi *1.5}{1-\frac{1.5}{2*3}}[/tex]

S = 25.132 ft

[tex]Q = SK\Delta T[/tex]

Q = 25.132*0.301 *(100-50)

Q = 378.247 Bt/hr

The "view factor" Fij depends on surface emissivity and surface geometry. a) True b) False

Answers

Answer:

(B) FALSE

Explanation:

view factor [tex]F_{ij}[/tex] depends on the surface emissivity and the surface of geometry  view factor is the term used in radiative heat transfer. View factor is depends upon the radiation which leave the surface and strike the surface.View factor is also called shape factor configuration factor it is denoted by  [tex]F_{ij}[/tex]

A Carnot refrigeration cycle absorbs heat at -12 °C and rejects it at 40 °C. a)-Calculate the coefficient of performance of this refrigeration cycle b)-If the cycle is absorbing 15 kW at the -12C temperature, how much power is required? c)-If a Carnot heat pump operates between the same temperatures as the above refrigeration cycle, determine the COP of heat pump? d)-What is the rate of heat rejection at the 40°C temperature if the heat pump absorbs 15 kw at the -12 C temperature?

Answers

Answer:

a)COP=5.01

b)[tex]W_{in}=2.998[/tex] KW

c)COP=6.01

d)[tex]Q_R=17.99 KW[/tex]

Explanation:

Given

[tex]T_L[/tex]= -12°C,[tex]T_H[/tex]=40°C

For refrigeration

  We know that Carnot cycle is an ideal cycle that have all reversible process.

So COP of refrigeration is given as follows

[tex]COP=\dfrac{T_L}{T_H-T_L}[/tex]  ,T in Kelvin.

[tex] COP=\dfrac{261}{313-261}[/tex]

a)COP=5.01

Given that refrigeration effect= 15 KW

We know that  [tex]COP=\dfrac{RE}{W_{in}}[/tex]

RE is the refrigeration effect

So

5.01=[tex]\dfrac{15}{W_{in}}[/tex]

b)[tex]W_{in}=2.998[/tex] KW

For heat pump

So COP of heat pump is given as follows

[tex]COP=\dfrac{T_h}{T_H-T_L}[/tex]  ,T in Kelvin.

[tex] COP=\dfrac{313}{313-261}[/tex]

c)COP=6.01

In heat pump

Heat rejection at high temperature=heat absorb at  low temperature+work in put

[tex]Q_R=Q_A+W_{in}[/tex]

Given that [tex]Q_A=15[/tex]KW

We know that  [tex]COP=\dfrac{Q_R}{W_{in}}[/tex]

[tex]COP=\dfrac{Q_R}{Q_R-Q_A}[/tex]

[tex]6.01=\dfrac{Q_R}{Q_R-15}[/tex]

d)[tex]Q_R=17.99 KW[/tex]

A mass of 7 kg undergoes a process during which there is heat transler frorn the mass at a rate of 2 kJ per kg, an elevation decrease of 40 m, and an increase in velocity from 13 m/s to 23 m/s. The specific internal energy decreases by 4 kJ/kg and the acceleration of gravity is constant at 9.7 m/s2. Determine the work for the process, in k.J

Answers

Answer:44.61 KJ

Explanation:

Let h_1,V_1,Z_1 be the initial specific enthalpy,velocity&elevation of the system

and h_2,V_2,Z_2 be the Final specific enthalpy,velocity&elevation of the system

mass(m)=7kg

Applying Steady Flow Energy Equation

[tex]m\left [ h_1+\frac{v_1^2}{2g}+gZ_1\right ][/tex]+Q=[tex]\left [ h_2+\frac{v_2^2}{2g}+gZ_2\right ][/tex]+W

[tex]h_1-h_2=4 KJ/kg[/tex]

[tex]V_1=13m/s[/tex]

[tex]V_2=23m/s[/tex]

[tex]Z_1-Z_2=40m[/tex]

substituting values

[tex]7\left [ h_1+\frac{13^{2}}{2g}+gZ_1\right ]+7\times2[/tex] = [tex]\left [ h_2+\frac{23^2}{2g}+gZ_2\right ][/tex]+W

W=[tex]7\left [h_1-h_2+\frac{V_1^2-V_2^2}{2000g}+g\frac{\left (Z_1-Z_2 \right )}{1000}\right ][/tex]+Q

W=[tex]7\left [4+\frac{13^2-23^2}{2000g}+g\frac{\left (40 \right )}{1000}[\right ][/tex]+[tex]2\times 7[/tex]

W=44.61KJ

What is the no-slip condition? What causes it?

Answers

The no-slip condition is the viscosity of a fluid.This is most likely brought on by stress or stressful situations.

Answer/Explanation:

The no-slip condition for viscous fluids assumes that at a solid boundary, the fluid will have zero velocity relative to the boundary. Along with a flow when adhesion is stronger than cohesion. ... Basically the molecules of the fluid crash into the molecules of the wall and get stopped.

Air is compressed in an isentropic process from an initial pressure and temperature of P1 = 90 kPa and T1=22°C to a final pressure of P2=900 kPa. Determine: a)- The final temperature of the air. b)-The work done per kg of air during the process.

Answers

Answer:

a) [tex]T_2=569.35 K[/tex]

b)Work done per kg of air=196.84 KJ/Kg

Explanation:

Given: [tex]\gamma =1.4[/tex] for air.

[tex]P_1=90 KPa ,T_=22^\circ C,P_2=900 KPa[/tex]

We know that  

[tex]\dfrac{T_2}{T_1}=\left (\frac{P_2}{P_1}\right )^{\dfrac{{\gamma-1}}{\gamma}}[/tex]

So  [tex]\dfrac{T_2}{295}=\left (\frac{900}{90}\right )^{\dfrac{{1.4-1}}{1.4}}[/tex]

[tex]T_2=569.35 K[/tex]

(a) [tex]T_2=569.35 K[/tex]

(b)Work for adiabatic process

  W=[tex]\frac{P_1V_1-P_2V_2}{\gamma -1}[/tex]

We know that PV=mRT for ideal gas.

 W=[tex]mR\frac{T_1-T_2}{\gamma -1}[/tex]

Now by putting values

work per kg of air=[tex]0.287\times \frac{295-569.35}{1.4 -1}[/tex]

Work w=-196.84 KJ/Kg    (Negative sign indicate work given to input.)

So work done per kg of air=196.84 KJ/Kg

In a horizontal pipeline a 150 mm diameter pipe is connected to a 250 mm diameter pipe. The flow rate in the pipeline is 0.15 m^3/s. Take the connection as a sudden enlargement and determine: (a) The pressure head loss vhen the vater flovs from the large pipe to the smaller pipe (take Cc=0.64) (b) The pressure head loss when vater flovs from the small pipe to the larger pipe (c) The loss of power in both cases

Answers

Answer:

a) [tex]h_L=1.17m[/tex]

b)[tex]h_L=1.52m[/tex]

c)[tex]P_1=1.721 kN[/tex]

  [tex]P_2=2.236 kN[/tex]

Explanation:

velocities of the pipe;

velocity of small dia pipe

[tex]v_{small}=\frac{Q}{A_{small}} =\frac{0.15}{\frac{\pi}{4}\times d^2 }= \frac{0.15}{\frac{\pi}{4}\times 0.15^2 }=8.52m/s[/tex]

velocity of larger dia pipe

[tex]v_{large}=\frac{Q}{A_{large}} =\frac{0.15}{\frac{\pi}{4}\times d^2 }= \frac{0.15}{\frac{\pi}{4}\times 0.25^2 }=3.05m/s[/tex]

a) pressure head loss when water is flowing from large to smaller pipe

  [tex]h_L=(\frac{1}{C_c} -1)^2 \times \frac{v^2}{2g}[/tex]

[tex]h_L=(\frac{1}{0.64} -1)^2 \times \frac{8.52^2}{2\times 9.81} = 1.17m[/tex]

b) pressure head loss when water flow from small pipe to large pipe

[tex]h_L= \frac{v^2}{2g}(1-\frac{A_{small}}{A_{large}} )^2[/tex]

[tex]h_L=\frac{8.52^2}{2\times9.81}(1-\frac{\frac{\pi}{4}\times 0.15^2}{\frac{\pi}{4}\times 0.25^2}} )^2= 1.52 m[/tex]

c) power loss in both cases are

[tex]P_1= \rho g Q h_{L1}= 1000 \times 9.81\times 0.15\times 1.17= 1.721 kN[/tex]

[tex]P_2= \rho g Q h_{L2}= 1000 \times 9.81\times 0.15\times 1.52= 2.236 kN[/tex]

The shear force diagram is always the slope of the bending moment diagram. a)True b)- False

Answers

Answer:

True

Explanation:

Shear force diagram is a diagram which is drawn by calculating the shear force either to the right of the section or to the left of the section .

shear force is also be define as the change of moment w.r.t to distance

                              V=[tex]\frac{\mathrm{d}M }{\mathrm{d} x}[/tex]

where V is shear force and M is bending moment.

from the equation we can clearly say that shear force diagram is slope of bending moment diagram.

The melting point of Pb (lead) is 327°C, is the processing at 20°C hot working or cold working?

Answers

Answer:

Explained

Explanation:

Cold working: It is plastic deformation of material at temperature below   recrystallization temperature. whereas hot working is deforming material above the recrystallization temperature.

Given melting point temp of lead is 327° C and lead recrystallizes at about

0.3 to 0.5 times melting temperature which will be higher that 20°C. Hence we can conclude that at 20°C lead will under go cold working only.

Which of the following are not related to a materials structure? (Mark all that apply) a)- Atomic bonding b)- Crystal structure c)- Atomic number d)- Microstructure

Answers

The answer is c) atomic number

Describe the design experiments method for product and process optimization

Answers

Answer:

Design of Experiment also known as DoE is a systematic methodology to understand how any process or parameters of any product affects the response variables like physical properties or performance of any product, etc. It serves the purpose of making the job easier.

It is technique to generate valuable information required with minimum experimentation with the use of these:

Statistical methodologyMathematical analysis to predict the output within the limits of experiments at any point.Experimental extremities

Process Optimization:

It includes the following:

Product prototype should be used in designingOptimization of significant value adding activitiesDetection and minimization of errorStrong built concept for the designTesting and validation of the process for further improvement in efficiencyTime, quality, environmental, manufacting and overall cost, safety and operational constraints should be duly noted.

An object of mass 521 kg, initially having a velocity of 90 m/s, decelerates to a final velocity of 14 m/s. What is the change in kinetic energy of the object, in kJ?

Answers

Answer:2058.992KJ

Explanation:

Given data

Mass of object[tex]\left ( m\right )[/tex]=521kg

initial velocity[tex]\left ( v_0\right )[/tex]=90m/s

Final velocity[tex]\left ( v\right )[/tex]=14m/s

kinetic energy of body is given by=[tex]\frac{1}{2}[/tex][tex]m[/tex][tex]v^{2}[/tex]

change in kinectic energy is given by substracting  final kinetic energy from initial kinetic energy of body.

Change in kinetic energy=[tex]\frac{1}{2}\times m[/tex][tex]\left ( V_0^{2}-V^2\right )[/tex]

Change in kinetic energy=[tex]\frac{1}{2}\times521[/tex][tex]\left ( 90^{2}-14^2\right )[/tex]

Change in kinetic energy=2058.992KJ

What does STP and NTP stands for in temperature measurement?

Answers

STP stands for standard temperature pressure and NTP stands for normal temperature pressure

Other Questions
Solve for n 6(n 8) = 4(12 5n) + 14nshow work please! If the domain of the square root function f(x) is x A box of mass ????=21.0 kgm=21.0 kg is pulled up a ramp that is inclined at an angle ????=21.0=21.0 angle with respect to the horizontal. The coefficient of kinetic friction between the box and the ramp is ????k=0.285k=0.285 , and the rope pulling the box is parallel to the ramp. If the box accelerates up the ramp at a rate of ????=2.09 m/s2a=2.09 m/s2 , calculate the tension ????TFT in the rope. Use ????=9.81 m/s2g=9.81 m/s2 for the acceleration due to gravity. Why were abrahams People called the isrealities Let f : A --> B where (8 points) f = {(a, 1), (b, 3), (c, 5), (d, 2)) a. What is the co-domain of f 3. Let A= {a, b,c,d) and B= {1, 2, 3, 4, 5, 6). b. What is the range of f? c. Is f-1 a function Explain . d. Can there exist a bijection between A and B? Explain A 2.3kg box, starting from rest, is pushed up a ramp by a 10 N force parallel to the ramp. The ramp is 2.0 m long and tilted at 17 degrees. The speed of the box at the top of the ramp is 0.80m/s.How much work does the force do on the system?What is the change in the kinetic energy of the system?What is the change in the gravitational potential energy of the system?What is the change in the thermal energy of the system? What was the effect of the change from hand power to machine power in industry? 1. It lead to the development of the automobile and airplane. 2. The Northeast remained the leading industrial region. 3. Business moved out of homes to the factory. Melina's father just died. She was very close to him, and simply cannot face the reality of his death. To those around her, it appears that Melina is not grieving at all. Melina is experiencing _____ grief. Simplify the expression 2(x + 7)(x2 3x 6). I need help with this A space station, in the form of a spoked wheel 120 m in diameter, rotates to provide an artificial gravity of 3.00 m/s for persons who walk around on the inner wall of the outer rim. Find the rate of the wheels rotation in revolutions per minute (rpm) that will produce this effect. An airplane in a wide outside loop can create an apparent zero weight inside the aircraft cabin. What must be the radius of curvature of the flight path for an aircraft moving at 350 km/h to create a condition of weightlessness inside the aircraft? Assume the acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s The unadjusted trial balance at year-end for a company that uses the percent of receivables method to determine its bad debts expense reports the following selected amounts:Accounts receivable $441,000 DebitAllowance for Doubtful Accounts 1,310 DebitNet Sales 2,160,000 CreditAll sales are made on credit.Based on past experience, the company estimates 2.5% of ending accounts receivable will be uncollectible.What adjusting entry should the company make at the end of the current year to record its estimated bad debts expense?a. Debit Bad Debts Expense $11,025; credit Allowance for Doubtful Accounts $11,025.b. Debit Bad Debts Expense $9,715; credit Allowance for Doubtful Accounts $9,715.c. Debit Bad Debts Expense $12,335; credit Allowance for Doubtful Accounts $12,335.d. Debit Bad Debts Expense $5,400; credit Allowance for Doubtful Accounts $5,400.e. Debit Bad Debts Expense $15,400; credit Allowance for Doubtful Accounts $15,400. G-1/6=1/6. Solve for G describe the impact of the early cold war Whats the slope of a line perpendicular to a line through points, E(5,7), F(3,1) Match the following terms with a short description of that term: Consistency, Atomicity, Isolation, Durability, Serializability.a.The data used by one transaction can not be used by another transaction until the first one has completed. b.The schedule for execution in a multiuser environment insures consistent results. c.A transaction takes the database from one consistent state to another. d.Once a transaction is done it can not be lost or undone. e.All statements within a transaction must be successfully completed or completely aborted. In both physical and chemical changes,a. energy can be gained or lost.b. matter is createdc. matter is destroyedd. Both a and brite your answers on the lines below. The melting point of an ionic compound will increase as which of the following increases Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:(x+y) = (x-y) + (2xy)Hint #1: c = a + bHint #2: pick 2 positive integers x and y, where x > y