Answer: 64
Step-by-step explanation:
the absolute value of a positive number is that number , the absolute value of a negative number is that numbers opposite .
The absolute value is a concept in mathematics that signifies the magnitude of a number, disregarding its positive or negative sign. The absolute value of a number refers to its magnitude, regardless of its sign. Thus, the absolute value of 64 is itself, which is 64.
Explanation:The absolute value is a concept in mathematics that signifies the magnitude of a number, disregarding its positive or negative sign. Think of it as a number's distance from zero. Considering your question, the absolute value of 64 is simply 64. This is because 64 is already a positive number, and the absolute value of a positive number is the number itself.
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can someone please tell me the aswer
Answer:
2x-2+3x
Step-by-step explanation:
2x-2+3x
combine like terms (2x + 3x = 5x)
So 2x-2+3x = 5x-2
Question is in the photo. check all that apply. please help ASAP
Answer:
[tex]x-2x-6=8x+12-x-4\\-x-6=7x+8[/tex]
Step-by-step explanation:
Given:
The equation is;
[tex]x-2(x+3)=4(2x+3)-(x+4)[/tex]
Now we need to simplify this equation we get;
Step 1: We need to simplify all the terms which are in brackets we get,
[tex]x-2x-6=8x+12-x-4[/tex]
Step 2: Now we need to simplify all variable term and non variable term we get:
[tex]-x-6=7x+8[/tex]
Answer:
These two equivalent equations Katrina has used
[tex]x - 2x - 6 = 8x + 12 - x - 4\\-x - 6 = 7x + 8\\[/tex]
Step-by-step explanation:
Given :
[tex]x - 2(x + 3) = 4(2x + 3) - (x + 4)\\[/tex]
Applying distributive property that is [tex]A\times (B +C) = A\times B + A\times C[/tex] we get
[tex]x - 2x + 3\times -2 = 4\times 2x + 4\times 3 - x - 4\\[/tex]
[tex]x - 2x - 6 = 8x + 12 - x - 4\\-x - 6 = 7x + 8\\[/tex]
PLEASE AWNSER THIS QUESTION ASAP ;((
Answer:
Yes then no
Step-by-step explanation:
A linear function is of the form y=mx+b, where b and m are constants(not variables). Since the input is the radius, we make that x. The circumference is πd, or 2πr, so if we plug in 2π for m, circumference for y, and 0 for b, this works. The area is πr², which would mean that m would have to be πr. Since r is not a constant, this does not work.
Whenever you sign a lease for an apartment, you typically have to pay a security deposit in case you have caused any wear or tear on the apartment that has to be repaired before it can be re-leased. If no repairs need to be made, you get your entire deposit back. One apartment building has apartments that rent for $500 a month and security deposit of $700. The total cost C (in dollars) it costs to rent the apartment for m months is given by the function C=500m+700. Graph the function and identify its domain and range. Identify the domain and range if a renter only leases an apartment for one year and then moves out and doesn't get the security deposit back.
Answer:
what is the question
Step-by-step explanation:
please solve much appreciated
Answer:
Two equivalent fractions with whole numbers may be 180/150, or 6/5The height of the tree is 39.6 feet.Explanation:
The diagram provides the proportion of the heights to the shadows:
[tex]\frac{x}{33}=\frac{1.8}{1.5}[/tex]From that you are asked (i) to simplify the fraction of the right side to one with whole numbers.
You can do that in two steps by multiplying both numerator and denominator by 10:
[tex]\frac{1.8\times 10}{1.5\times 10}=\frac{180}{150}[/tex]You can simplify that fraction if you divide by the greatest common factor of 180 and 150, which is 30:
[tex]\frac{180/30}{150/30}=\frac{6}{5}[/tex]The second part (ii) asks to find the height of the tree, that is x. To solve for x you can multiply both sides by the denominator of the fraction on the left and then simplify:
[tex]\frac{x}{33}=\frac{6}{5}\\ \\ x=\frac{6\times 33}{5}\\ \\ x=\frac{198}{5}=39.6[/tex]
Thus, the height of the three is 39.6 feet.
Given ∠ABE = 45° and ∠EAB = 63° in ΔABE and∠MNP= 72° and ∠NMP = 63° in ΔMNP. Are the two triangles, ΔABE and ΔMPN similar? If so, by what criterion?
Answer:
Yes ,we can prove the two triangles are similar by angle angle test.
Step-by-step explanation:
Given:
∠ABE = 45°
∠EAB = 63° and
∠MNP= 72°
∠NMP = 63°
To Prove:
ΔABE ~ ΔMPN
Proof:
In a Triangle sum of the angles of a triangle is 180°
In ΔMPN
∴ ∠MNP + ∠NMP + ∠MPN = 180°
Substituting the given values we get,
[tex]72+63+\angle MPN = 180\\135 + \angle MPN = 180\\\angle MPN = 180-135\\\angle MPN = 45[/tex]
∠MPN = 45° ..........................( 1 )
Now,for triangles to be similar
minimum two angles should be congruent i.e AA test.all the three sides should be proportional i.e SSS testIn Δ ABE and Δ MPN
∠ ABE ≅ ∠ MPN = 45° ……….{From ( 1 ) and Given}
∠ EAB ≅ ∠ NMP = 63° ………...{Given}
Δ ABE ~ Δ MPN ….{Angle-Angle test}
..........Proved
What is the equation of the line that is perpendicular to and
has the same y-intercept as the given line?
y=x+1
y= x+5
y = 5x + 1
y= 5x + 5
Angelica was at target and saw that a pair of slippers was $15. She also noticed that there is a 30% off sale on all slippers. What is the cost (sale price) of the slippers after the discount?
The cost of slippers is $10.5 after discount.
Step-by-step explanation:
Given,
Price of slippers = $15
Sale = 30%
Amount of discount = 30% of price of slippers
[tex]Amount\ of\ discount=\frac{30}{100}*15\\Amount\ of\ discount=\frac{450}{100}\\Amount\ of\ discount=\$4.5[/tex]
Sale price = Price of slippers - amount of discount
[tex]Sale\ price=15-4.5\\Sale\ price=\$10.5[/tex]
The cost of slippers is $10.5 after discount.
Keywords: percentage, subtraction
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To find the cost of the slippers after the 30% discount, multiply the original price by 30% and subtract the discount from the original price. The cost of the slippers after the discount is $10.50.
Explanation:To find the cost of the slippers after the 30% discount, first calculate the amount of the discount by multiplying the original price by 30% (or 0.30).
Discount = $15 × 0.30 = $4.50
Next, subtract the discount from the original price to find the sale price:
Sale Price = $15 - $4.50 = $10.50
Therefore, the cost of the slippers after the discount is $10.50.
Will give brainliest plz help
Answer:
[tex]\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1[/tex]
Step-by-step explanation:
Given:
Center of the ellipse is, [tex](h,k)=(-4,-3)[/tex]
Minor axis length is, [tex]2b=6[/tex]
A vertex of the ellipse is at (1, -3)
Now, distance between the center and the vertex is half of the length of the major axis.
Using distance formula for (-4, -3) and (1, -3), we get:
[tex]a=\sqrt{(1+4)^2+(-3+3)^2}=5[/tex]
Therefore, the value of half of major axis is, [tex]a=5[/tex]. Also,
[tex]2b=6\\b=\frac{6}{2}=3[/tex]
Now, equation of an ellipse with center [tex](h,k)[/tex] is given as:
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]
Plug in [tex]h=-4,k=-3,a=5,b=3[/tex] and determine the equation.
[tex]\frac{(x-(-4))^2}{5^2}+\frac{(y-(-3))^2}{3^2}=1\\\\\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1[/tex]
Therefore, the equation of the ellipse is:
[tex]\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1[/tex]
A textbook store sold a combined total 402 of psychology and math textbooks in a week. The number of psychology textbooks sold was two times the number of math textbooks sold. How many textbooks of each type were sold?
Answer:
The number of textbooks of each type were sold is 134 math and 268 psychology books.
Step-by-step explanation:
Given:
Total number of math and psychology textbooks sold in a week is 402.
Now, let the number of math textbooks sold be [tex]x[/tex].
And, the number of psychology textbooks be [tex]2x[/tex].
According to question:
[tex]x+2x=402[/tex]
[tex]3x=402[/tex]
Dividing both sides by 3 we get:
[tex]x=134[/tex]
So, total number of math textbooks were 134 .
And, total number of psychology textbooks were [tex]2x=2\times 134[/tex]
[tex]=268[/tex].
Therefore, the number of textbooks of each type were sold is 134 math and 268 psychology books.
A number is chosen at random from the first 100 positive integers. Find the probability that the number is either even or
a perfect square
3/5
11/20
1/20
Answer:
[tex]\frac{11}{20}[/tex]
Step-by-step explanation:
Total no. of possible outcome= 100 (from 1 to 100)
total no. of favorable outcome= 60 (50 even and 5 odd perfect square)
Hence PROBABILITY=[tex]\\\frac{55}{100}[/tex]
=[tex]\frac{11}{20}[/tex]
Finley's pumpkin had a mass of 6.56.56, point, 5 kilograms (\text{kg})(kg)left parenthesis, start text, k, g, end text, right parenthesis before he carved it. After carving it, the pumpkin had a mass of 3.9\,\text{kg}3.9kg3, point, 9, start text, k, g, end text.
What was the percent decrease in the mass of the pumpkin?
Answer:
There was 40% decrease in the mass of the pumpkin.
Step-by-step explanation:
Given:
Mass of pumpkin before carving = 6.5 kg
Mass of pumpkin after carving = 3.9 kg
Decrease in mass = Mass of pumpkin before carving - Mass of pumpkin after carving = 6.5 kg - 3.9 kg = 2.6 kg
Now to find the percentage decrease in mass we need to divide Decrease in mass with the total mass of pumpkin before carving and then multiply by 100
% Decrease in mass = [tex]\frac{\textrm{Decrese in mass}}{\textrm{Mass of Pumpkin before carving}}\times100 = 40\%[/tex]
Hence, there was 40% decrease in the mass of the pumpkin.
Answer:
40%
Step-by-step explanation:
I had this problem
If D=8 , what is the value of the expression 4+d/2? A.4 B.6 C.8 D.12 E.14
If the question is (4+D)/2 the answer is 6 but if the question is 4+(D/2) the answer is 8. It depends on which way the question is written.
Answer:
the answer is 8
Step-by-step explanation:
If the question is (4+D)/2 the answer is 6 but if the question is 4+(D/2) the answer is 8. It depends on which way the question is written.
make x the subject of the formula.
pls help urgently. I will mark as brainliest
Answer:
see explanation
Step-by-step explanation:
Given
(bx + a)(ax + b) = (ax² + b)b ← distribute parenthesis on both sides
abx² + a²x + b²x + ab = abx² + b² ( subtract abx² from both sides )
a²x + b²x + ab = b² ( subtract ab from both sides )
a²x + b²x = b² - ab ← factor out x from each term on the left side
x(a² + b²) = b² - ab ← divide both sides by (a² + b²)
x = [tex]\frac{b^2-ab}{a^2+b^2}[/tex]
Answer:
x = -b/a
Step-by-step explanation:
(bx + a)(ax + b) = (ax^2 + b)(b) needs to be muliplied out as a first step to solving for x:
abx^2 + b^2 + a^2x + ab = abx^2 + b^2
Notice that abx^2 shows up on both sides of this equation, so we can cancel it out:
b^2 + a^2x + ab = b^2
Also, b^2 shows up on both sides, so we can also cancel the b^2 terms:
a^2x + ab = 0
Dividing both sides by a, we get ax + b = 0
and so ax = -b,
which means that x = -b/a
Patsy has cheerleading practice every fourth day. She wants to be in the school play, but they have practice every sixth day. If both start on September 5th, what would be the next date she has to choose between cheerleading and play practice? Show your work and explain.
Answer:
September 17th will be the first date that she has to choose between cheerleading and play practice.
Step-by-step explanation:
Least Common Multiple for 4 and 6 is 12 that is LCM(4, 6) = 12
12 days after September 5th is September 17th
Patsy would need to choose between cheerleading and play practice on September 29th, as this is the next date when both practices fall on the same day, calculated by finding the least common multiple of the practice schedules.
Explanation:To determine when Patsy has to choose between cheerleading and play practice, we need to find the least common multiple (LCM) of the two practice schedules, since she has cheerleading every fourth day and play practice every sixth day.
First, list the multiples of both 4 and 6 until we find a common one:
Multiples of 4: 4, 8, 12, 16, 20, 24, 28, ...Multiples of 6: 6, 12, 18, 24, 30, ...The lowest common multiple of 4 and 6 is 12, but since our sequence started on September 5th and 12 is not a multiple of both 4 and 6, we need to keep going. Continuing our list, 24 is the next common multiple but still not satisfying both conditions. At 24 days, the cycle would repeat itself, and Patsy would again have both practices on the same day.
If these practices both start on September 5th, to find the next date she has both practices, we add 24 days to September 5th. Because September has 30 days, adding 24 days to September 5th results in September 29th. Hence, Patsy would need to choose between cheerleading and play practice on September 29th.
3x² + 7x - 5 + 2x²
Simplify
Answer:
3x^2 + 7x - 5 + 2x^2
= 5x^2 + 7x - 5 (a=5, b=7, c=-5)
x = (-b+/- √(b^2 - 4ac))/2a
= (-7+/- √(49+100))/10
= (-7+√149)/10, (-7-√149)/10
Hope this helps!
Given O below, if XY and YZ are congruent, what is the measure of chord XY
Answer:
B. 10.2
Step-by-step explanation:
Answer : The value of chord XY is, 10.2 units
Step-by-step explanation :
As we are given that, XY and YZ are congruent.
XY and YZ are congruent by SSA.
The ΔXOY and ΔZOY are congruent triangles.
Side OX = Side OZ (side)
Side OY = Side OY (common side)
∠XOY = ∠ZOY (angle)
That means, in this two sides and one angle of a triangle are equal to another triangle then the triangles are congruent.
So, Side XY = Side YZ
As we are given :
Chord YZ = 10.2
So, Chord YZ = Chord XY = 10.2
Hence, the value of chord XY is, 10.2 units
Simplify: 8x - (14 +4x)
Answer:
4x-14
Step-by-step explanation:
8x-(14+4x)
8x-14-4x
8x-4x-14
4x-14
what is the ratio for the surface areas of the cones shown below, given that they are similar and that the ratio of their radii and altitudes is 5:4?
Answer:
25:16 is the surface area of the cones.
Step-by-step explanation:
Given: The ratio of their radii and altitudes is 5:4.
Area of similar figures are proportional to the squares of their corresponding sides and this ratio is called scale factor.
Let z be the scale factor
∴z= [tex]\frac{5}{4}[/tex]
Now, let x be the surface area of the larger cone
and let y be the surface are of smaller cone.
∴ [tex]z^{2} = \frac{x}{y}[/tex]
next substituting the value of z ,
⇒[tex](\frac{5}{4} )^{2} =\frac{x}{y}[/tex]
∴ [tex]\frac{x}{y} = \frac{25}{16}[/tex]
The ratio for the surface area of cones is 25:16
Answer:
The correct answer is 25:16
Step-by-step explanation:
The graph of a system of equations with the same slope and the same y-intercepts will have no solutions. (1 point)
Answer:
The statement is false
Step-by-step explanation:
we know that
If a system of equations has two equations with the same slope and the same y-intercept, then both equations represent the same line
so
we have a consistent dependent system
The system has has an infinite number of solutions
therefore
The statement is false
Assume that in October of a particular year about 215 billion text messages were sent or received in the US, and the prediction is that in the next month it will be a 13% increase. About how many will be sent or received in November of the same year? Rounded to the nearest tenth of a billion.
Answer:
There will be [tex]243[/tex] billion messages sent or received in November.
Step-by-step explanation:
Given.
Number of text messages sent or received [tex]=215[/tex] billion.
Increment on the very next month [tex]=13\%=\frac{13}{100}=0.13[/tex]
Lets find what is [tex]13\%\ of\ 215[/tex]
⇒[tex]13\%\ of\ 215[/tex]
⇒[tex]0.13\times 215=27.95[/tex]
So we will add this value to our previous months data.
Now
Number of text messages sent in the month of November [tex]=(27.5+215)=242.95[/tex] billion.
Rounding to the nearest tenth the answer will be [tex]243[/tex] billion.
So [tex]243[/tex] billion text messages were sent or received in November.
DeShawn is selling tickets to a play. Adult tickets cost $13 each and student tickets cost $9 each. After one day of sales, DeShawn sold 23 tickets and took in a total of $271. How many student tickets did DeShawn sell?
Answer:
The number of student's tickets sold was 7
Step-by-step explanation:
Let
x ----> number of adult's tickets sold
y ----> number of student's tickets sold
we know that
[tex]x+y=23[/tex] ----> [tex]x=23-y[/tex] ---> equation A
[tex]13x+9y=271[/tex] ----> equation B
solve the system by substitution
substitute equation A in equation B
[tex]13(23-y)+9y=271[/tex]
solve for y
[tex]299-13y+9y=271[/tex]
[tex]13y-9y=299-271[/tex]
[tex]4y=28[/tex]
[tex]y=7[/tex]
therefore
The number of student's tickets sold was 7
Mary borrows $5,000 dollars from her mother at a 3% simple interest rate and pays her $600 in interest after t years.
What is the value of t?
2
3
4
5
Answer:
4
Step-by-step explanation:
The simple interest per year is 3% times $5000 which is 150 dollars.
Now, we have the equation 150x = 600.
We solve and get x = 4
Which of the sets of ordered pairs represents a function? (5 points) A = {(1, −5), (8, −5), (8, 7), (2, 9)} B = {(7, −4), (7, −2), (6, −3), (−9, 5)}
Step-by-step explanation:
For any function,any point in the domain has a unique image in the codomain.
For set [tex]A[/tex]:
[tex]f(8)=-5[/tex] from the point [tex](8,-5)[/tex]
[tex]f(8)=7[/tex] from the point [tex](8,7)[/tex]
For a same point [tex]8[/tex],there are two images.
So,[tex]A[/tex] does not represent a function.
For set [tex]B[/tex]:
[tex]f(7)=-4[/tex] from the point [tex](7,-4)[/tex]
[tex]f(7)=-2[/tex] from the point [tex](7,-2)[/tex]
For a same point [tex]7[/tex],there are two images.
So,[tex]B[/tex] does not represent a function.
Which symbol can be used to correctly compare the two fractions? Use > , < , or =. Enter your answer in the box. 75100 34
75100 > 34
75100 is greater than 34
Answer:
its <
Step-by-step explanation:
Between which two ordered pairs does the graph of f(x) = one-halfx2 + x – 9 cross the negative x-axis?
Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction
(–6, 0) and (–5, 0)
(–4, 0) and (–3, 0)
(–3, 0) and (–2, 0)
(–2, 0) and (–1, 0)
The graph of the quadratic function f(x) = 0.5x² + x - 9 crosses the negative x-axis between the ordered pairs (-7,0) and (-6,0), and between (-2,0) and (-1,0).
Explanation:The graph of the quadratic function f(x) = 0.5x² + x - 9 crosses the negative x-axis at those x-values that make the function equal to zero. To find these, we solve for x in the equation 0.5x² + x - 9 = 0 using the quadratic formula x = -b ± √(b² - 4ac) / 2a.
Here, a = 0.5, b = 1 and c = -9. Substituting these into the formula gives x = -1 ± √(1 + 36) / 1 = -1 ± √(37) / 1. The two possible solutions are approximately -7.06 and +5.06. Therefore, the ranges of x-values crossing the negative x-axis are between the ordered pairs (-7,0) and (-6,0), as well as between (-2,0) and (-1,0).
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The function f(x) = one-halfx2 + x - 9 intersects the negative x-axis between the ordered pairs (-4, 0) and (-3, 0) and also between (-3, 0) and (-2, 0) when solved using the quadratic formula.
Explanation:The question concerned is a quadratic function, specifically, it wants to know where f(x) = one-halfx2 + x – 9 intersects with the negative x-axis. The x-axis is the line where y = 0, so we need to solve the equation 0.5x² + x - 9 = 0 to locate the roots. By applying the quadratic formula, x = [-b ± sqrt(b² - 4ac)] / (2a), we substitute our coefficients into the equation to get: x = [-1 ± sqrt((1)² - 4*0.5*(-9))] / (2*0.5). This will lead to two solutions, x = -2 and x = -3. Hence, the function f(x) = one-halfx2 + x – 9 intersects the negative x-axis between the ordered pairs (-4, 0) and (-3, 0) and also between (-3, 0) and (-2, 0).
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What is the perimeter?
Answer:
total sum is called perimwter
the perimeter will be the outer border, and in this case we have three semi-circles and one square, well, the semi-circles have a diameter of 7, we can just get the circumference of all 3 semi-circles add them and append the 7 ft at the bottom, Check picture below.
[tex]\bf \textit{circumference of a semicircle}\\\\ C=\cfrac{\pi d}{2}~~ \begin{cases} d = diameter\\[-0.5em] \hrulefill\\ d=7 \end{cases}\qquad \implies \stackrel{\textit{circumference of all 3 semi-circles}}{3\left( \cfrac{\pi 7}{2} \right)\implies \cfrac{21\pi }{2}} \\\\\\ \stackrel{\textit{sum of all borders}}{\cfrac{21\pi }{2}~~+~~7}~~\approx ~~32.99+7~~\approx~~ 39.99[/tex]
How to put this promble in standard notation
3.25x10
Answer:
multiply both 3.25 and 10 by 100
or
multiple 3.25 by 10 then multiply by 10
What is the domain of the function f(x)=-4log2(x+3)-6
Enter your answer in the box.
All real numbers greater than
Answer:
-3
Step-by-step explanation:
Given, f(x)=-4log2(x+3)-6
So, for domain of f(x) ,we have to find the domain of log2(x+3) as all other things are just numbers which do not affect the domain.
For domain of f(x), 2(x+3) > 0
Thus, x + 3 > 0
x > -3.
So, all real numbers greater than -3 are in the domain of f(x).
A contractor needs to buy nails to build a house. The nails come in small boxes and large boxes. Each small box has 150 nails and each large box has 400 nails. The contractor bought 3 times as many large boxes as small boxes, which altogether had 2700 nails. Determine the number of small boxes purchased and the number of large boxes purchased.
The contractor bought 2 small boxes and 6 large boxes of nails. This was determined by setting up and solving a system of equations based on the given conditions.
Explanation:To solve the problem of determining the number of small and large boxes of nails purchased by the contractor, we can set up a system of equations based on the information given:
Each small box contains 150 nails.Each large box contains 400 nails.The contractor bought 3 times as many large boxes as small boxes.Altogether, the nails totaled 2700.Let's denote the number of small boxes as S, and the number of large boxes as L. The equations then are:
L = 3S (3 times as many large boxes as small boxes)150S + 400L = 2700 (total number of nails)Substituting the value of L from equation (1) into equation (2):
150S + 400(3S) = 2700
Solving for S:
150S + 1200S = 2700
1350S = 2700
S = 2
Then, substituting S = 2 into the first equation to find L:
L = 3(2) = 6
Therefore, the contractor bought 2 small boxes and 6 large boxes of nails.
The contractor bought 2 small boxes and 6 large boxes, totaling 2700 nails, with each small box containing 150 nails.
Let's denote:
- x as the number of small boxes purchased.
- y as the number of large boxes purchased.
We're given the following information:
1. Each small box contains 150 nails.
2. Each large box contains 400 nails.
3. The total number of nails purchased is 2700.
4. The contractor bought 3 times as many large boxes as small boxes, so y = 3x.
We can set up two equations to represent the given information:
1. Total number of nails equation:
150x + 400y = 2700
2. Relationship between the number of small and large boxes:
y = 3x
Now, let's substitute the value of y from the second equation into the first equation:
150x + 400(3x) = 2700
150x + 1200x = 2700
1350x = 2700
Now, let's solve for x:
[tex]\[ x = \frac{2700}{1350} \][/tex]
x = 2
So, the number of small boxes purchased [tex](\( x \))[/tex] is 2.
Now, let's find the number of large boxes [tex](\( y \))[/tex]:
y = 3x
y = 3(2)
y = 6
So, the number of large boxes purchased [tex](\( y \))[/tex] is 6.
To summarize:
- The contractor purchased 2 small boxes.
- The contractor purchased 6 large boxes.