The _____ along a gene specifies the type of protein that will be produced.
A.order of RNA bases
B.number of DNA bases
C.order of DNA bases
D.number of RNA bases

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Answers

Answer 1
I believe the answer to this is d. 

Related Questions

1. Aqueous solutions of chromium(III) iodide and sodium hydroxide react to give a chromium(III) hydroxide precipitate and aqueous sodium iodide.
2. Aqueous solutions of iron(II) sulfate and barium nitrate react to give a barium sulfate precipitate and aqueous iron(II) nitrate.

Express your answer as a chemical equation. Identify all of the phases in your answer. Enter noreaction if there is no reaction.

Answers

1- The original equation of the reaction is :
CrI3 + NaOH → Cr(OH)3 + NaI 
but this is not a balanced equation so we have to balance it :
-first, we have 3 I atoms on the left side and 1  I atom on the right side 
so to makes the no.of atoms on both sides equal we put 3NaI instead of NaI
CrI3 + NaOH → Cr(OH)3 + 3NaI
- then no.of Na atoms on the left side is 1 and on the right side is 3 so, we put 3NaOH instead of NaOH
CrI3 + 3NaOH → Cr(OH)3 + 3NaI
now we have :
Cr atoms = 1 on both sides
I atoms = 3 on both sides
Na atoms = 3 on both sides
O&H atoms = 3 on both sides
So the final balanced equation of our reaction is:
CrI3(aq) + 3NaOH(aq)  Cr(OH)3(s) + 3NaI(aq)

2 - the chemical equation of the second reaction is :
FeSO4 + Ba(NO3)2 → BaSO4 + Fe(NO3)2
let's see if it is the balanced equation or not?
we have:
no of Fe atom on both sides = 1
no of (SO4) atom on both sides are equal
 no of Ba atom on both sides = 1
no of (NO3) group on both sides= 2 
so this is our balanced equation, so the final equation for this reaction is:
FeSO4(aq) + Ba(NO3)2(aq) BaSO4(s) + Fe(NO3)2(aq)

Final answer:

For reaction 1, the balanced equation is CrI3(aq) + 3NaOH(aq) → Cr(OH)3(s) + 3NaI(aq). For reaction 2, it is FeSO4(aq) + Ba(NO3)2(aq) → BaSO4(s) + Fe(NO3)2(aq). The products Cr(OH)3(s) and BaSO4(s) form precipitates in their reactions.

Explanation:

Based on your questions, we can establish the following balanced chemical equations:

The synthesis of chromium(III) hydroxide from chromium(III) iodide and sodium hydroxide:CrI3(aq) + 3NaOH(aq) → Cr(OH)3(s) + 3NaI(aq).The synthesis of barium sulfate from iron(II) sulfate and barium nitrate:FeSO4(aq) + Ba(NO3)2(aq) → BaSO4(s) + Fe(NO3)2(aq).

This shows the precipitation reactions that can occur between certain metallic ions in solution. The precipitates are the insoluble products - chromium(III) hydroxide and barium sulfate, respectively.

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