the applied force required to push something across a surface as friction increases is what?

To design a horizontal curve for a two-lane road, you can calculate the radius, degree of curvature, and length of the curve using formulas.

To design a horizontal curve, we need to calculate the radius, degree of curvature, and length of the curve. First, we can calculate the radius using the formula: R = (V2) / (15 * f), where R is the radius in feet, V is the design speed in miles per hour, and f is the superelevation. Plugging in the values, we get: R = (702) / (15 * 0.06) = 43,333.33 feet. The degree of curvature can be calculated using the formula: (180 * L) / (π * R), where L is the length of the curve in feet. Since the central angle is given as 40 degrees, the degree of curvature is also 40 degrees. Finally, we can calculate the length of the curve using the formula: L = (π * R * d) / 180, where d is the degree of curvature. Plugging in the values, we get: L = (π * 43,333.33 * 40) / 180 = 9,632.87 feet.

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The direction of motion of the cars after collision will be south of east. This is determined by the conservation of momentum, with the direction being the sum of the momenta of the two cars, taking into account their initial velocity and mass.

This question involves the conservation of momentum, a key concept in physics. Since the two cars stick together after the collision, the direction of their motion is the sum of their momenta, taking into account their mass and initial velocity.

First, convert the speeds from km/h to m/s. The 1500-kg car was travelling at 25 m/s towards the east (90 km/h) and the 3000-kg car was travelling at 16.67 m/s towards the south (60 km/h).

Momentum (p) is mass (m) times velocity (v), so the momentum of the first car is 1500 kg * 25 m/s = 37500 kg*m/s and the second car's momentum is 3000 kg * 16.67 m/s = 50000 kg*m/s. Since they stick together after the collision, the total momentum must remain the same. However, the momentum now has two components, one towards the east and the other towards the south. The magnitude of the resultant velocity is found using Pythagoras' theorem, sqrt[(37500 kg*m/s)^2 + (50000 kg*m/s)^2], and the direction is given by the arctangent of the ratio of the two components. Therefore, the direction of the cars will be south of east.

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The two cars will move together after the collision with a velocity of approximately 13.89 m/s at an angle of 53.12° south of east. This result is derived by applying the principle of conservation of momentum. We found the momentum components in the eastward and southward directions and used them to determine the direction and magnitude of the combined velocity.

This is a classic example of an inelastic collision where two objects stick together after collision. We use the conservation of momentum to find the direction of motion after the collision.

First, let's convert velocities to meters per second (m/s):

1500-kg car: 90 km/h = 25 m/s

3000-kg car: 60 km/h = 16.67 m/s

Next, we calculate the momentum of each car:

Eastward momentum of the 1500-kg car:

1500 kg * 25 m/s = 37500 kg·m/s

Southward momentum of the 3000-kg car:

3000 kg * 16.67 m/s = 50010 kg·m/s

Since the cars stick together after the collision, their combined mass is 1500 kg + 3000 kg = 4500 kg.

To find the velocity components of the combined mass after the collision:

Eastward velocity component:

(37500 kg·m/s) / 4500 kg = 8.33 m/s

Southward velocity component:

(50010 kg·m/s) / 4500 kg = 11.11 m/s

We combine these components to find the magnitude and direction of the final velocity:

Magnitude = √((8.33 m/s)² + (11.11 m/s)²)

or, Magnitude = √(69.39 + 123.4)

Magnitude ≈ 13.89 m/s

Direction: arctan(11.11 / 8.33)

Direction ≈ 53.12° south of east

So, the cars will move at a velocity of approximately 13.89 m/s in a direction that is 53.12 degrees south of east after the collision.

Answer:

A on edge

Explanation:

Answer:

constructive + destructive.

Explanation:

edge 22.

The frequency of light is approximately [tex]\( 1.016 \times 10^{15} \)[/tex] Hz.

To determine the frequency of light that should be used to illuminate the metal in order to produce photoelectrons with a maximum kinetic energy of 2.4 eV, we can use the relationship between energy, frequency, and wavelength in the context of the photoelectric effect.

The energy of a photon (light particle) is given by Planck's equation:

[tex]\[ E = h \cdot f \][/tex]

Where:

- [tex]\( E \)[/tex] is the energy of the photon in joules (J)

-[tex]\( h \)[/tex] is Planck's constant, approximately [tex]\( 6.626 \times 10^{-34} \)[/tex] J·s

- [tex]\( f \)[/tex] is the frequency of the light in hertz (Hz)

We are given the maximum kinetic energy of the photoelectrons as 2.4 eV. To convert this to joules, we use the conversion factor [tex]\( 1 \, \text{eV} = 1.602 \times 10^{-19} \, \text{J} \)[/tex]

[tex]\[ E_{\text{max}} = 2.4 \, \text{eV} \times (1.602 \times 10^{-19} \, \text{J/eV}) \]\\\[ E_{\text{max}} = 3.845 \times 10^{-19} \, \text{J} \][/tex]

Now, since the photoelectrons are emitted only when the wavelength of light is less than 295 nm (nanometers), we can use the speed of light equation to relate frequency and wavelength:

[tex]\[ c = f \cdot \lambda \][/tex]

Where:

- [tex]\( c \)[/tex] is the speed of light, approximately [tex]\( 3.00 \times 10^8 \)[/tex] m/s

- [tex]\( f \)[/tex] is the frequency of the light in hertz (Hz)

- [tex]\( \lambda \)[/tex] is the wavelength of the light in meters (m)

First, we convert the wavelength limit of 295 nm to meters:

[tex]\[ \lambda_{\text{max}} = 295 \, \text{nm} \times (1 \, \text{m} / 10^9 \, \text{nm}) \][/tex]

[tex]\[ \lambda_{\text{max}} = 2.95 \times 10^{-7} \, \text{m} \][/tex]

Now, we can rearrange the speed of light equation to solve for frequency:

[tex]\[ f = \frac{c}{\lambda_{\text{max}}} \][/tex]

[tex]\[ f = \frac{3.00 \times 10^8 \, \text{m/s}}{2.95 \times 10^{-7} \, \text{m}} \][/tex]

[tex]\[ f = 1.016 \times 10^{15} Hz[/tex]

Therefore, the frequency of light that should be used to illuminate the metal and produce photoelectrons with a maximum kinetic energy of 2.4 eV is approximately [tex]\( 1.016 \times 10^{15} \)[/tex] Hz.

Answer:

3805.59 N

Explanation:

Parameters given:

Mass of satellite, m = 3700 kg

Mass of Mars, M = [tex]6.4191 * 10^{23} kg[/tex]

Radius of Mars, r = [tex]3.397 * 10^6[/tex] m

Distance between the satellite and the surface of Mars, D = 1.9 times r

D = [tex]1.9 * 3.397 * 10^6[/tex] = [tex]6.454 * 10^6 m[/tex]

The gravitational force of attraction is given as:

[tex]F = \frac{GMm}{D^2}[/tex]

where G = gravitational constant = [tex]6.67428 * 10^{-11}Nm^2/kg^2[/tex]

[tex]F = \frac{6.67428 * 10^{-11} * 6.4191 * 10^{23} *3700}{(6.454 * 10^6)^2}[/tex]

[tex]F = 3805.59 N[/tex]

The gravitational force of attraction is 3805.59 N

The solenoid must have about 2332 turns

[tex]\texttt{ }[/tex]

Let's recall magnetic field strength from current carrying wire and from center of the solenoid as follows:

[tex]\boxed {B = \mu_o \frac{I}{2 \pi d} } [/tex]

B = magnetic field strength from current carrying wire (T)

μo = permeability of free space = 4π × 10⁻⁷ (Tm/A)

I = current (A)

d = distance (m)

[tex]\texttt{ }[/tex]

[tex]\boxed {B = \mu_o \frac{I N}{L} } [/tex]

B = magnetic field strength at the center of the solenoid (T)

μo = permeability of free space = 4π × 10⁻⁷ (Tm/A)

I = current (A)

N = number of turns

L = length of solenoid (m)

Let's tackle the problem now !

[tex]\texttt{ }[/tex]

Given:

Current = I = 4.3 A

Length = L = 42 cm = 0.42 m

Magnetic field strength = B = 0.030 T

Permeability of free space = μo = 4π × 10⁻⁷ T.m/A

Asked:

Number of turns = N = ?

Solution:

[tex]B = \mu_o \frac{I N}{L}}[/tex]

[tex]\frac{I N}{L} = B \div \mu_o[/tex]

[tex]IN = BL \div \mu_o[/tex]

[tex]N = BL \div (\mu_o I)[/tex]

[tex]N = ( 0.030 \times 0.42 ) \div ( 4 \pi \times 10^{-7} \times 4.3 )[/tex]

[tex]\boxed {N \approx 2332}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Magnetic Field

Given the force acting on the object, the change in its momentum is 4kg.m/s.

To determine the object's change in momentum, we use the Impulse Momentum Theorem:

The impulse applied to a body or matter is equal to the change in its momentum

Impulse = Change in Momentum

[tex]Impulse = F * dt[/tex]

Where F is the force applied and [tex]dt[/tex] is the elapsed time

Hence

[tex]Change \ in \ Momentum = F * dt[/tex]

We substitute our given values into the equation

[tex]Change \ in \ Momentum = 8 kg.m/s^2 * 0.50s\\\\Change \ in \ Momentum =4kg.m/s[/tex]

Therefore, given the force acting on the object, the change in its momentum is 4kg.m/s.

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Transformers, specifically step-up transformers, are crucial for efficiently transmitting electrical energy from power plants to users by increasing the voltage, resulting in reduced current and minimization of Joule losses. High voltage transmission leads to greater efficiency and lower energy losses, making the process both economical and environmentally friendly.

The electrical device that makes it possible to transmit electrical energy efficiently from a power plant to users is the transformer. Transformers play a critical role in adjusting the voltage levels during the transmission of electric power over long distances. When power is generated, a step-up transformer increases the voltage from the power plant, which results in a proportional decrease in current and thus minimizes resistive power losses known as Joule losses. These minimized losses are crucial for maintaining efficiency since identical currents flow through both the load and transmission lines, where power is dissipated usefully in the load but wasted in the resistance of the transmission lines.

The electric potential difference is 7.5 V.

Electric potential difference between two points is defined as the work done in moving unit positive charge between the two points. Electric potential difference can also be defined as the work done W per unit charge q in an electric field.

[tex]\Delta V=\frac{W}{q}[/tex]......(1)

Work done by a force is the product of the force F and the displacement s made in the direction of the force. Assuming that the displacement is parallel to the line of action of the force,

[tex]W=F.s[/tex]......(2)

Rewrite equation (1) using equation (2).

[tex]\Delta V=\frac{Fs}{q}[/tex]......(3)

Substitute the given values of force, displacement and charge in the equation (3).

[tex]\Delta V=\frac{Fs}{q}\\ =\frac{(25*10^-^6N)(15m)}{(50*10^-^6C)} \\ =7.5V[/tex]

The potential difference between the two points is 7.5 V

A centrifuge in a medical laboratory rotates at an angular speed of 3,650 rev/min, the constant angular acceleration of the centrifuge is approximately -1522.71 rad/s².

We can apply the following formula to determine the centrifuge's constant angular acceleration:

Δθ = ω₀t + (1/2)αt²

Δθ = ω₀t + (1/2)αt²

Since the final angular speed is 0, the formula becomes:

Δθ = ω₀t

48 rev * (2π rad/rev) = 381.92 rad/s * t

Simplifying:

96π rad = 381.92 rad/s * t

Dividing both sides by 381.92 rad/s:

t ≈ 0.251 s

Now, we can calculate the angular acceleration (α) using the rearranged formula:

α = (0 - ω₀) / t

α = (0 - 381.92 rad/s) / 0.251 s

α = -1522.71 rad/s²

Thus, the constant angular acceleration of the centrifuge is approximately -1522.71 rad/s².

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Answer:

Option (D)

Explanation:

A cover crop is usually defined as a special type of crop that is cultivated in order to increase the productivity of the soil, rather than focusing on the productivity of the crop. These are very commonly used and it helps in the decreasing amount of weeds, controlling pests and diseases, increasing the fertility of the soil, reduction of soil erosion. It also enhances the biodiversity.

Thus, the main purpose of the cover crop is to prevent the erosion of the topsoil by the agents such as water and wind.

Hence, the correct answer is option (D).

Answer : Electric potential is 600 V

Explanation :

It is given that,

Electric charge, [tex]q=4.5\times 10^{-5}\ C[/tex]

Electric potential energy, [tex]U=0.027\ J[/tex]

The relation between the electric potential and the electric potential energy is given by :

[tex]U=qV[/tex]

[tex]V=\dfrac{U}{q}[/tex]

[tex]V=\dfrac{0.027\ J}{4.5\times 10^{-5}\ C}[/tex]

[tex]V=600\ V[/tex]

Hence, the electric potential is 600 V.

The force on a particle in a magnetic field can be determined using F = qvBsin(\theta). By rearranging the equation to solve for \theta, we can find the angle the particle's velocity makes with the magnetic field for any given force, charge, velocity, and field strength.

The situation described is a classic example of Lorenz force experienced by a charged particle moving through a magnetic field. The force exerted on a charged particle when it moves through a magnetic field can be calculated with the following equation:

F = qvBsin(\theta)

where:

To find the angle \(\theta\), we can rearrange the equation:

\theta = arcsin(\frac{F}{q v B})

For part A:

Using the information given, where F = 4.8 \times 10^{-6} N, q = 0.32 \times 10^{-6} C, v = 18 m/s, and B = 0.95 T, we can calculate the angle.

\(\theta = arcsin(\frac{4.8 \times 10^{-6}}{0.32 \times 10^{-6} \times 18 \times 0.95}) = arcsin(\frac{4.8}{0.32 \times 18 \times 0.95})\)

This returns an angle \(\theta\), which will be in degrees once evaluated using a calculator.

For part B, you would apply the same approach but with F = 3.0 \times 10^{-6} N, to find the different angle.

The coefficient of kinetic friction is obtained by considering the forces acting on the child as they slide. These are the force of gravity (mg sin θ) and the force of kinetic friction (μk mg cos θ). Setting these forces equal gives us an equation that can be solved to find the coefficient of kinetic friction, μk.

To figure out the coefficient of kinetic friction, we need to consider the forces acting on the child as they slide down the playground. There are two key forces to consider, the force caused by gravity which is pulling the child down the slide, and the force of kinetic friction which is trying to slow the child down.

The force of gravity working to pull the child down the slide, or the component of the weight down the slope is given as mg sin θ. Here m is the mass of the child, g is the acceleration due to gravity (9.8 m/s^2), and θ is the angle of the slide. The force of kinetic friction, which opposes the motion, is expressed as μk mg cos θ, where μk is the coefficient of kinetic friction we're trying to find.

Since the child is sliding down the slide with an acceleration of 1.12 m/s², the force due to gravity exceeds the force of friction. Setting up the equation μk mg cos θ = mg sin θ - ma, where a is the acceleration of 1.12 m/s², and solving for μk gives us the coefficient of kinetic friction between the child and the slide.

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Answer:

aluminum...

Explanation:

Explanation:

It is given that,

Mass of the car, m = 525 kg

Applied force, F = 375 N

The coefficient of friction felt by the car is 0.42, [tex]\mu=0.42[/tex]

(a) The weight of the car is given by :

[tex]W=mg[/tex]

[tex]W=525\times 9.8[/tex]

W = 5145 N

(b) The force of friction acts in the opposite direction of motion. It can be calculated as :

[tex]f=\mu mg[/tex]

[tex]f=0.42\times 5145[/tex]

f = 2160.9 N

(c) Here, the force of friction is greater than the applied force. As a result, the ball will not moves. So, the net force acting on this car is 0.

(d) As the net force acting on the car is 0. There will be no acceleration in the car.    

Final answer:

a. The force weight of the car is 5145 N. b. The force friction acting on the car is 216.09 N. c. The net force acting on the car is 158.91 N. d. The acceleration of the car is 0.714 m/s².

Explanation:

a. To calculate the force weight of the car, we can use the formula:

Force weight = mass * acceleration due to gravity

Given that the mass of the car (m) is 525 kg and the acceleration due to gravity (g) is 9.8 m/s², we can substitute these values into the formula:

Force weight = 525 kg * 9.8 m/s² = 5145 N

So, the force weight of the car is 5145 N.

b. To calculate the force friction acting on the car, we can use the formula:

Force friction = coefficient of friction * force weight

Given that the coefficient of friction (µ) is 0.0420 and the force weight is 5145 N, we can substitute these values intothe formula:

Force friction = 0.0420 * 5145 N = 216.09 N

So, the force friction acting on the car is 216.09 N.

c. The net force acting on the car can be calculated by subtracting the force friction from the force applied by the engine:

Net force = force applied - force friction

Given that the force applied by the engine is 375 N and the force friction is 216.09 N, we can substitute these values into the formula:

Net force = 375 N - 216.09 N = 158.91 N

So, the net force acting on the car is 158.91 N.

d. To calculate the acceleration of the car, we can use Newton's second law of motion:

Force = mass * acceleration

Given that the force applied by the engine is 375 N and the mass of the car is 525 kg, we can substitute these values into the formula:

375 N = 525 kg * acceleration

Solving for acceleration:

acceleration = 375 N / 525 kg = 0.714 m/s²

So, the acceleration of the car is 0.714 m/s².

The period of a wave is found to be 50 seconds. What is the frequency of the wave?

0.02 Hz