The average monthly amount Isabella has spent on gasoline since 1990 is shown in the table. Use the data in the table to complete the statements. Let x be the number of years since 1990. The year 2005 corresponds to an x-value of . The function that best models the data, with numerical values rounded to the nearest hundredth, is f(x) = x + 22.08. Models have their limitations. For which year would this model not make sense to use?

Answers

Answer 1
Answer 1: 15
Answer 2: 11.55
Answer 3: 1985


Related Questions

Use inductive reasoning to find the next term in the sequence 1, 2, 4, 7, 11, 16… what is the next term?
a. 18
b. 19
c. 22
d. 26

Answers

Hello,

[tex]u_1=1\\ u_2=2\\ u_3=4\\ u_4=7\\ u_5=11\\ u_6=16\\ u_2-u_1=2-1=1\\ u_3-u_2=4-2=2\\ u_4-u_3=7-4=3\\ u_5-u_4=11-7=4\\ u_6-u_5=16-11=5\\ ... u_n-u_{n-1}=n-1\\ \boxed{u_n=u_{n-1}+n-1}\\ u_7=u_6+(7-1)=16+6=22\\ [/tex]

Answer C

PLZ HELP!!!! 43 POINTS!!!!! Koji is installing a rectangular window in an office building. The window is 8 2/3 ft wide and 5 3/4 ft high. The formula for the area of a rectangle is A=bh. What is the area of the window?

Answers

49 and 10/12
  multiply 8 and 2/3 by 5 and 3/4!

WILL GIVE A BRAINLEST!!!!!!!!!!

Which is true about the statements

The graph of f(x) has a vertex of (–4, 6).
The graph of f(x) is horizontally stretched.
The graph of f(x) opens upward.
The graph of f(x) has a domain of x <=–6.

Answers

the second option


hope this helps<3

Answer: B) The graph of f(x) is horizontally stretched.


Step-by-step explanation: We are given an absolute function [tex]f(x)=-\frac{2}{3} |x+4|-6[/tex].

The standard equation of an absolute function is [tex]f(x)= a|x-h|+k[/tex].

Where (h,k) is the vertex of the absolute function.

If we compare [tex]f(x)=-\frac{2}{3} |x+4|-6[/tex] and [tex]f(x)= a|x-h|+k[/tex], we can see a=[tex]-\frac{2}{3}[/tex], h= -4 and h= -6.

Therefore, vertex of the given function is (-4,-6).Because we have value of a is a negative number so it would open down.An absolute function always have domain " All real numbers".

Therefore, first, third and fourth options are incorrect.

So, the second option would only be applicable.

B) The graph of f(x) is horizontally stretched.

PLEASE HELP ASAP! THANKS!




RANDOM ANSWERS WILL BE MODERATED!

Answers

Asked and answered elsewhere.
https://brainly.com/question/9006279

Find the volume of the prism. 1,728 cu. in. 864 cu. in. 288 cu. in.

Answers

1728 inces

you multiply 12 by 12 by 12

Volume of cube is given by the formula :

[tex] Volume = a * a * a [/tex]

Where a is edge of the cube.

We are given edge of cube as 12 inches.

Plugging the value of edge in given formula:

[tex] Volume = 12 * 12 * 12 [/tex]

Volume = 1728 cubic inches.

Answer : Volume of cube is 1728 cubic inches.


Volume of cube is given by the formula :

[tex] Volume = a * a * a [/tex]

Where a is edge of the cube.

We are given edge of cube as 12 inches.

Plugging the value of edge in given formula:

[tex] Volume = 12 * 12 * 12 [/tex]

Volume = 1728 cubic inches.

Answer : Volume of cube is 1728 cubic inches.


So I need to add 2 teaspoons of conditioner for every 10 gallons of water in a tank. I have a 2.5-gallon tank, how much conditioner do I need to put in the tank? Please help I don't want my fish to die.

Answers

So, you need 2 teaspoons of conditioner for every 10 gallons of water. 

This is really just a simple equation:

2/10=x/2.5

Now, there are several ways you can really solve this, but i'll give you the basic version. You know for 10 gallons, you need 2 teaspoons. Divide, this means for every 1 teaspoon, you need 5 gallons. This here is a simplification. 

Now, in order to get from 5 gallons per 1 teaspoon to 2.5 gallons per X teaspoons, you have to figure out the differences in what you know. 2.5 is half of 5, and what you do to one side of an equation, you do to the other. The first half was divided by half, so divide the second half (1 teaspoon) by half as well. 

1/2=.5, AKA half.

2 teaspoons of conditioner for every 10 gallons
For 2.5 gallons, you need .5 teaspoons, or 2.46 ml.

Your answer is .5 teaspoons, basically HALF of a teaspoon.

~Hope this helps!



0.5 teaspoon of conditioner to 2.5 gallon of tank.

What is ratio?

Comparing two amounts of the same units and determining the ratio tells us how much of one quantity is in the other. Two categories can be used to categorise ratios. Part to whole ratio is one, and part to part ratio is the other. The part-to-part ratio shows the relationship between two separate entities or groupings.

Given

So, you need 2 teaspoons of conditioner for every 10 gallons of water.

2/10=x/2.5

Now, know for 10 gallons, you need 2 teaspoons. Divide, this means for every 1 teaspoon, you need 5 gallons. This here is a simplification.

x =0.5

2 teaspoons of conditioner for every 10 gallons

For 2.5 gallons, you need .5 teaspoons.

Hence 0.5 teaspoon of conditioner to 2.5 gallon of tank.

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Is it possible to place 158 books on three shelves so that the first shelf has 8 less books than the second and 5 more books than the third shelf?

Answers

Let
x-----------------> books in the first shelf
y-----------------> books in the second shelf
z-----------------> books in the third shelf
we know that
x+y+z=158-------------> equation (1)
x=y-8---------> y=x+8 ------->  equation (2)
x=z+5--------> z=x-5  --------> equation (3)

 substitute (2) and (3) in (1)
x+(x+8)+(x-5)=158--------> 3x=155----------> x=51.7


the number of books in the first shelf (x=51.7) is not a whole number
therefore

the answer is
Is not possible to place the amount of 158 books in the amounts indicated in the problem



Yes, it is possible to place 158 books on three shelves with the given conditions. The distribution will be 49 books on the first shelf, 57 books on the second, and 52 books on the third shelf.

To solve this problem, let's use algebra. Let x represent the number of books on the second shelf. According to the given conditions, the first shelf would have x - 8 books, and the third shelf would have x - 5. The total number of books on all three shelves is 158, and the equation representing the total number of books is:

x + (x - 8) + (x - 5) = 158

Combining like terms:

3x - 13 = 158

Adding 13 on both sides:

3x = 171

Dividing both sides by 3:

x = 57

Therefore, the second shelf has 57 books, the first shelf has 49 books (57 - 8), and the third shelf has 52 books (57 - 5).

It is possible to place the books on the three shelves as required, and the answer is yes, with the distribution being 49 books on the first shelf, 57 books on the second, and 52 books on the third.

What is the following difference? 11 square root 45 - 4 square root 5

Answers

11√45 - 4√5

= 11√(9 * 5) - 4√5

= (11 · √9 · √5) - 4√5

= (11 · 3 · √5) - 4√5

= (11 * 3)√5 - 4√5

= 33√5 - 4√5

= (33-4)√5

= 29√5

Answer:

[tex]29\sqrt{5}.[/tex]

Step-by-step explanation:

The difference is

[tex]11\sqrt{45}-4\sqrt{5}[/tex]

To simplify let's try to covert [tex]\sqrt{45}[/tex] in terms of [tex]\sqrt{5}[/tex]:

45 = 9*5, then [tex]\sqrt{45} = \sqrt{9*5} = \sqrt{9}\sqrt{5} = 3\sqrt{5}[/tex]. So,

[tex]11\sqrt{45}-4\sqrt{5} = 11(3\sqrt{5})-4\sqrt{5} = 33\sqrt{5} -4\sqrt{5} = 29\sqrt{5}.[/tex]

Find the zeros K(x) = -x²+ 2x + 15 EXPLAIN EVERY STEP!

Answers

Take out - 1
k(x) = -1(x^2 - 2x - 15) Now factor what's inside the brackets. The numbers you pick must add to - 2 and multiply to -15. 
When you multiply to -15 you should note that one of the numbers is plus and the other is minus.
(x -  )(x +  ) is the way it looks.
They differ by 2 and the "largest" one is minus. That means your answer is -5 and +3
k(x) = - (x - 5)(x + 3)
Now for the zeros.
x - 5 can be a zero
x - 5 = 0
x = 5

x + 3 = 0
x = - 3
 

3 times the complement of an angle is 30 more than the supplement of the original angle. What is the measure of the angle? 15° 30° 60° 90°

Answers

1. By definition, the sum of the Suplementary angles is 180° and the sum of the Complementary angles is 90°. Keeping this on mind, you have:

 90-x (The complement of the angle)
 180-x (The sumplement of the angle)

 "x" is the angle that you want to calculate.

 2. Then, you have:

 3(90-x)+30=180-x
 (270-3x)+30=180-x
 300-3x=180-x
 300-180=-x+3x
 120=2x
 120/2=x
 x=60°

 What is the measure of the angle? 

 The answer is: The measure of the angle is 60°.

When you add two rational numbers, each number can be written as a?

Answers

When you add two rational numbers, each number can be written as a  

✔ fraction .

Step-by-step explanation:

When you add two rational numbers, each number can be written as a fraction.

What is a rational number?

A Rational number can be defined as any number which can be represented in the form of p/q where q ≠ 0. It can be made by dividing an integer by an integer.

For the given situation,

The sum of two rational numbers is rational.

The closure property of addition of rational number states that if we add two rational number, then the sum of these two rational number will also be a rational number.

Adding two rationals is the same as adding two such fractions, which will result in another fraction of this same form since integers are closed under addition and multiplication.

Hence we can conclude that when you add two rational numbers, each number can be written as a fraction.

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write the polynomial in standard form. Then name the polynomial based on it's degree and number of terms

6 - 12x + 13x^2 - 4x^2
@kewlgeek555

Answers

9x^2-12x+6; trinomial and quadratic

I can explain if needed

Bernadette is at the turtle tank. There are 32 green (g) and yellow (y) turtles in the tank. There are 3 times as many yellow turtles as green turtles. Using the guess and check method, determine how many yellow turtles are in the tank.

Answers

Answer:

24

Step-by-step explanation:

The turtle tank has 24 yellow turtles, computed using the guess and check method.

What is the guess and check method?

The guess and check method is the process of guessing a solution to the given conditions that will be satisfying all the conditions.

How to solve the question?

In the question, we are informed that Bernadette is at the turtle tank, which has 32 green and yellow turtles in the tank. We are also informed that there are 3 times as many yellow turtles as green turtles.

Assuming the number of green turtles to be g, and the number of yellow turtles to be y, we can write the equation g + y = 32, as the total number of turtles is given to be 32.

Now, we are told that the number of yellow turtles is 3 times the number of yellow turtles.

Thus, we can say that y = 3g.

Substituting this in the equation, we get g + 3g = 32, or, 4g = 32.

We are asked to solve this equation by the guess and check method.

If we guess g to be 7, the equation is not satisfied as we get 28 = 32.

If we guess g to be 9, the equation is not satisfied as we get 36 = 32.

If we guess g to be 8, the equation is satisfied as we get 32 = 32.

Thus, the correct value for g is 8.

Thus, y = 3g = 3*8 = 24.

Thus, the turtle tank has 24 yellow turtles, computed using the guess and check method.

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Need help on questions 1, and 2 please

Answers

1. See the attached graph.

2. All translations are considered rigid motion. The locations of points on the figure do not change relative to one another.

what's the sum or difference
1. 4x^10-9x^10

2. 3y^5-10y^5

@kewlgeek555

Answers

To find the sum of these problems, we need to simplify by combining like terms.

1. -5x^10
Since both terms have an exponent of 5, they can both be subtracted.

2. -7y^5
Same reason as above.

Hope this helps!

PLEASE HELP
7.05a

1. Find the first six terms of the sequence.
a1 = -6, an = 4 • an-1


A) 0, 4, -24, -20, -16, -12
B) -24, -96, -384, -1536, -6144, -24,576
C) -6, -24, -20, -16, -12, -8
D) -6, -24, -96, -384, -1536, -6144

2. Find an equation for the nth term of the arithmetic sequence.
-15, -6, 3, 12, ...

A) an = -15 + 9(n + 1)
B) an = -15 x 9(n - 1)
C) an = -15 + 9(n + 2)
D) an = -15 + 9(n - 1)

3. Find an equation for the nth term of the arithmetic sequence.
a14 = -33, a15 = 9

A) an = -579 + 42(n + 1)
B) an = -579 + 42(n - 1)
C) an = -579 - 42(n + 1)
D) an = -579 - 42(n - 1)

4. Determine whether the sequence converges or diverges. If it converges, give the limit.
48, 8, four divided by three , two divided by nine , ...

A) Converges; two hundred and eighty eight divided by five
B) Converges; 0
C) Diverges
D) Converges; -12432

5. Find an equation for the nth term of the sequence.
-3, -12, -48, -192, ...

A) an = 4 • -3n + 1
B) an = -3 • 4n - 1
C) an = -3 • 4n
D) an = 4 • -3n

6. Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively.

A) an = 7 • (-3)n + 1
B) an = 7 • 3n - 1
C) an = 7 • (-3)n - 1
D) an = 7 • 3n

7. Write the sum using summation notation, assuming the suggested pattern continues.
5 - 15 + 45 - 135 + ...

A) summation of five times three to the power of the quantity n plus one from n equals zero to infinity
B) summation of five times negative three to the power of n from n equals zero to infinity
C) summation of five times three to the power of n from n equals zero to infinity
D) summation of five times negative three to the power of the quantity n plus one from n equals zero to infinity

8. Write the sum using summation notation, assuming the suggested pattern continues.
-9 - 3 + 3 + 9 + ... + 81

A) summation of the quantity negative nine plus six n from n equals zero to fifteen
B) summation of negative fifty four times n from n equals zero to fifteen
C) summation of negative fifty four times n from n equals zero to infinity
D) summation of the quantity negative nine plus six n from n equals zero to infinity

9. Write the sum using summation notation, assuming the suggested pattern continues.
64 + 81 + 100 + 121 + ... + n2 + ...

A) summation of n squared from n equals eight to infinity
B) summation of n minus one squared from n equals eight to infinity
C) summation of n squared from n equals nine to infinity
D) summation of n plus one squared from n equals eight to infinity

10. Find the sum of the arithmetic sequence.
17, 19, 21, 23, ..., 35

A) 260
B) 179
C) 37
D) 160

11. Find the sum of the geometric sequence.
1, one divided by two, one divided by four, one divided by eight, one divided by sixteen

A) one divided by twelve
B) 93
C) negative one divided by forty eight
D) thirty one divided by sixteen

12. An auditorium has 30 rows with 10 seats in the first row, 12 in the second row, 14 in the third row, and so forth. How many seats are in the auditorium?

A) 1170
B) 735
C) 1230
D) 600

13. Use mathematical induction to prove the statement is true for all positive integers n.

The integer n3 + 2n is divisible by 3 for every positive integer n.




14. A certain species of tree grows an average of 3.8 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 5 meters tall.

Answers

These are 14 questions and 14 answers.

Since this exceeds the limit and I had to delete the last questions and I copied all the answers to a file that is attache. See the attachment with all the answers.

1) Question 1. Find the first six terms of the sequence: a1 = -6, an = 4 • an-1


Answer: option D) -6, -24, -96, -384, -1536, -6144

Explanation:

A(1) = - 6

A(n) = 4 * A(n-1)

n                 A(n)

1                 - 6

2                  4 * (-6) = - 24

3                  4 * (-24) = - 96

4                  4 * (-96) = - 384

5                  4 * (-384) = - 1536

6                  4 * ( -1536) = -6144

So, the first six terms are: -6, - 24, - 96, - 384, - 1536, - 6144.

2) Question 2: Find an equation for the nth term of the arithmetic sequence.
-15, -6, 3, 12, ...

Answer: option D) - 15 + 9(n - 1)

Explanation:

1. find the difference between the consecutive terms:

-6 - (-15) = -6 + 15 = 9
3 - (-6) = 3 + 6 = 9
12 - 3 = 9

So, the difference is 9, and you can find any term adding 9 to the previous.

2. Since the first term is - 15, you have:

First term, A1 = - 15 + 9(0) = - 15
Second term, A2 =  - 15 + 9(1) = - 6
Third term, A3 = -15 + 9(2) = - 15 + 18 = 3
Fourth term, A4 = - 15 + 9(3) = - 15 + 27 = 12

3. So, the general formula is An = - 15 + 9 (n - 1), which is the option D)

3) Question 3. Find an equation for the nth term of the arithmetic sequence A14 = - 33, A15 = 9.

Answer: option B) An = - 579 + 42(n - 1)

Explanation:

1) Find the difference: 9 - (-33) = 9 + 33 = 42

2) A15 = A1 + 42 * (15 - 1)

=> A1 = A15 - 42(15 - 1)

A1 = A15 - 42(14)

A1 = 9 - 588 = - 579

Therefore, the formula es An = - 579 + 42(n - 1)

4) Question 4. Determine whether the sequence converges or diverges. If it converges, give the limit.

48, 8, 4/3, 2/9, ...


Answer: the sequence converges to 288/5

Explanation:

That is a geometric sequence.

The ratio is 1/6: 8/48 = 1/6; (4/3) / 8 = 4/24 = 1/6; (2/9)/(4/3) = 6/36 = 1/6.

The convergence criterium is that if |ratio| < 1 then the series, this is the sum of all the terms, converge to: A1 / (1 - ratio)

Then the limit 48 / (1 - 1/6) = 48 / (5/6) = 48*6 / 5 = 288/5

5) Question 5. Find an equation for the nth term of the sequence.

-3, -12, - 48, -192

Answer: - 3 * (4)^(n-1)

Explanation: clearly any term (from the second) is the previous term multiplied by 4.

The first term is  -3
The second term is -3(4) = - 12
The third term is -3(4)(4)= - 48
The fourth term is - 3 (4)(4)(4) = - 192

So, the general formula for the nth term is -3 * 4^ (n-1)

6) Question 6. Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively.

Answer: An =7 * (-3)^(n-1)

Explanation:

1) The fith term is the second term * (ratio)^3: A5 = A3 * (r)^3

2)  A5 = 567, A2 = - 21 => r^3 = A5 / A2 = - 567 / 21 = - 27

=> r = ∛(-27) = - 3

3) So the first term is A1 = A2 / r = -21 / -3 = 7

4) The general formula is

An =7 * (-3)^(n-1)

7) Question 7. Write the sum using summation notation, assuming the suggested pattern continues.

5 - 15 + 45 - 135 + ...

Answer: option B) summation of five times negative three to the power of n from n equals zero to infinity

Explanation:

5 = 5
-15 = 5 (-3)
45 = 5(-3)^2
-135 = 5(-3)^3

=> 5 + 5(-3) + 5(-3)^2 + 5(-3)^3+....

Using the summation notation that is:


∑ (5)(-3)^n
n=0

Which means summation of five times negative three to the power of n from n equals zero to infinity

8) Question 8. Write the sum using summation notation, assuming the suggested pattern continues.
-9 - 3 + 3 + 9 + ... + 81

Answer: option A) summation of the quantity negative nine plus six n from n equals zero to fifteen

Explanation:

Find the difference:

-3 - (-9) = - 3 + 9 = 6
3 - (-3) = 3 + 3 = 6
9 - 3 = 6

First term: - 9
Second term: - 9 + 6(1)
Third term: - 9 + 6(2)

nth term = - 9 + (n -1)

Summation = [- 9] + [- 9 + 6(1) + [-9 + 6(2)] + [-9 + 6(3) ]+ .... [-9 + 6(15) ]

Using summation notation:

15
∑ [-9 + 6n]
n=0

which means summation of the quantity negative nine plus six n from n equals zero to fifteen.


9) Question 9. Write the sum using summation notation, assuming the suggested pattern continues.


64 + 81 + 100 + 121 + ... + n2 + ...

Answer: A) summation of n squared from n equals eight to infinity

Explanation:

64 = 8^2

81 = 9^2

100 = 10^2

121 = 11^2

n^2


=>


∑ n^2

n=8


which means summation of n squared from n equals eight to infinity

10) Question 10. Find the sum of the arithmetic sequence.
17, 19, 21, 23, ..., 35


Answer: 260


Explanation:

The difference is 2:

The sum is: 17 + 19 + 21 + 23 + 25 + 27 + 29 + 31 + 33 + 35.

You can use the formula for the sum of an arithmetic sequence:


(A1 + An) * n / 2 = (17 + 35)*10/2 = 260



11) Question 11. Find the sum of the geometric sequence. 

1, 1/2, 1/4, 1/8, 1/16

Answer: option D) 31/16


Explanation:


You can either sum the 5 terms or use the formula for the partial sum of a geometric sequence.

The formula is: Sum = A * ( 1 - r^n) / (1 - r)


Here A = 1, r = 1/2, and n = 5 => Sum = 1 * (1 - (1/2)^5 ) / (1 - 1/2) =


= [ 1 - 1/32] / [1/2] = [31/32] / [1/2] = 31 / 16

help me, please............

Answers

The second choice. Because X cannot be in denominator.
B, or the second one, which is
-3/x

Solve.

x² + 4x + 4 = 18


​ A x=−4±3√ ​2

​ B x=2±3√ ​2

​ C x=4±9√ ​2

D x=−2±3√2

Answers

Solve.

x² + 4x + 4 = 18


​ A x=−4±3√ ​2

​ B x=2±3√ ​2

​ C x=4±9√ ​2

D x=−2±3√2



[tex]x^2 + 4x + 4 = 18 \\ \\ x^2+4x+4-18= 0 \\ \\ x^2+4x-14=0 \\ \\ x_1_y_2= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \qquad a= 1\qquad b= 4\qquad c= -14 \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{4^2-4(1)(-14)} }{2(1)} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{16-(-56)} }{2} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{72} }{2} \\ \\ \\ x_1= \dfrac{-4+ \sqrt{72} }{2} \qquad\qquad x_2= \dfrac{-4+ \sqrt{72} }{2}\\ \\ \\ x_1= \dfrac{-4+ \sqrt{2^3*3^2} }{2} \qquad\qquad x_2= \dfrac{-4- \sqrt{2^3*3^2} }{2}[/tex]

[tex] x_1= \dfrac{-4+2*3 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 2*3\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4+6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 6\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4}{2} + \dfrac{6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4}{2}- \dfrac{ 6\sqrt{2} }{2} \\ \\ \\ x_1= -2 + 3 \sqrt{2} \qquad\qquad\quad x_2= -2- 3\sqrt{2} \\ \\ \\ \boxed{x= -2\pm 3\sqrt{2} } \to D) [/tex]

This was the correct answer, I even provided proof from my own test. Hope this helps!

He first three terms of a geometric sequence are as follows. 10 , 30 , 90 find the next two terms of this sequence.+

Answers

10*3=30
30*3=90
90*3=270
270*3=810

or

10*3^1=30
10*3^2=90
10*3^3=270
10*3^4=810

the next two terms of this sequence are 270 and 810.

The next two terms of the given geometric sequence is 810.

The first three terms of a geometric sequence are 10, 30, 90.

What is a geometric sequence?

A geometric sequence is a special type of sequence where the ratio of every two successive terms is a constant. This ratio is known as a common ratio of the geometric sequence.

The formula to find nth term of the geometric sequence is [tex]a_n = ar^{n - 1[/tex].

Where, a = first term of the sequence, r= common ratio and n = number of terms.

Here, the common ratio is 30/10 = 90/30 = 3

Now, [tex]a_4=10\times 3^{4-1}[/tex]

= 10 × 3³

= 270

[tex]a_5=10\times 3^{5-1}[/tex]

= 810

Therefore, the next two terms of the given geometric sequence is 810.

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please help me and explain it

Answers

[tex]m= \cfrac{y_2-y_1}{x_2-x_1} \\ \\ y_2-y_1=m(x_2-x_1) \\ \\ \boxed{y_2=m(x_2-x_1)+y_1 }[/tex]

The masses of four planets in a solar system outside the Milky Way are given below. Mass of Planet A: 5.97 × 10 24 kg; Mass of Planet B: 3.30 × 10 23 kg; Mass of Planet C: 1.89 × 10 27 kg; Mass of Planet D: 4.87 × 10 24 kg What is the order of these planets from least to greatest mass?
Planet C; Planet B; Planet D; Planet A Planet C; Planet A; Planet D; Planet B Planet B; Planet D; Planet A; Planet C Planet A; Planet D; Planet B; Planet C\

Answers

For this case, the first thing we will do is write a table:
 Mass of Planet A: 5.97 × 10 24 kg;
 Mass of Planet B: 3.30 × 10 23 kg;
 Mass of Planet C: 1.89 × 10 27 kg;
 Mass of Planet D: 4.87 × 10 24 kg
 We observe that according to the scientific notation we have:
 3.30 × 10 23 kg <4.87 × 10 24 kg <5.97 × 10 24 kg <1.89 × 10 27 kg
 Therefore the order of the planets from lowest to highest mass is:
 Planet B, Planet D, Planet A, Planet C
 Answer: 
 Planet B, Planet D, Planet A, Planet C

The order of the planets from least to greatest mass is Planet B, Planet D, Planet A, Planet C.

To determine the order of the planets from least to greatest mass, we need to compare the given masses:

Mass of Planet A: 5.97 × 1024 kg

Mass of Planet B: 3.30 × 1023 kg

Mass of Planet C: 1.89 × 1027 kg

Mass of Planet D: 4.87 × 1024 kg

These masses help us rank the planets:

Planet B: 3.30 × 1023 kg

Planet D: 4.87 × 1024 kg

Planet A: 5.97 × 1024 kg

Planet C: 1.89 × 1027 kg

Therefore, the order of the planets from least to greatest mass is Planet B, Planet D, Planet A, Planet C.

Find two consecutive whole numbers that 101 lies between

Answers

We can see here that the two consecutive whole numbers that 101 lies between are 100 and 102.

To find two consecutive whole numbers that 101 lies between, we can start by finding the smaller whole number.

Since 101 is greater than 100, the smaller whole number would be 100.

To find the larger whole number, we can add 2 to the smaller whole number:

100 + 2 = 102

Thus, we see here that 100 and 102 are the two consecutive numbers where 101 lies between. As we see above, we see the process of finding the numbers.

Consecutive numbers are numbers that follow each other in order without any gaps and have a difference of 1 between each number. In other words, they are numbers that come one after another in a sequence.

As cars passed a checkpoint, the following speeds were clocked and recorded. Speed (mph): 55 62 61 54 68 72 59 61 70
What are the minimum, first quartile, median, third quartile, and maximum of the data set? Show your work.

Answers

We have ---- >  55, 62, 61, 54, 68, 72, 59 ,61, 70  

In total 9 numbers

step 1

order  the numbers  from smallest to largest

54,55,59,61,61,62,68,70,72

1) What is the minimum of the data set ?

The lowest number is the minimum------------ > 54

2) What is the median of the data set ?

Find the number that is in the middle  

54,55,59,61,61,62,68,70,72

The middle number is 61. That is the median.  

Find the middle of each half. Since these numbers are between 2 numbers, you average the numbers (add then divide by 2).  

55+59=114/2=57 This is the first quartile.  

68+70=138/2=69 This is the third quartile

3) What is the first quartile of the data set ?

the answer is 57

4) What is the third quartile of the data set ?

the answer is 69

5) What is the maximum of the data set ?

The highest is the maximum------------ > 72

Answer:

Minimum = 54

Maximum = 72

Median = 61

First quartile = 57

Third quartile = 69

Step-by-step explanation:

Data : 55 62 61 54 68 72 59 61 70

Arrange the data is ascending order

54 , 55, 59, 61,61 ,62 , 68,70 ,72

So, minimum = 54

Maximum = 72

Median is the mid value .

There are nine observations.

So, 5th observation is the median

So, Median = 61

First quartile = It is the median of data of the left side data of the median .

Left side data : 54 , 55, 59, 61

There are four observations

Median = [tex]\frac{\frac{n}{2}th+(\frac{n}{2}+1)th}{2}[/tex]

Median = [tex]\frac{\frac{4}{2}th+(\frac{4}{2}+1)th}{2}[/tex]

Median = [tex]\frac{2th+3rd}{2}[/tex]

Median = [tex]\frac{55+59}{2}[/tex]

Median = [tex]57[/tex]

First quartile = 57

Third quartile = It is the median of data of the right side data of the median .

Right side data : 62 , 68,70 ,72

There are four observations

Median = [tex]\frac{\frac{n}{2}th+(\frac{n}{2}+1)th}{2}[/tex]

Median = [tex]\frac{\frac{4}{2}th+(\frac{4}{2}+1)th}{2}[/tex]

Median = [tex]\frac{2th+3rd}{2}[/tex]

Median = [tex]\frac{68+70}{2}[/tex]

Median = [tex]69[/tex]

Third quartile = 69

Hence minimum is 54 , maximum is 72 ,median is 61 , first quartile is 57 and third quartile is 69

22.6 is an outlier for which of the following sets of data?
1. 22.6, 21.5, 23.7, 22.6, 28.9, 22.6, 20.9

2. 2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9

3. 20.5, 20.8, 21.6, 22.6, 23.7, 24.5, 25.1

4. 13.6, 31.7, 25.8, 22.6, 18.9, 21.6, 30.5

Answers

22.6 is an outlier for the second data set. The reason for this is that 22.6 is nowhere near the rest of the data points. Outliers are numbers that are either a lot bigger or a lot smaller than the rest of the other numbers in the set. In this case, 22.6 is a lot bigger.

Step-by-step explanation:  B

I need more math help, the!

Cement truck A can pour 200 cubic ft of concrete in 20 minutes. It only takes truck B 15 minutes to do the same job. If they both work together,how long will it take them to pour the 200 cubic feet?

I need help setting up the problem and solving it, thank you!

Answers

Track A takes 20 minutes
Track B takes 15 minutes
In 1 minute track be will do a fraction of 1/20, while track B will do 1/15
Both tracks in a minute = 1/20+1/15
                                      = 35/300
Therefore the two tracks will take 300/35 minutes to fill the 200 cubic feet
That is 300/35
           = 8.57  minutes
           ≈ 9 minutes

the distance light travels in one second (one light-second) is about 1.86 x 10^5 miles. Saturn is about 475 light-seconds from the sun. About how many miles from the sun is saturn?

Answers

the distance light travels in one second (one light second ) - 1.86 x 10^5 miles
Saturn is 475 light seconds away from the sun. Using this information we are asked to find the distance saturn is away from the sun.
1 light second - 1.86 x 10^5 miles
Therefore 475 light seconds -1.86 x 10^5 miles/light second * 475 light seconds 
                                             = 8.83 x 10^7 miles
Saturn is 8.83 x 10^7 miles away from the sun

Answer:

Step-by-step explanation:

Given that the distance light travels in one light second about

[tex]1.86(10^5) miles[/tex]

Distance of Saturn from Sun = Time taken for travel x speed

Here speed = [tex]1.86 x 10^5[/tex]

Time taken = 475 light seconds

Hence distance = [tex]1.86 x 10^5x475\\=883.5x10^5\\=8.835x10^7[/tex] miles

Which equation demonstrates the distributive property?
A) 3 (2 + 8) = 3 (8 + 2)
B) 3 (2 + 8) = 3 × 2 + 3 × 8
C) (3 × 2) × 8 = 3 × (2 × 8)
D) 3 × (2 × 8) = 3 × (8 × 2)

Answers

The distributive property takes a number outside the parentheses and multiplies it by every term inside the parentheses.

The answer is:
B) 3(2+8) = 3x2 + 3x8

Hope this helps! :)

Let ​f(x)=x2+14x+48​. What are the zeros of the function? Enter your answers in the boxes.

Answers

Remember that to find the zeroes of a quadratic expression of the form [tex]a x^{2} +bx+c[/tex] we could either factor it or use the quadratic formula. When [tex]a=1[/tex], like in our case, is often way easier and faster factor the expression than using the quadratic formula. The only thing we need to do to factor the expression is find tow number whose product is 48 and its sum is 14; those numbers are 6 and 8. [tex](6)(8)=48[/tex] and [tex]6+8=14[/tex]. Now we can factor our quadratic like follows:
[tex] x^{2} +14x+48=(x+6)(x+8)[/tex]
Since we are trying to find the zeroes of the function, we are going to set each one of our factored binomial equal to zero and solve for x:
[tex]x+6=0[/tex]
[tex]x=-6[/tex]
and
[tex]x+8=0[/tex]
[tex]x=-8[/tex]

We can conclude that the zeroes of the function [tex]f(x)= x^{2} +14x+48[/tex] are [tex]x=-6[/tex] and [tex]x=-8[/tex].

Answer:x= -6 and -8

Step-by-step explanation: I took the test

James has $32 and earns $10 per week for his allowance. What is the initial value for the scenario described?
A.10
B.32
C.42
D.320

Answers

Your answer should be B.

This answer is confirmed!

(4) Check my work please?

Answers

You have the correct x and y values. Nice work.

x/3 = 3/4
x*4 = 3*3
4x = 9
x = 9/4

AC = AD+DC
AC = 4+x
AC = 4+9/4
AC = 16/4 + 9/4
AC = 25/4

AB^2 + BC^2 = AC^2
5^2 + y^2 = (25/4)^2
25 + y^2 = 625/16
y^2 = 625/16 - 25
y^2 = 625/16 - 400/16
y^2 = 225/16
y = sqrt(225/16)
y = 15/4
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