Write the equilibrium-constant, kp, expression for the reaction a(g)+4b(l)<--------->3c(g)+d(g)
Answer:
[tex]K_{p} =\frac{(P_{c} )^{3}(P_{d} ) }{(P_{a}) }[/tex]
Explanation:
The equilibrium constant is expressed as the relationship between the molar concentration of reagents and products. The expression of a generic reaction is:
aA + bB <--------> cC + dD
[tex]K_{p}=\frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b}}[/tex]
The numerator is the product of the concentrations of the products and the denominator is the product of the reagents. Each term in the equation is raised to a power whose value is that of the stoichiometric coefficient in the balanced equation.
When it comes to gas mixtures, it is sometimes more appropriate to describe the composition in terms of partial pressures. So in this case we will have:
[tex]K_{p} =\frac{(P_{c} )^{3}(P_{d} ) }{(P_{a})(P_{b}) ^{4} }[/tex]
As the concentration and partial pressure of pure liquids and solids can be considered as 1, the final equation will be:
[tex]K_{p} =\frac{(P_{c}) ^{3}(P_{d} ) }{(P_{a}) } [/tex]
Braddy connected the lose wire to the battery and created an electromagnet. He picked up 45 thumb tacks with his electromagnet, though his goal was to pick up 50 thumb tacks. What could Braddy do to increase the strength of his electromagnet and pick up more thumbtacks?
A) Use fewer coils of wire.
B) Use a screw instead of a nail.
C) Use two batteries instead of one.
D) Replace the nail with a piece of steel.
Braddy could use two batteries instead of one. One way he could increase the strength of his magnet is to increase the current and add a second battery. He could also add more coils of wire, not use fewer.
what makes a nucleus stable
87 g of oxygen gas would occupy how many liters of volume at stp
What is the approximate total number of atoms in a 1.0 mole of lithium?
Answer:
6.0 × 10^23
Explanation:
Big brain mode
An element has three naturally occurring isotopes. Use the information below to calculate the weighted average atomic mass of the element, showing both the setup and the final answer for the calculation.
Isotope
Atomic Mass
Percent Abundance
X 1.01 u 99.984%
Y 2.01 u 0.014%
Z 3.02 u 0.002%
What mass due to waters of crystallization is present in a 3.38 g sample of FeSO4 •7H2O?
The mass due to water of crystallization present in a 3.38 g sample of FeSO4 •7H2O is 1.53 g
What is water of crystallization?The water of crystallization is the moles of water present in one molecule of a salt which forms part of the crystal lattice.
For the given salt:
molar mass of salt FeSO4 •7H2O = 278 g/mol
mass of water on 1 mole FeSO4 •7H2O = 7 × 18 = 126 g
Mass due to waters of crystallization present in a 3.38 g sample of FeSO4 •7H2O = 3.38 × 126/278
Mass of water of crystallization = 1.53 g
Therefore, the mass due to water of crystallization present in a 3.38 g sample of FeSO4 •7H2O is 1.53 g.
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Ga2O3(s) + 3SOCl2(l) --> 2GaCl3(s) +3SO2
In a certain reaction, 71.8 g of Ga2O3 is reacted with 110.8 g SOCl2.The GaCl3 produced is collected and its mass founded to be 97.66 g.
What is the theoretical yield of GaCl3?
I'm a really stuck in this. I kind of suck in chemistry, please help me. I would really appreciate it.
I have to write one to two paragraphs about : What is the relationship between the atomic numbers and ionic radii of the elements in group 1?
And
What is the relationship between atomic numbers and first ionization energies?
These Are The Elements in group 1 of the periodic table:
lithium
sodium
potassium
rubidium
cesium
The equilibrium constant k for the synthesis of ammonia is 6.8x105 at 298 k. what will k be for the reaction at 375 k?
The value of K for the reaction at 375 k is : 326
Given data :
Initial temperature ( T1 ) = 298 k
rate constant ( k1 ) = 6.8 * 10⁵
Final temperature ( T2 ) = 375 k
Determine the value of K2applying the relationship below
Log ( K₂ / K₁ ) = ΔH / 2.303 * R * ( T₂-T₁ / T₂T₁ ) ----- ( 1 )
equation ( 1 ) becomes
Log K₂ - log (6.8 * 10⁵ ) = - 7100940 / 213967725
Log K₂ - ( 5 + log 6.8 ) = - 3.318
therefore Log K₂ = 2.5145
K₂ = 10^2.5145
= 326
Hence we can conclude that The value of K for the reaction at 375 k is : 326
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Attached below is the complete question
The equilibrium constant K for the synthesis of ammonia changes with temperature, and to determine K at 375 K, the Van't Hoff equation should be used, which requires the standard enthalpy change of the reaction, ΔH°. Without ΔH°, the exact value of K at 375 K cannot be determined.
Explanation:The equilibrium constant K for the synthesis of ammonia will vary with temperature due to the inherent properties of the reaction and the effect of temperature on reaction dynamics. In thermodynamics, the Van't Hoff equation relates the change in the equilibrium constant with temperature, which is described as:
ln(K2/K1) = -ΔH°/R * (1/T2 - 1/T1)
where:
K1 and K2 are the equilibrium constants at temperatures T1 and T2, respectively,ΔH° is the standard enthalpy change of the reaction,R is the universal gas constant, andT1 and T2 are the initial and final temperatures in Kelvin.To determine K at 375 K, one would need the value of ΔH° for the reaction. In absence of this information, the question cannot be fully answered. However, generally a rise in temperature for an exothermic reaction, like the synthesis of ammonia, results in a lower equilibrium constant due to Le Chatelier's Principle.
You mix sugar in water and stir until it's completely dissolved. in this system, the water is the ________, the sugar is the ________, and the end result is a ________. solute; solution; solvent solvent; solution; solute solution; solvent; solute solvent; solute; solution solute; solvent; solution
Answer: water is the solvet, sugar is the solute and the the end result is a solution.
Explanation:
Binary Solution is a homogeneous mixture of two components called as solute and solvent.
Solute is the component which is present in smaller proportion and is solid for solid in liquid solution and solvent is the component which is present in larger proportion and is liquid for solid in liquid solution.
Concentrated solution is one in which there is more amount of solid.
Dilute solution is one in which there is more amount of liquid.
Thus as sugar is lesser in amount , it is the solute. Water is preset in larger amount, thus it is the solvent and the end result is the solution.
10,300 milliliters is the same as: cm3 and L
Answer : The 10300 milliliter in [tex]cm^3[/tex] and L are, [tex]10300 cm^3[/tex] and 10.3 L respectively.
Explanation :
The conversion used from milliliters to centimeter cube is:
[tex]1ml=1cm^3[/tex]
As we are given the volume 10300 ml. Now we have to determine the volume in centimeter cube.
As, [tex]1ml=1cm^3[/tex]
So, [tex]10300ml=\frac{10300ml}{1ml}\times 1cm^3=10300cm^3[/tex]
The volume in centimeter cube is, [tex]10300cm^3[/tex]
The conversion used from milliliters to liter is:
1 ml = 0.001 L
As we are given the volume 10300 ml. Now we have to determine the volume in liter.
As, 1 ml volume = 0.001 L
So, 10300 ml volume = [tex]\frac{10300ml}{1ml}\times 0.001L=10.3L[/tex]
The volume in liter is, 10.3 L
Answer:
The 10300 milliliter in and L are, and 10.3 L respectively.
Explanation:
For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4? 4 9 10 16 32
Answer: The number of sub-levels the for the energy level n = 4 are 4.
Explanation:
The number of sub-levels in an energy level is determined from the azimuthal quantum number.
Principle Quantum Number: This quantum number describes the size of the orbital. It is represented by n where n = 1,2,3,4....
Azimuthal Quantum Number: This quantum number describes the shape of the orbital and also determines the sub-levels in an energy level. It is represented by the symbol 'l'. The value of 'l' ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...
For n = 4, the value of l = 0(s), 1(p), 2(d), 3(f) and these are the number of sub-levels.
Hence, the number of sublevels the for the energy level n = 4 are 4.
In an experiment, an unknown gas effuses at one-half the speed of oxygen gas, which has a molar mass of 32 g/mol. which might be the unknown gas?
PLEASE HELP!!
1. Which of these is the balanced equation for this reaction?
A. V2O5 + HCl ? VOCl3 + H2O
B. V2O5 + HCl ? 2VOCl3 + 3H2O
C. V2O5 + 3HCl ? 2VOCl3 + H2O
D. V2O5 + 6HCl ? 2VOCl3 + 3H2O
2. __N2 + __O2 + __H2O ? __HNO3
What coefficient values will balance the reaction?
A. 2,5,2,4
B. 2,2,2,2
C. 2,2,1,2
D. 1,3,1,2
3.The chemical formula of a compound can tell you -
A. the proportions of elements in the compound.
B. the three-dimensional structure of the compound.
C. the type and arrangement of bonds in the compound.
D. the properties of the elements in the compound.
4.The reaction equation below shows the formation of aluminum oxide. Which set of coefficients balances the equation? Al + O2 ?Al2O3
A. 1,1,1
B. 2,3,5
C. 2,4,5
D. 4,3,2
5.Which of the following is the balanced equation for this process?
A.2NH4NO3? 2N2 + O2 + 4H2O
B.NH4NO3? N2 + 3O2 + H2O
C.2NH4NO3? N2 + O2 + 3H2O
D.2NH4NO3? N2 + 3O2 + 2H2O
How many carbon atoms are in 15.6 kg of acetone? acetone is ch3coch3. the density of acetone is 1.30 g/ml?
Which of the following can be measured in amps with an ammeter
Why are graphs used to understand an objects motion?
An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a circuit that "clicks" in response to current. The faster the current, the more clicks per minute. In this experiment, the number of clicks in one minute is recorded for each color of light shining on the photocell. To change the color of light, a different color of cellophane is placed over the same flashlight and the flashlight is then located a specific distance from the photocell.
In the above experiment, which factor is the independent variable?
A)the number of clicks
B)the color of the light
C)the original source of the light
D)the photocell
Use the periodic table to answer this question.
Sodium reacts with chlorine gas to form sodium chloride. 2Na + Cl2 → 2NaCl
What mass of chlorine gas will react with 92.0 g of sodium?
246 g Cl2
298 g Cl2
142 g Cl2
63 g Cl2
Which of the following is NOT a characteristic of a strong acid and a strong base?
Has a [H+] higher than water
Completely dissociates in water
Has a pH at the extreme end of the scale
Is corrosive to most metals
What was the original element formed moments after the Big Bang? What then created higher order elements?
Hydrogen was the first element formed right after the Big Bang, followed by helium and a small amount of lithium during a period known as Big Bang nucleosynthesis. The heavier elements were created in the cores of stars or during supernovae much later in the universe's history. The CMB is evidence of the universe's early state when neutral hydrogen atoms first formed.
Explanation:The original element formed moments after the Big Bang was hydrogen. After that, the processes that occurred in the early universe allowed for the fusion of hydrogen nuclei into helium and a small amount of lithium. This period of nucleosynthesis occurred within a few hundred seconds of the Big Bang. Heavier elements were created much later in the cores of stars and during supernova explosions.
During the first few minutes after the Big Bang, conditions were ripe for nuclear fusion due to the extremely high temperatures. Protons and neutrons combined to form deuterium (a stable isotope of hydrogen), which then fused into helium. Only about 5% of the current universe's ordinary matter was created during this brief period of Big Bang nucleosynthesis.
As the universe cooled and expanded, fusion became less viable and only the fusion within stars continued the process of creating heavier elements. The Cosmic Microwave Background (CMB) radiation that we observe today is a remnant from the time when the universe cooled enough for neutral hydrogen atoms to form, making the universe transparent to radiation again.
When will the net enthalpy of formation of a solution (δhsolution) be endothermic?
Which are examples of dynamic equilibrium? Check all that apply.
A cooking pot left under a dripping faucet eventually fills with water and overflows.
A person's bank account balance remains constant because income and expenses are equal.
When a small amount of sugar is added to pure water, the sugar dissolves completely.
When humidity is high, the rate at which water evaporates from the surface of a puddle is the same as the rate at which water vapor condenses from the air, so the puddle's size does not change.
Sodium moves between many different compounds during chemical reactions on Earth, but the total amount of sodium on Earth is constant.
B, D. and E are correct
The proton pump _____. see concept 36.2 (page 786) the proton pump _____. see concept 36.2 (page 786) uses the energy stored in atp to produce a hydrogen ion gradient across membranes. uses the energy of a proton gradient to generate atp is a passive process operates by osmosis releases kinetic energy
The periodic law describes trends seeing across which of the following?
Periods within the periodic table
Radio activity within the periodic table
Elements with the same number of protons
The top half of periodic table
Which is not a hydrogenous sediment?
manganese nodules
calcium carbonates
evaporites
calcareous ooze
my answer is the letter D. calcareous ooze
Because calcareous ooze is a Biogenous sediment not a hydrogenous sediment
What are charged atoms of elements that have an unequal number of protons and electrons?
(3) consider a the titration of 1.0 m sulfurous acid (h2so3, ka1 = 1.5e-2, ka2 = 1.0e-7) with 2.0 m naoh. what is the ph at the equivalence point of the titration?
The pH at the equivalence point of the titration of 1.0 M sulfurous acid (H2SO3) with 2.0 M NaOH is 7.08. The pH is slightly basic due to the hydrolysis of the resulting sulfite ion in water, which forms OH- ions.
Explanation:The titration of 1.0 M
sulfurous acid
(H2SO3) with 2.0 M NaOH is a process in which a strong base (NaOH) neutralizes a weak acid (H2SO3). The result at equivalence point is not a neutral solution (pH 7); instead, it is slightly basic because the sulfite ion (SO3^2-) produced from the titration processes hydrolyzes water to produce hydroxide ions (OH-) and render the solution basic.
From the given Ka values (Ka1 = 1.5e-2 and Ka2 = 1.0e-7), we find that the second ionization can be ignored due to its low extent. When 1 mol of H2SO3 is neutralized by 1 mol of NaOH, a solution containing 1 M of SO3^2- is formed. This anion will react with water to generate hydroxide ions. SO3^2- + H2O ↔ HSO3^- + OH-, for which the Kb can be calculated as Kw/Ka1= [1.0e-14]/[1.5e-2] = 6.7x10^-13.
By solving the equilibrium expression Kb = [HSO3^-][OH-]/[SO3^2-], considering the initial concentration of SO3^2- as 1 M and the formation of equal amounts of HSO3^- and OH-, we find [OH-] = √(Kb)= 8.2x10^-7. Finally, using the relationship pOH = -log[OH-] and pH = 14 - pOH, we find that the pH at the equivalence point is 14 + log{8.2x10^-7} = 7.08.
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The pH at the equivalence point of the titration of 1.0 M sulfurous acid (H₂SO₃) with 2.0 M sodium hydroxide (NaOH) is 7.00. The second dissociation constant of H₂SO₃ and the concentrations of HSO₃⁻ formed at the equivalence point.
The pH at the equivalence point of a titration involving 1.0 M sulfurous acid (H₂SO₃) with 2.0 M sodium hydroxide (NaOH), we need to follow these steps:
Identify the acid and base reactions: Sulfurous acid (H₂SO₃) has two dissociation constants (Ka1 = 1.5 × 10⁻² and Ka2 = 1.0 × 10⁻⁷), which means it is a diprotic acid undergoing two ionization steps: H₂SO₃ ⇌ H⁺ + HSO₃⁻ and HSO₃⁻ ⇌ H⁺ + SO₃²⁻.Calculate the moles of H₂SO₃ and NaOH: Given 1.0 M H₂SO₃ and 2.0 M NaOH, let's assume we use 1 L of H₂SO₃ and 0.5 L of NaOH to reach the equivalence point, meaning we have 1 mol H₂SO₃ neutralized by 1 mol NaOH.Determine the species present at equivalence point: At the first equivalence point, the solution mainly contains HSO₃⁻ as the product with a concentration of approximately 0.5 M due to the reaction H₂SO₃ + 2NaOH → NA₂SO₃ + 2H₂O.Calculate the pH: To find the pH, use the remaining concentration of HSO₃⁻ and the second dissociation constant (Ka2 = 1.0 × 10⁻⁷). Applying the Henderson-Hasselbalch equation: pH = pKa2 + log([HSO₃⁻]/[H₂SO₄]). Since [HSO₃⁻] ≈ 0.5 M and [H₂SO₄] ≈ 0, the contribution of HSO₃⁻ will dominate, simplifying the pH calculation to: pH = -log(1.0 × 10⁻⁷) = 7.00.What are the properties of the aluminum in the can