Answer:
The Range Rule of Thumb says that the range is about four times the standard deviation. So, if you need to calculate it, you need to divide range (Maximum - Minimum) with 4, S=[tex]\frac{R}{4}[/tex].
Step-by-step explanation:
R=1490 - 904
S = 586 / 4 = 149.5
If you compare the exact standard desviation (149.5 cm) with the estimated (146.5 cm), it is a difference of 3 cm, is not neccesary round the result.
Hope my answer has been useful.
Answer:
x_bar = 1197 cm^3 , s.d_e = 146.5 cm^3
Outside the 15 cm^3 tolerance. Not a good estimation.
Step-by-step explanation:
Given:
- Lowest value of brain volume L = 904 cm^3
- Highest value of brain volume H = 1490 cm^3
- Exact standard deviation s.d_a = 174.7 cm^3
Find:
Use the range rule of thumb to estimate the standard deviation s and compare the result to the exact standard deviation of 174.7 cm^3 assuming the estimate is accurate if it is within 15 cm^3.
Solution:
- The rule of thumb states that the max and min limits are +/- 2 standard deviations about the mean x_bar. Hence, we will set up two equations.
L = x_bar - 2*s.d_e
H = x_bar + 2*s.d_e
Where, s.d_e is the estimated standard deviation.
- Solve the two equations simultaneously and you get the following:
x_bar = 1197 cm^3 , s.d_e = 146.5 cm^3
- The exact standard deviation is s.d_a = 174.7 cm^3
So, the estimates differs by:
s.d_a - s.d_e = 174.7 - 146.5 = 28.2 cm^3
Hence, its outside the tolerance of 15 cm^3. Not a good approximation.
Which graph represents the function f(x) = –x^2 + 5?
Answer:
See below.
Step-by-step explanation:
This will be a parabola with axis of symmetry x = 0 and will open downwards.
The vertex will be at the point (0 , 5). The graph will intersect the x axis at
(-√5, 0) and (√5, 0).
Answer:
its a
Step-by-step explanation:
10. Sketch the graph of -5x^2- 16xy +7y^2-198 0. Show the steps used in rotating the axes
Find a power series representation for the function. (Give your power series representation centered at x = 0.)f(x) = x3x2 + 1f(x) = ∞n = 0 Determine the interval of convergence. (Enter your answer using interval notation.)
I suppose you mean
[tex]f(x)=\dfrac{x^3}{x^2+1}[/tex]
Recall that for [tex]|x|<1[/tex], we have
[tex]\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n[/tex]
Then
[tex]\dfrac1{1+x^2}=\dfrac1{1-(-x^2)}=\displaystyle\sum_{n=0}^\infty(-x^2)^n=\sum_{n=0}^\infty(-1)^nx^{2n}[/tex]
which is valid for [tex]|-x^2|=|x|^2<1[/tex], or more simply [tex]|x|<1[/tex].
Finally,
[tex]f(x)=\displaystyle\frac{x^3}{x^2+1}=\sum_{n=0}^\infty(-1)^nx^{2n+3}[/tex]
Consider the integral 8 (x2+1) dx 0 (a) Estimate the area under the curve using a left-hand sum with n = 4. 250 Is this sum an overestimate or an underestimate of the true value? overestimate underestimate (b) Estimate the area under the curve using a right-hand sum with n = 4. 248
Answer:
(a) 120 square units (underestimate)
(b) 248 square units
Step-by-step explanation:
(a) left sum
See the attachment for a diagram of the areas being summed (in orange). This is the sum of the first 4 table values for f(x), each multiplied by 2 (the width of the rectangle). Quite clearly, the curve is above the rectangle for the entire interval, so the rectangle area underestimates the area under the curve.
left sum = 2(1 + 5 + 17 + 37) = 2(60) = 120 . . . . square units
(b) right sum
The right sum is the sum of the last 4 table values for f(x), each multiplied by 2 (the width of the rectangle). This sum is ...
right sum = 2(5 +17 + 37 +65) = 2(124) = 248 . . . . square units
You obtain a loan of $7500 at 16.5% compounded monthly. If you make $300 payments monthly, what is the term of the loan? Find the size of the concluding payment if: a. the last full payment is increased to pay off the loan b. the last smaller payment is made one month after the last full payment.
Answer:
last installment is $540
Step-by-step explanation:
principal amount (p) = $7500
rate (r) = 16.5 %
installment = $300
to find out
full payment is increased to pay off the loan and the last smaller payment is made one month after the last full payment
solution
we know monthly installment is $300 so amount will be paid i.e.
amount = $300×12×N ..............1
here N is no of installment
and we know amount formula i.e.
amount = principal ( 1+r/100)^N
put amount value and principal rate
300×12×N = 7500 ( 1+16.5/100)^N
(3600 ×N ) / 7500 = 1.165^N
0.48N = 1.165^N
by the graphical we will get N = 3.65
so 3.65 year
so as that put N in equation 1 we get
amount = $300×12× 3.65
amount = $13140
we can say there are 43 installment so remaining money is $13140 - ($300 × 43 installment )
i.e. = $240 and last installment will be $300 + $240 = $540
so last installment is $540
Audrey Graco plans to conduct book signings in several cities to promote her new novel. She wishes to visit Knoxville, Chattanooga, Chapel Hill, Charlotte, Raleigh, and Richmond. How many different ways can she visit each of these cities and return to her starting point in Wilmington? O A. 720 O B. 30 O C. 29 O D. 120 Click to select vour answer
Audrey can visit the six cities in which she plans to conduct book signings and return to her starting point in 720 different ways. This is because of the mathematical principle of permutations.
Explanation:Audrey's problem deals with permutations because the order of the places she visits matters. In general, the number of ways to arrange 'n' items (in Audrey's case, 'n' cities) in a specific order is given by 'n things taken n at a time' which is mathematically represented as n! (n factorial). In this case, Audrey is visiting 6 cities (Knoxville, Chattanooga, Chapel Hill, Charlotte, Raleigh, and Richmond), and then returning to her original city, Wilmington. So, the number of ways she can visit these cities can be represented as 6!, which equals 720.
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help me please i’m so far behind and i’m trying to finish before summer ends im freaking out
Answer:
The equation 2.5x -10.5 = 64(0.5^x) is true when x=5
Step-by-step explanation:
we need to solve the equation 2.5x -10.5 = 64(0.5^x)
We have to put the given values of x in the functions f(x) and g(x) and find their values
x f(x) = 2.5x -10.5 g(x) = 64(0.5^x)
2 2.5(2)-10.5 = -5.5 64(0.5^2) = 16
3 2.5(3) - 10.5 = -3 64(0.5^3) = 8
4 2.5(4) - 10.5 = -0.5 64(0.5^4) = 4
5 2.5(5) - 10.5 = 2 64(0.5^5) = 2
6 2.5(6) - 10.5 = 4.5 64(0.5^6) = 1
So, we need to solve the equation 2.5x -10.5 = 64(0.5^x)
This holds when x = 5 as shown in the table above.
A solid, homogeneous sphere with a mass of m0, a radius of r0 and a density of ρ0 is placed in a container of water. Initially the sphere floats and the water level is marked on the side of the container. What happens to the water level, when the original sphere is replaced with a new sphere which has different physical parameters? Notation: r means the water level rises in the container, f means falls, s means stays the same. Combination answers like 'f or s' are possible answers in some of the cases. The new sphere has a mass of m = m0 and a density of ρ > ρ0. A: r B: f C: s D: r or s E: f or s The new sphere has a mass of m < m0 and a radius of r = r0. A: r B: f C: s D: r or s E: f or s The new sphere has a mass of m > m0 and a radius of r = r0.
Answer:
A: rB: fA: rStep-by-step explanation:
1. Greater density means the sphere has more mass in the same volume. The volume of water that must be displaced to equal that increased mass must be increased, causing the water level to rise.
__
2. Less mass means less water must be displaced to equal the mass of the new sphere, causing the water level to fall.
__
3. More mass is the same as higher density (see 1). The water level will rise.
Archimedes' principle states that the upward force acting on a body floating or immersed in a fluid is equal to the weight of the displaced fluid
The level of the water in the three situations are as follows;
Situation 1; Falls or stays the same, E: f or s
Situation 2; Falls, B: f
Situation 3, Rises A: r
The reason for the above selection is as follows;
The given details of the arrangements are;
The mass of the solid homogeneous sphere = m₀
The radius of the sphere = r₀
The density of the sphere = ρ₀
The location the sphere is placed = Floating in a container of water
The required parameter;
The provision of an estimate of the water level when the sphere is replaced with a new sphere with different physical parameters
Notation;
r = The water level rises
f = The water level falls
s = The water level stays the same
Situation 1; The mass of the new sphere, m = m₀
The density of the new sphere, ρ > ρ₀
Here, the denser sphere of equal mass = Smaller sphere, r < r₀
if the sphere floats, then the volume of the water displaced is equal to the
mass of the sphere, which is therefore, equal to the volume of the water
displaced by the original sphere
Therefore, the water level remains the same, s
However, if the sphere sinks, then the water displaced is less than the
mass m = m₀, of the sphere and therefore, the level falls, f
Therefore, the correct option is E: f or s
Situation 2: The mass of the new sphere, m < m₀
The radius of the new sphere, r = r₀
Here, we have equal radius and therefore equal volume and lesser density
Given that the volume of the water displaced for a floating body is equal to
the weight of body, and that the mass of the new sphere is less than the
mass of the original sphere, the mass of the water displaced and therefore,
the volume of water displaced is less and therefore, the water level falls
The correct option is therefore B: f falls
Situation 3: The mass of the new sphere, m > m₀, and the radius r = r₀
therefore the new sphere is denser than the original sphere and the
therefore, the mass of the water displaced where the sphere floats is m >
m₀, which is more than the water displaced for the original sphere and the
level of water rises, r, and the correct option is A: r
Therefore;
In situation 1, we have option E: f or s
In situation 2, the correct option is B: f
In situation 3, the correct option is A: r
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8) Use Reduction of order to solve. One solution of homogeneo x2y" +7xy' +5y =x 1 x>0 y1 = X here y1 is a solution of the corresponding homogeneous.
I suspect there's a typo in the question, because [tex]y_1=x[/tex] is *not* a solution to the corresponding homogeneous equation. We have [tex]{y_1}'=1[/tex] and [tex]{y_1}''=0[/tex], so the ODE reduces to
[tex]0+7x+5x=12x\neq0[/tex]
Let [tex]y=x^m[/tex], then [tex]y'=mx^{m-1}[/tex] and [tex]y''=m(m-1)x^{m-2}[/tex], and substituting these into the (homogeneous) ODE gives
[tex]m(m-1)x^m+7mx^m+5x^m=0\implies m(m-1)+7m+5=m^2+6m+5=(m+5)(m+1)=0[/tex]
which then admits the characteristic solutions [tex]y_1=\dfrac1x[/tex] and [tex]y_2=\dfrac1{x^5}[/tex].
Now to find a solution to the non-homogeneous ODE. We look for a solution of the form [tex]y(x)=v(x)y_1(x)[/tex] or [tex]y(x)=v(x)y_2(x)[/tex].
It doesn't matter which one we start with, so let's use the first case. We get derivatives [tex]y'=x^{-1}v'-x^{-2}v[/tex] and [tex]y''=x^{-1}v''-2x^{-2}v'+2x^{-3}v[/tex]. Substituting into the ODE yields
[tex]x^2(x^{-1}v''-2x^{-2}v'+2x^{-3}v)+7x(x^{-1}v'-x^{-2}v)+5x^{-1}v=x[/tex]
[tex]xv''+5v'=x[/tex]
Substitute [tex]w=v'[/tex], so that [tex]w'=v''[/tex] and
[tex]xw'+5w=x[/tex]
which is linear in [tex]w[/tex], and we can condense the left side as the derivative of a product after multiplying both sides by [tex]x^4[/tex]:
[tex]x^5w'+5x^4=x^5\implies(x^5w)'=x^5\implies x^5w=\dfrac{x^6}6+C\implies w=\dfrac x6+\dfrac C{x^5}[/tex]
Integrate to solve for [tex]v[/tex]:
[tex]v=\dfrac{x^2}{12}+\dfrac{C_1}{x^4}+C_2[/tex]
Then multiply both sides by [tex]y_1=\dfrac1x[/tex] to solve for [tex]y[/tex]:
[tex]y=\dfrac x{12}+\dfrac{C_1}{x^5}+\dfrac{C_2}x[/tex]
so we found another fundamental solution [tex]y_3=x[/tex] that satisifes this ODE.
The following data summarizes results from 941 pedestrian deaths that were caused by accidents. If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was intoxicated.
Pedestrian Pedestrian
Intoxicated Not intoxicated
Driver Intoxicated 56 71
Driver Not intoxicated 292 522
Answer:
P=0.3698 or 36.98%
Step-by-step explanation:
Complete the table by adding the totals to each column and row.
Pedestrian Pedestrian
Intoxicated Not intoxicated Totals
Driver Intoxicated 56 71 127
Driver Not intoxicated 292 522 814
Totals 348 593 941
The probability that the pedestrian was intoxicated or the driver was intoxicated is the opposite event of neither of them was intoxicated. The total of cases when neither of them was intoxicated is 593. So the probability is:
P1=593/941=0.6302
The probability of the opposite event is one minus the probability calculated:
P=1-0.6302=0.3698
And this is the probability that the pedestrian was intoxicated or the driver was intoxicated.
Ted is not particularly creative. He uses the pickup line "If I could rearrange the alphabet, I'd put U and I together." The random variable x is the number of girls Ted approaches before encountering one who reacts positively. Determine whether the table describes a probability distribution. If it does, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied.
x P(x)
1 0.001
2 0.025
3 0.101
4 0.246
5 0.503
Answer:
Not a probability distribution
Step-by-step explanation:
The given table doesn't describe a probability distribution as in order for the given distribution to be a probability distribution the sum of probabilities is required to be equal to one.
Here,
Sum of probabilities = 0.001+0.025+0.101+0.246+0.503 = 0.876
The sum of probabilities is not equal to one.
Therefore, the given distribution is not a probability distribution ..
Use undetermined coefficients to find the particular solution to 7t + 5=y''+y'-4y У, (t) - Preview Get help: Video Points possible: 1 This is attempt 1 of 2. Post this question to forum License
Suppose [tex]y_p=a_0+a_1t[/tex] is a solution to the ODE. Then [tex]{y_p}'=a_1[/tex] and [tex]{y_p}''=0[/tex], and substituting these into the ODE gives
[tex]a_1-4(a_0+a_1t)=7t+5\implies\begin{cases}-4a_1=7\\-4a_0+a_1=5\end{cases}\implies a_0=-\dfrac{27}{16},a_1=-\dfrac74[/tex]
Then the particular solution to the ODE is
[tex]y_p=-\dfrac{27}{16}-\dfrac74t[/tex]
1) Homer and Marge have purchased a home for $189 000. The real estate agent informs them that homes in their area have generally depreciated by 11% every six years. Based on this, how much should they be able to sell their home for in 15 years? (3 points)
Answer:
They should be able to sell their home for $149706.9
Step-by-step explanation:
Let's first understand the situation.
There is an initial value for the house which is $189000. However, this value varies every 6 years because of a 11% depreciation of the total value.
Because the depreciation is not executed during the 6 years in a constant way, but instead after the whole 6 years have passed, then we can calculate how many depreciations will be applied within the next 15 years:
total years/years needed for depreciation=15years/6years=2.5
The above means that only 2 depreciations are going to be applied. Remember that depreciation is only applied if the whole 6 years have passed.
Now, after the first 6 years the depreciation (D) is:
D = 0.11 * $189000 = $20790,
which means that the value of the house will be:
(initial value) - D = $189000 - $20790 = $168210
Now, after the following 6 years, first 12 years, the depreciation (D) is:
D = 0.11 * $168210 = $18503.1,
which means that the value of the house will be:
(initial value) - D = $168210 - $18503.1 = $149706.9
In conclusion, in 15 years from now, they should be able to sell their home for $149706.9
A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 98% confidence interval with an error of no more than 0.08. A consultant has informed them that a previous study found the mean to be 6.6 fast food meals per week and found the standard deviation to be 0.7. What is the minimum sample size required to create the specified confidence interval? Round your answer up to the next integer.
Answer:
415
Step-by-step explanation:
Confidence Level = 98%
Z-value for this confidence level = z = 2.326
Margin of error = E = 0.08
Mean = u = 6.6
Standard deviation = [tex]\sigma=0.7[/tex]
Required Sample Size = n = ?
The formula for margin of error is:
[tex]E=z\frac{\sigma}{\sqrt{n}}[/tex]
Re-arranging the equation for n, and using the given values we get:
[tex]n=(\frac{z\sigma}{E} )^{2}\\\\ n=(\frac{2.326 \times 0.7}{0.08} )\\\\ n=415[/tex]
Thus, the minimum sample size required to create the specified confidence interval is 415
The minimum sample size required to construct a 98% confidence interval with an error of no more than 0.08 is 255.
Explanation:To determine the minimum sample size required to construct a 98% confidence interval with an error of no more than 0.08, we can use the formula:
n = (Z * sigma / E) ^ 2
where n is the sample size, Z is the Z-score corresponding to the desired confidence level, sigma is the standard deviation, and E is the desired margin of error.
In this case, the Z-score for a 98% confidence level is approximately 2.33. Substituting the given values of sigma = 0.7 and E = 0.08 into the formula, we can calculate the minimum sample size:
n = (2.33 * 0.7 / 0.08) ^ 2
n ≈ 254.43
Rounding up to the next integer, the minimum sample size required is 255.
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A thief steals an ATM card and must randomly guess the correct seven-digit pin code from a 4-key keypad. Repetition of digits is allowed. What is the probability of a correct guess on the first try?
The probability of guessing the correct seven-digit pin code on the first try is very low, approximately 0.000024%.
Given that,
A thief steals an ATM card.
The thief must guess the correct seven-digit pin code.
The pin code is entered using a 4-key keypad.
The probability of guessing the correct seven-digit pin code on the first try depends on a few factors.
To break it down,
if the thief has a 4-key keypad and repetition of digits is allowed, that means there are four options for each digit.
So, there are a total of 4⁷ (4 raised to the power of 7) possible combinations.
Since the thief is trying to guess the correct pin code on the first try, there is only one correct combination out of the total possible combinations.
Therefore,
The probability of guessing the correct pin code on the first try would be 1 out of 4⁷, or approximately 0.00000024, or 0.000024%.
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The probability of randomly guessing a 7-digit PIN from a 4-key keypad is 1 in 16,384. This equals approximately 0.000061 or 0.0061%. Each digit has 4 possible options, and there are 7 digits in total.
The probability of guessing a seven-digit PIN code correctly from a 4-key keypad (where repetition of digits is allowed) can be calculated as follows:
Since each of the 7 digits in the PIN can be any of 4 possible digits (0 through 3), the total number of possible combinations is calculated by raising the number of choices per digit to the power of the number of digits:
→ Total possible combinations = 4^7
= 4⁷
= 16384
Therefore, the probability of guessing the correct PIN on the first try is the reciprocal of the total number of possible combinations:
→ Probability of a correct guess = 1 / 16384
Hence, the probability is approximately 0.000061 or 0.0061%.
The annual snowfall in a town has a mean of 35 inches and a standard deviation of 11 inches. Last year there were 60 inches of snow. How many standard deviations from the mean is that
Answer:
z=2.27
Step-by-step explanation:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
where z is the deviation from mean.
mean (μ) = 35 inches
standard deviation (σ) = 11 inches
last year snow fall (x) = 60 inches
[tex]z=\frac{x-\mu}{\sigma}[/tex]
[tex]z=\frac{60-35}{11}[/tex]
z=2.27
now, the standard deviation for the 60 inches snow from the mean is calculated to be 2.27
Is x+y+1=0 a tangent of both y^2=4x and x^2=4y parabolas?
Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
__
For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
__
For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
___
If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
_____
Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.
Final Question Math Need help!!
Answer:
Dear, Have a look at pic
Identify the radius and center.
x^2 + y^2 - 2x + 4y - 11 = 0
The answer is:
Center: (1,-2)
Radius: 4 units.
Why?To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
Where,
"h" and "k"are the coordinates of the center of the circle and "r" is its radius.
So, we need to complete the square for both variable "x" and "y".
The given equation is:
[tex]x^2+y^2-2x+4y-11=0[/tex]
So, solving we have:
[tex]x^2+y^2-2x+4y=11[/tex]
[tex](x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16[/tex]
[tex](x^2-1)+(y^2-(-2))=16[/tex]
Now, we have that:
[tex]h=1\\k=-2\\r=\sqrt{16}=4[/tex]
So,
Center: (1,-2)
Radius: 4 units.
Have a nice day!
Note: I have attached a picture for better understanding.
A floor refinishing company charges $1.83 per square foot to strip and refinish a tile floor for up to 1000 square feet. There is an additional charge of $350 for toxic waste disposal for any job which includes more than 150 square feet of tile.
A) Express the cost, y, of refinishing a floor as a function of the number of square feet, x, to be refinished.
b) Graph the function, give the domain and range.
Answer:
Here x represents the number of square feet to be refinished and y represents the cost of refinishing the floor,
Given,
The cost of a tile floor for up to 1000 square feet is $1.83 per square,
So, the cost of x square feet of tile = 1.83x for x ≤ 1000
⇒ y = 1.83x for x ≤ 1000
Since, there is an additional charge of $350 for toxic waste disposal for any job which includes more than 150 square feet of tile.
That is, y = 1.83x + 350, for x > 150
So, y must be 1.83x for x ≤ 150.
A) Hence, the function that express the cost, y, of refinishing a floor as a function of the number of square feet, x, to be refinished, is,
[tex]y=\begin{cases}1.83x & \text{ if } 0\leq x\leq 150 \\ 1.83x+350 & \text{ if } 150< x\leq 1000\end{cases}-----(1)[/tex]
B) The domain of the function = all possible value of x
⇒ Domain = 0 ≤ x ≤ 1000
Range = All possible value of y,
Since, the range of function y=1.83x, 0≤ x ≤ 150 is [0, 274.5]
While the range of function y = 1.83x + 350, for x > 150 is (624.5, 2180]
Hence, the range of the function (1) = [0, 274.5]∪(624.5, 2180]
The cost of refinishing a floor can be expressed as a piecewise function based on the number of square feet to be refinished. The domain of the function is all real numbers, and the range is all real numbers greater than or equal to 0.
Explanation:Let x represent the number of square feet to be refinished.
For x ≤ 150, the cost of refinishing a floor is simply $1.83 per square foot. So, the cost function, y, for x ≤ 150 is y = 1.83x.
For x > 150, there is an additional charge of $350 for toxic waste disposal. So, the cost function, y, for x > 150 is y = 350 + 1.83x.
The overall cost function, y, is given by:
y = 1.83x, for x ≤ 150
y = 350 + 1.83x, for x > 150
The domain of the function is all real numbers, since any positive number of square feet can be refinished. The range of the function is all real numbers greater than or equal to 0, since the cost cannot be negative.
Problem 4. Let m and n be two integers. Show that m^3- n^3 is even if and only if m n is even.
Answer:
The expression [tex]m^3-n^3[/tex] is even if both variables (m and n) are even or both are odd
Step-by-step explanation:
Let's remember the logical operations with even and odd numbers
odd*odd=odd
even*even=even
odd*even=even
odd-odd=even
even-even=even
even-odd=odd
Now, the original expression is:
[tex]m^3-n^3[/tex] which can be expressed as:
[tex](m*(m*m))-(n*(n*n))[/tex]
If m and n are both odd, then:
[tex](m*(m*m))=odd*(odd*odd)=odd*(odd)=odd[/tex]
[tex](n*(n*n))=odd*(odd*odd)=odd*(odd)=odd[/tex]
Then, [tex](m*(m*m))-(n*(n*n))=odd-odd=even[/tex]
If m and n are both even, then:
[tex](m*(m*m))=even*(even*even)=odd*(even)=even[/tex]
[tex](m*(m*m))=even*(even*even)=odd*(even)=even[/tex]
Then, [tex](m*(m*m))-(n*(n*n))=even-even=even[/tex]
Finally if one of them is even, for example m, and the other is odd, for example n, then:
[tex](m*(m*m))=even*(even*even)=odd*(even)=even[/tex]
[tex](n*(n*n))=odd*(odd*odd)=odd*(odd)=odd[/tex]
Then, [tex](m*(m*m))-(n*(n*n))=even-odd=odd[/tex]
In conclusion, the expression [tex]m^3-n^3[/tex] is even if both variables (m and n) are even or both are odd. If one of them is even and the other one is odd, then the expression is odd.
Please help me with this
Answer:
The correct answer is first option
24
Step-by-step explanation:
From the figure we get, mAXM = 72° and m<AMR = 38°
Also it is given that, all triangles are isosceles triangles and
m<FXA = 96°
To find the measure of <FXM
From the figure we get,
m<FXA = m<AXM + m<FXM
m<FXM = m<FXA - m<AXM
= 96 - 72
= 24
Therefore the correct answer is first option
24
An advertising company wishes to estimate the population mean of the distribution of hours of television watched per household per day. Suppose that the population standard deviation of hours watched per household per day is known to be 2.8 hours. The company decides that it wants the 99% confidence interval for the population mean to be no longer than 0.5 (hour). What is the minimum sample size that will result in a small enough confidence interval?
Answer: 208
Step-by-step explanation:
Given : An advertising company wishes to estimate the population mean of the distribution of hours of television watched per household per day.
Standard deviation : [tex]2.8\text{ hours}[/tex]
Margin of error : [tex]\pm0.5\text{ hour}[/tex]
Significance level : [tex]\alpha=1-0.99=0.01[/tex]
Critical value : [tex]z_{\alpha/2}=2.576[/tex]
The formula to calculate the sample size is given by :-
[tex]n=(\dfrac{z_{\alpha/2}\sigma}{E})^2[/tex]
[tex]\Rightarrow\ n=(\dfrac{2.576\times2.8}{0.5})^2=208.09793536\approx208[/tex]
Hence, the minimum required sample size must be 208.
In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose to raise his or her hand. Eight hands go up. Then the professor asked everyone with a pierced ear to do likewise. This time there are 35 hands raised. How many students have piercings both on their ears and their noses?
Answer:
3 students
Step-by-step explanation:
If everyone in the class has either a pierced nose or ear, we just simply have to add up the total number of hands raised and minus the number of students in the class.
35+8=43
43-40=3
3 students have both a pierced nose and pierced ear.
Which of the following directors made Bonnie and Clyde? a. Arthur Penn b. Warren Beaty c. Stanley Kubrick d. None of the above
Answer:
a) Arthur Penn
Step-by-step explanation:
There are three feature films based on Bonnie and Clyde they are the following:
"The Bonnie Parker Story" released in 1958 was directed by William Witney.
"Bonnie and Clyde" released in 1967 was directed by Arthur Penn.
Warren Beaty is primarily an actor who has directed six films including a tv movie and five feature films.
"The Highwaymen" was directed by John Lee Hancock released 2019.
Answer:
A. Arthur Penn
Step-by-step explanation:
Bonnie and Clyde A defining film of the New Hollywood generation was Bonnie and Clyde (1967). Produced by and starring Warren Beatty and directed by Arthur Penn, its combination of graphic violence and humor, as well as its theme of glamorous disaffected youth, was a hit with audiences.
For a dosage of x cubic centimeters (cc) of a certain drug, assume that the resulting blood pressure B is approximated by B (x) = 0.06 x^2 - 0.3 x^3 . Find the dosage at which the resulting blood pressure is maximized. Round to two decimal places.
Answer:
The number of dosage is 0.13.
Step-by-step explanation:
Here, the given function that represents the blood pressure,
[tex]B(x)=0.06x^2 - 0.3x^3[/tex]
Where, x is the number of dosage in cubic centimeters,
Differentiating the above function with respect to x,
[tex]B'(x)=0.12x-0.9x^2[/tex]
For maximum or minimum blood pressure,
[tex]B'(x)=0[/tex]
[tex]0.12x-0.9x^2=0[/tex]
[tex]-0.9x^2=-0.12x[/tex]
[tex]x=\frac{0.12}{0.9}=\frac{2}{15}[/tex]
Again differentiating B'(x) with respect to x,
[tex]B''(x)=0.12-1.8x[/tex]
Since, at x = 2/15,
[tex]B''(\frac{2}{15})=0.12-1.8(\frac{2}{15})=0.12-0.24=-0.12=\text{Negative value}[/tex]
So, at x = 2/15 the value of B(x) is maximum,
Hence, the number of dosage at which the resulting blood pressure is maximized = 2/15 = 0.133333333333 ≈ 0.13
The maximum blood pressure results from a dosage of approximately 0.13 cubic centimeters, based on the mathematical model given in the problem.
Explanation:To find the maximum blood pressure using the formula B (x) = 0.06 x^2 - 0.3 x^3, we need to first find the derivative of this equation, as the maximum point on any curve happens when its derivative equals zero.
First, differentiate B(x) with respect to x: B'(x) = 2*0.06x - 3*0.3x^2 = 0.12x - 0.9x^2 Next, set this derivative equal to zero and solve for x: 0 = 0.12x - 0.9x^2 0 = x(0.12 - 0.9x) So x = 0 or x = 0.12/0.9 = 0.133 Lastly, we need to determine if these x-values give a maximum or minimum in B(x). We do this by either taking the second derivative of B(x) or by testing points on either side of the x-values we found. If we find the second derivative, we find that B''(x) = 0.12 -1.8x, which is negative for x = 0.133. This means that the blood pressure is maximized at an x-value of 0.133 cc, or, rounded to two decimal places, 0.13 ccLearn more about Maximum Blood Pressure From Drug Dosage here:
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Q2. On a cold day, hailstones fall with a velocity of (2i− 6k) m s−1 . If a cyclist travels through the hail at 10i ms−1 , what is the velocity of the hail relative to the cyclist? At what angle are the hailstones falling relative to the cyclist
Answer:[tex]-8\hat{i}-6\hat{k}[/tex]
[tex]\theta =\tan^{-1}\left ( \frac{3}{4} \right )[/tex]
Step-by-step explanation:
Given
Velocity of hailstones fall[tex]\left ( V_h\right )=2\hat{i}-6\hat{k}[/tex] m/s
Velocity of cyclist [tex]\left ( V_c\right )=10\hat{i}[/tex] m/s
Therefore
Velocity of hail with respect to cyclist[tex]\left ( V_{hc}\right )[/tex]
[tex]V_{hc}=V_h-V_c[/tex]
[tex]V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}[/tex]
[tex]V_{hc}=-8\hat{i}-6\hat{k}[/tex]
and angle of hails falling relative to the cyclist is given by
[tex]\theta =\tan^{-1}\left ( \frac{3}{4}\right )[/tex]
[tex]\theta [/tex] is the angle made with the vertical
Write an equation of the horizontal asymptote for this function. Also, interpret what this asymptote means in the context of the problem (in terms of the fish population and the number of years since the fish were introduced into the lake.)
Answer:
Step-by-step explanation:
First, finding the horizontal asymptote:
[tex]\lim_{t \to \infty} = \frac{200+40t}{1+0.05t} = \frac{\frac{200}{t} 40 }{\frac{1}{t} 0.05} = 800[/tex]
In the context of the problem, the horizontal asymptote speaks about where the population of the fish is headed and capped.
25 Points! Please answer asap! Carly stated “All pairs of rectangles are dilations”. Which pair of rectangles would prove that Carly’s statement is incorrect? (Images below)
Answer:
C
Step-by-step explanation:
A. First two rectangles are dilations because
[tex]\dfrac{2}{4}=\dfrac{4}{8}=0.5[/tex]
B. Second two rectangles are dilations because
[tex]\dfrac{2}{4}=\dfrac{3}{6}=0.5[/tex]
C. Third two rectangles are not dilations because
[tex]\dfrac{3}{4}\neq \dfrac{2}{3}[/tex]
D. Fourth two rectangles are dilations because
[tex]\dfrac{3}{4}=\dfrac{1.5}{2}=0.75[/tex]
Answer:
c please correct me if im wrong
Step-by-step explanation:
The functions q and r are defined as follows.
q(x) = -2x +1
r(x) = 2x^2 - 1
Find the value of .
q(r(4))
Answer:
q(r(4)) = -61
Step-by-step explanation:
q(x) = -2x +1
r(x) = 2x^2 - 1
q(r(4))
First find r(4)
f(4) = 2 (4)^2 -1
= 2 *16 -1
= 32-1
= 31
Then put this value in for x in q(x)
q(r(4)) = q(31) = -2(31)+1
= -62+1
= -61
Answer:
The value of q( r(4) ) = -61
Step-by-step explanation:
It is given that,
q(x) = - 2x +1
r(x) = 2x^2 - 1
To find the value of q(r(4))
r(x) = 2x^2 - 1
r(4) = 2( 4^2) - 1 [Substitute 4 instead of x]
= 2(16) - 1
= 32 - 1 = 31
q( x ) = -2x +1
q( r(4) ) = q(31) [Substitute 31 instead of x)
= (-2*31) +1
= -62 + 1 = -61
Therefore the value of q(r(4)) = -61