The combustion of titanium with oxygen produces titanium dioxide: ti (s) + o2(g) â tio2 (s) when 1.000 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °c to 60.00 °c. in a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kj/k. the heat of reaction for the combustion of a mole of ti in this calorimeter is ________ kj/mol.

Final answer:

The correct IUPAC name for MgBr2 is 'magnesium bromide', where 'magnesium' denotes the metal cation and 'bromide' denotes the nonmetal anion with its ending changed to 'ide'.

Explanation:

The correct name for the compound MgBr2 is magnesium bromide. According to the International Union of Pure and Applied Chemistry (IUPAC) system of nomenclature, binary ionic compounds (compounds consisting of a metal and a nonmetal) are named by writing the name of the metal (the cation) followed by the name of the nonmetal (the anion) with its ending changed to 'ide'. In our case, 'Mg' stands for magnesium, and 'Br' stands for bromine; when combined in the compound MgBr2, the bromine becomes bromide. The prefix 'di' is not used in this name because the stoichiometry (the ratio of Mg to Br) is inferred by the charges on the ions; magnesium has a +2 charge and bromine has a -1 charge, so two bromine atoms are required to balance the charge of one magnesium atom.

Answer:

               The Equilibrium will shift to the left.

Explanation:

                      The reaction at equilibrium is as follow,

                              CH₃COOH       ↔    CH3COO⁻ + H⁺

According to Le Chatelier's Principle," When a system (reaction) at equilibrium is subjected to any stress (like change in Concentration, Pressure, Temperature e.t.c) the system (reaction) tends to adjust itself in such a way so as to minimize the effect of that change".

Hence, in above reaction when Sodium Acetate (source of CH₃COO⁻) is added the equilibrium will shift in left side and will decrease the concentration of CH₃COO⁻ions.

Final answer:

The addition of CH₃COONa, which contributes more acetate ions, will result in a leftward shift of the chemical equilibrium of the reaction CH₃COOH ⇌ CH₃COO⁻ (aq) + H⁺(aq), as predicted by Le Chatelier's principle.

Explanation:

When CH₃COONa is added to the solution, the chemical equilibrium of the reaction CH₃COOH ⇌ CH₃COO− (aq) + H⁺(aq) will shift. This is because CH₃COONa disassociates in water to form sodium ions (Na⁺) and acetate ions (CH₃COO⁻). By Le Chatelier's principle, adding more of a product (in this case, CH₃COO⁻) will shift the equilibrium to the left, towards the reactants, to counteract the change. This results in a decrease in the H+ concentration and is known as the common ion effect.

The equilibrium will therefore shift toward the formation of CH₃COOH, causing the concentration of CH₃COO⁻ and H⁺ to be reduced, which is in line with Le Chatelier's principle of equilibrium adjustment.

The given balanced chemical equation is,

[tex] Fe_{2}O_{3} + 3CO -->2 Fe (s) + 3CO_{2}(g) [/tex]

Part A:

Converting 3.65 L CO to moles:

[tex] 3.65 L * \frac{1 mol}{22.4 L} = 0.163 mol CO [/tex]

Moles of Fe that will be produced from 0.163 mol CO:

[tex] 0.163 mol CO * \frac{2 mol Fe}{3 mol CO} = 0.1086 mol Fe [/tex]

Mass of Fe = [tex] 0.1086 mol Fe * \frac{55.85 g}{1 mol} = 6.07 g Fe [/tex]

Part B: Actual yield of Fe = 4.23 g Fe.

Theoretical yield = 6.07 g Fe

Percentage yield = [tex] \frac{Actual yield (g)}{Theoretical yield (g)}*100 [/tex]

=69.7 %

The plastic is a polymer. A polymer is defined as a substance which is made from the monomers. The plastic is made of petroleum or coal materials. The correct option is D.

The wide range of synthetic or semi synthetic materials which use polymers as a main ingredient is defined as the plastic. The property plasticity makes it possible for the plastics to be moulded or pressured into objects of various shapes.

Most of the modern plastics are from the fossil fuel based chemicals such as natural gas or petroleum. The raw materials like natural gas, oil or plants are refined into ethane and propane. Both of these molecules are subjected to a process called cracking.

As a result of cracking, ethane and propane changes into ethylene and propylene. These materials are combined to form many polymers.

Thus the correct option is D.

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Neon (Ne) has a greater chance of forming a momentary dipole due to its completely filled outer electron shell.

The element with a greater chance of forming a momentary dipole is neon (Ne). Neon has a completely filled outer electron shell, which makes it inert and less likely to form chemical bonds. This means that when neon interacts with other elements, it can induce temporary dipole moments in the other atoms or molecules, creating momentary attractions between them.

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Answer : This chemical equation represents a single replacement reaction.

Explanation :

Single replacement reaction : It is defined as the reaction in which the most reactive metal displace the least reactive metal form its solution.

The given balanced chemical reaction is:

[tex]Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)[/tex]

The given chemical reaction is a single replacement reaction because in this reaction, iron is most reactive metal than the copper. So, iron can displace the copper metal form its solution and it forms iron (II) sulfate and copper as a product.

Hence, the chemical equation represents a single replacement reaction.

Hydrophobic molecules are nonpolar molecules that cluster away from water molecules. They have nonpolar covalent bonds and examples include oil, fats, and waxes.

Nonpolar molecules that cluster away from water molecules are called hydrophobic molecules. Hydrophobic molecules typically have nonpolar covalent bonds, which means the electronegativity difference between the bonded atoms is minimal. This leads to an absence of partial charges on the atoms, resulting in overall nonpolarity. Examples of hydrophobic molecules include oil, fats, and waxes.

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Final answer:

Ammonium carbonate decomposes when heated, resulting in water, ammonia, and carbon dioxide. The balanced chemical equation for this reaction is (NH4)2CO3(s) → 2 NH3(g) + CO2(g) + H2O(l). This is an example of a decomposition reaction.

Explanation:

When ammonium carbonate is heated, a decomposition reaction occurs, resulting in the formation of water (H2O), ammonia (NH3), and carbon dioxide (CO2). The balanced chemical equation for this reaction is:

(NH4)2CO3(s) → 2 NH3(g) + CO2(g) + H2O(l)

The formulas for the reaction products are ammonia (NH3), carbon dioxide (CO2), and water (H2O). This chemical equation shows that for each mole of ammonium carbonate heated, two moles of ammonia, one mole of carbon dioxide, and one mole of water are produced.

Some molecules begin sticking together when you add in more molecules because like attracts like and opposites repel.

A collection of two and more substances joined through chemical bonds is still referred to as a molecule.

like attracts like means It is repulsive when two items with identical charges interact. That is fascinating to watch how two objects with opposing charges interact.

Some molecules begin sticking together when you add in more molecules because like attracts like and opposites repel

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Answer: Option (C) is the correct answer.

Explanation:

Non-metals are the substances which gain electrons in order to gain stability and hence they form anions.

Some properties of non-metals are as follows.

But non-metals when gain an electron they they acquire a negative charge. Hence, when non-metal is present in ionic form in a solution then it is able to conduct electricity.

Thus, we can conclude that has a negative charge when a current is run through its solution is a characteristic of most non-metals and is not a characteristic of most metals.

Explanation:

When there occurs sharing of electrons between two different atoms then bond formed between them is known as a covalent bond.

When only one electron is shared then a single covalent bond is formed.

When only two electrons are shared then a double covalent bond is formed.

When three electrons are shared then a triple covalent bond is formed.

Thus, we can conclude that a chemical bond formed when two atoms share six electrons is a triple bond; it is best described as a covalent bond.

In this problem, we are asked to find the new concentration.

So, we use the dilution equation;

M1V1 = M2V2

Where M1 = concentration in molarity (moles/Liters) of the concentrated solution,

V2 =volume of the concentrated solution,

M2 =concentration in molarity of the dilute solution, and

V2 = volume of the dilute solution.

Before substituting the formula, convert the given mL to L since the unit for molarity is (moles/Liter).

Use the conversion factor (1000 mL = 1 L), so:

10.0 mL = 0.01 L

100 mL= 0.1 L

Now, we substitute the given (in liters) to the formula.

(0.50 M) (0.01 L) = M2(0.1 L)

M2 = [(0.50 M) (0.01 L)] / 0.1 L

M2 = 0.05 M

Answer: 0.050

Explanation:

Ans: Lowest coefficient in front of Ca(OH)2 is 3

Given equation:

Ca(OH)2 + H3PO3 → Ca3(PO3)2 + H2O

Reactants:                  Products:

Ca = 1                          Ca = 3

O = 5                           O = 7  

H = 5                           H = 2

P = 1                             P = 2

Balanced equation:

3Ca(OH)2 + 2H3PO3 → Ca3(PO3)2 + 6H2O

Answer:

130.1 x 10²³ molecules of sugar  

Explanation:

One dozen = 12 donuts

1 doughnut = 1.8 moles of sugar

12 doughnut = (1.8 x 12) moles of sugar = 21.6 moles of sugar

1 mole of any substance contains Avogadro’s number (6.023 x 10²³) of molecules.

1 mole of sugar = 6.023 x 10²³ molecules of sugar

21.6 moles of sugar = (6.023 x 10²³ x 21.6) molecules of sugar  

                                 = 130.1 x 10²³ molecules of sugar  

Answer:

A.) 130.032 x 10^23

Explanation:

I got it correct on founders edtell

Using the van't Hoff equation and the provided equilibrium constants at two different temperatures, the enthalpy change (ΔHrxn) of the reaction can be calculated.

The student wants to find the change in the heat content, or enthalpy change (ΔHrxn), of a reaction given the equilibrium constants at different temperatures. This can be done through the van't Hoff equation, which relates the equilibrium constant (K) to temperature (T) and enthalpy change (ΔHrxn). Using the provided equilibrium constants at 298 K and 764 K, as well as the constants 55.7 x 103J/mol and 8.314 J/mol K, we can set up and solve the van't Hoff equation to calculate ΔHrxn.

The van't Hoff equation is ln(K2/K1) = (-ΔHrxn/R)(1/T1 - 1/T2), where R is the ideal gas constant (8.314 J/mol K). By rearranging for ΔHrxn, we can input the given values for K1, K2, T1, and T2 to determine the enthalpy change for the reaction.