The compound diborane (b2h6) was at one time considered for use as a rocket fuel. its combustion reaction is b2h6(g) + 3 o2(â) â 2 hbo2(g) + 2 h2o(â) the fact that hbo2, a reactive compound, was produced rather than the relatively inert b2o3 was a factor in the discontinuation of the investigation of the diborane as a fuel. what mass of liquid oxygen (lox) would be needed to burn 106.3 g of b2h6?

If 23 g of sodium reacts completely with 71 g of chlorine, the limiting reactant is determined, and approximately 59 grams of sodium chloride (NaCl) can be produced.

1. Calculate the moles of each reactant:

Sodium: 23 g / 23 g/mol = 1 mol

Chlorine: 71 g / (2 * 35.5 g/mol) = 1 mol

2. Determine the limiting reactant:

In this case, both sodium and chlorine have the same number of moles (1 mol each). Therefore, neither is technically "limiting" the reaction. However, for calculating the theoretical yield (maximum amount of product), we need to consider that one reactant might be completely consumed before the other.

3. Calculate the grams of product based on the limiting reactant (assuming complete consumption of one reactant):

Since both reactants have the same amount, choosing either sodium or chlorine as the limiting reactant will give the same result. Let's assume sodium is completely consumed.

NaCl produced: 1 mol Na x (1 mol NaCl / 1 mol Na) x (23 g NaCl/mol + 35.5 g NaCl/mol) = 58.5 g NaCl

4. Round the answer to the nearest gram:

58.5 g rounded to the nearest gram is 59 g.

Therefore, if 23 g of sodium reacts completely with 71 g of chlorine, we can expect around 59 grams of sodium chloride (NaCl) to be produced.

If 23 g of sodium reacts with 71 g of chlorine, based on stoichiometry and the limiting reagent principle, 94 grams of sodium chloride would be the expected product, rounded to the nearest gram.

If 23 g of sodium reacts completely with 71 g of chlorine, the amount of product formed can be determined using stoichiometry based on the balanced chemical equation 2 Na(s) + Cl2(g) → 2 NaCl(s).

Based on the molar mass of the reactants and products, we can conclude that 45.98 amu of sodium will react with 70.90 amu of chlorine to produce 275.9 amu of sodium chloride. Converting these amounts to grams, we find that every 22.99 g of sodium reacts with 35.45 g of chlorine to produce 58.45 g of sodium chloride (NaCl).

Given the ratio of sodium to chlorine to sodium chloride is 1:1.545:2.54 in terms of grams, we can calculate that 23 g of sodium will react with 35.54 g (23 g × 1.545) of chlorine to produce a total of 58.54 g (23 g × 2.54) of sodium chloride. Since the question states that we have 71 g of chlorine, sodium is the limiting reagent, and therefore the maximum yield of NaCl will be based on the amount of sodium.

Thus, if 23 g of sodium reacts completely with 71 g of chlorine, 94 grams of sodium chloride (NaCl) would be the expected rounded product to the nearest gram.

Answer:

6 hope this helps

Answer:

C. Nitrogen (N) and sulfur (S)

Explanation:

Hello,

In this case, we could differentiate the nonmetals from the metals by understanding they do not have or have very tiny values of properties such as bright, hardness, electric conductivity, heat conductivity and others. Moreover, they are allocated at the right of the periodic table. In such a way, since nitrogen tends to be a gas and sulfur a yellowish powder, they are classified as nonmetals whereas, lithium, barium, palladium, zinc, beryllium and magnesium are considered as metals as they have the aforementioned properties.

Best regards.

We can see here that the nonmetals among the options provided are:

C. Nitrogen (N) and Sulfur (S)

Nonmetals are a group of elements found on the right side of the periodic table. They are characterized by their properties, which are distinct from those of metals.

Nonmetals generally have properties such as being poor conductors of heat and electricity, having lower melting and boiling points, and being more brittle compared to metals. Nitrogen and sulfur are both nonmetals, whereas the other elements listed in the options (lithium, barium, palladium, zinc, beryllium, and magnesium) are metals or metal-like elements.

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Answer:

to change the core

Explanation:

Answer:  It increased the number of molecular collisions.

Justification:

The collision theory states the reaction is the result of the collisions between the particles (atoms, ions, or molecules).

The increase of the temperature as solid is added is the result of the reaction of solid X when it is placed into the solution.

Since, the main postulate of the collision theory is that the particles have to collide to react, the amount of particles is a decisive factor of the reaction rate. The raise of the temperature when the solid is added is an evidence of this postulate: more particles → more collisions → more reactions → increase in temperature.

The Ka and Kb reactions for the HSO3- ion in water, acting as an acid and base respectively, are: 1) Ka Reaction: HSO3-(aq) + H2O(l) → H3O+(aq) + SO3 2-(aq), 2) Kb Reaction: HSO3-(aq) + H2O(l) → OH-(aq) + H2SO3(aq).

The HSO3- ion is amphoteric, meaning it can act as both an acid and a base. The ka and kb reactions for this ion in water would be as follows:

In the Ka reaction, the bisulfite ion (HSO3-) donates a hydrogen ion (H+) to water, thereby acting as an acid. The resultant ions are hydronium (H3O+) and sulfite (SO3 2-).

In the Kb reaction, the bisulfite ion (HSO3-) accepts a hydrogen ion (H+) from water, thus acting as a base. The resulting species are hydroxide ion (OH-) and sulfurous acid (H2SO3).

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The balanced reactions for [tex]HSO_{3}^{-}[/tex]⁻ in water are [tex]HSO_{3}[/tex](aq) + H₂O(l) ⇌ [tex]SO^{2-} _{3}[/tex]⁻(aq) + H₃O⁺(aq) for its Ka, and [tex]HSO_{3} ^{-}[/tex]⁻(aq) + H₂O(l) ⇌ [tex]H_{2} SO_{3}[/tex](aq) + OH⁻(aq) for its [tex]k_{b}[/tex]. The equilibrium constant expressions for these reactions are written accordingly. This demonstrates [tex]HSO_{3} ^{-}[/tex] acting both as an acid and a base.

When  (hydrogen sulfite ion) behaves as an acid in water, it donates a proton (H⁺) to form [tex]SO_{3} ^{2-}[/tex]and H₃O⁺. The balanced equation for this equilibrium reaction is:

[tex]HSO_{3} ^{2-}[/tex](aq) + H₂O(l) ⇌ [tex]SO_{3} ^{2-}[/tex](aq) + H₃O⁺(aq)

The equilibrium constant expression for this reaction ([tex]k_{a}[/tex]) can be written as:

[tex]k_{a}[/tex] = [[tex]SO_{3} ^{2-}[/tex]⁻][H₃O⁺] / [[tex]HSO_{3} ^{-}[/tex]]

When [tex]HSO_{3} ^{-}[/tex] behaves as a base, it accepts a proton (H⁺) from water to form [tex]H_{2} SO_{3}[/tex] and OH⁻. The balanced equation for this equilibrium reaction is:

[tex]HSO_{3} ^{-}[/tex](aq) + H₂O(l) ⇌ [tex]H_{2} SO_{3}[/tex] (aq) + OH⁻(aq)

The equilibrium constant expression for this reaction ([tex]k_{b}[/tex]) can be written as:

Kb = [[tex]H_{2}SO_{3}[/tex]][[tex]OH_{-}[/tex]] / [[tex]HSO_{3} ^{-}[/tex]]

Final answer:

The water has a Ka value, more precisely referred to as ionization constant (Kw), of 1.0 × 10^-14 at 25 °C.

Explanation:

The water has a Ka value that is actually known as the ionization constant for water, Kw. The Ka value is a specific term generally used for the acid dissociation constant of substances other than water. For water at 25 °C, the product of the concentrations of the hydrogen ions ([H3O+]) and the hydroxide ions ([OH-]) is 1.0 × 10^-14, so Kw is 1.0 × 10^-14. This means that in pure water, or in a neutral aqueous solution, the concentration of hydrogen ions and hydroxide ions are both 1.0 × 10^-7 M. Therefore, the correct answer to the question 'water has a Ka value of what?' is 1 × 10^-14.

Answer:

B/ the second option

Explanation:

This is the answer on e2020

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Final answer:

The balanced equation for the thermal dehydration of barium chloride is [tex]\[ BaCl_2 \cdot 2H_2O \xrightarrow[\text{}]{\text{Heat}} BaCl_2 + 2H_2O \uparrow \][/tex]

Explanation:

The thermal dehydration of barium chloride (BaCl₂) involves the removal of water molecules from its hydrated form. Barium chloride commonly exists as a dihydrate, BaCl₂·2H₂O. The balanced chemical equation for the thermal dehydration of barium chloride dihydrate is:

[tex]\[ BaCl_2 \cdot 2H_2O \xrightarrow[\text{}]{\text{Heat}} BaCl_2 + 2H_2O \uparrow \][/tex]

In this equation, the dihydrate on the left side loses two water molecules upon heating, producing anhydrous barium chloride (BaCl₂) and releasing water vapor. The upward arrow indicates the release of water in the form of steam or water vapor.

This process is a common example of thermal decomposition reactions, where a substance breaks down into simpler components upon exposure to heat. Understanding such reactions is crucial in various chemical and industrial processes, providing insights into the behavior of compounds under specific conditions.

Answer:

1) Conservation of Matter states that the reactants have to equal the products.

2) Products and reactants in a balanced chemical reaction have the same number of atoms of each element.

3) Three (3) atoms of carbon would need to be represented.

Explanation:Number of atoms on the left and on the right side of the balanced chemical reaction is the same, for example: Mg + 2HCl → H₂ + MgCl₂. There are two hydrogen atoms, two chlorine atoms and one magnesium atom on both side of chemical reaction.

1. Conservation of Matter states that the reactants have to equal the products.

2. Products and reactants in a balanced chemical reaction have the same number of atoms of each element.

3. If the equation on the board had shown 3 atoms of carbon on the reactants side, then there would need to be 3 atoms of carbon on the products side.

Conservation of Matter is a law of science that states that matter cannot be created or destroyed. This means that the total mass of the reactants in a chemical reaction must equal the total mass of the products.

Atoms are the basic unit of matter. A molecule is a group of atoms that are bonded together.

In a balanced chemical equation, the number of atoms of each element is the same on the reactant side and the product side. This is because the law of conservation of matter must be obeyed.

So, if the equation on the board had shown 3 atoms of carbon on the reactants side, then there would need to be 3 atoms of carbon on the products side in order for the equation to be balanced.

Here is an example of a balanced chemical equation:

2 H₂ + O₂ → 2 H₂O

In this equation, there are 2 hydrogen atoms on the reactant side and 2 hydrogen atoms on the product side. There is also 1 oxygen atom on the reactant side and 1 oxygen atom on the product side. This is a balanced equation because the law of conservation of matter is obeyed.

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Answer b is the answer for the equation:

Yes, your answer is correct. Heating an air-filled, sealed can results in stronger and more frequent collisions of air molecules against the wall, leading to an increase in pressure.

When you heat an air-filled, sealed can, the collisions of air molecules against the wall of the can become stronger and more frequent. This is because as the temperature inside the can increases, the air molecules move faster and collide more energetically with the can walls. This increased movement results in a rise in pressure inside the can due to an increased number of collisions and force per collision. This concept is based on the principles of gas pressure and the kinetic molecular theory, which relate temperature, molecular speed, and pressure in a contained gas.

Gas pressure is indeed caused by collisions between gas molecules and the container walls. An increase in temperature causes the molecules to move faster, leading to more collisions with the walls, which translates into an increase in pressure. Furthermore, the concept that gas pressure can be increased by compressing a gas into a smaller volume explains why a canister feels cold when its gas is released: the surrounding air absorbs the energy from the expanding gas.

Answer:

3.3 atm

Explanation:

This is a simple application of Dalton's law of partial pressure which state that the total pressure exerted by a mixture of gas is the sum of the individual partial pressure of the component gases.

[tex]P_{total} = P_1 + P_2 + ........ + P_n[/tex]

Hence, the total pressure of the gas mixture becomes:

[tex]P_{total} = P_{methane} + P_{hydrogen} + ........ + P_{nitrogen}[/tex]

                         = 1 + 1.2 + 1.1

                                 = 3.3 atm

The total pressure of the mixture is 3.3 atm

1) polar solvents dissolve ionic or polar solutes

2) Non-polar solvents dissolve non-polar solutes

3) Non-polar solvents do not dissolve polar and ionic solutes 

4) Polar solvents do not dissolve non-polar solutes.

There are exceptions, but the rule is applicable in here.

The correct answer is option (A). The theoretical yield of hydrogen (H₂) is approximately 1.11 g.

To find the theoretical yield of hydrogen gas (H₂) produced in this reaction, follow these steps:

1. Determine the molar mass of HCl:

- The molar mass of HCl = 1.01 g/mol (for H) + 35.45 g/mol (for Cl) = 36.46 g/mol.

2. Calculate the number of moles of HCl in 40.0 g:

[tex]\text{moles of HCl} = \frac{40.0 \, \text{g}}{36.46 \, \text{g/mol}} = 1.095 \ moles[/tex]

3. Using the stoichiometry of the balanced equation:

For every 2 moles of HCl, 1 mole of H₂ is produced.

Therefore, moles of H₂ produced = [tex]\frac{1.095 \, \text{moles of HCl}}{2} = 0.5475 \ moles \ of \ H_2[/tex].

4. Determine the molar mass of H₂:

- The molar mass of H₂ = 2.016 g/mol.

5. Calculate the theoretical yield of H₂ in grams:

[tex]{mass\ of {H_2}} = 0.5475 \times 2.016 = 1.103824 g[/tex]

6. Round to the nearest gram: - 1.11 g

So, the theoretical yield of hydrogen gas is approximately: A) 1.11 g

The complete question is:

Consider the balanced equation. [tex]2HCl + Mg \rightarrow MgCl_2 + H_2[/tex] if 40.0 g of HCl react with an excess of magnesium metal, what is the theoretical yield of hydrogen?

A) 1.11 g

B) 2.22 g

C) 52.2 g 1

D) 104 g