The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion
s = 4 sin(πt) + 3 cos(πt),
where t is measured in seconds. (Round your answers to two decimal places.)

A. Find the average velocity during each time period.
(i) [1, 2]
(ii) [1, 1.1]
(iii) [1, 1.01]
(iv) [1, 1.001]

B. Estimate the instantaneous velocity of the particle when t = 1.

Answer:

13/4

Step-by-step explanation:

The slope of the line between 2 points is found by

m = (y2-y1)/(x2-x1)

   = (6--7)/(-3--7)

   = (6+7)/(-3+7)

   = 13/4

Answer:

The slope is 13/4.

Step-by-step explanation:

Slope formula:

[tex]\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\displaystyle \frac{6-(-7)}{(-3)-(-7)}=\frac{13}{4}[/tex]

[tex]\huge\boxed{\frac{13}{4}}[/tex], which is our answer.

Answer:

The amount he should borrow is 19.25 hundreds dollars.

Step-by-step explanation:

Given : The cost (in hundreds of dollars) of tuition at the community college is given by [tex]T = 1.25c + 3[/tex], where c is the number of credits the student has registered for. If a student is planning to take out a loan to cover the cost of 13 credits.

To find : Use the model to determine how much money he should borrow?

Solution :

The model is given by [tex]T = 1.25c + 3[/tex]

Where,

c is the number of credits the student has registered.

T is the cost of tuition at the community college.

If a student is planning to take out a loan to cover the cost of 13 credits.

The amount he should borrow will get by putting the value of c in the model,

[tex]T = 1.25c + 3[/tex]

[tex]T = 1.25(13) + 3[/tex]

[tex]T = 16.25 + 3[/tex]

[tex]T =19.25[/tex]

Therefore, The amount he should borrow is 19.25 hundreds dollars.

Answer:

first trip 20 mph, trip back 35 mph, distance = 70 miles.

Step-by-step explanation:

A round trip takes 3.5 hours going one way and 2 hour to return.

Let the speed of first trip = v mph

Given that the trip back is at a speed 15 mph faster than the speed of first trip.

Therefore, the speed of trip back  =  ( v+15 ) mph

Let the Distance between places = d miles

Now we use the formula

[tex]Time=\frac{Distance}{Velocity}[/tex]

[tex]\frac{Distance}{Velocity}[/tex] = 3.5

and [tex]\frac{D}{V+15}[/tex] = 2

dividing these two

[tex]\frac{v+15}{v}[/tex] = [tex]\frac{3.5}{2}[/tex]

2v + 30 = 3.5v

v = 20 mph

d = 3.5 × 20 = 70 miles

The speed of the first trip is 20 mph and the speed of trip back (20+15) 35 mph. and the distance is 70 miles.

Answer:

20212

Step-by-step explanation:

Divide 185 by [tex]3^4[/tex] as [tex]3^4[/tex] is closest to 185

After dividing we get remainder 23 and quotient 2

Divide the remainder 23 by [tex]3^3[/tex] we get remainder 23 and quotient 0

Divide the remainder  23 by [tex]3^2[/tex] we get remainder 5 and quotient 2

Divide the remainder 5 by [tex]3^1[/tex] we get remainder 2 and quotient 1

Divide the remainder 2 by [tex]3^0[/tex] we get remainder 0 and quotient 2

Taking all the quotient values we get 20212

Hence, 185₁₀=20212₃

Answer:

The required amount of mice is 11.82 gram.

Step-by-step explanation:

Given : Assuming that it is known from previous studies that σ = 4.5 grams. If we wish to be 95% confident that the mean weight of the sample will be within 3 grams of the population mean for all mice subjected to this protein diet.

To find : How many mice should be included in our sample?

Solution :

The formula used in the situation is

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Where, z value at 95% confidence interval is z=1.96

[tex]\mu=3[/tex] gram is the mean of the population

[tex]\sigma=4.5[/tex] gram is the standard deviation of the sample

Substituting the value, to find x sample mean

[tex]1.96=\frac{x-3}{4.5}[/tex]

[tex]1.96\times 4.5=x-3[/tex]

[tex]8.82=x-3[/tex]

[tex]x=8.82+3[/tex]

[tex]x=11.82[/tex]

Therefore, The required amount of mice is 11.82 gram.

Answer:

monthly payment is $377

C is the correct option.

Step-by-step explanation:

The formula for the monthly payment is given by

[tex]C=\frac{Prt(1+r)^n}{(1+r)^n-1}[/tex]

Given that,

P =  $20,000

n = 5 years = 60 months

r = 0.05

Substituting these values in the formula

[tex]C=\frac{20000\cdot \frac{0.05}{12}(1+\frac{0.05}{12})^{60}}{(1+\frac{0.05}{12})^{60}-1}[/tex]

On simplifying, we get

[tex]C=\$377.425\\\\C\approx \$377[/tex]

Therefore, the monthly payment is $377

C is the correct option.

Answer:

64

Step-by-step explanation:

[tex]mean=\frac{sum\ of\ total\ number\ of\ score}{total\ number\ of\ students}[/tex]

we have given that mean of 9 students is 84

so total score of 9 students = mean×9

                                              =84×9=756

and we have given mean score of exam is 82 and there is total 10 students so the total score of 10 students =10×82

                                                      =820

so the unreadable score = score of 10 students -score of 9 students =820-756=64

Answer: (0.066,0.116)

Step-by-step explanation:

The confidence interval for proportion is given by :-

[tex]p_1-p_2\pm z_{\alpha/2}\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}[/tex]

Given : The proportion of men have red/green color blindness = [tex]p_1=\dfrac{89}{950}\approx0.094[/tex]

The proportion of women have red/green color blindness = [tex]p_2=\dfrac{6}{2050}\approx0.003[/tex]

Significance level : [tex]\alpha=1-0.99=0.01[/tex]

Critical value : [tex]z_{\alpha/2}=z_{0.005}=\pm2.576[/tex]

Now, the 99% confidence interval for the difference between the color blindness rates of men and women will be:-

[tex](0.094-0.003)\pm (2.576)\sqrt{\dfrac{0.094(1-0.094)}{950}+\dfrac{0.003(1-0.003)}{2050}}\approx0.091\pm 0.025\\\\=(0.09-0.025,0.09+0.025)=(0.066,\ 0.116)[/tex]

Hence, the 99% confidence interval for the difference between the color blindness rates of men and women= (0.066,0.116)

The solution of the given differential equation involves rearranging it into the standard form of a first-order linear differential equation, determining the integrating factor, and subsequently solving for the dependent variable y(x) via integration.

To solve the given differential equation, we can rewrite it in the form of dy/dx = f(x, y). That gives us (2(y-4x^2))/x = dy/dx. The resulting equation is a first-order linear differential equation, which can be solved using an integrating factor.

Here, the standard form of the differential equation is dy/dx + P(x)y = Q(x). Comparing this with our equation, we find P(x) = -2/x and Q(x) = -8x. We know that μ(x) = exp(∫P(x) dx) is the integrating factor. On solving we get μ(x) = 1/x2. We then multiply through our differential equation by μ(x) and integrate both sides to solve for y(x).

These steps on how to solve the differential equation involve certain knowledge in differential equation theory, namely about first-order linear differential equations, integrating factors, and the process of integration.

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The 99% confidence interval for the proportion of returned surveys is between 35.378% and 40.4213%, based on 931 responses from 2455 surveyed subjects.

To construct a 99% confidence interval for the proportion of returned surveys, we will use the formula for a proportion confidence interval which includes the sample proportion (π), the z-value that corresponds to the desired level of confidence, and the standard error of the proportion.

The sample proportion (π) can be calculated as the number of returned surveys divided by the total number of surveys sent:

π = 931 / 2455 = 0.379

The z-value for a 99% confidence interval is approximately 2.576. The standard error (SE) of π is calculated using the formula:

SE = √(π(1 - π) / n)

SE = √(0.379(1-0.379)/2455)

SE = √(0.379 * 0.621 / 2455)

SE = √(0.2353 / 2455)

SE = √(0.0000958)

SE = 0.009788

Now, we can calculate the margin of error (ME):

ME = z * SE

ME = 2.576 * 0.009788

ME = 0.025213

Finally, the 99% confidence interval (CI) is calculated as:

CI = π ± ME

CI = 0.379 ± 0.025213

CI = [0.353787, 0.404213]

We can be 99% confident that the true proportion of returned surveys falls between 35.378% and 40.4213%.

Answer:

520 girls attended the picnic

Step-by-step explanation:

Hello

step 1

Let

Homewood middle school total students=1200

A=unknown=total of girls

(2/3)A=total girls attended the picnic

B=unknown= total of boys

(1/2)B=total boys attended the picnic

step2

replace

[tex]A+B=1200\ equation (1) \\\frac{2A}{3}+\frac{B}{2}=730\ equation(2)\\[/tex]

Step 3

find A and B

from equation (1)

[tex]A=1200-B\ equation\ (3)\\\\[/tex]

from equation (2)

[tex]\frac{2A}{3}+\frac{B}{2}=730\\\frac{2A}{3}=730-\frac{B}{2}\\A=(730-\frac{B}{2})*\frac{3}{2} \\1200-B=1095-\frac{3B}{4}\\A=A\\-B+\frac{3B}{4}=1095-1200\\-\frac{B}{4}=-105\\ B=420\\\\hence\\\\A=1200-B\\A=1200-420\\A=780[/tex]

total girls attended  the picnic=(2/3)A=(2/3)780=520

520 girls attended the picnic

Answer:

520

Step-by-step explanation:

i also got the problem and got it wrong - i found the answer is 520

Answer:

So since your point is (-8,6), then your vertical line is x=-8 and horizontal line is y=6.

Step-by-step explanation:

Horizontal lines are in the form y=b.

Vertical lines are in the form x=a.

a and b are just constant numbers.

So anyways, in general:

The horizontal line going through (a,b) is y=b.

The vertical line going through (a,b) is x=a.

So since your point is (-8,6), then your vertical line is x=-8 and horizontal line is y=6.

Answer:

1680 ways

Step-by-step explanation:

Total number of integers = 10

Number of integers to be selected = 6

Second smallest integer must be 3. This means the smallest integer can be either 1 or 2. So, there are 2 ways to select the smallest integer and only 1 way to select the second smallest integer.

2 ways   1 way                                      

Each of the line represent the digit in the integer.

After selecting the two digits, we have 4 places which can be filled by 7 integers. Number of ways to select 4 digits from 7 will be 7P4 = 840

Therefore, the total number of ways to form 6 distinct integers according to the given criteria will be = 1 x 2 x 840 = 1680 ways

Therefore, there are 1680 ways to pick six distinct integers.

Answer:

70 total selections

Step-by-step explanation:

The set: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

You know that that 3 is definitly a part of the set, so you can ignore it. If 3 is the second smallest, the smallest number in the set is either 1 or 2, not both.

The number of ways to choose between 1 and 2 is [tex]2^{C}1[/tex] ways which is equal to 2, so all that's left is choosing from the group of the set between 4 and 10.

Since you've already chosen 2 numbers (3 and 1 or 2) you need to find out how many ways can you choose 4 out of the numbers between 4 and 10. Since there are 7 numbers from 4 to 10, you need to figure out [tex]7^{C}4[/tex] which is equal to 35.

Since you are looking to find the cross between the 2, multiply 2 by 35 = 70, the answer.

Answer:

[tex]g(4) = 8 \pi h\\\\g(\frac{3}{2}) = 3 \pi h\\\\ g(2c) = 4 \pi ch\\\\g(c+3) = 2 \pi hc+6\pi h[/tex]

Step-by-step explanation:

You need to substitute [tex]r=4[/tex] into [tex]g(r) = 2 \pi r h[/tex]. Then:

[tex]g(4) = 2 \pi(4)h\\\\g(4) = 8 \pi h[/tex]

Substitute [tex]r=\frac{3}{2}[/tex] into [tex]g(r) = 2 \pi r h[/tex]. Then:

[tex]g(\frac{3}{2}) = 2 \pi(\frac{3}{2})h\\\\g(\frac{3}{2}) = 3 \pi h[/tex]

Substitute [tex]r=2c[/tex] into [tex]g(r) = 2 \pi r h[/tex]. Then:

[tex]g(2c) = 2 \pi(2c))h\\\\g(2c) = 4 \pi ch[/tex]

Substitute [tex]r=c+3[/tex] into [tex]g(r) = 2 \pi r h[/tex]. Then:

[tex]g(c+3) = 2 \pi (c+3)h\\\\g(c+3) = 2 \pi hc+6\pi h[/tex]

For this case we have the following function:

[tex]g (r) = 2 \pi * r * h[/tex]

We must evaluate the function for different values:

[tex]g (4) = 2 \pi * (4) * h = 8 \pi*h\\g (\frac {3} {2}) = 2 \pi * (\frac {3} {2}) * h = 3 \pi*h\\g (2c) = 2 \pi * (2c) * h = 4 \pi * c * h\\g (c + 3) = 2 \pi * (c + 3) * h = 2 \pi * c * h + 6 \pi * h[/tex]

Answer:

[tex]g (4) = 8 \pi*h\\g (\frac {3} {2}) =3 \pi*h\\g (2c) = 4 \pi * c * h\\g (c + 3) = 2 \pi * c * h + 6 \pi * h[/tex]

Answer:

We know that equation of a circle with origin as it's center is given by

[tex]x^{2}+y^{2}=r^{2}\\\\\therefore x^{2}+y^{2}=2^{2}\\\\(\frac{x}{2})^{2}+(\frac{y}{2})^{2}=1\\\\[/tex]

Comparing with [tex]sin^{2}(\theta )+cos^{2}(\theta )=1[/tex] we get

[tex]\frac{x}{2}=sin(\theta )\\\\\therefore x=2sin(\theta )\\\\\frac{y}{2}=cos(\theta )\\\\\therefore y=cos(\theta )[/tex]

Since [tex]sin(\theta ),cos(\theta )[/tex] have a period of 2π but in the given question we need to increase the period to 4π  thus we reduce the argument by 2

[tex]\therefore x=2sin(\frac{\theta }{2})\\\\y=2cos(\frac{\theta }{2})[/tex]

The parametric equations for a clockwise circle of radius 2 centered at origin traced out once for a full revolution (0 ≤ t ≤ 4π) are x = 2 cos(-t/2), y = -2 sin(t/2). This can be confirmed by substituting -t/2 for t in Pythagorean Identity sin²(t) + cos²(t) = 1 which results in 1, proving the correctness of the equations.

The parametric equations for a circle of radius 2, centered at the origin, traced out once in the clockwise direction for 0 ≤ t ≤ 2π are x = 2 cos(t), y = 2 sin(t). However, as your question indicates the path traced out in the clockwise direction, the equations would be changed to x = 2 cos(-t) and y = 2 sin(-t). This is achieved by replacing t with -t in the original equations.

In the context of the question, parametric equations which are traced out once for a full revolution (0 ≤ t ≤ 4π in the negative or clockwise direction) are x = 2 cos(-t/2), y = -2 sin(t/2). This is because time is needed twice as much to make a full revolution, so 2t is replaced with t/2.

To verify these equations, you can use the Pythagorean Identity sin²(t) + cos²(t) = 1, substituting -t/2 for t in this identity equation, you will find that the result indeed equals 1, confirming these are the correct parametric equations.

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The nominal value - without discounting the inflation rate - of income was $ 3000.

If the interest rate was 6%, a rule of three is enough to find the value of the original investment.

3000 - 6%

x - 100%

x = 50,000

The value of the investment was $ 50,000

In this case, the inflation rate also requires a simple calculation.

Inflation corroded $ 1000 dollars of income of $ 3000

Therefore the inflation rate will be 1000/3000 = 33.3%

The chance you don't get an apple is:

                     [tex]\dfrac{38}{44}[/tex]

We know that the probability of an outcome is the chance of getting an outcome and it is calculated by:

Taking the  ratio of number of favorable outcomes to total number of outcomes.

A refrigerator contains 6 apples, 5 oranges, 10 bananas, 3 pears, 7 peaches, 11 plums, and 2 mangoes.

Total number of fruits in the refrigerator i.e. total number of outcomes are: 6+5+10+3+7+11+2

                                                                      = 44

Also the number of favorable outcomes i.e. number of fruits which are not apples in the refrigerator are: 44-6=38

This means that the probability of not getting an apple is:

[tex]\text{Probability(not\ getting\ an\ apple)}=\dfrac{38}{44}[/tex]

Final answer:

The chance you do not get an apple is38/44, or roughly86.36.

Explanation:

The chance you do not get an apple is38/44.

To calculate this, add up the total number of fruits in the refrigerator banning apples, which is 5 oranges 10 bananas 3 pears 7 peaches 11 catches 2 mangos = 38 fruits. The total number of fruits in the refrigerator is 6 apples 5 oranges 10 bananas 3 pears 7 peaches 11 catches 2 mangos = 44 fruits.

simplifies to19/22 or roughly0.8636, so the chance you do not get an apple is0.8636 or86.36.

Answer: The probability that the racket is wood or defective is 0.6.

Step-by-step explanation:

Since we have given that

Number of wood tennis rackets = 100

Number of graphite tennis rackets = 100

Total number of rackets = 200

Number of wood are defective = 12

Number of graphite are defective = 20

Total number of defectives = 32

We need to find the probability that the racket is wood or defective.

Let A be the event of wood tennis rackets.

Let B be the event of defective.

So, it becomes,

[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\P(A\cup B)=\dfrac{100}{200}+\dfrac{32}{200}-\dfrac{12}{200}\\\\P(A\cup B)=\dfrac{100+32-12}{200}=\dfrac{120}{200}=0.6[/tex]

Hence, the probability that the racket is wood or defective is 0.6.

Answer:

[tex]y(x)=c_1e^{-\frac{5}{2}x}+c_2xe^{-\frac{5}{2}x}[/tex]

Step-by-step explanation:

The given differential equation is 4y"+20y'+25y = 0

The characteristics equation is given by

[tex]4r^2+20r+25=0[/tex]

Now, solve the equation for r

Factor by middle term splitting

[tex]4r^2+10r+10r+25=0\\\\2r(2r+5)+5(2r+5)=0[/tex]

Factored out the common term

[tex](2r+5)(2r+5)=0[/tex]

Use Zero product property

[tex](2r+5)=0,(2r+5)=0[/tex]

Solve for r

[tex]r_{1,2}=-\frac{5}{2}[/tex]

We got the repeated roots.

Hence, the general equation for the differential equation is

[tex]y(x)=c_1e^{-\frac{5}{2}x}+c_2xe^{-\frac{5}{2}x}[/tex]

Final answer:

The general solution to the differential equation 4y"+20y'+25y = 0 is y(x) = (A + Bx)e^(-5/2x), where A and B are constants determined by initial conditions.

Explanation:

The general solution to the differential equation 4y"+20y'+25y = 0 can be found by looking for solutions in the form of y = ekx, where k is a constant. Substituting y into the differential equation, we get a characteristic equation of (ak² +bk+c)y= 0, which simplifies to (4k² + 20k + 25)y = 0. This is a quadratic equation in k that can be factored as (2k + 5)². Therefore, the two values of k that satisfy this equation are both -5/2, giving us a repeated root.

The general solution for a second-order linear homogeneous differential equation with repeated roots is y = (A + Bx)ekx, where A and B are constants determined by the initial conditions. In this case, k = -5/2, hence the general solution is y(x) = (A + Bx)e-5/2x.

To find the cost of resurfacing the path, we first calculate the area of the path which is 300 square feet. We then multiply this by the unit cost of resurfacing which comes out to be $600.

This is a problem in area calculation and application of unit cost. Firstly, we need to calculate the area for the path surrounding the pool. The total area of the pool and the path is (14+2*3) feet by (30+2*3) feet = 20 feet by 36 feet, which equals 720 square feet. The area of the pool itself is 14 feet by 30 feet = 420 square feet. So, the area of just the path is 720-420 = 300 square feet. With a cost of $2 per square foot to resurface the path, the total cost would be 300*$2 = $600.

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Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly  among the given student the probability that this student is wearing a ring or necklace is

[tex]P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1[/tex]

[tex]P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4[/tex]

The sum of probabilty is equal to 1 because it completes the set

Therefore the required probabilty is 0.4

Final answer:

The probability that a randomly chosen student is wearing either a ring or a necklace is 40%. This conclusion is based on the complement of the given percentage of students who wear neither, assuming that there is no overlap in the 20% and 30% who wear rings and necklaces respectively.

Explanation:

To find the probability that a randomly chosen student is wearing a ring or a necklace, we need to understand that 'or' in probability means either one or the other, or both. According to the question, 60% of the students wear neither, which means 40% of the students wear either a ring, a necklace, or both. Since 20% wear a ring and 30% wear a necklace, we might be tempted to add these percentages to get 50%. However, doing so could potentially double-count students who wear both a ring and a necklace.

Without additional information, we can simply state that the probability that a student is wearing a ring or a necklace is the complement of the probability of a student wearing neither, which is 40%. Here we're assuming that students either wear a ring or a necklace or both, as there is no mention of wearing neither in the probabilities given.

Answer: Mean = 760

Standard deviation = 6.16

Step-by-step explanation:

Given : The number of trials: [tex]n=800[/tex]

The probability that  a certain protection system will be recovered :[tex]p=0.95[/tex]

We know that the mean and standard deviation of binomial distribution is given by :_

[tex]\text{Mean}=np[/tex]

[tex]\text{Standard deviation}=\sqrt{np(1-p)}[/tex], where n is the number of trials and p is the probability of success.

Now, the mean and standard deviation of the number of cars recovered after being stolen is given by :-

[tex]\text{Mean}=800\times0.95=760[/tex]

[tex]\text{Standard deviation}=\sqrt{800\times0.95(1-0.95)}\\\\=6.164414002\approx6.16[/tex]

Hence, the mean is 760 and standard deviation is 6.16 .

The mean and standard deviation of the number of cars recovered after being stolen can be found using the properties of the binomial distribution.

To find the mean and standard deviation of the number of cars recovered after being stolen, we can use the properties of the binomial distribution. In this case, the probability of recovering a car is 0.95, and the number of stolen cars is 800.

The mean can be calculated by multiplying the number of trials (800) by the probability of success (0.95), giving us a mean of 760 cars.

The standard deviation can be calculated using the formula:

standard deviation = sqrt(n * p * (1 - p))

Substituting in the values, we get:

standard deviation = sqrt(800 * 0.95 * (1 - 0.95))

standard deviation ≈ 8.72 cars.

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Answer:

p(A and B) =0.1316

Step-by-step explanation:

We know that [tex]p(B|A)=\frac{p(A\cap B)}{p(A)}\\\\p(B\cap A )=p(B|A)\times p(A)[/tex]

Applying values we get

[tex]p(A and B)=0.47\times 0.28\\\\p(AandB)=0.1316[/tex]

a. Recall that

[tex]\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C[/tex]

For [tex]|x|<1[/tex], we have

[tex]\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n[/tex]

By integrating both sides, we get

[tex]\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}[/tex]

If [tex]x=0[/tex], then

[tex]\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0[/tex]

so that

[tex]\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}[/tex]

We can shift the index to simplify the sum slightly.

[tex]\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n[/tex]

b. The power series for [tex]x\ln(1-x)[/tex] can be obtained simply by multiplying both sides of the series above by [tex]x[/tex].

[tex]\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n[/tex]

c. We have

[tex]\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)[/tex]

[tex]\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}[/tex]

The power series of f(x) = ln(1 - x) is  [tex]\rm -\sum^{\infty}_{n=1}\dfrac{x^{n} }{n}[/tex], the power series of xln(1 - x) is  [tex]\rm -\sum^{\infty}_{n=1}\dfrac{x^{n+1} }{n}[/tex] and the value of ln(2) is [tex]\rm \sum^{\infty}_{n=0}\dfrac{1}{n2^n}[/tex].

Given :

f(x) = ln (1−x)

a) The integration of 1/(1 - x) is given by:

[tex]\rm \int \dfrac{1}{1-x}dx=-ln|1-x| + C[/tex]

When |x| >1 :

[tex]\dfrac{1}{1-x} = \sum^{\infty}_{n=0} x^n[/tex]

Now, integrate on both sides in the above equation.

[tex]\rm -ln(1-x) = C+\sum^{\infty}_{n=0}\dfrac{x^{n+1} }{n+1}[/tex]   --- (1)

Now, at (x = 0) the above expression becomes:

[tex]\rm -ln(1-0) = C+\sum^{\infty}_{n=0}\dfrac{0^{n+1} }{n+1}[/tex]

By simplifying the above expression in order to get the value of C.

C = 0

Now, substitute the value of C in expression (1).

[tex]\rm ln(1-x) =-\sum^{\infty}_{n=0}\dfrac{x^{n+1} }{n+1}[/tex]

Now, by shifting the index the above expression becomes:

[tex]\rm ln(1-x) =-\sum^{\infty}_{n=1}\dfrac{x^{n} }{n}[/tex]

b) Now, multiply by 'x' in the above expression in order to get the power series of (x ln(1 - x)).

[tex]\rm xln(1-x) =-\sum^{\infty}_{n=1}\dfrac{x^{n+1} }{n}[/tex]

c) Now, substitute the value x = 1/2 in the expression (1).

[tex]\rm ln2 = \sum^{\infty}_{n=0}\dfrac{1}{n2^n}[/tex]

For more information, refer to the link given below:

https://brainly.com/question/16407904

Answer:

[tex] f ( 2 x ) = 4 x ^ 2 - 8 [/tex]

Step-by-step explanation:

We are given the following expression and we are to simplify the given function:

[tex] f ( x ) = x ^ 2 - 8 [/tex]

Applying the function [tex]f(2x)[/tex] on [tex] f ( x ) = x ^ 2 - 8 [/tex] to get:

[tex] f ( 2 x ) = ( 2 x ) ^ 2 - 8 [/tex]

[tex] f ( 2 x ) = 4 x ^ 2 - 8 [/tex]

Answer:

The length of the ladder is 10 m.

Step-by-step explanation:

Let x shows the distance of the top of ladder from the bottom of base of the wall, y shows the distance of the bottom of ladder from the base of the wall and l is the length of the ladder,

Given,

[tex]\frac{dx}{dt}=-0.675\text{ m/s}[/tex]

[tex]\frac{dy}{dt}=0.9\text{ m/s}[/tex]

y = 6 m,

Since, the wall is assumed perpendicular to the ground,

By the pythagoras theorem,

[tex]l^2=x^2+y^2[/tex]

Differentiating with respect to t ( time ),

[tex]0=2x\frac{dx}{dt}+2y\frac{dy}{dt}[/tex]     ( the length of wall would be constant )

By substituting the value,

[tex]0=2x(-0.675)+2(6)(0.9)[/tex]

[tex]0=-1.35x+10.8[/tex]

[tex]\implies x=\frac{10.8}{1.35}=8[/tex]

Hence, the length of the ladder is,

[tex]L=\sqrt{x^2+y^2}=\sqrt{8^2+6^2}=\sqrt{64+36}=\sqrt{100}=10\text{ m}[/tex]

Answer:

The length of ladder=8m.

Step-by-step explanation:

Given

The rate at which the top of a ladder slides down a vertical wall,[tex]\frac{\mathrm{d}z}{\mathrm{d}t}[/tex]= 0.675m/s

The distance of bottom of ladder from the wall,x=6m

The rate at which it slides away from the wall ,[tex]\frac{\mathrm{d}x}{\mathrm{d}t}[/tex]=0.9m/s

Let length of ladder =z

Length of wall=y

Distance between foot of ladder and wall=x

By using pythogorous theorem

[tex]x^2+y^2=z^2[/tex]

Differentiate w.r.t time

[tex]x\frac{\mathrm{d}x}{\mathrm{d}t}=z\frac{\mathrm{d}z}{\mathrm{d}t}[/tex]

y does not change hence, [tex]\frac{\mathrm{d}y}{\mathrm{d}t}=0[/tex]

[tex]6\times 0.9=z\times 0.675[/tex]

[tex]z=\frac{5.4}{0.675}[/tex]

z=8 m

Hence, the length of ladder=8m.

Answer:

$16.583

Step-by-step explanation:

Given :Your friend, Isabel, has a credit card with an APR of 19.9%!

To Find : How many dollars would she pay as a finance charge for just 1 month on a $1000 charge?

Solution:

We are given that finance charge for just 1 month on a $1000 charge.

So, Finance charge = [tex]\frac{19.9\% \times 1000}{12}[/tex]

Finance charge = [tex]\frac{\frac{199}{1000}\times 1000}{12}[/tex]

Finance charge = [tex]\frac{199\times 1000}{12}[/tex]

Finance charge = [tex]16.583[/tex]

Hence she pay $16.583 as a finance charge for just 1 month on a $1000 charge.

[tex]_{12}C_5=\dfrac{12!}{5!7!}=\dfrac{8\cdot9\cdot10\cdot11\cdot12}{120}=792[/tex]

792>20, so yeah, he will be able.

Answer:

792>20, so yeah, he will be able.

Step-by-step explanation:

Answer:

Equation is 4x + 6 = 598, where x represents smaller number.

Numbers are 148, 152, 156 and 160

Step-by-step explanation:

Let x be the smaller natural number,

So, the other consecutive natural numbers are x+1, x+2, x+3,

According to the question,

Sum of x, x+1, x+2 and x+3 is 598,

⇒ x + x + 1 + x + 2 + x + 3 = 598

⇒ 4x + 6 = 598

Which are the required equation,

Subtract 6 on both sides,

4x = 592

Divide both sides by 4,

x = 148

Hence, the numbers are 148, 152, 156 and 160

Final answer:

The equation to find four consecutive natural numbers with a sum of 598 is 4x + 6 = 598. Solving for x gives the first number as 148, which leads to the sequence: 148, 149, 150, and 151.

Explanation:

The student is tasked with finding four consecutive natural numbers whose sum is 598.

To solve this problem, we introduce a variable to represent the first number in the sequence, and then express the following three numbers in terms of this variable.

Let's denote the first number as x. Then the next three numbers will be x+1, x+2, and x+3, respectively. Our equation to find the numbers is:

x + (x+1) + (x+2) + (x+3) = 598

Combining like terms, we get:

4x + 6 = 598

We then solve for x:

4x = 598 - 6

4x = 592

x = 592 / 4

x = 148

So the four consecutive numbers are 148, 149, 150, and 151.

Answer and Step-by-step explanation:

Since we have given that

AB = 0

where A and B are n  x n matrices.

Consider determinant on both sides,

[tex]\mid AB\mid=\mid 0\mid\\\\\mid A\mid \mid B\mid =0\\\\either\ \mid A\mid =0\ or\ \mid B\mid =0[/tex]

since A is invertible, then |A| ≠ 0

so, it means |B| = 0.

Hence, B is not invertible.

Hence proved.